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  • SQL SERVER- Differences Between Left Join and Left Outer Join

    - by pinaldave
    There are a few questions that I had decided not to discuss on this blog because I think they are very simple and many of us know it. Many times, I even receive not-so positive notes from several readers when I am writing something simple. However, assuming that we know all and beginners should know everything is not the right attitude. Since day 1, I have been keeping a small journal regarding questions that I receive in this blog. There are around 200+ questions I receive every day through emails, comments and occasional phone calls. Yesterday, I received a comment with the following question: What are the differences between Left Join and Left Outer Join? Click here to read original comment. This question has triggered the threshold of receiving the same question repeatedly. Here is the answer: There is absolutely no difference between LEFT JOIN and LEFT OUTER JOIN. The same is true for RIGHT JOIN and RIGHT OUTER JOIN. When you use LEFT JOIN keyword in SQL Server, it means LEFT OUTER JOIN only. I have already written in-depth visual diagram discussing the JOINs. I encourage all of you to read the article for further understanding of the JOINs: Read Introduction to JOINs – Basic of JOINs Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Joins, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Joining on a common table, how do you get a FULL OUTER JOIN to expand on another table?

    - by stimpy77
    I've scoured StackOverflow and Google for an answer to this problem. I'm trying to create a Microsot SQL Server 2008 view. Not a stored procedure. Not a function. Just a query (i.e. a view). I have three tables. The first table defines a common key, let's say "CompanyID". The other two tables have a sometimes-common field, let's say "EmployeeName". I want a single table result that, when my WHERE clause says "WHERE CompanyID = 12" looks like this: CompanyID | TableA | TableB 12 | John Doe | John Doe 12 | Betty Sue | NULL 12 | NULL | Billy Bob I've tried a FULL OUTER JOIN that looks like this: SELECT Company.CompanyID, TableA.EmployeeName, TableB.EmployeeName FROM Company FULL OUTER JOIN TableA ON Company.CompanyID = TableA.CompanyID FULL OUTER JOIN TableB ON Company.CompanyID = TableB.CompanyID AND (TableA.EmployeeName IS NULL OR TableB.EmployeeName IS NULL OR TableB.EmployeeName = TableA.EmployeeName) I'm only getting the NULL from one matched table, I'm not getting the expansion for the other table. In the above sample, I'm basically only getting the first and third rows and not the second. Can someone help me create this query and show me how this is done correctly? BTW I already have a stored procedure that looks very clean and populates an in-memory table, but that isn't what I want. Thanks.

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  • Formatted Ubuntu partition & now grub says "error: no such partition" - can't enter windows

    - by qwBJ
    I had installed Ubuntu (current version: 11.xx) alongside Windows Vista. Now I formatted the Ubuntu partition & merged it with another partition (without thinking, obviously). Now, when I restart the computer, GRUB probably tries to find the old partition (which does no longer exist) and says: error: no such partition. grub rescue> Now I dont know what to do (I'm a total beginner). I tried to re-install Ubuntu on the newly formatted partition but this won't work, because after removing the install-usb (which I am said to do during installation) I find the above error-message again. I guess I need some way to reconfigure grub OR to reinstall grub/ubuntu (on the newly formatted partition) OR to reinstall the windows boot manager (without reinstall. Windows), but I have no idea how to do either of these things.

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  • Create a AD-LDS partition under a child of the primary partition

    - by ixe013
    I have a AD-LDS instance running on a Server 2008 R2. I have this application partition, created at installation : dc=enterprise,dc=example,dc=com I have succesfully followed this procedure to create application partitions. They are named : cn=stuff,dc=enterprise,dc=example,dc=com cn=things,dc=enterprise,dc=example,dc=com If I configure my client(s) to follow referals, I can search from dc=enterprise,dc=example,dc=com and find objects under cn=stuff and cn=things. How can I create (or move after the fact) the stuff and things partitions so they are logically located under a OU under the initial partition, ending up with something like : cn=stuff,ou=applications,dc=enterprise,dc=example,dc=com cn=things,ou=applications,dc=enterprise,dc=example,dc=com

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  • Shrink a mounted LVM partition

    - by javanix
    I fear I already know the answer to this question, but here goes. I need to carve out a new partition on a running system. /var/ is mounted from an LVM volume (hdd1_vg-var) and has only 3% used disk space. / is mounted separately (hdd1_vg-root) and has about 80% used disk space. Filesystem Size Used Avail Use% Mounted on /dev/**/hdd1_vg-root 2.0G 1.4G 481M 75% / /dev/**/hdd1_vg-var 33G 699M 31G 3% /var Unfortunately I don't have any free extents to grow this partition organically - vgdisplay shows: Total PE 10000 Alloc PE / Size 10000 / 39.06 GB Free PE / Size 0 / 0 So seeing that I have all this free disk space on /var/, can I shrink /var/ without un-mounting it or is this just a pipe dream? I am really hoping to be able to do this work on a running system - un-mounting would of course not be difficult but it would interfere with system functionality.

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  • Resize primary partition

    - by telebog
    I have a hdd with the folowing partition table 12Gb Primary Partition (ntfs) 140Gb Extended Partition (ntfs) I want to install windows 7 and I need more space for the Primary Partition. The problem is that when I resize partitons I obtain: 12Gb Primary Partition (ntfs) 110Gb Extended Partition (ntfs) 30Gb Free Space So I can't allocate the free space to primary partition because the free space is at the end of the disk. Is there a solution to extend the primary partition as: 42Gb Primary Partition (ntfs) 110Gb Extended Partition (ntfs) without repartitioning the entire disk? I used partition magic, gparted-live-0.4.6-4 and others with no success. With the Disk Management from Vista I manage to extend primary partition, but made my partitions dinamic.

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  • Oracle Database 12 c New Partition Maintenance Features by Gwen Lazenby

    - by hamsun
    One of my favourite new features in Oracle Database 12c is the ability to perform partition maintenance operations on multiple partitions. This means we can now add, drop, truncate and merge multiple partitions in one operation, and can split a single partition into more than two partitions also in just one command. This would certainly have made my life slightly easier had it been available when I administered a data warehouse at Oracle 9i. To demonstrate this new functionality and syntax, I am going to create two tables, ORDERS and ORDERS_ITEMS which have a parent-child relationship. ORDERS is to be partitioned using range partitioning on the ORDER_DATE column, and ORDER_ITEMS is going to partitioned using reference partitioning and its foreign key relationship with the ORDERS table. This form of partitioning was a new feature in 11g and means that any partition maintenance operations performed on the ORDERS table will also take place on the ORDER_ITEMS table as well. First create the ORDERS table - SQL CREATE TABLE orders ( order_id NUMBER(12), order_date TIMESTAMP, order_mode VARCHAR2(8), customer_id NUMBER(6), order_status NUMBER(2), order_total NUMBER(8,2), sales_rep_id NUMBER(6), promotion_id NUMBER(6), CONSTRAINT orders_pk PRIMARY KEY(order_id) ) PARTITION BY RANGE(order_date) (PARTITION Q1_2007 VALUES LESS THAN (TO_DATE('01-APR-2007','DD-MON-YYYY')), PARTITION Q2_2007 VALUES LESS THAN (TO_DATE('01-JUL-2007','DD-MON-YYYY')), PARTITION Q3_2007 VALUES LESS THAN (TO_DATE('01-OCT-2007','DD-MON-YYYY')), PARTITION Q4_2007 VALUES LESS THAN (TO_DATE('01-JAN-2008','DD-MON-YYYY')) ); Table created. Now the ORDER_ITEMS table SQL CREATE TABLE order_items ( order_id NUMBER(12) NOT NULL, line_item_id NUMBER(3) NOT NULL, product_id NUMBER(6) NOT NULL, unit_price NUMBER(8,2), quantity NUMBER(8), CONSTRAINT order_items_fk FOREIGN KEY(order_id) REFERENCES orders(order_id) on delete cascade) PARTITION BY REFERENCE(order_items_fk) tablespace example; Table created. Now look at DBA_TAB_PARTITIONS to get details of what partitions we have in the two tables – SQL select table_name,partition_name, partition_position position, high_value from dba_tab_partitions where table_owner='SH' and table_name like 'ORDER_%' order by partition_position, table_name; TABLE_NAME PARTITION_NAME POSITION HIGH_VALUE -------------- --------------- -------- ------------------------- ORDERS Q1_2007 1 TIMESTAMP' 2007-04-01 00:00:00' ORDER_ITEMS Q1_2007 1 ORDERS Q2_2007 2 TIMESTAMP' 2007-07-01 00:00:00' ORDER_ITEMS Q2_2007 2 ORDERS Q3_2007 3 TIMESTAMP' 2007-10-01 00:00:00' ORDER_ITEMS Q3_2007 3 ORDERS Q4_2007 4 TIMESTAMP' 2008-01-01 00:00:00' ORDER_ITEMS Q4_2007 4 Just as an aside it is also now possible in 12c to use interval partitioning on reference partitioned tables. In 11g it was not possible to combine these two new partitioning features. For our first example of the new 12cfunctionality, let us add all the partitions necessary for 2008 to the tables using one command. Notice that the partition specification part of the add command is identical in format to the partition specification part of the create command as shown above - SQL alter table orders add PARTITION Q1_2008 VALUES LESS THAN (TO_DATE('01-APR-2008','DD-MON-YYYY')), PARTITION Q2_2008 VALUES LESS THAN (TO_DATE('01-JUL-2008','DD-MON-YYYY')), PARTITION Q3_2008 VALUES LESS THAN (TO_DATE('01-OCT-2008','DD-MON-YYYY')), PARTITION Q4_2008 VALUES LESS THAN (TO_DATE('01-JAN-2009','DD-MON-YYYY')); Table altered. Now look at DBA_TAB_PARTITIONS and we can see that the 4 new partitions have been added to both tables – SQL select table_name,partition_name, partition_position position, high_value from dba_tab_partitions where table_owner='SH' and table_name like 'ORDER_%' order by partition_position, table_name; TABLE_NAME PARTITION_NAME POSITION HIGH_VALUE -------------- --------------- -------- ------------------------- ORDERS Q1_2007 1 TIMESTAMP' 2007-04-01 00:00:00' ORDER_ITEMS Q1_2007 1 ORDERS Q2_2007 2 TIMESTAMP' 2007-07-01 00:00:00' ORDER_ITEMS Q2_2007 2 ORDERS Q3_2007 3 TIMESTAMP' 2007-10-01 00:00:00' ORDER_ITEMS Q3_2007 3 ORDERS Q4_2007 4 TIMESTAMP' 2008-01-01 00:00:00' ORDER_ITEMS Q4_2007 4 ORDERS Q1_2008 5 TIMESTAMP' 2008-04-01 00:00:00' ORDER_ITEMS Q1_2008 5 ORDERS Q2_2008 6 TIMESTAMP' 2008-07-01 00:00:00' ORDER_ITEM Q2_2008 6 ORDERS Q3_2008 7 TIMESTAMP' 2008-10-01 00:00:00' ORDER_ITEMS Q3_2008 7 ORDERS Q4_2008 8 TIMESTAMP' 2009-01-01 00:00:00' ORDER_ITEMS Q4_2008 8 Next, we can drop or truncate multiple partitions by giving a comma separated list in the alter table command. Note the use of the plural ‘partitions’ in the command as opposed to the singular ‘partition’ prior to 12c– SQL alter table orders drop partitions Q3_2008,Q2_2008,Q1_2008; Table altered. Now look at DBA_TAB_PARTITIONS and we can see that the 3 partitions have been dropped in both the two tables – TABLE_NAME PARTITION_NAME POSITION HIGH_VALUE -------------- --------------- -------- ------------------------- ORDERS Q1_2007 1 TIMESTAMP' 2007-04-01 00:00:00' ORDER_ITEMS Q1_2007 1 ORDERS Q2_2007 2 TIMESTAMP' 2007-07-01 00:00:00' ORDER_ITEMS Q2_2007 2 ORDERS Q3_2007 3 TIMESTAMP' 2007-10-01 00:00:00' ORDER_ITEMS Q3_2007 3 ORDERS Q4_2007 4 TIMESTAMP' 2008-01-01 00:00:00' ORDER_ITEMS Q4_2007 4 ORDERS Q4_2008 5 TIMESTAMP' 2009-01-01 00:00:00' ORDER_ITEMS Q4_2008 5 Now let us merge all the 2007 partitions together to form one single partition – SQL alter table orders merge partitions Q1_2005, Q2_2005, Q3_2005, Q4_2005 into partition Y_2007; Table altered. TABLE_NAME PARTITION_NAME POSITION HIGH_VALUE -------------- --------------- -------- ------------------------- ORDERS Y_2007 1 TIMESTAMP' 2008-01-01 00:00:00' ORDER_ITEMS Y_2007 1 ORDERS Q4_2008 2 TIMESTAMP' 2009-01-01 00:00:00' ORDER_ITEMS Q4_2008 2 Splitting partitions is a slightly more involved. In the case of range partitioning one of the new partitions must have no high value defined, and in list partitioning one of the new partitions must have no list of values defined. I call these partitions the ‘everything else’ partitions, and will contain any rows contained in the original partition that are not contained in the any of the other new partitions. For example, let us split the Y_2007 partition back into 4 quarterly partitions – SQL alter table orders split partition Y_2007 into (PARTITION Q1_2007 VALUES LESS THAN (TO_DATE('01-APR-2007','DD-MON-YYYY')), PARTITION Q2_2007 VALUES LESS THAN (TO_DATE('01-JUL-2007','DD-MON-YYYY')), PARTITION Q3_2007 VALUES LESS THAN (TO_DATE('01-OCT-2007','DD-MON-YYYY')), PARTITION Q4_2007); Now look at DBA_TAB_PARTITIONS to get details of the new partitions – TABLE_NAME PARTITION_NAME POSITION HIGH_VALUE -------------- --------------- -------- ------------------------- ORDERS Q1_2007 1 TIMESTAMP' 2007-04-01 00:00:00' ORDER_ITEMS Q1_2007 1 ORDERS Q2_2007 2 TIMESTAMP' 2007-07-01 00:00:00' ORDER_ITEMS Q2_2007 2 ORDERS Q3_2007 3 TIMESTAMP' 2007-10-01 00:00:00' ORDER_ITEMS Q3_2007 3 ORDERS Q4_2007 4 TIMESTAMP' 2008-01-01 00:00:00' ORDER_ITEMS Q4_2007 4 ORDERS Q4_2008 5 TIMESTAMP' 2009-01-01 00:00:00' ORDER_ITEMS Q4_2008 5 Partition Q4_2007 has a high value equal to the high value of the original Y_2007 partition, and so has inherited its upper boundary from the partition that was split. As for a list partitioning example let look at the following another table, SALES_PAR_LIST, which has 2 partitions, Americas and Europe and a partitioning key of country_name. SQL select table_name,partition_name, high_value from dba_tab_partitions where table_owner='SH' and table_name = 'SALES_PAR_LIST'; TABLE_NAME PARTITION_NAME HIGH_VALUE -------------- --------------- ----------------------------- SALES_PAR_LIST AMERICAS 'Argentina', 'Canada', 'Peru', 'USA', 'Honduras', 'Brazil', 'Nicaragua' SALES_PAR_LIST EUROPE 'France', 'Spain', 'Ireland', 'Germany', 'Belgium', 'Portugal', 'Denmark' Now split the Americas partition into 3 partitions – SQL alter table sales_par_list split partition americas into (partition south_america values ('Argentina','Peru','Brazil'), partition north_america values('Canada','USA'), partition central_america); Table altered. Note that no list of values was given for the ‘Central America’ partition. However it should have inherited any values in the original ‘Americas’ partition that were not assigned to either the ‘North America’ or ‘South America’ partitions. We can confirm this by looking at the DBA_TAB_PARTITIONS view. SQL select table_name,partition_name, high_value from dba_tab_partitions where table_owner='SH' and table_name = 'SALES_PAR_LIST'; TABLE_NAME PARTITION_NAME HIGH_VALUE --------------- --------------- -------------------------------- SALES_PAR_LIST SOUTH_AMERICA 'Argentina', 'Peru', 'Brazil' SALES_PAR_LIST NORTH_AMERICA 'Canada', 'USA' SALES_PAR_LIST CENTRAL_AMERICA 'Honduras', 'Nicaragua' SALES_PAR_LIST EUROPE 'France', 'Spain', 'Ireland', 'Germany', 'Belgium', 'Portugal', 'Denmark' In conclusion, I hope that DBA’s whose work involves maintaining partitions will find the operations a bit more straight forward to carry out once they have upgraded to Oracle Database 12c. Gwen Lazenby is a Principal Training Consultant at Oracle. She is part of Oracle University's Core Technology delivery team based in the UK, teaching Database Administration and Linux courses. Her specialist topics include using Oracle Partitioning and Parallelism in Data Warehouse environments, as well as Oracle Spatial and RMAN.

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  • Most optimal order (of joins) for left join

    - by Ram
    I have 3 tables Table1 (with 1020690 records), Table2(with 289425 records), Table 3(with 83692 records).I have something like this SELECT * FROM Table1 T1 /* OK fine select * is bad when not all columns are needed, this is just an example*/ LEFT JOIN Table2 T2 ON T1.id=T2.id LEFT JOIN Table3 T3 ON T1.id=T3.id and a query like this SELECT * FROM Table1 T1 LEFT JOIN Table3 T3 ON T1.id=T3.id LEFT JOIN Table2 T2 ON T1.id=T2.id The query plan shows me that it uses 2 Merge Join for both the joins. For the first query, the first merge is with T1 and T2 and then with T3. For the second query, the first merge is with T1 and T3 and then with T2. Both these queries take about the same time(40 seconds approx.) or sometimes Query1 takes couple of seconds longer. So my question is, does the join order matter ?

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  • Failed to install GRUB on a separate '/boot' partition on a fake RAID 0 (12.04LTS)

    - by gerben
    I'm having some problems getting GRUB configured for Ubuntu 12.04LTS on a fake RAID 0. I can either get the GRUB rescue prompt at startup, or just a GRUB prompt but I cannot boot to Ubuntu manually. How can I configure the GRUB to actually use the Ubuntu install? The steps taken: Installing Ubuntu on fake raid The Ubuntu installer cannot install Ubuntu on the drive. After defining the partitions to use it fails with "Error: ???", pressing OK terminates the installer. Therefore, I used GParted to configure the partitions: /dev/mapper/sil_agadaccfacbg : (the RAID configuration, created partition): /dev/mapper/sil_agadaccfacbg1:ext2, 200MiB, (with 'boot' flag) /dev/mapper/sil_agadaccfacbg3:ext2, 67.75GiB, (which will contain Ubuntu) /dev/mapper/sil_agadaccfacbg2:extended, 1.00GiB, (for swap) Contains: /dev/mapper/sil_agadaccfacbg5: unknown Because of the fake-RAID, I already mounted the destination partitions before running the Ubuntu installer: > mkdir /mnt/boot > sudo mount /dev/mapper/sil_agadaccfacbg1 /mnt/boot > mkdir /mnt/ubuntu > sudo mount /dev/mapper/sil_agadaccfacbg3 /mnt/ubuntu In the installer I chose the following partition usage: /dev/mapper/sil_agadaccfacbg1 ext2, mount at /boot (209MB) /dev/mapper/sil_agadaccfacbg3 ext2, mount at / (72751MB) /dev/mapper/sil_agadaccfacbg5 swap Device for boot loader installation: /dev/mapper/sil_agadaccfacbg, linux device-mapper (striped) (74.0GB) This will install Ubuntu, but will fail to install GRUB (it seems to use /dev/sda no matter which one I choose) Installing GRUB with dpkg-reconfigure I followed this guide, but adapted it for two partitions: sudo mount /dev/mapper/sil_agadaccfacbg3 /mnt/ubuntu sudo mount --bind /dev /mnt/ubuntu/dev sudo mount --bind /proc /mnt/ubuntu/proc sudo mount --bind /sys /mnt/ubuntu/sys sudo mount /dev/mapper/sil_agadaccfacbg1 /mnt/boot sudo mount --bind /boot /mnt/boot sudo chroot /mnt/ubuntu dpkg-reconfigure grub-pc However, it does not ask where to install GRUB (I should choose /dev/mapper/sil_agadaccfacbg somewhere..) After reboot I get the GRUB rescue prompt with message no such device Installing GRUB with grub-install After the same mount commands as above, I continued with: > sudo grub-install --root-directory=/mnt/boot /dev/mapper/sil_agadaccfacbg This gives the following message: /usr/sbin/grub-probe: error: cannot find a device for /mnt/boot/boot/grub (is /dev mounted?) It does succeed when mounting just the boot partition : sudo mount /dev/mapper/sil_agadaccfacbg1 /mnt sudo grub-install --root-directory=/mnt/ /dev/mapper/sil_agadaccfacbg This finishes with: Installation finished. No error reported. After reboot I get the GRUB console, with welcome text. Attempting to manually start Ubuntu: ls (hd0) (hd0,msdos3) : (Ubuntu install partition) (hd0,msdos1) : (Ubuntu boot partition) (hd1) (hd1,msdos1) : (Ubuntu live USB) ls (hd0,msdos3)/ contains: - vmlinuz - lib/ - tmp/ - initrd.img - mnt/ - var/ - proc/ - boot/ - root/ - etc/ - run/ - media/ - sbin/ - bin/ - selinux/ - dev/ - srv/ - home/ - sys/ ls (hd0,msdos1)/ contains: -grub/ -boot/ -initrd.img-3.8.0-29-generic -vmlinuz-3.8.0.29-generic -config-3.8 linux (hd0,msdos3)/vmlinuz This returns "error: out of disk" Installing GRUB on Ubuntu partition with grub-install > sudo mount /dev/mapper/sil_agadaccfacbg3 /mnt > sudo grub-install --root-directory=/mnt/ /dev/mapper/sil_agadaccfacbg This finishes with message: > Installation finished. No error reported. After reboot get the message "error: out of disk" and the GRUB rescue prompt. Configuring GRUB with grub-mkconfig Attempting to run grub-mkconfig with different destinations results in the same message: /usr/sbin/grub-probe: error: cannot find a device for / (is /dev mounted?). Remarks: Initially I didn't use a separate /boot partition, but the GRUB install then also failed. Because some mention that a small partition at the beginning of the drive is necessary on old machines, I retried with a /boot partition This is a single boot (no other OS's installed/used)

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  • LINQ to SQL - Left Outer Join with multiple join conditions

    - by dan
    I have the following SQL which I am trying to translate to LINQ: SELECT f.value FROM period as p LEFT OUTER JOIN facts AS f ON p.id = f.periodid AND f.otherid = 17 WHERE p.companyid = 100 I have seen the typical implementation of the left outer join (ie. into x from y in x.DefaultIfEmpty() etc.) but am unsure how to introduce the other join condition ('AND f.otherid = 17') EDIT Why is the 'AND f.otherid = 17' condition part of the JOIN instead of in the WHERE clause? Because f may not exist for some rows and I still want these rows to be included. If the condition is applied in the WHERE clause, after the JOIN - then I don't get the behaviour I want. Unfortunately this: from p in context.Periods join f in context.Facts on p.id equals f.periodid into fg from fgi in fg.DefaultIfEmpty() where p.companyid == 100 && fgi.otherid == 17 select f.value seems to be equivalent to this: SELECT f.value FROM period as p LEFT OUTER JOIN facts AS f ON p.id = f.periodid WHERE p.companyid = 100 && AND f.otherid = 17 which is not quite what I'm after.

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  • Moving users folder on Windows-7 to another partition - bad idea?

    - by Donat
    Hi, I'd like to re-submit here a question posted by Benjol on Aug 17at 5:57 "Moving users folder on Windows Vista to another partition - bad idea?" (I can't post one than one link until I earn "10 reputation" and removed my "answer" there to post my follow-up questions here). I am anxiously getting ready at long last to to carry out a clean install (using custom install option) from Vista to Windows-7 Home Premium 64bit with the free upgrade I received late October. For my Vista system I successfully set-up last Summer a multi-partitions scheme with Users and Program Data on a a different partition than the operating system (see link below, and its subsequent links in my comment for details). http://tuts4tech.net/2009/08/05/windows-7-move-the-users-and-program-files-directories-to-a-different-partition/comment-page-1/#comment-562 I was planning a similar set-up for windows 7, a little more streamlined, with OS, Program Files on C:, Users and Program Data on D:, and TV media recording on a separate partition. Reading the Question submitted by Benjol, I am second guessing too. Is moving Users and Program Data on a different partition than the default primary partition with OS and Program Files such a good idea? The couple of people I talked to at the official Microsoft Windows 7 booth at CES 2010 gave the same answer to the intention of moving the Users profile folder to another partition. In a nutshell, they all told me that they used to do this in XP and less in Vista but not anymore with Windows 7... "It is stable, after two months still no problem" I had the feeling it was a scripted answer to emphasize how Windows 7 is so stable and efficient... (Will Windows-7 system not become bugged down over the course of several months to a year or two? Only time will tell) Long story short, I share the same view than Benjol expressed with respect to being "able to backup and restore system and user data independently." I just received a 2TB usb2, eSATA external hard drive as a back-up drive, which includes NTI Shadow 4 (4.1.0.150) for back-up solution. I took note of the issue with NTUSER.DAT and I will read more about Volume Shadow Copy Service (VSS) for Windows 7. I am willing to put the effort if placing Users and Program Data on a different partition would allow to restore a fresher OS+Program image when the system gets bugged down. Questions: Is it such a bad idea? What is the "easy route" referred by Benjol in his post? Is it to just relocate folders to another partition using the Folder property tool? (It is not practical for several users and might not provide a straightforward restore process of just OS and Program Files when needed.) I am starting to learn about Windows 7 libraries. Would Windows 7 libraries be another alternative to achieve this? All this reading to decide how to organize the partition scheme for my custom system is starting to be confusing. I apologize for this lengthy Question. It is my first day here on SuperUser and I am just learning how different from a discussion thread it is. Thank you in advance for all your suggestions and comments. Donat

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  • SQL : where vs. on in join

    - by Erwin
    Perhaps a dumb question, but consider these 2 tables : T1 Store Year 01 2009 02 2009 03 2009 01 2010 02 2010 03 2010 T2 Store 02 Why is this INNER JOIN giving me the results I want (filtering the [year] in the ON clause) : select t1.* from t1 inner join t2 on t1.store = t2.store and t1.[year] = '2009' Store Year 02 2009 And why the LEFT OUTER JOIN include records of year 2010 ? select t1.* from t1 left outer join t2 on t1.store = t2.store and t1.year = '2009' where t2.store is null 01 2009 03 2009 01 2010 02 2010 03 2010 And I have to write the [year] filter in the 'WHERE' clause : select t1.* from t1 left outer join t2 on t1.store = t2.store where t2.store is null and t1.year = '2009' 01 2009 03 2009 Like I said, perhaps a dumb question, but it's bugging me !

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  • SQL: Gather right hand values from a join

    - by Max Williams
    Let's say a question has many tags, via a join table called taggings. I do a join thus: SELECT DISTINCT `questions`.id FROM `questions` LEFT OUTER JOIN `taggings` ON `taggings`.taggable_id = `questions`.id LEFT OUTER JOIN `tags` ON `tags`.id = `taggings`.tag_id I want to order the results according to a particular tag name, eg 'piano', so that piano is at the top, then by all the other tags in alphabetical order. Currently i'm using this order clause: ORDER BY (tags.name = 'piano') desc, tags.name Which is going completely wrong - the first results i get back aren't even tagged with 'piano' at all. I think my problem is that i need to group the tag names somehow and do my ordering test against that: i think that doing it against the straight tags.name isn't working due to the structure of the resultant join table (it does work if i just do a simple select on the tags table) but i can't get my head around how to fix it. grateful for any advice, max

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  • how to mount a partition inside a partition

    - by facha
    Hello, everyone I have a block device (/dev/sda5) that has been partitioned inside by a virtual machine. So, when I look inside with fdisk /dev/sda5, I see: sda5p1 sda5p2 and so on. Is it possible to mount them on my host system? Thanks in advance.

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  • Conditional Join - join 1 tables 2 ways

    - by Jon H
    I have a set of (not very well normalised or relational) tables named PLAN, GROUP, PRODUCT CLIENT Most have linkage i.e. PLAN - CLIENT on clno GROUP to PRODUCT on PRODCD However, the linkage between PLAN and GROUP is tricky. A plan has 2 field of interest GRPNO and PRODCD. What I want to do is if GRPNO != 0 then join GROUP on GRPNO. However if GRPNO = 0 then I want to join GROUP on PRODCD. The frustrating thing is that the fileds I want to return in my queries are the same across the board I just need to be able to vary the join, or join the same table twice. The best I can come up with is 2 queries and merge them using datasets, or possibly using a union. Is there a nifty way to do this in one select? I should point out I am access Foxpro over ODBC to do this. Thank you!

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  • How to add a Linux Partition on FreeBSD

    - by Ömer
    Today I installed FreeBSD 9.0 PPC on my Mac mini G4 with 40GB HDD. During installation, (using the FSBD utility 'gpart') I have allocated a total of about 23GB for FreeBSD leaving 17GB totally free (neither partitioned, nor formatted) for a later Linux installation. Now, when try to install Linux (Ubuntu 10.10 PPC) on the remaining 17GB, the Linux/Ubuntu installer (or Linux's Disk Utility for the same matter) wants presumably a linux partition and when I try to add a (Linux) partition on that area using Linux DU it fails with this message: Error creating partition: helper exited with exit code 1: In part_add_partition: device_file=/dev/hda, start=23363101696, size=16644660224, type= Entering MS-DOS parser (offset=0, size=40007761920) No MSDOS_MAGIC found Exiting MS-DOS parser Entering Apple parser Mac MAGIC found, block_size=512 map_count = 17 Leaving Apple parser Apple partition table detected containing partition table scheme = 2 got it Error: The partition's data region doesn't occupy the entire partition. ped_disk_new() failed Now, I'm trying to add a Linux partition on FreeBSD running on the harddisk. I use seemingly most suitable tool for this job: gpart. Here is the 'gpart show ad0' But it seems unable to add a Linux partition because "man gpart" doesn't list either "Linux Partition" nor anything like Ext2 or Ext3/Ext4. The closest thing to Linux Partition in gpart is "mbr" but it doesn't work: #gpart add -t mbr ado So, how to add properly a Linux Partition on FreeBSD? Thanks.

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  • Checking partition alignment with PowerCLI

    - by Julian
    I'm trying to verify that the file system partitions within each of the servers I'm working on are aligned correctly. I've got the following script that when I've tried running will either claim that all virtual servers are aligned or not aligned based on which if statement I use (one is commented out): $myArr = @() $vms = get-vm | where {$_.PowerState -eq "PoweredOn" -and $_.Guest.OSFullName -match "Microsoft Windows*" } | sort name foreach($vm in $vms){ $wmi = get-wmiobject -class "win32_DiskPartition" -namespace "root\CIMV2" -ComputerName $vm foreach ($partition in $wmi){ $Details = "" | Select-Object VMName, Partition, Status #if (($partition.startingoffset % 65536) -isnot [decimal]){ if ($partition.startingoffSet -eq "65536"){ $Details.VMName = $partition.SystemName $Details.Partition = $partition.Name $Details.Status = "Partition aligned" } else{ $Details.VMName = $partition.SystemName $Details.Partition = $partition.Name $Details.Status = "Partition not aligned" } $myArr += $Details } } $myArr | Export-CSV -NoTypeInformation "C:\users\myself\Documents\Scripts\PartitionAlignment.csv" Would anyone know what is wrong with my code? I'm still learning about partitions so I'm not sure how I need to check the starting off-set number to verify alignment. EDIT: $myArr = @() $vms = get-vm | where {$_.PowerState -eq "PoweredOn" -and $_.Guest.OSFullName -match "Microsoft Windows*" } | sort name $wmi = get-wmiobject -class "win32_DiskPartition" -namespace "root\CIMV2" -ComputerName $vm #foreach ($_ In Get-WMIObject Win32_DiskPartition | Select Name, BlockSize, NumberOfBlocks, StartingOffSet, @{n='Alignment'; e={$_.StartingOffSet/$_.BlockSize}}) {$_} foreach ($wmi| Select Name, BlockSize, NumberOfBlocks, StartingOffSet, @{n='Alignment'; e={$_.StartingOffSet/$_.BlockSize}}) {$_}

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  • SQL: Join multiple tables and get a grouped sum

    - by Scienceprodigy
    I have a database with 3 tables that have related data. One table has transactions, and the other two relate to transaction categories. Basically it's financial data, so each transaction has a category (i.e. "gasoline" for a gas purchase transaction). A short version of my Transactions table looks like this- Transactions Table: ________________________________ | ID | Type | Amount | Category | --------------------------------- I also have two more tables relating a category to a categories parent. So basically, every Category entry in the Transactions Table belongs to a parent category (i.e. "gasoline" would belong to say "Automotive Expenses"). For categories, and their parent, I have two tables - Category Children: ____________________________________________ | ID | Parent Category ID | Child Category | -------------------------------------------- Category Parent: ________________________ | ID | Parent Category | ------------------------ What I'm trying to do is query the database and have it return a total spending by parent category. To get "spending" the Type of transactions must be "Debit". I tried the following statement: SELECT category_parents.parent_category, SUM(amount) AS totals FROM (transactions INNER JOIN category_children ON transactions.category = 'category_children.child_category') INNER JOIN category_parents ON category_children.parent_category_id = category_parents._id WHERE trans_type = 'Debit' GROUP BY parent_category ORDER BY totals DESC but it gives me the following exception: 12-31 13:51:21.515: ERROR/Exception on query(4403): android.database.sqlite.SQLiteException: no such column: category_children.parent_category_id: , while compiling: SELECT category_parents.parent_category, SUM(amount) AS totals FROM (transactions INNER JOIN category_children ON transactions.category='category_children.child_category') INNER JOIN category_parents ON category_children.parent_category_id=category_parents._id where trans_type='Debit' group by parent_category order by totals desc Any help is appreciated. (EXTRA CREDIT: I also need to make another statement to do spending by child category, given the parent category)

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  • Remove Duplicates from LEFT OUTER JOIN

    - by Kaushik Gopal
    Hey folk my question is quite similar to http://stackoverflow.com/questions/757957/restricting-a-left-join I have a variation in that request though and the comment didn't allow too many characters hence posting as a new question. I hope this doesn't go against the posting rules/etiquette. Assuming i have a table SHOP and another table LOCATION. Location is a sort of child table of table SHOP, that has two columns of interest, one is a Division Key (calling it just KEY) and a "SHOP" number. This matches to the Number "NO" in table SHOP. I tried this left outer join: SELECT S.NO, L.KEY FROM SHOP S LEFT OUTER JOIN LOCATN L ON S.NO = L.SHOP But i'm getting a lot of duplicates since there are many locations that belong to a single shop. I want to eliminate them and just get a list of "shop, key" entries without duplicates. any ideas how? (edit: ORACLE 10g Database)

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  • MySQL Dynamicly determine the tabel to use with inner join

    - by user366990
    He guys, I'm stuck with a problem and I hope someone can help me out. I have a date. For example 2009-10-1. This date is used to check in which season I am working. This could be summer or winter. If whe are in the summer the table to use for my inner join whould be 'summer09_rooms'. If winter 'winter09_rooms'. So I basicly whant to do a CASE WHEN in my INNER JOIN. How to accomplish this. The query would look like this: SELECT name, arrival_date, departure_date FROM holliday a INNER JOIN ( CASE when arrival_date BETWEEN 2009-10-1 AND 2009-4-1 THEN summer09_rooms b ELSE winter09_rooms b END ) ON a.dossier=b.dossier Of course this query isn't working but now I hope you'l see what I want to accomplish. Kind regards, Digital Human

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  • Linux DD command partition -to- partition

    - by Ben Jackson
    I just used the DD command to copy the contents of one partition over to another partition on another drive, like this: dd if=/dev/sda2 of=/dev/sdb2 bs=4096 conv=noerror sda2 partition was 66GB and sdb2 was 250GB. I read that by doing this the extra space on the drive I am copying to will be wasted, is this true? I wasn't worried about loosing the extra space for the time being however, I just ran: sudo kill -USR1 (PID) to view the current status of DD and it has written over 66GB of data, will it continue to write data until it gets to 250GB? If so, is there a way to stop the process without corrupting it as waiting for it to write blank space seems like a waste of time.

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