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  • Spring security request matcher is not working with regex

    - by Felipe Cardoso Martins
    Using Spring MVC + Security I have a business requirement that the users from SEC (Security team) has full access to the application and FRAUD (Anti-fraud team) has only access to the pages that URL not contains the words "block" or "update" with case insensitive. Bellow, all spring dependencies: $ mvn dependency:tree | grep spring [INFO] +- org.springframework:spring-webmvc:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-asm:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-beans:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-context:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-context-support:jar:3.1.2.RELEASE:compile [INFO] | \- org.springframework:spring-expression:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework:spring-core:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework:spring-web:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework.security:spring-security-core:jar:3.1.2.RELEASE:compile [INFO] | \- org.springframework:spring-aop:jar:3.0.7.RELEASE:compile [INFO] +- org.springframework.security:spring-security-web:jar:3.1.2.RELEASE:compile [INFO] | +- org.springframework:spring-jdbc:jar:3.0.7.RELEASE:compile [INFO] | \- org.springframework:spring-tx:jar:3.0.7.RELEASE:compile [INFO] +- org.springframework.security:spring-security-config:jar:3.1.2.RELEASE:compile [INFO] +- org.springframework.security:spring-security-acl:jar:3.1.2.RELEASE:compile Bellow, some examples of mapped URL path from spring log: Mapped URL path [/index] onto handler 'homeController' Mapped URL path [/index.*] onto handler 'homeController' Mapped URL path [/index/] onto handler 'homeController' Mapped URL path [/cellphone/block] onto handler 'cellphoneController' Mapped URL path [/cellphone/block.*] onto handler 'cellphoneController' Mapped URL path [/cellphone/block/] onto handler 'cellphoneController' Mapped URL path [/cellphone/confirmBlock] onto handler 'cellphoneController' Mapped URL path [/cellphone/confirmBlock.*] onto handler 'cellphoneController' Mapped URL path [/cellphone/confirmBlock/] onto handler 'cellphoneController' Mapped URL path [/user/update] onto handler 'userController' Mapped URL path [/user/update.*] onto handler 'userController' Mapped URL path [/user/update/] onto handler 'userController' Mapped URL path [/user/index] onto handler 'userController' Mapped URL path [/user/index.*] onto handler 'userController' Mapped URL path [/user/index/] onto handler 'userController' Mapped URL path [/search] onto handler 'searchController' Mapped URL path [/search.*] onto handler 'searchController' Mapped URL path [/search/] onto handler 'searchController' Mapped URL path [/doSearch] onto handler 'searchController' Mapped URL path [/doSearch.*] onto handler 'searchController' Mapped URL path [/doSearch/] onto handler 'searchController' Bellow, a test of the regular expressions used in spring-security.xml (I'm not a regex speciality, improvements are welcome =]): import java.util.Arrays; import java.util.List; public class RegexTest { public static void main(String[] args) { List<String> pathSamples = Arrays.asList( "/index", "/index.*", "/index/", "/cellphone/block", "/cellphone/block.*", "/cellphone/block/", "/cellphone/confirmBlock", "/cellphone/confirmBlock.*", "/cellphone/confirmBlock/", "/user/update", "/user/update.*", "/user/update/", "/user/index", "/user/index.*", "/user/index/", "/search", "/search.*", "/search/", "/doSearch", "/doSearch.*", "/doSearch/"); for (String pathSample : pathSamples) { System.out.println("Path sample: " + pathSample + " - SEC: " + pathSample.matches("^.*$") + " | FRAUD: " + pathSample.matches("^(?!.*(?i)(block|update)).*$")); } } } Bellow, the console result of Java class above: Path sample: /index - SEC: true | FRAUD: true Path sample: /index.* - SEC: true | FRAUD: true Path sample: /index/ - SEC: true | FRAUD: true Path sample: /cellphone/block - SEC: true | FRAUD: false Path sample: /cellphone/block.* - SEC: true | FRAUD: false Path sample: /cellphone/block/ - SEC: true | FRAUD: false Path sample: /cellphone/confirmBlock - SEC: true | FRAUD: false Path sample: /cellphone/confirmBlock.* - SEC: true | FRAUD: false Path sample: /cellphone/confirmBlock/ - SEC: true | FRAUD: false Path sample: /user/update - SEC: true | FRAUD: false Path sample: /user/update.* - SEC: true | FRAUD: false Path sample: /user/update/ - SEC: true | FRAUD: false Path sample: /user/index - SEC: true | FRAUD: true Path sample: /user/index.* - SEC: true | FRAUD: true Path sample: /user/index/ - SEC: true | FRAUD: true Path sample: /search - SEC: true | FRAUD: true Path sample: /search.* - SEC: true | FRAUD: true Path sample: /search/ - SEC: true | FRAUD: true Path sample: /doSearch - SEC: true | FRAUD: true Path sample: /doSearch.* - SEC: true | FRAUD: true Path sample: /doSearch/ - SEC: true | FRAUD: true Tests Scenario 1 Bellow, the important part of spring-security.xml: <security:http entry-point-ref="entryPoint" request-matcher="regex"> <security:intercept-url pattern="^.*$" access="ROLE_SEC" /> <security:intercept-url pattern="^(?!.*(?i)(block|update)).*$" access="ROLE_FRAUD" /> <security:access-denied-handler error-page="/access-denied.html" /> <security:form-login always-use-default-target="false" login-processing-url="/doLogin.html" authentication-failure-handler-ref="authFailHandler" authentication-success-handler-ref="authSuccessHandler" /> <security:logout logout-url="/logout.html" success-handler-ref="logoutSuccessHandler" /> </security:http> Behaviour: FRAUD group **can't" access any page SEC group works fine Scenario 2 NOTE that I only changed the order of intercept-url in spring-security.xml bellow: <security:http entry-point-ref="entryPoint" request-matcher="regex"> <security:intercept-url pattern="^(?!.*(?i)(block|update)).*$" access="ROLE_FRAUD" /> <security:intercept-url pattern="^.*$" access="ROLE_SEC" /> <security:access-denied-handler error-page="/access-denied.html" /> <security:form-login always-use-default-target="false" login-processing-url="/doLogin.html" authentication-failure-handler-ref="authFailHandler" authentication-success-handler-ref="authSuccessHandler" /> <security:logout logout-url="/logout.html" success-handler-ref="logoutSuccessHandler" /> </security:http> Behaviour: SEC group **can't" access any page FRAUD group works fine Conclusion I did something wrong or spring-security have a bug. The problem already was solved in a very bad way, but I need to fix it quickly. Anyone knows some tricks to debug better it without open the frameworks code? Cheers, Felipe

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  • Spring MVC annotation config problem

    - by Seth
    I'm trying to improve my spring mvc configuration so as to not require a new config file for every servlet I add, but I'm running into problems. I've tried using this tutorial as a starting point, but I'm running into an issue that I can't figure out. The problem is that when I do a GET to my servlet, I get back a 404 error. Here's my config and a representative java snippet from a Controller: web.xml: <?xml version="1.0" encoding="UTF-8"?> <web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"> <display-name>SightLogix Coordination System</display-name> <description>SightLogix Coordination System</description> <servlet> <servlet-name>Spring MVC Dispatcher Servlet</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/application-context.xml /WEB-INF/application-security.xml </param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>Spring MVC Dispatcher Servlet</servlet-name> <url-pattern>/slcs/*</url-pattern> </servlet-mapping> <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/application-context.xml /WEB-INF/application-security.xml </param-value> </context-param> <listener> <listener-class> org.springframework.web.context.ContextLoaderListener </listener-class> </listener> <filter> <filter-name>springSecurityFilterChain</filter-name> <filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class> </filter> <filter-mapping> <filter-name>springSecurityFilterChain</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> </web-app> application-context.xml: <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:mvc="http://www.springframework.org/schema/mvc" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation=" http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/mvc http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd" default-init-method="init" default-destroy-method="destroy"> <mvc:annotation-driven /> <context:component-scan base-package="top.level" /> </beans> application-security.xml: <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <http> <intercept-url pattern="/**" access="ROLE_MANAGER" requires-channel="https" /> <http-basic /> </http> <authentication-manager> <authentication-provider user-service-ref="myUserDetailsService"> <password-encoder hash="sha"/> </authentication-provider> </authentication-manager> <beans:bean id="myUserDetailsService" class="path.to.my.UserDetailsServiceImpl"> </beans:bean> </beans:beans> Snippet of a Controller class (one of many, but they all look essentially like this): @Controller @RequestMapping("/foo.xml") public class FooController { @RequestMapping(method=RequestMethod.GET) public void handleGET(HttpServletRequest request, HttpServletResponse response) throws IOException { ... Can anyone tell me what I'm doing incorrectly? Thanks!

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  • How can I Convert XML to an Object using Spring 3.0 mvc while making RESTful request

    - by brock
    Hi, I'm using the Spring 3.0 RC1 framework and I'm currently testing out Spring mvc. I wanted to use Spring mvc to handle restful requests. I have set up my controller to handle the URI request. I am passing in xml with the request. So on the controller I have a method like follows: public void request(RequestObject request) { doSomething(); } I am having a hard time converting the xml to the RequestObject. I haven't seen much documentation on this and I was wondering if anyone could point me in the right direction. I'm guess that you would have to annotate the RequestObject using JAXB or something in order to tell Spring to convert the xml file to RequestObject but I'm not sure. Thanks for all of your help!!

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  • How to implement login page using Spring Security so that it works with Spring web flow?

    - by simon
    I have a web application using Spring 2.5.6 and Spring Security 2.0.4. I have implemented a working login page, which authenticates the user against a web service. The authentication is done by defining a custom authentincation manager, like this: <beans:bean id="customizedFormLoginFilter" class="org.springframework.security.ui.webapp.AuthenticationProcessingFilter"> <custom-filter position="AUTHENTICATION_PROCESSING_FILTER" /> <beans:property name="defaultTargetUrl" value="/index.do" /> <beans:property name="authenticationFailureUrl" value="/login.do?error=true" /> <beans:property name="authenticationManager" ref="customAuthenticationManager" /> <beans:property name="allowSessionCreation" value="true" /> </beans:bean> <beans:bean id="customAuthenticationManager" class="com.sevenp.mobile.samplemgmt.web.security.CustomAuthenticationManager"> <beans:property name="authenticateUrlWs" value="${WS_ENDPOINT_ADDRESS}" /> </beans:bean> The authentication manager class: public class CustomAuthenticationManager implements AuthenticationManager, ApplicationContextAware { @Transactional @Override public Authentication authenticate(Authentication authentication) throws AuthenticationException { //authentication logic return new UsernamePasswordAuthenticationToken(principal, authentication.getCredentials(), grantedAuthorityArray); } The essential part of the login jsp looks like this: <c:url value="/j_spring_security_check" var="formUrlSecurityCheck"/> <form method="post" action="${formUrlSecurityCheck}"> <div id="errorArea" class="errorBox"> <c:if test="${not empty param.error}"> ${sessionScope["SPRING_SECURITY_LAST_EXCEPTION"].message} </c:if> </div> <label for="loginName"> Username: <input style="width:125px;" tabindex="1" id="login" name="j_username" /> </label> <label for="password"> Password: <input style="width:125px;" tabindex="2" id="password" name="j_password" type="password" /> </label> <input type="submit" tabindex="3" name="login" class="formButton" value="Login" /> </form> Now the problem is that the application should use Spring Web Flow. After the application was configured to use Spring Web Flow, the login does not work anymore - the form action to "/j_spring_security_check" results in a blank page without error message. What is the best way to adapt the existing login process so that it works with Spring Web Flow?

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  • How to read spring-application-context.xml and AnnotationConfigWebApplicationContext both in spring mvc

    - by Suvasis
    In case I want to read bean definitions from spring-application-context.xml, I would do this in web.xml file. <context-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/applicationContext.xml </param-value> </context-param> <listener> <listener-class>org.springframework.web.context.ContextLoaderListener</listener-class> </listener> In case I want to read bean definitions through Java Configuration Class (AnnotationConfigWebApplicationContext), I would do this in web.xml <servlet> <servlet-name>appServlet</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <init-param> <param-name>contextClass</param-name> <param-value> org.springframework.web.context.support.AnnotationConfigWebApplicationContext </param-value> </init-param> <init-param> <param-name>contextConfigLocation</param-name> <param-value> org.package.MyConfigAnnotatedClass </param-value> </init-param> </servlet> How do I use both in my application. like reading beans from both configuration xml file and annotated class. Is there a way to load spring beans in xml file while we are using AppConfigAnnotatedClass to instantiate/use rest of the beans.

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  • Howcan I get started with Spring Batch?

    - by C. Ross
    I'm trying to learn Spring Batch, but the startup guide is very confusing. Comments like You can get a pretty good idea about how to set up a job by examining the unit tests in the org.springframework.batch.sample package (in src/main/java) and the configuration in src/main/resources/jobs. aren't exactly helpful. Also I find the Sample project very complicated (17 non-empty Namespaces with 109 classes)! Is there a simpler place to get started with Spring Batch?

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  • What are annotations and how do they actually work for frameworks like Spring?

    - by Rachel
    I am new to Spring and now a days I hear a lot about Spring Framework. I have two sets of very specific questions: Set No. 1: What are annotations in general ? How does annotations works specifically with Spring framework ? Can annotations be used outside Spring Framework or are they Framework specific ? Set No. 2: What module of Spring Framework is widely used in Industry ? I think it is Spring MVC but why it is the most used module, if am correct or correct me on this ? I am newbie to Spring and so feel free to edit this questions to make more sense.

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  • What is annotations and how do it actually works for frameworks like Spring ?

    - by Rachel
    I am new to Spring and now a days I hear a lot about Spring Framework. I have two sets of very specific questions: Set No. 1: What are annotations in general ? How does annotations works specifically with Spring framework ? Can annotations be used outside Spring Framework or are they Framework specific ? Set No. 2: What module of Spring Framework is widely used in Industry ? I think it is Spring MVC but why it is the most used module, if am correct or correct me on this ? I am newbie to Spring and so feel free to edit this questions to make more sense.

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  • Spring @PostConstruct function in a @Repository called multiple times

    - by Seth
    I have a DAO that I'm trying to inject into a couple different places: @Repository public class FooDAO { @Autowired private HibernateManager sessionFactory; @PostConstruct public void doSomeDatabaseStuff() throws DataAccessException { ... } } And my application-context.xml is a fairly simple context:component-scan: <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-2.5.xsd" default-init-method="init" default-destroy-method="destroy"> <context:component-scan base-package="top.level"/> </beans> The DAO is accessed from a couple servlets in my application server through @Autowired properties. As far as I understand, anything annotated with @Repository should default to being a singleton and thus doSomeDatabaseStuff() should only be called once (as is my intention). The problem is that I'm seeing doSomeDatabaseStuff() called multiple times. What's going on here? Have I set something up incorrectly? I'm using spring 3.0.0. Thanks for the help.

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  • Spring security - Reach users ID without passing it through every controller

    - by nilsi
    I have a design issue that I don't know how to solve. I'm using Spring 3.2.4 and Spring security 3.1.4. I have a Account table in my database that looks like this: create table Account (id identity, username varchar unique, password varchar not null, firstName varchar not null, lastName varchar not null, university varchar not null, primary key (id)); Until recently my username was just only a username but I changed it to be the email address instead since many users want to login with that instead. I have a header that I include on all my pages which got a link to the users profile like this: <a href="/project/users/<%= request.getUserPrincipal().getName()%>" class="navbar-link"><strong><%= request.getUserPrincipal().getName()%></strong></a> The problem is that <%= request.getUserPrincipal().getName()%> returns the email now, I don't want to link the user's with thier emails. Instead I want to use the id every user have to link to the profile. How do I reach the users id's from every page? I have been thinking of two solutions but I'm not sure: Change the principal to contain the id as well, don't know how to do this and having problem finding good information on the topic. Add a model attribute to all my controllers that contain the whole user but this would be really ugly, like this. Account account = entityManager.find(Account.class, email); model.addAttribute("account", account); There are more way's as well and I have no clue which one is to prefer. I hope it's clear enough and thank you for any help on this. ====== Edit according to answer ======= I edited Account to implement UserDetails, it now looks like this (will fix the auto generated stuff later): @Entity @Table(name="Account") public class Account implements UserDetails { @Id private int id; private String username; private String password; private String firstName; private String lastName; @ManyToOne private University university; public Account() { } public Account(String username, String password, String firstName, String lastName, University university) { this.username = username; this.password = password; this.firstName = firstName; this.lastName = lastName; this.university = university; } public String getUsername() { return username; } public String getPassword() { return password; } public String getFirstName() { return firstName; } public String getLastName() { return lastName; } public void setUsername(String username) { this.username = username; } public void setPassword(String password) { this.password = password; } public void setFirstName(String firstName) { this.firstName = firstName; } public void setLastName(String lastName) { this.lastName = lastName; } public University getUniversity() { return university; } public void setUniversity(University university) { this.university = university; } public int getId() { return id; } public void setId(int id) { this.id = id; } @Override public Collection<? extends GrantedAuthority> getAuthorities() { // TODO Auto-generated method stub return null; } @Override public boolean isAccountNonExpired() { // TODO Auto-generated method stub return false; } @Override public boolean isAccountNonLocked() { // TODO Auto-generated method stub return false; } @Override public boolean isCredentialsNonExpired() { // TODO Auto-generated method stub return false; } @Override public boolean isEnabled() { // TODO Auto-generated method stub return true; } } I also added <%@ taglib prefix="sec" uri="http://www.springframework.org/security/tags" %> To my jsp files and trying to reach the id by <sec:authentication property="principal.id" /> This gives me the following org.springframework.beans.NotReadablePropertyException: Invalid property 'principal.id' of bean class [org.springframework.security.authentication.UsernamePasswordAuthenticationToken]: Bean property 'principal.id' is not readable or has an invalid getter method: Does the return type of the getter match the parameter type of the setter? ====== Edit 2 according to answer ======= I based my application on spring social samples and I never had to change anything until now. This are the files I think are relevant, please tell me if theres something you need to see besides this. AccountRepository.java public interface AccountRepository { void createAccount(Account account) throws UsernameAlreadyInUseException; Account findAccountByUsername(String username); } JdbcAccountRepository.java @Repository public class JdbcAccountRepository implements AccountRepository { private final JdbcTemplate jdbcTemplate; private final PasswordEncoder passwordEncoder; @Inject public JdbcAccountRepository(JdbcTemplate jdbcTemplate, PasswordEncoder passwordEncoder) { this.jdbcTemplate = jdbcTemplate; this.passwordEncoder = passwordEncoder; } @Transactional public void createAccount(Account user) throws UsernameAlreadyInUseException { try { jdbcTemplate.update( "insert into Account (firstName, lastName, username, university, password) values (?, ?, ?, ?, ?)", user.getFirstName(), user.getLastName(), user.getUsername(), user.getUniversity(), passwordEncoder.encode(user.getPassword())); } catch (DuplicateKeyException e) { throw new UsernameAlreadyInUseException(user.getUsername()); } } public Account findAccountByUsername(String username) { return jdbcTemplate.queryForObject("select username, firstName, lastName, university from Account where username = ?", new RowMapper<Account>() { public Account mapRow(ResultSet rs, int rowNum) throws SQLException { return new Account(rs.getString("username"), null, rs.getString("firstName"), rs.getString("lastName"), new University("test")); } }, username); } } security.xml <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:beans="http://www.springframework.org/schema/beans" xsi:schemaLocation="http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd"> <http pattern="/resources/**" security="none" /> <http pattern="/project/" security="none" /> <http use-expressions="true"> <!-- Authentication policy --> <form-login login-page="/signin" login-processing-url="/signin/authenticate" authentication-failure-url="/signin?error=bad_credentials" /> <logout logout-url="/signout" delete-cookies="JSESSIONID" /> <intercept-url pattern="/addcourse" access="isAuthenticated()" /> <intercept-url pattern="/courses/**/**/edit" access="isAuthenticated()" /> <intercept-url pattern="/users/**/edit" access="isAuthenticated()" /> </http> <authentication-manager alias="authenticationManager"> <authentication-provider> <password-encoder ref="passwordEncoder" /> <jdbc-user-service data-source-ref="dataSource" users-by-username-query="select username, password, true from Account where username = ?" authorities-by-username-query="select username, 'ROLE_USER' from Account where username = ?"/> </authentication-provider> <authentication-provider> <user-service> <user name="admin" password="admin" authorities="ROLE_USER, ROLE_ADMIN" /> </user-service> </authentication-provider> </authentication-manager> </beans:beans> And this is my try of implementing a UserDetailsService public class RepositoryUserDetailsService implements UserDetailsService { private final AccountRepository accountRepository; @Autowired public RepositoryUserDetailsService(AccountRepository repository) { this.accountRepository = repository; } @Override public UserDetails loadUserByUsername(String username) throws UsernameNotFoundException { Account user = accountRepository.findAccountByUsername(username); if (user == null) { throw new UsernameNotFoundException("No user found with username: " + username); } return user; } } Still gives me the same error, do I need to add the UserDetailsService somewhere? This is starting to be something else compared to my initial question, I should maybe start another question. Sorry for my lack of experience in this. I have to read up.

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  • Infinite loop using Spring Security - Login page is protected even though it should allow anonymous

    - by Tai Squared
    I have a Spring application (Spring version 2.5.6.SEC01, Spring Security version 2.0.5) with the following setup: web.xml <welcome-file-list> <welcome-file> index.jsp </welcome-file> </welcome-file-list> The index.jsp page is in the WebContent directory and simply contains a redirect: <c:redirect url="/login.htm"/> In the appname-servlet.xml, there is a view resolver to point to the jsp pages in WEB-INF/jsp <bean id="viewResolver" class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value=".jsp" /> </bean> In the security-config.xml file, I have the following configuration: <http> <!-- Restrict URLs based on role --> <intercept-url pattern="/WEB-INF/jsp/login.jsp*" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/WEB-INF/jsp/header.jsp*" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/WEB-INF/jsp/footer.jsp*" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/login*" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/index.jsp" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/logoutSuccess*" access="ROLE_ANONYMOUS" /> <intercept-url pattern="/css/**" filters="none" /> <intercept-url pattern="/images/**" filters="none" /> <intercept-url pattern="/**" access="ROLE_ANONYMOUS" /> <form-login login-page="/login.jsp"/> </http> <authentication-provider> <jdbc-user-service data-source-ref="dataSource" /> </authentication-provider> However, I can't even navigate to the login page and get the following error in the log: WARNING: The login page is being protected by the filter chain, but you don't appear to have anonymous authentication enabled. This is almost certainly an error. I've tried changing the ROLE_ANONYMOUS to IS_AUTHENTICATED_ANONYMOUSLY, changing the login-page to index.jsp, login.htm, and adding different intercept-url values, but I can't get it so the login page is accesible and security applies to the other pages. What do I have to change to avoid this loop?

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  • How to expose an entity via alternate keys with spring data rest

    - by dan carter
    Spring-data-rest does a great job exposing entities via their primary key for GET, PUT and DELETE etc. operations. /myentityies/123 It also exposes search operations. /myentities/search/byMyOtherKey?myOtherKey=123 In my case the entities have a number of alternate keys. The systems calling us, will know the objects by these IDs, rather than our internal primary key. Is it possible to expose the objects via another URL and have the GET, PUT and DELETE handled by the built-in spring-data-rest controllers? /myentities/myotherkey/456 We'd like to avoid forcing the calling systems to have to make two requests for each update. I've tried playing with @RestResource path value, but there doesn't seem to be a way to add additional paths.

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  • Project generation problem using Spring Roo

    - by Harry
    Hi, I just downloaded SpringSource Tool Suite, and tried to generate a demo application using roo, but i'm getting error below Code: Created /home/dev/springsource/workspace/demo/pom.xml Undo create /home/dev/springsource/workspace/demo/pom.xml Invalid dependency scope: PROVIDED [Timer-0] NullPointerException at org.springframework.roo.classpath.itd.AbstractItdMetadataProvider.notify(AbstractItdMetadataProvider.java:84) What is the problem? is this Maven issue? Using: Ubuntu 8.10, SpringSource Tool Suite Version: 2.3.3.M1, Roo 1.1.0.M1, Apache Maven Thanks

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  • No flow definition found. Spring web flow

    - by user184794
    Hi, I am new to Spring webflow and now I am trying the example in Spring recipes book and I know this is a basic question. I am getting the error as follows, org.springframework.webflow.definition.registry.NoSuchFlowDefinitionException: No flow definition '${flowExecutionUrl}&_eventId=next' found at org.springframework.webflow.definition.registry.FlowDefinitionRegistryImpl.getFlowDefinitionHolder(FlowDefinitionRegistryImpl.java:126) at org.springframework.webflow.definition.registry.FlowDefinitionRegistryImpl.getFlowDefinition(FlowDefinitionRegistryImpl.java:61) at org.springframework.webflow.executor.FlowExecutorImpl.launchExecution(FlowExecutorImpl.java:138) at org.springframework.webflow.mvc.servlet.FlowHandlerAdapter.handle(FlowHandlerAdapter.java:193).... Shown below is my configurations, <bean name="flowController" class="org.springframework.webflow.mvc.servlet.FlowController"> <property name="flowExecutor" ref="flowExecutor"></property> </bean> <webflow:flow-executor id="flowExecutor" /> <webflow:flow-registry id="flowRegistry" > <webflow:flow-location path="/WEB-INF/flows/welcome/welcome.xml"></webflow:flow-location> </webflow:flow-registry> /WEB-INF/flows/welcome/welcome.xml, <view-state id="welcome"> <transition on="next" to="introduction" /> <transition on="skip" to="menu" /> </view-state> <view-state id="introduction"> <on-render> <evaluate expression="libraryService.getHolidays()" result="requestScope.holidays" /> </on-render> <transition on="next" to="menu" /> </view-state> <view-state id="menu"></view-state> In welcome.jsp, <a href="${flowExecutionUrl}&_eventId=next">Next</a> <a href="${flowExecutionUrl}&_eventId=skip">Skip</a> Please let me know what is going wrong. I am using 2.0.9 Release. Thanks in advance, SD

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  • spring-roo dojox.grid.DataGrid not rendered

    - by Steve Wall
    Hello, I'm using spring-roo trying to use dojox.grid.DataGrid. The page renders as a plain table. Why does it not use the DataGrid? Thanks! Steve <div xmlns:spring="http://www.springframework.org/tags" xmlns:c="http://java.sun.com/jsp/jstl/core" xmlns:jsp="http://java.sun.com/JSP/Page" version="2.0"><jsp:output omit-xml-declaration="yes" /> <script type="text/javascript"> dojo.require("dijit.TitlePane"); </script> <script type="text/javascript" src="&lt;c:url value=&quot;/resources/dojo/dojo.js&quot; /&gt;"> </script> <script type="text/javascript" src="&lt;c:url value=&quot;/resources/spring/Spring.js&quot; /&gt;"> </script> <script type="text/javascript" src="&lt;c:url value=&quot;/resources/spring/Spring-Dojo.js&quot; /&gt;"> </script> <script type="text/javascript"> dojo.require("dojox.grid.DataGrid"); dojo.require("dojox.data.CsvStore"); </script> <div id="_title"><spring:message var="app_name" code="application.name" /> <spring:message var="title" code="welcome.titlepane" arguments="${app_name}" /> <script type="text/javascript"> Spring.addDecoration(new Spring.ElementDecoration( { elementId : '_title', widgetType : 'dijit.TitlePane', widgetAttrs : { title : '${title}' } })); </script> <h4>Title</h4> <table dojoType="dojox.grid.DataGrid"> <thead> <tr> <th field="fieldName" width="200px">Column Name</th> <th field="fieldName" width="200px">Column Name</th> </tr> </thead> <tbody> <tr> <td>test1</td> <td>test2</td> </tr> <tr> <td>test3</td> <td>test4</td> </tr> </tbody> </table> </div> </div>

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  • Spring security problem, Error creating bean with name 'org.springframework.web.servlet.mvc.annotati

    - by benaissa
    Hello; I'm developping a web application with spring mvc, i started by developping the web application after i'm trying to add spring security; but i have this message, and i don't find a solution, thanks 16-04-2010 12:10:22:296 6062 ERROR org.springframework.web.servlet.DispatcherServlet - Context initialization failed org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping': Initialization of bean failed; nested exception is java.lang.NoClassDefFoundError: org/springframework/beans/factory/generic/GenericBeanFactoryAccessor at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:527) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:456) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:286) at org.springframework.web.servlet.DispatcherServlet.createDefaultStrategy(DispatcherServlet.java:770) at org.springframework.web.servlet.DispatcherServlet.getDefaultStrategies(DispatcherServlet.java:737) at org.springframework.web.servlet.DispatcherServlet.initHandlerMappings(DispatcherServlet.java:518) at org.springframework.web.servlet.DispatcherServlet.initStrategies(DispatcherServlet.java:410) at org.springframework.web.servlet.DispatcherServlet.onRefresh(DispatcherServlet.java:398) at org.springframework.web.servlet.FrameworkServlet.onApplicationEvent(FrameworkServlet.java:474) at org.springframework.context.event.GenericApplicationListenerAdapter.onApplicationEvent(GenericApplicationListenerAdapter.java:51) at org.springframework.context.event.SourceFilteringListener.onApplicationEventInternal(SourceFilteringListener.java:97) at org.springframework.context.event.SourceFilteringListener.onApplicationEvent(SourceFilteringListener.java:68) at org.springframework.context.event.SimpleApplicationEventMulticaster.multicastEvent(SimpleApplicationEventMulticaster.java:97) at org.springframework.context.support.AbstractApplicationContext.publishEvent(AbstractApplicationContext.java:301) at org.springframework.context.support.AbstractApplicationContext.finishRefresh(AbstractApplicationContext.java:888) at org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:426) at org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:402) at org.springframework.web.servlet.FrameworkServlet.initWebApplicationContext(FrameworkServlet.java:316) at org.springframework.web.servlet.FrameworkServlet.initServletBean(FrameworkServlet.java:282) at org.springframework.web.servlet.HttpServletBean.init(HttpServletBean.java:126) at javax.servlet.GenericServlet.init(GenericServlet.java:212) at org.apache.catalina.core.StandardWrapper.loadServlet(StandardWrapper.java:1173) at org.apache.catalina.core.StandardWrapper.allocate(StandardWrapper.java:809) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:129) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:852) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:588) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:489) at java.lang.Thread.run(Thread.java:619) Caused by: java.lang.NoClassDefFoundError: org/springframework/beans/factory/generic/GenericBeanFactoryAccessor at org.springframework.web.servlet.mvc.annotation.DefaultAnnotationHandlerMapping.determineUrlsForHandler(DefaultAnnotationHandlerMapping.java:113) at org.springframework.web.servlet.handler.AbstractDetectingUrlHandlerMapping.detectHandlers(AbstractDetectingUrlHandlerMapping.java:79) at org.springframework.web.servlet.handler.AbstractDetectingUrlHandlerMapping.initApplicationContext(AbstractDetectingUrlHandlerMapping.java:57) at org.springframework.context.support.ApplicationObjectSupport.initApplicationContext(ApplicationObjectSupport.java:119) at org.springframework.web.context.support.WebApplicationObjectSupport.initApplicationContext(WebApplicationObjectSupport.java:69) at org.springframework.context.support.ApplicationObjectSupport.setApplicationContext(ApplicationObjectSupport.java:73) at org.springframework.context.support.ApplicationContextAwareProcessor.invokeAwareInterfaces(ApplicationContextAwareProcessor.java:99) at org.springframework.context.support.ApplicationContextAwareProcessor.postProcessBeforeInitialization(ApplicationContextAwareProcessor.java:82) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.applyBeanPostProcessorsBeforeInitialization(AbstractAutowireCapableBeanFactory.java:394) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.initializeBean(AbstractAutowireCapableBeanFactory.java:1405) at org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:519) ... 32 more Caused by: java.lang.ClassNotFoundException: org.springframework.beans.factory.generic.GenericBeanFactoryAccessor at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1516) at org.apache.catalina.loader.WebappClassLoader.loadClass(WebappClassLoader.java:1361) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320) ... 43 more

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  • Spring redirecting back to referrer

    - by Eqbal
    I have some resources in my application that require redirection to another resource (form) if some context information is not set. After the context gets set (requires two user steps), I need to redirect back to the requested resource. How do I achieve that. I am using annotation based controllers in Spring 3. Is org.springframework.security.web.savedrequest.HttpSessionRequestCache of any use.

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  • Spring Web MVC: Use same request mapping for request parameter and path variable

    - by ngeek
    Good people: is there a way to express that my Spring Web MVC controller method should be matched either by a request handing in a ID as part of the URI path ... @RequestMapping(method=RequestMethod.GET, value="campaigns/{id}") public String getCampaignDetails(Model model, @PathVariable("id") Long id) { ... or if the client sends in the ID as a HTTP request parameter in the style ... @RequestMapping(method=RequestMethod.GET, value="campaigns") public String getCampaignDetails(Model model, @RequestParam("id") Long id) { This seems to me a quite common real-world URL scheme where I don't want to add duplicate code, but I wasn't able to find an answer yet. Any advice highly welcome.

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  • Spring Security 3.0 and Active Directory LDAP: DOMAIN\user login

    - by Bernd Haug
    I would like to have users authenticate against an ActiveDirectory LDAP server using the DOMAIN\user.name syntax. I think that should be possible with SpringSec 3.0 since the docs mention an "alternative syntax" which I guess refers to the DOM\user syntax instead of a bind DN, but the docs don't elaborate further. Is there some way to configure Spring Sec 3 LDAP to use "the MS way" or do I have to write my own Authenticator implementation (against e.g. the java.naming.directory package, which I've tested to be able to use the MS syntax as its SECURITY_PRINCIPAL)?

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  • Httpsession with Spring 3 MVC

    - by vipul12389
    I want to use httpsession in Spring 3 MVC..i have searched all the web and got this solution..at http://forum.springsource.org/showthread.php?98850-Adding-to-stuff-to-the-session-while-using-ResponseBody Basically, My application auto authenticates user by getting winId and authorizes through LDAP..(Its a intranet site) Here is the flow of the application, 1. User enters Aplication url (http://localhost:8082/eIA_Mock_5) it has a welcome page (index.jsp) Index.jsp gets winId through jQuery and hits login.html (through Ajax) and passes windowsId login.html (Controller) authenticates through LDAP and gives back 'Valid' String as a response javascript, upon getting the correct response, redirects/loads welcome page i.e. goes to localhost:8082/eIA_Mock_5/welcome.html Now, i have filter associated with it..which checks for is session valid for each incoming request..Now the problem is even though i set data on to httpsession, yet the filter or any other controller fails to get the data through session as a result it doesnt proceeds further.. here is the code..and could you suggest what is wrong actually ?? Home_Controller.java @Controller public class Home_Controller { public static Log logger = LogFactory.getLog(Home_Controller.class); @RequestMapping(value={"/welcome"}) public ModelAndView loadWelcomePage(HttpServletRequest request,HttpServletResponse response) { ModelAndView mdv = new ModelAndView(); try{ /*HttpSession session = request.getSession(); UserMasterBean userBean = (UserMasterBean)session.getAttribute("userBean"); String userName=userBean.getWindowsId(); if(userName==null || userName.equalsIgnoreCase("")) { mdv.setViewName("homePage"); System.out.println("Unable to authenticate user "); logger.debug("Unable to authenticate user "); } else { System.out.println("Welcome User "+userName); logger.debug("Welcome User "+userName); */ mdv.setViewName("homePage"); /*}*/ } catch(Exception e){ logger.debug("inside authenticateUser ",e); e.printStackTrace(); } return mdv; } @RequestMapping(value = "/login", method = RequestMethod.GET) public @ResponseBody String authenticateUser(@RequestParam String userName,HttpSession session) { logger.debug("inside authenticateUser"); String returnResponse=new String(); try{ logger.debug("userName for Authentication "+userName); System.out.println("userName for Authentication "+userName); //HttpSession session = request.getSession(); if(userName==null || userName.trim().equalsIgnoreCase("")) returnResponse="Invalid"; else { System.out.println("uname "+userName); String ldapResponse = LDAPConnectUtil.isValidActiveDirectoryUser(userName, ""); if(ldapResponse.equalsIgnoreCase("true")) { returnResponse="Valid"; System.out.println(userName+" Authenticated"); logger.debug(userName+" Authenticated"); UserMasterBean userBean = new UserMasterBean(); userBean.setWindowsId(userName); //if(session.getAttribute("userBean")==null) session.setAttribute("userBean", userBean); } else { returnResponse="Invalid"; //session.setAttribute("userBean", null); System.out.println("Unable to Authenticate the user through Ldap"); logger.debug("Unable to Authenticate the user through Ldap"); } System.out.println("ldapResponse "+ldapResponse); logger.debug("ldapResponse "+ldapResponse); System.out.println("returnResponse "+returnResponse); } UserMasterBean u = (UserMasterBean)session.getAttribute("userBean"); System.out.println("winId "+u.getWindowsId()); } catch(Exception e){ e.printStackTrace(); logger.debug("Exception in authenticateUser ",e); } return returnResponse; } Filter public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) { System.out.println("in PageFilter"); boolean flag = false; HttpServletRequest objHttpServletRequest = (HttpServletRequest)request; HttpServletResponse objHttpServletResponse = (HttpServletResponse)response; HttpSession session = objHttpServletRequest.getSession(); String contextPath = objHttpServletRequest.getContextPath(); String servletPath = objHttpServletRequest.getSession().getServletContext().getRealPath(objHttpServletRequest.getServletPath()); logger.debug("contextPath :" + contextPath); logger.debug("servletPath :" + servletPath); System.out.println("in PageFilter, contextPath :" + contextPath); System.out.println("in PageFilter, servletPath :" + servletPath); if (servletPath.endsWith("\\") || servletPath.endsWith("/") || servletPath.indexOf("css") > 0 || servletPath.indexOf("jsp") > 0 || servletPath.indexOf("images") > 0 || servletPath.indexOf("js") > 0 || servletPath.endsWith("index.jsp") || servletPath.indexOf("xls") > 0 || servletPath.indexOf("ini") > 0 || servletPath.indexOf("login.html") > 0 || /*servletPath.endsWith("welcome.html") ||*/ servletPath.endsWith("logout.do") ) { System.out.println("User is trying to access allowed pages like Login.jsp, errorPage.jsp, js, images, css"); logger.debug("User is trying to access allowed pages like Login.jsp, errorPage.jsp, js, images, css"); flag = true; } if (flag== false) { System.out.println("flag = false"); if(session.getAttribute("userBean") == null) System.out.println("yes session.userbean is null"); if ((session != null) && (session.getAttribute("userBean") != null)) { System.out.println("session!=null && session.getAttribute(userId)!=null"); logger.debug("IF Part"); UserMasterBean userBean = (UserMasterBean)session.getAttribute("userBean"); String windowsId = userBean.getWindowsId(); logger.debug("User Id " + windowsId + " allowed access"); System.out.println("User Id " + windowsId + " allowed access"); flag = true; } else { System.out.println("else .....session!=null && session.getAttribute(userId)!=null"); logger.debug("Else Part"); flag = false; } } if (flag == true) { try { System.out.println("before chain.doFilter(request, response)"); chain.doFilter(request, response); } catch (Exception e) { e.printStackTrace(); try { objHttpServletResponse.sendRedirect(contextPath + "/logout.do"); } catch (Exception ex) { ex.printStackTrace(); } } } else { try { System.out.println("before sendRedirect"); objHttpServletResponse.sendRedirect(contextPath + "/jsp/errorPage.jsp"); } catch (Exception ex) { ex.printStackTrace(); } } System.out.println("end of PageFilter"); } Index.jsp <script type="text/javascript"> //alert("inside s13"); var WinNetwork = new ActiveXObject("WScript.Network"); var userName=WinNetwork.UserName; alert(userName); $.ajax({ url : "login.html", data : "userName="+userName, success : function(result) { alert("result == "+result); if(result=="Valid") window.location = "http://10.160.118.200:8082/eIA_Mock_5/welcome.html"; } }); </script> web.xml has a filter entry with URL pattern as * I am using spring 3 mvc

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  • Error while splitting application context file in spring

    - by Krupal
    I am trying to split the ApplicationContext file in Spring. For ex. the file is testproject-servlet.xml having all the entries. Now I want to split this single file into multiple files according to logical groups like : group1-services.xml, group2-services.xml I have created following entries in web.xml : <servlet> <servlet-name>testproject</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <init-param> <param-name>contextConfigLocation</param-name> <param-value> /WEB-INF/group1-services.xml, /WEB-INF/group2-services.xml </param-value> </init-param> <load-on-startup>1</load-on-startup> </servlet> I am using SimpleUrlHandlerMapping as: RegisterController PayrollServicesController I also have the controller defined as : .. .. The problem is that I have splitted the ApplicationContext file "testproject-servlet.xml" into two different files and I have kept the above entries in "group1-services.xml". Is it fine? I want to group things logically based on their use in seperate .xml files. But I am getting the following error when I try to access a page inside the application : org.springframework.web.servlet.DispatcherServlet noHandlerFound WARNING: No mapping for [/TestProject/payroll_services.htm] in DispatcherServlet with name 'testproject' Please tell me how to resolve it. Thanks in Advance !

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  • Spring Security 3.1 xsd and jars mismatch issue

    - by kmansoor
    I'm Trying to migrate from spring framework 3.0.5 to 3.1 and spring-security 3.0.5 to 3.1 (not to mention hibernate 3.6 to 4.1). Using Apache IVY. I'm getting the following error trying to start Tomcat 7.23 within Eclipse Helios (among a host of others, however this is the last in the console): org.springframework.beans.factory.BeanDefinitionStoreException: Line 7 in XML document from ServletContext resource [/WEB-INF/focus-security.xml] is invalid; nested exception is org.xml.sax.SAXParseException: Document root element "beans:beans", must match DOCTYPE root "null". org.xml.sax.SAXParseException: Document root element "beans:beans", must match DOCTYPE root "null". my security config file looks like this: <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:jdbc="http://www.springframework.org/schema/jdbc" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.1.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.1.xsd http://www.springframework.org/schema/jdbc http://www.springframework.org/schema/jdbc/spring-jdbc-3.1.xsd"> Ivy.xml looks like this: <dependencies> <dependency org="org.hibernate" name="hibernate-core" rev="4.1.7.Final"/> <dependency org="org.hibernate" name="com.springsource.org.hibernate.validator" rev="4.2.0.Final" /> <dependency org="org.hibernate.javax.persistence" name="hibernate-jpa-2.0-api" rev="1.0.1.Final"/> <dependency org="org.hibernate" name="hibernate-entitymanager" rev="4.1.7.Final"/> <dependency org="org.hibernate" name="hibernate-validator" rev="4.3.0.Final"/> <dependency org="org.springframework" name="spring-context" rev="3.1.2.RELEASE"/> <dependency org="org.springframework" name="spring-web" rev="3.1.2.RELEASE"/> <dependency org="org.springframework" name="spring-tx" rev="3.1.2.RELEASE"/> <dependency org="org.springframework" name="spring-webmvc" rev="3.1.2.RELEASE"/> <dependency org="org.springframework" name="spring-test" rev="3.1.2.RELEASE"/> <dependency org="org.springframework.security" name="spring-security-core" rev="3.1.2.RELEASE"/> <dependency org="org.springframework.security" name="spring-security-web" rev="3.1.2.RELEASE"/> <dependency org="org.springframework.security" name="spring-security-config" rev="3.1.2.RELEASE"/> <dependency org="org.springframework.security" name="spring-security-taglibs" rev="3.1.2.RELEASE"/> <dependency org="net.sf.dozer" name="dozer" rev="5.3.2"/> <dependency org="org.apache.poi" name="poi" rev="3.8"/> <dependency org="commons-io" name="commons-io" rev="2.4"/> <dependency org="org.slf4j" name="slf4j-api" rev="1.6.6"/> <dependency org="org.slf4j" name="slf4j-log4j12" rev="1.6.6"/> <dependency org="org.slf4j" name="slf4j-ext" rev="1.6.6"/> <dependency org="log4j" name="log4j" rev="1.2.17"/> <dependency org="org.testng" name="testng" rev="6.8"/> <dependency org="org.dbunit" name="dbunit" rev="2.4.8"/> <dependency org="org.easymock" name="easymock" rev="3.1"/> </dependencies> I understand (hope) this error is due to a mismatch between the declared xsd and the jars on the classpath. Any pointers will be greatly appreciated.

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  • Spring aspectj jar not configured correctly

    - by newguy
    I am getting this error when I tried to use a JPA object created by Roo. Entity manager has not been injected (is the Spring Aspects JAR configured as an AJC/AJDT aspects library?) I have followed some online advice to add the spring-aspects.jar to aspectj path in Eclipse but I still get this error. Does anyone know how to solve this? The environment I am using is Spring 3.0.5, Hibernate 3.6 and JBoss 6.0.0.Final.

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