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  • Linux: cat /dev/video0 TS into some kind of ring puffer

    - by user155384
    I want to cat a /dev/video0 device output (Transport Stream) into a temporary ring buffer. In fact i do not want that the file is growing over the time. Simultaneously access is not possible. So the purpose is to have a file (buffer, Fifo, whatever) to be accessed by more than one consumer (example: tail -f, mencoder, VLC, ....). Some kind of scenario: 1# cat /dev/video0 > mybuffer.ts And then multiple access 2# tail -f mybuffer.ts > extract1.ts 2# tail -f mybuffer.ts > extract2.ts 3# ffmpeg ... Does someone have an idea how to do something like this?

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  • They Wrote The Book On It

    - by steve.diamond
    First of all, an apology to you all for my not posting this yesterday, when I should have. For those of you bloggers out there, you know the difference between "Save" and "Preview." But I temporarily forgot it. Nevertheless, while I'm not impressed with this mishap, I'm blown away by the initiative three of my colleagues have taken. Jeff Saenger, Tim Koehler, and Louis Peters, recently wrote a book, "Oracle CRM On Demand Deployment Guide." Not only that, they got this book PUBLISHED. These guys know their stuff. They have worked in the CRM industry for many years. And trust me, they command a lot of respect inside this organization. In the words of Louis Peters (who posted this verbiage yesterday on LinkedIn), "We've assembled all the best practices and lessons learned over the past six years working with CRM On Demand. The book covers a range of topics - working with SaaS-based applications, planning and executing a successful rollout, designing elegant and high-performing applications, and working effectively with Oracle. We even included several sample designs based on successful real-world deployments. Our main target audience is the CRM On Demand project team - sponsors, project managers, administrators, developers - really anyone planning, implementing or maintaining the application." Now these guys don't know it, but I'll be interviewing one of them and including audio excerpts of that conversation right here next Wednesday. In the meantime, if you want to learn more about successful CRM deployments in general, and working with Oracle CRM On Demand in particular, you should check out this book.

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  • Asterisk/FreePBX: Allow other Google Talk clients to ring when using motif module

    - by larsks
    I've recently installed FreePBX to act as a link between a SIP soft phone and my Google Talk account. It was easy to set up and outbound calls work just fine, but I've run into two problems with inbound calls that I'm not sure how to resolve. I'm using an inbound route to forward all calls from Google to my soft phone. If the soft phone is not currently registered, Asterisk answers and immediately generates a fast-busy signal (reporting CHANUNAVAIL in the logs), and the call is lost. If the soft phone is registered, Asterisk "answers" the call before rining the soft phone, which means that other Google Talk clients never ring (since from their perspective someone has answered the call). For solving (1) seems like I could use the ChanIsAvail() function (or this answer) to prevent Asterisk from answering in the event that the phone isn't registered. However, I'm not sure what to do about (2), because the behavior I want is for Asterisk to not "answer" the call until I answer the call on the soft phone. How do I configure Asterisk (ideally within the FreePBX framework) such that I can continue to receive calls at other Google Talk clients in addition to forwarding them to a SIP phone?

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  • Quick CPU ring mode protection question

    - by b-gen-jack-o-neill
    Hi, me again :) I am very curious in messing up with HW. But my top level "messing" so far was linked or inline assembler in C program. If my understanding of CPU and ring mode is right, I cannot directly from user mode app access some low level CPU features, like disabling interrupts, or changing protected mode segments, so I must use system calls to do everything I want. But, if I am right, drivers can run in ring mode 0. I actually don´t know much about drivers, but this is what I ask for. I just want to know, is learning how to write your own drivers and than call them the way I should go, to do what I wrote? I know I could write whole new OS (at least to some point), but what I exactly want to do is acessing some low level features of HW from standart windows application. So, is driver the way to go?

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  • Tim Heuer's editable combobox and tab stops

    - by Vinzz
    I'm using Tim Heuer's editable combo box in one of my Silverlight 3 projects and it works rather well. This control has an issue with tab stops though, that I don't understand yet... You have to hit tab twice so as to move to the next item. Did anyone manage to make this control support tabstops?

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  • Tim Thumb for an External Host / CDN

    - by Wes
    I'm running a stock copy of tim thumb on a clients website. Works great but does not support external hosts for the pictures. My clients uses an amazon CDN / Flickr for all of their websites pictures which doesnt allow me to resize on the fly. Has anyone found a work around for this? http://code.google.com/p/timthumb/

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  • traversal of multiple separate web services in a ring network

    - by qkrsppopcmpt
    I am facing a design problem, here is some basic requirement: Aggregator 1. Separate service for blog,video,images and associations. 2. Each of the service should be completely separate, that means they run on separate tomcat. 3. And each aggregator must be able to query local database and other aggregators 4. Traversal of services must be asynchronous using a ring network. For example, we have a ring like ws1-ws2-ws3-ws4-ws1. Each node represents one type of one aggregator. The traveral goes in this way: the query from ws1 to ws2, and ws1 is waiting for the response from ws2 asynchronously; ws2 to ws3, also ws2 wait for ws3 asynchronously. If ws3 has the data, reply to ws2 then to ws1, then reply. However if ws3 goes away, the traversal should go back to ws2, then to ws1, then go to ws4, then go to ws3 again. then tells ws4 since ws3 fails. The required technology is axis2 and tomcat 6. Does anybody have any clue about it? If it is clear, I can clarify the question more clearly. Thanks very much.

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  • (Android) How to catch a "ring" event?

    - by rockit
    Hi android developers! I'm clearly a newb, and I was wondering if anyone knows how I can detect a "ring" event on my cellphone through the android sdk? Generally I want to do something with the phone when it begins ringing! Any thoughts? If you want to simply point me to a page in the api documents that would be a good answer for me, I just don't know how to start my research!

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  • Tim Berners-Lee indigné par le programme PRISM, le père du web dénonce l'hypocrisie occidentale sur l'espionnage

    Tim Berners-Lee indigné par le programme PRISM, le père du web dénonce l'hypocrisie occidentale sur l'espionnageSir Timothy John Berners-Lee était en Grande-Bretagne cette semaine pour recevoir le Queen Elizabeth Price en ingénierie. Lors de la cérémonie, le « père d'internet » a été abordé pour partager son ressenti face à l'actualité qui secoue les médias du monde entier : l'affaire Edward Snowden et les espionnages sur internet à l'échelle gouvernemental qu'il a dénoncés . Tim Berners-Lee dénonce l'hypocrisie des gouvernements occidentaux, grands donneurs de leçons, qui ne manquent pas une seul...

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  • issue with std::advance on std::sets

    - by tim
    I've stumbled upon what I believe is a bug in the stl algorithm advance. When I'm advancing the iterator off of the end of the container, I get inconsistent results. Sometimes I get container.end(), sometimes I get the last element. I've illustrated this with the following code: #include <algorithm> #include <cstdio> #include <set> using namespace std; typedef set<int> tMap; int main(int argc, char** argv) { tMap::iterator i; tMap the_map; for (int i=0; i<10; i++) the_map.insert(i); #if EXPERIMENT==1 i = the_map.begin(); #elif EXPERIMENT==2 i = the_map.find(4); #elif EXPERIMENT==3 i = the_map.find(5); #elif EXPERIMENT==4 i = the_map.find(6); #elif EXPERIMENT==5 i = the_map.find(9); #elif EXPERIMENT==6 i = the_map.find(2000); #else i = the_map.end(); #endif advance(i, 100); if (i == the_map.end()) printf("the end\n"); else printf("wuh? %d\n", *i); return 0; } Which I get the following unexpected (according to me) behavior in experiment 3 and 5 where I get the last element instead of the_map.end(). [tim@saturn advance]$ uname -srvmpio Linux 2.6.18-1.2798.fc6 #1 SMP Mon Oct 16 14:37:32 EDT 2006 i686 athlon i386 GNU/Linux [tim@saturn advance]$ g++ --version g++ (GCC) 4.1.1 20061011 (Red Hat 4.1.1-30) Copyright (C) 2006 Free Software Foundation, Inc. This is free software; see the source for copying conditions. There is NO warranty; not even for MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. [tim@saturn advance]$ g++ -DEXPERIMENT=1 advance.cc [tim@saturn advance]$ ./a.out the end [tim@saturn advance]$ g++ -DEXPERIMENT=2 advance.cc [tim@saturn advance]$ ./a.out the end [tim@saturn advance]$ g++ -DEXPERIMENT=3 advance.cc [tim@saturn advance]$ ./a.out wuh? 9 [tim@saturn advance]$ g++ -DEXPERIMENT=4 advance.cc [tim@saturn advance]$ ./a.out the end [tim@saturn advance]$ g++ -DEXPERIMENT=5 advance.cc [tim@saturn advance]$ ./a.out wuh? 9 [tim@saturn advance]$ g++ -DEXPERIMENT=6 advance.cc [tim@saturn advance]$ ./a.out the end [tim@saturn advance]$ g++ -DEXPERIMENT=7 advance.cc [tim@saturn advance]$ ./a.out the end [tim@saturn advance]$ From the sgi website (see link at top), it has the following example: list<int> L; L.push_back(0); L.push_back(1); list<int>::iterator i = L.begin(); advance(i, 2); assert(i == L.end()); I would think that the assertion should apply to other container types, no? What am I missing? Thanks!

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  • Apple est-elle une marque "juste pour les riches" ? Son CEO intérimaire Tim Cook ne le souhaite pas

    Apple est-elle une marque "juste pour les riches" ? Son CEO intérimaire Tim Cook ne le souhaite pas Il y a quelques jours, Tim Cook, qui assure la direction d'Apple pendant l'absence de Steve Jobs, a répondu à une interview. Jusque là, rien d'anormal. Mais l'homme y a tenu des propos polémiques, en affirmant qu'il ne voulait pas que ses produits soient "juste pour les riches". Il explique ensuite que la firme va travailler au développement de produits et d'offres moins coûteux. Il faut dire qu'actuellement, la firme à la pomme à une réputation d'entreprise fabriquant des machines de qualité et fournissant l'élite, du fait de ses tarifs plus élevés que la concurrence. Si les fanbo...

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  • How do ring and bus network connect to router?

    - by lantopology
    Sorry this is probably a very silly question, but for some reason i am confused. How does a LAN with bus or ring topology connect to a router and other LANs? For example in a star network they all connect to a switch which can then connect to a router, but where does a switch go and fit in a bus or ring topology? In this image of a ring network there is no switch: http://www.brainbell.com/tutorials/Networking/images/01fig04.gif would the switch in the ring network simply be placed alongside the other nodes? Thank you very much

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  • delay ring between two font style changing

    - by Hesam Qodsi
    Hi I want to change font style of a control , for a short time. for example 2 secounds. I do like : label1.Font = new Font(label1.Font, label1.Font.Style | FontStyle.Bold); for(int i=0,i<4000000,i++); label1.Font = new Font(label1.Font, label1.Font.Style | FontStyle.Regular); but it doesn't work. what is the problem?

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  • C++ socket protocol design issue (ring inclusion)

    - by Martin Lauridsen
    So I have these two classes, mpqs_client and client_protocol. The mpqs_client class handles a Boost socket connection to a server (sending and receiving messages with some specific format. Upon receiving a message, it calls a static method, parse_message(..), in the class client_protocol, and this method should analyse the message received and perform some corresponding action. Given some specific input, the parse_message method needs to send some data back to the server. As mentioned, this happens through the class mpqs_client. So I could, from mpqs_client, pass "this" to parse_message(..) in client_protocol. However, this leads to a two-way association relationship between the two classes. Something which I reckon is not desireable. Also, to implement this, I would need to include the other in each one, and this gives me a terrible pain. I am thinking this is more of a design issue. What is the best solution here? Code is posted below. Class mpqs_client: #include "mpqs_client.h" mpqs_client::mpqs_client(boost::asio::io_service& io_service, tcp::resolver::iterator endpoint_iterator) : io_service_(io_service), socket_(io_service) { ... } ... void mpqs_client::write(const network_message& msg) { io_service_.post(boost::bind(&mpqs_client::do_write, this, msg)); } Class client_protocol: #include "../network_message.hpp" #include "../protocol_consts.h" class client_protocol { public: static void parse_message(network_message& msg, mpqs_sieve **instance_, mpqs_client &client_) { ... switch (type) { case MPQS_DATA: ... break; case POLYNOMIAL_DATA: ... break; default: break; } }

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  • Picking photo from Photochooser or holding hardware back button cause active timers ring

    - by Nznoonee
    This is very strange problem, and all the people I had asked to confirm it said that it takes place. I have a Threading.Timer instance which fires every 15 minutes. And if I call the PhotoChooser view and then select a photo from it, when going back to the calling page my application calls that timer's callback! I tried different timers either it be Timer from Threading namespace or Dispatcher timer. The same happens when being in my app I hold the back button of my device and then choose the app from the list. My application is as plain as it can be - the timer with a callback and method calling PhotoChooser. Could anyone help with solution or workaround please?

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  • Apple publie un rapport sur sa diversité, « en tant que PDG, je ne suis pas satisfait de ces chiffres » a déclaré Tim Cook

    Apple publie un rapport sur sa diversité, « en tant que PDG, je ne suis pas satisfait de ces chiffres » a déclaré Tim Cook Apple a suivi l'exemple de ses concurrents et s'est également décidé à publier les statistiques sur la diversité de ses employés américains. Aux États-Unis, l'entreprise a déclaré que 55% de son effectif est de la race blanche, 15% sont d'origines asiatiques, 11% sont hispaniques et 7% sont noirs. 2 % se revendiquent comme appartenant à deux catégories, 1 % dans la catégorie...

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  • WEB203 &ndash; Jump into Silverlight!&hellip; and Become Effective Immediately with Tim Huckaby, Fou

    - by Robert Burger
    Getting ready for the good stuff. Definitely wish there were more Silverlight and WCF RIA sessions, but this is a start.  Was lucky to get a coveted power-enabled seat.  Luckily, due to my trustily slow Verizon data card, I can get these notes out amidst a total Internet outage here.  This is the second breakout session of the day, and is by far standing-room only.  I stepped out before the session started to get a cool Diet COKE and wouldn’t have gotten back in if I didn’t already have a seat. Tim says this is an intro session and that he’s been begging for intro sessions at TechEd for years and that by looking at this audience, he thinks the demand is there.  Admittedly, I didn’t know this was an intro session, or I might have gone elsewhere.  But, it was the very first Silverlight session, so I had to be here. Tim says he will be providing a very good comprehensive reference application at the end of the presentation.  He has just demoed it, and it is a full CRUD-based Sales Manager application based on…  AdventureWorks! Session Agenda What it is / How to get started Declarative Programming Layout and Controls, Events and Commands Working with Data Adding Style to Your Application   Silverlight…  “WPF Light” Why is the download 4.2MB?  Because the direct competitor is a 4.2MB download.  There is no technical reason it is not the entire framework.  It is purely to “be competitive”.   Getting Started Get all of the following downloads from www.silverlight.net/getstarted Install VS2010 or Visual Web Developer Express 2010 Install Silverlight 4 Tools for VS2010 Install Expression Blend 4 Install the Silverlight 4 Toolkit   Reference Application Features Uses MVVM pattern – a way to move data access code that would normally be inline within the UI and placing it in nice data access libraries Images loaded dynamically from the database, converting GIF to PNG because Silverlight does not support GIF. LINQ to SQL is the data access model WCF is the data provider and is using binary message encoding   Declarative Programming XAML replaces code for UI representation Attributes control Layout and Style Event handlers wired-up in XAML Declarative Data Binding   Layout Overview Content rendering flows inside of parent Fixed positioning (Canvas) is seldom used Panels are used to house content Margins and Padding over fixed size   Panels StackPanel – Arranges child elements into a single line oriented horizontally or vertically Grid – A flexible grid are that consists of rows and columns Canvas – An are where positions are specifically fixed WrapPanel (in Toolkit) – Positions child elements in sequential position left to right and top to bottom. DockPanel (in Toolkit) – Positions child controls within a dockable area   Positioning Horizontal and Vertical Alignment Margin – Separates an element from neighboring elements Padding – Enlarges the effective size of an element by a thickness   Controls Overview Not all controls created equal Silverlight, as a subset of WPF, so many WPF controls do not exist in the core Siverlight release Silverlight Toolkit continues to add controls, but are released in different quality bands Plenty of good 3rd party controls to fill the gaps Windows Phone 7 is to have 95% of controls available in Silverlight Core and Toolkit.   Events and Commands Standard .NET Events Routed Events Commands – based on the ICommand interface – logical action that can be invoked in several ways   Adding Style to Your Application Resource Dictionaries – Contains a hash table of key/value pairs.  Silverlight can only use Static Resources whereas WPF can also use Dynamic Resources Visual State Manager Silverlight 4 supports Implicit styles ResourceDictionary.MergedDictionaries combines many different file-based resources   Downloads

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  • Ruby Gems Not Installing, Hangs While Getting Gems

    - by Tim Hoolihan
    I recently cleared out all of my ruby install and installed form sources using the instructions at hivelogic I have have been able to install a few gems, but most of the time, "sudo gem install rails" hangs. I've added the -V flag, and it just seems to hang, I don't get any error. And the process can not be killed. I can only reboot to kill the process. My ruby info: [tim@ ~]# ruby -v ruby 1.8.7 (2010-01-10 patchlevel 249) [i686-darwin10.2.0] [tim@ ~]# gem -v 1.3.6 [tim@ ~]# gem environment RubyGems Environment: - RUBYGEMS VERSION: 1.3.6 - RUBY VERSION: 1.8.7 (2010-01-10 patchlevel 249) [i686-darwin10.2.0] - INSTALLATION DIRECTORY: /usr/local/lib/ruby/gems/1.8 - RUBY EXECUTABLE: /usr/local/bin/ruby - EXECUTABLE DIRECTORY: /usr/local/bin - RUBYGEMS PLATFORMS: - ruby - x86-darwin-10 - GEM PATHS: - /usr/local/lib/ruby/gems/1.8 - /Users/tim/.gem/ruby/1.8 - GEM CONFIGURATION: - :update_sources => true - :verbose => true - :benchmark => false - :backtrace => false - :bulk_threshold => 1000 - :sources => ["http://gems.rubyforge.org/", "http://gems.rubyforge.org"] - REMOTE SOURCES: - http://gems.rubyforge.org/ - http://gems.rubyforge.org [tim@ ~]# which ruby /usr/local/bin/ruby [tim@ ~]# which gem /usr/local/bin/gem [tim@ ~]# uname -a Darwin tim-hoolihans-macbook-pro-15.local 10.2.0 Darwin Kernel Version 10.2.0: Tue Nov 3 10:37:10 PST 2009; root:xnu-1486.2.11~1/RELEASE_I386 i386 [tim@ ~]# Any ideas?

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  • load-views when running multiple noir servers

    - by Roth Michaels
    I'm experimenting with using noir to start three servers (each to handle a different aspect of the application). I am trying to do this so that I can run all three servers within one application while developing and easily decouple the project into three different applications for deployment. It is no problem to use noir.server/start and noir.server/stop to run the jetty servers I need. What I'm trying to figure out is some way to call load-views (or something like that) with a different set views for each server so that URI conflicts are handled by the correct defpage.

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  • OpenGL - drawing 2D polygons shapes with texture

    - by plonkplonk
    I am trying to make a few effects in a C+GL game. So far I draw all my sprites as a quad, and it works. However, I am trying to make a large ring appear at times, with a texture following that ring, as it takes less memory than a quad with the ring texture inside. The type of ring I want to make is not a round-shaped GL mesh ring (the "tube" type) but a "paper" 2D ring. That way I can modify the "width" of the ring, getting more of the effect than a simple quad+ring texture. So far all my attempts have been...kind of ridiculous, as I don't understand GL's coordinates too well (and I can't really understand the available documentation...I am just a designer with no coder help or background. A n00b, basically). glBegin(GL_POLYGON); for(i = 0;i < 360; i += 10){ glTexCoord2f(0, 0); glVertex2f(Cos(i)*(H-10),Sin(i)H); glTexCoord2f(0, HP); glVertex2f(Sin(i)(H-10),Cos(i)*(H-10)); glTexCoord2f(WP, HP); glVertex2f(Cos(i)H,Sin(i)(H-10)); glTexCoord2f(WP, 0); glVertex2f(Sin(i)*H,Cos(i)*H); } glEnd(); This is my last attempt, and it seems to generate a "sunburst" from the right edge of the circle instead of a ring. It's an amusing effect but definitely not what I want. Other results included the circle looking exactly the same as the quad textured (aka drawing a sprite literally) or something that looked like a pop-art filter, by working on this train of thought. Seems like my logic here is entirely flawed, so, what would be the easiest way to obtain such a ring? No need to reply in code, just some guidance for a non-math-skilled user...

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