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  • Website badge system

    - by linkyndy
    I am currently working on a widget-based website, built entirely on user socialization. Since a reputation system pays off for attracting users, I decided to implement one of these. Now, I would like to hear some solutions on how should this be implemented the right way (take, for example, Foursquare's badge system). Basically, I need to be able to do the following: have a badges table, where I can add, edit and delete badges; be able to enable and disable a badge; be able to introduce a new badge, but without writing new code - simply give some parameters to the add badge form regarding what should be followed in order for a user to receive a badge; be able to give badges in real time - meaning that whenever a user accomplishes whatever it needs to receive a badge, the system should know immediately to give the badge to that user; also, the system should not be overloaded with "badge listeners" - I believe interrogating each user request with every badge requirements is time consuming; These being said, I would like to hear your opinions on how to implement the right way a badge system (logic, database schema, methods etc.) Thank you very much!

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  • Straight Line Equation between two points

    - by dafero
    Hi, I need to paint the line witch links two points. I developed my own solution using the straight line equation, but my results are different than using the "professional" programs (such as GIMP or even MS Paint). Here is a example of what I want: But my algorithm does this: *The green point is out of the figure and this is not possible. Any ideas? Anyone know which code is been using for this, in "professional" apps? Thanks! Daniel.

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  • Sort a 2D Points List (first by X and then Y)

    - by Mikos
    I am trying to sort a List of 2D Points first by x co-ordinate and then by y co-ordinate. I implemented the IComparer interface as follows: class PointComparer : IComparer<Point> { public int Compare(Point x, Point y) { if (x.Y != y.Y) { return x.Y - y.Y; } else { return x.X - y.X; } } } And then call my sorting as follows: pointsList.Sort(new PointComparer()); For some reason the list doesn't sort. Surely is something very simple and silly, but stuck on this for quite a while....TIA

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  • Labeling algorithm for points

    - by Qwertie
    I need an algorithm to place horizontal text labels for multiple series of points on the screen (basically I need to show timestamps and other information for a history of moving objects on a map; in general there are multiple data points per object). The text labels should appear close to their points--above, below, or on the right side--but should not overlap other points or text labels. Does anyone know an algorithm/heuristic for this?

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  • FLOT: How to make different colored points in same data series, connected by a line?

    - by Mega Matt
    Hi all, I think I may have stumbled onto a limitation of Flot, but I'm not sure. I'm trying to represent a single data series over time. The items' "State" is represented on the Y-Axis (there are 5 of them), and time is on the X-Axis (items can change states over time). I want the graph to have points and lines connecting those points for each data series. In addition to tracking an item's State over time, I'd also like to represent it's "Status" at any of the particular points. This I would like to do by changing the color of the points. What this means is a single item may have different Statuses at different times, meaning for a single data series I need a line that connects different points (dots) of different colors. The only thing I've seen so far is the ability to specify the color for all points in a given dataseries. Does anyone know if there's a way to specify colors individually? Thanks.

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  • Any reliable polygon normal calculation code?

    - by Jenko
    Do you have any reliable face normal calculation code? I'm using this but it fails when faces are 90 degrees upright or similar. // the normal point var x:Number = 0; var y:Number = 0; var z:Number = 0; // if is a triangle with 3 points if (points.length == 3) { // read vertices of triangle var Ax:Number, Bx:Number, Cx:Number; var Ay:Number, By:Number, Cy:Number; var Az:Number, Bz:Number, Cz:Number; Ax = points[0].x; Bx = points[1].x; Cx = points[2].x; Ay = points[0].y; By = points[1].y; Cy = points[2].y; Az = points[0].z; Bz = points[1].z; Cz = points[2].z; // calculate normal of a triangle x = (By - Ay) * (Cz - Az) - (Bz - Az) * (Cy - Ay); y = (Bz - Az) * (Cx - Ax) - (Bx - Ax) * (Cz - Az); z = (Bx - Ax) * (Cy - Ay) - (By - Ay) * (Cx - Ax); // if is a polygon with 4+ points }else if (points.length > 3){ // calculate normal of a polygon using all points var n:int = points.length; x = 0; y = 0; z = 0 // ensure all points above 0 var minx:Number = 0, miny:Number = 0, minz:Number = 0; for (var p:int = 0, pl:int = points.length; p < pl; p++) { var po:_Point3D = points[p] = points[p].clone(); if (po.x < minx) { minx = po.x; } if (po.y < miny) { miny = po.y; } if (po.z < minz) { minz = po.z; } } if (minx > 0 || miny > 0 || minz > 0){ for (p = 0; p < pl; p++) { po = points[p]; po.x -= minx; po.y -= miny; po.z -= minz; } } var cur:int = 1, prev:int = 0, next:int = 2; for (var i:int = 1; i <= n; i++) { // using Newell method x += points[cur].y * (points[next].z - points[prev].z); y += points[cur].z * (points[next].x - points[prev].x); z += points[cur].x * (points[next].y - points[prev].y); cur = (cur+1) % n; next = (next+1) % n; prev = (prev+1) % n; } } // length of the normal var length:Number = Math.sqrt(x * x + y * y + z * z); // if area is 0 if (length == 0) { return null; }else{ // turn large values into a unit vector x = x / length; y = y / length; z = z / length; }

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  • A problem with connected points and determining geometry figures based on points' location analysis

    - by StolePopov
    In school we have a really hard problem, and still no one from the students has solved it yet. Take a look at the picture below: http://d.imagehost.org/0422/mreza.gif That's a kind of a network of connected points, which doesn't end and each point has its own number representing it. Let say the numbers are like this: 1-23-456-78910-etc. etc.. (You can't see the number 5 or 8,9... on the picture but they are there and their position is obvious, the point in middle of 4 and 6 is 5 and so on). 1 is connected to 2 and 3, 2 is connected to 1,3,5 and 4 etc. The numbers 1-2-3 indicate they represent a triangle on the picture, but the numbers 1-4-6 do not because 4 is not directly connected with 6. Let's look at 2-3-4-5, that's a parallelogram (you know why), but 4-6-7-9 is NOT a parallelogram because the in this problem there's a rule which says all the sides must be equal for all the figures - triangles and parallelograms. Also there are hexagons, for ex. 4-5-7-9-13-12 is a hexagon - all sides must be equal here too. 12345 - that doesn't represent anything, so we ignore it. I think i explained the problem well. The actual problem which is given to us by using an input of numbers like above to determine if that's a triangle/parallelogram/hexagon(according to the described rules). For ex: 1 2 3 - triangle 11 13 24 26 -parallelogram 1 2 3 4 5 - nothing 11 23 13 25 - nothing 3 2 5 - triangle I was reading computational geometry in order to solve this, but i gave up quickly, nothing seems to help here. One friend told me this site so i decided to give it a try. If you have any ideas about how to solve this, please reply, you can use pseudo code or c++ whatever. Thank you very much.

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  • k-d tree implementation [closed]

    - by user466441
    when i run my code and debugged,i got this error - this 0x00093584 {_Myproxy=0x00000000 _Mynextiter=0x00000000 } std::_Iterator_base12 * const - _Myproxy 0x00000000 {_Mycont=??? _Myfirstiter=??? } std::_Container_proxy * _Mycont CXX0017: Error: symbol "" not found _Myfirstiter CXX0030: Error: expression cannot be evaluated + _Mynextiter 0x00000000 {_Myproxy=??? _Mynextiter=??? } std::_Iterator_base12 * but i dont know what does it means,code is this #include<iostream> #include<vector> #include<algorithm> using namespace std; struct point { float x,y; }; vector<point>pointleft(4); vector<point>pointright(4); //we are going to implement two comparison function for x and y coordinates,we need it in calculation of median (we should sort vector //by x or y according to depth informaton,is depth even or odd. bool sortby_X(point &a,point &b) { return a.x<b.x; } bool sortby_Y(point &a,point &b) { return a.y<b.y; } //so i am going to implement to median finding algorithm,one for finding median by x and another find median by y point medianx(vector<point>points) { point temp; sort(points.begin(),points.end(),sortby_X); temp=points[(points.size()/2)]; return temp; } point mediany(vector<point>points) { point temp; sort(points.begin(),points.end(),sortby_Y); temp=points[(points.size()/2)]; return temp; } //now construct basic tree structure struct Tree { float x,y; Tree(point a) { x=a.x; y=a.y; } Tree *left; Tree *right; }; Tree * build_kd( Tree *root,vector<point>points,int depth) { point temp; if(points.size()==1)// that point is as a leaf { if(root==NULL) root=new Tree(points[0]); return root; } if(depth%2==0) { temp=medianx(points); root=new Tree(temp); for(int i=0;i<points.size();i++) { if (points[i].x<temp.x) pointleft[i]=points[i]; else pointright[i]=points[i]; } } else { temp=mediany(points); root=new Tree(temp); for(int i=0;i<points.size();i++) { if(points[i].y<temp.y) pointleft[i]=points[i]; else pointright[i]=points[i]; } } return build_kd(root->left,pointleft,depth+1); return build_kd(root->right,pointright,depth+1); } void print(Tree *root) { while(root!=NULL) { cout<<root->x<<" " <<root->y; print(root->left); print(root->right); } } int main() { int depth=0; Tree *root=NULL; vector<point>points(4); float x,y; int n=4; for(int i=0;i<n;i++) { cin>>x>>y; points[i].x=x; points[i].y=y; } root=build_kd(root,points,depth); print(root); return 0; } i am trying ti implement in c++ this pseudo code tuple function build_kd_tree(int depth, set points): if points contains only one point: return that point as a leaf. if depth is even: Calculate the median x-value. Create a set of points (pointsLeft) that have x-values less than the median. Create a set of points (pointsRight) that have x-values greater than or equal to the median. else: Calculate the median y-value. Create a set of points (pointsLeft) that have y-values less than the median. Create a set of points (pointsRight) that have y-values greater than or equal to the median. treeLeft = build_kd_tree(depth + 1, pointsLeft) treeRight = build_kd_tree(depth + 1, pointsRight) return(median, treeLeft, treeRight) please help me what this error means?

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  • Replace XML Bullet Points Found in Feed in Classic ASP

    - by StevieB
    Hey I am currently reading in a XML file which contains bullet list in the following container i.e. ? the average pension contribution rate for executive directors . I am having a problem with symbol directly before the text of each bullet point I want to remove it i.e Replace(text,"old","new") but i cant seem to find what value that bullet point actually is to replace of that makes sense. Thanks

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  • Compute directional light frustum from view furstum points and light direction

    - by Fabian
    I'm working on a friends engine project and my task is to construct a new frustum from the light direction that overlaps the view frustum and possible shadow casters. The project already has a function that creates a frustum for this but its way to big and includes way to many casters (shadows) which can't be seen in the view frustum. Now the only parameter of this function are the normalized light direction vector and a view class which lets me extract the 8 view frustum points in world space. I don't have any additional infos about the scene. I have read some of the related Questions here but non seem to fit very well to my problem as they often just point to cascaded shadow maps. Sadly i can't use DX or openGl functions directly because this engine has a dedicated math library. From what i've read so far the steps are: Transform view frustum points into light space and find min/max x and y values (or sometimes minima and maxima of all three axis) and create a AABB using the min/max vectors. But what comes after this step? How do i transform this new AABB back to world space? What i've done so far: CVector3 Points[8], MinLight = CVector3(FLT_MAX), MaxLight = CVector3(FLT_MAX); for(int i = 0; i<8;++i){ Points[i] = Points[i] * WorldToShadowMapMatrix; MinLight = Math::Min(Points[i],MinLight); MaxLight = Math::Max(Points[i],MaxLight); } AABox box(MinLight,MaxLight); I don't think this is the right way to do it. The near plain probably has to extend into the direction of the light source to include potentional shadow casters. I've read the Microsoft article about cascaded shadow maps http://msdn.microsoft.com/en-us/library/windows/desktop/ee416307%28v=vs.85%29.aspx which also includes some sample code. But they seem to use the scenes AABB to determine the near and far plane which I can't since i cant access this information from the funtion I'm working in. Could you guys please link some example code which shows the calculation of such frustum? Thanks in advance! Additional questio: is there a way to construct a WorldToFrustum matrix that represents the above transformation?

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  • Online Reputation Management - The Basics

    Bad publicity is just a reality of doing business these days, especially for any company that is even moderately in the public eye. With hundreds of television channels, a print media network larger than the entire European Union and the Internet, negative comments are hurled at everyone from the Pope to Oprah.

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  • How Web Optimization Services Work to Increase Your on the Internet Reputation

    SEO is a symbol of search engine optimization and that is the key to success from the enterprise. No site has meaning if it seriously isn't properly promoted. Anytime any web surfer is in look up of any certain merchandise, providers or data he makes use of the easiest method of browsing as a result of search engine optimization and this is habit of many individuals to only search straight into 5 or six major sites for their goal. No person has time to seem directly into 100 pages of internet search engine as there is no need to have when he finds in major pages.

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  • How can I set Windows Server 2008 juntion points to Every Read Allow?

    - by brendan
    We have apps running on Windows Server 2003 and now 2008 as well. Unfortunately some of our code relies on inspecting the Documents and Settings directory which no longer exists in Windows 2003. It looks like there are "Junction Points" set up for backwards compatibility - http://msdn.microsoft.com/en-us/library/bb756982.aspx. But it seems like nothing I can do can get me access. I basically need to be able to call from a command line on both 2003 and 2008: C:\Documents and Settings\Administrator\Local Settings\Application Data\Google\Chrome\Application\chrome.exe Which translates in Windows 2008 to : C:\Users\Administrator\AppData\Local\Google\Chrome\Application\chrome.exe I've tried setting up my own "Documents and Settings" folder in 2008 but it won't let me as that seems to be reserved for these Juntion Points.

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  • Rotating multiple points at once in 2D

    - by Deukalion
    I currently have an editor that creates shapes out of (X, Y) coordinates and then triangulate that to make up a shape of those points. What will I have to do to rotate all of those points simultaneously? Say I click the screen in my editor, it locates the point where I've clicked and if I move the mouse up or down from that point it calculates rotation on X and Y axis depending on new position relevant to first position, say I move up 10 on the Y axis it rotates that way and the same way for X. Or simply, somehow to enter rotation degree: 90, 180, 270, 360, for example. I use VertexPositionColor at the moment. What are the best algorithms or methods that I can look at to rotate multiple points in 2D at once? Also: Since this is an editor I do now want to rotate it on the Matrix, so if I want to rotate the whole shape 180 degree that's the new "position" of all the points, so that's the new rotation = 0 for example. Later on I probably will use World Matrix rotation for this, but not now.

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  • Drawing Grid in 3D view - Mathematically calculate points and draw line between them (Not working)

    - by Deukalion
    I'm trying to draw a simple grid from a starting point and expand it to a size. Doing this mathematically and drawing the lines between each point, but since the "DrawPrimitives(LineList)" doesn't work the way it should work, And this method can't even draw lines between four points to create a simple Rectangle, so how does this method work exactly? Some sort of coordinate system: [ ][ ][ ][ ][ ][ ][ ] [ ][2.2][ ][0.2][ ][2.2][ ] [ ][2.1][1.1][ ][1.1][2.1][ ] [ ][2.0][ ][0.0][ ][2.0][ ] [ ][2.1][1.1][ ][1.1][2.1][ ] [ ][2.2][ ][0.2][ ][2.2][ ] [ ][ ][ ][ ][ ][ ][ ] I've checked with my method and it's working as it should. It calculates all the points to form a grid. This way I should be able to create Points where to draw line right? This way, if I supply the method with Size = 2 it starts at 0,0 and works it through all the corners (2,2) on each side. So, I have the positions of each point. How do I draw lines between these? VerticeCount = must be number of Points in this case, right? So, tell me, if I can't supply this method with Point A, Point B, Point C, Point D to draw a four vertice rectangle (Point A - B - C - D) - how do I do it? How do I even begin to understand it? As far as I'm concered, that's a "Line list" or a list of points where to draw lines. Can anyone explain what I'm missing? I wish to do this mathematically so I can create a a custom grid that can be altered.

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  • 554 - Sending MTA’s poor reputation

    - by Phil Wilks
    I am running an email server on 77.245.64.44 and have recently started to have problems with remote delivery of emails sent using this server. Only about 5% of recipients are rejecting the emails, but they all share the following common message... Remote host said: 554 Your access to this mail system has been rejected due to the sending MTA's poor reputation. As far as I can tell my server is not on any blacklists, and it is set up correctly (the reverse DNS checks out and so on). I'm not even sure what the "Sending MTA" is, but I assume it's my server. If anyone could shed any light on this I'd really appreciate it! Here's the full bounce message... Could not deliver message to the following recipient(s): Failed Recipient: [email protected] Reason: Remote host said: 554 Your access to this mail system has been rejected due to the sending MTA's poor reputation. If you believe that this failure is in error, please contact the intended recipient via alternate means. -- The header and top 20 lines of the message follows -- Received: from 79-79-156-160.dynamic.dsl.as9105.com [79.79.156.160] by mail.fruityemail.com with SMTP; Thu, 3 Sep 2009 18:15:44 +0100 From: "Phil Wilks" To: Subject: Test Date: Thu, 3 Sep 2009 18:16:10 +0100 Organization: Fruity Solutions Message-ID: MIME-Version: 1.0 Content-Type: multipart/alternative; boundary="----=_NextPart_000_01C2_01CA2CC2.9D9585A0" X-Mailer: Microsoft Office Outlook 12.0 Thread-Index: Acosujo9LId787jBSpS3xifcdmCF5Q== Content-Language: en-gb x-cr-hashedpuzzle: ADYN AzTI BO8c BsNW Cqg/ D10y E0H4 GYjP HZkV Hc9t ICru JPj7 Jd7O Jo7Q JtF2 KVjt;1;YwBoAGEAcgBsAG8AdAB0AGUALgBoAHUAbgB0AC0AZwByAHUAYgBiAGUAQABzAHUAbgBkAGEAeQAtAHQAaQBtAGUAcwAuAGMAbwAuAHUAawA=;Sosha1_v1;7;{F78BB28B-407A-4F86-A12E-7858EB212295};cABoAGkAbABAAGYAcgB1AGkAdAB5AHMAbwBsAHUAdABpAG8AbgBzAC4AYwBvAG0A;Thu, 03 Sep 2009 17:16:08 GMT;VABlAHMAdAA= x-cr-puzzleid: {F78BB28B-407A-4F86-A12E-7858EB212295} This is a multipart message in MIME format. ------=_NextPart_000_01C2_01CA2CC2.9D9585A0 Content-Type: text/plain; charset="us-ascii" Content-Transfer-Encoding: 7bit

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  • GeoDjango: is there an out-of-the-box way to generate clusters of points?

    - by vaughnkoch
    Hi, I'm trying to compute clusters on a set of points in Python, using GeoDjango. The problem: Given a set of points, output a set of clusters of those points. (i'm fine specifying # of clusters/cluster size/distance in advance to simplify) There are a few solutions on the web to do clustering, so it's a well known problem. I thought that GeoDjango would handle these types of problems out of the box, but it's not clear how - I've searched the GeoDjango documentation, Google, and a few other places, but couldn't find anything. Before I roll my own clustering solution, I thought I'd ask to see if there's a straightforward way to do this using GEOS or another package within GeoDjango.

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