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• How to get table cells evenly spaced?

  - by DaveDev

  I'm trying to create a page with a number of static html tables on them. What do I need to do to get them to display each column the same size as each other column in the table? The HTML is as follows: <span class="Emphasis">Interest rates</span><br /> <table cellpadding="0px" cellspacing="0px" class="PerformanceTable"> <tr><th class="TableHeader"></th><th class="TableHeader">Current rate as at 31 March 2010</th><th class="TableHeader">31 December 2009</th><th class="TableHeader">31 March 2009</th></tr> <tr class="TableRow"><td>Index1</td><td class="PerformanceCell">1.00%</td><td>1.00%</td><td>1.50%</td></tr> <tr class="TableRow"><td>index2</td><td class="PerformanceCell">0.50%</td><td>0.50%</td><td>0.50%</td></tr> <tr class="TableRow"><td>index3</td><td class="PerformanceCell">0.25%</td><td>0.25%</td><td>0.25%</td></tr> </table> <span>Source: Bt</span><br /><br /> <span class="Emphasis">Stock markets</span><br /> <table cellpadding="0px" cellspacing="0px" class="PerformanceTable"> <tr><th class="TableHeader"></th><th class="TableHeader">As at 31 March 2010</th><th class="TableHeader">1 month change</th><th class="TableHeader">QTD change</th><th class="TableHeader">12 months change</th></tr> <tr class="TableRow"><td>index1</td><td class="PerformanceCell">1169.43</td><td class="PerformanceCell">5.88%</td><td class="PerformanceCell">4.87%</td><td class="PerformanceCell">46.57%</td></tr> <tr class="TableRow"><td>index2</td><td class="PerformanceCell">1958.34</td><td class="PerformanceCell">7.68%</td><td class="PerformanceCell">5.27%</td><td class="PerformanceCell">58.31%</td></tr> <tr class="TableRow"><td>index3</td><td class="PerformanceCell">5679.64</td><td class="PerformanceCell">6.07%</td><td class="PerformanceCell">4.93%</td><td class="PerformanceCell">44.66%</td></tr> <tr class="TableRow"><td>index4</td><td class="PerformanceCell">2943.92</td><td class="PerformanceCell">8.30%</td><td class="PerformanceCell">-0.98%</td><td class="PerformanceCell">44.52%</td></tr> <tr class="TableRow"><td>index5</td><td class="PerformanceCell">978.81</td><td class="PerformanceCell">9.47%</td><td class="PerformanceCell">7.85%</td><td class="PerformanceCell">26.52%</td></tr> <tr class="TableRow"><td>index6</td><td class="PerformanceCell">3177.77</td><td class="PerformanceCell">10.58%</td><td class="PerformanceCell">6.82%</td><td class="PerformanceCell">44.84%</td></tr> </table> <span>Source: B</span><br /><br /> I'm also open to suggestion on how to tidy this up, if there are any? :-)

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• Why will my AdRotator not display images? (Image paths are correct)

  - by KSwift87

  Hi. I'm writing a simple web application in C# and I've gotten to the part where I must add an AdRotator object and link four images to it. I have done this, but no matter what I do the images will not show up; only the alternate text. It makes no sense because the paths are correct. Supposedly AdRotator controls are really simple to use... But anyway below is my code. Search.aspx: <%@ Page Language="C#" MasterPageFile="~/Site.Master" AutoEventWireup="true" CodeBehind="Search.aspx.cs" Inherits="Module6.WebForm2" Title="Search" %> <asp:Content ID="Content1" ContentPlaceHolderID="head" runat="server"> </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="ContentPlaceHolder1" runat="server"> <form id="Search" runat="server"> This is the Search page! <div class="StartCalendar"> <asp:Calendar ID="Calendar1" runat="server" Caption="Start Date" TodayDayStyle-Font-Bold="true" TodayDayStyle-ForeColor="Crimson" SelectedDayStyle-BackColor="DarkCyan" /> </div> <div class="EndCalendar"> <asp:Calendar ID="Calendar2" runat="server" Caption="End Date" TodayDayStyle-Font-Bold="true" TodayDayStyle-ForeColor="Crimson" SelectedDayStyle-BackColor="DarkCyan" /> </div> <br /><br /> <div class="Search"> <asp:Button ID="btnSearch" runat="server" Text="Search" UseSubmitBehavior="true" /> </div><br /><br /> <div class="CenterAd"> <asp:AdRotator ID="AdRotator1" runat="server" Target="_blank" AdvertisementFile="~/Advertisements.xml" /> </div> <br /><br /> <div class="Results"> <asp:GridView ID="gvResults" runat="server" /> </div> </form> </asp:Content> Advertisements.xml: <?xml version="1.0" encoding="utf-8" ?> <Advertisements> <Ad> <ImageURL>~/images/colts.jpg</ImageURL> <AlternateText>Colts Image</AlternateText> </Ad> <Ad> <ImageURL>~/images/conseco.gif</ImageURL> <AlternateText>Conseco Image</AlternateText> </Ad> <Ad> <ImageURL>~/images/IndianapolisIndians.png</ImageURL> <AlternateText>Indianapolis Indians Image</AlternateText> </Ad> <Ad> <ImageURL>~/images/pacers.gif</ImageURL> <AlternateText>Pacers Image</AlternateText> </Ad> </Advertisements> Any and all help is GREATLY appreciated.

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• why the data can't dispaly in the form???(error-mysql_fetch_array():)

  - by shimaTun

  I've created a code to view the data. Now it seem contain an error. When I run this page this error display: Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource in C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userView.php on line 93 the code : <?php //======================================================================================================================= PROCESS DATA ======================================================= START. include "connectioncomplaint.php"; ?> <?php $subject = $_GET['type']; $comment = $_GET['id']; //echo 'test : ' . $name; //Tarik data dari sini $queryDetail = " SELECT * FROM campuscomplaint " . " WHERE subject = '" . $subject . "' AND comment = '" . $comment . "' "; //echo 'QUERY DETAIL :' . $queryDetail . '<br>' ; $resulDetail = mysql_query($queryDetail); //echo 'RESULT DETAIL :' . $resultDetail + 0 . '<br>' ; $detail = mysql_fetch_array($resultDetail); //echo $detail . '<br>'; //echo 'detail subject is : ' . $detail['subject'] . '<br>'; //echo 'detail comment is : ' . $detail['comment'] . '<br>'; //echo $detail[$x] . '<br>'; ?> code for form: <tr> <td bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5">From:</td> <td bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5"><input type="text" name="to" size="40" maxlength="80" value="<?php echo $detail['userid']; ?>"/></td> </tr> <tr> <td width="38%" bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5">Subject:</td> <td width="62%" bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5"><input type="text" name="subject" size="40" maxlength="80" value="<?php echo $detail['subject']; ?>"/></td> </tr> <tr> <td bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5">Comment:</td> <td bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5"><textarea name="comment" rows="5" cols="40"><?php echo $detail['message']; ?></textarea></td> </tr> <tr> <td bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5"><p>&nbsp;</p> <p>&nbsp;</p></td> <td bordercolor="#FFFFFF" bgcolor="#FFFFFF" class="register style5"><input type="submit" name="submit" value="Submit Comment" onClick="return OnButton1();"/></td> </tr>

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• HTML and PHP simple contact form.

  - by user317128

  I tried to make a simple contact form via HTML and PHP but the form doesnt seem to submit. it stays on the HTML page and doesnt post to the php form. would love someone to look over the code, thanks in advanced. simple_form.html cdoe <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Simple Feedback Form</title> </head> <body> <form action="send_simpleform.php" method="post"> <p>Your name<br /> <input name="sender_name" type="text" size="30" /></p> <p>Email<br /> <input name="sender_email" type="text" size="30" /></p> <p>Message<br /> <textarea name="message" cols="30" rows="5"></textarea></p> <input name="submit" type="button" value="Send This Form" /> </form> </body> </html> send_simpleform.php code <? if (($_POST[sender_name] == "") || ($_POST[sender_email] == "") || ($_POST[message] == "") { header("Location: simple_form.php"); exit; } $msg = "Email sent from wwwsite\n"; $msg .= "Sender's Name:\t $_POST[senders_name]\n"; $msg .= "Sender's E-mail:\t $_POST[senders_email]\n"; $msg .= "Sender's Message:\t $_POST[message]\n"; $to = "[email protected]"; $subject = "Website feedback message"; $mailheaders = "From: My web site <www.testwebsite.com>\n"; $mailherders .= "Reply to: $_POST[sender_email]\n"; $mail($to, $subject, $msg, $mailheaders); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Simple Feedback Form Sent</title> </head> <body> <h1>The following email has been sent</h1> <p>Your Name:<br /> <? echo "$_POST[sender_name]"; ?> <p>Your Email Adress:<br /> <? echo "$_POST[sender_email]"; ?> <p>Message:<br /> <? echo "$_POST[message]"; ?> </p> </body> </html>

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• Animated background image in a hidden <div> doesn't load or loads not animated

  - by Guanche

  Hello, I have spent the whole day trying to make a script which on "submit" hides the form and shows hidden with animated progress bar. The problem is that Internet Explorer doesn't show animated gif images in hidden divs. The images are static. I visited many websites and found a script which uses: document.getElementById(id).style.backgroundImage = 'url(/images/load.gif)'; Finally, my script works in Internet Explorer, Firefox, Opera but... Google Chrome doesn't display the image at all. I see only div text. After many tests I discovered the following: the only way to see the background image in Google Chrome is to include the same image somewhere in the page (outside of hidden div) with 1px dimensions: <img src="/images/load.gif" width="1" heigh="1" /> This did the trick but... after this dirty solution Microsoft Explorer for some reason shows the image as static again. So, my question is: is there any way how to force Gogle Chrome to show the image? Thanks. This is my script: <script language="JavaScript" type="text/javascript"> function ver (id, elementId){ if (document.getElementById('espera').style.visibility == "visible") { return false; }else{ var esplit = document.forms[0]['userfile'].value.split("."); ext = esplit[esplit.length-1]; if (document.forms[0]['userfile'].value == '') { alert('Please select a file'); return false; }else{ if ((ext.toLowerCase() == 'jpg')) { document.getElementById(id).style.position = 'absolute'; document.getElementById(id).style.display = 'inline'; document.getElementById(id).style.visibility = "visible"; document.getElementById(id).style.backgroundImage = 'url(/images/load.gif)'; document.getElementById(id).style.height = "100px"; document.getElementById(id).style.backgroundColor = '#f3f3f3'; document.getElementById(id).style.backgroundRepeat = "no-repeat"; document.getElementById(id).style.backgroundPosition = "50% 50%"; var element; if (document.all) element = document.all[elementId]; else if (document.getElementById) element = document.getElementById(elementId); if (element && element.style) element.style.display = 'none'; return true; }else{ alert('This is not a jpg file'); return false; } } } } </script> <div id="frmDiv"> <form enctype="multipart/form-data" action="/upload.php" method="post" name="upload3" onsubmit="return ver('espera','frmDiv');"> <input type="hidden" name="max_file_size" value="4194304" /> <table border="0" cellspacing="1" cellpadding="2" width="100%"> <tr bgcolor="#f5f5f5"> <td>File (jpg)</td> <td> <input type="file" name="userfile" class="upf" /></td></tr> <tr bgcolor="#f5f5f5"> <td>&nbsp;</td> <td> <input class="upf2" type="submit" name="add" value="Upload" /> </td></tr></table></form> </div> <div id="espera" style="display:none;text-align:center;float:left;width:753px;">&nbsp;<br />&nbsp;<br />&nbsp;<br />&nbsp;<br /> &nbsp;<br />Please wait...<br />&nbsp; </div>

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• HTML / PHP form

  - by user317128

  I am trying to code an all in one HTML/PHP contact from with error checking. When I load this file in my browser there is not HTML. I am a newb php programmer so most likely forgot something pretty obvious. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>All In One Feedback Form</title> </head> <body> <? $form_block = " <input type=\"hidden\" name=\"op\" value=\"ds\"> <form method=\"post\" action=\"$server[PHP_SELF]\"> <p>Your name<br /> <input name=\"sender_name\" type=\"text\" size=30 value=\"$_POST[sender_name]\" /></p> <p>Email<br /> <input name=\"sender_email\" type=\"text\" size=30 value=\"$_POST[sender_email]\"/></p> <p>Message<br /> <textarea name=\"message\" cols=30 rows=5 value=\"$_POST[message]\"></textarea></p> <input name=\"submit\" type=\"submit\" value=\"Send This Form\" /> </form>"; if ($_POST[op] != "ds") { //they see this form echo "$form_block"; } else if ($_POST[op] == "ds") { if ($_POST[sender_name] == "") { $name_err = "Please enter your name<br>"; $send = "no"; } if ($_POST[sender_email] == "ds") { $email_err = "Please enter your email<br>"; $send = "no"; } if ($_POST[message] == "ds") { $message_err = "please enter message<br>"; $send = "no"; } if ($send != "no") { //its ok to send $to = "[email protected]"; $subject = "All in one web site feed back"; $mailheaders = "From: website <some email [email protected]> \n"; $mailheaders .= "Reply-To: $_POST[sender_email]\n"; $msg = "Email sent from this site www.ccccc.com\n"; $msg .= "Senders name: $_POST[senders_name]\n"; $msg .= "Sender's E-Mail: $_POST[sender_email]\n"; $msg .= "Message: $_POST[message]\n\n"; mail($to, $subject, $msg, $mailheaders); echo "<p>Mail has been sent</p>"; } else if ($send == "no") { echo "$name_err"; echo "$email_err"; echo "$message_err"; echo "$form_block"; } } ?> </body> </html> FYI I am trying the example from a book named PHP 6 Fast and Easy Wed Development

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• HTML / PHP from

  - by user317128

  I am trying to code an all in one HTML/PHP contact from with error checking. When I load this file in my browser there is not HTML. I am a newb php programmer so most likely forgot something pretty obvious. <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>All In One Feedback Form</title> </head> <body> <? $form_block = " <input type=\"hidden\" name=\"op\" value=\"ds\"> <form method=\"post\" action=\"$server[PHP_SELF]\"> <p>Your name<br /> <input name=\"sender_name\" type=\"text\" size=30 value=\"$_POST[sender_name]\" /></p> <p>Email<br /> <input name=\"sender_email\" type=\"text\" size=30 value=\"$_POST[sender_email]\"/></p> <p>Message<br /> <textarea name=\"message\" cols=30 rows=5 value=\"$_POST[message]\"></textarea></p> <input name=\"submit\" type=\"submit\" value=\"Send This Form\" /> </form>"; if ($_POST[op] != "ds") { //they see this form echo "$form_block"; } else if ($_POST[op] == "ds") { if ($_POST[sender_name] == "") { $name_err = "Please enter your name<br>"; $send = "no"; } if ($_POST[sender_email] == "ds") { $email_err = "Please enter your email<br>"; $send = "no"; } if ($_POST[message] == "ds") { $message_err = "please enter message<br>"; $send = "no"; } if ($send != "no") { //its ok to send $to = "[email protected]"; $subject = "All in one web site feed back"; $mailheaders = "From: website <some email [email protected]> \n"; $mailheaders .= "Reply-To: $_POST[sender_email]\n"; $msg = "Email sent from this site www.ccccc.com\n"; $msg .= "Senders name: $_POST[senders_name]\n"; $msg .= "Sender's E-Mail: $_POST[sender_email]\n"; $msg .= "Message: $_POST[message]\n\n"; mail($to, $subject, $msg, $mailheaders); echo "<p>Mail has been sent</p>"; } else if ($send == "no") { echo "$name_err"; echo "$email_err"; echo "$message_err"; echo "$form_block"; } } ?> </body> </html> FYI I am trying the example from a book named PHP 6 Fast and Easy Wed Development

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• Bug in CF9: values for unique struct keys referenced and overwritten by other keys.

  - by Gin Doe

  We've run into a serious issue with CF9 wherein values for certain struct keys can be referenced by other keys, despite those other keys never being set. See the following examples: Edit: Looks like it isn't just something our servers ate. This is Adobe bug-track ticket 81884: http://cfbugs.adobe.com/cfbugreport/flexbugui/cfbugtracker/main.html#bugId=81884. <cfset a = { AO = "foo" } /> <cfset b = { AO = "foo", B0 = "bar" } /> <cfoutput> The following should throw an error. Instead both keys refer to the same value. <br />Struct a: <cfdump var="#a#" /> <br />a.AO: #a.AO# <br />a.B0: #a.B0# <hr /> The following should show a struct with 2 distinct keys and values. Instead it contains a single key, "AO", with a value of "bar". <br />Struct b: <cfdump var="#b#" /> This is obviously a complete show-stopper for us. I'd be curious to know if anyone has encountered this or can reproduce this in their environment. For us, it happens 100% of the time on Apache/CF9 running on Linux, both RH4 and RH5. We're using the default JRun install on Java 1.6.0_14. To see the extent of the problem, we ran a quick loop to find other naming sequences that are affected and found hundreds of matches for 2 letter key names. A similar loop found more conflicts in 3 letter names. <cfoutput>Testing a range of affected key combinations. This found hundreds of cases on our platform. Aborting after 50 here.</cfoutput> <cfscript> teststring = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"; stringlen = len(teststring); matchesfound = 0; matches = ""; for (i1 = 1; i1 <= stringlen; i1++) { symbol1 = mid(teststring, i1, 1); for (i2 = 1; i2 <= stringlen; i2++) { teststruct = structnew(); symbol2 = mid(teststring, i2, 1); symbolwhole = symbol1 & symbol2; teststruct[ symbolwhole ] = "a string"; for (q1 = 1; q1 <= stringlen; q1++) { innersymbol1 = mid(teststring, q1, 1); for (q2 = 1; q2 <= stringlen; q2++) { innersymbol2 = mid(teststring, q2, 1); innersymbolwhole = innersymbol1 & innersymbol2; if ((i1 != q1 || i2 != q2) && structkeyexists(teststruct, innersymbolwhole)) { // another affected pair of keys! writeoutput ("<br />#symbolwhole# = #innersymbolwhole#"); if (matchesfound++ > 50) { // we've seen enough abort; } } } } } } </cfscript> And edit again: This doesn't just affect struct keys but names in the variables scope as well. At least the variables scope has the presence of mind to throw an error, "can't load a null": <cfset test_b0 = "foo" /> <cfset test_ao = "bar" /> <cfoutput> test_b0: #test_b0# <br />test_ao: #test_ao# </cfoutput>

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• Oracle Unicode problem when using NLS_CHARACTERSET is WE8ISO8859P1 and NLS_NCHAR_CHARACTERSET is AL16UTF16, and ColdFusion as programming language

  - by tsurahman

  I have 2 Oracle 10g database, XE and Enterprise XE Enterprise and this are the data type I've use in the test table and then I tried to test to insert some Unicode char from http://www.sustainablegis.com/unicode/ and the results are XE Enterprise for this test, I use ColdFusion 9 developer edition <cfprocessingDirective pageencoding="utf-8"> <cfset setEncoding("form","utf-8")> <form action="" method="post"> Unicode : <br> <textarea name="txaUnicode" id="txaUnicode" cols="50" rows="10"></textarea> <br><br> Language : <br> <input type="Text" name="txtLanguage" id="txtLanguage"> <br><br> <input type="Submit"> </form> <cfset dsn = "theDSN"> <cfif StructKeyExists(FORM, "FIELDNAMES")> <cfquery name="qryInsert" datasource="#dsn#"> INSERT INTO UNICODE ( C_VARCHAR2, C_CHAR, C_CLOB, C_NVARCHAR2, LANGUAGE ) VALUES ( <cfqueryparam cfsqltype="CF_SQL_VARCHAR" value="#FORM.TXAUNICODE#">, <cfqueryparam cfsqltype="CF_SQL_CHAR" value="#FORM.TXAUNICODE#">, <cfqueryparam cfsqltype="CF_SQL_LONGVARCHAR" value="#FORM.TXAUNICODE#">, <cfqueryparam cfsqltype="CF_SQL_VARCHAR" value="#FORM.TXAUNICODE#">, <cfqueryparam cfsqltype="CF_SQL_VARCHAR" value="#FORM.TXTLANGUAGE#"> ) </cfquery> </cfif> <cfquery name="qryUnicode" datasource="#dsn#"> SELECT * FROM UNICODE ORDER BY LANGUAGE </cfquery> <table border="1"> <thead> <tr> <th>LANGUAGE</th> <th>C_VARCHAR2</th> <th>C_CHAR</th> <th>C_CLOB</th> <th>C_NVARCHAR2</th> </tr> </thead> <tbody> <cfoutput query="qryUnicode"> <tr> <td>#qryUnicode.LANGUAGE#</td> <td>#qryUnicode.C_VARCHAR2#</td> <td>#qryUnicode.C_CHAR#</td> <td>#qryUnicode.C_CLOB#</td> <td>#qryUnicode.C_NVARCHAR2#</td> </tr> </cfoutput> </tbody> </table> from this guide http://www.stanford.edu/dept/itss/docs/oracle/10g/server.101/b10749/ch6unicode.htm#i1007297 I think for my Enterprise database it should produce same thing as XE (at least for NVARCHAR2 column) since the typical solution from that guide said: Use NCHAR and NVARCHAR2 datatypes to store Unicode characters Keep WE8ISO8859P1 as the database character set Use AL16UTF16 as the national character set So, how to make it works too in my Enterprise database? Thank you :)

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• PHP: Strange Date Problem

  - by Me-and-Coding

  Hi, I have two users in my database whose birth date is set to: 1985-01-26 And then i have function which when provided the users' date, tells how many days are left in the birthday. Here is the function: function retage($iy,$im,$id) { if(!empty($iy)>0 && intval($im)>0 && intval($id)>0) { $tdo=$iy.'-'.$im.'-'.$id; $tdc=date('Y').'-'.$im.'-'.$id; /*echo "<br/>";*/ $cd=date('Y-n-j'); /*echo "<br/>";*/ if(strtotime($tdc)>strtotime($cd))//coming { $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); $td=floor((strtotime($tdc)-strtotime($cd))/(24*3600)); if($td==1) { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' day to go'; } else { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' days to go'; } $ty='<font color="#C7C5C5">is turning '.$ty.' on <br>'.date('M jS Y',strtotime($tdc)).'</font>'; //return 'is turning '.$ty.' on '.$tdc; } elseif(strtotime($tdc)<strtotime($cd))//past { $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); if($ty>0) { //$td='gone '.floor((strtotime($cd)-strtotime($tdc))/(24*3600)).' days ago'; $ndays=floor((strtotime($cd)-strtotime($tdc))/(24*3600)); if($ndays==1) $td=' gone '.round((strtotime($cd)-strtotime($tdc))/(24*3600)).' day ago'; else $td=' gone '.round((strtotime($cd)-strtotime($tdc))/(24*3600)).' days ago'; $ty='<font color="#C7C5C5">had turned '.$ty.' on <br>'.date('M jS Y',strtotime($tdc)).'</font>'; //return 'had turned '.$ty.' on '.$tdc; } else { $tdc=(date('Y')+1).'-'.$im.'-'.$id; $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); //$td=floor((strtotime($tdc)-strtotime($cd))/(24*3600)).' days to go'; $td=floor((strtotime($tdc)-strtotime($cd))/(24*3600)); if($td==1) { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' day to go'; } else { $td=round((strtotime($tdc)-strtotime($cd))/(24*3600)).' days to go'; } $ty='<font color="#C7C5C5">is turning '.$ty.' on <br>'.date('M jS Y',strtotime($tdc)).'</font>'; //return 'is turning '.$ty.' on '.$tdc; } } else//today { $ty=floor((strtotime($tdc)-strtotime($tdo))/(3600*24*365)); if($ty>0) { $td='today'; $ty='<font color="#C7C5C5">has turned <br>'.$ty.' on today </font>'; //return 'has turned '.$ty.' on today'; } else { $ty='<font color="#C7C5C5">today</font>';$td=''; //return ''; } } } else { $ty='';$td=''; //return ''; } $ta[0]=$ty; $ta[1]=$td ; return $ta; } I use below code to show the days remaining: while($rs=mysql_fetch_array($result)) { if (isset($rs['byear'],$rs['bmonth'],$rs['bdate'])) { $tmptxt = retage($rs['byear'],$rs['bmonth'],$rs['bdate']); echo $tmptxt[1]; } } The strange thing is that for one user, the days remaining is shown correctly eg: gone 120 days ago And for other user having same birth date, this is shown: Jan 1st 1970 -14755 days to go Strange: When I use the same function outside of the loop and test with date 1985-01-26, the correct result is shown. Note: You can check out the function for yourself. Could you please tell what could be wrong there, your help will be highly appreciated. Thanks.

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• Javascript: Dynamic Check box (Fieldset with Father/Child Checkboxes)

  - by BoDiE2003

  I have a problem here, when I select any of the 'father' checkboxes all the child checkboxes are getting enabled or disabled. So I need each father checkbox to affect it own child fieldset. Could someone help me with this. Thank you <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html lang="en"> <head> <title>toggle disabled</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8"> <style type="text/css"> .cssDisabled { color: #ccc; } </style> <script src="http://prototypejs.org/assets/2009/8/31/prototype.js" type="text/javascript"> </script> <script type="text/javascript"> Event.observe(window, 'load', function(){ // for all items in the group_first class $$('.father').each(function(chk1){ // watch for clicks chk1.observe('click', function(evt){ dynamicCheckbox(); }); dynamicCheckbox(); }); }); function dynamicCheckbox (){ // count how many of group_first are checked, // doEnable true if any are checked var doEnable = ($$('.father:checked').length > 0) ? true : false; // for each in group_second, enable the checkbox, and // remove the cssDisabled class from the parent label $$('.child').each(function(item){ if (doEnable) { item.enable().up('label').removeClassName('cssDisabled'); } else { item.disable().up('label').addClassName('cssDisabled'); } }); }; </script> </head> <body> <fieldset> <legend>First Group</legend> <label><input type="checkbox" value="1" class="father" />Check box 1</label><br /> <label><input type="checkbox" value="2" class="father" checked/>Check box 2</label> </fieldset> <fieldset> <legend>Second Group</legend> <label class="cssDisabled"><input type="checkbox" value="x" class="child" disabled="disabled" />Check box x</label><br /> <label class="cssDisabled"><input type="checkbox" value="y" class="child" disabled="disabled" />Check box y</label><br /> <label class="cssDisabled"><input type="checkbox" value="z" class="child" disabled="disabled" />Check box z</label> </fieldset> <fieldset> <legend>First Group</legend> <label><input type="checkbox" value="3" class="father" />Check box 1</label><br /> </fieldset> <fieldset> <legend>Second Group</legend> <label class="cssDisabled"><input type="checkbox" value="x" class="child" disabled="disabled" />Check box x</label><br /> <label class="cssDisabled"><input type="checkbox" value="y" class="child" disabled="disabled" />Check box y</label><br /> <label class="cssDisabled"><input type="checkbox" value="z" class="child" disabled="disabled" />Check box z</label> </fieldset> </body> </html>

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• Adding to database with multiple text boxes

  - by kira423

  What I am trying to do with this script is allow users to update a url for their websites, and since each user isn't going to have the same amount of websites is is hard for me to just add $_POST['website'] for each of these. Here is the script <?php include("config.php"); include("header.php"); include("functions.php"); if(!isset($_SESSION['username']) && !isset($_SESSION['password'])){ header("Location: pubs.php"); } $getmember = mysql_query("SELECT * FROM `publishers` WHERE username = '".$_SESSION['username']."'"); $info = mysql_fetch_array($getmember); $getsites = mysql_query("SELECT * FROM `websites` WHERE publisher = '".$info['username']."'"); $postback = $_POST['website']; $webname = $_POST['webid']; if($_POST['submit']){ var_dump( $_POST['website'] ); $update = mysql_query("UPDATE `websites` SET `postback` = '$postback' WHERE name = '$webname'"); } print" <div id='center'> <span id='tools_lander'><a href='export.php'>Export Campaigns</a></span> <div id='calendar_holder'> <h3>Please define a postback for each of your websites below. The following variables should be used when creating your postback.<br /> cid = Campaign ID<br /> sid = Sub ID<br /> rate = Campaign Rate<br /> status = Status of Lead. 1 means payable 2 mean reversed<br /> A sample postback URL would be <br /> http://www.example.com/postback.php?cid=#cid&sid=#sid&rate=#rate&status=#status</h3> <table class='balances' align='center'> <form method='POST' action=''>"; while($website = mysql_fetch_array($getsites)){ print" <tr> <input type ='hidden' name='webid' value='".$website['id']."' /> <td style='font-weight:bold;'>".$website['name']."'s Postback:</td> <td><input type='text' style='width:400px;' name='website[]' value='".$website['postback']."' /></td> </tr>"; } print" <td style='float:right;position:relative;left:150px;'><input type='submit' name='submit' style='font-size:15px;height:30px;width:100px;' value='Submit' /></td> </form> </table> </div>"; include("footer.php"); ?> What I am attempting to do insert the what is inputted in the text boxes to their corresponding websites, and I cannot think of any other way to do it, and this obviously does not works and returns a notice stating Array to string conversion If there is a more logical way to do this please let me know.

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• I can't upload mp3 files using Codeigniter

  - by Drew

  There are lots of suggested fixes for this but none of them work for me. I have tried making the upload class (using the following methods: http://codeigniter.com/forums/viewthread/148605/ and http://codeigniter.com/forums/viewthread/125441/). When i try to upload an mp3 i get the error message "The filetype you are attempting to upload is not allowed". Below is my code for my model and my form (i've got a very skinny controller). If someone could help me out with this I would be eternally grateful. --Model-- function do_upload() { $soundfig['upload_path'] = './uploads/nav'; $soundfig['allowed_types'] = 'mp3'; $this->load->library('upload', $soundfig); if ( ! $this->upload->do_upload()) { $error = array('error' => $this->upload->display_errors()); return $error; } else { /* $data = $this->upload->data('userfile'); */ $sound = $this->upload->data(); /* $full_path = 'uploads/nav/' . $data['file_name']; */ $sound_path = 'uploads/nav/' . $sound['file_name']; if($this->input->post('active') == '1'){ $active = '1'; }else{ $active = '0'; } $spam = array( /* 'image_url' => $full_path, */ 'sound' => $sound_path, 'active' => $active, 'url' => $this->input->post('url') ); $id = $this->input->post('id'); $this->db->where('id', $id); $this->db->update('NavItemData', $spam); return true; } } --View - Form-- <?php echo form_open_multipart('upload/do_upload');?> <?php if(isset($buttons)) : foreach($buttons as $row) : ?> <h2><?php echo $row->name; ?></h2> <!-- <input type="file" name="userfile" size="20" /><br /> --> <input type="file" name="userfile" size="20" /> <input type="hidden" name="oldfile" value="<?php echo $row->image_url; ?>" /> <input type="hidden" name="id" value="<?php echo $row->id; ?>" /> <br /><br /> <label>Url: </label><input type="text" name="url" value="<?php echo $row->url; ?>" /><br /> <input type="checkbox" name="active" value="1" <?php if($row->active == '1') { echo 'checked'; } ?> /><br /><br /> <input type="submit" value="submit" /> </form> <?php endforeach; ?> <?php endif; ?>

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• Unique Alpha numeric generator

  - by AAA

  Hi, I want to give our users in the database a unique alpha-numeric id. I am using the code below, will this always generate a unique id? Below is the updated version of the code: old php: // Generate Guid function NewGuid() { $s = strtoupper(md5(uniqid(rand(),true))); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; New PHP: // Generate Guid function NewGuid() { $s = strtoupper(uniqid("something",true)); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; Will the second (new php) code guarantee 100% uniqueness. Final code: PHP // Generate Guid function NewGuid() { $s = strtoupper(uniqid(rand(),true)); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; $alphabet = '123456789abcdefghijkmnopqrstuvwxyzABCDEFGHJKLMNPQRSTUVWXYZ'; function base_encode($num, $alphabet) { $base_count = strlen($alphabet); $encoded = ''; while ($num >= $base_count) { $div = $num/$base_count; $mod = ($num-($base_count*intval($div))); $encoded = $alphabet[$mod] . $encoded; $num = intval($div); } if ($num) $encoded = $alphabet[$num] . $encoded; return $encoded; } function base_decode($num, $alphabet) { $decoded = 0; $multi = 1; while (strlen($num) > 0) { $digit = $num[strlen($num)-1]; $decoded += $multi * strpos($alphabet, $digit); $multi = $multi * strlen($alphabet); $num = substr($num, 0, -1); } return $decoded; } echo base_encode($Guid, $alphabet); } So for more stronger uniqueness, i am using the $Guid as the key generator. That should be ok right?

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• Problems uploading different file types in codeigniter

  - by Drew

  Below is my script that i'm using to upload different files. All the solutions I've found deal only with multiple image uploads. I am totally stumped for a solution on this. Can someone tell me what it is i'm supposed to be doing to upload different files in the same form? Thanks function do_upload() { $config['upload_path'] = './uploads/nav'; $config['allowed_types'] = 'gif|jpg|png'; $config['max_size'] = '2000'; $this->load->library('upload', $config); if ( ! $this->upload->do_upload('userfile')) { $error = array('error' => $this->upload->display_errors()); return $error; } else { $soundfig['upload_path'] = './uploads/nav'; $soundfig['allowed_types'] = 'mp3|wav'; $this->load->library('upload', $soundfig); if ( ! $this->upload->do_upload('soundfile')) { $error = array('error' => $this->upload->display_errors()); return $error; } else { $data = $this->upload->data('userfile'); $sound = $this->upload->data('soundfile'); $full_path = 'uploads/nav/' . $data['file_name']; $sound_path = 'uploads/nav/' . $sound['file_name']; if($this->input->post('active') == '1'){ $active = '1'; }else{ $active = '0'; } $spam = array( 'image_url' => $full_path, 'sound' => $sound_path, 'active' => $active, 'url' => $this->input->post('url') ); $id = $this->input->post('id'); $this->db->where('id', $id); $this->db->update('NavItemData', $spam); return true; } } } Here is my form: <?php echo form_open_multipart('upload/do_upload');?> <?php if(isset($buttons)) : foreach($buttons as $row) : ?> <h2><?php echo $row->name; ?></h2> <input type="file" name="userfile" size="20" /><br /> <input type="file" name="soundfile" size="20" /> <input type="hidden" name="oldfile" value="<?php echo $row->image_url; ?>" /> <input type="hidden" name="id" value="<?php echo $row->id; ?>" /> <br /><br /> <label>Url: </label><input type="text" name="url" value="<?php echo $row->url; ?>" /><br /> <input type="checkbox" name="active" value="1" <?php if($row->active == '1') { echo 'checked'; } ?> /><br /><br /> <input type="submit" value="submit" /> </form> <?php endforeach; ?> <?php endif; ?>

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• ASP.NET gridview control in side update panel has a problem

  - by Eyla

  Greetings, I have gridview with SelectedIndexChanged event. when I click on a record in gridview it should call the SelectedIndexChanged event and do some operations. SelectedIndexChanged event is working OK, but when I put the gridview inside ajax updatepanle SelectedIndexChanged event will not response even if I add AsyncPostBackTrigger trigger for SelectedIndexChanged event. Please look at my code and advice me what I should do!! Thank you <%@ Page Title="" Language="C#" MasterPageFile="~/Master.Master" AutoEventWireup="true" CodeBehind="WebForm1.aspx.cs" Inherits="IMAM_APPLICATION.WebForm1" %> <%@ Register Assembly="AjaxControlToolkit" Namespace="AjaxControlToolkit" TagPrefix="cc1" %> <asp:Content ID="Content1" ContentPlaceHolderID="ContentPlaceHolder1" runat="server"> <div id="mydiv"> <asp:UpdatePanel ID="UpdatePanel1" runat="server"> <ContentTemplate> <br /> <br /> <br /> <asp:GridView ID="GridView1" runat="server" style="position:absolute; top: 280px; left: 30px; height: 240px; width: 915px;" PageSize="5" onselectedindexchanged="GridView1_SelectedIndexChanged" AutoGenerateColumns="False" DataKeyNames="idcontact_info"> <Columns> <asp:CommandField ShowSelectButton="True" /> <asp:BoundField AccessibleHeaderText="Midle Name" DataField="Midle_Name" /> <asp:BoundField DataField="Last_Name" HeaderText="Last Name" /> <asp:BoundField DataField="Phone_home" HeaderText="Phone Home" /> <asp:BoundField DataField="cell_home" HeaderText="Mobile Home" /> <asp:BoundField DataField="phone_work" HeaderText="Phone Work" /> <asp:BoundField DataField="cell_Work" HeaderText="Mobile Work" /> <asp:BoundField DataField="Email_Home" HeaderText="Personal Home" /> <asp:BoundField DataField="Email_work" HeaderText="Work Email" /> </Columns> </asp:GridView> <br /> <br /> <br /></ContentTemplate> <Triggers> <asp:AsyncPostBackTrigger ControlID="GridView1" EventName="SelectedIndexChanged" /> </Triggers> </asp:UpdatePanel> <asp:RadioButton ID="rdoSearchFlat" runat="server" style="position:absolute; top: 565px; left: 70px;" Text="Flat Search" GroupName="Search"/> <asp:TextBox ID="txtSearch" runat="server" style="position:absolute; top: 560px; left: 170px;" ></asp:TextBox> <asp:Button ID="btnSearch" runat="server" Text="Search" style="position:absolute; top: 555px; left: 375px;" CausesValidation="False" onclick="btnSearch_Click"/> <asp:Label ID="Label7" runat="server" Style="position: absolute; top: 630px; left: 85px;" Text="First Name"></asp:Label> <asp:TextBox ID="txtFirstName" runat="server" Style="top: 630px; left: 185px; position: absolute; height: 22px; width: 128px"> </asp:TextBox> </div> </asp:Content>

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• how can I exit from a php script and continue right after the script?

  - by Samir Ghobril

  Hey guys, I have this piece of code, and when I add return after echo(if there is an error and I need to continue right after the script) I can't see the footer, do you know what the problem is? <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html lang="en" > <head> <title>Login | JM Today </title> <link href="Mainstyles.css" type="text/css" rel="stylesheet" /> </head> <body> <div class="container"> <?php include("header.php"); ?> <?php include("navbar.php"); ?> <?php include("cleanquery.php") ?> <div id="wrap"> <?php ini_set('display_errors', 'On'); error_reporting(E_ALL | E_STRICT); $conn=mysql_connect("localhost", "***", "***") or die(mysql_error()); mysql_select_db('jmtdy', $conn) or die(mysql_error()); if(isset($_POST['sublogin'])){ if(( strlen($_POST['user']) >0) && (strlen($_POST['pass']) >0)) { checklogin($_POST['user'], $_POST['pass']); } elseif((isset($_POST['user']) && empty($_POST['user'])) || (isset($_POST['pass']) && empty($_POST['pass']))){ echo '<p class="statusmsg">You didn\'t fill in the required fields.</p><br/><input type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } } else{ echo '<p class="statusmsg">You came here by mistake, didn\'t you?</p><br/><input type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } function checklogin($username, $password){ $username=mysql_real_escape_string($username); $password=mysql_real_escape_string($password); $result=mysql_query("select * from users where username = '$username'"); if($result != false){ $dbArray=mysql_fetch_array($result); $dbArray['password']=mysql_real_escape_string($dbArray['password']); $dbArray['username']=mysql_real_escape_string($dbArray['username']); if(($dbArray['password'] != $password ) || ($dbArray['username'] != $username)){ echo '<p class="statusmsg">The username or password you entered is incorrect. Please try again.</p><br/><input type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } $_SESSION['username']=$username; $_SESSION['password']=$password; if(isset($_POST['remember'])){ setcookie("jmuser",$_SESSION['username'],time()+60*60*24*356); setcookie("jmpass",$_SESSION['username'],time()+60*60*24*356); } } else{ echo'<p class="statusmsg"> The username or password you entered is incorrect. Please try again.</p><br/>input type="button" value="Retry" onClick="location.href='."'login.php'\">"; return; } } ?> </div> <br/> <br/> <?php include("footer.php") ?> </div> </body> </html>

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• Event handle in drop-down menu.

  - by QLiu

  Hello fellows, I am trying to develop a dynamic drop down menu by a customized widget style The custom widget has two main features: Read user's location cookies variable to set the proper contact phone number in the CP pages When users select on the drop down menu, it triggers onChange event, it re-select the contact phone number based on users' selections, but it won't reset the location cookies. My widgets conatins two files: Controller.php: Simply one, it uses to handle get cookies variables class serial extends Widget { function __construct() { parent::__construct(); } function generateWidgetInformation() { $this->info['notes'] = "Serial Number search Box"; } function getData() { //Get cookies code will go here, and pass to view.php $this->data['locale'] = 'gb';// for test purpose now } } view.php is about Presentation layer contains HTML, which get the data from my controller <div style="border: 1px solid black; display: block;" id="<?=$this->instanceID;?>"></div> <script>locale2contact('<?=$this->data['locale']?>', '<?=$this->instanceID;?>');</script> And then the Javascript function, call locale2contact var element_id =''; //Define Global Variables, //Receive the cookies locale, and instance id from view.php function locale2contact(locale, instance_id) { var details = ''; this.element_id=instance_id; //assing the instance id into global variable // alert(instance_id); //Check whether we got the instance id from view files if (locale == 'gb') details = 'UK Contact Details<br>' + build_dropdown(locale); else if (locale == 'fr') details = 'French Contact Details<br>'+build_dropdown(locale); else if (locale == 'be') details = 'Belgian Contact Details<br>'+ build_dropdown(locale); else details = 'Unknown Contact Detail'; writeContactInfo(details); } //Build the drop down menu with pre-selected option by using cookies. function build_dropdown(locale) { var dropdown = '<select onChange=changeContactInfo(this.options[selectedIndex].text)>'; dropdown += '<option' + (locale == 'gb' ? ' selected' : '') + '>UK</option>'; dropdown += '<option' + (locale == 'be' ? ' selected' : '') + '>Belgium</option>'; dropdown += '</select>'; return dropdown; } // Not smart way in here, once the people select the drop down box, it reselect the drop down menu and reset the contact info function changeContactInfo(selected) { var details =''; //alert(this.element_id); //alert(locale); if (selected == 'UK') details = 'UK Contact Details<br>' + build_dropdown2(selected); else if (selected == 'fr') details = 'French Contact Details<br>'+ build_dropdown2(selected); else if (selected == 'Belgium') details = 'Belgian Contact Details<br>'+ build_dropdown2(selected); else details = 'Unknown Contact Detail'; writeContactInfo(details); } //Build the drop down menu function build_dropdown2(selected) { var dropdown = '<select onChange=changeContactInfo(this.options[selectedIndex].text)>'; dropdown += '<option' + (selected == 'UK' ? ' selected' : '') + '>UK</option>'; dropdown += '<option' + (selected == 'Belgium' ? ' selected' : '') + '>Belgium</option>'; dropdown += '</select>'; return dropdown; } //Back to view function writeContactInfo(details) { document.getElementById(this.element_id).innerHTML = details; //update the instance field in view } Javascript function is not efficient. As you see, I got two similar duplicate functions to handle events. Users go to the page, the widget read the cookies variable to display contact info (locale2contact)and preselect the drop-down menu (function build_dropdown) If users select the drop down menu, the displya contact info change (function changeContactInfo), and then I need to rebuild the drop down menu with user previously selection (function build_dropdown2). I am looking for best practices for adding this functionality to RightNow widget. Thank you. I really do not like the way i am doing now. It works; but the code looks bad.

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• Calling Object Methods in Code

  - by Mister R2

  I'm a bit new to PHP, and I'm more experienced with strongly-typed languages such as JAVA, C# or C++.I'm currently writing a web tool in PHP, and I am having an issue trying to do what I want. The simple idea of what I want to do in code is run through some emails I used PHP-IMAP to get. I then create email objects (a class I defined), and put them in an array. Later on the code, however, I cycle through those emails to display them. However, as you might have guessed I'd have an issue with, I try to use an Email Class object method in that later loop -- and I'm pretty sure PHP doesn't know that the variables in the array happen to be Email Class objects! I wrote a toString method, and I want to call it in the loop. While I don't need to do this for the final version of this tool, I would like to find out what I'm missing. This is the class and the loop where I'm calling the method: include 'imap_email_interface.php'; class ImapEmail implements imap_email_interface { // Email data var $msgno; var $to; var $from; var $subject; var $body; var $attachment; // Email behavior /* PHP 4 ~ legacy constructor */ public function ImapEmail($message_number) { $this->__construct(); $this->msgno = $message_number; } /* PHP 5 Constructor */ public function __construct($message_number) { $this->msgno = $message_number; } public function send($send_to) { // Not Yet Needed! Seriously! } public function setHeaderDirectly($TO, $FROM, $SUBJECT) { $this->to = $TO; $this->from = $FROM; $this->subject = $SUBJECT; } public function setHeaderIndirectly($HEADER) { if (isset($HEADER->to[0]->personal)) $this->to = '"'.$HEADER->to[0]->personal.'", '.$HEADER->to[0]->mailbox.'@'.$HEADER->to[0]->host; else $this->to = $HEADER->to[0]->mailbox.'@'.$HEADER->to[0]->host; $this->from = '"'.$HEADER->from[0]->personal.'", '.$HEADER->from[0]->mailbox.'@'.$HEADER->from[0]->host; $this->subject = $HEADER->subject; } public function setBody($BODY) { $this->body = $BODY; } public function setAttachment($ATTCH) { $this->attachment = $ATTCH; } public function toString() { $str = '[TO]: ' . $this->to . '<br />' . '[FROM]: ' . $this->from . '<br />' . '[SUBJECT]: ' . $this->subject . '<br />'; $str .= '[Attachment]: '.$this->attachment.'<br />'; return $str; } } ?> The Loop: foreach ($orderFileEmails as $x) { $x->toString(); echo '<br /><br />'; } Any ideas?

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• PHP - Code Sample - Polymorphism Implementation - How to allow for expansion?

  - by darga33

  I've read numerous SO posts about Polymorphism, and also the other really good one at http://net.tutsplus.com/tutorials/php/understanding-and-applying-polymorphism-in-php/ Good stuff!!! I'm trying to figure out how a seasoned PHP developer that follows all the best practices would accomplish the following. Please be as specific and detailed as possible. I'm sure your answer is going to help a lot of people!!! :-) While learning Polymorphism, I came across a little stumbling block. Inside of the PDFFormatter class, I had to use (instanceof) in order to figure out if some code should be included in the returned data. I am trying to be able to pass in two different kinds of profiles to the formatter. (needs to be able to handle multiple kinds of formatters but display the data specific to the Profile class that is being passed to it). It doesn't look bad now, but imagine 10 more kinds of Profiles!! How would you do this? The best answer would also include the changes you would make. Thanks sooooooo much in advance!!!!! Please PHP only! Thx!!! File 1. FormatterInterface.php interface FormatterInterface { public function format(Profile $Profile); } File 2. PDFFormatter.php class PDFFormatter implements FormatterInterface { public function format(Profile $Profile) { $format = "PDF Format<br /><br />"; $format .= "This is a profile formatted as a PDF.<br />"; $format .= 'Name: ' . $Profile->name . '<br />'; if ($Profile instanceof StudentProfile) { $format .= "Graduation Date: " . $Profile->graduationDate . "<br />"; } $format .= "<br />End of PDF file"; return $format; } } File 3. Profile.php class Profile { public $name; public function __construct($name) { $this->name = $name; } public function format(FormatterInterface $Formatter) { return $Formatter->format($this); } } File 4. StudentProfile.php class StudentProfile extends Profile { public $graduationDate; public function __construct($name, $graduationDate) { $this->name = $name; $this->graduationDate = $graduationDate; } } File 5. index.php //Assuming all files are included...... $StudentProfile = new StudentProfile('Michael Conner', 55, 'Unknown, FL', 'Graduate', '1975', 'Business Management'); $Profile = new Profile('Brandy Smith', 44, 'Houston, TX'); $PDFFormatter = new PDFFormatter(); echo '<hr />'; echo $StudentProfile->format($PDFFormatter); echo '<hr />'; echo $Profile->format($PDFFormatter);

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• Moving from MySQL to MySQLi? I have the code here but I don't get it

  - by MuqMan

  I have posted the code there, please help me out as I am a newbie, I don't know much in terms of deprecation and stuff. <?php session_start(); include('settings.php'); $issub = $_POST['issub']; if($issub == "yes") { require('settings.php'); $dbcon = mysql_connect($dbhost, $dbuser, $dbpword); if(!dbcon) { die('Could not connect'.mysql_error()); } $selectdb = mysql_select_db($db, $dbcon); $formset = 'yes'; $val = 0; $user = trim($_POST['username'], ' '); $luser = mysql_real_escape_string($user); $password = $_POST['password']; $lpassword = mysql_real_escape_string($password); $selectdb; $userq = mysql_query("SELECT user FROM users WHERE user='".$luser."'"); $userresult = @mysql_result($userq, 0); //echo $userresult; if($userresult == $user) { $val = $val + 1; $usercorrect = 'yes'; } else { $usercorrect = 'no'; } $dbselect; $passwordq = mysql_query("SELECT password FROM users where user='".$luser."'"); $passresult = @mysql_result($passwordq, 0); if($passresult == sha1($password)) { $val = $val + 1; $passcorrect = 'yes'; } else { $passcorrect = 'no'; } if ($val == 2) { $_SESSION['loggedin'] = 'yes'; $_SESSION['uloggedin'] = $user; header('location: logged.php'); } }?> <?php ini_set('display_errors', 1); require('testinclude.php'); ?> <body> <div id="loginform"> <form action="/login.php" method="post" > <input type="hidden" name="issub" value="yes" /> <?php if($usercorrect == 'no') { echo '<span class="required"><i><small>The email address or password you entered is incorrect, please try again.</a></small></i></span>'; } ?> <br /> email: <?php if ($issub == 'yes') { if($user == null){ echo '<br /><span class="required"><i><small>Please enter your email address</a></small></i></span>'; } } ?> <br /><input type="text" name="username" id="usename" /> <br /> password: <br /><input type="password" name="password" id="password" /> <br /> <input type="submit" value="login" /> </form> <div> </body>

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• May 2011 Release of the Ajax Control Toolkit

  - by Stephen Walther

  I’m happy to announce that the Superexpert team has published the May 2011 release of the Ajax Control Toolkit at CodePlex. You can download the new release at the following URL: http://ajaxcontroltoolkit.codeplex.com/releases/view/65800 This release focused on improving the ModalPopup and AsyncFileUpload controls. Our team closed a total of 34 bugs related to the ModalPopup and AsyncFileUpload controls. Enhanced ModalPopup Control You can take advantage of the Ajax Control Toolkit ModalPopup control to easily create popup dialogs in your ASP.NET Web Forms applications. When the dialog appears, you cannot interact with any page content which appears behind the modal dialog. For example, the following page contains a standard ASP.NET Button and Panel. When you click the Button, the Panel appears as a popup dialog: <%@ Page Language="vb" AutoEventWireup="false" CodeBehind="Simple.aspx.vb" Inherits="ACTSamples.Simple" %> <%@ Register TagPrefix="act" Namespace="AjaxControlToolkit" Assembly="AjaxControlToolkit" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title>Simple Modal Popup Sample</title> <style type="text/css"> html { background-color: blue; } #dialog { border: 2px solid black; width: 500px; background-color: White; } #dialogContents { padding: 10px; } .modalBackground { background-color:Gray; filter:alpha(opacity=70); opacity:0.7; } </style> </head> <body> <form id="form1" runat="server"> <div> <act:ToolkitScriptManager ID="tsm" runat="server" /> <asp:Panel ID="dialog" runat="server"> <div id="dialogContents"> Here are the contents of the dialog. <br /> <asp:Button ID="btnOK" Text="OK" runat="server" /> </div> </asp:Panel> <asp:Button ID="btnShow" Text="Open Dialog" runat="server" /> <act:ModalPopupExtender TargetControlID="btnShow" PopupControlID="dialog" OkControlID="btnOK" DropShadow="true" BackgroundCssClass="modalBackground" runat="server" /> </div> </form> </body> </html>     Notice that the page includes two controls from the Ajax Control Toolkit: the ToolkitScriptManager and the ModalPopupExtender control. Any page which uses any of the controls from the Ajax Control Toolkit must include a ToolkitScriptManager. The ModalPopupExtender is used to create the popup. The following properties are set: · TargetControlID – This is the ID of the Button or LinkButton control which causes the modal popup to be displayed. · PopupControlID – This is the ID of the Panel control which contains the content displayed in the modal popup. · OKControlID – This is the ID of a Button or LinkButton which causes the modal popup to close. · DropShadow – Displays a drop shadow behind the modal popup. · BackgroundCSSClass – The name of a Cascading Style Sheet class which is used to gray out the background of the page when the modal popup is displayed. The ModalPopup is completely cross-browser compatible. For example, the following screenshots show the same page displayed in Firefox 4, Internet Explorer 9, and Chrome 11: The ModalPopup control has lots of nice properties. For example, you can make the ModalPopup draggable. You also can programmatically hide and show a modal popup from either server-side or client-side code. To learn more about the properties of the ModalPopup control, see the following website: http://www.asp.net/ajax/ajaxcontroltoolkit/Samples/ModalPopup/ModalPopup.aspx Animated ModalPopup Control In the May 2011 release of the Ajax Control Toolkit, we enhanced the Modal Popup control so that it supports animations. We made this modification in response to a feature request posted at CodePlex which got 65 votes (plenty of people wanted this feature): http://ajaxcontroltoolkit.codeplex.com/workitem/6944 I want to thank Dani Kenan for posting a patch to this issue which we used as the basis for adding animation support for the modal popup. Thanks Dani! The enhanced ModalPopup in the May 2011 release of the Ajax Control Toolkit supports the following animations: OnShowing – Called before the modal popup is shown. OnShown – Called after the modal popup is shown. OnHiding – Called before the modal popup is hidden. OnHidden – Called after the modal popup is hidden. You can use these animations, for example, to fade-in a modal popup when it is displayed and fade-out the popup when it is hidden. Here’s the code: <act:ModalPopupExtender ID="ModalPopupExtender1" TargetControlID="btnShow" PopupControlID="dialog" OkControlID="btnOK" DropShadow="true" BackgroundCssClass="modalBackground" runat="server"> <Animations> <OnShown> <Fadein /> </OnShown> <OnHiding> <Fadeout /> </OnHiding> </Animations> </act:ModalPopupExtender>     So that you can experience the full joy of this animated modal popup, I recorded the following video: Of course, you can use any of the animations supported by the Ajax Control Toolkit with the modal popup. The animation reference is located here: http://www.asp.net/ajax/ajaxcontroltoolkit/Samples/Walkthrough/AnimationReference.aspx Fixes to the AsyncFileUpload In the May 2011 release, we also focused our energies on performing bug fixes for the AsyncFileUpload control. We fixed several major issues with the AsyncFileUpload including: It did not work in master pages It did not work when ClientIDMode=”Static” It did not work with Firefox 4 It did not work when multiple AsyncFileUploads were included in the same page It generated markup which was not HTML5 compatible The AsyncFileUpload control is a super useful control. It enables you to upload files in a form without performing a postback. Here’s some sample code which demonstrates how you can use the AsyncFileUpload: <%@ Page Language="vb" AutoEventWireup="false" CodeBehind="Simple.aspx.vb" Inherits="ACTSamples.Simple1" %> <%@ Register TagPrefix="act" Namespace="AjaxControlToolkit" Assembly="AjaxControlToolkit" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head id="Head1" runat="server"> <title>Simple AsyncFileUpload</title> </head> <body> <form id="form1" runat="server"> <div> <act:ToolkitScriptManager ID="tsm" runat="server" /> User Name: <br /> <asp:TextBox ID="txtUserName" runat="server" /> <asp:RequiredFieldValidator EnableClientScript="false" ErrorMessage="Required" ControlToValidate="txtUserName" runat="server" /> <br /><br /> Avatar: <act:AsyncFileUpload ID="async1" ThrobberID="throbber" UploadingBackColor="yellow" ErrorBackColor="red" CompleteBackColor="green" UploaderStyle="Modern" PersistFile="true" runat="server" /> <asp:Image ID="throbber" ImageUrl="uploading.gif" style="display:none" runat="server" /> <br /><br /> <asp:Button ID="btnSubmit" Text="Submit" runat="server" /> </div> </form> </body> </html> And here’s the code-behind for the page above: Public Class Simple1 Inherits System.Web.UI.Page Private Sub btnSubmit_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles btnSubmit.Click If Page.IsValid Then ' Get Form Fields Dim userName As String Dim file As Byte() userName = txtUserName.Text If async1.HasFile Then file = async1.FileBytes End If ' Save userName, file to database ' Redirect to success page Response.Redirect("SimpleDone.aspx") End If End Sub End Class   The form above contains an AsyncFileUpload which has values for the following properties: ThrobberID – The ID of an element in the page to display while a file is being uploaded. UploadingBackColor – The color to display in the upload field while a file is being uploaded. ErrorBackColor – The color to display in the upload field when there is an error uploading a file. CompleteBackColor – The color to display in the upload field when the upload is complete. UploaderStyle – The user interface style: Traditional or Modern. PersistFile – When true, the uploaded file is persisted in Session state. The last property PersistFile, causes the uploaded file to be stored in Session state. That way, if completing a form requires multiple postbacks, then the user needs to upload the file only once. For example, if there is a server validation error, then the user is not required to re-upload the file after fixing the validation issue. In the sample code above, this condition is simulated by disabling client-side validation for the RequiredFieldValidator control. The RequiredFieldValidator EnableClientScript property has the value false. The following video demonstrates how the AsyncFileUpload control works: You can learn more about the properties and methods of the AsyncFileUpload control by visiting the following page: http://www.asp.net/ajax/ajaxcontroltoolkit/Samples/AsyncFileUpload/AsyncFileUpload.aspx Conclusion In the May 2011 release of the Ajax Control Toolkit, we addressed over 30 bugs related to the ModalPopup and AsyncFileUpload controls. Furthermore, by building on code submitted by the community, we enhanced the ModalPopup control so that it supports animation (Thanks Dani). In our next sprint for the June release of the Ajax Control Toolkit, we plan to focus on the HTML Editor control. Subscribe to this blog to keep updated.

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• HTML Parsing for multiple input files using java code [closed]

  - by mkp

  FileReader f0 = new FileReader("123.html"); StringBuilder sb = new StringBuilder(); BufferedReader br = new BufferedReader(f0); while((temp1=br.readLine())!=null) { sb.append(temp1); } String para = sb.toString().replaceAll("<br>","\n"); String textonly = Jsoup.parse(para).text(); System.out.println(textonly); FileWriter f1=new FileWriter("123.txt"); char buf1[] = new char[textonly.length()]; textonly.getChars(0,textonly.length(),buf1,0); for(i=0;i<buf1.length;i++) { if(buf1[i]=='\n') f1.write("\r\n"); f1.write(buf1[i]); } I've this code but it is taking only one file at a time. I want to select multiple files. I've 2000 files and I've given them numbering name from 1 to 2000 as "1.html". So I want to give for loop like for(i=1;i<=2000;i++) and after executing separate txt file should be generated.

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• Loose typing not applied to objects

  - by TecBrat

  I have very little experience working with classes and object. I work in a loosely typed language, PHP. I was working with a SimpleXML object and ran into a problem where I was trying to do math with an element of that object like $results->ProductDetail->{'Net'.$i}; If I echoed that value, I'd get 0.53 but when I tried to do math with it, it was converted to 0 Is there a reason that a loosely typed language would not recognize that as a float and handle it as such? Why would "echo" handle it as a string but the math fail to convert it? Example: $xml='<?xml version="1.0" encoding="UTF-8" ?>'; $xml.='<Test> <Item> <Price>0.53</Price> </Item> </Test>'; $result=simplexml_load_string($xml); var_dump($result->Item->Price); echo '<br>'; echo $result->Item->Price; echo '<br>'; echo 1+$result->Item->Price; echo '<br>'; echo 1+(float)$result->Item->Price; Output: object(SimpleXMLElement)#4 (1) { [0]=> string(4) "0.53" } 0.53 1 1.53

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• What are the common techniques to handle user-generated HTML modified differently by different browsers?

  - by Jakie

  I am developing a website updater. The front end uses HTML, CSS and JavaScript, and the backend uses Python. The way it works is that <p/>, <b/> and some other HTML elements can be updated by the user. To enable this, I load the webpage and, with JQuery, convert all those elements to <textarea/> elements. Once they the content of the text area is changed, I apply the change to the original elements and send it to a Python script to store the new content. The problem is that I'm finding that different browsers change the original HTML. How do you get around this issue? What Python libraries do you use? What techniques or application designs do you use to avoid or overcome this issue? The problems I found are: IE removes the quotes around class and id attributes. For example, <img class='abc'/> becomes <img class=abc/>. Firefox removes the backslash from the line breaks: <br \> becomes <br>. Some websites have very specific display technicalities, so an insertion of a simple "\n"(which IE does) can affect the display of a website. Example: changing <img class='headingpic' /><div id="maincontent"> to <img class='headingpic'/>\n <div id="maincontent"> inserts a vertical gap in IE. The things I have unsuccessfully tried to overcome these issues: Using either JQuery or Python to remove all >\n< occurences, <br> etc. But this fails because I get different patterns in IE, sometimes a ·\n, sometimes a \n···. In a Python, parse the new HTML, extract the new text/content, insert it into the old HTML so the elements and format never change, just the content. This is very difficult and seems to be overkill.

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