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  • Reference Data Management and Master Data: Are Relation ?

    - by Mala Narasimharajan
    Submitted By:  Rahul Kamath  Oracle Data Relationship Management (DRM) has always been extremely powerful as an Enterprise Master Data Management (MDM) solution that can help manage changes to master data in a way that influences enterprise structure, whether it be mastering chart of accounts to enable financial transformation, or revamping organization structures to drive business transformation and operational efficiencies, or restructuring sales territories to enable equitable distribution of leads to sales teams following the acquisition of new products, or adding additional cost centers to enable fine grain control over expenses. Increasingly, DRM is also being utilized by Oracle customers for reference data management, an emerging solution space that deserves some explanation. What is reference data? How does it relate to Master Data? Reference data is a close cousin of master data. While master data is challenged with problems of unique identification, may be more rapidly changing, requires consensus building across stakeholders and lends structure to business transactions, reference data is simpler, more slowly changing, but has semantic content that is used to categorize or group other information assets – including master data – and gives them contextual value. In fact, the creation of a new master data element may require new reference data to be created. For example, when a European company acquires a US business, chances are that they will now need to adapt their product line taxonomy to include a new category to describe the newly acquired US product line. Further, the cross-border transaction will also result in a revised geo hierarchy. The addition of new products represents changes to master data while changes to product categories and geo hierarchy are examples of reference data changes.1 The following table contains an illustrative list of examples of reference data by type. Reference data types may include types and codes, business taxonomies, complex relationships & cross-domain mappings or standards. Types & Codes Taxonomies Relationships / Mappings Standards Transaction Codes Industry Classification Categories and Codes, e.g., North America Industry Classification System (NAICS) Product / Segment; Product / Geo Calendars (e.g., Gregorian, Fiscal, Manufacturing, Retail, ISO8601) Lookup Tables (e.g., Gender, Marital Status, etc.) Product Categories City à State à Postal Codes Currency Codes (e.g., ISO) Status Codes Sales Territories (e.g., Geo, Industry Verticals, Named Accounts, Federal/State/Local/Defense) Customer / Market Segment; Business Unit / Channel Country Codes (e.g., ISO 3166, UN) Role Codes Market Segments Country Codes / Currency Codes / Financial Accounts Date/Time, Time Zones (e.g., ISO 8601) Domain Values Universal Standard Products and Services Classification (UNSPSC), eCl@ss International Classification of Diseases (ICD) e.g., ICD9 à IC10 mappings Tax Rates Why manage reference data? Reference data carries contextual value and meaning and therefore its use can drive business logic that helps execute a business process, create a desired application behavior or provide meaningful segmentation to analyze transaction data. Further, mapping reference data often requires human judgment. Sample Use Cases of Reference Data Management Healthcare: Diagnostic Codes The reference data challenges in the healthcare industry offer a case in point. Part of being HIPAA compliant requires medical practitioners to transition diagnosis codes from ICD-9 to ICD-10, a medical coding scheme used to classify diseases, signs and symptoms, causes, etc. The transition to ICD-10 has a significant impact on business processes, procedures, contracts, and IT systems. Since both code sets ICD-9 and ICD-10 offer diagnosis codes of very different levels of granularity, human judgment is required to map ICD-9 codes to ICD-10. The process requires collaboration and consensus building among stakeholders much in the same way as does master data management. Moreover, to build reports to understand utilization, frequency and quality of diagnoses, medical practitioners may need to “cross-walk” mappings -- either forward to ICD-10 or backwards to ICD-9 depending upon the reporting time horizon. Spend Management: Product, Service & Supplier Codes Similarly, as an enterprise looks to rationalize suppliers and leverage their spend, conforming supplier codes, as well as product and service codes requires supporting multiple classification schemes that may include industry standards (e.g., UNSPSC, eCl@ss) or enterprise taxonomies. Aberdeen Group estimates that 90% of companies rely on spreadsheets and manual reviews to aggregate, classify and analyze spend data, and that data management activities account for 12-15% of the sourcing cycle and consume 30-50% of a commodity manager’s time. Creating a common map across the extended enterprise to rationalize codes across procurement, accounts payable, general ledger, credit card, procurement card (P-card) as well as ACH and bank systems can cut sourcing costs, improve compliance, lower inventory stock, and free up talent to focus on value added tasks. Change Management: Point of Sales Transaction Codes and Product Codes In the specialty finance industry, enterprises are confronted with usury laws – governed at the state and local level – that regulate financial product innovation as it relates to consumer loans, check cashing and pawn lending. To comply, it is important to demonstrate that transactions booked at the point of sale are posted against valid product codes that were on offer at the time of booking the sale. Since new products are being released at a steady stream, it is important to ensure timely and accurate mapping of point-of-sale transaction codes with the appropriate product and GL codes to comply with the changing regulations. Multi-National Companies: Industry Classification Schemes As companies grow and expand across geographies, a typical challenge they encounter with reference data represents reconciling various versions of industry classification schemes in use across nations. While the United States, Mexico and Canada conform to the North American Industry Classification System (NAICS) standard, European Union countries choose different variants of the NACE industry classification scheme. Multi-national companies must manage the individual national NACE schemes and reconcile the differences across countries. Enterprises must invest in a reference data change management application to address the challenge of distributing reference data changes to downstream applications and assess which applications were impacted by a given change. References 1 Master Data versus Reference Data, Malcolm Chisholm, April 1, 2006.

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  • EJB Lifecycle and Relation to WARs

    - by Adam Tannon
    I've been reading up on EJBs (3.x) and believe I understand the basics. This question is a "call for confirmation" that I have interpreted the Java EE docs correctly and that I understand these fundamental concepts: An EJB is to an App Container as a Web App (WAR) is to a Web Container Just like you deploy a WAR to a Web Container, and that container manages your WAR's life cycle, you deploy an EJB to an App Container, and the container manages your EJB's life cycle When the App Container fires up and deploys an EJB, it is given a unique "identifier" and URL that can be used by JNDI to look up the EJB from another tier (like the web tier) So, when your web app wants to invoke one of your EJB's methods, it looks the EJB up using some kind of service locator (JNDI) and invoke the method that way Am I on-track or way off-base here? Please correct me & clarify for me if any of these are incorrect. Thanks in advance!

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  • What is Perl's relation with hackers?

    - by K.Steff
    I know Perl is a language revered by many hackers (as in hacker vs cracker) and respected by many good programmers for its expressiveness. I also realize it is useful to know and it's very handy at generalizing common Unix tasks (Unix here includes Linux and Cygwin). I also know that being a good hacker probably means you're a good programmer in general (references on this one are sparse around the web, but about everything Paul Graham has ever written seems approving of this statement to me). So my question is whether there is a reason that attracts hackers to Perl in particular? Will learing Perl improve my general programming, problem-solving and hacking skills if done properly? Does it present unique tools that are more useful to a hacker?

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  • Severity and relation to occurence - priority?

    - by user970696
    I have been browsing through some webpages related to testing and found one dealing with the metrics of testing. It says: The severity level of a defect indicates the potential business impact for the end user (business impact = effect on the end user x frequency of occurrence). I do not think think this is correct or what am I missing? Usually it is the priority which is the result of such a calculation (severe bug that occurs rarely is still severe but does not have to be fixed immediately). Also from this description, what is the difference between the effect on the end user and business impact?

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  • What is Perl's relation to hackers? [closed]

    - by K.Steff
    I know Perl is a language revered by many hackers (as in hacker vs cracker) and respected by many good programmers for its expressiveness. I also realize it is useful to know and it's very handy at generalizing common Unix tasks (Unix here includes Linux and Cygwin). I also know that being a good hacker probably means you're a good programmer in general (references on this one are sparse around the web, but about everything Paul Graham has ever written seems approving of this statement to me). So my question is whether there is a reason that attracts hackers to Perl in particular? Will learing Perl improve my general programming, problem-solving and hacking skills if done properly? Does it present unique tools that are more useful to a hacker?

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  • ContactsContract.CommonDataKinds.Relation does not show in Contacts app

    - by Mark R
    I programatically added almost every type of contact field to a contact and they all work except for Relation. Relation types get added to the contacts database, but they don't show up in the Contacts app. I don't see a way to add Relation information through the Contacts GUI for a standard Gmail contact either. Does the Contacts app just not support this data type?

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  • Problem with between join for sqlalchemy orm relation.

    - by Gary van der Merwe
    I'm trying to create a relation that has a between join. Here is a shortish example of what I'm trying to do: #!/usr/bin/env python import sqlalchemy as sa from sqlalchemy import orm from sqlalchemy.engine.base import Engine from sqlalchemy.ext.declarative import declarative_base metadata = sa.MetaData() Base = declarative_base(metadata=metadata) engine = sa.create_engine('sqlite:///:memory:') class Network(Base): __tablename__ = "network" id = sa.Column(sa.Integer, primary_key=True) ip_net_addr_db = sa.Column('ip_net_addr', sa.Integer, index=True) ip_broadcast_addr_db = sa.Column('ip_broadcast_addr', sa.Integer, index=True) # This can be determined from the net address and the net mask, but we store # it in the db so that we can join with the address table. ip_net_mask_len = sa.Column(sa.SmallInteger) class Address(Base): __tablename__ = "address" ip_addr_db = sa.Column('ip_addr', sa.Integer, primary_key=True, index=True, unique=True) Network.addresses = orm.relation(Address, primaryjoin=Address.ip_addr_db.between( Network.ip_net_addr_db, Network.ip_broadcast_addr_db), foreign_keys=[Address.ip_addr_db]) metadata.create_all(engine) Session = orm.sessionmaker(bind=engine) Network() I you run this, you get this error: ArgumentError: Could not determine relation direction for primaryjoin condition 'address.ip_addr BETWEEN network.ip_net_addr AND network.ip_broadcast_addr', on relation Network.addresses. Do the columns in 'foreign_keys' represent only the 'foreign' columns in this join condition ? The answer to that question is Yes, but I cant figure out how to tell it that

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  • PHPMyAdmin: "General relation features: Disabled"

    - by Simón
    I've been looking around for something like this for a while, and I've found some tips on similar issues, but not exactly the same. I really don't know what to do. I downloaded and installed WAMP, and I have a MySQL and PHPMyAdmin setup according to common indications that can be found everywhere (securing MySQL root account, etc.). When I log into PHPMyAdmin (either as root or as pma), I see the following message at the bottom of the page: The additional features for working with linked tables have been deactivated. To find out why click here. And when following the link, got a page with the following: Server: localhost $cfg['Servers'][$i]['pmadb'] ... OK $cfg['Servers'][$i]['relation'] ... OK General relation features: Disabled $cfg['Servers'][$i]['table_info'] ... OK Display Features: Disabled $cfg['Servers'][$i]['table_coords'] ... OK $cfg['Servers'][$i]['pdf_pages'] ... OK Creation of PDFs: Disabled $cfg['Servers'][$i]['column_info'] ... OK Displaying Column Comments: Disabled Bookmarked SQL query: Disabled Browser transformation: Disabled $cfg['Servers'][$i]['history'] ... OK SQL history: Disabled $cfg['Servers'][$i]['designer_coords'] ... OK Designer: Disabled Somebody please explain to me, why the heck if all settings are "OK" the features remain "Disabled"? Note: at first all the settings were "not OK" and I managed to add the settings to config.inc.php, and then created the tables using scripts/create_tables.php. Of course I have already tried restarting the server or clearing the browser cache (several times, so I am sure the problem comes elsewhere).

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  • inverse relation to multiple inheriting classes in django

    - by Ofri Raviv
    Here are my schematic models: class Law(models.Model): ... class Bill(models.Model): ... # data for a proposed law, or change of an existing law class PrivateBill(Bill): ... # data for a Bill that was initiated by a parliament member class GovernmentBill(Bill): ... # data for a Bill that was initiated by the government It is possible and likely that in the future I (or maybe someone else) would want to add more Bill types. Every Bill should point to a Law (indicating what law this bill is going to change) and my question is: What is the best way to implement this? If I add the ForeignKey(Law) to Bill, I'll have a relation from every Bill to Law, but a Law would only have an inverse relation to Bills (bill_set), and not a different inverse relation to each type of bill. Of course I'll be able to filter each type of bill to get only the ones pointing to a specific Law, but this is something I think I'll need to use often, so I think having privatebill_set, governmentbill_set etc would make the code more readable. Another possible solution is to add the foreign key to each of the inheriting classes (this would give me a privatebill_set, governmentbill_set, futurebill_set), but that seems hairy because I would be relying on future programmers to remember to add that relation. How would you solve this?

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  • How to configure Hibernate database reverse engineering tool to map database table relation as a ent

    - by Piotr Kochanski
    Is it possible to configure Hibernate reverse engineering and code generation tool in such a way that one-to-many relation between tables is mapped to entities inheritance instead of enrites relation? I have Person table and Employee table, which are related with the foreign key (Person contains basic information, Employee the rest). In my Java code I would like this relation mapped to inheritance Employee extends Person. This can be done by hand, but maybe I missed some custom configuration parameter that I can use. I couldn't find any official documentation - docs link on RedHat Hibernate page (http://www.hibernate.org/5.html#A10) is broken...

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  • Parent-Child relation while using object data source

    - by Saba
    Hello guys I am experiencing with a class generator I've written, which generates a class for each table in database with each table field as a property and such. Before that, I used to add a typed dataset to the project and add some tables to it. It automatically detected the relationship between tables and when I added a parent table as data source of a datagrid, I could add another datagrid and use the foreing key data member of it's bindingsource to fill it, and when someone moved the focus on parent datagrid, the data in child datagrid would change accordingly. Now that I have my classes, I add an object as data source for my 2 datagrids, but obviously it doesn't detect a parent child relation. But It'd really help if I could have that foreign key relation in my object datasources. Is there any way to have that relation in object datasource?

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  • Rails: Modeling an optional relation in ActiveRecord

    - by Hassinus
    I would like to map a relation between two Rails models, where one side can be optionnal. Let's me be more precise... I have two models: Profile that stores user profile information (name, age,...) and User model that stores user access to the application (email, password,...). To give you more information, User model is handled by Devise gem for signup/signin. Here is the scenario of my app: 1/ When a user register, a new row is created in User table and there is an equivalent in Profile table. This leads to the following script: class User < ActiveRecord::Base belongs_to :profile end 2/ A user can create it's profile without registering (kind of public profile with public information), so a row in Profile doesn't have necessarily a User row equivalent (here is the optional relation, the 0..1 relation in UML). Question: What is the corresponding script to put in class Profile < AR::Base to map optionally with User? Thanks in advance.

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  • Relation between .p7b and .spc digital certificate files

    - by Frederick
    My company have just renewed their digital certificate from Thawte. The previous certificate I was using had an 'spc' extension. The new certificate I've been handed ends in a 'p7b'. Although I can use this p7b file directly for signing, I was just wondering whether there's some way to convert this to an spc file which I can then sign with as I was doing previously. Is it a recommended practice to use p7b directly for signing? Secondly, what exactly is the relation, if any, between the two types of files?

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  • Why do i get a circular reference exception when calling to_json on an ActiveRecord::Relation

    - by midas06
    In Rails 3 (beta 3 on 1.8.7), when calling to_json on a relation i get a circular reference exception. Converting that relation to an array first, and THEN calling to_json works. Code That fails: Model.where().to_json (Where model is any model in your Rails 3 app) Code that works: Model.where().to_a.to_json This can be reproed on the console. Has anyone else run in to this? Is this expected?

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  • Are there known problems with >= and <= and the eval function in JS?

    - by Augier
    I am currently writing a JS rules engine which at one point needs to evaluate boolean expressions using the eval() function. Firstly I construct an equation as such: var equation = "relation.relatedTrigger.previousValue" + " " + relation.operator + " " + "relation.value"; relation.relatedTrigger.previousValue is the value I want to compare. relation.operator is the operator (either "==", "!=", <=, "<", "", ="). relation.value is the value I want to compare with. I then simply pass this string to the eval function and it returns true or false as such: return eval(equation); This works absolutely fine (with words and numbers) or all of the operators except for = and <=. E.g. When evaluating the equation: relation.relatedTrigger.previousValue <= 100 It returns true when previousValue = 0,1,10,100 & all negative numbers but false for everything in between. I would greatly appreciate the help of anyone to either answer my question or to help me find an alternative solution. Regards, Augier. P.S. I don't need a speech on the insecurities of the eval() function. Any value given to relation.relatedTrigger.previousValue is predefined. edit: Here is the full function: function evaluateRelation(relation) { console.log("Evaluating relation") var currentValue; //if multiple values if(relation.value.indexOf(";") != -1) { var values = relation.value.split(";"); for (x in values) { var equation = "relation.relatedTrigger.previousValue" + " " + relation.operator + " " + "values[x]"; currentValue = eval(equation); if (currentValue) return true; } return false; } //if single value else { //Evaluate the relation and get boolean var equation = "relation.relatedTrigger.previousValue" + " " + relation.operator + " " + "relation.value"; console.log("relation.relatedTrigger.previousValue " + relation.relatedTrigger.previousValue); console.log(equation); return eval(equation); } } Answer: Provided by KennyTM below. A string comparison doesn't work. Converting to a numerical was needed.

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  • iphone coredata removing records between two entities connected by relation ship

    - by satyam
    I'm implementing core data in my iphone app. It has two entities. Entity1: LatestData Entity2: LatestDetailedData LatestData has URL, publishedDate, heading LatestDetailedData has URL, NewsDescription, PublishedDate, Author Both entities have same URL for a record. Both the entities are connected with inverse relation ship. And the relation ship is "delete-Cascaded" What I want: If I remove a record in LatestData, I want the record with same URL in LatestDetailedData must also be deleted. How?

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  • A many-to-many relation joined disallows intellisense/lookup in joined table

    - by BerggreenDK
    I want to be able to select a product and retrieve all sub-parts(products) within it. My approach is to find the Product id and then retrieve the list of ProductParts with that as a parent and while fetching those, follow the key back to the Product child to get the name and details of each Part. I was hoping to use something similar to: part.linked_product_id.name I have two tables. One for [Product] and and a relation [ProductPart] that has two FK ID's to [Product] Table Product() { int ID; // (PRIMARY, NOT NULL) String Name; ... details removed for overview purpose... } Table ProductPart() { int Product_ID; // FK (linked with relation to Product/parent) int Part_Product_ID; // FK (linked with relation to Product/childen) ... details removed for overview purpose... } I have checked the SQL-diagram and it shows the two relations (both are one to many) and in my DBML they also looks right. Here is my LINQ to SQL snippet that doesnt work for me... wondering why my joins dont work as supposed. FaultySnippet() { ProductDataContext db = new ProductDataContext(); var list = ( from part in db.ProductParts join prod in db.Products on part.Part_Product_ID equals prod.ID where (part.Product_ID == product_ID) select new { Name = part.Part_Product_ID. ?? // <-- NO details from Joined table? ... rest of properties from ProductPart join... I hoped... } ); }

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  • doctrine findby relation

    - by iggnition
    I'm having trouble selecting a subset of data with doctrine. I have 3 tables Location Contact Contact_location The contact and location tables hold a name and an id the other table holds only ID's. For instance: Location loc_id: 1 name: detroit Contact contact_id: 1 name: Mike Contact_location loc_id: 1 contact_id: 1 In doctrine there is a many to many relation between the location and contact tables with contact_location as the ref_class. What i want to do is on my location page i want to find all contacts where for instance the loc_id = 1. I tried: $this->installedbases = Doctrine::getTable('contact')->findByloc_id(1); hoping doctrine would see the relation and get it, but it does not. How can i make doctrine search in relevant related tables? I read it can be done using Findby but i find the documentation unclear.

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  • When to use memberEnd and when navigableOwnedEnd in an UML class diagram?

    - by Ivan
    I've download a trial of Altova UModel and am starting using UML. As a practical beginning I am modelling a personal information manager application, which includes a web bookmark managing. A Bookmark can belong to many (or no) Tags at once and a Tag can contain many (or no if all the bookmarks it contained were deleted) bookmarks. The relation has to be both-way navigable - a user has to be able to see all Bookmarks with a particular Tags ans all Tags of a Bookmark. What is the correct UML relation between Bookmark and Tag classes? As far as I understand UML now, it is an Association (not an Aggregation). But for a 2-way navigable many-to-many relation I can specify ends roles as "memberEnd" or "when navigableOwnedEnd", graphically the connection looks the same in both cases (an arrow) (which as I understand means navigability) but a property appears in the class box in case only when "memberEnd" is used. How should I specif it in the model If I mean both-way navigable many-to-many relation there?

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  • Relation/Sort not working in rails controller?

    - by Elliot
    I have the following relation in my rails app: genre - has many - authors authors - belong to genre and has many books books - belongs to authors and belongs to users (users can add books to the db) in my controller I have: @books=current_user.books(:include => [:author => :genre], :order => 'created_at DESC') While I am able to use the @books variable in my views - nothing is done correctly (i.e. its not showing me only books added by that user, and its not descending by created_at)... any ideas? -- Also I'm using clearance for the user auth, so current_user without the @ in the controller seems to work fine Actually, I think the relation is working, only the sort might not be working...

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  • When to use memberEnd and when navigableOwnedEnd (in Altova notation) in an UML class diagram?

    - by Ivan
    I've download a trial of Altova UModel and am starting using UML. As a practical beginning I am modelling a personal information manager application, which includes a web bookmark managing. A Bookmark can belong to many (or no) Tags at once and a Tag can contain many (or no if all the bookmarks it contained were deleted) bookmarks. The relation has to be both-way navigable - a user has to be able to see all Bookmarks with a particular Tags ans all Tags of a Bookmark. What is the correct UML relation between Bookmark and Tag classes? As far as I understand UML now, it is an Association (not an Aggregation). But for a 2-way navigable many-to-many relation I can specify ends roles as "memberEnd" or "when navigableOwnedEnd", graphically the connection looks the same in both cases (an arrow) (which as I understand means navigability) but a property appears in the class box in case only when "memberEnd" is used. How should I specif it in the model If I mean both-way navigable many-to-many relation there?

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  • Network ActiveRecord relation with Rails

    - by Zag zag..
    Hi, I have a has and belongs to many relation between User and Article models, and I would like to link them even if an article if not hosted on the same database then a user. For example, If an article exists at foo.com/articles/3 and a user exists at bar.com/users/1, If would like to be able to do from foo.com web interface or bar.com web interface this kind of query: a_user.articles (or an_article.users). I think this can be possible adding a field like "url" in users and articles tables. But I don't know how to process for ActiveRecord. My Article model looks like this: class Article < ActiveRecord::Base has_and_belongs_to_many :users end Is there yet some example of project using this kind of relation over internet? Many thanks

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  • One on One table relation - is it harmful to keep relation in both tables?

    - by EBAGHAKI
    I have 2 tables that their rows have one on one relation.. For you to understand the situation, suppose there is one table with user informations and there is another table that contains a very specific informations and each user can only link to one these specific kind of informations ( suppose second table as characters ) And that character can only assign to the user who grabs it, Is it against the rules of designing clean databases to hold the relation key in both tables? User Table: user_id, name, age, character_id Character Table: character_id, shape, user_id I have to do it for performance, how do you think about it?

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