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  • Quick, beginner MASM register question - DX:AX

    - by Francisco P.
    Hello, I am currently studying for an exam I'll have on x86 assembly. I didn't have much luck googling for ":", too common of a punctuation mark :/ IDIV - Signed Integer Division Usage: IDIV src Modifies flags: (AF,CF,OF,PF,SF,ZF undefined) Signed binary division of accumulator by source. If source is a byte value, AX is divided by "src" and the quotient is stored in AL and the remainder in AH. If source is a word value, DX:AX is divided by "src", and the quotient is stored in AL and the remainder in DX. Taken from "Intel Opcodes and Mnemonics" What does DX:AX mean? Thanks a lot for your time :)

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  • Recognizing when to use the mod operator

    - by Will
    I have a quick question about the mod operator. I know what it does; it calculates the remainder of a division. My question is, how can I identify a situation where I would need to use the mod operator? I know I can use the mod operator to see whether a number is even or odd and prime or composite, but that's about it. I don't often think in terms of remainders. I'm sure the mod operator is useful and I would like to learn to take advantage of it. I just have problems identifying where the mod operator is applicable. In various programming situations, it is difficult for me to see a problem and realize "hey! the remainder of division would work here!" Any tips or strategies? Thanks

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  • Microsoft SQL 2005 - using the modulo operator

    - by cc0
    So I have a silly problem, I have not used much MSSQL before, or any SQL for that matter. I basically have a minor mathematical problem that I need solved, and I thought modulo would be good. I have a number of dates in the database, but I need them be rounded off to the closest [dynamic integer] (could be anything from 0 to 5000000) which will be input as a parameter each time this query is called. So I thought I'd use modulo to find the remainder, then subtract that remainder from the date. If there is a better way, or an integrated function, please let me know! What would be the syntax for that? I've tried a lot of things, but I keep getting error messages like integers/floats/decimals can't be used with the modulo operators. I tried casting to all kinds of numeric datatypes. Any help would be appreciated.

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  • How to interpolate hue values in HSV colour space?

    - by nick
    Hi, I'm trying to interpolate between two colours in HSV colour space to produce a smooth colour gradient. I'm using a linear interpolation, eg: h = (1 - p) * h1 + p * h2 s = (1 - p) * s1 + p * s2 v = (1 - p) * v1 + p * v2 (where p is the percentage, and h1, h2, s1, s2, v1, v2 are the hue, saturation and value components of the two colours) This produces a good result for s and v but not for h. As the hue component is an angle, the calculation needs to work out the shortest distance between h1 and h2 and then do the interpolation in the right direction (either clockwise or anti-clockwise). What formula or algorithm should I use? EDIT: By following Jack's suggestions I modified my JavaScript gradient function and it works well. For anyone interested, here's what I ended up with: // create gradient from yellow to red to black with 100 steps var gradient = hsbGradient(100, [{h:0.14, s:0.5, b:1}, {h:0, s:1, b:1}, {h:0, s:1, b:0}]); function hsbGradient(steps, colours) { var parts = colours.length - 1; var gradient = new Array(steps); var gradientIndex = 0; var partSteps = Math.floor(steps / parts); var remainder = steps - (partSteps * parts); for (var col = 0; col < parts; col++) { // get colours var c1 = colours[col], c2 = colours[col + 1]; // determine clockwise and counter-clockwise distance between hues var distCCW = (c1.h >= c2.h) ? c1.h - c2.h : 1 + c1.h - c2.h; distCW = (c1.h >= c2.h) ? 1 + c2.h - c1.h : c2.h - c1.h; // ensure we get the right number of steps by adding remainder to final part if (col == parts - 1) partSteps += remainder; // make gradient for this part for (var step = 0; step < partSteps; step ++) { var p = step / partSteps; // interpolate h var h = (distCW <= distCCW) ? c1.h + (distCW * p) : c1.h - (distCCW * p); if (h < 0) h = 1 + h; if (h > 1) h = h - 1; // interpolate s, b var s = (1 - p) * c1.s + p * c2.s; var b = (1 - p) * c1.b + p * c2.b; // add to gradient array gradient[gradientIndex] = {h:h, s:s, b:b}; gradientIndex ++; } } return gradient; }

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  • Microsoft SQL Server 2005 - using the modulo operator

    - by cc0
    So I have a silly problem, I have not used much SQL Server before, or any SQL for that matter. I basically have a minor mathematical problem that I need solved, and I thought modulo would be good. I have a number of dates in the database, but I need them be rounded off to the closest [dynamic integer] (could be anything from 0 to 5000000) which will be input as a parameter each time this query is called. So I thought I'd use modulo to find the remainder, then subtract that remainder from the date. If there is a better way, or an integrated function, please let me know! What would be the syntax for that? I've tried a lot of things, but I keep getting error messages like integers/floats/decimals can't be used with the modulo operators. I tried casting to all kinds of numeric datatypes. Any help would be appreciated.

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  • Django how to handle # in variable name.

    - by Jack
    I've got a dictionary in python which is assigned as a template variable. One of the keys is named "#text" but when i try to access it using {{ artist.image.3."#text"}} I get an error which is File "/home/jack/Desktop/test/appengine/lib/django/django/template/__init__.py", line 558, in __init__ raise TemplateSyntaxError, "Could not parse the remainder: %s" % token[upto:] TemplateSyntaxError: Could not parse the remainder: "#text" So how can I use this in the template? I've tried putting quotes around it but to no avail. I'd like to not modify the dictionary if possible, but if its easy enough to do then I guess its okay. Thanks

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  • To "null" or not to "null" my class's attributes

    - by Helper Method
    When I write a class in Java, I like to initialize the attributes which are set to a default value directly and attributes which are set by the caller in the constructor, something like this: public class Stack<E> { private List<E> list; private size = 0; public Stack(int initialCapacity) { list = new ArrayList<E>(initialCapacity); } // remainder omitted } Now suppose I have a Tree class: public class Tree<E> { private Node<E> root = null; // no constructor needed, remainder omitted } Shall I set the root attribute to null, to mark that it is set to null by default, or omit the null value?

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  • SQL SERVER – Various Leap Year Logics

    - by pinaldave
    Earlier I wrote one article on Leap Year and created one video about Leap Year. My point of view was to demonstrate how we can use SQL Server 2012 features to identify Leap year. How ever during the conversation I had some really good conversation. Here are updates for those who have missed reading the excellent comments on the blog. Incorrect Logic There are so many people still think Leap Year is the event which is consistently happening at every four year and the way to find it is divide the year with 4 and if the remainder is 0. That year is leap year. Well, it is not correct. Comment by David Bridge Check out this excerpt from wikipedia page http://en.wikipedia.org/wiki/Leap_year “most years that are evenly divisible by 4 are leap years…” “…Some exceptions to this rule are required since the duration of a solar year is slightly less than 365.25 days. Years that are evenly divisible by 100 are not leap years, unless they are also evenly divisible by 400, in which case they are leap years. For example, 1600 and 2000 were leap years, but 1700, 1800 and 1900 were not. Similarly, 2100, 2200, 2300, 2500, 2600, 2700, 2900 and 3000 will not be leap years, but 2400 and 2800 will be.” If you use logic of divide by 4 and remainder is 0 to find leap year, you will may end up with inaccurate result. The correct way to identify the year is to figure out the days of February and if the count is 29, the year is for sure leap year. Valid Alternate Solutions Comment by sainswor99insworth IIF((@Year%4=0 AND @Year%100 != 0) OR @Year%400=0, 1,0) Comment by Madhivanan Madhivanan has written a blog post about an year ago where he listed multiple ways to find leap year. Comment by Jayan DECLARE @year INT SET @year = 2012 IF (((@year % 4 = 0) AND (@year % 100 != 0)) OR (@year % 400 = 0)) PRINT ’1' ELSE print ’0' Comment by David DECLARE @Year INT = 2012 SELECT ISDATE('2/29/' + CAST(@Year AS CHAR(4))) Comment by David Bridge Incidentally – Another approach would be to take one day off March 1st and see if it is 29. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: PostADay, SQL, SQL Authority, SQL DateTime, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • Help with this optimization

    - by Milo
    Here is what I do: I have bitmaps which I draw into another bitmap. The coordinates are from the center of the bitmap, thus on a 256 by 256 bitmap, an object at 0.0,0.0 would be drawn at 128,128 on the bitmap. I also found the furthest extent and made the bitmap size 2 times the extent. So if the furthest extent is 200,200 pixels, then the bitmap's size is 400,400. Unfortunately this is a bit inefficient. If a bitmap needs to be drawn at 500,500 and the other one at 300,300, then the target bitmap only needs to be 200,200 in size. I cannot seem to find a correct way to draw in the components correctly with a reduced size. I figure out the target bitmap size like this: float AvatarComposite::getFloatWidth(float& remainder) const { float widest = 0.0f; float widestNeg = 0.0f; for(size_t i = 0; i < m_components.size(); ++i) { if(m_components[i].getSprite() == NULL) { continue; } float w = m_components[i].getX() + ( ((m_components[i].getSprite()->getWidth() / 2.0f) * m_components[i].getScale()) / getWidthToFloat()); float wn = m_components[i].getX() - ( ((m_components[i].getSprite()->getWidth() / 2.0f) * m_components[i].getScale()) / getWidthToFloat()); if(w > widest) { widest = w; } if(wn > widest) { widest = wn; } if(w < widestNeg) { widestNeg = w; } if(wn < widestNeg) { widestNeg = wn; } } remainder = (2 * widest) - (widest - widestNeg); return widest - widestNeg; } And here is how I position and draw the bitmaps: int dw = m_components[i].getSprite()->getWidth() * m_components[i].getScale(); int dh = m_components[i].getSprite()->getHeight() * m_components[i].getScale(); int cx = (getWidth() + (m_remainderX * getWidthToFloat())) / 2; int cy = (getHeight() + (m_remainderY * getHeightToFloat())) / 2; cx -= m_remainderX * getWidthToFloat(); cy -= m_remainderY * getHeightToFloat(); int dx = cx + (m_components[i].getX() * getWidthToFloat()) - (dw / 2); int dy = cy + (m_components[i].getY() * getHeightToFloat()) - (dh / 2); g->drawScaledSprite(m_components[i].getSprite(),0.0f,0.0f, m_components[i].getSprite()->getWidth(),m_components[i].getSprite()->getHeight(),dx,dy, dw,dh,0); I basically store the difference between the original 2 * longest extent bitmap and the new optimized one, then I translate by that much which I would think would cause me to draw correctly but then some of the components look cut off. Any insight would help. Thanks

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  • Add multiple payment options in Google Product feed XML

    - by crmpicco
    In my Google Product feed I have both Visa and MasterCard listed as accepted payment methods. Is it possible, and is there any benefit, in adding the remainder of my payment options; American Express, Delta, Maestro etc. <g:payment_accepted>Visa</g:payment_accepted> <g:payment_accepted>MasterCard</g:payment_accepted> I can't find anything in the specification that mentions the payment methods. My feed applies to the UK, US and EU.

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  • Konsole's user interface changes

    <B>Sascha's Hideout:</B> "Konsole does a brilliant job at being a terminal emulator but it doesn't follow user interface standards set by the majority of KDE apps very well. The remainder of this post is mostly about the menu bar and popup menus."

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  • php split array into smaller even arrays

    - by SoulieBaby
    I have a function that is supposed to split my array into smaller, evenly distributed arrays, however it seems to be duplicating my data along the way. If anyone can help me out that'd be great. Here's the original array: Array ( [0] => stdClass Object ( [bid] => 42 [name] => Ray White Mordialloc [imageurl] => sp_raywhite.gif [clickurl] => http://www.raywhite.com/ ) [1] => stdClass Object ( [bid] => 48 [name] => Beachside Osteo [imageurl] => sp_beachside.gif [clickurl] => http://www.beachsideosteo.com.au/ ) [2] => stdClass Object ( [bid] => 53 [name] => Carmotive [imageurl] => sp_carmotive.jpg [clickurl] => http://www.carmotive.com.au/ ) [3] => stdClass Object ( [bid] => 51 [name] => Richmond and Bennison [imageurl] => sp_richmond.jpg [clickurl] => http://www.richbenn.com.au/ ) [4] => stdClass Object ( [bid] => 50 [name] => Letec [imageurl] => sp_letec.jpg [clickurl] => www.letec.biz ) [5] => stdClass Object ( [bid] => 39 [name] => Main Street Mordialloc [imageurl] => main street cafe.jpg [clickurl] => ) [6] => stdClass Object ( [bid] => 40 [name] => Ripponlea Mitsubishi [imageurl] => sp_mitsubishi.gif [clickurl] => ) [7] => stdClass Object ( [bid] => 34 [name] => Adrianos Pizza & Pasta [imageurl] => sp_adrian.gif [clickurl] => ) [8] => stdClass Object ( [bid] => 59 [name] => Pure Sport [imageurl] => sp_psport.jpg [clickurl] => http://www.puresport.com.au/ ) [9] => stdClass Object ( [bid] => 33 [name] => Two Brothers [imageurl] => sp_2brothers.gif [clickurl] => http://www.2brothers.com.au/ ) [10] => stdClass Object ( [bid] => 52 [name] => Mordialloc Travel and Cruise [imageurl] => sp_morditravel.jpg [clickurl] => http://www.yellowpages.com.au/vic/mordialloc/mordialloc-travel-cruise-13492525-listing.html ) [11] => stdClass Object ( [bid] => 57 [name] => Southern Suburbs Physiotherapy Centre [imageurl] => sp_sspc.jpg [clickurl] => http://www.sspc.com.au ) [12] => stdClass Object ( [bid] => 54 [name] => PPM Builders [imageurl] => sp_ppm.jpg [clickurl] => http://www.hotfrog.com.au/Companies/P-P-M-Builders ) [13] => stdClass Object ( [bid] => 36 [name] => Big River [imageurl] => sp_bigriver.gif [clickurl] => ) [14] => stdClass Object ( [bid] => 35 [name] => Bendigo Bank Parkdale / Mentone East [imageurl] => sp_bendigo.gif [clickurl] => http://www.bendigobank.com.au ) [15] => stdClass Object ( [bid] => 56 [name] => Logical Services [imageurl] => sp_logical.jpg [clickurl] => ) [16] => stdClass Object ( [bid] => 58 [name] => Dicount Lollie Shop [imageurl] => new dls logo.jpg [clickurl] => ) [17] => stdClass Object ( [bid] => 46 [name] => Patterson Securities [imageurl] => cmyk patersons_withtag.jpg [clickurl] => ) [18] => stdClass Object ( [bid] => 44 [name] => Mordialloc Personal Trainers [imageurl] => sp_mordipt.gif [clickurl] => # ) [19] => stdClass Object ( [bid] => 37 [name] => Mordialloc Cellar Door [imageurl] => sp_cellardoor.gif [clickurl] => ) [20] => stdClass Object ( [bid] => 41 [name] => Print House Graphics [imageurl] => sp_printhouse.gif [clickurl] => ) [21] => stdClass Object ( [bid] => 55 [name] => 360South [imageurl] => sp_360.jpg [clickurl] => ) [22] => stdClass Object ( [bid] => 43 [name] => Systema [imageurl] => sp_systema.gif [clickurl] => ) [23] => stdClass Object ( [bid] => 38 [name] => Lowe Financial Group [imageurl] => sp_lowe.gif [clickurl] => http://lowefinancial.com/ ) [24] => stdClass Object ( [bid] => 49 [name] => Kim Reed Conveyancing [imageurl] => sp_kimreed.jpg [clickurl] => ) [25] => stdClass Object ( [bid] => 45 [name] => Mordialloc Sporting Club [imageurl] => msc logo.jpg [clickurl] => ) ) Here's the php function which is meant to split the array: function split_array($array, $slices) { $perGroup = floor(count($array) / $slices); $Remainder = count($array) % $slices ; $slicesArray = array(); $i = 0; while( $i < $slices ) { $slicesArray[$i] = array_slice($array, $i * $perGroup, $perGroup); $i++; } if ( $i == $slices ) { if ($Remainder > 0 && $Remainder < $slices) { $z = $i * $perGroup +1; $x = 0; while ($x < $Remainder) { $slicesRemainderArray = array_slice($array, $z, $Remainder+$x); $remainderItems = array_merge($slicesArray[$x],$slicesRemainderArray); $slicesArray[$x] = $remainderItems; $x++; $z++; } } }; return $slicesArray; } Here's the result of the split (it somehow duplicates items from the original array into the smaller arrays): Array ( [0] => Array ( [0] => stdClass Object ( [bid] => 57 [name] => Southern Suburbs Physiotherapy Centre [imageurl] => sp_sspc.jpg [clickurl] => http://www.sspc.com.au ) [1] => stdClass Object ( [bid] => 35 [name] => Bendigo Bank Parkdale / Mentone East [imageurl] => sp_bendigo.gif [clickurl] => http://www.bendigobank.com.au ) [2] => stdClass Object ( [bid] => 38 [name] => Lowe Financial Group [imageurl] => sp_lowe.gif [clickurl] => http://lowefinancial.com/ ) [3] => stdClass Object ( [bid] => 39 [name] => Main Street Mordialloc [imageurl] => main street cafe.jpg [clickurl] => ) [4] => stdClass Object ( [bid] => 48 [name] => Beachside Osteo [imageurl] => sp_beachside.gif [clickurl] => http://www.beachsideosteo.com.au/ ) [5] => stdClass Object ( [bid] => 33 [name] => Two Brothers [imageurl] => sp_2brothers.gif [clickurl] => http://www.2brothers.com.au/ ) [6] => stdClass Object ( [bid] => 40 [name] => Ripponlea Mitsubishi [imageurl] => sp_mitsubishi.gif [clickurl] => ) ) [1] => Array ( [0] => stdClass Object ( [bid] => 44 [name] => Mordialloc Personal Trainers [imageurl] => sp_mordipt.gif [clickurl] => # ) [1] => stdClass Object ( [bid] => 41 [name] => Print House Graphics [imageurl] => sp_printhouse.gif [clickurl] => ) [2] => stdClass Object ( [bid] => 39 [name] => Main Street Mordialloc [imageurl] => main street cafe.jpg [clickurl] => ) [3] => stdClass Object ( [bid] => 48 [name] => Beachside Osteo [imageurl] => sp_beachside.gif [clickurl] => http://www.beachsideosteo.com.au/ ) [4] => stdClass Object ( [bid] => 33 [name] => Two Brothers [imageurl] => sp_2brothers.gif [clickurl] => http://www.2brothers.com.au/ ) [5] => stdClass Object ( [bid] => 40 [name] => Ripponlea Mitsubishi [imageurl] => sp_mitsubishi.gif [clickurl] => ) ) [2] => Array ( [0] => stdClass Object ( [bid] => 56 [name] => Logical Services [imageurl] => sp_logical.jpg [clickurl] => ) [1] => stdClass Object ( [bid] => 43 [name] => Systema [imageurl] => sp_systema.gif [clickurl] => ) [2] => stdClass Object ( [bid] => 48 [name] => Beachside Osteo [imageurl] => sp_beachside.gif [clickurl] => http://www.beachsideosteo.com.au/ ) [3] => stdClass Object ( [bid] => 33 [name] => Two Brothers [imageurl] => sp_2brothers.gif [clickurl] => http://www.2brothers.com.au/ ) [4] => stdClass Object ( [bid] => 40 [name] => Ripponlea Mitsubishi [imageurl] => sp_mitsubishi.gif [clickurl] => ) ) [3] => Array ( [0] => stdClass Object ( [bid] => 53 [name] => Carmotive [imageurl] => sp_carmotive.jpg [clickurl] => http://www.carmotive.com.au/ ) [1] => stdClass Object ( [bid] => 45 [name] => Mordialloc Sporting Club [imageurl] => msc logo.jpg [clickurl] => ) [2] => stdClass Object ( [bid] => 33 [name] => Two Brothers [imageurl] => sp_2brothers.gif [clickurl] => http://www.2brothers.com.au/ ) [3] => stdClass Object ( [bid] => 40 [name] => Ripponlea Mitsubishi [imageurl] => sp_mitsubishi.gif [clickurl] => ) ) [4] => Array ( [0] => stdClass Object ( [bid] => 59 [name] => Pure Sport [imageurl] => sp_psport.jpg [clickurl] => http://www.puresport.com.au/ ) [1] => stdClass Object ( [bid] => 54 [name] => PPM Builders [imageurl] => sp_ppm.jpg [clickurl] => http://www.hotfrog.com.au/Companies/P-P-M-Builders ) [2] => stdClass Object ( [bid] => 40 [name] => Ripponlea Mitsubishi [imageurl] => sp_mitsubishi.gif [clickurl] => ) ) [5] => Array ( [0] => stdClass Object ( [bid] => 46 [name] => Patterson Securities [imageurl] => cmyk patersons_withtag.jpg [clickurl] => ) [1] => stdClass Object ( [bid] => 34 [name] => Adriano's Pizza & Pasta [imageurl] => sp_adrian.gif [clickurl] => # ) ) [6] => Array ( [0] => stdClass Object ( [bid] => 55 [name] => 360South [imageurl] => sp_360.jpg [clickurl] => ) [1] => stdClass Object ( [bid] => 37 [name] => Mordialloc Cellar Door [imageurl] => sp_cellardoor.gif [clickurl] => ) ) [7] => Array ( [0] => stdClass Object ( [bid] => 49 [name] => Kim Reed Conveyancing [imageurl] => sp_kimreed.jpg [clickurl] => ) [1] => stdClass Object ( [bid] => 58 [name] => Dicount Lollie Shop [imageurl] => new dls logo.jpg [clickurl] => ) ) [8] => Array ( [0] => stdClass Object ( [bid] => 51 [name] => Richmond and Bennison [imageurl] => sp_richmond.jpg [clickurl] => http://www.richbenn.com.au/ ) [1] => stdClass Object ( [bid] => 52 [name] => Mordialloc Travel and Cruise [imageurl] => sp_morditravel.jpg [clickurl] => http://www.yellowpages.com.au/vic/mordialloc/mordialloc-travel-cruise-13492525-listing.html ) ) [9] => Array ( [0] => stdClass Object ( [bid] => 50 [name] => Letec [imageurl] => sp_letec.jpg [clickurl] => www.letec.biz ) [1] => stdClass Object ( [bid] => 36 [name] => Big River [imageurl] => sp_bigriver.gif [clickurl] => ) ) ) ^^ As you can see there are duplicates from the original array in the newly created smaller arrays. I thought I could remove the duplicates using a multi-dimensional remove duplicate function but that didn't work. I'm guessing my problem is in the array_split function. Any suggestions? :)

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  • Better viewing of postfix mail queue files than postcat?

    - by Geekman
    So I got a call early this morning about a client needing to see what email they have waiting to be delivered sitting in our secondary mail server. Their link for the main server had (still is) been down for two days and they needed to see their email. So I wrote up a quick perl script to use mailq in combination with postcat to dump each email for their address into separate files, tar'd it up and sent it off. Horrible code, I know, but it was urgent. My solution works OK in that it at least gives a raw view, but I thought tonight it would be nice if I had a solution where I could provide their email attachments and maybe remove some "garbage" header text as well. Most of the important emails seem to have a PDF or similar attached. I've been looking around but the only method of viewing queue files I can see is the postcat command, and I really don't want to write my own parser - so I was wondering if any of you have already done so, or know of a better command to use? Here's the code for my current solution: #!/usr/bin/perl $qCmd="mailq | grep -B 2 \"someemailaddress@isp\" | cut -d \" \" -f 1"; @data = split(/\n/, `$qCmd`); $i = 0; foreach $line (@data) { $i++; $remainder = $i % 2; if ($remainder == 0) { next; } if ($line =~ /\(/ || $line =~ /\n/ || $line eq "") { next; } print "Processing: " . $line . "\n"; `postcat -q $line > $line.email.txt`; $subject=`cat $line.email.txt | grep "Subject:"`; #print "SUB" . $subject; #`cat $line.email.txt > \"$subject.$line.email.txt\"`; } Any advice appreciated.

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  • Python IOError: Not a gzipped file (Gzip and Blowfish Encrypt/Compress)

    - by notbad.jpeg
    I'm having some problems with python's built-in library gzip. Looked through almost every other stack question about it, and none of them seem to work. MY PROBLEM IS THAT WHEN I TRY TO DECOMPRESS I GET THE IOError I'm Getting: Traceback (most recent call last): File "mymodule.py", line 61, in return gz.read() File "/usr/lib/python2.7/gzip.py", line 245, readself._read(readsize) File "/usr/lib/python2.7/gzip.py", line 287, in _readself._read_gzip_header() File "/usr/lib/python2.7/gzip.py", line 181, in _read_gzip_header raise IOError, 'Not a gzipped file'IOError: Not a gzipped file This is my code to send it over SMB, it might not make sense why i do things, but it's normally in a while loop and memory efficient, I just simplified it. buffer = cStringIO.StringIO(output) #output is from a subprocess call small_buffer = cStringIO.StringIO() small_string = buffer.read() #need a string to write to buffer gzip_obj = gzip.GzipFile(fileobj=small_buffer,compresslevel=6, mode='wb') gzip_obj.write(small_string) compressed_str = small_buffer.getvalue() blowfish = Blowfish.new('abcd', Blowfish.MODE_ECB) remainder = '|'*(8 - (len(compressed_str) % 8)) compressed_str += remainder encrypted = blowfish.encrypt(compressed_str) #i send it over smb, then retrieve it later Then this is the code that retrieves it: #buffer is a cStringIO object filled with data from smb retrieval decrypter = Blowfish.new('abcd', Blowfish.MODE_ECB) value = buffer.getvalue() decrypted = decrypter.decrypt(value) buff = cStringIO.StringIO(decrypted) buff.seek(0) gz = gzip.GzipFile(fileobj=buff) return gz.read() Here's the problem return gz.read()

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  • dealing cards in Clojure

    - by Ralph
    I am trying to write a Spider Solitaire player as an exercise in learning Clojure. I am trying to figure out how to deal the cards. I have created (with the help of stackoverflow), a shuffled sequence of 104 cards from two standard decks. Each card is represented as a (defstruct card :rank :suit :face-up) The tableau for Spider will be represented as follows: (defstruct tableau :stacks :complete) where :stacks is a vector of card vectors, 4 of which contain 5 cards face down and 1 card face up, and 6 of which contain 4 cards face down and 1 card face up, for a total of 54 cards, and :complete is an (initially) empty vector of completed sets of ace-king (represented as, for example, king-hearts, for printing purposes). The remainder of the undealt deck should be saved in a ref (def deck (ref seq)) During the game, a tableau may contain, for example: (struct-map tableau :stacks [[AH 2C KS ...] [6D QH JS ...] ... ] :complete [KC KS]) where "AH" is a card containing {:rank :ace :suit :hearts :face-up false}, etc. How can I write a function to deal the stacks and then save the remainder in the ref?

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  • Two questions on ensuring EndInvoke() gets called on a list of IAsyncResult objects

    - by RobV
    So this question is regarding the .Net IAsyncResult design pattern and the necessity of calling EndInvoke as covered in this question Background I have some code where I'm firing off potentially many asynchronous calls to a particular function and then waiting for all these calls to finish before using EndInvoke() to get back all the results. Question 1 I don't know whether any of the calls has encountered an exception until I call EndInvoke() and in the event that an exception occurs in one of the calls the entire method should fail and the exception gets wrapped into an API specific exception and thrown upwards. So my first question is what's the best way then to ensure that the remainder of the async calls get properly terminated? Is a finally block which calls EndInvoke() on the remainder of the unterminated calls (and ignores any further exceptions) the best way to do this? Question 2 Secondly when I first fire off all my asyc calls I then call WaitHandle.WaitAll() on the array of WaitHandle instances that I've got from my IAsyncResult instances. The method which is firing all these async calls has a timeout to adhere to so I provide this to the WaitAll() method. Then I test whether all the calls have completed, if not then the timeout must have been reached so the method should also fail and throw another API specific exception. So my second question is what should I do in this case? I need to call EndInvoke() to terminate all these async calls before I throw the error but at the same time I don't want the code to get stuck since EndInvoke() is blocking. In theory at least if the WaitAll() call times out then all the async calls should themselves have timed out and thrown exceptions (thus completing the call) since they are also governed by a timeout but this timeout is potentially different from the main timeout

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  • Division by zero: Undefined Behavior or Implementation Defined in C and/or C++ ?

    - by SiegeX
    Regarding division by zero, the standards say: C99 6.5.5p5 - The result of the / operator is the quotient from the division of the first operand by the second; the result of the % operator is the remainder. In both operations, if the value of the second operand is zero, the behavior is undefined. C++03 5.6.4 - The binary / operator yields the quotient, and the binary % operator yields the remainder from the division of the first expression by the second. If the second operand of / or % is zero the behavior is undefined. If we were to take the above paragraphs at face value, the answer is clearly Undefined Behavior for both languages. However, if we look further down in the C99 standard we see the following paragraph which appears to be contradictory(1): C99 7.12p4 - The macro INFINITY expands to a constant expression of type float representing positive or unsigned infinity, if available; Do the standards have some sort of golden rule where Undefined Behavior cannot be superseded by a (potentially) contradictory statement? Barring that, I don't think it's unreasonable to conclude that if your implementation defines the INFINITY macro, division by zero is defined to be such. However, if your implementation does not define such a macro, the behavior is Undefined. I'm curious what the consensus on this matter for each of the two languages. Would the answer change if we are talking about integer division int i = 1 / 0 versus floating point division float i = 1.0 / 0.0 ? Note (1) The C++03 standard talks about the library which includes the INFINITY macro.

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  • Is there a better tool than postcat for viewing postfix mail queue files?

    - by Geekman
    So I got a call early this morning about a client needing to see what email they have waiting to be delivered sitting in our secondary mail server. Their link for the main server had (still is) been down for two days and they needed to see their email. So I wrote up a quick Perl script to use mailq in combination with postcat to dump each email for their address into separate files, tar'd it up and sent it off. Horrible code, I know, but it was urgent. My solution works OK in that it at least gives a raw view, but I thought tonight it would be nice if I had a solution where I could provide their email attachments and maybe remove some "garbage" header text as well. Most of the important emails seem to have a PDF or similar attached. I've been looking around but the only method of viewing queue files I can see is the postcat command, and I really don't want to write my own parser - so I was wondering if any of you have already done so, or know of a better command to use? Here's the code for my current solution: #!/usr/bin/perl $qCmd="mailq | grep -B 2 \"someemailaddress@isp\" | cut -d \" \" -f 1"; @data = split(/\n/, `$qCmd`); $i = 0; foreach $line (@data) { $i++; $remainder = $i % 2; if ($remainder == 0) { next; } if ($line =~ /\(/ || $line =~ /\n/ || $line eq "") { next; } print "Processing: " . $line . "\n"; `postcat -q $line > $line.email.txt`; $subject=`cat $line.email.txt | grep "Subject:"`; #print "SUB" . $subject; #`cat $line.email.txt > \"$subject.$line.email.txt\"`; } Any advice appreciated.

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  • Sorting in Lua, counting number of items

    - by Josh
    Two quick questions (I hope...) with the following code. The script below checks if a number is prime, and if not, returns all the factors for that number, otherwise it just returns that the number prime. Pay no attention to the zs. stuff in the script, for that is client specific and has no bearing on script functionality. The script itself works almost wonderfully, except for two minor details - the first being the factor list doesn't return itself sorted... that is, for 24, it'd return 1, 2, 12, 3, 8, 4, 6, and 24 instead of 1, 2, 3, 4, 6, 8, 12, and 24. I can't print it as a table, so it does need to be returned as a list. If it has to be sorted as a table first THEN turned into a list, I can deal with that. All that matters is the end result being the list. The other detail is that I need to check if there are only two numbers in the list or more. If there are only two numbers, it's a prime (1 and the number). The current way I have it does not work. Is there a way to accomplish this? I appreciate all the help! function get_all_factors(number) local factors = 1 for possible_factor=2, math.sqrt(number), 1 do local remainder = number%possible_factor if remainder == 0 then local factor, factor_pair = possible_factor, number/possible_factor factors = factors .. ", " .. factor if factor ~= factor_pair then factors = factors .. ", " .. factor_pair end end end factors = factors .. ", and " .. number return factors end local allfactors = get_all_factors(zs.param(1)) if zs.func.numitems(allfactors)==2 then return zs.param(1) .. " is prime." else return zs.param(1) .. " is not prime, and its factors are: " .. allfactors end

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  • How to open multiple socket connections and do callbacks in PHP

    - by Click Upvote
    I'm writing some code which processes a queue of items. The way it works is this: Get the next item flagged as needing to be processed from the mysql database row. Request some info from a google API using Curl, wait until the info is returned. Do the remainder of the processing based on the info returned. Flag the item as processed in the db, move onto the next item. The problem is that on step # 2. Google sometimes takes 10-15 seconds to return the requested info, during this time my script has to remain halted and wait. I'm wondering if I could change the code to do the following instead: Get the next 5 items to be processed as usual. Request info for items 1-5 from google, one after the other. When the info for item 1 is returned, a 'callback' should be done which calls up a function or otherwise calls some code which then does the remainder of the processing on items 1-5. And then the script starts over until all pending items in db are marked processed. How can something like this be achieved?

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  • SDL_surface that contains several images

    - by l19
    Suppose I have a SDL_Surface that is just one image. What if I wanted to make that SDL_Surface have three copies of that image, one below the other? I came up with this function, but it doesn't do anything: void adjust(SDL_Surface* img) { int imageHeight = img->h; int desiredHeight = 3*imageHeight; int repetitions = desiredHeight / imageHeight ; int remainder = desiredHeight % imageHeight ; SDL_Rect rect; rect.x = 0; rect.y = 0; rect.w = img->w; rect.h = img->h; int i = 0; for (i ; i < repetitions ; i++) { rect.y = i* imageHeight; SDL_BlitSurface(img,NULL,img,&rect); } rect.y += remainder; SDL_BlitSurface(img,NULL,img,&rect); }

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  • Scheduled Mail in asp.net

    - by Chendur Paandian
    Hai Guys, My application deals scheduled mail concept (i.e) every morning 6.00 am my users gets a remainder mail about their activities for the day... I dont know how to do this.... Many told use windows service but i will host my website on a shared server i may not get rights to do windows service... Is there any dll for sending mails at a schduled time through asp.net application ..please help me out guys......

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  • Enabling Bitlocker in Native VHD Boot

    - by Trevor Sullivan
    I have a laptop with a single hard drive, using the GUID Partition Table (GPT) disk layout, with the following partitions: 120MB EFI System Partition 300MB Microsoft Reserved Partition (MSR) Remainder - GPT primary partition I have a Windows 8 Professional VHD configured as a native-boot VHD on the GPT primary partition. Can I use Bitlocker to encrypt my main partition, or to encrypt the VHD volume?

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  • Slot Machine Pay Out

    - by Kris.Mitchell
    I have done a lot of research into random number generators for slot machines, reel stop calculations and how to physically give the user a good chance on winning. What I can't figure out is how to properly insure that the machine is going to have a payout rating of (lets say) 95%. So, I have a reel set up wit 22 spaces on it. Filled with 16 different symbols. When I get my random number, mod divide it by 64 and get the remainder, I hop over to a loop up table to see how the virtual stop relates to the reel position. Now that I have how the reels are going to stop, do I make sure the payout ratio is correct? For every dollar they put in, how to I make sure the machine will pay out .95 cents? Thanks for the ideas. I am working in actionscript, if that helps with the language issues, but in general I am just looking for theory.

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