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• Can't use command line – "command not found" after editing PATH

  - by MEM

  I'm running OS X Mavericks and was trying to install MAMP PRO 2.2. I was trying to configure the PATH variable to have the PHP binaries of MAMP PRO. I added the following line on my ~/.bash_profile file: export PATH=/Applications/MAMP PRO/bin/php/php5.5.3/bin:$PATH As you may notice, since I have MAMP PRO and not just MAMP, I've added a space. As a consequence, I know have the following error each time I run the terminal: -bash: export: `PRO/bin/php/php5.5.3/bin:/usr/bin:/bin:/usr/sbin:/sbin:/usr/local/bin': not a valid identifier Worst: I can't get any command to run, like: ls, clear etc. I always get: "command not found" I don't even know the absolute path for ls. How can I make the commands work again, so that I can properly fix the path I was trying to setup on the .bash_profile file?

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• Rollback driver in Windows via command line

  - by ultrasawblade

  I have a remote system in which I've updated the Nvidia graphics driver, but now RDPDD.dll, which I'm guessing stands for RDP Display Driver, will not load (found this out via Event Viewer). I can use Sysinternal's Psexec to execute commands though. I'm sure something has gone very wrong and the user of this system (a CAD engineer) won't be able to use his system normally. I've tried two remote reboots and that has not resolved the issue. So I would like to use the "Roll Back" option for the Nvidia driver in the device manager. Is there a command-line way of doing this?

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• Ubuntu from console/command-line/shell

  - by Xolve

  Earlies linux distros though required lot of manual work they were quite good to use from commandline. If the X-server didn't start or you just want a shell to work they all supported. Network was configured by init; sound was up and ready; new devices inserted would be configured and their configureation was placed in fstab. Also there were small scripts I found on many distros which on X used windows while on console they switched to ncurses. But now this all needs GUI with a desktop manager (KDE, GNOME) for the new paradigms :'-( require GUI (NetworkManger, hal etc.). So if on just command line you have to be root, looks like they believe only geeky admins need that, and need to edit config files or type big commands. Any way so that this is easy in Ubnubtu through shell again.

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• Resize windows command line prompt?

  - by Yuval

  Hi, I'm working on a Windows xp machine. I wrote a program in assembly that outputs some text, and am trying to create a screenshot of the command line output (start-run-"cmd"). The problem is that the text initially printed by the program gets pushed up by later text and I cannot scroll to it. I tried playing around with the width and height under properties = layout but it seems to resize the window itself (the borders) without resizing the textarea inside the window (text does not have more "room", but the window is bigger). Does anybody know a workaround/solution for this? Thank you!

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• Refreshing Windows Media library by command line

  - by dangowans

  Many file download managers allow you to run a command after your download finishes. Is there a command line to run a Windows Media Player 12 library refresh? Videos don't show up in the available list on my PS3 until the library is refreshed. Right now, I manually open Windows Media Player after the downloads finish, watch the bottom-right corner for the refresh to complete (ie. Update Complete), then close the player. This works, but there has to be a better way. Yes, I know PS3 Media Server would do the trick, and I do use it when I need to transcode something, but WMP is running all the time, so I'd like to take advantage of it.

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• Learn Linux Command Line for Web Server Management [closed]

  - by Jonathan

  I've searched high and low for a good resource for learning the Linux command line. I've found a handful of separate resources, but none that really can assist in web server management. I'm currently learning through trial an error with 'man' pages, along with Google. I was just wondering if anyone had a solid resource that they used to learn, and would be willing to share it with me. Thanks so much for your time, I really appreciate it! EDIT: I have a few CentOS servers at current, and I know the basics, I'm just trying to get to a more advanced level.

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• Is there a fully-functional dropdown replacement for HTML SELECT that works in IE?

  - by Ken Paul

  We determined in a previous question that many features of HTML SELECTs are not supported in IE. Is there an alternative widget that you would recommend from your experience that meets the following requirements? Respects the contentEditable property (does not allow selection changes if true) Respects the disabled property of individual OPTIONs (shows them "grayed out" or with strike-through font, and makes them un-selectable) Supports Option Groups (OPTGROUP elements) Supports style options such as border and margin in the SELECT and all sub-elements Supports dynamic add and delete of OPTION and OPTGROUP elements Supports the above in IE version 6 and above EDIT: As noted by @Joel Coehoorn, items 3 and 5 above are currently supported in IE. They are included here to make sure they are not overlooked in a replacement widget.

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• Decode html tag so that it can be read when it goes back to the server more specifically the controller

  - by Yusuf

  My engine is Aspx. How can I decode/encode the html tags that is in my text box. I have the html tag to make it more readable. I tried the ValidationRequest and the htmlDecode(freqQuestion.Answer) but no luck. I just keep getting the same message. Server Error in '/Administrator' Application. A potentially dangerous Request.Form value was detected from the client (QuestionAnswer="...ics Phone:123-456-7890 Description: Request Validation has detected a potentially dangerous client input value, and processing of the request has been aborted. This value may indicate an attempt to compromise the security of your application, such as a cross-site scripting attack. To allow pages to override application request validation settings, set the requestValidationMode attribute in the httpRuntime configuration section to requestValidationMode="2.0". Example: . After setting this value, you can then disable request validation by setting validateRequest="false" in the Page directive or in the configuration section. However, it is strongly recommended that your application explicitly check all inputs in this case. For more information, see http://go.microsoft.com/fwlink/?LinkId=153133. View Page <%@ Page Title="" Language="C#" MasterPageFile="~/Views/Shared/Site.Master" validateRequest="false" Inherits="System.Web.Mvc.ViewPage<dynamic>" %> <asp:Content ID="Content1" ContentPlaceHolderID="TitleContent" runat="server"> EditFreqQuestionsUser </asp:Content> <asp:Content ID="Content2" ContentPlaceHolderID="MainContent" runat="server"> <script type="text/javascript"> $(document).ready(function () { $("#freqQuestionsUserUpdateButton").click(function () { $("#updateFreqQuestionsUser").submit(); }); }); </script> <h2>Edit Freq Questions User </h2> <%Administrator.DarkstarAdminProductionServices.FreqQuestionsUser freqQuestionsUser = ViewBag.freqQuestionsUser != null ? ViewBag.freqQuestionsUser : new Administrator.DarkstarAdminProductionServices.FreqQuestionsUser(); %> <%List<string> UserRoleList = Session["UserRoles"] != null ? (List<string>)Session["UserRoles"] : new List<string>(); %> <form id="updateFreqQuestionsUser" action="<%=Url.Action("SaveFreqQuestionsUser","Prod")%>" method="post"> <table> <tr> <td colspan="3" class="tableHeader">Freq Questions User Details <input type ="hidden" value="<%=freqQuestionsUser.freqQuestionsUserId%>" name="freqQuestionsUserId"/> </td> </tr> <tr> <td colspan="2" class="label">Question Description:</td> <td class="content"> <input type="text" maxlength="2000" name="QuestionDescription" value="<%=freqQuestionsUser.questionDescription%>" /> </td> </tr> <tr> <td colspan="2" class="label">QuestionAnswer:</td> <td class="content"> <input type="text" maxlength="2000" name="QuestionAnswer" value="<%=Server.HtmlDecode(freqQuestionsUser.questionAnswer)%>" /> </td> </tr> <tr> <td colspan="3" class="tableFooter"> <br /> <a id="freqQuestionsUserUpdateButton" href="#" class="regularButton">Save</a> <a href="javascript:history.back()" class="regularButton">Cancel</a> </td> </tr> </table> </form> </asp:Content> Controller [AuthorizeAttribute(AdminRoles = "EditFreqQuestionsUser")] public ActionResult SaveFreqQuestionsUser(string QuestionDescription, string QuestionAnswer) { Guid freqQuestionsUserId = Request.Form["freqQuestionsUserId"] != null ? new Guid(Request.Form["freqQuestionsUserId"]) : Guid.Empty; //load agreement eula ref AdminProductionServices.FreqQuestionsUser freqqQuestionsUser = Administrator.Models.AdminProduction.FreqQuestionsUser.LoadFreqQuestionsUser(freqQuestionsUserId, string.Empty, string.Empty)[0]; freqqQuestionsUser.questionDescription = QuestionDescription; freqqQuestionsUser.questionAnswer = QuestionAnswer; //save it Administrator.Models.AdminProduction.FreqQuestionsUser.addFreqQuestionsUser(freqqQuestionsUser); return RedirectToAction("SearchFreqQuestionsUser", "Prod", new { FreqQuestionsUserId = freqQuestionsUserId }); }

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• Squid proxy not serving modified html content

  - by Matthew

  I'm trying to use squid to modify the page content of web page requests. I followed the upside-down-ternet tutorial which showed instructions for how to flip images on pages. I need to change the actual html of the page. I've been trying to do the same thing as in the tutorial, but instead of editing the image I'm trying to edit the html page. Below is a php script I'm using to try to do it. All jpg images get flipped, but the content on the page does not get edited. The edited index.html files written contain the edited content, but the pages the users receive don't contain the edited content. #!/usr/bin/php <?php $temp = array(); while ( $input = fgets(STDIN) ) { $micro_time = microtime(); // Split the output (space delimited) from squid into an array. $temp = split(' ', $input); //Flip jpg images, this works correctly if (preg_match("/.*\.jpg/i", $temp[0])) { system("/usr/bin/wget -q -O /var/www/cache/$micro_time.jpg ". $temp[0]); system("/usr/bin/mogrify -flip /var/www/cache/$micro_time.jpg"); echo "http://127.0.0.1/cache/$micro_time.jpg\n"; } //Don't edit files that are obviously not html. $temp[0] contains url of file to get elseif (preg_match("/(jpg|png|gif|css|js|\(|\))/i", $temp[0], $matches)) { echo $input; } //Otherwise, could be html (e.g. `wget http://www.google.com` downloads index.html) else{ $time = time() . microtime(); //For unique directory names $time = preg_replace("/ /", "", $time); //Simplify things by removing the spaces mkdir("/var/www/cache/". $time); //Create unique folder system("/usr/bin/wget -q --directory-prefix=\"/var/www/cache/$time/\" ". $temp[0]); $filename = system("ls /var/www/cache/$time/"); //Get filename of downloaded file //File is html, edit the content (this does not work) if(preg_match("/.*\.html/", $filename)){ //Get the html file contents $contentfh = fopen("/var/www/cache/$time/". $filename, 'r'); $content = fread($contentfh, filesize("/var/www/cache/$time/". $filename)); fclose($contentfh); //Edit the html file contents $content = preg_replace("/<\/body>/i", "<!-- content served by proxy --></body>", $content); //Write the edited file $contentfh = fopen("/var/www/cache/$time/". $filename, 'w'); fwrite($contentfh, $content); fclose($contentfh); //Return the edited page echo "http://127.0.0.1/cache/$time/$filename\n"; } //Otherwise file is not html, don't edit else{ echo $input; } } } ?>

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• Command-Line Parsing API from TestAPI library - Type-Safe Commands how to

  - by MicMit

  Library at http://testapi.codeplex.com/ Excerpt of usage from http://blogs.msdn.com/ivo_manolov/archive/2008/12/17/9230331.aspx A third common approach is forming strongly-typed commands from the command-line parameters. This is common for cases when the command-line looks as follows: some-exe COMMAND parameters-to-the-command The parsing in this case is a little bit more involved: Create one class for every supported command, which derives from the Command abstract base class and implements an expected Execute method. Pass an expected command along with the command-line arguments to CommandLineParser.ParseCommand – the method will return a strongly-typed Command instance that can be Execute()-d. // EXAMPLE #3: // Sample for parsing the following command-line: // Test.exe run /runId=10 /verbose // In this particular case we have an actual command on the command-line (“run”), which we want to effectively de-serialize and execute. public class RunCommand : Command { bool? Verbose { get; set; } int? RunId { get; set; } public override void Execute() { // Implement your "run" execution logic here. } } Command c = new RunCommand(); CommandLineParser.ParseArguments(c, args); c.Execute(); ============================ I don't get if we instantiate specific class before parsing arguments , what's the point of command line argument "run" which is very first one. I thought the idea was to instantiate and execute command/class based on a command line parameter ( "run" parameter becomes instance RunCommand class, "walk" becomes WalkCommand class and so on ). Can it be done with the latest version ?

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• Collision of dot and line in 2D space

  - by Anderiel

  So i'm trying to make my first game on android. The thing is i have a small moving ball and i want it to bounce from a line that i drew. For that i need to find if the x,y of the ball are also coordinates of one dot from the line. I tried to implement these equations about lines x=a1 + t*u1 y=a2 + t*u2 = (x-a1)/u1=(y-a2)/u2 (t=t which has to be if the point is on the line) where x and y are the coordinates im testing, dot[a1,a2] is a dot that is on the line and u(u1,u2) is the vector of the line. heres the code: public boolean Collided() { float u1 =Math.abs(Math.round(begin_X)-Math.round(end_X)); float u2 =Math.abs(Math.round(begin_Y)-Math.round(end_Y)); float t_x =Math.round((elect_X - begin_X)/u1); float t_y =Math.round((elect_Y - begin_Y)/u2); if(t_x==t_y) { return true; } else { return false; } } points [begin_X,end_X] and [begin_Y,end_Y] are the two points from the line and [elect_X,elect_Y] are the coordinates of the ball theoreticaly it should work, but in the reality the ball most of the time just goes straigth through the line or bounces somewhere else where it shouldnt

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• Height of a html window's content (not just the viewport height)

  - by gatapia

  Hi All, I'm trying to get the height of a html window's content. This is the full height of the content not the visible height. I have had some (very limited) success using: document.getElementsByTagName('html')[0].offsetHeight in FireFox. This however fails in IEs and it fails in Chrome when using absolute positioned elements (http://code.google.com/p/chromium/issues/detail?id=38999). A sample html file that can be used to reproduce this is: <html> <head> <style> div { border:solid 1px red; height:2000px; width:400px; } .broken { position:absolute; top:0; left:0; } .fixed { position:relative; top:0; left:0; } </style> <script language='javascript'> window.onload = function () { document.getElementById('window.height').innerHTML = window.innerHeight; document.getElementById('window.screen.height').innerHTML = window.screen.height; document.getElementById('document.html.height').innerHTML = document.getElementsByTagName('html')[0].offsetHeight; } </script> </head> <body> <div class='fixed'> window.height: <span id='window.height'>&nbsp;</span> <br/> window.screen.height: <span id='window.screen.height'></span> <br/> document.html.height: <span id='document.html.height'></span> <br/> </div> </body> </html> Thanks All Guido Tapia

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• HTML inside webView

  - by Samuh

  I am posting some data to a server using DefaultHttpClient class and in the response stream I am getting a HTML file. I save the stream as a string and pass it onto another activity which contains a WebView to render this HTML on the screen: response = httpClient.execute(get); InputStream is = response.getEntity().getContent(); BufferedReader br = new BufferedReader(new InputStreamReader(is,"utf-8")); StringBuffer sb = new StringBuffer(); String line; while((line=br.readLine())!=null){ sb.append(line); sb.append("\n"); } is.close(); Intent intent = new Intent(this,Trial.class); intent.putExtra("trial",sb.toString()); startActivity(intent); Log.i("SB",sb.toString()); In Second Activity, the code to load the WebView reads: WebView browser = ((WebView)findViewById(R.id.trial_web)); browser.getSettings().setJavaScriptEnabled(true); browser.loadData(html,"text/html", "utf-8"); When I run this code, the WebView is not able to render the HTML content properly. It actually shows the HTML string in URL encoded format on the screen. Interestingly, If I copy the Loggers output to HTML file and then load this HTML in my WebView(using webview.loadurl(file:///assets/xyz.html)) everything works fine. I suspect some problem with character encoding. What is going wrong here? Please help. Thanks.

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• Distributing a custom command line tool to enterprise servers

  - by Jeremy Baker

  I've been tasked with building a command line tool that we will be providing to our enterprise customers so that they can use the API to upload data to our platform. The API works with standard cURL requests, so I can do most of the basic functionality with simple bash scripting, although I would like to provide something that is solid and really makes it easy for them to use and I don't know what I don't know. It's been a good 8 years since I've really done any serious sysadmin work. Most of the good tools I use these days are written in Ruby or Python and have a standard distribution process (Gems, for example). However, I know rhel and other platforms have their own package managers. Finally, the question: In today's day and age, what language / distribution method should I consider in order to cover the widest range of platforms without having to build completely different versions for each platform? I'd also love any general feedback you have about building similar projects, or links to projects that you think do a good job of this now and have open source code that I could read. Thanks in advance!

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• multiple Perl ` print $cgi->header, <<HTML; .... HTML ` statement gives problem

  - by dexter

  i have something like: #!/usr/bin/perl use strict; use warnings; use CGI::Simple; use DBI; my $cgi = CGI::Simple->new; if ($cgi->param('selid')) { print $cgi->header, <<HTML; <br/>this is SELECT HTML } elsif ($cgi->param('delid')) { print $cgi->header, <<HTML; <b>this is DELETE</b> HTML } elsif ($cgi->param('upid')) { print $cgi->header, <<HTML; <b>this is UPDATE</b> HTML } when i run this i get an error like: Error message: Can't find string terminator " HTML" anywhere before EOF at C:/xampp/htdocs/perl/action.pl line 14. , and when give space between << and HTML; like :print $cgi->header, << HTML; error changes to: Error message: Can't find string terminator " " anywhere before EOF at C:/xampp/htdocs/perl/action.pl line 14. , what would be the reason for this? note: parameters are passed from another page('selid' or 'delid' or 'upid')

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• Why "alt" attribute for <img> tag has been considered mandatory by the HTML validator .. ?

  - by infant programmer

  Is there any logical or technical reason (with the W3C validation) for making alt as required attribute .. This is my actual problem:though my page is perfect enough with respect to W3C validation rules .. Only error I am getting is line XX column YY - Error: required attribute "ALT" not specified I know the significance of "alt" attribute and I have omitted that where it is unnecessary .. (to be more elaborate .. I have added the image to increase the beauty of my page and I don't want alt attribute to show irrelevant message to the viewer) getting rid of the error is secondary .. rather I am curious to know whether is it a flaw with validation rules .. ?? I thank stackOverflow and all the members who responded me .. I got my doubt clarified .. :-)

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• embedded php in html to include header (top part of page) into the page

  - by Andy

  Hi there, I'm trying to put the top of my page (which is all html) in a seperate file so I only need to change things once like the menu bar etc. So I googled some and found a solution on this website as well, but it doesn't work and I don't know why. So I have a page like article.html and on the top I have this: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html lang="en"> <head> <?php include("/pages/header.php"); ?> <!-- rest of the html code --> In the header.php I have the html that should be on the top of each page and it starts with: <?php /** * @author name * website header */ ?> <!-- html code --> So what's wrong with this. When I open the page article.html and right click on it to view the source, I can see the php from above calling the header.php file. Thanks!

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• Starting airplay from command line, to send output of 'Say' Mac OS X command to airplay

  - by Fabien

  Ok, Sunday question :) Trying to make a little joke... 1) if you open a terminal, and type "say -a ?", Mac OS X will give you the list of devices it can send spoken words to. On mine, it says: 39 AirPlay 47 Built-in Output 2) I have a Denon airplay-ready received in my living room and I'm trying to send spoken words to my wife downstairs... I can send music without any problem using iTunes so, from an infrastructure standpoint, I'm all set. 3) I want my computer to say (out of the blue) "Honey, why don't you bring me a cup of coffee". I can make it say that locally on my internal laptop speakers, but I can't seem to send that to device 39 successfully. I am suspecting that there are a few other things that need to be setup before it works, i.e. setting up airplay output to "denon", maybe opening a channel and reserving it. I don't know. Has anyone played with this? Is there a way to setup airplay from the command line? That would be awesome :)

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• mysql command line not working

  - by Sandeepan Nath

  I have mysql running in my fedora system. I have xampp setup on the system and php projects present in the webspace are working fine. PhpMyAdmin is working fine. echoing phpinfo() in a PHP script also shows mysql enabled. But running mysql connect command mysql -u[username] -p[password] Gives this - bash: mysql: command not found How do I fix that? Any pointers? I guess I need to do some pointing (define some path in some file) so that my system knows that mysql is installed. What exactly do I have to do? Additional Details This system was someone else's and he is not available here. May be PHP/Mysql was setup already in the system. I just freshly extracted xampp for linux into /opt/lampp/ and have put all the above mentioned things (PHP projects and PhpMyAdmin) there. After doing that I had a socket problem (PhpMyAdmin was not working and showing this)- #2002 - The server is not responding (or the local MySQL server's socket is not correctly configured) I restarted lampp using ./lampp restart but problem remained. Then after turning on system today, I started lampp and everything worked just fine. No project issues anymore only command line Mysql not working

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• How to perform this Windows 7 permissions change on many files via GUI or command line

  - by hippietrail

  After using my external hard drive on another Windows 7 computer to tweak photos with Windows Live Photo Gallery then upload them to Facebook I found the modified images were now not visible on the original Windows 7 computer. I'm not sure if the things I tried to get it working subsequently changed anything, but I do know this is the sequence of actions that makes the permissions of the modified files match those of the unmodified files: Right click on broken image file, select "Properties" On the "Security" tab press the "Advanced" button In the "Permissions" tab press the "Continue" button with the shield icon on it Tick the box marked "Include inheritable permissions from this object's parent Click the "Remove" button to remove the only current entry "Type: Allow, Name: Administrators (XYZ\Administrators), Permission: Full control, Inherited From: OK on the "Permissions" tab. OK on the "Security" tab. Now this same procedure does not work at the folder level. It results in "access denied" dialogs. I'm looking for some way to perform this exact modification on all the images I edited on the other computer. I'm happy to use the Windows GUI in Explorer or any other included tools. I'm happy to use the Windows command line. I'd prefer not to use a third-party tool since I'd have to be satisfied it's not doing anything else. I'm not looking for a different way to change permissions to other settings to make an external drive full of photos editable on multiple computers. At least not in this question.

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• How do I access a mounted Windows share from the command line?

  - by Bryan

  Hello all, I use Places > Connect to Server... to connect to a Windows share in my work environment (requires Kerberos authentication). When I do so, I can access the Windows share via Nautilus, but I can't figure out how to access the share from the command line without using smbclient. For example, the share isn't mounted under /mnt or /media. I also looked into ~/.gvfs but that's empty as well. Is it possible to access the mounted Windows share from the command line without using smbclient?

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• What does it mean to "have experience with the Unix/Linux command line"? [closed]

  - by Aerovistae

  I'm a new comp sci grad applying to jobs, and this requirement confuses me, especially since the job description (Python back-end developer) says it's the single most important thing ("Everything else we can teach you!") I mean, I know how to use the command line... I know your standard run-of-the-mill stuff like navigating around and manipulating files and permissions and using pipes and running applications, but what are they looking for when they say something like that? I'm aware there's no end to what you can do with the command line, but I was under the impression that after a certain point it's the sort of thing that only benefits server/system administrators.

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• How to enter the Default Keyring password via the command line?

  - by Jerkofalltrades

  Is there a way to enter the default keyring password using the command line? For instance: You have a remote setup of Ubuntu 10.10 thats set to auto login. You don't want to remove the keyring password. All right the system boots up and logs in automatically, then asks for the keyring password now at this point you can create ssh connections but you can't remote desktop. What can you do to enter the keyring password at this point? Also, to better clarify, this is from a remote connection using the command line.

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• When is it appropriate to use colour in a command-line application?

  - by marcoms

  Currently I have a command-line application in C called btcwatch. It has a -C option that it can receive as an argument that compares the current price of Bitcoin with a price that was stored beforehand with -S. Example output with this option is: $ btcwatch -vC # -v = verbose buy: UP $ 32.000000 USD (100.000000 -> 132.000000) sell: UP $ 16.000000 USD (100.000000 -> 116.000000) The dilemma is whether to use colour for the UP or DOWN string (green and red, respectively). Most command-line applications I know of (apart from git) stay away from colour in their output. In my desire for btcwatch to look and be quite "standard" (use of getopt, Makefiles, etc), I'm not sure if colour would look out of place in this situation.

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• Draw a line in crystal report

  - by Aniruddha

  I want to draw a line in Crystal report. I can do that from a sub-menu but this line I need to draw in a Group section Field object with a background color property set to some color. So whenever I draw a line it gets overlapped by this FieldObject. How can I make sure that line would be visible over the background color of object?

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