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  • Are comonads a good fit for modeling the Wumpus world?

    - by Tim Stewart
    I'm trying to find some practical applications of a comonad and I thought I'd try to see if I could represent the classical Wumpus world as a comonad. I'd like to use this code to allow the Wumpus to move left and right through the world and clean up dirty tiles and avoid pits. It seems that the only comonad function that's useful is extract (to get the current tile) and that moving around and cleaning tiles would not use be able to make use of extend or duplicate. I'm not sure comonads are a good fit but I've seen a talk (Dominic Orchard: A Notation for Comonads) where comonads were used to model a cursor in a two-dimensional matrix. If a comonad is a good way of representing the Wumpus world, could you please show where my code is wrong? If it's wrong, could you please suggest a simple application of comonads? module Wumpus where -- Incomplete model of a world inhabited by a Wumpus who likes a nice -- tidy world but does not like falling in pits. import Control.Comonad -- The Wumpus world is made up of tiles that can be in one of three -- states. data Tile = Clean | Dirty | Pit deriving (Show, Eq) -- The Wumpus world is a one dimensional array partitioned into three -- values: the tiles to the left of the Wumpus, the tile occupied by -- the Wumpus, and the tiles to the right of the Wumpus. data World a = World [a] a [a] deriving (Show, Eq) -- Applies a function to every tile in the world instance Functor World where fmap f (World as b cs) = World (fmap f as) (f b) (fmap f cs) -- The Wumpus world is a Comonad instance Comonad World where -- get the part of the world the Wumpus currently occupies extract (World _ b _) = b -- not sure what this means in the Wumpus world. This type checks -- but does not make sense to me. extend f w@(World as b cs) = World (map world as) (f w) (map world cs) where world v = f (World [] v []) -- returns a world in which the Wumpus has either 1) moved one tile to -- the left or 2) stayed in the same place if the Wumpus could not move -- to the left. moveLeft :: World a -> World a moveLeft w@(World [] _ _) = w moveLeft (World as b cs) = World (init as) (last as) (b:cs) -- returns a world in which the Wumpus has either 1) moved one tile to -- the right or 2) stayed in the same place if the Wumpus could not move -- to the right. moveRight :: World a -> World a moveRight w@(World _ _ []) = w moveRight (World as b cs) = World (as ++ [b]) (head cs) (tail cs) initWorld = World [Dirty, Clean, Dirty] Dirty [Clean, Dirty, Pit] -- cleans the current tile cleanTile :: Tile -> Tile cleanTile Dirty = Clean cleanTile t = t Thanks!

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  • Projection matrix + world plane ~> Homography from image plane to world plane

    - by B3ret
    I think I have my wires crossed on this, it should be quite easy. I have a projection matrix from world coordinates to image coordinates (4D homogeneous to 3D homgeneous), and therefore I also have the inverse projection matrix from image coordinates to world "rays". I want to project points of the image back onto a plane within the world (which is given of course as 4D homogeneous vector). The needed homography should be uniquely identified, yet I can not figure out how to compute it. Of course I could also intersect the back-projected rays with the world plane, but this seems not a good way, knowing that there MUST be a homography doing this for me. Thanks in advance, Ben

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  • What language has the longest "Hello world" program?

    - by Kip
    In most scripting languages, a "Hello world!" application is very short: print "Hello world" In C++, it is a little more complicated, requiring at least 46 non-whitespace characters: #include <cstdio> int main() { puts("Hello world"); } Java, at 75 non-whitespace characters, is even more verbose: class A { public static void main(String[] args) { System.out.print("Hello world"); } } Are there any languages that require even more non-whitespace characters than Java? Which language requires the most? Notes: I'm asking about the length of the shortest possible "hello world" application in a given language. A newline after "Hello world" is not required. I'm not counting whitespace, but I know there is some language that uses only whitespace characters. If you use that one you can count the whitespace characters.

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  • Creating a voxel world with 3D arrays using threads

    - by Sean M.
    I am making a voxel game (a bit like Minecraft) in C++(11), and I've come across an issue with creating a world efficiently. In my program, I have a World class, which holds a 3D array of Region class pointers. When I initialize the world, I give it a width, height, and depth so it knows how large of a world to create. Each Region is split up into a 32x32x32 area of blocks, so as you may guess, it takes a while to initialize the world once the world gets to be above 8x4x8 Regions. In order to alleviate this issue, I thought that using threads to generate different levels of the world concurrently would make it go faster. Having not used threads much before this, and being still relatively new to C++, I'm not entirely sure how to go about implementing one thread per level (level being a xz plane with a height of 1), when there is a variable number of levels. I tried this: for(int i = 0; i < height; i++) { std::thread th(std::bind(&World::load, this, width, height, depth)); th.join(); } Where load() just loads all Regions at height "height". But that executes the threads one at a time (which makes sense, looking back), and that of course takes as long as generating all Regions in one loop. I then tried: std::thread t1(std::bind(&World::load, this, w, h1, h2 - 1, d)); std::thread t2(std::bind(&World::load, this, w, h2, h3 - 1, d)); std::thread t3(std::bind(&World::load, this, w, h3, h4 - 1, d)); std::thread t4(std::bind(&World::load, this, w, h4, h - 1, d)); t1.join(); t2.join(); t3.join(); t4.join(); This works in that the world loads about 3-3.5 times faster, but this forces the height to be a multiple of 4, and it also gives the same exact VAO object to every single Region, which need individual VAOs in order to render properly. The VAO of each Region is set in the constructor, so I'm assuming that somehow the VAO number is not thread safe or something (again, unfamiliar with threads). So basically, my question is two one-part: How to I implement a variable number of threads that all execute at the same time, and force the main thread to wait for them using join() without stopping the other threads? How do I make the VAO objects thread safe, so when a bunch of Regions are being created at the same time across multiple threads, they don't all get the exact same VAO? Turns out it has to do with GL contexts not working across multiple threads. I moved the VAO/VBO creation back to the main thread. Fixed! Here is the code for block.h/.cpp, region.h/.cpp, and CVBObject.h/.cpp which controls VBOs and VAOs, in case you need it. If you need to see anything else just ask. EDIT: Also, I'd prefer not to have answers that are like "you should have used boost". I'm trying to do this without boost to get used to threads before moving onto other libraries.

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  • ZooZoo’s Are Back! Watch & Download ICC Cricket World Cup 2011 ZooZoo Ads

    - by Gopinath
    For the past couple of years VodaFone ZooZoo’s are integral part of major Cricket events. We have seen them as part of IPL 2 and IPL 3 and now as part of the on going ICC Cricket World Cup 2011 new ZooZoo ads are back on Televisions.  ZooZoos are adorable and they are my favourite videos to watch to relax. So here I’m going to post all the ZooZoo ads that are being aired on televisions as part of ICC Cricket World Cup 2011. If you love to keep the ZooZoo ads collections on you PC, you can click the download link next to each ad and save the videos. Downloads are available in FLV (for viewing on computers) and MP4 (for mobile phones) . Have Fun! Excited girl Zoozoo Interview [Download It] Pilot ZooZoo Interview [Download It] Angry Zoozoo Interview [Download It] Two ZooZoos Interview [Download It] This article titled,ZooZoo’s Are Back! Watch & Download ICC Cricket World Cup 2011 ZooZoo Ads, was originally published at Tech Dreams. Grab our rss feed or fan us on Facebook to get updates from us.

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  • Finding furthermost point in game world

    - by user13414
    I am attempting to find the furthermost point in my game world given the player's current location and a normalized direction vector in screen space. My current algorithm is: convert player world location to screen space multiply the direction vector by a large number (2000) and add it to the player's screen location to get the distant screen location convert the distant screen location to world space create a line running from the player's world location to the distant world location loop over the bounding "walls" (of which there are always 4) of my game world check whether the wall and the line intersect if so, where they intersect is the furthermost point of my game world in the direction of the vector Here it is, more or less, in code: public Vector2 GetFurthermostWorldPoint(Vector2 directionVector) { var screenLocation = entity.WorldPointToScreen(entity.Location); var distantScreenLocation = screenLocation + (directionVector * 2000); var distantWorldLocation = entity.ScreenPointToWorld(distantScreenLocation); var line = new Line(entity.Center, distantWorldLocation); float intersectionDistance; Vector2 intersectionPoint; foreach (var boundingWall in entity.Level.BoundingWalls) { if (boundingWall.Intersects(line, out intersectionDistance, out intersectionPoint)) { return intersectionPoint; } } Debug.Assert(false, "No intersection found!"); return Vector2.Zero; } Now this works, for some definition of "works". I've found that the further out my distant screen location is, the less chance it has of working. When digging into the reasons why, I noticed that calls to Viewport.Unproject could result in wildly varying return values for points that are "far away". I wrote this stupid little "test" to try and understand what was going on: [Fact] public void wtf() { var screenPositions = new Vector2[] { new Vector2(400, 240), new Vector2(400, -2000), }; var viewport = new Viewport(0, 0, 800, 480); var projectionMatrix = Matrix.CreatePerspectiveFieldOfView(MathHelper.PiOver4, viewport.Width / viewport.Height, 1, 200000); var viewMatrix = Matrix.CreateLookAt(new Vector3(400, 630, 600), new Vector3(400, 345, 0), new Vector3(0, 0, 1)); var worldMatrix = Matrix.Identity; foreach (var screenPosition in screenPositions) { var nearPoint = viewport.Unproject(new Vector3(screenPosition, 0), projectionMatrix, viewMatrix, worldMatrix); var farPoint = viewport.Unproject(new Vector3(screenPosition, 1), projectionMatrix, viewMatrix, worldMatrix); Console.WriteLine("For screen position {0}:", screenPosition); Console.WriteLine(" Projected Near Point = {0}", nearPoint.TruncateZ()); Console.WriteLine(" Projected Far Point = {0}", farPoint.TruncateZ()); Console.WriteLine(); } } The output I get on the console is: For screen position {X:400 Y:240}: Projected Near Point = {X:400 Y:629.571 Z:599.0967} Projected Far Point = {X:392.9302 Y:-83074.98 Z:-175627.9} For screen position {X:400 Y:-2000}: Projected Near Point = {X:400 Y:626.079 Z:600.7554} Projected Far Point = {X:390.2068 Y:-767438.6 Z:148564.2} My question is really twofold: what am I doing wrong with the unprojection such that it varies so wildly and, thus, does not allow me to determine the corresponding world point for my distant screen point? is there a better way altogether to determine the furthermost point in world space given a current world space location, and a directional vector in screen space?

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  • How do I run WarCraft Frozen Throne (DOTA)?

    - by DarKoza
    I am Using Linux for the very first time And i have one question. Dunno if it will be answered,but i hope so.. I have fujitsu ah 530 with intergrated video card(INTEL HD) so can i play my fav game on linux? And how to do it? I installed it via Wine,but when i am starting the game with It,the game windows shows soooo poor,its unplayable,i can take i screenshot. Here's a screenshot of what I'm experiencing:

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  • Data Structure for Small Number of Agents in a Relatively Big 2D World

    - by Seçkin Savasçi
    I'm working on a project where we will implement a kind of world simulation where there is a square 2D world. Agents live on this world and make decisions like moving or replicating themselves based on their neighbor cells(world=grid) and some extra parameters(which are not based on the state of the world). I'm looking for a data structure to implement such a project. My concerns are : I will implement this 3 times: sequential, using OpenMP, using MPI. So if I can use the same structure that will be quite good. The first thing comes up is keeping a 2D array for the world and storing agent references in it. And simulate the world for each time slice by checking every cell in each iteration and further processing if an agents is found in the cell. The downside is what if I have 1000x1000 world and only 5 agents in it. It will be an overkill for both sequential and parallel versions to check each cell and look for possible agents in them. I can use quadtree and store agents in it, but then how can I get the information about neighbor cells then? Please let me know if I should elaborate more.

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  • Attaching two objects and changing their world matrices accordingly

    - by A-Type
    I'm having a hard time wrapping my head around the transformations required to bind two objects together in either a two-way or one-way relationship. I will need to implement both types. For the first case, I want to be able to 'couple' two ships together in space. The ships have different mass, of course. Forces applied to either ship will use combined mass and moment of inertia to calculate and move both ships. The trick is, being sure that the point at which they are coupled remains the same, and they don't move at all relative to each other. The second case is similar: I want a ship to be able to enter the atmosphere of a planet and move relative to the planet. The planet will be orbiting the sun, which is fixed at 0,0,0. Essentially, when the ship is sitting still outside of the atmosphere, the planet will move past it on its course-- but when the ship is sitting still inside the atmosphere, it moves and rotates with the planet, so that it is always relative to the horizon. Essentially, the vertices which make up the ship are now transformed just like the ones that make up the planet, except that the ship can move itself around relative to the planet. I get the feeling I can implement both of these with the same code. Essentially, I am thinking of giving each object (which I call Fixtures) a list of "slave" Fixtures onto which that Fixture's world matrix is imposed. So, this would be the planet imposing its world on any contained ships. In the case of coupling, I would simply make each ship a slave of the other, somehow. Obviously I can't just multiply the ship's world matrix by the planet's, or each ship by the others. What I'd like some help with is what calculations to make in order to get a nice, seamless relative world to the other object. I was thinking maybe I could just multiply the world of the slave by the inverse of the master, but then when you couple two ships you would lose all that world data. So, perhaps I need an intermediate "world" which is the absolute world, but use a secondary "final world" to actually transform the objects?

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  • Hello World bootloader not working!

    - by Newbie
    Hello. I've been working through the tutorials on this webpage which progressively creates a bootloader that displays Hello World. The 2nd tutorial (where we attempt to get an "A" to be output) works perfectly, and yet the 1st tutorial doesn't work for me at all! (The BIOS completely ignores the floppy disk and boots straight into Windows). This is less of an issue, although any explanations would be appreciated. The real problem is that I can't get the 3rd tutorial to work. Instead on outputting "Hello World", I get an unusual character (and blinking cursor) in the bottom-left corner of the screen. It looks a bit like a smiley face inside a rounded rectangle. Does anyone know how to get Hello World to display as it should?

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  • Screen space to world space

    - by user13414
    I am writing a 2D game where my game world has x axis running left to right, y axis running top to bottom, and z axis out of the screen: Whilst my game world is top-down, the game is rendered on a slight tilt: I'm working on projecting from world space to screen space, and vice-versa. I have the former working as follows: var viewport = new Viewport(0, 0, this.ScreenWidth, this.ScreenHeight); var screenPoint = viewport.Project(worldPoint.NegateY(), this.ProjectionMatrix, this.ViewMatrix, this.WorldMatrix); The NegateY() extension method does exactly what it sounds like, since XNA's y axis runs bottom to top instead of top to bottom. The screenshot above shows this all working. Basically, I have a bunch of points in 3D space that I then render in screen space. I can modify camera properties in real time and see it animate to the new position. Obviously my actual game will use sprites rather than points and the camera position will be fixed, but I'm just trying to get all the math in place before getting to that. Now, I am trying to convert back the other way. That is, given an x and y point in screen space above, determine the corresponding point in world space. So if I point the cursor at, say, the bottom-left of the green trapezoid, I want to get a world space reading of (0, 480). The z coordinate is irrelevant. Or, rather, the z coordinate will always be zero when mapping back to world space. Essentially, I want to implement this method signature: public Vector2 ScreenPointToWorld(Vector2 point) I've tried several things to get this working but am just having no luck. My latest thinking is that I need to call Viewport.Unproject twice with differing near/far z values, calculate the resultant Ray, normalize it, then calculate the intersection of the Ray with a Plane that basically represents ground-level of my world. However, I got stuck on the last step and wasn't sure whether I was over-complicating things. Can anyone point me in the right direction on how to achieve this?

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  • Camera Projection back Into 3D world, offset error

    - by Anthony
    I'm using XNA to simulate a robot in a 3D world and then do image analysis on what the camera sees. I have my camera looking down in front of the direction that the robot is going, and I have the robot detecting white pixels. I'm trying to take the white pixels that it finds and project them back into the 3D world so that I can see if it is actually detecting the correct pixels. I almost have it working, but there is an offset between where the white is in in the World and were I put my orange triangles (which represent what the robot things is white). /// <summary> /// Takes a bool map of and makes vertex positions based on the map. /// </summary> /// <param name="c"> The bool map</param> private void ProjectBoolMapOnGroundAnthony2(bool[,] c) { float triangleSize = 0.04f; // Point of interest in World W cordinate system. Vector3 pointOfInterest_W = Vector3.Zero; // Point of interest in Robot Cordinate system R Vector3 pointOfInterest_R = Vector3.Zero; // alpha is the angle from the robot camera to where it is looking in the center. //double alpha = Math.Atan(1.8f / 1); /// Matrix representation of the view determined by the position, target, and updirection. Matrix View = ((SimulationMain)Game).mainRobot.robotCameraView.View; /// Matrix representation of the view determined by the angle of the field of view (Pi/4), aspectRatio, nearest plane visible (1), and farthest plane visible (1200) Matrix Projection = ((SimulationMain)Game).mainRobot.robotCameraView.Projection; /// Matrix representing how the real world cordinates differ from that of the rendering by the camera. Matrix World = ((SimulationMain)Game).mainRobot.robotCameraView.World; Plane groundPlan = new Plane(Vector3.UnitZ, 0.0f); for (int x = 0; x < this.screenWidth; x++) { for (int y = 0; y < this.screenHeight; ) { if (c[x, y] == true && this.count1D < 62000) { int j = 1; Vector3 nearPlanePoint = Game.GraphicsDevice.Viewport.Unproject(new Vector3(x, y, 0), Projection, View, World); Vector3 farPlanePoint = Game.GraphicsDevice.Viewport.Unproject(new Vector3(x, y, 1), Projection, View, World); //Vector3 pointOfInterest_W = Vector3.in Ray ray = new Ray(nearPlanePoint, farPlanePoint); pointOfInterest_W = ray.Position + ray.Direction * (float) ray.Intersects(groundPlan); this.vertexArray2[this.count1D + 0].Position.X = pointOfInterest_W.X - triangleSize; this.vertexArray2[this.count1D + 0].Position.Y = pointOfInterest_W.Y - triangleSize * j; this.vertexArray2[this.count1D + 0].Position.Z = pointOfInterest_W.Z; this.vertexArray2[this.count1D + 0].Color = Color.DarkOrange; // Put another vertex a the position but +1 in the X direction triangleSize //this.vertexArray2[this.count1D + 1].Position.X = pointOnGroud.X + 3; //this.vertexArray2[this.count1D + 1].Position.Y = pointOnGroud.Y + j; this.vertexArray2[this.count1D + 1].Position.X = pointOfInterest_W.X; this.vertexArray2[this.count1D + 1].Position.Y = pointOfInterest_W.Y + triangleSize * j; this.vertexArray2[this.count1D + 1].Position.Z = pointOfInterest_W.Z; this.vertexArray2[this.count1D + 1].Color = Color.Red; // Put another vertex a the position but +1 in the X direction //this.vertexArray2[this.count1D + 0].Position.X = pointOnGroud.X; //this.vertexArray2[this.count1D + 0].Position.Y = pointOnGroud.Y + 3 + j; this.vertexArray2[this.count1D + 2].Position.X = pointOfInterest_W.X + triangleSize; this.vertexArray2[this.count1D + 2].Position.Y = pointOfInterest_W.Y - triangleSize * j; this.vertexArray2[this.count1D + 2].Position.Z = pointOfInterest_W.Z; this.vertexArray2[this.count1D + 2].Color = Color.Orange; this.count1D += 3; y += j; } else { y++; } } } } The world is a grass texture with lines on it. The world plane is normal at (0,0,1). Any ideas on why there is an offset? Any Ideas? Thanks for the help, Anthony G.

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  • Oracle Open World – Larry Ellison

    - by Tim Koekkoek
    On 30th September, Oracle Open World 2012 started. Oracle Open World is the world’s largest and most important annual conference for Oracle users, technologists, partners and customers. The conference consists of various trainings, exhibitions, hands-on workshops, networking and of course, keynotes from big names across the IT industry. The keynote of Larry Ellison, CEO of Oracle, is always one of the highlights of Oracle Open World. Interested in what he said this year? Please see below some highlights of his keynote: For more information about Oracle Open World, check http://www.oracle.com/openworld/index.html!

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  • Box2d world width and height ratio with screen width and height

    - by Sujith
    I have view, for example GameView which extends SurfaceView . I have integrated Box2D physics in GameView. I have two widths , GameView width, height and Box2D physics world width ,height. I need to get the position of box2d world with the GameView co-ordinates. For example, Total width of screen = 240 Total height of screen = 320 Screen points needed to be mapped onto box2d co-ordinates (x,y) = 127, 139 For this i need to get the max width and height of the Box2d physics world. Is there is any way to get the max width and height of Box2d world. or Can i limit the width and height of box2d world within the screen resolution.

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  • Java 2D World question

    - by Munkybunky
    I have a 2D world background made up of a Grid of graphics, which I display on screen with a viewport (800x600) and it all works. My question is I have the following code to convert the mouse co-ordinates to world co-ordinates then World co-ordinates to grid co-ordinates then grid co-ordinates to screen co-ordinates. //Add camerax to mouse screen co-ords to convert to world co-ords. int cursorx_world=(int)camerax+(int)GameInput.mousex; int cursorx_grid=(int)cursorx_world/blocksize; // World Co-ords / gridsize give grid co-ords int cursorx_screen=-(int)camerax+(cursorx_grid*blocksize); So is there anyway I can convert straight from mouse screen co-ords to screen co-ordinates?

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  • Running multiple box2D world objects on a server

    - by CharbelAbdo
    I'm creating a multiplayer game using LibGdx (with Box2d) and Kryonet. Since this is the first time I work on multiplayer games, I read a bit about server - client implementations, and it turns out that the server should handle important tasks like collision detection, hits, characters dying etc... Based on some articles (like the excellent Gabriel Gambetta Fast paced multiplayer series), I also know that the client should work in parallel to avoid the lag while the server responds to commands. Physics wise, each game will have 2 players, and any projectiles fired. What I'm thinking of doing is the following: Create a physics world on the client When the game is signaled to start, I create the same physics world on the server (without any rendering obviously). Whenever the player issues a command (move or fire), I send the command to the server and immediately start processing it on the client. When the server receives the command, it applies it on the server's world (set velocity etc...) Each 100ms, the server sends the new state to the client which corrects what was calculated locally. Any critical action (hit, death, level up) is calculated only on the server and sent to the client. Essentially, I would have a Box2d World object running on the server for each game in progress, in sync with the worlds running on the clients. The alternative would be to do my own calculations on the server instead of relying on Box2D to do them for me, but I'm trying to avoid that. My question is: Is it wise to have, for example, 1000 instances of the World object running and executing steps on the server? Tomcat used around 750 MBytes of memory when trying it without any object added to the world. Anybody tried that before? If not, is there any alternative? Google did not help me, are there any guidelines to use when you want to have physics on both the client and the server? Thanks for any help.

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  • How to improve Minecraft-esque voxel world performance?

    - by SomeXnaChump
    After playing Minecraft I marveled a bit at its large worlds but at the same time I found them extremely slow to navigate, even with a quad core and meaty graphics card. Now I assume Minecraft is fairly slow because: A) It's written in Java, and as most of the spatial partitioning and memory management activities happen in there, it would naturally be slower than a native C++ version. B) It doesn't partition its world very well. I could be wrong on both assumptions; however it got me thinking about the best way to manage large voxel worlds. As it is a true 3D world, where a block can exist in any part of the world, it is basically a big 3D array [x][y][z], where each block in the world has a type (i.e BlockType.Empty = 0, BlockType.Dirt = 1 etc.) Now, I am assuming to make this sort of world perform well you would need to: A) Use a tree of some variety (oct/kd/bsp) to split all the cubes out; it seems like an oct/kd would be the better option as you can just partition on a per cube level not a per triangle level. B) Use some algorithm to work out which blocks can currently be seen, as blocks closer to the user could obfuscate the blocks behind, making it pointless to render them. C) Keep the block object themselves lightweight, so it is quick to add and remove them from the trees. I guess there is no right answer to this, but I would be interested to see peoples' opinions on the subject. How would you improve performance in a large voxel-based world?

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  • Forbes Announcing The World’s Top 20 Billionaires

    - by Suganya
    Forbes company recently conducted a survey to figure out the world’s Billionaires list and has released it listing the top 20 names of the Billionaires. The company says that for the third time in the last three years the world has a new richest man for this year. So it means that Bill Gates was beaten up by someone else in world. Who is the new richest man in the world?   Forbes.Com announced the richest man in world and this time it is not Bill Gates. But it is Carlos Slim Helu who is into Telecom industry. Carlos lives in Mexico and he had the third richest man’s place last year. Having shown a Net worth of $ 53.5 Billion, Carlos has increased $18.5 Billion in a year. Carlos swooped on the privatization of Mexico’s national telephone service during the last decade and now has achieved the world’s first richest man. Following Carlos, in the second position is Bill Gates with the Nett worth of $53 Billion. As Bill Gates requires no great introduction, lets move on to the next place. The third place is occupied by Warren Buffett followed by Mukesh Ambani and Lakshmi Mittal in fourth and fifth places respectively. The top 20 names of world’s richest people, their occupation and the Nett worth that they hold are S.No Name Nett Worth (in $ Billion) Source of Income 1 Carlos Slim Helu 53.5 Telecom 2 Bill Gates 53 Microsoft 3 Warren Buffett 47 Investments 4 Mukesh Ambani 29 Petrochemical, Oil and Gas 5 Lakshmi Mittal 28.7 Steel 6 Lawrence Ellison 28 Oracle 7 Bernard Arnault 27.5 Luxury Goods 8 Eike Batista 27 Mining, Oil 9 Amancio Ortega 25 Fashion, Retail 10 Karl Albrecht 23.5 Supermarkets 11 Ingvar Kamprad and Family 23 IKEA 12 Christy Walton and Family 22.5 Wal-Mart 13 Stefan Persson 22.4 H & M 14 Li Ka-shing 21 Diversified 15 Jim C. Walton 20.7 Wal-Mart 16 Alice Walton 20.6 Wal-Mart 17 Liliane Bettencourt 20 L’Oreal 18 S. Robson Walton 19.8 Wal-Mart 19 Prince Alwaleed bin Talal Alsaud 19.4 Diversified 20 David Thomson and Family 19 Thomson Reuters   Source: Forbes and Image Credit : kevindooley Join us on Facebook to read all our stories right inside your Facebook news feed.

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  • "Hello World" in less than 20 bytes

    - by xelurg
    We have had an interesting competition once, where everyone would write their implementation of hello world program. One requirement was that is should be less than 20 bytes in compiled form. the winner would be the one whose version is the smallest... What would be your solution? :) Platform: 32bit, x86 OS: DOS, Win, GNU/Linux, *BSD Language: Asm, C, or anything else that compiles into binary executable (i.e. no bash scripts and stuff ;)

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  • Reimplementing data structures in the real world

    - by Jason
    The topic of algorithms class today was reimplementing data structures, specifically ArrayList in Java. The fact that you can customize a structure for in various ways definitely got me interested, particularly with variations of add() & iterator.remove() methods. But is reimplementing and customizing a data structure something that is of more interest to the academics vs the real-world programmers? Has anyone reimplemented their own version of a data structure in a commercial application/program, and why did you pick that route over your particular language's implementation?

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  • C & MinGW: Hello World gives me the error "programm too big to fit in memory"

    - by user1692088
    I'm new here. Here's my problem: I installed MinGW on my Windows 7 Home Premium 32-bit Netbook with Intel Atom CPU N550, 1.50GHz and 2GB RAM. Now I made a file named hello.h and tried to compile it via CMD with the following command: "gcc c:\workspace\c\helloworld\hello.h -o out.exe" It compiles with no error, but when I try to run out.exe, it gives me following error: "program too big to fit in memory" Things I have checked: I have added "C:\MinGW\bin" to the Windows PATH Variable I have googled for about one hour, but ever since I'm a newbie, I can't really figure out what the problem is. I have compiled the same code on my 64-bit machine, compiles perfectly, but cannot be run due to 64-bit <- 16-bit problematic. I'd really appreciate, if someone could figure out, what the problem is. Btw, here's my hello.h: #include <stdio.h> int main(void){ printf("Hello, World\n"); } ... That's it. Thanks for your replies. Cheers, Boris

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  • How Star Wars Changed the World [Infographic]

    - by ETC
    The Star Wars film franchise has had an enormous impact on the world of film, gaming, and special effects. Check out this interesting infographic to see how Star Wars has impacted the world. Created by Michelle Devereau, the “How Star Wars Changed the World” infographic is a massive under taking of charting and cross-referencing. It does an excellent job highlighting the impact the Star Wars films have had on film, television, gaming, and the surrounding technologies. At minimum you’ll nail down some new trivia (I learned, for example, that famed puppeteer and voice actor Frank Oz was the man behind Yoda), even better you’ll have an appreciate for what a sweeping effect Star Wars has had. For readers behind finicky firewalls, click here to view a local mirror of the image. How Star Wars Changed the World [Daily Infographic] Latest Features How-To Geek ETC Should You Delete Windows 7 Service Pack Backup Files to Save Space? What Can Super Mario Teach Us About Graphics Technology? Windows 7 Service Pack 1 is Released: But Should You Install It? How To Make Hundreds of Complex Photo Edits in Seconds With Photoshop Actions How to Enable User-Specific Wireless Networks in Windows 7 How to Use Google Chrome as Your Default PDF Reader (the Easy Way) Reclaim Vertical UI Space by Moving Your Tabs to the Side in Firefox Wind and Water: Puzzle Battles – An Awesome Game for Linux and Windows How Star Wars Changed the World [Infographic] Tabs Visual Manager Adds Thumbnailed Tab Switching to Chrome Daisies and Rye Swaying in the Summer Wind Wallpaper Read On Phone Pushes Data from Your Desktop to the Appropriate Android App

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  • Hello World Pagelet

    - by astemkov
    Introduction The goal of this exercise is to give you a basic feel of how you can use Pagelet Producer to proxy a web page We will proxy a simple static Hello World web page, cut one section out of that page and present it as a pagelet that you can later insert on your own application page or to your portal page such as WebCenter Portal space or WebCenter Interaction community page. Hello World sample app This is the static web page we will work with: Let's assume the following: The Hello World web page is running on server http://appserver.company.com:1234/ The Hello World web page path is: http://appserver.company.com:1234/helloworld/ Initial Pagelet Producer setup Let's assume that the Pagelet Producer server is running on http://pageletserver.company.com:8889/pagelets/ First let's check that Pagelet Producer is up and running. In order to do that we just need to access the following URL: http://pageletserver.company.com:8889/pagelets/ And this is what should be returned: Now you can access Pagelet Producer administration screens using this URL: http://pageletserver.company.com:8889/pagelets/admin This is how the UI looks: Now if you connect to the internet via proxy server, you need to configure proxy in Pagelet Producer settings. In the Navigator pane: Jump To - Settings Click on "Proxy" Enter your proxy server configuration: Creating a resource First thing that you need to do is to create a resource for your web page. This will tell Pagelet Producer that all sub-paths of the web page should be proxied. It also will allow you to setup common rules of how your web page should be proxied and will serve as a container for your pagelets. In the Navigator pane: Jump To - Resources Click on any existing resource (ex. welcome_resource) Click on "Create selected type" toolbar button at the top of the Navigator pane Select "Web" in the "Select Producer Type" dialog box and click "OK" Now after the resource is created let's click on "General" sub-item a specify the following values Name = AppServer Source URL = http://appserver.company.com:1234/ Destination URL = /appserver/ Click on "Save" toolbar button at the top of the Navigator pane After the resource is created our web page becomes accessible by the URL: http://pageletserver.company.com:8889/pagelets/appserver/helloworld/ So in original web page address Source URL is replaced with Pagelet Producer URL (http://pageletserver.company.com:8889/pagelets) + Destination URL Creating a pagelet Now let's create "Hello World" pagelet. Under the resource node activate Pagelets subnode Click on "Create selected type" toolbar button at the top of the Navigator pane Click on "General" sub-node of newly created pagelet and specify the following values Name = Hello_World Library = MyLib Library is used for logical grouping. The portals use the "Library" value to group pagelets in their respective UI's. For example, when adding pagelets to a WebCenter Portal space you would see the individual pagelets listed under the "Library" name. URL Suffix = helloworld/index.html this is where the Hello World page html is served from Click on "Save" toolbar button at the top of the Navigator pane The Library name can be anything you want, it doesn't have to match the resource name at all. It is used as a logical grouping of pagelets, and you can include pagelets from multiple resources into the same library or create a new library for each pagelet. After you save the pagelet you can access it here: http://pageletserver.company.com:8889/pagelets/inject/v2/pagelet/MyLib/Hello_World which is : http://pageletserver.company.com:8889/pagelets/inject/v2/pagelet/ + [Library] + [Name] Or to test the injection of a pagelet into iframe you can click on the pagelets "Documentation" sub-node and use "Access Pagelet using REST" URL: This is what we will see: Clipping The pagelet that we just created covers the whole web page, but we want just the "Hello World" segment of it. So let's clip it. Under the Hello_World pagelet node activate Clipper sub-node Click on "Create selected type" toolbar button at the top of the Navigator pane Specify a Name for newly created clipper. For example: "c1" Click on "Content" sub-node of the clipper Click on "Launch Clipper" button New browser window will open By moving a mouse pointer over the web page select the area you want to clip: Click left mouse button - the browser window will disappear and you will see that Clipping Path was automatically generated Now let's save and access the link from the "Documentation" page again Here's our pagelet nicely clipped and ready for being used on your Web Center Space

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