Search Results

Search found 1102 results on 45 pages for 'recurrence relation'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 7/45 | < Previous Page | 3 4 5 6 7 8 9 10 11 12 13 14  | Next Page >

  • errors with libosmscout [migrated]

    - by Katlego Moukangwe
    I am using the libosmscout library for routing and I get the following error when I run the Routing demo; Routing . 169639811 169639816 169639831 253045594 //Running the routing demo with the map in the current directory. Cannot get start way! There was an error while calculating the route! I think It might be during the import stage since I get the following warnings; !! Cannot resolve way member 28693141 for relation 28322 boundary_administrative Mecklenburg-Vorpommern !! Cannot resolve way member 152675051 for relation 28936 boundary_administrative Bergedorf !! Cannot resolve way member 26496646 for relation 28964 boundary_administrative Harburg (Hamburg) !! Node 323985058 of way 135078286 cannot be joined with any other way of the relation 1817154 Neuenkirchen WW Multipolygon relation 2136137 has conflicting types for outer boundary (place_island vs. boundary_administrative) !! Cannot resolve way member 162656856 for relation 2174826 landuse_forest

    Read the article

  • How is this relation in 4th normal form? Is the dependency trivial?

    - by squ
    I have a question that concerns multi value dependency. The relation looks like this: R(A,B) with A -->> B (A multi value determines B) I've been told that this relation is in 4th normal form, but I don't really se how. I know that if the multi value dependency is trivial, then it doesn't violate the 4th normal form. But is this trivial? It would be trivial if it, for example, looked like this: {A,B} -->> B But the first dependency example shouldn't be trivial. The other rule for 4th NF says that A in this case needs to be a super key of the relation, but it isn't. As far as I can tell, A isn't a super key, since {A,B} is needed to identify a tuple. So the question is, why is this in 4th normal form? It seems to be violating both of the rules.

    Read the article

  • What&rsquo;s wrong with See[Mike]Code? (no relation)

    - by mbcrump
    I have been hearing a lot about the website See[Mike]Code. Basically, the site creates an interview url and a job candidate url and lets you see the potential programmer’s code (specifically .NET developer). Below is the candidate’s URL   Below is the interviewer url   So you might think, ah, this is a good thing. We can screen candidates cheaper and more efficiently. In reality, this is only a good thing if you want your programmer to develop using notepad.  I use the most efficient tools that exist to do my job. I would simply fire up VS2010 and type “for” and hit the tab key twice and get the following template.   I have no problem keeping MSDN/Google in one of my monitors. I spend time learning VS macros and using Aurora XAML/Expression to produce my XAML for WPF. Sure, I can write a for loop without using the VS Macro, but the real question is, “Why should I?”. My point being, if you really want to test a .NET programmer knowledge then fire up his native working environment and let him use the features of the IDE to develop the simple 10-line program. For a more sophisticated program, then give him 20 minutes and allow access to msdn/google. If the programmer cannot find at the right path then give him the boot.

    Read the article

  • What does "enterprise" means in relation to software architecture?

    - by SkonJeet
    I see the term "enterprise" being thrown around software developers and programmers a lot and used loosely it seems. en·ter·prise/'ent?r?priz/ Noun: A project or undertaking, typically one that is difficult or requires effort. Initiative and resourcefulness. Can someone please clarify what this term actually encompasses? "At an enterprise level", "enterprise scale"? There are even "enterprise editions" of things. What exactly does it mean? It obviously doesn't make sense judging by the above definition so more specifically to software what does one mean when using the word enterprise? EDIT: To add a spin on this - how does this term then fit into phrases such as Enterprise Framework Model? What does data access and data context have to do with company-wide descriptions?

    Read the article

  • When is the best time to do self learning in relation with software management?

    - by shankbond
    It all started from here. I have been following Software Estimation: Demystifying the Black Art (Best Practices (Microsoft)). The third chapter says that in Software Management: You cannot give too much time to software developers, if you give it to them, then it is likely that extra time given to them will be filled by some other tasks (in other words, the developers will eat that time :)) Parkinson's Law You can also not squeeze the time from their schedule because if you do that, it is likely that they will develop poor quality product, poor design and will hurt you in the long run, there will be a panic situation and total chaos in the project, lots of rework etc. My question is related to the first point. If you don't give enough time then will the typical software engineer learn his/her skills? The market is always coming with new technologies, you need to learn them. Even with the existing familiar technologies there are always best practices and dos and don'ts.

    Read the article

  • What is the relation between NetworkManager and network service in Fedora/RHEL/Centos?

    - by Patrick L
    Hi I am new to Fedora/Centos/RHEL. I am confused about NetworkManager and network service in these Linux OS. May I know what is the relation between NetworkManager and network service? If I am using NetworkManager, do i need to turn off network service? Similarly, if I am using network service, do I need to turn off NetworkManager? Will they conflict with each other if I use both application at the same time?

    Read the article

  • Do you know any studies on relation of productivity of a programmer and the workstation used?

    - by Tomasz Blachowicz
    I was wondering if there are any studies (formal or not-so-formal) that show correlation between a developer productivity and the workstation used to develop software. It is often heard as argument that the high spec workstations increase the productivity (or the low spec machines impact productivity to the greater extent). To me it sound reasonable, however I'd like to verify the statement with some studies if such exists. Can you help me with that?

    Read the article

  • Do you know any studies on relation of productivity of a programmer and the workstation used?

    - by Tomasz Blachowicz
    I was wondering if there are any studies (formal or not-so-formal) that show correlation between a developer productivity and the workstation used to develop software. It is often heard as argument that the high spec workstations increase the productivity (or the low spec machines impact productivity to the greater extent). To me it sound reasonable, however I'd like to verify the statement with some studies if such exists. Can you help me with that?

    Read the article

  • What's the relation between website's traffic and Google Adsense revenue?

    - by user1592845
    Are there some relations between the website's daily traffic and Google's Adsense revenue? In other word, Suppose the same Ad. will be published on two different websites, the first has average daily traffic 2000 visits while the other has only 100 visits. Does one click on that ad. on the first website will make revenue more than the second website? I've got misunderstand with Google documentation and I need to make a clear idea about this subject.

    Read the article

  • lack of update in xen kernel has any relation to guest operating systems?

    - by austin powers
    Hi , due to these two problems I've coped http://serverfault.com/questions/133578/not-able-to-install-g-and-gcc-on-debian also there is another link but due to my low reputation I couldn't put it through. I just wondering whether the hosted operating system (XEN) has any relation to its guest operating system or not? and when I type uname -r on my VPS it shows : 2.6.18-164.9.1.el5xen where as my installed O/S on my vps is debian 5.04 regards.

    Read the article

  • How do I cluster strings based on a relation between two strings?

    - by Tom Wijsman
    If you don't know WEKA, you can try a theoretical answer. I don't need literal code/examples... I have a huge data set of strings in which I want to cluster the strings to find the most related ones, these could as well be seen as duplicate. I already have a set of couples of string for which I know that they are duplicate to each other, so, now I want to do some data mining on those two sets. The result I'm looking for is a system that would return me the possible most relevant couples of strings for which we don't know yet that they are duplicates, I believe that I need clustering for this, which type? Note that I want to base myself on word occurrence comparison, not on interpretation or meaning. Here is an example of two string of which we know they are duplicate (in our vision on them): The weather is really cold and it is raining. It is raining and the weather is really cold. Now, the following strings also exist (most to least relevant, ignoring stop words): Is the weather really that cold today? Rainy days are awful. I see the sunshine outside. The software would return the following two strings as most relevant, which aren't known to be duplicate: The weather is really cold and it is raining. Is the weather really that cold today? Then, I would mark that as duplicate or not duplicate and it would present me with another couple. How do I go to implement this in the most efficient way that I can apply to a large data set?

    Read the article

  • sqlalchemy: what is the difference between declaring the cascade within the foreign key vs relation?

    - by steve
    what is the difference between declaring the cascade within a foreign key vs relations? class Contact(Base): __tablename__ = 'contacts' id = Column(Integer, primary_key=True) addresses = relation("Address", backref="contact") class Address(Base): __tablename__ = 'addresses' id = Column(Integer, primary_key=True) contact_id = Column(Integer, ForeignKey('contact.id', onupdate="CASCADE", ondelete="CASCADE"))) vs class Contact(Base): __tablename__ = 'contacts' id = Column(Integer, primary_key=True) addresses = relation("Address", backref="contact", cascade="all, delete-orphan") class Address(Base): __tablename__ = 'addresses' id = Column(Integer, primary_key=True) contact_id = Column(Integer, ForeignKey('contact.id')) with the foreign key declaration, it seems like the cascade is enforced at the database level. how does the relations approach work? thanks!

    Read the article

  • How do I specify a null relation in SQLAlchemy?

    - by Jesse
    Not sure what the correct title for this question should be. I have the following schema: Matters have a one-many relationship to WorkItems. WorkItems have a one-one (or one-zero) relationship to LineItems. I am trying to create the following relation between Matters and WorkItems Matter.unbilled_work_items = orm.relation(WorkItem, primaryjoin = (Matter.id == WorkItem.matter_id) and (WorkItem.line_item_id == None), foreign_keys = [WorkItem.matter_id, WorkItem.line_item_id], viewonly=True ) This throws: AttributeError: '_Null' object has no attribute 'table' That seems to be saying that the second clause in the primaryjoin returns an object of type _Null, but it seems to be expecting something with a "table" attribute. This seems like it should be pretty straightforward to me, am I missing something obvious?

    Read the article

  • How do I search for an array of values in a many to many relation?

    - by Kristian Gudal
    Hey I have a problem with my LINQ to Entity model many to mant relation. I am new to both C# and LINQ, so bear with me. I have a model containing pictures and tags, where each picture can have many tags, and each tag can be on many pictures. In the db there is a normal relation table, but in the object model I see it as picture.tags (as a list) and tag.pictures (as a list). A search query contains several tags, and the result of the search is to contain all pictures that are tagged with all the tags (but maybe more) I have searched for. The number of tags to search for is not fixed. How can this best be done?

    Read the article

  • Delete Entity in Many to Many Relation. Don't get error but entity is not deleted

    - by Shapper
    I have, in EF5, two entities: User and Role. Between User and Role there is a many to many relation. I don't have an entity for the UserRoles database which sets the relation. I have a User and I want to delete a role without loading it from the database. Context context = new Context(); User user = context.Users.First(x => x.Id == 4); user.Roles = new List<Role>(); Role role = new Role { Id = 20 }; context.Roles.Attach(role); user.Roles.Remove(role); context.SaveChanges(); I don't get any error but the role is not removed. Any idea why? Thank you, Miguel

    Read the article

  • Why can't I save my model with a generic relation twice in Django?

    - by e-satis
    I got a model TrackedItem with a generic relation linking to any model it is supposed to track. If I do that: t = TrackedItem(content_object=MyModel) t.save() t.save() I get : IntegrityError: (1062, "Duplicate entry '1' for key 'PRIMARY'") Indeed, the first save has created an entry with "1" as a PK. But the second save should not insert, it should update. How am I suppose to update a model I can't save twice? With an ordinary model I can save as much as I want.

    Read the article

  • Can a problem have a relation of aggregation and composition both between two classes at same point

    - by learner
    Can a problem have a relation of aggregation and composition both between two classes at same point of time? Like any real time scenario where there can be aggregation corresponding to one method and composition related to other method. I m unable to figure out any scenario where both composition and aggregation occurs simultaneously between two classes. Any help will be appreciable.

    Read the article

  • JAXB: How to avoid repeated namespace definition for xmlns:xsi

    - by sfussenegger
    I have a JAXB setup where I use a @XmlJavaTypeAdapter to replace objects of type Person with objects of type PersonRef that only contains the person's UUID. This works perfectly fine. However, the generated XML redeclares the same namespace (xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance") every time it's used. While this is generally okay, it just doesn't feel right. How can I configure JAXB to declare xmlns:xsi at the very beginning of the document? Can I manually add namespace declarations to the root element? Here's an example of what I want to achive: Current: <person uuid="6ec0cf24-e880-431b-ada0-a5835e2a565a"> <relation type="CHILD"> <to xsi:type="personRef" uuid="56a930c0-5499-467f-8263-c2a9f9ecc5a0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"/> </relation> <relation type="CHILD"> <to xsi:type="personRef" uuid="6ec0cf24-e880-431b-ada0-a5835e2a565a" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"/> </relation> <!-- SNIP: some more relations --> </person> Wanted: <person uuid="6ec0cf24-e880-431b-ada0-a5835e2a565a" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <relation type="CHILD"> <to xsi:type="personRef" uuid="56a930c0-5499-467f-8263-c2a9f9ecc5a0"/> </relation> <relation type="CHILD"> <to xsi:type="personRef" uuid="6ec0cf24-e880-431b-ada0-a5835e2a565a"/> </relation> <!-- SNIP: some more relations --> </person>

    Read the article

  • Composite primary keys in N-M relation or not?

    - by BerggreenDK
    Lets say we have 3 tables (actually I have 2 at the moment, but this example might illustrate the thought better): [Person] ID: int, primary key Name: nvarchar(xx) [Group] ID: int, primary key Name: nvarchar(xx) [Role] ID: int, primary key Name: nvarchar(xx) [PersonGroupRole] Person_ID: int, PRIMARY COMPOSITE OR NOT? Group_ID: int, PRIMARY COMPOSITE OR NOT? Role_ID: int, PRIMARY COMPOSITE OR NOT? Should any of the 3 ID's in the relation PersonGroupRole be marked as PRIMARY key or should they all 3 be combined into one composite?? whats the real benefit of doing it or not? I can join anyways as far as I know, so Person JOIN PersonGroupRole JOIN Group gives me which persons are in which Groups etc. I will be using LINQ/C#/.NET on top of SQL-express and SQL-server, so if there is any reasons regarding language/SQL that might make the choice more clear, thats the platform I ask about. Looking forward to see what answers pops up, as I have thought of these primary keys/indexes many times when making combined ones.

    Read the article

  • what is the relation between actual pixels and html(css) pixels in blackberry?

    - by HelpMeToHelpYou
    I am implementing one phonegap application. here everything going fine but when i am talking device specifications like 1)BlackBerry Bold Touch 9900 Screen specifications are as following Body Dimensions 115 x 66 x 10.5 mm (4.53 x 2.60 x 0.41 in) Weight 130 g (4.59 oz) Keyboard QWERTY Display Type TFT capacitive touchscreen, 16M colors Size 640 x 480 pixels, 2.8 inches (~286 ppi pixel density) But when i test following function in java script function findScreenSize() { alert("width:"+window.innerWidth +"Height:"+ window.innerHeight); } it displaying SIZE width : 356 Height : 267 (356 x 267) 2)BlackBerry Bold Touch 9930 Screen specifications are as following Body Dimensions 115 x 66 x 10.5 mm (4.53 x 2.60 x 0.41 in) Weight 130 g (4.59 oz) Keyboard QWERTY - Touch-sensitive controls Display Type TFT capacitive touchscreen, 16M colors Size 640 x 480 pixels, 2.8 inches (~286 ppi pixel density) then i run same javaScript function i got following output it displaying SIZE width : 417 Height : 313 (417 x 313) why it is behaving like this ? Can anybody know relation between core pixel and HTML pixel please give answer

    Read the article

  • How to check if two records have a self-referencing relation?

    - by Machine
    Consider the following schema with users and their collegues (friends): Users User: columns: user_id: name: user_id as userId type: integer(8) unsigned: 1 primary: true autoincrement: true first_name: name: first_name as firstName type: string(45) notnull: true last_name: name: last_name as lastName type: string(45) notnull: true email: type: string(45) notnull: true unique: true relations: Collegues: class: User local: invitor foreign: invitee refClass: CollegueStatus equal: true onDelete: CASCADE onUpdate: CASCADE Join table: CollegueStatus: columns: invitor: type: integer(8) unsigned: 1 primary: true invitee: type: integer(8) unsigned: 1 primary: true status: type: enum(8) values: [pending, accepted, denied] default: pending notnull: true Now, let's say I two records, one for the user making a HTTP request (the logged in user), and one record for a user he wants to send a message to. I want to check if these users are collegues. Questions: Does Doctrine have any pre-build functionality to check if two records with with self-relations are related? If not, how would you write a method to check this? Where would you put said method? (In the User-class, UserTable-class etc) I could probably do something like this: public function (User $user1, User $user2) { // Ensure we load collegues if $user1 was fetched with DQL that // doesn't load this relation $collegues = $user1->get('Collegues'); $areCollegues = false; foreach($collegues as $collegue) { if($collegue['userId'] === $user2['userId']) { $areCollegues = true; break; } } return $areCollegues; } But this looks a neither efficient nor pretty. I just feel that it should be solved already for self-referencing relations to be nice to use.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 3 4 5 6 7 8 9 10 11 12 13 14  | Next Page >