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Search found 4967 results on 199 pages for 'bourne shell'.

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  • grep 5 seconds of input from the serial port inside a shell-script

    - by pica
    I've got a device that I'm operating next to my PC and as it runs it's spitting log lines out it's serial port. I have this wired to my PC and I can see the log lines fine if I'm using either minicom or something like: ttylog -b 115200 -d /dev/ttyS0 I want to write 5 seconds of the device serial output to a temp file (or assign it to a variable) and then later grep that file for keywords that will let me know how the device is operating. I've already tried redirecting the output to a file while running the command in the background, and then sleeping 5 seconds and killing the process, but the log lines never get written to my temp file. Example: touch tempFile ttylog -b 115200 -d /dev/ttyS0 >> tempFile & serialPID=$! sleep 5 #kill ${serialPID} #does not work, gets wrong PID killall ttylog cat tempFile The file gets created but never filled with any data. I can also replace the ttylog line with: ttylog -b 115200 -d /dev/ttyS0 |tee -a tempFile & In neither case do I ever see any log lines logged to stdout or the log file unless I have multiple versions of ttylog running by mistake (see commented out line, D'oh). I have no idea what's going on here. It seems to be a failure of redirection within my script. Am I on the right track? Is there a better way to sample 5 seconds of the serial port?

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  • Shell script argument parsing

    - by Peter Coulton
    There are a number of questions about this sort of thing but lets imagine we are targeting a generic Linux system with both getopt and getopts installed (not that we'll use either, but they seem popular) How do I parse both long (--example | --example simple-option) and short argruments (-e | -esimple-example | -e simple-example)

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  • GnuPG Shell Script - Refuses to read password

    - by OopsForgotMyOtherUserName
    The script below used to work on Mac OS X, but, since moving it to Ubuntu, it doesn't seem to read from the password file at all. Even when I run it from the command line, no matter what I do, I get a popup prompt asking me for the password. As this will run via cron, I don't want this to happen... I want it to read the password from the file with no prompt. To note, I did try using passphrase-fd and passphrase-file, neither of which worked... #!/bin/sh p=$(<pass.txt) set -- $p pass_phrase=$1 destination="/var/www/decrypted" cd /var/sl_bin/ for FILE in *.pgp; do FILENAME=${FILE%.pgp} gpg --passphrase "$pass_phrase" --output "$destination/$FILENAME" --decrypt "$FILE" rm -f $FILE done

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  • Difference between piping a file to sh and calling a shell file

    - by Peter Coulton
    This is what was trying to do: $ wget -qO- www.example.com/script.sh | sh which quietly downloads the script and prints it to stdout which is then piped to sh. This unfortunately doesn't quite work, failing to wait for user input a various points, aswell as a few syntax errors. This is what actually works: $ wget -qOscript www.example.com/script.sh && chmod +x ./script && ./script But what's the difference? I'm thinking maybe piping the file doesn't execute the file, but rather executes each line individually, but I'm new to this kind of thing so I don't know.

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  • FTP to SFTP in shell scripting

    - by Kimi
    This script is to connect to different servers and copy a file from a loaction defined. It is mandatory to use sftp and not ftp. #!/usr/bin/ksh -xvf Detail="jyotibo|snv4915|/tlmusr1/tlm/rt/jyotibo/JyotiBo/ jyotibo|snv4915|/tlmusr1/tlm/rt/jyotibo/JyotiBo/" password=Unix11! c_filename=import.log localpath1=`pwd` for i in $Detail do echo $i UserName=`echo $i | cut -d'|' -f1` echo $UserName remotehost=`echo $i | cut -d'|' -f2` echo $remotehost remote_path=`echo $i | cut -d'|' -f3` echo $remote_path { echo "open $remotehost user $UserName $password lcd $localpath1 cd $remote_path bi prompt mget $c_filename prompt " } |ftp -i -n -v 2>&1 done I want to do the similar thing using sftp instead of ftp.

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  • crone tab shell script do not save output

    - by Anas
    i use cron tab with command wget http://www.mydomain.com/page.php to run one of my pages in server. It works, but problem is output is sved with names page.php, page.php1, page.php2, page.php3 etc. Can i run the page using wget without sving output

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  • Selecting Update queries alone from list of files using shell script

    - by Harish
    I am trying to get Update queries from a list of files using this script.I need to take lines containing "Update" alone and not "Updated" or "UpdateSQL"As we know all update queries contain set I am using that as well.But I need to remove cases like Updated and UpdatedSQL can anyone help? nawk -v file="$TEST" 'BEGIN{RS=";"} /[Uu][Pp][Dd][Aa][Tt][Ee] .*[sS][eE][tT]/{ gsub(/.*UPDATE/,"UPDATE");gsub(/.*Update/,"Update");gsub(/.*update/,"update");gsub(/\n+/,"");print file,"#",$0;} ' "$TEST" >> $OUT

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  • Shell - Run additional command on failure

    - by Shawn
    I have this script that I am currently running that works great for all instances but one: #!/bin/sh pdfopt test.pdf test.opt.pdf &>/dev/null pdf2swf test.opt.pdf test.swf [ "$?" -ne 0 ] && exit 2 More lines to execute follow the above code ... How would I go about changing this script to run "pdf2swf test.pdf test.swf" if "pdf2swf test.opt.pdf test.swf" fails? If the second attempt fails, then I would "exit 2". Thanks

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  • storing passed arguments in separate variables -shell scripting

    - by Nathan Pk
    In my script "script.sh" , I want to store 1st and 2nd argument to some variable and rest to another separate variable. What command I must use to implement this task? Number of arguments that is passed to a script is random) When I run the command in console ./script.sh abc def ghi jkl mn o p qrs xxx #It can have any number of arguments In this case, I want my script to store "abc" and "def" in one variable. "ghi jkl mn o p qrs xxx" should be stored in another variable.

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  • Shell script task status monitoring

    - by Bikram Agarwal
    I'm running an ANT task in background and checking in 60 second intervals whether that task is complete or not. If it is not, every 60 seconds, a message should be displayed on screen - "Deploy process is still running. $slept seconds since deploy started", where $slept is 60, 120, 180 n so on. There's a limit of 1200 seconds, after which the script will show the log via 'ant log' command and ask the user whether to continue. If the user chooses to continue, 300 seconds are added to the time limit and the process repeats. The code that I am using for this task is - ant deploy & limit=1200 deploy_check() { while [ ${slept:-0} -le $limit ]; do sleep 60 && slept=`expr ${slept:-0} + 60` if [ $$ = "`ps -o ppid= -p $!`" ]; then echo "Deploy process is still running. $slept seconds since deploy started." else wait $! && echo "Application ${New_App_Name} deployed successfully" || echo "Deployment of ${New_App_Name} failed" break fi done } deploy_check if [ $$ = "`ps -o ppid= -p $!`" ]; then echo "Deploy process did not finish in $slept seconds. Here's the log." ant log echo "Do you want to kill the process? Press Ctrl+C to kill. Press Enter to continue." read log limit=`expr ${limit} + 300` deploy_check fi Now, the problem is - this code is not working. This looks like a perfectly good code and yet, this is not working. Can anyone point out what is wrong with this code, please.

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  • Shell script to name videos on device

    - by Jordan
    I have a .sh script that automounts any usb device that is plugged in. I need it to also find if there are videos in a certain location on the device that is plugged in then write them to a videos.txt file. Here's what I have and its not working. Also I need it to put the mountpoint in the videos.txt file. ${MOUNTPOINT}$count is the path to the mounted device. VIDEOS=ls ${MOUNTPOINT}$count/dcim/100Video | grep mp4 if [ "$VIDEOS" -ne "" ] ; then "${MOUNTPOINT}$count" > ${MOUNTPOINT}$count/videos.txt; "$VIDEOS" >> ${MOUNTPOINT}$count/videos.txt; fi What am I doing wrong?

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  • Linux: shell builtin string matching

    - by gmatt
    I am trying to become more familiar with using the builtin string matching stuff available in shells in linux. I came across this guys posting, and he showed an example a="abc|def" echo ${a#*|} # will yield "def" echo ${a%|*} # will yield "abc" I tried it out and it does what its advertised to do, but I don't understand what the $,{},#,*,| are doing, I tried looking for some reference online or in the manuals but I couldn't find anything. Can anyone explain to me what's going on here?

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  • Running shell scripts with sudo through my web app

    - by nfm
    I have some functionality that interfaces with the server's OS in my web application. I've written a bash script and am able to run it from within my app. However, some functionality of the script requires superuser privileges. What is the most sane way to run this script securely? It is being passed arguments from a web form, but should only be able to be called by authenticated users that I trust not to haxxor it.

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  • An agenda in Korn Shell: New / Edit / Delete / View appointment

    - by Abaco
    As stated in the title, I have to write a simple script which should perform some typical agenda's functions. The script must use crontab. The functions are: Creating a new appointment Edit an existent appointment Delete an appointment List the appointment I really don't have a clue how to do this, can you help me with some hint? Maybe a bit of sweet code? Thank you very much, Abaco EDIT: To be more specific on my question Point 1: how can I edit a crontab thorugh ksh? How can I insert a new line? Can you link me some documentation or a bit of code about this?

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  • How to: Simulating keystroke inputs in shell to an app running in an embedded target

    - by fzkl
    I am writing an automation script that runs on an embedded linux target. A part of the script involves running an app on the target and obtaining some data from the stdout. Stdout here is the ssh terminal connection I have to the target. However, this data is available on the stdout only if certain keys are pressed and the key press has to be done on the keyboard connected to the embedded target and not on the host system from which I have ssh'd into the target. Is there any way to simulate this? Edit: Elaborating on what I need - I have an OpenGL app that I run on the embedded linux (works like regular linux) target. This displays some graphics on the embedded system's display device. Pressing f on the keyboard connected to the target outputs the fps data onto the ssh terminal from which I control the target. Since I am automating the process of running this OpenGL app and obtaining the fps scores, I can't expect a keyboard to be connected to the target let alone expect a user to input a keystroke on the embedded target keyboard. How do I go about this? Thanks.

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  • Substring extraction using bash shell scripting and awk

    - by rohanbk
    So, I have a file called 'dummy' which contains the string: "There is 100% packet loss at node 1". I also have a small script that I want to use to grab the percentage from this file. The script is below. result=`grep 'packet loss' dummy` | awk '{ first=match($0,"[0-9]+%") last=match($0," packet loss") s=substr($0,first,last-first) print s}' echo $result I want the value of $result to basically be 100% in this case. But for some reason, it just prints out a blank string. Can anyone help me?

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  • Telnet SMTP with expect or shell script

    - by Fendrix
    Want to build up a Auth Smtp Connection with expect script... just to test I wanted to get ehlo parameters but expect is not working like this #!/usr/bin/expect set timeout -1 set smtp [lindex $argv 0] set port [lindex $argv 1] spawn telnet $smtp $port expect "[2]{2,}[0]{1,}" send "ehlo" I expect the code 220 to come from mailserver to continue to send ehlo ... just like ..../...:telnet smtp.mail.yahoo.de 25 Trying 77.238.184.85... Connected to smtp2-de.mail.vip.ukl.yahoo.com. Escape character is '^]'. 220 smtp116.mail.ukl.yahoo.com ESMTP ehlo 250-smtp116.mail.ukl.yahoo.com 250-AUTH LOGIN PLAIN XYMCOOKIE 250-PIPELINING 250-SIZE 41697280 250 8BITMIME

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  • shell scripting: nested subshell ++

    - by jhon
    Hi guys, more than a problem, this is a request for "another way to do this" actually, if a want to use the result from a previous command I into another one, I use: R1=$("cat somefile | awk '{ print $1 }'" ) myScript -c $R1 -h123 then, a "better way"is: myScript -c $("cat somefile | awk '{ print $1 }'" ) -h123 but, what if I have to use several times the result, let's say: using several times $R1, well the 2 options: option 1 R1=$("cat somefile | awk '{ print $1}'") myScript -c $R1 -h123 -x$R1 option 2 myScript -c $("cat somefile | awk '{ print $1 }'" ) -h123 -x $("cat somefile | awk '{ print $1 }'" ) do you know another way to "store" the result of a previous command/script and use it as a argument into another command/script? thanks

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  • Korn Shell SegFault

    - by C. Ross
    I have found the following script causes a segmentation fault and core in kshell on AIX. Can anyone explain why I get the following results? Seg Fault doOutput(){ Echo "Something" } doOutput() >&1 OR doOutput(){ Echo "Something" } echo `doOutput()` No Output doOutput(){ Echo "Something" } doOutput() Correct doOutput(){ Echo "Something" } doOutput OR doOutput(){ Echo "Something" } doOutput >&1

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  • Function behaviour on shell(ksh) script

    - by footy
    Here are 2 different versions of a program: this Program: #!/usr/bin/ksh printmsg() { i=1 print "hello function :)"; } i=0; echo I printed `printmsg`; printmsg echo $i Output: # ksh e I printed hello function :) hello function :) 1 and Program: #!/usr/bin/ksh printmsg() { i=1 print "hello function :)"; } i=0; echo I printed `printmsg`; echo $i Output: # ksh e I printed hello function :) 0 The only difference between the above 2 programs is that printmsg is 2times in the above program while printmsg is called once in the below program. My Doubt arises here: To quote Be warned: Functions act almost just like external scripts... except that by default, all variables are SHARED between the same ksh process! If you change a variable name inside a function.... that variable's value will still be changed after you have left the function!! But we can clearly see in the 2nd program's output that the value of i remains unchanged. But we are sure that the function is called as the print statement gets the the output of the function and prints it. So why is the output different in both?

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