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  • MYSQL sum() for distinct rows

    - by makeee
    I'm looking for help using sum() in my SQL query (not posting full query since the scenario is fairly simple). I have COUNT(DISTINCT conversions.id) in my query. I use DISTINCT because I'm doing "group by" for multiple columns and this ensures the same row is not counted more than once. Now I want to add: SUM(conversions.value) as conversion_value The problem is that the "value" for each row is counted more than once (due to the multiple group bys) I basically want to do SUM(conversions.value) for each DISTINCT conversions.id. Is that possible?

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  • Fastest way to pad a number in Java to a certain number of digits

    - by Martin
    Am trying to create a well-optimised bit of code to create number of X-digits in length (where X is read from a runtime properties file), based on a DB-generated sequence number (Y), which is then used a folder-name when saving a file. I've come up with three ideas so far, the fastest of which is the last one, but I'd appreciate any advice people may have on this... 1) Instantiate a StringBuilder with initial capacity X. Append Y. While length < X, insert a zero at pos zero. 2) Instantiate a StringBuilder with initial capacity X. While length < X, append a zero. Create a DecimalFormat based on StringBuilder value, and then format the number when it's needed. 3) Create a new int of Math.pow( 10, X ) and add Y. Use String.valueOf() on the new number and then substring(1) it. The second one can obviously be split into outside-loop and inside-loop sections. So, any tips? Using a for-loop of 10,000 iterations, I'm getting similar timings from the first two, and the third method is approximately ten-times faster. Does this seem correct? Full test-method code below... // Setup test variables int numDigits = 9; int testNumber = 724; int numIterations = 10000; String folderHolder = null; DecimalFormat outputFormat = new DecimalFormat( "#,##0" ); // StringBuilder test long before = System.nanoTime(); for ( int i = 0; i < numIterations; i++ ) { StringBuilder sb = new StringBuilder( numDigits ); sb.append( testNumber ); while ( sb.length() < numDigits ) { sb.insert( 0, 0 ); } folderHolder = sb.toString(); } long after = System.nanoTime(); System.out.println( "01: " + outputFormat.format( after - before ) + " nanoseconds" ); System.out.println( "Sanity check: Folder = \"" + folderHolder + "\"" ); // DecimalFormat test before = System.nanoTime(); StringBuilder sb = new StringBuilder( numDigits ); while ( sb.length() < numDigits ) { sb.append( 0 ); } DecimalFormat formatter = new DecimalFormat( sb.toString() ); for ( int i = 0; i < numIterations; i++ ) { folderHolder = formatter.format( testNumber ); } after = System.nanoTime(); System.out.println( "02: " + outputFormat.format( after - before ) + " nanoseconds" ); System.out.println( "Sanity check: Folder = \"" + folderHolder + "\"" ); // Substring test before = System.nanoTime(); int baseNum = (int)Math.pow( 10, numDigits ); for ( int i = 0; i < numIterations; i++ ) { int newNum = baseNum + testNumber; folderHolder = String.valueOf( newNum ).substring( 1 ); } after = System.nanoTime(); System.out.println( "03: " + outputFormat.format( after - before ) + " nanoseconds" ); System.out.println( "Sanity check: Folder = \"" + folderHolder + "\"" );

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  • Cocoa @sum array operator too slow - alternatives?

    - by icodestuff
    I've got a text field value bound to a key path that uses @sum. When the array controller is filtered, the text field updates properly, but extremely slowly, lagging the UI or outright beachballing after every key press (less so as the number of items in arrangedObjects decreases). There is no lag if I don't use @sum; I've narrowed it down to this. Is there a faster way to do the same thing?

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  • SQL Update to the SUM if it's joined values

    - by CL4NCY
    Hi, I'm trying to update a field in the database to the sum of it's joined values: UPDATE P SET extrasPrice = SUM(E.price) FROM dbo.BookingPitchExtras AS E INNER JOIN dbo.BookingPitches AS P ON E.pitchID = P.ID AND P.bookingID = 1 WHERE E.[required] = 1 When I run this I get the following error: "An aggregate may not appear in the set list of an UPDATE statement." Any ideas?

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  • SQL Update to the SUM of its joined values

    - by CL4NCY
    Hi, I'm trying to update a field in the database to the sum of its joined values: UPDATE P SET extrasPrice = SUM(E.price) FROM dbo.BookingPitchExtras AS E INNER JOIN dbo.BookingPitches AS P ON E.pitchID = P.ID AND P.bookingID = 1 WHERE E.[required] = 1 When I run this I get the following error: "An aggregate may not appear in the set list of an UPDATE statement." Any ideas?

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  • Getting N random numbers that the sum is M

    - by marionmaiden
    Hello I want to get N random numbers that the sum of them is a value. For example, let's suppose I want 5 random numbers that their sum is 1 Then, a valid possibility is: 0.2 0.2 0.2 0.2 0.2 Other possibility is: 0.8 0.1 0.03 0.03 0.04 And so on. I need this for the creation of the matrix of belongings of the Fuzzy C-means.

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  • Best way to score and sum in Scala?

    - by adam77
    Is there a better way of doing this: val totalScore = set.foldLeft(0)( _ + score(_) ) or this: val totalScore = set.map(score(_)).sum I think it's quite a common operation so was expecting something sleeker like: val totalScore = set.sum( score(_) )

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  • algorithm to print the digits in the correct order

    - by Aga Waw
    I've been trying to write an algorithm that will print separately the digits from an integer. I have to write it in Pseudocode. I know how to write an algorithm that reverse the digits. digi(n): while n != 0: x = n % 10 n = n // 10 print (x) But I don't know how to write an algorithm to print the digits in the correct order. f.eg. the input is integer 123467 and the output is: 1 2 3 4 6 7 The numbers will be input from the user, and we cannot convert them to a string. I just need help gettin started on writing algorithms. Thanks

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  • Removing the last digits in string [migrated]

    - by Ruriko
    I have a string that looks like this: [APPLE PIE] Sei Shoujo Sentai Lakers 3 Battle Team Lakers 3 (100% FULL-PIC)_20121104_032834 I want to remove the digits at the end of the string, basically the 16 digits at the end of the string. In the end it should look like this: [APPLE PIE] Sei Shoujo Sentai Lakers 3 Battle Team Lakers 3 (100% FULL-PIC) This is my code that I have written so far var str="[APPLE PIE] Sei Shoujo Sentai Lakers 3 Battle Team Lakers 3 (100% FULL-PIC)_20121104_032834"; var n=str.substr(1,74); document.write(n); The problem is the string will be different so each will have different amount of characters. So how I remove the digits at the end of the string in javascript?

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  • Sum an Array - Objective-C

    - by Graham
    Hi Guys, I'm just starting out and I'm looking for an easy way to sum a simple array. I've read into apple developer site on key value coding and I don't understand how to apply that to my array or if that's the appropriate way to sum this. My stumbling block with the key value coding is the .keypathToProperty - I can sort of understand that you need a further reference in a 2D array but they don't show the array code, only the keypath to the title of the row so I can't figure it out yet. NSMutableArray *numArray = [NSMutableArray arrayWithCapacity:4]; [numArray addObject:num1]; [numArray addObject:num2]; [numArray addObject:num3]; [numArray addObject:num4]; I appreciate the replies! Thanks Graham

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  • Generating Running Sum of Ratings in SQL

    - by Koobz
    I have a rating table. It boils down to: rating_value created +2 april 3rd -5 april 20th So, every time someone gets rated, I track that rating event in the database. I want to generate a rating history/time graph where the rating is the sum of all ratings up to that point in time on a graph. I.E. A person's rating on April 5th might be select sum(rating_value) from ratings where created <= april 5th The only problem with this approach is I have to run this day by day across the interval I'm interested in. Is there some trick to generating a running total using this sort of data? Otherwise, I'm thinking the best approach is to create a denormalized "rating history" table alongside the individual ratings.

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  • MySQL count/sum fields

    - by Conor H
    Hi There, What I am trying to achieve is a report on daily financial transactions. With my SQL query I would like to count the total number of cash transactions, the total cash value and the same for checks. I only want to do this for a specified date. Here is a snippet of the query that I am having trouble with. These sum and count commands are processing all the data in the table and not for the selected date. (SELECT SUM(amount) FROM TRANSACTION WHERE payment_type.name = 'cash') AS total_cash, (SELECT COUNT(*) FROM TRANSACTION WHERE payment_type.name = 'cash') AS total_cash_transactions Sorry if I havent posted enough detail as I haven't time. If you need more info just ask.. Cheers.

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  • ruby: sum corresponding members of two arrays

    - by jjnevis
    I've got two (or more) arrays with 12 integers in each (corresponding to values for each month). All I want is to add them together so that I've got a single array with summed values for each month. Here's an example with three values: [1,2,3] and [4,5,6] = [5,7,9] The best I could come up with was: [[1,2,3],[4,5,6]].transpose.map{|arr| arr.inject{|sum, element| sum+element}} #=> [5,7,9] Is there a better way of doing this? It just seems such a basic thing to want to do.

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  • SUM a pair of COUNTs from two tables based on a time variable

    - by Kevin O.
    Been searching for an answer to this for the better part of an hour without much luck. I have two regional tables laid out with the same column names and I can put out a result list for either table based on the following query (swap Table2 for Table1): SELECT Table1.YEAR, FORMAT(COUNT(Table1.id),0) AS Total FROM Table1 WHERE Table1.variable='Y' GROUP BY Table1.YEAR Ideally I'd like to get a result that gives me a total sum of the counts by year, so instead of: | REGION 1 | | REGION 2 | | YEAR | Total | | YEAR | Total | | 2010 | 5 | | 2010 | 1 | | 2009 | 2 | | 2009 | 3 | | | | | 2008 | 4 | I'd have: | MERGED | | YEAR | Total | | 2010 | 6 | | 2009 | 5 | | 2008 | 4 | I've tried a variety of JOINs and other ideas but I think I'm caught up on the SUM and COUNT issue. Any help would be appreciated, thanks!

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  • PHP Sum Array - sum only elemants of an array

    - by Homer_J
    Hi all, I have have an array as follows: $row[6] This section of the array has 4 numbers within it that I can display and use without any problems, what I'd like to be able to do is sum the first two numbers and the last two numbers separately. Is there any way to do this? Thanks in advance, Homer.

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  • How to select from tableA sum of grouped numbers from tableB above their sums average in Oracle?

    - by Nazgulled
    I have data like this: tableA.ID --------- 1 2 3 tableB.ID tableB.NUM -------------------- 1 10 1 15 2 18 3 12 2 15 3 13 1 12 I need to select tableA IDs where the sum of their NUMs in tableB is above the average of all tableA IDs sums. In other words: SUM ID=1 -> 10+15+12 = 37 SUM ID=2 -> 18+12+15 = 45 SUM ID=3 -> 12+13 = 25 AVG ALL IDs -> (37+45+25)/3 = 35 The SELECT must only show ID 1 and 2 because 37 35, 45 35 but 25 < 35. This is my current query which is working fine: SELECT tableA.ID FROM tableA, tableB WHERE tableA.ID = tableB.ID HAVING SUM(tableB.NUM) > ( SELECT AVG(MY_SUM) FROM ( SELECT SUM(tableB.NUM) MY_SUM FROM tableA, tableB WHERE tableA.ID = tableB.ID GROUP BY tableA.ID ) ) GROUP BY tableA.ID But I have a feeling there might be a better way without all those nested SELECTs. Perhaps 2, but 3 feels like too much. I'm probably wrong though. For instance, why can't I do something simple like this: SELECT tableA.ID FROM tableA, tableB WHERE tableA.ID = tableB.ID HAVING SUM(tableB.NUM) > AVG(SUM(tableB.NUM)) GROUP BY tableA.ID Or this: SELECT tableA.ID, SUM(tableB.NUM) MY_SUM FROM tableA, tableB WHERE tableA.ID = tableB.ID HAVING MY_SUM > AVG(MY_SUM) GROUP BY tableA.ID

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  • sum not working properly abap

    - by Eva Dias
    I'm trying to sum up some values but it keeps giving me weird values. I'm posting the code to help, and an image too of what is happening. at end of kunnr. soma-waers = <fs_main-waers. soma-wrbtr = <fs_main-wrbtr. soma-fwste = <fs_main-fwste. soma-hwaer = <fs_main-hwaer. soma-dmbtr = <fs_main-dmbtr. soma-hwste = <fs_main-hwste. APPEND soma TO it_soma. LOOP AT it_soma INTO soma. IF sy-tabix = 1. FORMAT COLOR COL_TOTAL INTENSIFIED OFF. SUM. WRITE: "/ sy-uline(137), / sy-vline NO-GAP, 'Subtotal' NO-GAP, '-' NO-GAP, soma-waers, 63 sy-vline NO-GAP, 64 soma-wrbtr NO-GAP, sy-vline NO-GAP, soma-fwste NO-GAP, sy-vline NO-GAP, soma-hwaer NO-GAP, sy-vline NO-GAP, soma-dmbtr NO-GAP, sy-vline NO-GAP, soma-hwste NO-GAP, sy-vline NO-GAP, / sy-uline(137). ELSE. ENDIF. ENDLOOP. ENDAT.

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  • PHP: why uniqid returned value is only 13 digits long

    - by Marco Demaio
    uniqid() function returns a 13 digits long hexadecimal number. According to the spec in php.net site, the function uses microtime to generate the unique value. But microtime returns numbers in string format as the following one: "0.70352700 12689396875" which are basically the microseconds and the seconds elapsed since 1970. This is a 9+11 digits decimal number. Converting a 20 decimal number into hex would result in a 16 digits hexadecimal NOT a 13 digits one. I also thought to take out the "0." part that seem to never change, and the last two digits of the microsec part that seem to remain always "00". Doing this the decimal number would be only 9+11-3 digits long, but still a decimal number of 17 digits when converted into hex would result in 14 digits hexadecimal number NOT 13. You probably think I'm crazy in asking such a thing, but I'm concerned about using uniqid, unique values are important to be unique, a duplicated value could screw up an entire application.

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  • Filezilla Install Problem: Hash Sum Mismatch

    - by kyleskool
    I'm new to the Ubuntu scene, and I tried to install Filezilla today by going to terminal and typing "sudo apt-get install filezilla", and got this error: Failed to fetch http://us.archive.ubuntu.com/ubuntu/pool/universe/w/wxwidgets2.8/libwxbase2.8-0_2.8.12.1-6ubuntu2_amd64.deb Hash Sum mismatch Failed to fetch http://us.archive.ubuntu.com/ubuntu/pool/universe/w/wxwidgets2.8/libwxgtk2.8-0_2.8.12.1-6ubuntu2_amd64.deb Hash Sum mismatch Failed to fetch http://universe/t/tinyxml/libtinyxml2.6.2_2.6.2-1build1_amd64.deb Hash Sum mismatch Failed to fetch http://universe/f/filezilla/filezilla-common_3.5.3-1ubuntu2_all.deb Hash Sum mismatch Failed to fetch http://universe/f/filezilla/filezilla_3.5.3-1ubuntu2_amd64.deb Hash Sum mismatch E: Unable to fetch some archives, maybe run apt-get update or try with --fix-missing? Running it again with "--fix-missing" appended to the command didn't work, nor did running apt-get update. Any suggestion? Thanks!

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  • select multiple columns using linq and sum them up

    - by Yustme
    Hi, How can i select multiple columns and calculate the total amount. For example, in my database i got a few fields which are named: 5hunderedBills, 2hunderedBills, 1hunderedBills, etc. And the value of those fields are for example: 5, 2, 3 And the sum would be: 5hunderedBills * 5 + 2hunderedBills * 2 + 1hunderedBills * 3 How can i do that with LINQ in one select statement?

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