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  • blurry lines between web application context layer, service layer and data access layer in spring

    - by thenaglecode
    I Originally asked this question in SO but on advice I have moved the question here... I'll admit I'm a spring newbie, but you can correct me if I'm wrong, this one liner looks kinda fishy in a best practices sort of way: @RepositoryRestResource(collectionResourceRel="people"...) public interface PersonRepository extends PagingAndSortingRepository<Person, Long> For those who are unaware, the following does many things: It is an interface definition that can be registered in an application context as a jpa repository, automagically hooking up all the default CRUD operations within a persistence context (that is externally configured). and also configures default controller/request-mapping/handler functionality at the namespace "/people" relative to your configured dispatcher servlet-mapping. Here's my point. I just crossed 3 conceptual layers with one line of code! this feels against my seperation-of-concern instincts but i wanted to hear your opinion. And for the sake of being on a question and answer site, I would like to know whether there is a better way of seperating these different layers - Service, Data, Controllers - whilst maintaining as minimal configuration as possible

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  • Spring security request matcher is not working with regex

    - by Felipe Cardoso Martins
    Using Spring MVC + Security I have a business requirement that the users from SEC (Security team) has full access to the application and FRAUD (Anti-fraud team) has only access to the pages that URL not contains the words "block" or "update" with case insensitive. Bellow, all spring dependencies: $ mvn dependency:tree | grep spring [INFO] +- org.springframework:spring-webmvc:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-asm:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-beans:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-context:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-context-support:jar:3.1.2.RELEASE:compile [INFO] | \- org.springframework:spring-expression:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework:spring-core:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework:spring-web:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework.security:spring-security-core:jar:3.1.2.RELEASE:compile [INFO] | \- org.springframework:spring-aop:jar:3.0.7.RELEASE:compile [INFO] +- org.springframework.security:spring-security-web:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-jdbc:jar:3.0.7.RELEASE:compile [INFO] | \- org.springframework:spring-tx:jar:3.0.7.RELEASE:compile [INFO] +- org.springframework.security:spring-security-config:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework.security:spring-security-acl:jar:3.1.2.RELEASE:compile Bellow, some examples of mapped URL path from spring log: Mapped URL path [/index] onto handler 'homeController' Mapped URL path [/index.*] onto handler 'homeController' Mapped URL path [/index/] onto handler 'homeController' Mapped URL path [/cellphone/block] onto handler 'cellphoneController' Mapped URL path [/cellphone/block.*] onto handler 'cellphoneController' Mapped URL path [/cellphone/block/] onto handler 'cellphoneController' Mapped URL path [/cellphone/confirmBlock] onto handler 'cellphoneController' Mapped URL path [/cellphone/confirmBlock.*] onto handler 'cellphoneController' Mapped URL path [/cellphone/confirmBlock/] onto handler 'cellphoneController' Mapped URL path [/user/update] onto handler 'userController' Mapped URL path [/user/update.*] onto handler 'userController' Mapped URL path [/user/update/] onto handler 'userController' Mapped URL path [/user/index] onto handler 'userController' Mapped URL path [/user/index.*] onto handler 'userController' Mapped URL path [/user/index/] onto handler 'userController' Mapped URL path [/search] onto handler 'searchController' Mapped URL path [/search.*] onto handler 'searchController' Mapped URL path [/search/] onto handler 'searchController' Mapped URL path [/doSearch] onto handler 'searchController' Mapped URL path [/doSearch.*] onto handler 'searchController' Mapped URL path [/doSearch/] onto handler 'searchController' Bellow, a test of the regular expressions used in spring-security.xml (I'm not a regex speciality, improvements are welcome =]): import java.util.Arrays; import java.util.List; public class RegexTest { public static void main(String[] args) { List<String> pathSamples = Arrays.asList( "/index", "/index.*", "/index/", "/cellphone/block", "/cellphone/block.*", "/cellphone/block/", "/cellphone/confirmBlock", "/cellphone/confirmBlock.*", "/cellphone/confirmBlock/", "/user/update", "/user/update.*", "/user/update/", "/user/index", "/user/index.*", "/user/index/", "/search", "/search.*", "/search/", "/doSearch", "/doSearch.*", "/doSearch/"); for (String pathSample : pathSamples) { System.out.println("Path sample: " + pathSample + " - SEC: " + pathSample.matches("^.*$") + " | FRAUD: " + pathSample.matches("^(?!.*(?i)(block|update)).*$")); } } } Bellow, the console result of Java class above: Path sample: /index - SEC: true | FRAUD: true Path sample: /index.* - SEC: true | FRAUD: true Path sample: /index/ - SEC: true | FRAUD: true Path sample: /cellphone/block - SEC: true | FRAUD: false Path sample: /cellphone/block.* - SEC: true | FRAUD: false Path sample: /cellphone/block/ - SEC: true | FRAUD: false Path sample: /cellphone/confirmBlock - SEC: true | FRAUD: false Path sample: /cellphone/confirmBlock.* - SEC: true | FRAUD: false Path sample: /cellphone/confirmBlock/ - SEC: true | FRAUD: false Path sample: /user/update - SEC: true | FRAUD: false Path sample: /user/update.* - SEC: true | FRAUD: false Path sample: /user/update/ - SEC: true | FRAUD: false Path sample: /user/index - SEC: true | FRAUD: true Path sample: /user/index.* - SEC: true | FRAUD: true Path sample: /user/index/ - SEC: true | FRAUD: true Path sample: /search - SEC: true | FRAUD: true Path sample: /search.* - SEC: true | FRAUD: true Path sample: /search/ - SEC: true | FRAUD: true Path sample: /doSearch - SEC: true | FRAUD: true Path sample: /doSearch.* - SEC: true | FRAUD: true Path sample: /doSearch/ - SEC: true | FRAUD: true Tests Scenario 1 Bellow, the important part of spring-security.xml: <security:http entry-point-ref="entryPoint" request-matcher="regex"> <security:intercept-url pattern="^.*$" access="ROLE_SEC" /> <security:intercept-url pattern="^(?!.*(?i)(block|update)).*$" access="ROLE_FRAUD" /> <security:access-denied-handler error-page="/access-denied.html" /> <security:form-login always-use-default-target="false" login-processing-url="/doLogin.html" authentication-failure-handler-ref="authFailHandler" authentication-success-handler-ref="authSuccessHandler" /> <security:logout logout-url="/logout.html" success-handler-ref="logoutSuccessHandler" /> </security:http> Behaviour: FRAUD group **can't" access any page SEC group works fine Scenario 2 NOTE that I only changed the order of intercept-url in spring-security.xml bellow: <security:http entry-point-ref="entryPoint" request-matcher="regex"> <security:intercept-url pattern="^(?!.*(?i)(block|update)).*$" access="ROLE_FRAUD" /> <security:intercept-url pattern="^.*$" access="ROLE_SEC" /> <security:access-denied-handler error-page="/access-denied.html" /> <security:form-login always-use-default-target="false" login-processing-url="/doLogin.html" authentication-failure-handler-ref="authFailHandler" authentication-success-handler-ref="authSuccessHandler" /> <security:logout logout-url="/logout.html" success-handler-ref="logoutSuccessHandler" /> </security:http> Behaviour: SEC group **can't" access any page FRAUD group works fine Conclusion I did something wrong or spring-security have a bug. The problem already was solved in a very bad way, but I need to fix it quickly. Anyone knows some tricks to debug better it without open the frameworks code? Cheers, Felipe

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  • Spring MVC annotation config problem

    - by Seth
    I'm trying to improve my spring mvc configuration so as to not require a new config file for every servlet I add, but I'm running into problems. I've tried using this tutorial as a starting point, but I'm running into an issue that I can't figure out. The problem is that when I do a GET to my servlet, I get back a 404 error. Here's my config and a representative java snippet from a Controller: web.xml: <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <display-name>SightLogix Coordination System</display-name> <description>SightLogix Coordination System</description> <servlet> <servlet-name>Spring MVC Dispatcher Servlet</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/application-context.xml /WEB-INF/application-security.xml </param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>Spring MVC Dispatcher Servlet</servlet-name> <url-pattern>/slcs/*</url-pattern> </servlet-mapping> <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/application-context.xml /WEB-INF/application-security.xml </param-value> </context-param> <listener> <listener-class> org.springframework.web.context.ContextLoaderListener </listener-class> </listener> <filter> <filter-name>springSecurityFilterChain</filter-name> <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> </filter> <filter-mapping> <filter-name>springSecurityFilterChain</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> </web-app> application-context.xml: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd" default-init-method="init" default-destroy-method="destroy"> <mvc:annotation-driven /> <context:component-scan base-package="top.level" /> </beans> application-security.xml: <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <http> <intercept-url pattern="/**" access="ROLE_MANAGER" requires-channel="https" /> <http-basic /> </http> <authentication-manager> <authentication-provider user-service-ref="myUserDetailsService"> <password-encoder hash="sha"/> </authentication-provider> </authentication-manager> <beans:bean id="myUserDetailsService" class="path.to.my.UserDetailsServiceImpl"> </beans:bean> </beans:beans> Snippet of a Controller class (one of many, but they all look essentially like this): @Controller @RequestMapping("/foo.xml") public class FooController { @RequestMapping(method=RequestMethod.GET) public void handleGET(HttpServletRequest request, HttpServletResponse response) throws IOException { ... Can anyone tell me what I'm doing incorrectly? Thanks!

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  • How can I Convert XML to an Object using Spring 3.0 mvc while making RESTful request

    - by brock
    Hi, I'm using the Spring 3.0 RC1 framework and I'm currently testing out Spring mvc. I wanted to use Spring mvc to handle restful requests. I have set up my controller to handle the URI request. I am passing in xml with the request. So on the controller I have a method like follows: public void request(RequestObject request) { doSomething(); } I am having a hard time converting the xml to the RequestObject. I haven't seen much documentation on this and I was wondering if anyone could point me in the right direction. I'm guess that you would have to annotate the RequestObject using JAXB or something in order to tell Spring to convert the xml file to RequestObject but I'm not sure. Thanks for all of your help!!

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  • Using an ODBC application with a JDBC driver

    - by Nick Retallack
    My company uses Vertica. We have Python applications that connect to it with pyodbc. I do most of my development on a Mac (Snow Leopard) and unfortunately Vertica has not released ODBC drivers for Mac. They do have JDBC drivers though. I don't think developing in Jython is a good compromise. Is there any way to use JDBC drivers with an ODBC application? Some kind of ODBC connector?

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  • How to implement login page using Spring Security so that it works with Spring web flow?

    - by simon
    I have a web application using Spring 2.5.6 and Spring Security 2.0.4. I have implemented a working login page, which authenticates the user against a web service. The authentication is done by defining a custom authentincation manager, like this: <beans:bean id="customizedFormLoginFilter" class="org.springframework.security.ui.webapp.AuthenticationProcessingFilter"> <custom-filter position="AUTHENTICATION_PROCESSING_FILTER" /> <beans:property name="defaultTargetUrl" value="/index.do" /> <beans:property name="authenticationFailureUrl" value="/login.do?error=true" /> <beans:property name="authenticationManager" ref="customAuthenticationManager" /> <beans:property name="allowSessionCreation" value="true" /> </beans:bean> <beans:bean id="customAuthenticationManager" class="com.sevenp.mobile.samplemgmt.web.security.CustomAuthenticationManager"> <beans:property name="authenticateUrlWs" value="${WS_ENDPOINT_ADDRESS}" /> </beans:bean> The authentication manager class: public class CustomAuthenticationManager implements AuthenticationManager, ApplicationContextAware { @Transactional @Override public Authentication authenticate(Authentication authentication) throws AuthenticationException { //authentication logic return new UsernamePasswordAuthenticationToken(principal, authentication.getCredentials(), grantedAuthorityArray); } The essential part of the login jsp looks like this: <c:url value="/j_spring_security_check" var="formUrlSecurityCheck"/> <form method="post" action="${formUrlSecurityCheck}"> <div id="errorArea" class="errorBox"> <c:if test="${not empty param.error}"> ${sessionScope["SPRING_SECURITY_LAST_EXCEPTION"].message} </c:if> </div> <label for="loginName"> Username: <input style="width:125px;" tabindex="1" id="login" name="j_username" /> </label> <label for="password"> Password: <input style="width:125px;" tabindex="2" id="password" name="j_password" type="password" /> </label> <input type="submit" tabindex="3" name="login" class="formButton" value="Login" /> </form> Now the problem is that the application should use Spring Web Flow. After the application was configured to use Spring Web Flow, the login does not work anymore - the form action to "/j_spring_security_check" results in a blank page without error message. What is the best way to adapt the existing login process so that it works with Spring Web Flow?

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  • ACL architechture for a Software As a service in Spring 3.0

    - by geoaxis
    I am making a software as a service using Spring 3.0 (Spring MVC, Spring Security, Spring Roo, Hibernate) I have to come up with a flexible access control list mechanism.I have three different kinds of users System (who can do any thing to the system, includes admin and internal daemons) Operations (who can add and delete users, organizations, and do maintenance work on behalf of users and organizations) End Users (they belong to one or more organization, for each organization, the user can have one or more roles, like being organization admin, or organization read-only member) (role like orgadmin can also add users for that organization) Now my question is, how should i model the entity of User? If I just take the End User, it can belong to one or more organizations, so each user can contain a set of references to its organizations. But how do we model the users role for each organization, So for example User UX belongs to organizations og1, og2 and og3, and for og1 he is both orgadmin, and org-read-only-user, where as for og2 he is only orgadmin and for og3 he is only org-read-only-user I have the possibility of making each user belong to one organization alone, but that's making the system bounded and I don't like that idea (although i would still satisfy the requirement) If you have a better extensible ACL architecture, please suggest it. Since its a software as a service, one would expect that alot of different organizations would be part if the same system. I had one concern that it is not a good idea to keep og1 and og2 data on the same DB (if og1 decides to spawn a 100 reports on the system, og2 should not suffer) But that is some thing advanced for now and is not directly related to ACL but to the physical distribution of data and setup of services based on those ACLs This is a community Wiki question, please correct any thing which you wish to do so. Thanks

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  • ClassNotFoundException com.mysql.jdbc.Driver

    - by Dusk
    This question might have asked here number of times . After doing some google search for the above error and doing some update, I can't understand why I'm still getting that error. I've already put my driver-- mysql-connector-java-5.1.5-bin in the classpath: Java_Home\jre\lib\ Java_Home\jre\lib\ext\ Java_Home\lib and the code which I'm using to connect to mysql database is: try{ Class.forName("com.mysql.jdbc.Driver"); Connection con=DriverManager.getConnection("jdbc:mysql://localhost:3306/mail","root",""); Statement stmt = con.createStatement(); ResultSet rs = stmt.executeQuery("select message_body from deadletter"); String dbtime; while (rs.next()) { dbtime = rs.getString(1); System.out.println(dbtime); } con.close(); } catch (SQLException e) { System.out.println("Connection Failed! Check output console"); e.printStackTrace(); } } and the complete stacktrace of the above exception is: java.lang.ClassNotFoundException: com.mysql.jdbc:Driver at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:307) at java.lang.ClassLoader.loadClass(ClassLoader.java:307) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301) at java.lang.ClassLoader.loadClass(ClassLoader.java:252) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:169) at mail.main(mail.java:114) Now, what's wrong I'm doing here?

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  • How to read spring-application-context.xml and AnnotationConfigWebApplicationContext both in spring mvc

    - by Suvasis
    In case I want to read bean definitions from spring-application-context.xml, I would do this in web.xml file. <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/applicationContext.xml </param-value> </context-param> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> In case I want to read bean definitions through Java Configuration Class (AnnotationConfigWebApplicationContext), I would do this in web.xml <servlet> <servlet-name>appServlet</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextClass</param-name> <param-value> org.springframework.web.context.support.AnnotationConfigWebApplicationContext </param-value> </init-param> <init-param> <param-name>contextConfigLocation</param-name> <param-value> org.package.MyConfigAnnotatedClass </param-value> </init-param> </servlet> How do I use both in my application. like reading beans from both configuration xml file and annotated class. Is there a way to load spring beans in xml file while we are using AppConfigAnnotatedClass to instantiate/use rest of the beans.

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  • Howcan I get started with Spring Batch?

    - by C. Ross
    I'm trying to learn Spring Batch, but the startup guide is very confusing. Comments like You can get a pretty good idea about how to set up a job by examining the unit tests in the org.springframework.batch.sample package (in src/main/java) and the configuration in src/main/resources/jobs. aren't exactly helpful. Also I find the Sample project very complicated (17 non-empty Namespaces with 109 classes)! Is there a simpler place to get started with Spring Batch?

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  • What are annotations and how do they actually work for frameworks like Spring?

    - by Rachel
    I am new to Spring and now a days I hear a lot about Spring Framework. I have two sets of very specific questions: Set No. 1: What are annotations in general ? How does annotations works specifically with Spring framework ? Can annotations be used outside Spring Framework or are they Framework specific ? Set No. 2: What module of Spring Framework is widely used in Industry ? I think it is Spring MVC but why it is the most used module, if am correct or correct me on this ? I am newbie to Spring and so feel free to edit this questions to make more sense.

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  • What is annotations and how do it actually works for frameworks like Spring ?

    - by Rachel
    I am new to Spring and now a days I hear a lot about Spring Framework. I have two sets of very specific questions: Set No. 1: What are annotations in general ? How does annotations works specifically with Spring framework ? Can annotations be used outside Spring Framework or are they Framework specific ? Set No. 2: What module of Spring Framework is widely used in Industry ? I think it is Spring MVC but why it is the most used module, if am correct or correct me on this ? I am newbie to Spring and so feel free to edit this questions to make more sense.

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  • Spring @PostConstruct function in a @Repository called multiple times

    - by Seth
    I have a DAO that I'm trying to inject into a couple different places: @Repository public class FooDAO { @Autowired private HibernateManager sessionFactory; @PostConstruct public void doSomeDatabaseStuff() throws DataAccessException { ... } } And my application-context.xml is a fairly simple context:component-scan: <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd" default-init-method="init" default-destroy-method="destroy"> <context:component-scan base-package="top.level"/> </beans> The DAO is accessed from a couple servlets in my application server through @Autowired properties. As far as I understand, anything annotated with @Repository should default to being a singleton and thus doSomeDatabaseStuff() should only be called once (as is my intention). The problem is that I'm seeing doSomeDatabaseStuff() called multiple times. What's going on here? Have I set something up incorrectly? I'm using spring 3.0.0. Thanks for the help.

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  • Spring security - Reach users ID without passing it through every controller

    - by nilsi
    I have a design issue that I don't know how to solve. I'm using Spring 3.2.4 and Spring security 3.1.4. I have a Account table in my database that looks like this: create table Account (id identity, username varchar unique, password varchar not null, firstName varchar not null, lastName varchar not null, university varchar not null, primary key (id)); Until recently my username was just only a username but I changed it to be the email address instead since many users want to login with that instead. I have a header that I include on all my pages which got a link to the users profile like this: <a href="/project/users/<%= request.getUserPrincipal().getName()%>" class="navbar-link"><strong><%= request.getUserPrincipal().getName()%></strong></a> The problem is that <%= request.getUserPrincipal().getName()%> returns the email now, I don't want to link the user's with thier emails. Instead I want to use the id every user have to link to the profile. How do I reach the users id's from every page? I have been thinking of two solutions but I'm not sure: Change the principal to contain the id as well, don't know how to do this and having problem finding good information on the topic. Add a model attribute to all my controllers that contain the whole user but this would be really ugly, like this. Account account = entityManager.find(Account.class, email); model.addAttribute("account", account); There are more way's as well and I have no clue which one is to prefer. I hope it's clear enough and thank you for any help on this. ====== Edit according to answer ======= I edited Account to implement UserDetails, it now looks like this (will fix the auto generated stuff later): @Entity @Table(name="Account") public class Account implements UserDetails { @Id private int id; private String username; private String password; private String firstName; private String lastName; @ManyToOne private University university; public Account() { } public Account(String username, String password, String firstName, String lastName, University university) { this.username = username; this.password = password; this.firstName = firstName; this.lastName = lastName; this.university = university; } public String getUsername() { return username; } public String getPassword() { return password; } public String getFirstName() { return firstName; } public String getLastName() { return lastName; } public void setUsername(String username) { this.username = username; } public void setPassword(String password) { this.password = password; } public void setFirstName(String firstName) { this.firstName = firstName; } public void setLastName(String lastName) { this.lastName = lastName; } public University getUniversity() { return university; } public void setUniversity(University university) { this.university = university; } public int getId() { return id; } public void setId(int id) { this.id = id; } @Override public Collection<? extends GrantedAuthority> getAuthorities() { // TODO Auto-generated method stub return null; } @Override public boolean isAccountNonExpired() { // TODO Auto-generated method stub return false; } @Override public boolean isAccountNonLocked() { // TODO Auto-generated method stub return false; } @Override public boolean isCredentialsNonExpired() { // TODO Auto-generated method stub return false; } @Override public boolean isEnabled() { // TODO Auto-generated method stub return true; } } I also added <%@ taglib prefix="sec" uri="http://www.springframework.org/security/tags" %> To my jsp files and trying to reach the id by <sec:authentication property="principal.id" /> This gives me the following org.springframework.beans.NotReadablePropertyException: Invalid property 'principal.id' of bean class [org.springframework.security.authentication.UsernamePasswordAuthenticationToken]: Bean property 'principal.id' is not readable or has an invalid getter method: Does the return type of the getter match the parameter type of the setter? ====== Edit 2 according to answer ======= I based my application on spring social samples and I never had to change anything until now. This are the files I think are relevant, please tell me if theres something you need to see besides this. AccountRepository.java public interface AccountRepository { void createAccount(Account account) throws UsernameAlreadyInUseException; Account findAccountByUsername(String username); } JdbcAccountRepository.java @Repository public class JdbcAccountRepository implements AccountRepository { private final JdbcTemplate jdbcTemplate; private final PasswordEncoder passwordEncoder; @Inject public JdbcAccountRepository(JdbcTemplate jdbcTemplate, PasswordEncoder passwordEncoder) { this.jdbcTemplate = jdbcTemplate; this.passwordEncoder = passwordEncoder; } @Transactional public void createAccount(Account user) throws UsernameAlreadyInUseException { try { jdbcTemplate.update( "insert into Account (firstName, lastName, username, university, password) values (?, ?, ?, ?, ?)", user.getFirstName(), user.getLastName(), user.getUsername(), user.getUniversity(), passwordEncoder.encode(user.getPassword())); } catch (DuplicateKeyException e) { throw new UsernameAlreadyInUseException(user.getUsername()); } } public Account findAccountByUsername(String username) { return jdbcTemplate.queryForObject("select username, firstName, lastName, university from Account where username = ?", new RowMapper<Account>() { public Account mapRow(ResultSet rs, int rowNum) throws SQLException { return new Account(rs.getString("username"), null, rs.getString("firstName"), rs.getString("lastName"), new University("test")); } }, username); } } security.xml <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xsi:schemaLocation="http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd"> <http pattern="/resources/**" security="none" /> <http pattern="/project/" security="none" /> <http use-expressions="true"> <!-- Authentication policy --> <form-login login-page="/signin" login-processing-url="/signin/authenticate" authentication-failure-url="/signin?error=bad_credentials" /> <logout logout-url="/signout" delete-cookies="JSESSIONID" /> <intercept-url pattern="/addcourse" access="isAuthenticated()" /> <intercept-url pattern="/courses/**/**/edit" access="isAuthenticated()" /> <intercept-url pattern="/users/**/edit" access="isAuthenticated()" /> </http> <authentication-manager alias="authenticationManager"> <authentication-provider> <password-encoder ref="passwordEncoder" /> <jdbc-user-service data-source-ref="dataSource" users-by-username-query="select username, password, true from Account where username = ?" authorities-by-username-query="select username, 'ROLE_USER' from Account where username = ?"/> </authentication-provider> <authentication-provider> <user-service> <user name="admin" password="admin" authorities="ROLE_USER, ROLE_ADMIN" /> </user-service> </authentication-provider> </authentication-manager> </beans:beans> And this is my try of implementing a UserDetailsService public class RepositoryUserDetailsService implements UserDetailsService { private final AccountRepository accountRepository; @Autowired public RepositoryUserDetailsService(AccountRepository repository) { this.accountRepository = repository; } @Override public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException { Account user = accountRepository.findAccountByUsername(username); if (user == null) { throw new UsernameNotFoundException("No user found with username: " + username); } return user; } } Still gives me the same error, do I need to add the UserDetailsService somewhere? This is starting to be something else compared to my initial question, I should maybe start another question. Sorry for my lack of experience in this. I have to read up.

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  • JDBC: What is the correct JDBC URL to connect to a RAC database

    - by Vinnie
    Hi, We were connecting to Oracle from our code with a simple (custom) JDBC connector class. This class reads the connection properties from a resource file and tries to make a connection to Oracle (thin connection). However, recently the database have moved to a RAC and now the application is unable to connect to the DB. Here is the TNSPING output: Used LDAP adapter to resolve the alias Attempting to contact (DESCRIPTION=(ADDRESS_LIST=(LOAD_BALANCE=OFF)(FAILOVER=ON) (ADDRESS=(PROTOCOL=TCP)(HOST=tst-db1.myco.com)(PORT=1604)) (ADDRESS=(PROTOCOL=TCP)(HOST=tst-db2.myco.com)(PORT=1604)))(CONNECT_DATA= SERVICE_NAME=mydb1.myco.com)(SERVER=DEDICATED))) OK (80 msec) What would be the correct URL to specify in this case. Regards, Ashish

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  • Infinite loop using Spring Security - Login page is protected even though it should allow anonymous

    - by Tai Squared
    I have a Spring application (Spring version 2.5.6.SEC01, Spring Security version 2.0.5) with the following setup: web.xml <welcome-file-list> <welcome-file> index.jsp </welcome-file> </welcome-file-list> The index.jsp page is in the WebContent directory and simply contains a redirect: <c:redirect url="/login.htm"/> In the appname-servlet.xml, there is a view resolver to point to the jsp pages in WEB-INF/jsp <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value=".jsp" /> </bean> In the security-config.xml file, I have the following configuration: <http> <!-- Restrict URLs based on role --> <intercept-url pattern="/WEB-INF/jsp/login.jsp*" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/WEB-INF/jsp/header.jsp*" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/WEB-INF/jsp/footer.jsp*" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/login*" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/index.jsp" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/logoutSuccess*" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/css/**" filters="none" /> <intercept-url pattern="/images/**" filters="none" /> <intercept-url pattern="/**" access="ROLE_ANONYMOUS" /> <form-login login-page="/login.jsp"/> </http> <authentication-provider> <jdbc-user-service data-source-ref="dataSource" /> </authentication-provider> However, I can't even navigate to the login page and get the following error in the log: WARNING: The login page is being protected by the filter chain, but you don't appear to have anonymous authentication enabled. This is almost certainly an error. I've tried changing the ROLE_ANONYMOUS to IS_AUTHENTICATED_ANONYMOUSLY, changing the login-page to index.jsp, login.htm, and adding different intercept-url values, but I can't get it so the login page is accesible and security applies to the other pages. What do I have to change to avoid this loop?

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  • How to expose an entity via alternate keys with spring data rest

    - by dan carter
    Spring-data-rest does a great job exposing entities via their primary key for GET, PUT and DELETE etc. operations. /myentityies/123 It also exposes search operations. /myentities/search/byMyOtherKey?myOtherKey=123 In my case the entities have a number of alternate keys. The systems calling us, will know the objects by these IDs, rather than our internal primary key. Is it possible to expose the objects via another URL and have the GET, PUT and DELETE handled by the built-in spring-data-rest controllers? /myentities/myotherkey/456 We'd like to avoid forcing the calling systems to have to make two requests for each update. I've tried playing with @RestResource path value, but there doesn't seem to be a way to add additional paths.

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  • Oracle JDBC intermittent Connection Issue

    - by Lipska
    I am experiencing a very strange problem This is a very simple use of JDBC connecting to an Oracle database OS: Ubuntu Java Version: 1.5.0_16-b02 1.6.0_17-b04 Database: Oracle 11g Release 11.1.0.6.0 When I make use of the jar file JODBC14.jar it connects to the database everytime When I make use of the jar file JODBC5.jar it connects some times and other times it throws an error ( shown below) If I recompile with Java 6 and use JODBC6.jar I get the same results as JODBC5.jar I need specific features in JODB5.jar that are not available in JODBC14.jar Any ideas Error Connecting to oracle java.sql.SQLException: Io exception: Connection reset at oracle.jdbc.driver.SQLStateMapping.newSQLException(SQLStateMapping.java:74) at oracle.jdbc.driver.DatabaseError.newSQLException(DatabaseError.java:110) at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:171) at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:227) at oracle.jdbc.driver.DatabaseError.throwSqlException(DatabaseError.java:494) at oracle.jdbc.driver.T4CConnection.logon(T4CConnection.java:411) at oracle.jdbc.driver.PhysicalConnection.(PhysicalConnection.java:490) at oracle.jdbc.driver.T4CConnection.(T4CConnection.java:202) at oracle.jdbc.driver.T4CDriverExtension.getConnection(T4CDriverExtension.java:33) at oracle.jdbc.driver.OracleDriver.connect(OracleDriver.java:474) at java.sql.DriverManager.getConnection(DriverManager.java:525) at java.sql.DriverManager.getConnection(DriverManager.java:171) at TestConnect.main(TestConnect.java:13) Code Below is the code I am using import java.io.; import java.sql.; public class TestConnect { public static void main(String[] args) { try { System.out.println("Connecting to oracle"); Connection con=null; Class.forName("oracle.jdbc.driver.OracleDriver"); con=DriverManager.getConnection( "jdbc:oracle:thin:@172.16.48.100:1535:sample", "JOHN", "90009000"); System.out.println("Connected to oracle"); con.close(); System.out.println("Goodbye"); } catch(Exception e){e.printStackTrace();} } }

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  • Strange Exception on getGeneratedKeys() with JDBC for MySQL 5.1

    - by sweeney
    Hello, I'm using JDBC to insert a row into a MYSQL database. I build a parameterized command, execute it and attempt to retrieve the auto generated keys as follows: String sql = "INSERT IGNORE INTO `users` (`email`, `pass-hash`) VALUES (?, ?)"; Connection conn = SQLAccess.getConnection(); PreparedStatement ps = conn.prepareStatement(sql); ps.setString(1, login); ps.setString(2, passHash); int count = ps.executeUpdate(); if (count == 1) { ResultSet rs = ps.getGeneratedKeys(); rs.next(); //some more stuff... } For some reason, I get the following SQLException on the line containing ResultSet rs = ps.getGeneratedKeys();: !Statement.Generated Keys Not Requested! Any thoughts? When I run the same query, as generated by running the app through the debugger, in a MySQL browser it executes without incident. Thanks, brian

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  • No flow definition found. Spring web flow

    - by user184794
    Hi, I am new to Spring webflow and now I am trying the example in Spring recipes book and I know this is a basic question. I am getting the error as follows, org.springframework.webflow.definition.registry.NoSuchFlowDefinitionException: No flow definition '${flowExecutionUrl}&_eventId=next' found at org.springframework.webflow.definition.registry.FlowDefinitionRegistryImpl.getFlowDefinitionHolder(FlowDefinitionRegistryImpl.java:126) at org.springframework.webflow.definition.registry.FlowDefinitionRegistryImpl.getFlowDefinition(FlowDefinitionRegistryImpl.java:61) at org.springframework.webflow.executor.FlowExecutorImpl.launchExecution(FlowExecutorImpl.java:138) at org.springframework.webflow.mvc.servlet.FlowHandlerAdapter.handle(FlowHandlerAdapter.java:193).... Shown below is my configurations, <bean name="flowController" class="org.springframework.webflow.mvc.servlet.FlowController"> <property name="flowExecutor" ref="flowExecutor"></property> </bean> <webflow:flow-executor id="flowExecutor" /> <webflow:flow-registry id="flowRegistry" > <webflow:flow-location path="/WEB-INF/flows/welcome/welcome.xml"></webflow:flow-location> </webflow:flow-registry> /WEB-INF/flows/welcome/welcome.xml, <view-state id="welcome"> <transition on="next" to="introduction" /> <transition on="skip" to="menu" /> </view-state> <view-state id="introduction"> <on-render> <evaluate expression="libraryService.getHolidays()" result="requestScope.holidays" /> </on-render> <transition on="next" to="menu" /> </view-state> <view-state id="menu"></view-state> In welcome.jsp, <a href="${flowExecutionUrl}&_eventId=next">Next</a> <a href="${flowExecutionUrl}&_eventId=skip">Skip</a> Please let me know what is going wrong. I am using 2.0.9 Release. Thanks in advance, SD

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