Search Results

Search found 7607 results on 305 pages for 'bash profile'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 20/305 | < Previous Page | 16 17 18 19 20 21 22 23 24 25 26 27  | Next Page >

  • How do I change HOMEDRIVE HOMEPATH and HOMESHARE in Windows XP?

    - by user26034
    I have got a laptop which is configured to have the user profile in a network drive. This is causing me a lot of headaches since the connectivity to my company is very slow. I want to relocate the profile of my user into a local directory. How do I do that? Those are the settings at the moment: C:\>set HOME HOMEDRIVE=P: HOMEPATH=\ HOMESHARE=\\SOMESERVER\_myuser$ The drive P is a network drive mapped to HOMESHARE. I can't find where windows is setting those environment variables, not even in the registry. The laptop is running Windows XP.

    Read the article

  • Profile pictures are neither displayed or stored in my Status.Net installation

    - by Ced
    I am running Status.Net 1.0.1 on my webhosting service. When I subscribe to a remote OStatus account, the avatar is neither displayed nor stored in my avatar/ directory. The INSTALLATION file suggests setting the avatar/, background/ and files/ directories to webserver writeable, but this does not help. Has anybody gotten this to work or could anyone point me in the right direction for a solution?

    Read the article

  • How to get the cursor position in bash ?

    - by Julien Nicoulaud
    In a bash script, I want to get the cursor column in a variable. It looks like using the ANSI escape code {ESC}[6n is the only way to get it, for example the following way: # Query the cursor position echo -en '\033[6n' # Read it to a variable read -d R CURCOL # Extract the column from the variable CURCOL="${CURCOL##*;}" # We have the column in the variable echo $CURCOL Unfortunately, this prints characters to the standard output and I want to do it silently. Besides, this is not very portable... Is there a pure-bash way to achieve this ?

    Read the article

  • Renaming and Moving Files in Bash

    - by KT
    HI, I'm completely new to Bash and StackOverflow. I need to move a set of files (all contained in the same folder) to a target folder where files with the same name could already exist. In case a specific file exists, I need to rename the file before moving it, by appending for example an incremental integer to the file name. The extensions should be preserved. The file names could contain dots in the middle. Originally, I was thinking about comparing the two folders to have a list of the existing files (I did this with "comm"), but then I got a bit stuck. I think I'm just trying to do things in the most complicated possible way. Any hint to do this in the "bash way"?

    Read the article

  • Regular expression in BASH

    - by Ryan
    Hello everyone, I was hoping someone could answer my quick question as I am going nuts! I have recently started learning regular expressions in my Java programming however am a little confused how to get certain features to work correctly directly in BASH. For example, the following code is not working as I think it should. echo 2222 | grep '2\{2\}' I am expecting it to return: 22 I have tried variations of it including: echo 2222 | grep '2{2}' echo 2222 | grep -P '2\{2\}' echo 2222 | grep -E '2\{2\}' However I am completely out of ideas. I'm sure this is a simple parameter / syntax fix and would love some help! P.S I've done tons of googling and every reference I find does not work in BASH; regex's can run on so many different platforms and engines =/

    Read the article

  • Inserting text to a file with Sed within Bash Script

    - by neversaint
    I tried to insert a text to the first line of a file using sed. I do this inside a bash script. But why it hangs at the line of sed execution? #! /bin/bash # Command to execute # ./mybashcode.sh test.nbq nbqfile=$1 nbqbase=$(basename $nbqfile nbq) taglistfiletemp="${nbqbase}taglist_temp" taglistfile="${nbqbase}taglist" ./myccode $nbqfile | sort | uniq -c | awk '{print $2}' > $taglistfiletemp noftags=$(wc -l $taglistfiletemp | awk '{print $1}') echo $noftags # We want to append output of noftags # to the first line of taglistfile sed '1i\ $noftags' > $taglistfile # why it hangs here # the content of taglistfile is NIL

    Read the article

  • bash bcmath functions

    - by Gordon
    I have two functions for GNU bc in a Bash script. BC_CEIL="define ceil(x) { if (x>0) { if (x%1>0) return x+(1-(x%1)) else return x } else return -1*floor(-1*x) }\n" BC_FLOOR="define floor(x) { if (x>0) return x-(x%1) else return -1*ceil(-1*x) }\n" echo -e "scale=2"$BC_CEIL$BC_FLOOR"ceil(2.5)" | bc Both functions work fine in interactive bc. bc does not seem to allow multiple functions on one line separated by ; though, so I have to echo -n | bc with newlines at the end of each function. The above output is 2.5, not the expected 3.0 that I get if I type it into bc -i myself. It seems that bash calls bc for each line of echo output, rather than echo'ing it all to a single instance. Is there any workaround for this?

    Read the article

  • bash : recursive listing of all files problem

    - by Michael Mao
    Run a recursive listing of all the files in /var/log and redirect standard output to a file called lsout.txt in your home directory. Complete this question WITHOUT leaving your home directory. An: ls -R /var/log/ /home/bqiu/lsout.txt I reckon the above bash command is not correct. This is what I've got so far: $ ls -1R .: cal.sh cokemachine.sh dir sort test.sh ./dir: afile.txt file subdir ./dir/subdir: $ ls -R | sed s/^.*://g cal.sh cokemachine.sh dir sort test.sh afile.txt file subdir But this still leaves all directory/sub-directory names (dir and subdir), plus a couple of empty newlines How could I get the correct result without using Perl or awk? Preferably using only basic bash commands(this is just because Perl and awk is out of assessment scope)

    Read the article

  • bash script to delete old deployments

    - by benjwarner
    I have a directory where our deployments go. A deployment (which is itself a directory) is named in the format: <application-name>_<date> e.g. trader-gui_20091102 There are multiple applications deployed to this same parent directory, so the contents of the parent directory might look something like this: trader-gui_20091106 trader-gui_20091102 trader-gui_20091010 simulator_20091106 simulator_20091102 simulator_20090910 simulator_20090820 I want to write a bash script to clean out all deployments except for the most current of each application. (The most current denoted by the date in the name of the deployment). So running the bash script on the above parent directory would leave: trader-gui_20091106 simulator_20091106 Any help would be appreciated.

    Read the article

  • using bash: write bit representation of integer to file

    - by theseion
    Hullo First, I want to use bash for this and the script should run on as many systems as possible (I don't know if the target system will have python or whatever installed). Here's the problem: I have a file with binary data and I need to replace a few bytes in a certain position. I've come up with the following to direct bash to the offset and show me that it found the place I want: dd bs=1 if=file iseek=24 conv=block cbs=2 | hexdump Now, to use "file" as the output: echo anInteger | dd bs=1 of=hextest.txt oseek=24 conv=block cbs=2 This seems to work just fine, I can review the changes made in a hex editor. Problem is, "anInteger" will be written as the ASCII representation of that integer (which makes sense) but I need to write the binary representation. How do I tell the command to convert the input to binary (possibly from a hex)?

    Read the article

  • Adding line with text between pattern and next occurence of the same pattern in bash

    - by kasper
    I am writing a bash script that modifies a file that looks like this: --- usr1 --- data data data data data data data data data data data data --- usr2 --- data data data data data data data data --- usr3 --- data data data data --- endline --- One question is: How to add next user line --- usrn --- after last user data lines? Second one is: How to delete specific user data lines (data lines and --- userx ---) i.e. I would like to delete usr2 with all his data set. It must work on bash 2.05 :) and I think it will use awk or sed, but I'm not sure.

    Read the article

  • bash: flushing stdin (standard input)

    - by rahul
    I have a bash script that gets some input as stdin. After processing, I copy a file using "-i" (interactive). However, this never gets executed since (I guess) standard input has not been flushed. To simplify with an example: #!/bin/bash while read line do echo $line done # the next line does not execute read -p "y/n" x echo "got $x" Place this in t.sh, and execute with: ls | ./t.sh The read is not executed. I need to flush stdin before the read. How could it do this?

    Read the article

  • How to do GUI for bash scripts?

    - by maxorq
    I want to do some graphic dialogs for my script but don't know how. I hear something about GTK-Server or something like that. If someone know how to link bash with tcl/tk I also be satisfied. Please do not post something like "change to C++" because my project must be a script in BASH, there are no other option. Any ideas? P.S. Sorry for bad english! EDIT: Thanks for answers but I don't want "graphics" like colors in console, but windows that shows like hmmmm..... net browser which I can move, minimalize etc. I will test xmessage, but I don't think that will be that what I searching for. EDIT2: And one more thing. I don't want make a simple dialog like yes/no, but some interface like progress bars and buttons, something like game :)

    Read the article

  • boolean type for while loop in bash?

    - by user151841
    I have a cron script on a shared web host that occasionally gets killed. I'd like to make a loop in bash that tries again if it gets killed, because most of the time it will make it. I'm having trouble with the syntax for storing a boolean value :P #!/bin/bash VAR=0; while [ $VAR ]; do if nice -19 mysqldump -uuser -ppassword -h database.hostname.com --skip-opt --all --complete-insert --add-drop-table database_name > ~/file/system/path/filename.sql; then VAR=1; fi done So the script recovers from a killed process okay, but once it's run properly, the new VAR value doesn't kill the while loop. What am I doing wrong?

    Read the article

  • Array in Bash Not Found

    - by Waffle
    I am trying to declare an array in bash, but when the code is run it says it cannot find the array. I have tried to write out the declaration of the array in several different ways, but it seems no matter how I try to declare it I cannot get it to work. I originally tried to declare it as such: candidate[1]= 0 candidate[2]= 0 candidate[3]= 0 The error messages that are returned are: votecalculation.sh: 13: candidate[1]=: not found votecalculation.sh: 14: candidate[2]=: not found votecalculation.sh: 15: candidate[3]=: not found After this I tried another solution I found online: ARRAY=( 'can1' 'can2' 'can3' ) When that is used it returns this error: votecalculation.sh: 12: Syntax error: "(" unexpected I am new to Bash and am getting really confused about arrays. Is there some specific way I need to declare an array or am I just going about it completely wrong?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 16 17 18 19 20 21 22 23 24 25 26 27  | Next Page >