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Search found 31 results on 2 pages for 'shiva b'.

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• dropdown list box to display in the row..

  - by kumar

  Please can any body tell me is this right what I am doing here.. I need to display a dropdown list box in each row in the grid var lastsel2; $("#table1").jqGrid({ scroll: 1, sortable: true, url: '/friends/names/shiva', datatype: "json", mtype: 'GET', height: 200, …

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• how to group data in a list

  - by prince23

  I need to group data of a list in c# ex: i have a data like this in a list c# i have a class called information.cs with these properties name,school, parent ex data name school parent kumar fes All manju fes kumar anu frank kumar anitha jss All rohit frank manju …

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• how to group data in a list c#

  - by prince23

  hi, i need to group data of a list in c# ex: i have a data like this in a list c# i have a class called information.cs with these properties name,school, parent ex data name school parent kumar fes All manju fes kumar anu frank kumar anitha jss All rohit frank …

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• issue in ObservableCollection

  - by prince23

  hi, i have an lsit with these data i have a class called information.cs with these properties name,school, parent ex data name school parent kumar fes All manju fes kumar anu frank kumar anitha jss All rohit frank manju anill vijaya manju vani …

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• Easiest, most fun way to program 2D games? Flash? XNA? Some other engine?

  - by Maxi

  Hi, this is a post detailing my search for the most enjoyable way for a hobbyist game programmer to sweeten his free time with making a game. My requirements: I looked at Flash first, I made a couple of small games but I'm doubtful of the performance. I would like to make a fairly large strategy game, with several hundred units fighting…

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• convert the output into an list

  - by prince23

  using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Linq.Expressions; using System.Xml.XPath; using System.Xml.Linq; namespace SampleProgram1 { class Program { static void Main(string[] args) { string xml = @"<people> …

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