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  • bash : recursive listing of all files problem

    - by Michael Mao
    Run a recursive listing of all the files in /var/log and redirect standard output to a file called lsout.txt in your home directory. Complete this question WITHOUT leaving your home directory. An: ls -R /var/log/ /home/bqiu/lsout.txt I reckon the above bash command is not correct. This is what I've got so far: $ ls -1R .: cal.sh cokemachine.sh dir sort test.sh ./dir: afile.txt file subdir ./dir/subdir: $ ls -R | sed s/^.*://g cal.sh cokemachine.sh dir sort test.sh afile.txt file subdir But this still leaves all directory/sub-directory names (dir and subdir), plus a couple of empty newlines How could I get the correct result without using Perl or awk? Preferably using only basic bash commands(this is just because Perl and awk is out of assessment scope)

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  • bash script to delete old deployments

    - by benjwarner
    I have a directory where our deployments go. A deployment (which is itself a directory) is named in the format: <application-name>_<date> e.g. trader-gui_20091102 There are multiple applications deployed to this same parent directory, so the contents of the parent directory might look something like this: trader-gui_20091106 trader-gui_20091102 trader-gui_20091010 simulator_20091106 simulator_20091102 simulator_20090910 simulator_20090820 I want to write a bash script to clean out all deployments except for the most current of each application. (The most current denoted by the date in the name of the deployment). So running the bash script on the above parent directory would leave: trader-gui_20091106 simulator_20091106 Any help would be appreciated.

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  • using bash: write bit representation of integer to file

    - by theseion
    Hullo First, I want to use bash for this and the script should run on as many systems as possible (I don't know if the target system will have python or whatever installed). Here's the problem: I have a file with binary data and I need to replace a few bytes in a certain position. I've come up with the following to direct bash to the offset and show me that it found the place I want: dd bs=1 if=file iseek=24 conv=block cbs=2 | hexdump Now, to use "file" as the output: echo anInteger | dd bs=1 of=hextest.txt oseek=24 conv=block cbs=2 This seems to work just fine, I can review the changes made in a hex editor. Problem is, "anInteger" will be written as the ASCII representation of that integer (which makes sense) but I need to write the binary representation. How do I tell the command to convert the input to binary (possibly from a hex)?

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  • Adding line with text between pattern and next occurence of the same pattern in bash

    - by kasper
    I am writing a bash script that modifies a file that looks like this: --- usr1 --- data data data data data data data data data data data data --- usr2 --- data data data data data data data data --- usr3 --- data data data data --- endline --- One question is: How to add next user line --- usrn --- after last user data lines? Second one is: How to delete specific user data lines (data lines and --- userx ---) i.e. I would like to delete usr2 with all his data set. It must work on bash 2.05 :) and I think it will use awk or sed, but I'm not sure.

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  • bash: flushing stdin (standard input)

    - by rahul
    I have a bash script that gets some input as stdin. After processing, I copy a file using "-i" (interactive). However, this never gets executed since (I guess) standard input has not been flushed. To simplify with an example: #!/bin/bash while read line do echo $line done # the next line does not execute read -p "y/n" x echo "got $x" Place this in t.sh, and execute with: ls | ./t.sh The read is not executed. I need to flush stdin before the read. How could it do this?

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  • Magic function `bash ` not found

    - by inspectorG4dget
    I have a bunch of simulations that I want to run on a high-performance cluster, on which I should make reservations to get computing time. Since the reservations are bounded by time, I am developing an automation script that I can scp into the cluster and run. This script will then download the relevant simulation files, run them, and upload the results. Part of this automation script is in bash (cp, scp, etc) and the rest is in python. In order to develop this automation, I am using an IPython notebook. So far, I've coded all the python automation stuff in my IPython notebook and am trying to write the bash part of it now. However, it seems that the magic %%bash doesn't work in my IPython notebook. I get the following error when I have this code in my cell: Cell %%bash echo hi Error File "<ipython-input-22-62ec98e35224>", line 3 echo hi ^ SyntaxError: invalid syntax On a whim, I tried this: Cell %%bash print "hi" Error hi ERROR: Magic function `bash` not found. So I tried this with %%system, %%! and %%shell. But none of those work; they all give me the same error. Why is this happening? How can I fix this? Metadata: IPython 0.13.dev Python 2.7.1 Mac OS X Lion

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  • How to do GUI for bash scripts?

    - by maxorq
    I want to do some graphic dialogs for my script but don't know how. I hear something about GTK-Server or something like that. If someone know how to link bash with tcl/tk I also be satisfied. Please do not post something like "change to C++" because my project must be a script in BASH, there are no other option. Any ideas? P.S. Sorry for bad english! EDIT: Thanks for answers but I don't want "graphics" like colors in console, but windows that shows like hmmmm..... net browser which I can move, minimalize etc. I will test xmessage, but I don't think that will be that what I searching for. EDIT2: And one more thing. I don't want make a simple dialog like yes/no, but some interface like progress bars and buttons, something like game :)

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  • boolean type for while loop in bash?

    - by user151841
    I have a cron script on a shared web host that occasionally gets killed. I'd like to make a loop in bash that tries again if it gets killed, because most of the time it will make it. I'm having trouble with the syntax for storing a boolean value :P #!/bin/bash VAR=0; while [ $VAR ]; do if nice -19 mysqldump -uuser -ppassword -h database.hostname.com --skip-opt --all --complete-insert --add-drop-table database_name > ~/file/system/path/filename.sql; then VAR=1; fi done So the script recovers from a killed process okay, but once it's run properly, the new VAR value doesn't kill the while loop. What am I doing wrong?

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  • Array in Bash Not Found

    - by Waffle
    I am trying to declare an array in bash, but when the code is run it says it cannot find the array. I have tried to write out the declaration of the array in several different ways, but it seems no matter how I try to declare it I cannot get it to work. I originally tried to declare it as such: candidate[1]= 0 candidate[2]= 0 candidate[3]= 0 The error messages that are returned are: votecalculation.sh: 13: candidate[1]=: not found votecalculation.sh: 14: candidate[2]=: not found votecalculation.sh: 15: candidate[3]=: not found After this I tried another solution I found online: ARRAY=( 'can1' 'can2' 'can3' ) When that is used it returns this error: votecalculation.sh: 12: Syntax error: "(" unexpected I am new to Bash and am getting really confused about arrays. Is there some specific way I need to declare an array or am I just going about it completely wrong?

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  • BASH SHELL IF ELSE run command in background

    - by bikerben
    I have used the & command before to make a script run another script in the background like so: #!/bin/bash echo "Hello World" script1.sh & script2.sh & echo "Please wait..." But lets say I have another script with an IF ELSE statment and I would like to set an ELIF statement mid flow as a background task witht the & and then carry on with processing the rest of my script knowing that while rest of the ELIF will carry running in the back ground: #!/bin/bash if cond1; then stuff sleep 10 & stuff stuff elif cond2; then something else else echo "foo" fi stuff echo "Hello World" I really hope this makes sense any help would be greatly appreciated.

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  • Help with variables and new lines, and quoting in a bash script

    - by Scott
    I would like to automate the following svn command. Note this command produces the desired results on my system - Ubuntu 10.04, svn 1.6.6, bash shell, when issued from the command line: svn ci -m $'Added new File: newFile.txt\nOrig loc: /etc/networking/newFile.txt' /home/user/svnDir/newFile.txt I would like to run that command in a bash script, assuming that the original full path to the file is contained in the variable $oFileFull, and the filename is in $oFileName. The script is executed from the svn directory. I need to allow for the possibility that the file name and or path contain spaces. so the line inside my shel script might look like: svn ci -m$'Added new file: ${oFileName}\nOrig loc: ${oFileFull}' ${oFileName} But I want the variables (which may contain spaces) expanded before the command is executed, and I cannot figure out how to do this while enclosing the svn comment in single quotes which is necessary in order to get the new line in the subversion comment log. I am pulling my hair out trying to figure out how to properly quote and assemble this command. Any help appreciated.

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  • Translate parse_git_branch function to zsh from bash (for prompt)

    - by yar
    I am using this function in Bash function parse_git_branch { git_status="$(git status 2> /dev/null)" pattern="^# On branch ([^${IFS}]*)" if [[ ! ${git_status}} =~ "working directory clean" ]]; then state="*" fi # add an else if or two here if you want to get more specific if [[ ${git_status} =~ ${pattern} ]]; then branch=${BASH_REMATCH[1]} echo "(${branch}${state})" fi } but I'm determined to use zsh. While I can use this perfectly as a shell script (even without a shebang) in my .zshrc the error is a parse error on this line if [[ ! ${git_status}}... What do I need to do to get it ready for zshell? Edit: The "actual error" I'm getting is " parse error near } and it refers to the line with the strange double }}, which works on Bash. Edit: Here's the final code, just for fun: parse_git_branch() { git_status="$(git status 2> /dev/null)" pattern="^# On branch ([^[:space:]]*)" if [[ ! ${git_status} =~ "working directory clean" ]]; then state="*" fi if [[ ${git_status} =~ ${pattern} ]]; then branch=${match[1]} echo "(${branch}${state})" fi } setopt PROMPT_SUBST PROMPT='$PR_GREEN%n@$PR_GREEN%m%u$PR_NO_COLOR:$PR_BLUE%2c$PR_NO_COLOR%(!.#.$)' RPROMPT='$PR_GREEN$(parse_git_branch)$PR_NO_COLOR' Thanks to everybody for your patience and help. Edit: The best answer has schooled us all: git status is porcelain (UI). Good scripting goes against GIT plumbing. Here's the final function: parse_git_branch() { in_wd="$(git rev-parse --is-inside-work-tree 2>/dev/null)" || return test "$in_wd" = true || return state='' git diff-index HEAD --quiet 2>/dev/null || state='*' branch="$(git symbolic-ref HEAD 2>/dev/null)" test -z "$branch" && branch='<detached-HEAD>' echo "(${branch#refs/heads/}${state})" } PROMPT='$PR_GREEN%n@$PR_GREEN%m%u$PR_NO_COLOR:$PR_BLUE%2c$PR_NO_COLOR%(!.#.$)' RPROMPT='$PR_GREEN$(parse_git_branch)$PR_NO_COLOR' Note that only the prompt is zsh-specific. In Bash it would be your prompt plus "\$(parse_git_branch)". This might be slower (more calls to GIT, but that's an empirical question) but it won't be broken by changes in GIT (they don't change the plumbing). And that is very important for a good script moving forward. Days Later: Ugh, it turns out that diff-index HEAD is NOT the same as checking status against working directory clean. So will this mean another plumbing call? I surely don't have time/expertise to write my own porcelain....

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  • BASH: Checking for environment variables

    - by Hamza
    Hi folks, I am trying to check the value of an environment variable and depending on the value do certain things and it works fine as long as the variable is set. When it isn't though I get a whole bunch of errors (as BASH is trying to compare the string I specify with an undefined variable, I guess) I tried implementing an extra check to prevent it happening but no luck. The block of code I am using is: #!/bin/bash if [ -n $TESTVAR ] then if [ $TESTVAR == "x" ] then echo "foo" exit elif [ $TESTVAR == "y" ] then echo "bar" exit else echo "baz" exit fi else echo -e "TESTVAR not set\n" fi And this the output: $ export TESTVAR=x $ ./testenv.sh foo $ export TESTVAR=y $ ./testenv.sh bar $ export TESTVAR=q $ ./testenv.sh baz $ unset TESTVAR $ ./testenv.sh ./testenv.sh: line 5: [: ==: unary operator expected ./testenv.sh: line 9: [: ==: unary operator expected baz My question is, shouldn't 'unset TESTVAR' nullify it? It doesn't seem to be the case... Thanks.

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  • Bash script with regex not behaving on Ubuntu

    - by user265330
    I have a Bash script that is working on my OpenSuSE box, but when copied across to my Ubuntu box, is not working. The script reads in from a file. The file has fields separated by white space (tabs and spaces). #!/bin/bash function test1() { while read LINE do if [[ $LINE =~ "^$" || $LINE =~ "^#.*" ]] ; then continue; fi set -- $LINE local field1=$1 local field2=$2 done < test.file } test1 with test.file containing: # Field1Header Field2Header abcdef A-2 ghijkl B-3 There seem to be two problems: (1) $field2, the one with the hyphen, is blank (2) The regex to strip out the blank lines and lines that start with # is not working Anyone know what's wrong? As I said, it works fine on OpenSuSE. Thanks, Paul

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  • Send the "ENTER" from a bash script

    - by Smat
    I am trying to create a bash script to simulate a mail attack to our mailserver. For this reason i want to create a bash script to send hundred of mails to our server, but when i launch the command: $telnet 192.168.12.1 25 <-- where 192.168.12.1 is the ip of our server The telnet session start and all the commands that i write later aren't executed. I also tried to create a second script to launch command on the telnet session after that this one are been created, but when i write from the second script: $echo -ne "EHLO domain.com\r\f" It print the command but doesn't do the ENTER so the command is not taken. Any idea?

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  • Validating parameters to a bash script

    - by nickf
    I'm a total newbie to doing any bash scripting, but I came up with a basic one to help automate the process of removing a number of folders as they become unneeded. #!/bin/bash rm -rf ~/myfolder1/$1/anotherfolder rm -rf ~/myfolder2/$1/yetanotherfolder rm -rf ~/myfolder3/$1/thisisafolder This is evoked like so: ./myscript.sh <{id-number}> The problem is that if you forget to type in the id-number (as I did just then), then it could potentially delete a lot of things that you really don't want deleted. Is there a way you can add any form of validation to the command line parameters? In my case, it'd be good to check that a) there is one parameter, b) it's numerical, and c) that folder exists; before continuing with the script.

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  • Batch To Bash Conversion

    - by Steven
    I need to know this Batch Script into Bash : @echo off set /p name= Name? findstr /m "%name%" ndatabase.txt if %errorlevel%==0 ( cls echo The name is found in the database! pause >nul exit ) cls echo. echo Name not found in database. pause >nul exit I am new to the Linux Kernel, so starting off with an easy distro - Ubuntu 12.10. My problem is that I do not really know much of Bash Script, since I am very accustomed to the Batch Script format; which is obviously a bad habit for my C++.

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  • convert Bash command to php

    - by Keverw
    This is the bash command echo -n x && (echo 618cf954-6576-491d-8ac6-a1b888c4705d |xxd -r -p |openssl base64|tr '/+' '_-') This is my php <? $uuid = "618cf954-6576-491d-8ac6-a1b888c4705d"; $voiceid = "x" . $uuid; $voiceid = base64_encode($voiceid); $voiceid = str_replace("+", "-", $voiceid); $voiceid = str_replace("/", "_", $voiceid); echo $voiceid; ?> The bash gives the right output, the php one isn't. I'm not sure what i need to do deferent in php.

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