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  • Nvidia System Tools compatible with GTX 560 Ti?

    - by Paula Ferreira
    I want to download and use Nvidia System Tools with ESA suport. But on the "Supported Products" tab my GTX 560 Ti isn't listed. The product was last released on April last year, but it shows support for both the GTX 570 and 580 as well as the GTX 4x family. All sister cards of the GTX 560. Has anyone successfuly ran this nvidia product with the GTX 560 Ti? Why wasn't this card included on the list of supported products?

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  • what are the rules for SLI ( GTX 550 Ti )

    - by equivalent8
    I got ASUS GTX 550 Ti and I want to SLI it with another graphic card. I heard that not all graphic cards are good idea to SLI, (or not all combinations) because sometimes the final performance could be even worse that with one graphic card. Is that true? What are the rules ? ( maybe chip-set needs to be same or something ? ) I was wondering if you can recommend me what Graphic card should I use as with mine. Should I use same one (GTX 550 Ti) ?

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  • iPhone: CPU power to do DSP/Fourier transform/frequency domain?

    - by mahboudz
    I want to analyze MIC audio on an ongoing basis (not just a snipper or prerecorded sample), and display frequency graph and filter out certain aspects of the audio. Is the iPhone powerful enough for that? I suspect the answer is a yes, given the Google and iPhone voice recognition, Shazaam and other music recognition apps, and guitar tuner apps out there. However, I don't know what limitations I'll have to deal with. Anyone play around with this area?

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  • Screen tearing with GeForce 550 Ti

    - by Konair0s
    Recently I switched to the new monitor and graphic card - DELL U2312HM and GeForce GTX 550 Ti. I have problems with screen tearing (like in this picture from Wikipedia). Usually it is somewhere in upper part of the screen. Mainly happens in videos (in flash videos tearing heavier). In games all fine, except in-game videos (sometimes even videos built on game engine), but gameplay itself is clear, even in very fast actions. Connection with DVI. Problems both in Linux (Debian GNU/Linux, openSUSE 12.1, Linux Mint 13) and Windows (Windows XP, Windows 7), with various driver versions. 1920x1080, 60Mhz. How can I resolve this?

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  • TI MSP430 Interrupt source

    - by TheDelChop
    Guys, I know that when working with the MSP430F2619 and TI's CCSv4, I can get more than one interrupt to use the same interrupt handler with code that looks something like this: #pragma vector=TIMERA1_VECTOR #pragma vector=TIMERA0_VECTOR __interrupt void Timer_A (void){ ServiceWatchdogTimer(); } My question is, when I find myself in that interrupt, is there a way to figure out which one of these interrupts got me here? Thank you, Joe

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  • Is Objective C fast enough for DSP/audio programming

    - by morgancodes
    I've been making some progress with audio programming for iPhone. Now I'm doing some performance tuning, trying to see if I can squeeze more out of this little machine. Running Shark, I see that a significant part of my cpu power (16%) is getting eaten up by objc_msgSend. I understand I can speed this up somewhat by storing pointers to functions (IMP) rather than calling them using [object message] notation. But if I'm going to go through all this trouble, I wonder if I might just be better off using C++. Any thoughts on this?

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  • Carousel not working in IE7/8

    - by user515990
    I am working with jquery.carouFredSel-4.0.3-packed.js for the carousal and it works good with IE9 and mozilla,but in IE7/8, it says "LOG: carouFredSel: Not enough items: not scrolling " whenever i am seeing it is not the case. The code i am using is <div class="carousel-wrapper"> <div class="mask"> <a class="arrow left off"><-</a> <a class="arrow left on" href="javascript:void(0);"><-</a> <ul> <dsp:droplet name="ForEach"> <dsp:param name="array" value="${listRecommended}"/> <dsp:oparam name="empty">no recommended apps</dsp:oparam> <dsp:oparam name="output"> <li> <a href="javascript:void(0);"><img src="${resourcePath}/images/apps/carousel-image1.jpg" alt="bakery story"/></a> <a href="javascript:void(0);"><dsp:valueof param="element.displayName"/></a><br/> <dsp:getvalueof var="averageRating" param="element.averageRating"/> <dsp:getvalueof var="rating" param="count"/> <div class="rating"> <div class="medium"> <dsp:droplet name="For"> <dsp:param name="howMany" value="${averageRating}"/> <dsp:oparam name="output"> <input checked="checked" class="star {split:1}" disabled="disabled" name="product-similar-'${rating}'" type="radio"> </dsp:oparam> </dsp:droplet> </div> </div> </li> </dsp:oparam> </dsp:droplet> </ul> </div> <a class="arrow right off">-></a> <a class="arrow right on" href="javascript:void(0);">-></a> </div> and javascript library is jquery.carouFredSel-4.0.3-packed.js. Please let me know if someone has faced similar problem. thanks in advance Hemish

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  • Beagleboard: How do I send/receive data to/from the DSP?

    - by snakile
    I have a beagleboard with TMS320C64x+ DSP. I'm working on an image processing beagleboard application. Here's how it's going to work: The ARM reads an image from a file and put the image in a 2D array. The arm sends the matrix to the DSP. The DSP receives the matrix. The DSP performs the image processing algorithm on the received matrix (the algorithm code uses about 5MB of dynamically allocated memory). The DSP sends the processed image (matrix) to the ARM. The arm received the matrix. The arm saved the processed image to a file. I'v already written the code for steps 1,3,5. What is the easiest way to do steps 3+4 (sending the data)? Code examples are welcome.

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  • jquery boxy plugin: prevent multiple instances of the same dialog when clicking the link multiple ti

    - by Lyon
    Hi, I'm using the Boxy jQuery plugin to open dialog windows and populating it through ajax. http://onehackoranother.com/projects/jquery/boxy/ Here's my code so far: $("a.create").click(function (e) { url = $(e.target).attr('href'); Boxy.load(url, {title:'Test'}); }); This opens up a dialog alright. However, if I click the link again, another dialog will open. How can I make it such that the previously opened Boxy dialog will come into focus? I only want one instance of this dialog. I tried assigning a variable to var ele = Boxy.load(); but the variable ele returns undefined... Alas, I can't make out much from the limited Boxy documentation available. Enabling the option modal: true would prevent the user from clicking on the link multiple times, but I don't want the overlay to show. Thanks for any light you can shed on this. -Lyon

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  • iTunes Visualizer Plugin in C# - Energy Function

    - by James D
    Hi, iTunes Visualizer plugin in C#. Easiest way to compute the "energy level" for a particular sample? I looked at this writeup on beat detection over at GameDev and have had some success with it (I'm not doing beat detection per se, but it's relevant). But ultimately I'm looking for a stupid-as-possible, quick-and-dirty approach for demo purposes. For those who aren't familiar with how iTunes structures visualization data, basically you're given this: struct VisualPluginData { /* SNIP */ RenderVisualData renderData; UInt32 renderTimeStampID; UInt8 minLevel[kVisualMaxDataChannels]; // 0-128 UInt8 maxLevel[kVisualMaxDataChannels]; // 0-128 }; struct RenderVisualData { UInt8 numWaveformChannels; UInt8 waveformData[kVisualMaxDataChannels][kVisualNumWaveformEntries]; // 512-point FFT UInt8 numSpectrumChannels; UInt8 spectrumData[kVisualMaxDataChannels][kVisualNumSpectrumEntries]; }; Ideally, I'd like an approach that a beginning programmer with little to no DSP experience could grasp and improve on. Any ideas? Thanks!

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  • Como estão os seus projetos em TI? ALM (Application lifecycle management) - Parte 1

    - by johnywercley
    O gráfico mostra um número assustador, em outras palavras, no mundo inteiro as coisas não andam bem, são pesquisas feitas por um importante orgão o “Stand Group”. Eles nos chamam atenção a quantidade de projetos com problemas, fazendo uma análise primária, somando a parte verde com azul veremos a porcentagem de projetos TI com problemas, projetos que chegam a de fato dar certo, são os de cores vermelhas, um número muito baixo. Se você fosse hoje investidor financeiro e tivesse que fazer um projeto...(read more)

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  • How do I fix error 1303 during TI Connect install?

    - by smoth190
    I recently purchased a TI-84 Plus graphing calculator, and I'm trying install the TI Connect software in order to connect the calculator to my computer via the USB cable. Unfortunately, I'm getting this error while trying to install the program: Error 1303. The installation has insufficient privileges to access this directory: E:\Data\Timothy\Documents\MyTIData. The installation cannot continue. Log on as administrator or contact your system administrator. However, my account is the only account on my PC, and it has administrative privileges. I've also tried running the installer with Run as Administrator, but with no luck. If I create the folder MyTIData manually, I receive this error: Error 1317. An error occurred while attempting to create the directory: E:\Data\Timothy\Documents\MyTIData I've reapplied the security settings to the E:\Data folder (and all its sub-directories) to Full for my account. I've also gone into Computer Management, and given SYSTEM full privileges for the entire disk. I've also logged out, logged back in, restarted, etc. but still, no luck. Now, I should mention that my Documents folder is not at the default location. I changed it due to my C: disk being a 90GB SSD, so I moved all my personal data onto the extra storage disk (which is ~1TB). I don't know if that is causing the issue, but it can't hurt throwing it out there. So why can't I install this program? Google'ing the problem brings up this error for various other installers (such as Visual Studio and Microsoft Office), but nothing for TI Connect. All the solutions are the same: Give the folder Full privileges...but I've already done this! I've also tried running the installer with and without the calculator plugged in, but it didn't change anything. In the prompt that contains the error, repeatedly clicking Retry or waiting a few moments before clicking Retry also produces no result.

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  • Se non ti sei unito alla Customer Experience Revolution? Il materiale è tutto qui!

    - by Silvia Valgoi
    Se ti sei perso questo interesante Executive workshop, non preoccuparti, qui puoi trovare gli interventi dei relatori.Durante l'evento Oracle, Accenture ed il professor Enrico Finzi hanno condiviso l'approccio alla Customer Experience vista come strategia per dare vita a processi più completi ed innovativi, per generare e gestire l’interazione con i consumatori, su tutti i canali. E' stato un momento importante per: comprendere perché la Customer Experience è diventata la componente più importante e strategica del tuo business scoprire come la Customer Experience accelleri l’acquisizione di nuovi clienti, incrementi la fidelizzazione ad un brand/prodotto/servizio, migliori l’efficienza operativa e sostenga le vendite conoscere come le soluzioni di Customer Experience possono aiutare le aziende a far vivere questa esperienza in modo coerente, personalizzata, attraverso tutti i canali e su tutti i dispositivi, ottenendo risultati misurabile Ecco le presentazioni e i video presentati durante i lavori: &amp;lt;p&amp;gt; &amp;lt;/p&amp;gt; Oracle Customer Experience - Empowering People. Powering Brands - Armando Janigro, Sales Development Manager, Oracle         How to win with Customer Experience - Nadia Dallafiore, Senior Manager CRM Retail  Accenture   Customer Experience e selezione Darwiniana della marca - Enrico Finzi, Sociologo, Presidente AstraRicerche   Engage.Win.Develop.Keep LinkedIn: Customer Concepts Exchange Facebook: Oracle Customer Experience

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  • Implementation of FIR filter in C#

    - by user261924
    Hi, at the moment im trying to implement a FIR lowpass filter on a wave file. The FIR coefficients where obtained using MATLAB using a 40 order. Now i need to implement the FIR algorithm in C# and im finding it difficult to implement it. Any help? Thanks

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  • VB FFT - stuck understanding relationship of results to frequency

    - by WaveyDavey
    Trying to understand an fft (Fast Fourier Transform) routine I'm using (stealing)(recycling) Input is an array of 512 data points which are a sample waveform. Test data is generated into this array. fft transforms this array into frequency domain. Trying to understand relationship between freq, period, sample rate and position in fft array. I'll illustrate with examples: ======================================== Sample rate is 1000 samples/s. Generate a set of samples at 10Hz. Input array has peak values at arr(28), arr(128), arr(228) ... period = 100 sample points peak value in fft array is at index 6 (excluding a huge value at 0) ======================================== Sample rate is 8000 samples/s Generate set of samples at 440Hz Input array peak values include arr(7), arr(25), arr(43), arr(61) ... period = 18 sample points peak value in fft array is at index 29 (excluding a huge value at 0) ======================================== How do I relate the index of the peak in the fft array to frequency ?

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  • Saturated addition of two signed Java 'long' values

    - by finnw
    How can one add two long values (call them x and y) in Java so that if the result overflows then it is clamped to the range Long.MIN_VALUE..Long.MAX_VALUE? For adding ints one can perform the arithmetic in long precision and cast the result back to an int, e.g.: int saturatedAdd(int x, int y) { long sum = (long) x + (long) y; long clampedSum = Math.max((long) Integer.MIN_VALUE, Math.min(sum, (long) Integer.MAX_VALUE)); return (int) clampedSum; } or import com.google.common.primitives.Ints; int saturatedAdd(int x, int y) { long sum = (long) x + (long) y; return Ints.saturatedCast(sum); } but in the case of long there is no larger primitive type that can hold the intermediate (unclamped) sum. Since this is Java, I cannot use inline assembly (in particular SSE's saturated add instructions.) It can be implemented using BigInteger, e.g. static final BigInteger bigMin = BigInteger.valueOf(Long.MIN_VALUE); static final BigInteger bigMax = BigInteger.valueOf(Long.MAX_VALUE); long saturatedAdd(long x, long y) { BigInteger sum = BigInteger.valueOf(x).add(BigInteger.valueOf(y)); return bigMin.max(sum).min(bigMax).longValue(); } however performance is important so this method is not ideal (though useful for testing.) I don't know whether avoiding branching can significantly affect performance in Java. I assume it can, but I would like to benchmark methods both with and without branching. Related: http://stackoverflow.com/questions/121240/saturating-addition-in-c

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  • i2s0: transmitter underrun (0)

    - by tbarbe
    were doing some audio stuff and I keep seeing this in the Organizer Console. Sun May 2 20:16:48 unknown kernel[0] : i2s0: transmitter underrun (0) Are these transmitter underruns bad? I think its just when were shutting down audio input...but could a few of these cause some issues later on?

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  • Downsampling and applying a lowpass filter to digital audio

    - by twk
    I've got a 44Khz audio stream from a CD, represented as an array of 16 bit PCM samples. I'd like to cut it down to an 11KHz stream. How do I do that? From my days of engineering class many years ago, I know that the stream won't be able to describe anything over 5500Hz accurately anymore, so I assume I want to cut everything above that out too. Any ideas? Thanks. Update: There is some code on this page that converts from 48KHz to 8KHz using a simple algorithm and a coefficient array that looks like { 1, 4, 12, 12, 4, 1 }. I think that is what I need, but I need it for a factor of 4x rather than 6x. Any idea how those constants are calculated? Also, I end up converting the 16 byte samples to floats anyway, so I can do the downsampling with floats rather than shorts, if that helps the quality at all.

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  • Autocorrelation returns random results with mic input (using a high pass filter)

    - by Niall
    Hello, Sorry to ask a similar question to the one i asked before (FFT Problem (Returns random results)), but i've looked up pitch detection and autocorrelation and have found some code for pitch detection using autocorrelation. Im trying to do pitch detection of a users singing. Problem is, it keeps returning random results. I've got some code from http://code.google.com/p/yaalp/ which i've converted to C++ and modified (below). My sample rate is 2048, and data size is 1024. I'm detecting pitch of both a sine wave and mic input. The frequency of the sine wave is 726.0, and its detecting it to be 722.950820 (which im ok with), but its detecting the pitch of the mic as a random number from around 100 to around 1050. I'm now using a High pass filter to remove the DC offset, but it's not working. Am i doing it right, and if so, what else can i do to fix it? Any help would be greatly appreciated! double* doHighPassFilter(short *buffer) { // Do FFT: int bufferLength = 1024; float *real = malloc(bufferLength*sizeof(float)); float *real2 = malloc(bufferLength*sizeof(float)); for(int x=0;x<bufferLength;x++) { real[x] = buffer[x]; } fft(real, bufferLength); for(int x=0;x<bufferLength;x+=2) { real2[x] = real[x]; } for (int i=0; i < 30; i++) //Set freqs lower than 30hz to zero to attenuate the low frequencies real2[i] = 0; // Do inverse FFT: inversefft(real2,bufferLength); double* real3 = (double*)real2; return real3; } double DetectPitch(short* data) { int sampleRate = 2048; //Create sine wave double *buffer = malloc(1024*sizeof(short)); double amplitude = 0.25 * 32768; //0.25 * max length of short double frequency = 726.0; for (int n = 0; n < 1024; n++) { buffer[n] = (short)(amplitude * sin((2 * 3.14159265 * n * frequency) / sampleRate)); } doHighPassFilter(data); printf("Pitch from sine wave: %f\n",detectPitchCalculation(buffer, 50.0, 1000.0, 1, 1)); printf("Pitch from mic: %f\n",detectPitchCalculation(data, 50.0, 1000.0, 1, 1)); return 0; } // These work by shifting the signal until it seems to correlate with itself. // In other words if the signal looks very similar to (signal shifted 200 data) than the fundamental period is probably 200 data // Note that the algorithm only works well when there's only one prominent fundamental. // This could be optimized by looking at the rate of change to determine a maximum without testing all periods. double detectPitchCalculation(double* data, double minHz, double maxHz, int nCandidates, int nResolution) { //-------------------------1-------------------------// // note that higher frequency means lower period int nLowPeriodInSamples = hzToPeriodInSamples(maxHz, 2048); int nHiPeriodInSamples = hzToPeriodInSamples(minHz, 2048); if (nHiPeriodInSamples <= nLowPeriodInSamples) printf("Bad range for pitch detection."); if (1024 < nHiPeriodInSamples) printf("Not enough data."); double *results = new double[nHiPeriodInSamples - nLowPeriodInSamples]; //-------------------------2-------------------------// for (int period = nLowPeriodInSamples; period < nHiPeriodInSamples; period += nResolution) { double sum = 0; // for each sample, find correlation. (If they are far apart, small) for (int i = 0; i < 1024 - period; i++) sum += data[i] * data[i + period]; double mean = sum / 1024.0; results[period - nLowPeriodInSamples] = mean; } //-------------------------3-------------------------// // find the best indices int *bestIndices = findBestCandidates(nCandidates, results, nHiPeriodInSamples - nLowPeriodInSamples - 1); //note findBestCandidates modifies parameter // convert back to Hz double *res = new double[nCandidates]; for (int i=0; i < nCandidates;i++) res[i] = periodInSamplesToHz(bestIndices[i]+nLowPeriodInSamples, 2048); double pitch2 = res[0]; free(res); free(results); return pitch2; } /// Finds n "best" values from an array. Returns the indices of the best parts. /// (One way to do this would be to sort the array, but that could take too long. /// Warning: Changes the contents of the array!!! Do not use result array afterwards. int* findBestCandidates(int n, double* inputs,int length) { //int length = inputs.Length; if (length < n) printf("Length of inputs is not long enough."); int *res = new int[n]; double minValue = 0; for (int c = 0; c < n; c++) { // find the highest. double fBestValue = minValue; int nBestIndex = -1; for (int i = 0; i < length; i++) { if (inputs[i] > fBestValue) { nBestIndex = i; fBestValue = inputs[i]; } } // record this highest value res[c] = nBestIndex; // now blank out that index. if(nBestIndex!=-1) inputs[nBestIndex] = minValue; } return res; } int hzToPeriodInSamples(double hz, int sampleRate) { return (int)(1 / (hz / (double)sampleRate)); } double periodInSamplesToHz(int period, int sampleRate) { return 1 / (period / (double)sampleRate); } Thanks, Niall. Edit: Changed the code to implement a high pass filter with a cutoff of 30hz (from What Are High-Pass and Low-Pass Filters?, can anyone tell me how to convert the low-pass filter using convolution to a high-pass one?) but it's still returning random results. Plugging it into a VST host and using VST plugins to compare spectrums isn't an option to me unfortunately.

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  • Matlab: Analysis of signal

    - by Mateusz
    Hi, I have a problem with this task: For free route perform frequency analysis and give parametrs of each signal component: time of beginning and ending of each component beginning and ending frequency amplitude (in time domain) in the beginning and end of each signal's component level of noise in dB Assume, that, the parametrs of each component like amplitude, frequency is changing lineary in time. Frequency of sampling is 1000Hz For example I have signal like this: Nx=64; fs=1000; t=1/fs*(0:Nx-1); %========================== A1=1; A2=4; f1=500; f2=1000; x1=A1*cos(2*pi*f1*t); x2=A2*sin(2*pi*f2*t); %========================== x=x1+x2;

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  • Normalize amplitude and phase with c#

    - by Lehto
    Hey I'm in the situation where i need to do some math related stuff in c# and for that i need some external libarys. The tool i look for should do the following actions: Process sound(wave/mp3): Normalize the amplitude Normalize the phase Any idea which way to go? And is there a big difference if a should to it on mp3 instead of wav Michael.

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