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  • How do you create a MANIFEST.MF that's available when you're testing and running from a jar in produ

    - by warvair
    I've spent far too much time trying to figure this out. This should be the simplest thing and everyone who distributes Java applications in jars must have to deal with it. I just want to know the proper way to add versioning to my Java app so that I can access the version information when I'm testing, e.g. debugging in Eclipse and running from a jar. Here's what I have in my build.xml: <target name="jar" depends = "compile"> <property name="version.num" value="1.0.0"/> <buildnumber file="build.num"/> <tstamp> <format property="TODAY" pattern="yyyy-MM-dd HH:mm:ss" /> </tstamp> <manifest file="${build}/META-INF/MANIFEST.MF"> <attribute name="Built-By" value="${user.name}" /> <attribute name="Built-Date" value="${TODAY}" /> <attribute name="Implementation-Title" value="MyApp" /> <attribute name="Implementation-Vendor" value="MyCompany" /> <attribute name="Implementation-Version" value="${version.num}-b${build.number}"/> </manifest> <jar destfile="${build}/myapp.jar" basedir="${build}" excludes="*.jar" /> </target> This creates /META-INF/MANIFEST.MF and I can read the values when I'm debugging in Eclipse thusly: public MyClass() { try { InputStream stream = getClass().getResourceAsStream("/META-INF/MANIFEST.MF"); Manifest manifest = new Manifest(stream); Attributes attributes = manifest.getMainAttributes(); String implementationTitle = attributes.getValue("Implementation-Title"); String implementationVersion = attributes.getValue("Implementation-Version"); String builtDate = attributes.getValue("Built-Date"); String builtBy = attributes.getValue("Built-By"); } catch (IOException e) { logger.error("Couldn't read manifest."); } } But, when I create the jar file, it loads the manifest of another jar (presumably the first jar loaded by the application - in my case, activation.jar). Also, the following code doesn't work either although all the proper values are in the manifest file. Package thisPackage = getClass().getPackage(); String implementationVersion = thisPackage.getImplementationVersion(); Any ideas?

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  • How to verify if the private key matches with the certificate..?

    - by surendhar_s
    I have the private key stored as .key file.. -----BEGIN RSA PRIVATE KEY----- MIICXAIBAAKBgQD5YBS6V3APdgqaWAkijIUHRK4KQ6eChSaRWaw9L/4u8o3T1s8J rUFHQhcIo5LPaQ4BrIuzHS8yzZf0m3viCTdZAiDn1ZjC2koquJ53rfDzqYxZFrId 7a4QYUCvM0gqx5nQ+lw1KoY/CDAoZN+sO7IJ4WkMg5XbgTWlSLBeBg0gMwIDAQAB AoGASKDKCKdUlLwtRFxldLF2QPKouYaQr7u1ytlSB5QFtIih89N5Avl5rJY7/SEe rdeL48LsAON8DpDAM9Zg0ykZ+/gsYI/C8b5Ch3QVgU9m50j9q8pVT04EOCYmsFi0 DBnwNBRLDESvm1p6NqKEc7zO9zjABgBvwL+loEVa1JFcp5ECQQD9/sekGTzzvKa5 SSVQOZmbwttPBjD44KRKi6LC7rQahM1PDqmCwPFgMVpRZL6dViBzYyWeWxN08Fuv p+sIwwLrAkEA+1f3VnSgIduzF9McMfZoNIkkZongcDAzjQ8sIHXwwTklkZcCqn69 qTVPmhyEDA/dJeAK3GhalcSqOFRFEC812QJAXStgQCmh2iaRYdYbAdqfJivMFqjG vgRpP48JHUhCeJfOV/mg5H2yDP8Nil3SLhSxwqHT4sq10Gd6umx2IrimEQJAFNA1 ACjKNeOOkhN+SzjfajJNHFyghEnJiw3NlqaNmEKWNNcvdlTmecObYuSnnqQVqRRD cfsGPU661c1MpslyCQJBAPqN0VXRMwfU29a3Ve0TF4Aiu1iq88aIPHsT3GKVURpO XNatMFINBW8ywN5euu8oYaeeKdrVSMW415a5+XEzEBY= -----END RSA PRIVATE KEY----- And i extracted public key from ssl certificate file.. Below is the code i tried to verify if private key matches with ssl certificate or not.. I used the modulus[i.e. private key get modulus==public key get modulus] to check if they are matching.. And this seems to hold only for RSAKEYS.. But i want to check for other keys as well.. Is there any other alternative to do the same..?? private static boolean verifySignature(File serverCertificateFile, File serverCertificateKey) { try { byte[] certificateBytes = FileUtils.readFileToByteArray(serverCertificateFile); //byte[] keyBytes = FileUtils.readFileToByteArray(serverCertificateKey); RandomAccessFile raf = new RandomAccessFile(serverCertificateKey, "r"); byte[] buf = new byte[(int) raf.length()]; raf.readFully(buf); raf.close(); PKCS8EncodedKeySpec kspec = new PKCS8EncodedKeySpec(buf); KeyFactory kf; try { kf = KeyFactory.getInstance("RSA"); RSAPrivateKey privKey = (RSAPrivateKey) kf.generatePrivate(kspec); CertificateFactory certFactory = CertificateFactory.getInstance("X.509"); InputStream in = new ByteArrayInputStream(certificateBytes); //Generate Certificate in X509 Format X509Certificate cert = (X509Certificate) certFactory.generateCertificate(in); RSAPublicKey publicKey = (RSAPublicKey) cert.getPublicKey(); in.close(); return privKey.getModulus() == publicKey.getModulus(); } catch (NoSuchAlgorithmException ex) { logger.log(Level.SEVERE, "Such algorithm is not found", ex); } catch (CertificateException ex) { logger.log(Level.SEVERE, "certificate exception", ex); } catch (InvalidKeySpecException ex) { Logger.getLogger(CertificateConversion.class.getName()).log(Level.SEVERE, null, ex); } } catch (IOException ex) { logger.log(Level.SEVERE, "Signature verification failed.. This could be because the file is in use", ex); } return false; } And the code isn't working either.. throws invalidkeyspec exception

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  • Sqlite issues with HTC Desire HD

    - by Greg
    Recently I have been getting a lot of complaints about the HTC Desire series and it failing while invoking sql statements. I have received reports from users with log snapshots that contain the following. I/Database( 2348): sqlite returned: error code = 8, msg = statement aborts at 1: [pragma journal_mode = WAL;] E/Database( 2348): sqlite3_exec to set journal_mode of /data/data/my.app.package/files/localized_db_en_uk-1.sqlite to WAL failed followed by my app basically burning in flames because the call to open the database results in a serious runtime error that manifests itself as the cursor being left open. There shouldn't be a cursor at this point as we are trying to open it. This only occurs with the HTC Desire HD and Z. My code basically does the following (changed a little to isolate the problem area). SQLiteDatabase db; String dbName; public SQLiteDatabase loadDb(Context context) throws IOException{ //Close any old db handle if (db != null && db.isOpen()) { db.close(); } // The name of the database to use from the bundled assets. String dbAsset = "/asset_dir/"+dbName+".sqlite"; InputStream myInput = context.getAssets().open(dbAsset, Context.MODE_PRIVATE); // Create a file in the app's file directory since sqlite requires a path // Not ideal but we will copy the file out of our bundled assets and open it // it in another location. FileOutputStream myOutput = context.openFileOutput(dbName, Context.MODE_PRIVATE); byte[] buffer = new byte[1024]; int length; while ((length = myInput.read(buffer)) > 0) { myOutput.write(buffer, 0, length); } // Close the streams myOutput.flush(); // Guarantee Write! myOutput.getFD().sync(); myOutput.close(); myInput.close(); // Not grab the newly written file File fileObj = context.getFileStreamPath(dbName); // and open the database return db = SQLiteDatabase.openDatabase(fileObj.getAbsolutePath(), null, SQLiteDatabase.OPEN_READONLY | SQLiteDatabase.NO_LOCALIZED_COLLATORS); } Sadly this phone is only available in the UK and I don't have one in my inventory. I am only getting reports of this type from the HTC Desire series. I don't know what changed as this code has been working without any problem. Is there something I am missing?

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  • Uploading files to varbinary(max) in SQL Server -- works on one server, not the other

    - by pjabbott
    I have some code that allows users to upload file attachments into a varbinary(max) column in SQL Server from their web browser. It has been working perfectly fine for almost two years, but all of a sudden it stopped working. And it stopped working on only the production database server -- it still works fine on the development server. I can only conclude that the code is fine and there is something up with the instance of SQL Server itself. But I have no idea how to isolate the problem. I insert a record into the ATTACHMENT table, only inserting non-binary data like the title and the content type, and then chunk-upload the uploaded file using the following code: // get the file stream System.IO.Stream fileStream = postedFile.InputStream; // make an upload buffer byte[] fileBuffer; fileBuffer = new byte[1024]; // make an update command SqlCommand fileUpdateCommand = new SqlCommand("update ATTACHMENT set ATTACHMENT_DATA.WRITE(@Data, NULL, NULL) where ATTACHMENT_ID = @ATTACHMENT_ID", sqlConnection, sqlTransaction); fileUpdateCommand.Parameters.Add("@Data", SqlDbType.Binary); fileUpdateCommand.Parameters.AddWithValue("@ATTACHMENT_ID", newId); while (fileStream.Read(fileBuffer, 0, fileBuffer.Length) > 0) { fileUpdateCommand.Parameters["@Data"].Value = fileBuffer; fileUpdateCommand.ExecuteNonQuery(); <------ FAILS HERE } fileUpdateCommand.Dispose(); fileStream.Close(); Where it says "FAILS HERE", it sits for a while and then I get a SQL Server timeout error on the very first iteration through the loop. If I connect to the development database instead, everything works fine (it runs through the loop many, many times and the commit is successful). Both servers are identical (SQL Server 9.0.3042) and the schemas are identical as well. When I open Activity Monitor right after the timeout to see what's going it, it says the last command is (@Data binary(1024),@ATTACHMENT_ID decimal(4,0))update ATTACHMENT set ATTACHMENT_DATA.WRITE(@Data, NULL, NULL) where ATTACHMENT_ID = @ATTACHMENT_ID which I would expect but it also says it has a status of "Suspended" and a wait type of "PAGEIOLATCH_SH". I looked this up and it seems to be a bad thing but I can't find anything specific to my stuation. Ideas?

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  • StringBuffer wont read whole stream into a string (JAVA/Android)

    - by Levara
    Hi all! I'm making an android program that retrieves content of a webpage using HttpURLConnection. I'm new to both Java and Android. Problem is: Reader reads whole page source, but in the last while iteration it doesn't append to stringBuffer that last part. Using debbuger I have determined that, in the last loop iteration, string buff is created, but stringBuffer just doesnt append it. I need to parse retrieved content. Is there any better way to handle the content for parsing than using strings. I've read on numerous other sites that string size in Java is limited only by available heap size. I've tried with StringBuilder too. Anyone know what could be the problem. Btw feel free to suggest any improvements to the code. Thanks! URL u; try { u = new URL("http://feeds.timesonline.co.uk/c/32313/f/440134/index.rss"); HttpURLConnection c = (HttpURLConnection) u.openConnection(); c.setRequestProperty("User-agent","Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1; .NET CLR 1.1.4322; InfoPath.1; .NET CLR 2.0.50727)"); c.setRequestMethod("GET"); c.setDoOutput(true); c.setReadTimeout(3000); c.connect(); StringBuffer stringBuffer = new StringBuffer(""); InputStream in = c.getInputStream(); InputStreamReader inp = new InputStreamReader(in); BufferedReader reader = new BufferedReader(inp); char[] buffer = new char[3072]; int len1 = 0; while ( (len1 = reader.read(buffer)) != -1 ) { String buff = new String(buffer,0,len1); stringBuffer.append(buff); } String stranica = new String(stringBuffer); c.disconnect(); reader.close(); inp.close(); in.close();

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  • How to use sound and images in a Java applet?

    - by Click Upvote
    Question 1: How should I structure my project so the sound and images files can be loaded most easily? Right now, I have the folder: C:\java\pacman with the sub-directory C:\java\pacman\src containing all the code, and C:\java\pacman\assets containing the images and .wav files. Is this the best structure or should I put the assets somewhere else? Question 2: What's the best way to refer to the images/sounds without using the full path e.g C:\java\pacman\assets\something.png to them? If I use the getCodeBase() function it seems to refer to the C:\java\pacman\bin instead of C:\java\pacman\. I want to use such a function/class which would work automatically when i compile the applet in a jar as well as right now when I test the applet through eclipse. Question 3: How should I load the images/sounds? This is what I'm using now: 1) For general images: import java.awt.Image; public Image getImg(String file) { //imgDir in this case is a hardcoded string containing //"C:\\java\\pacman\\assets\\" file=imgDir + file; return new ImageIcon(file).getImage(); } The images returned from this function are used in the drawImage method of the Graphics class in the paint method of the applet. 2) For a buffered image, which is used to get subImages and load sprites from a sprite sheet: public BufferedImage getSheet() throws IOException { return ImageIO.read(new File(img.getPath("pacman-sprites.png"))); } Later: public void loadSprites() { BufferedImage sheet; try { sheet=getSheet(); redGhost.setNormalImg(sheet.getSubimage(0, 60, 20, 20)); redGhost.setUpImg(sheet.getSubimage(0, 60, 20, 20)); redGhost.setDownImg(sheet.getSubimage(30, 60, 20, 20)); redGhost.setLeftImg(sheet.getSubimage(30, 60, 20, 20)); redGhost.setRightImg(sheet.getSubimage(60, 60, 20, 20)); } catch (IOException e) { System.out.println("Couldnt open file!"); System.out.println(e.getLocalizedMessage()); } } 3) For sound files: import sun.audio.*; import java.io.*; public synchronized void play() { try { InputStream in = new FileInputStream(filename); AudioStream as = new AudioStream(in); AudioPlayer.player.start(as); } catch (IOException e) { e.printStackTrace(); } }

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  • Strange Java Socket Behavior (Connects, but Doesn't Send)

    - by Donald Campbell
    I have a fairly complex project that boils down to a simple Client / Server communicating through object streams. Everything works flawlessly for two consecutive connections (I connect once, work, disconnect, then connect again, work, and disconnect). The client connects, does its business, and then closes. The server successfully closes both the object output stream and the socket, with no IO errors. When I try to connect a third time, the connection appears to go through (the ServerSocket.accept() method goes through and an ObjectOutputStream is successfully created). No data is passed, however. The inputStream.readUnshared() method simply blocks. I have taken the following memory precautions: When it comes time to close the sockets, all running threads are stopped, and all objects are nulled out. After every writeUnshared() method call, the ObjectOutputBuffer is flushed and reset. Has anyone encountered a similar problem, or does anyone have any suggestions? I'm afraid my project is rather large, and so copying code is problematic. The project boils down to this: SERVER MAIN ServerSocket serverSocket = new ServerSocket(port); while (true) { new WorkThread(serverSocket.accept()).start(); } WORK THREAD (SERVER) public void run() { ObjectInputBuffer inputBuffer = new ObjectInputBuffer(new BufferedInputStream(socket.getInputStream())); while (running) { try { Object myObject = inputBuffer.readUnshared(); // do work is not specified in this sample doWork(myObject); } catch (IOException e) { running = false; } } try { inputBuffer.close(); socket.close(); } catch (Exception e) { System.out.println("Could not close."); } } CLIENT public Client() { Object myObject; Socket mySocket = new Socket(address, port); try { ObjectOutputBuffer output = new ObjectOutputBuffer(new BufferedOutputStream(mySocket.getOutputStream())); output.reset(); output.flush(); } catch (Exception e) { System.out.println("Could not get an input."); mySocket.close(); return; } // get object data is not specified in this sample. it simply returns a serializable object myObject = getObjectData(); while (myObject != null) { try { output.writeUnshared(myObject); output.reset(); output.flush(); } catch (Exception e) { e.printStackTrace(); break; } // catch } // while try { output.close(); socket.close(); } catch (Exception e) { System.out.println("Could not close."); } } Thank you to everyone who may be able to help!

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  • Listfield layout question - blackberry

    - by Kai
    I'm having an interesting anomaly when displaying a listfield on the blackberry simulator: The top item is the height of a single line of text (about 12 pixels) while the rest are fine. Does anyone know why only the top item is being drawn this way? Also, when I add an empty venue in position 0, it still displays the first actual venue this way (item in position 1). Not sure what to do. Thanks for any help. The layout looks like this: ----------------------------------- | *part of image* | title | ----------------------------------- | | title | | * full image * | address | | | city, zip | ----------------------------------- The object is called like so: listField = new ListField( venueList.size() ); listField.setCallback( this ); listField.setSelectedIndex(-1); _middle.add( listField ); Here is the drawListRow code: public void drawListRow( ListField listField, Graphics graphics, int index, int y, int width ) { listField.setRowHeight(90); Hashtable item = (Hashtable) venueList.elementAt( index ); String venue_name = (String) item.get("name"); String image_url = (String) item.get("image_url"); String address = (String) item.get("address"); String city = (String) item.get("city"); String zip = (String) item.get("zip"); EncodedImage img = null; try { String filename = image_url.substring( image_url.indexOf("crop/") + 5, image_url.length() ); FileConnection fconn = (FileConnection) Connector.open( "file:///SDCard/Blackberry/project1/" + filename, Connector.READ); if ( !fconn.exists() ) { } else { InputStream input = fconn.openInputStream(); byte[] data = new byte[(int)fconn.fileSize()]; input.read(data); input.close(); if(data.length > 0) { EncodedImage rawimg = EncodedImage.createEncodedImage(data, 0, data.length); int dw = Fixed32.toFP(Display.getWidth()); int iw = Fixed32.toFP(rawimg.getWidth()); int sf = Fixed32.div(iw, dw); img = rawimg.scaleImage32(sf * 4, sf * 4); } else { } } } catch(IOException ef) { } graphics.drawText( venue_name, 140, y, 0, width ); graphics.drawText( address, 140, y + 15, 0, width ); graphics.drawText( city + ", " + zip, 140, y + 30, 0, width ); if(img != null) { graphics.drawImage(0, y, img.getWidth(), img.getHeight(), img, 0, 0, 0); } }

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  • Two collections and a for loop. (Urgent help needed) Checking an object variable against an inputted

    - by Elliott
    Hi there, I'm relatively new to java, I'm certain the error is trivial. But can't for the life of me spot it. I have an end of term exam on monday and currently trying to get to grips with past papers! Anyway heregoes, in another method (ALGO_1) I search over elements of and check the value H_NAME equals a value entered in the main. When I attempt to run the code I get a null pointer exception, also upon trying to print (with System.out.println etc) the H_NAME value after each for loop in the snippet I also get a null statement returned to me. I am fairly certain that the collection is simply not storing the data gathered up by the Scanner. But then again when I check the collection size with size() it is about the right size. Either way I'm pretty lost and would appreciate the help. Main questions I guess to ask are: from the readBackground method is the data.add in the wrong place? is the snippet simply structured wrongly? oh and another point when I use System.out.println to check the Background object values name, starttime, increment etc they print out fine. Thanks in advance.(PS im guessing the formatting is terrible, apologies.) snippet of code: for(Hydro hd: hydros){ System.out.println(hd.H_NAME); for(Background back : backgs){ System.out.println(back.H_NAME); if(back.H_NAME.equals(hydroName)){ //get error here public static Collection<Background> readBackground(String url) throws IOException { URL u = new URL(url); InputStream is = u.openStream(); InputStreamReader isr = new InputStreamReader(is); BufferedReader b = new BufferedReader(isr); String line =""; Vector<Background> data = new Vector<Background>(); while((line = b.readLine())!= null){ Scanner s = new Scanner(line); String name = s.next(); double starttime = Double.parseDouble(s.next()); double increment = Double.parseDouble(s.next()); double sum = 0; double p = 0; double nterms = 0; while((s.hasNextDouble())){ p = Double.parseDouble(s.next()); nterms++; sum += p; } double pbmean = sum/nterms; Background SAMP = new Background(name, starttime, increment, pbmean); data.add(SAMP); } return data; } Edit/Delete Message

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  • Getting huge lags when downloading files via Service

    - by Copa
    I have a Service which receives URLs to download. The Service than downloads these URLs and save them to a file on the SD Card. When I put more than 2 items in the download queue my device is unusable. It nearly freezes. Huge lags and so on. Any idea? Sourcecode: private static boolean downloading = false; private static ArrayList<DownloadItem> downloads = new ArrayList<DownloadItem>(); /** * called once when the service started */ public static void start() { Thread thread = new Thread(new Runnable() { @Override public void run() { while (true) { if (downloads.size() > 0 && !downloading) { downloading = true; DownloadItem item = downloads.get(0); downloadSingleFile(item.getUrl(), item.getFile()); } } } }); thread.start(); } public static void addDownload(DownloadItem item) { downloads.add(item); } private static void downloadSuccessfullFinished() { if (downloads.size() > 0) downloads.get(0).setDownloaded(true); downloadFinished(); } private static void downloadFinished() { // remove the first entry; it has been downloaded if (downloads.size() > 0) downloads.remove(0); downloading = false; } private static void downloadSingleFile(String url, File output) { final int maxBufferSize = 4096; HttpResponse response = null; try { response = new DefaultHttpClient().execute(new HttpGet(url)); if (response != null && response.getStatusLine().getStatusCode() == 200) { // request is ok InputStream is = response.getEntity().getContent(); BufferedInputStream bis = new BufferedInputStream(is); RandomAccessFile raf = new RandomAccessFile(output, "rw"); ByteArrayBuffer baf = new ByteArrayBuffer(maxBufferSize); long current = 0; long i = 0; // read and write 4096 bytes each time while ((current = bis.read()) != -1) { baf.append((byte) current); if (++i == maxBufferSize) { raf.write(baf.toByteArray()); baf = new ByteArrayBuffer(maxBufferSize); i = 0; } } if (i > 0) // write the last bytes to the file raf.write(baf.toByteArray()); baf.clear(); raf.close(); bis.close(); is.close(); // download finished get start next download downloadSuccessfullFinished(); return; } } catch (Exception e) { // not successfully downloaded downloadFinished(); return; } // not successfully downloaded downloadFinished(); return; }

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  • Command Not working in separate thread in J2me.

    - by RishiPatel
    I am creating a bluetooth application. I created a simple midlet with a exit command and i create a thread for finding the service and discovering the device. While doing so it displays a animated screen on which i added the parent commandListener for exit command. After successful connection both user is represented with greetings(Current screen calls the parent Display method setCurrent for displaying itself). This screen also have CommandListener set to the parent. Now i want to add few more commands. I Implemented the CommandLIstener Interface in this class, added few commands but the commands are not working. I dont whats wen wrong. I am giving u Code snippets to fully describle my issue : - package name Imports here public class MyMidlet extends MIDlet implements CommandListener { public CommandListener theListener; public Display theDisplay; public Command exitCommand; public MyMidlet() { // Retrieve the display for this MIDlet //Create the initial screen } public void startApp() throws MIDletStateChangeException { } public void pauseApp() { } public void destroyApp(boolean unconditional) { } public void commandAction(Command c, Displayable d) { // Determine if the exit command was selected if (c == exitCommand) { //End application here notifyDestroyed(); } else { //Start the new thread here } } } Now here is the code for the class which is invoked by the above midlet in a separate thread; package here; imports here public class MyService implements Runnable, CommandListener { private MyMidlet parent; private StreamConnection conn; private OutputStream output; private InputStream input; public Command sendCommand; private TextField messageToSend Form form; public BChatService(boolean isServer, BChatMidlet parent) { //some stuff here this.parent = parent; } public void run() { //functino for showing animation here try { input = conn.openInputStream(); output = conn.openOutputStream(); } catch (IOException e) { displayError("IO Error", "An error occurred while opening " + "the input and output streams" + "(IOException: " + e.getMessage() + ")"); try { conn.close(); } catch (Exception ex) { } return; } // Create the Form here when service is discoverd and greets the users Command sendCommand = new Command("Send", Command.ITEM, 2); exitCommand = new Command("Exit", Command.EXIT, 1); form.addCommand(exitCommand); form.addCommand(sendCommand); parent.theDisplay.setCurrent(form); form.setCommandListener(this); public void commandAction(Command c, Displayable d) { if (c == exitCommand) { // End the game parent.destroyApp(true); parent.notifyDestroyed(); } if(c == sendCommand) { form.append("SOme text here"); } } } When i select the Send command, the string doesnt append in form neither exit command works. What can be the possible cause for it?? I need to implement this functionality...Is there any other way to achieve this??

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  • 2 dimensional arraylists in java

    - by Chris Maness
    So here's the deal I'm working on a project that requires me to have a 2 dimensional arraylist of 1 dimensional arrays. But every time I try to load in my data I get an error: Can't do this opperation because of bad input java.lang.IndexOutOfBoundsException: Index: 1, Size: 0 On some of the inputs. I've got no idea where I'm going wrong on this one. A little help please? Source Code: import java.io.BufferedInputStream; import java.io.File; import java.io.FileInputStream; import java.io.FileNotFoundException; import java.io.IOException; import java.util.ArrayList; import java.util.Scanner; import javax.swing.JOptionPane; import java.io.InputStream; public class Facebull { public static void main (String[] args) { if(args.length != 0){ load(args[0]); } else{ load("testFile"); } } public static void load(String fname) { int costOfMach = 0; ArrayList <Integer> finalMach = new ArrayList<Integer>(); ArrayList <ArrayList<int[]>>machines = new ArrayList<ArrayList<int[]>>(); Scanner inputFile = null; File f = new File(fname); if (f.exists ()) { try { inputFile = new Scanner (f); } catch (FileNotFoundException e) { JOptionPane.showMessageDialog(null,"Can't find the file\n" + e); } int i = 0; while (inputFile.hasNext ( )) { String str = inputFile.nextLine ( ); String [ ] fields = str.split ("[\t ]"); System.out.println(str); if (!(fields[0].isEmpty() || fields[0].equals (""))){ fields[0] = fields[0].substring(1); fields[1] = fields[1].substring(1); fields[2] = fields[2].substring(1); try { //data to be inputed is 0 and 3 location of data is 1 and 2 int[] item = new int[2]; item[1] = Integer.parseInt(fields[0]); item[0] = Integer.parseInt(fields[3]); if(machines.size() < Integer.parseInt(fields[1])){ ArrayList<int[]> column = new ArrayList<int[]>(); machines.add (Integer.parseInt(fields[1])-1, column); System.out.println("we're in the if"); } machines.get(Integer.parseInt(fields[1])-1).add(Integer.parseInt(fields[2])-1, item); } //catches any exception catch (Exception e) { System.out.println("Can't do this opperation because of bad input \n" + e); } } } inputFile.close ( ); } System.out.print(machines); }//end load }

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  • Android: Unable to access a local website over HTTPS

    - by user1253789
    I am trying to access a locally hosted website and get its HTML source to parse. I have few questions: 1) Can I use "https://An IP ADDRESS HERE" as a valid URL to try and access. I do not want to make changes in the /etc/hosts file so I want to do it this way. 2) I cannot get the html, since it is giving me Handshake exceptions and Certificate issues. I have tried a lot of help available over the web , but am not successful. Here is the code I am using: public class MainActivity extends Activity { private TextView textView; String response = ""; String finalresponse=""; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); textView = (TextView) findViewById(R.id.TextView01); System.setProperty("javax.net.ssl.trustStore","C:\\User\\*" ); System.setProperty("javax.net.ssl.trustStorePassword", "" ); } private class DownloadWebPageTask extends AsyncTask<String, Void, String> { @Override protected String doInBackground(String... urls) { TrustManager[] trustAllCerts = new TrustManager[] { new X509TrustManager() { public java.security.cert.X509Certificate[] getAcceptedIssuers() { return null; } public void checkClientTrusted(java.security.cert.X509Certificate[] certs, String authType) { } public void checkServerTrusted(java.security.cert.X509Certificate[] certs, String authType) { } } }; try { SSLContext sc = SSLContext.getInstance("SSL"); sc.init(null, trustAllCerts, new java.security.SecureRandom()); HttpsURLConnection.setDefaultSSLSocketFactory(sc.getSocketFactory()); } catch (Exception e) { } try { URL url = new URL("https://172.27.224.133"); HttpsURLConnection con =(HttpsURLConnection)url.openConnection(); con.setHostnameVerifier(new AllowAllHostnameVerifier()); finalresponse=readStream(con.getInputStream()); } catch (Exception e) { e.printStackTrace(); } return finalresponse; } private String readStream(InputStream in) { BufferedReader reader = null; try { reader = new BufferedReader(new InputStreamReader(in)); String line = ""; while ((line = reader.readLine()) != null) { response+=line; } } catch (IOException e) { e.printStackTrace(); } finally { if (reader != null) { try { reader.close(); } catch (IOException e) { e.printStackTrace(); } } } return response; } @Override protected void onPostExecute(String result) { textView.setText(finalresponse); } } public void readWebpage(View view) { DownloadWebPageTask task = new DownloadWebPageTask(); task.execute(new String[] { "https://172.27.224.133" }); } }

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  • OutOfMemoryError loading Bitmap via DefaultHttpClient

    - by Goddchen
    i have a simple problem: Although i'm using sampleSize properly, my code doesn't even reach the BitmapFactorycode, since DefaultHttpClient is already throwing the exception. Here is my code: DefaultHttpClient client = new DefaultHttpClient(); HttpGet request = new HttpGet(mSongInfo.imageLarge); HttpResponse response = client.execute(request); int sampleSize = 1; while (response.getEntity().getContentLength() / sampleSize / sampleSize > 100 * 1024) { sampleSize *= 2; } BitmapFactory.Options options = new BitmapFactory.Options(); options.inSampleSize = sampleSize; final Bitmap bitmap = BitmapFactory.decodeStream(response .getEntity().getContent(), null, options); And here is the exception: 0 java.lang.OutOfMemoryError: (Heap Size=11463KB, Allocated=7623KB, Bitmap Size=9382KB) 1 at org.apache.http.util.ByteArrayBuffer.<init>(ByteArrayBuffer.java:53) 2 at org.apache.http.impl.io.AbstractSessionInputBuffer.init(AbstractSessionInputBuffer.java:82) 3 at org.apache.http.impl.io.SocketInputBuffer.<init>(SocketInputBuffer.java:98) 4 at org.apache.http.impl.SocketHttpClientConnection.createSessionInputBuffer(SocketHttpClientConnection.java:83) 5 at org.apache.http.impl.conn.DefaultClientConnection.createSessionInputBuffer(DefaultClientConnection.java:170) 6 at org.apache.http.impl.SocketHttpClientConnection.bind(SocketHttpClientConnection.java:106) 7 at org.apache.http.impl.conn.DefaultClientConnection.openCompleted(DefaultClientConnection.java:129) 8 at org.apache.http.impl.conn.DefaultClientConnectionOperator.openConnection(DefaultClientConnectionOperator.java:173) 9 at org.apache.http.impl.conn.AbstractPoolEntry.open(AbstractPoolEntry.java:164) 10 at org.apache.http.impl.conn.AbstractPooledConnAdapter.open(AbstractPooledConnAdapter.java:119) 11 at org.apache.http.impl.client.DefaultRequestDirector.execute(DefaultRequestDirector.java:359) 12 at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:555) 13 at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:487) 14 at org.apache.http.impl.client.AbstractHttpClient.execute(AbstractHttpClient.java:465) 15 at de.goddchen.android.easysongfinder.fragments.SongFragment$1.run(SongFragment.java:79) 16 at java.lang.Thread.run(Thread.java:1027) As you can see, the code doesn't even reach the part where i check the size (Content-Length) of the image and calculate a proper sample size. I wasn't aware that simply calling DefaultHttpClient.execute(...) will already load the complete content into the memory. Am i doing something wrong? What is the right way to first retrieve the content length and then start reading the content from an InputStream? EDIT To avoid common answers that show how to load images from a URL: i already know how to do that, i have also posted the code above, so why do you keep referencing tutorials on that? I explicitly was very clear about the problem: Why is HttpClient.execute(...)already fetching the whole content and storing it in memory instead of providing a proper ÌnputStreamto me? Please don't post any beginner tutorials on how to load aBitmap`from a URL...

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  • How to detect invalid image URL with JAVA?

    - by Cataclysm
    I have a method to download image from URL. As like below.. public static byte[] downloadImageFromURL(final String strUrl) { InputStream in; ByteArrayOutputStream out = new ByteArrayOutputStream(); try { URL url = new URL(strUrl); in = new BufferedInputStream(url.openStream()); byte[] buf = new byte[2048]; int n = 0; while (-1 != (n = in.read(buf))) { out.write(buf, 0, n); } out.close(); in.close(); } catch (IOException e) { return null; } return out.toByteArray(); } I have an image url and it is valid. for example. https://encrypted-tbn1.gstatic.com/images?q=tbn:ANd9GcTxfYM-hnD-Z80tgWdIgQKchKe-MXVUfTpCw1R5KkfJlbRbgr3Zcg My problem is I don't want to download if image is really not exists.Like .... https://encrypted-tbn1.gstatic.com/images?q=tbn:ANd9GcTxfYM-hnD-Z80tgWdIgQKchKe-MXVUfTpCw1R5KkfJlbRbgr3Zcgaaaaabbbbdddddddddddddddddddddddddddd This image shouldn't be download by my method. So , how can I know the giving image URL is not really exists. I don't want to validate my URL (I think that may not my solution ). So, I googled for that. From this article ... How to check if a URL exists or returns 404 with Java? and Java check if file exists on remote server using its url But this con.getResponseCode() will always return status code "200". This mean my method will also download invalid image urls. So , I output my bufferStream as like... System.out.println(in.read(buf)); Invalid image URL produces "43". So , I add these lines of codes in my method. if (in.read(buf) == 43) { return null; } It is ok. But I don't think that will always satisfy. Has another way to get it ? am I right? I would really appreciate any suggestions. This problem may struct my head. Thanks for reading my question.

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  • Using the HTML5 &lt;input type=&quot;file&quot; multiple=&quot;multiple&quot;&gt; Tag in ASP.NET

    - by Rick Strahl
    Per HTML5 spec the <input type="file" /> tag allows for multiple files to be picked from a single File upload button. This is actually a very subtle change that's very useful as it makes it much easier to send multiple files to the server without using complex uploader controls. Please understand though, that even though you can send multiple files using the <input type="file" /> tag, the process of how those files are sent hasn't really changed - there's still no progress information or other hooks that allow you to automatically make for a nicer upload experience without additional libraries or code. For that you will still need some sort of library (I'll post an example in my next blog post using plUpload). All the new features allow for is to make it easier to select multiple images from disk in one operation. Where you might have required many file upload controls before to upload several files, one File control can potentially do the job. How it works To create a file input box that allows with multiple file support you can simply do:<form method="post" enctype="multipart/form-data"> <label>Upload Images:</label> <input type="file" multiple="multiple" name="File1" id="File1" accept="image/*" /> <hr /> <input type="submit" id="btnUpload" value="Upload Images" /> </form> Now when the file open dialog pops up - depending on the browser and whether the browser supports it - you can pick multiple files. Here I'm using Firefox using the thumbnail preview I can easily pick images to upload on a form: Note that I can select multiple images in the dialog all of which get stored in the file textbox. The UI for this can be different in some browsers. For example Chrome displays 3 files selected as text next to the Browse… button when I choose three rather than showing any files in the textbox. Most other browsers display the standard file input box and display the multiple filenames as a comma delimited list in the textbox. Note that you can also specify the accept attribute in the <input> tag, which specifies a mime-type to specify what type of content to allow.Here I'm only allowing images (image/*) and the browser complies by just showing me image files to display. Likewise I could use text/* for all text formats registered on the machine or text/xml to only show XML files (which would include xml,xst,xsd etc.). Capturing Files on the Server with ASP.NET When you upload files to an ASP.NET server there are a couple of things to be aware of. When multiple files are uploaded from a single file control, they are assigned the same name. In other words if I select 3 files to upload on the File1 control shown above I get three file form variables named File1. This means I can't easily retrieve files by their name:HttpPostedFileBase file = Request.Files["File1"]; because there will be multiple files for a given name. The above only selects the first file. Instead you can only reliably retrieve files by their index. Below is an example I use in app to capture a number of images uploaded and store them into a database using a business object and EF 4.2.for (int i = 0; i < Request.Files.Count; i++) { HttpPostedFileBase file = Request.Files[i]; if (file.ContentLength == 0) continue; if (file.ContentLength > App.Configuration.MaxImageUploadSize) { ErrorDisplay.ShowError("File " + file.FileName + " is too large. Max upload size is: " + App.Configuration.MaxImageUploadSize); return View("UploadClassic",model); } var image = new ClassifiedsBusiness.Image(); var ms = new MemoryStream(16498); file.InputStream.CopyTo(ms); image.Entered = DateTime.Now; image.EntryId = model.Entry.Id; image.ContentType = "image/jpeg"; image.ImageData = ms.ToArray(); ms.Seek(0, SeekOrigin.Begin); // resize image if necessary and turn into jpeg Bitmap bmp = Imaging.ResizeImage(ms.ToArray(), App.Configuration.MaxImageWidth, App.Configuration.MaxImageHeight); ms.Close(); ms = new MemoryStream(); bmp.Save(ms,ImageFormat.Jpeg); image.ImageData = ms.ToArray(); bmp.Dispose(); ms.Close(); model.Entry.Images.Add(image); } This works great and also allows you to capture input from multiple input controls if you are dealing with browsers that don't support multiple file selections in the file upload control. The important thing here is that I iterate over the files by index, rather than using a foreach loop over the Request.Files collection. The files collection returns key name strings, rather than the actual files (who thought that was good idea at Microsoft?), and so that isn't going to work since you end up getting multiple keys with the same name. Instead a plain for loop has to be used to loop over all files. Another Option in ASP.NET MVC If you're using ASP.NET MVC you can use the code above as well, but you have yet another option to capture multiple uploaded files by using a parameter for your post action method.public ActionResult Save(HttpPostedFileBase[] file1) { foreach (var file in file1) { if (file.ContentLength < 0) continue; // do something with the file }} Note that in order for this to work you have to specify each posted file variable individually in the parameter list. This works great if you have a single file upload to deal with. You can also pass this in addition to your main model to separate out a ViewModel and a set of uploaded files:public ActionResult Edit(EntryViewModel model,HttpPostedFileBase[] uploadedFile) You can also make the uploaded files part of the ViewModel itself - just make sure you use the appropriate naming for the variable name in the HTML document (since there's Html.FileFor() extension). Browser Support You knew this was coming, right? The feature is really nice, but unfortunately not supported universally yet. Once again Internet Explorer is the problem: No shipping version of Internet Explorer supports multiple file uploads. IE10 supposedly will, but even IE9 does not. All other major browsers - Chrome, Firefox, Safari and Opera - support multi-file uploads in their latest versions. So how can you handle this? If you need to provide multiple file uploads you can simply add multiple file selection boxes and let people either select multiple files with a single upload file box or use multiples. Alternately you can do some browser detection and if IE is used simply show the extra file upload boxes. It's not ideal, but either one of these approaches makes life easier for folks that use a decent browser and leaves you with a functional interface for those that don't. Here's a UI I recently built as an alternate uploader with multiple file upload buttons: I say this is my 'alternate' uploader - for my primary uploader I continue to use an add-in solution. Specifically I use plUpload and I'll discuss how that's implemented in my next post. Although I think that plUpload (and many of the other packaged JavaScript upload solutions) are a better choice especially for large uploads, for simple one file uploads input boxes work well enough. The advantage of this solution is that it's very easy to handle on the server side. Any of the JavaScript controls require special handling for uploads which I'll also discuss in my next post.© Rick Strahl, West Wind Technologies, 2005-2012Posted in HTML5  ASP.NET  MVC   Tweet !function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="//platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs"); (function() { var po = document.createElement('script'); po.type = 'text/javascript'; po.async = true; po.src = 'https://apis.google.com/js/plusone.js'; var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(po, s); })();

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  • How to use Azure storage for uploading and displaying pictures.

    - by Magnus Karlsson
    Basic set up of Azure storage for local development and production. This is a somewhat completion of the following guide from http://www.windowsazure.com/en-us/develop/net/how-to-guides/blob-storage/ that also involves a practical example that I believe is commonly used, i.e. upload and present an image from a user.   First we set up for local storage and then we configure for them to work on a web role. Steps: 1. Configure connection string locally. 2. Configure model, controllers and razor views.   1. Setup connectionsstring 1.1 Right click your web role and choose “Properties”. 1.2 Click Settings. 1.3 Add setting. 1.4 Name your setting. This will be the name of the connectionstring. 1.5 Click the ellipsis to the right. (the ellipsis appear when you mark the area. 1.6 The following window appears- Select “Windows Azure storage emulator” and click ok.   Now we have a connection string to use. To be able to use it we need to make sure we have windows azure tools for storage. 2.1 Click Tools –> Library Package manager –> Manage Nuget packages for solution. 2.2 This is what it looks like after it has been added.   Now on to what the code should look like. 3.1 First we need a view which collects images to upload. Here Index.cshtml. 1: @model List<string> 2:  3: @{ 4: ViewBag.Title = "Index"; 5: } 6:  7: <h2>Index</h2> 8: <form action="@Url.Action("Upload")" method="post" enctype="multipart/form-data"> 9:  10: <label for="file">Filename:</label> 11: <input type="file" name="file" id="file1" /> 12: <br /> 13: <label for="file">Filename:</label> 14: <input type="file" name="file" id="file2" /> 15: <br /> 16: <label for="file">Filename:</label> 17: <input type="file" name="file" id="file3" /> 18: <br /> 19: <label for="file">Filename:</label> 20: <input type="file" name="file" id="file4" /> 21: <br /> 22: <input type="submit" value="Submit" /> 23: 24: </form> 25:  26: @foreach (var item in Model) { 27:  28: <img src="@item" alt="Alternate text"/> 29: } 3.2 We need a controller to receive the post. Notice the “containername” string I send to the blobhandler. I use this as a folder for the pictures for each user. If this is not a requirement you could just call it container or anything with small characters directly when creating the container. 1: public ActionResult Upload(IEnumerable<HttpPostedFileBase> file) 2: { 3: BlobHandler bh = new BlobHandler("containername"); 4: bh.Upload(file); 5: var blobUris=bh.GetBlobs(); 6: 7: return RedirectToAction("Index",blobUris); 8: } 3.3 The handler model. I’ll let the comments speak for themselves. 1: public class BlobHandler 2: { 3: // Retrieve storage account from connection string. 4: CloudStorageAccount storageAccount = CloudStorageAccount.Parse( 5: CloudConfigurationManager.GetSetting("StorageConnectionString")); 6: 7: private string imageDirecoryUrl; 8: 9: /// <summary> 10: /// Receives the users Id for where the pictures are and creates 11: /// a blob storage with that name if it does not exist. 12: /// </summary> 13: /// <param name="imageDirecoryUrl"></param> 14: public BlobHandler(string imageDirecoryUrl) 15: { 16: this.imageDirecoryUrl = imageDirecoryUrl; 17: // Create the blob client. 18: CloudBlobClient blobClient = storageAccount.CreateCloudBlobClient(); 19: 20: // Retrieve a reference to a container. 21: CloudBlobContainer container = blobClient.GetContainerReference(imageDirecoryUrl); 22: 23: // Create the container if it doesn't already exist. 24: container.CreateIfNotExists(); 25: 26: //Make available to everyone 27: container.SetPermissions( 28: new BlobContainerPermissions 29: { 30: PublicAccess = BlobContainerPublicAccessType.Blob 31: }); 32: } 33: 34: public void Upload(IEnumerable<HttpPostedFileBase> file) 35: { 36: // Create the blob client. 37: CloudBlobClient blobClient = storageAccount.CreateCloudBlobClient(); 38: 39: // Retrieve a reference to a container. 40: CloudBlobContainer container = blobClient.GetContainerReference(imageDirecoryUrl); 41: 42: if (file != null) 43: { 44: foreach (var f in file) 45: { 46: if (f != null) 47: { 48: CloudBlockBlob blockBlob = container.GetBlockBlobReference(f.FileName); 49: blockBlob.UploadFromStream(f.InputStream); 50: } 51: } 52: } 53: } 54: 55: public List<string> GetBlobs() 56: { 57: // Create the blob client. 58: CloudBlobClient blobClient = storageAccount.CreateCloudBlobClient(); 59: 60: // Retrieve reference to a previously created container. 61: CloudBlobContainer container = blobClient.GetContainerReference(imageDirecoryUrl); 62: 63: List<string> blobs = new List<string>(); 64: 65: // Loop over blobs within the container and output the URI to each of them 66: foreach (var blobItem in container.ListBlobs()) 67: blobs.Add(blobItem.Uri.ToString()); 68: 69: return blobs; 70: } 71: } 3.4 So, when the files have been uploaded we will get them to present them to out user in the index page. Pretty straight forward. In this example we only present the image by sending the Uri’s to the view. A better way would be to save them up in a view model containing URI, metadata, alternate text, and other relevant information but for this example this is all we need.   4. Now press F5 in your solution to try it out. You can see the storage emulator UI here:     4.1 If you get any exceptions or errors I suggest to first check if the service Is running correctly. I had problem with this and they seemed related to the installation and a reboot fixed my problems.     5. Set up for Cloud storage. To do this we need to add configuration for cloud just as we did for local in step one. 5.1 We need our keys to do this. Go to the windows Azure menagement portal, select storage icon to the right and click “Manage keys”. (Image from a different blog post though).   5.2 Do as in step 1.but replace step 1.6 with: 1.6 Choose “Manually entered credentials”. Enter your account name. 1.7 Paste your Account Key from step 5.1. and click ok.   5.3. Save, publish and run! Please feel free to ask any questions using the comments form at the bottom of this page. I will get back to you to help you solve any questions. Our consultancy agency also provides services in the Nordic regions if you would like any further support.

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  • Adding multiple data importers support to web applications

    - by DigiMortal
    I’m building web application for customer and there is requirement that users must be able to import data in different formats. Today we will support XLSX and ODF as import formats and some other formats are waiting. I wanted to be able to add new importers on the fly so I don’t have to deploy web application again when I add new importer or change some existing one. In this posting I will show you how to build generic importers support to your web application. Importer interface All importers we use must have something in common so we can easily detect them. To keep things simple I will use interface here. public interface IMyImporter {     string[] SupportedFileExtensions { get; }     ImportResult Import(Stream fileStream, string fileExtension); } Our interface has the following members: SupportedFileExtensions – string array of file extensions that importer supports. This property helps us find out what import formats are available and which importer to use with given format. Import – method that does the actual importing work. Besides file we give in as stream we also give file extension so importer can decide how to handle the file. It is enough to get started. When building real importers I am sure you will switch over to abstract base class. Importer class Here is sample importer that imports data from Excel and Word documents. Importer class with no implementation details looks like this: public class MyOpenXmlImporter : IMyImporter {     public string[] SupportedFileExtensions     {         get { return new[] { "xlsx", "docx" }; }     }     public ImportResult Import(Stream fileStream, string extension)     {         // ...     } } Finding supported import formats in web application Now we have importers created and it’s time to add them to web application. Usually we have one page or ASP.NET MVC controller where we need importers. To this page or controller we add the following method that uses reflection to find all classes that implement our IMyImporter interface. private static string[] GetImporterFileExtensions() {     var types = from a in AppDomain.CurrentDomain.GetAssemblies()                 from t in a.GetTypes()                 where t.GetInterfaces().Contains(typeof(IMyImporter))                 select t;       var extensions = new Collection<string>();     foreach (var type in types)     {         var instance = (IMyImporter)type.InvokeMember(null,                        BindingFlags.CreateInstance, null, null, null);           foreach (var extension in instance.SupportedFileExtensions)         {             if (extensions.Contains(extension))                 continue;               extensions.Add(extension);         }     }       return extensions.ToArray(); } This code doesn’t look nice and is far from optimal but it works for us now. It is possible to improve performance of web application if we cache extensions and their corresponding types to some static dictionary. We have to fill it only once because our application is restarted when something changes in bin folder. Finding importer by extension When user uploads file we need to detect the extension of file and find the importer that supports given extension. We add another method to our page or controller that uses reflection to return us importer instance or null if extension is not supported. private static IMyImporter GetImporterForExtension(string extensionToFind) {     var types = from a in AppDomain.CurrentDomain.GetAssemblies()                 from t in a.GetTypes()                 where t.GetInterfaces().Contains(typeof(IMyImporter))                 select t;     foreach (var type in types)     {         var instance = (IMyImporter)type.InvokeMember(null,                        BindingFlags.CreateInstance, null, null, null);           if (instance.SupportedFileExtensions.Contains(extensionToFind))         {             return instance;         }     }       return null; } Here is example ASP.NET MVC controller action that accepts uploaded file, finds importer that can handle file and imports data. Again, this is sample code I kept minimal to better illustrate how things work. public ActionResult Import(MyImporterModel model) {     var file = Request.Files[0];     var extension = Path.GetExtension(file.FileName).ToLower();     var importer = GetImporterForExtension(extension.Substring(1));     var result = importer.Import(file.InputStream, extension);     if (result.Errors.Count > 0)     {         foreach (var error in result.Errors)             ModelState.AddModelError("file", error);           return Import();     }     return RedirectToAction("Index"); } Conclusion That’s it. Using couple of ugly methods and one simple interface we were able to add importers support to our web application. Example code here is not perfect but it works. It is possible to cache mappings between file extensions and importer types to some static variable because changing of these mappings means that something is changed in bin folder of web application and web application is restarted in this case anyway.

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  • Image Preview in ASP.NET MVC

    - by imran_ku07
      Introduction :         Previewing an image is a great way to improve the UI of your site. Also it is always best to check the file type, size and see a preview before submitting the whole form. There are some ways to do this using simple JavaScript but not work in all browsers (like FF3).In this Article I will show you how do this using ASP.NET MVC application. You also see how this will work in case of nested form.   Description :          Create a new ASP.NET MVC project and then add a file upload and image control into your View. <form id="form1" method="post" action="NerdDinner/ImagePreview/AjaxSubmit">            <table>                <tr>                    <td>                        <input type="file" name="imageLoad1" id="imageLoad1"  onchange="ChangeImage(this,'#imgThumbnail')" />                    </td>                </tr>                <tr>                    <td align="center">                        <img src="images/TempImage.gif" id="imgThumbnail" height="200px" width="200px">                     </td>                </tr>            </table>        </form>           Note that here NerdDinner is refers to the virtual directory name, ImagePreview is the Controller and ImageLoad is the action name which you will see shortly          I will use the most popular jQuery form plug-in, that turns a form into an AJAX form with very little code. Therefore you must get these from Jquery site and then add these files into your page.          <script src="NerdDinner/Scripts/jquery-1.3.2.js" type="text/javascript"></script>        <script src="NerdDinner/Scripts/jquery.form.js" type="text/javascript"></script>            Then add the javascript function. <script type="text/javascript">function ChangeImage(fileId,imageId){ $("#form1").ajaxSubmit({success: function(responseText){ var d=new Date(); $(imageId)[0].src="NerdDinner/ImagePreview/ImageLoad?a="+d.getTime(); } });}</script>             This function simply submit the form named form1 asynchronously to ImagePreviewController's method AjaxSubmit and after successfully receiving the response, it will set the image src property to the action method ImageLoad. Here I am also adding querystring, preventing the browser to serve the cached image.           Now I will create a new Controller named ImagePreviewController. public class ImagePreviewController : Controller { [AcceptVerbs(HttpVerbs.Post)] public ActionResult AjaxSubmit(int? id) { Session["ContentLength"] = Request.Files[0].ContentLength; Session["ContentType"] = Request.Files[0].ContentType; byte[] b = new byte[Request.Files[0].ContentLength]; Request.Files[0].InputStream.Read(b, 0, Request.Files[0].ContentLength); Session["ContentStream"] = b; return Content( Request.Files[0].ContentType+";"+ Request.Files[0].ContentLength ); } public ActionResult ImageLoad(int? id) { byte[] b = (byte[])Session["ContentStream"]; int length = (int)Session["ContentLength"]; string type = (string)Session["ContentType"]; Response.Buffer = true; Response.Charset = ""; Response.Cache.SetCacheability(HttpCacheability.NoCache); Response.ContentType = type; Response.BinaryWrite(b); Response.Flush(); Session["ContentLength"] = null; Session["ContentType"] = null; Session["ContentStream"] = null; Response.End(); return Content(""); } }             The AjaxSubmit action method will save the image in Session and return content type and content length in response. ImageLoad action method will return the contents of image in response.Then clear these Sessions.           Just run your application and see the effect.   Checking Size and Content Type of File:          You may notice that AjaxSubmit action method is returning both content type and content length. You can check both properties before submitting your complete form.     $(myform).ajaxSubmit({success: function(responseText)            {                                var contentType=responseText.substring(0,responseText.indexOf(';'));                var contentLength=responseText.substring(responseText.indexOf(';')+1);                // Here you can do your validation                var d=new Date();                $(imageId)[0].src="http://weblogs.asp.net/MoneypingAPP/ImagePreview/ImageLoad?a="+d.getTime();            }        });  Handling Nested Form Case:          The above code will work if you have only one form. But this is not the case always.You may have a form control which wraps all the controls and you do not want to submit the whole form, just for getting a preview effect.           In this case you need to create a dynamic form control using JavaScript, and then add file upload control to this form and submit the form asynchronously  function ChangeImage(fileId,imageId)         {            var myform=document.createElement("form");                    myform.action="NerdDinner/ImagePreview/AjaxSubmit";            myform.enctype="multipart/form-data";            myform.method="post";            var imageLoad=document.getElementById(fileId).cloneNode(true);            myform.appendChild(imageLoad);            document.body.appendChild(myform);            $(myform).ajaxSubmit({success: function(responseText)                {                                    var contentType=responseText.substring(0,responseText.indexOf(';'));                    var contentLength=responseText.substring(responseText.indexOf(';')+1);                    var d=new Date();                    $(imageId)[0].src="http://weblogs.asp.net/MoneypingAPP/ImagePreview/ImageLoad?a="+d.getTime();                    document.body.removeChild(myform);                }            });        }            You also need append the child in order to send request and remove them after receiving response.

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  • Launching Intent.ACTION_VIEW intent not working on saved image file

    - by Savvas Dalkitsis
    First of all let me say that this questions is slightly connected to another question by me. Actually it was created because of that. I have the following code to write a bitmap downloaded from the net to a file in the sd card: // Get image from url URL u = new URL(url); HttpGet httpRequest = new HttpGet(u.toURI()); HttpClient httpclient = new DefaultHttpClient(); HttpResponse response = (HttpResponse) httpclient.execute(httpRequest); HttpEntity entity = response.getEntity(); BufferedHttpEntity bufHttpEntity = new BufferedHttpEntity(entity); InputStream instream = bufHttpEntity.getContent(); Bitmap bmImg = BitmapFactory.decodeStream(instream); instream.close(); // Write image to a file in sd card File posterFile = new File(Environment.getExternalStorageDirectory().getAbsolutePath()+"/Android/data/com.myapp/files/image.jpg"); posterFile.createNewFile(); BufferedOutputStream out = new BufferedOutputStream(new FileOutputStream(posterFile)); Bitmap mutable = Bitmap.createScaledBitmap(bmImg,bmImg.getWidth(),bmImg.getHeight(),true); mutable.compress(Bitmap.CompressFormat.JPEG, 100, out); out.flush(); out.close(); // Launch default viewer for the file Intent intent = new Intent(); intent.setAction(android.content.Intent.ACTION_VIEW); intent.setDataAndType(Uri.parse(posterFile.getAbsolutePath()),"image/*"); ((Activity) getContext()).startActivity(intent); A few notes. I am creating the "mutable" bitmap after seeing someone using it and it seems to work better than without it. And i am using the parse method on the Uri class and not the fromFile because in my code i am calling these in different places and when i am creating the intent i have a string path instead of a file. Now for my problem. The file gets created. The intent launches a dialog asking me to select a viewer. I have 3 viewers installed. The Astro image viewer, the default media gallery (i have a milstone on 2.1 but on the milestone the 2.1 update did not include the 3d gallery so it's the old one) and the 3d gallery from the nexus one (i found the apk in the wild). Now when i launch the 3 viewers the following happen: Astro image viewer: The activity launches but i see nothing but a black screen. Media Gallery: i get an exception dialog shown "The application Media Gallery (process com.motorola.gallery) has stopped unexpectedly. Please try again" with a force close option. 3D gallery: Everything works as it should. When i try to simply open the file using the Astro file manager (browse to it and simply click) i get the same option dialog but this time things are different: Astro image viewer: Everything works as it should. Media Gallery: Everything works as it should. 3D gallery: The activity launches but i see nothing but a black screen. As you can see everything is a complete mess. I have no idea why this happens but it happens like this every single time. It's not a random bug. Am i missing something when i am creating the intent? Or when i am creating the image file? Any ideas?

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  • asp.net image aspect ratio help

    - by StealthRT
    Hey all, i am in need of some help with keeping an image aspect ratio in check. This is the aspx code that i have to resize and upload an image the user selects. <%@ Page Trace="False" Language="vb" aspcompat="false" debug="true" validateRequest="false"%> <%@ Import Namespace=System.Drawing %> <%@ Import Namespace=System.Drawing.Imaging %> <%@ Import Namespace=System %> <%@ Import Namespace=System.Web %> <SCRIPT LANGUAGE="VBScript" runat="server"> const Lx = 500 ' max width for thumbnails const Ly = 60 ' max height for thumbnails const upload_dir = "/uptest/" ' directory to upload file const upload_original = "sample" ' filename to save original as (suffix added by script) const upload_thumb = "thumb" ' filename to save thumbnail as (suffix added by script) const upload_max_size = 512 ' max size of the upload (KB) note: this doesn't override any server upload limits dim fileExt ' used to store the file extension (saves finding it mulitple times) dim newWidth, newHeight as integer ' new width/height for the thumbnail dim l2 ' temp variable used when calculating new size dim fileFld as HTTPPostedFile ' used to grab the file upload from the form Dim originalimg As System.Drawing.Image ' used to hold the original image dim msg ' display results dim upload_ok as boolean ' did the upload work ? </script> <% randomize() ' used to help the cache-busting on the preview images upload_ok = false if lcase(Request.ServerVariables("REQUEST_METHOD"))="post" then fileFld = request.files(0) ' get the first file uploaded from the form (note:- you can use this to itterate through more than one image) if fileFld.ContentLength > upload_max_size * 1024 then msg = "Sorry, the image must be less than " & upload_max_size & "Kb" else try originalImg = System.Drawing.Image.FromStream(fileFld.InputStream) ' work out the width/height for the thumbnail. Preserve aspect ratio and honour max width/height ' Note: if the original is smaller than the thumbnail size it will be scaled up If (originalImg.Width/Lx) > (originalImg.Width/Ly) Then L2 = originalImg.Width newWidth = Lx newHeight = originalImg.Height * (Lx / L2) if newHeight > Ly then newWidth = newWidth * (Ly / newHeight) newHeight = Ly end if Else L2 = originalImg.Height newHeight = Ly newWidth = originalImg.Width * (Ly / L2) if newWidth > Lx then newHeight = newHeight * (Lx / newWidth) newWidth = Lx end if End If Dim thumb As New Bitmap(newWidth, newHeight) 'Create a graphics object Dim gr_dest As Graphics = Graphics.FromImage(thumb) ' just in case it's a transparent GIF force the bg to white dim sb = new SolidBrush(System.Drawing.Color.White) gr_dest.FillRectangle(sb, 0, 0, thumb.Width, thumb.Height) 'Re-draw the image to the specified height and width gr_dest.DrawImage(originalImg, 0, 0, thumb.Width, thumb.Height) try fileExt = System.IO.Path.GetExtension(fileFld.FileName).ToLower() originalImg.save(Server.MapPath(upload_dir & upload_original & fileExt), originalImg.rawformat) thumb.save(Server.MapPath(upload_dir & upload_thumb & fileExt), originalImg.rawformat) msg = "Uploaded " & fileFld.FileName & " to " & Server.MapPath(upload_dir & upload_original & fileExt) upload_ok = true catch msg = "Sorry, there was a problem saving the image." end try ' Housekeeping for the generated thumbnail if not thumb is nothing then thumb.Dispose() thumb = nothing end if catch msg = "Sorry, that was not an image we could process." end try end if ' House Keeping ! if not originalImg is nothing then originalImg.Dispose() originalImg = nothing end if end if %> What i am looking for is a way to just have it go by the height of what i set it: const Ly = 60 ' max height for thumbnails And have the code for the width just be whatever. So if i had an image... say 600 x 120 (w h) and i used photoshop to change just the height, it would keep it in ratio and have it 300 x 60 (w x h). Thats what i am looking to do with this code here. However, i can not think of a way to do this (or to just leave a wildcard for the width setting. Any help would be great :o) David

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  • android - Caused by: android.view.ViewRootImpl$CalledFromWrongThreadException

    - by chinna_82
    Im trying to get image from my URL and display in application but it throw error Caused by: android.view.ViewRootImpl$CalledFromWrongThreadException: Only the original thread that created a view hierarchy can touch its views. Below is my code Code package com.smartag.bird.dev; public class MainActivity extends Activity { static String ndefMsg = null; static String ndefMsg1 = null; NfcAdapter mNfcAdapter; PendingIntent mNfcPendingIntent; IntentFilter[] mNdefExchangeFilters; static final String TAG = "Read Tag"; TextView mTitle; private static ImageView imageView; static String url = "http://sposter.smartag.my/images/chicken_soup.jpg"; private static Bitmap downloadBitmap; private static BitmapDrawable bitmapDrawable; private static boolean largerImg = false; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); //setContentView(R.layout.main); mNfcAdapter = NfcAdapter.getDefaultAdapter(this); mNfcPendingIntent = PendingIntent.getActivity(this, 0, new Intent(this, getClass()).addFlags(Intent.FLAG_ACTIVITY_SINGLE_TOP), 0); IntentFilter ndefDetected = new IntentFilter(NfcAdapter.ACTION_NDEF_DISCOVERED); try { ndefDetected.addDataType("text/plain"); } catch (MalformedMimeTypeException e) { } mNdefExchangeFilters = new IntentFilter[] { ndefDetected }; if (NfcAdapter.ACTION_NDEF_DISCOVERED.equals(getIntent().getAction())) { NdefMessage[] messages = getNdefMessages(getIntent()); byte[] payload = messages[0].getRecords()[0].getPayload(); ndefMsg = new String(payload); setIntent(new Intent()); // Consume this intent. } ConnectivityManager connManager = (ConnectivityManager) getSystemService(CONNECTIVITY_SERVICE); NetworkInfo mWifi = connManager.getNetworkInfo(ConnectivityManager.TYPE_WIFI); if(ndefMsg == null || ndefMsg.length() == 0) { startActivity(new Intent(MainActivity.this, MainMenu.class)); } else { setContentView(R.layout.main); if (mWifi.isConnected()) { ndefMsg1 = ndefMsg; new DownloadFilesTask().execute(); ndefMsg = null; } else { AlertDialog.Builder dialog = new AlertDialog.Builder(this); dialog.setTitle("Attention"); dialog.setMessage("No Internet Connection. Please enable the wifi."); dialog.setPositiveButton("OK", new DialogInterface.OnClickListener() { public void onClick(DialogInterface dialog, int whichButton) { } }); dialog.show(); } } } private class DownloadFilesTask extends AsyncTask<Void, Void, Void> { protected void onPostExecute(Void result) { } @Override protected Void doInBackground(Void... params) { try { URL myFileUrl = new URL("http://sposter.smartag.my/images/chicken_soup.jpg"); HttpURLConnection conn= (HttpURLConnection)myFileUrl.openConnection(); conn.setDoInput(true); conn.connect(); InputStream is = conn.getInputStream(); downloadBitmap = BitmapFactory.decodeStream(is); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } ImageView image = (ImageView) findViewById(R.id.imview); image.setImageBitmap(downloadBitmap); return null; } } }

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  • Problem simulating HTTP POST using HttpClient

    - by user560904
    I am trying to programatically send a HTTP Post request using HttpClient to http://ojp.nationalrail.co.uk/en/s/planjourney/query but it is not liking the request I send it. I copied the headers and body from what Chrome browser sends so it is identical but it doesn't like what I send as the HTML mentions there's an error. <div class="padding"> <h1 class="sifr"><strong>Sorry</strong>, something went wrong</h1> <div class="error-message"> <div class="error-message-padding"> <h2>There is a problem with the page you are trying to access.</h2> <p>It is possible that it was either moved, it doesn't exist or we are experiencing some technical difficulties.</p> <p>We are sorry for the inconvenience.</p> </div> </div> </div> Here is my Java program which uses HttpClient: package com.tixsnif; import org.apache.http.*; import org.apache.http.client.HttpClient; import org.apache.http.client.entity.UrlEncodedFormEntity; import org.apache.http.client.methods.HttpPost; import org.apache.http.impl.client.DefaultHttpClient; import org.apache.http.message.BasicNameValuePair; import org.apache.http.protocol.HTTP; import java.io.*; import java.util.*; import java.util.zip.GZIPInputStream; public class WebScrapingTesting { public static void main(String[] args) throws Exception { String target = "http://ojp.nationalrail.co.uk/en/s/planjourney/query"; HttpClient client = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(target); BasicNameValuePair[] params = { new BasicNameValuePair("jpState", "single"), new BasicNameValuePair("commandName", "journeyPlannerCommand"), new BasicNameValuePair("from.searchTerm", "Basingstoke"), new BasicNameValuePair("to.searchTerm", "Reading"), new BasicNameValuePair("timeOfOutwardJourney.arrivalOrDeparture", "DEPART"), new BasicNameValuePair("timeOfOutwardJourney.monthDay", "Today"), new BasicNameValuePair("timeOfOutwardJourney.hour", "10"), new BasicNameValuePair("timeOfOutwardJourney.minute", "15"), new BasicNameValuePair("timeOfReturnJourney.arrivalOrDeparture", "DEPART"), new BasicNameValuePair("timeOfReturnJourney.monthDay", "Today"), new BasicNameValuePair("timeOfReturnJourney.hour", "18"), new BasicNameValuePair("timeOfReturnJourney.minute", "15"), new BasicNameValuePair("_includeOvertakenTrains", "on"), new BasicNameValuePair("viaMode", "VIA"), new BasicNameValuePair("via.searchTerm", "Station name / code"), new BasicNameValuePair("offSetOption", "0"), new BasicNameValuePair("_reduceTransfers", "on"), new BasicNameValuePair("operatorMode", "SHOW"), new BasicNameValuePair("operator.code", ""), new BasicNameValuePair("_lookForSleeper", "on"), new BasicNameValuePair("_directTrains", "on")}; httpPost.setHeader("Host", "ojp.nationalrail.co.uk"); httpPost.setHeader("User-Agent", "Mozilla/5.0 (Macintosh; U; Intel Mac OS X 10_6_4; en-US) AppleWebKit/534.10 (KHTML, like Gecko) Chrome/8.0.552.231 Safari/534.10"); httpPost.setHeader("Accept-Encoding", "gzip,deflate,sdch"); httpPost.setHeader("Accept", "text/html,application/xhtml+xml,application/xml;q=0.9,**/*//*;q=0.8"); httpPost.setHeader("Accept-Language", "en-us,en;q=0.8"); httpPost.setHeader("Accept-Charset", "ISO-8859-1,utf-8;q=0.7,*;q=0.7"); httpPost.setHeader("Origin", "http://www.nationalrail.co.uk/"); httpPost.setHeader("Referer", "http://www.nationalrail.co.uk/"); httpPost.setHeader("Content-Type", "application/x-www-form-urlencoded"); httpPost.setHeader("Cookie", "JSESSIONID=B2A3419B79C5D999CA4806B459675CCD.app201; Path=/"); UrlEncodedFormEntity urlEncodedFormEntity = new UrlEncodedFormEntity(Arrays.asList(params)); urlEncodedFormEntity.setContentEncoding(HTTP.UTF_8); httpPost.setEntity(urlEncodedFormEntity); HttpResponse response = client.execute(httpPost); InputStream input = response.getEntity().getContent(); GZIPInputStream gzip = new GZIPInputStream(input); InputStreamReader isr = new InputStreamReader(gzip); BufferedReader br = new BufferedReader(isr); String line = null; while((line = br.readLine()) != null) { System.out.printf("\n%s", line); } client.getConnectionManager().shutdown(); } } I keep the JSESSION ID updated if it expires but there seems to be another problem that I cannot see. Am I missing something rather obvious? He

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  • ASP.NET Send Image Attachment With Email Without Saving To Filesystem

    - by KGO
    I'm trying to create a form that will send an email with an attached image and am running into some problems. The form I am creating is rather large so I have created a small test form for the purpose of this question. The email will send and the attachment will exist on the email, but the image is corrupt or something as it is not viewable. Also.. I do not want to save the image to the filesystem. You may think it is convoluted to take the image file from the fileupload to a stream, but this is due to the fact that the real form I am working on will allow multiple files to be added through a single fileupload and will be saved in session, thus the images will not be coming from the fileupload control directly on submit. File: TestAttachSend.aspx <%@ Page Language="C#" AutoEventWireup="true" CodeFile="TestAttachSend.aspx.cs" Inherits="TestAttachSend" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title></title> </head> <body> <form id="form1" runat="server"> <div> <h1>Send Email with Image Attachment</h1> Email Address TO: <asp:TextBox ID="txtEmail" runat="server"></asp:TextBox><br /> Attach JPEG Image: <asp:FileUpload ID="fuImage" runat="server" /><br /> <br /> <asp:Button ID="btnSend" runat="server" Text="Send" onclick="btnSend_Click" /><br /> <br /> <asp:label ID="lblSent" runat="server" text="Image Sent!" Visible="false" EnableViewState="false"></asp:label> </div> </form> </body> </html> File: TestAttachSend.aspx.cs using System; using System.Collections.Generic; using System.Web; using System.Web.UI; using System.Web.UI.WebControls; using System.Net.Mail; using System.IO; public partial class TestAttachSend : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { } protected void btnSend_Click(object sender, EventArgs e) { if (fuImage.HasFile && fuImage.PostedFile.ContentType == System.Net.Mime.MediaTypeNames.Image.Jpeg) { SmtpClient emailClient = new SmtpClient(); MailMessage EmailMsg = new MailMessage(); EmailMsg.To.Add(txtEmail.Text.Trim()); EmailMsg.From = new MailAddress(txtEmail.Text.Trim()); EmailMsg.Subject = "Attached Image"; EmailMsg.Body = "Image is attached!"; MemoryStream imgStream = new MemoryStream(); System.Drawing.Image img = System.Drawing.Image.FromStream(fuImage.PostedFile.InputStream); string filename = fuImage.PostedFile.FileName; img.Save(imgStream, System.Drawing.Imaging.ImageFormat.Jpeg); EmailMsg..Attachments.Add(new Attachment(imgStream, filename, System.Net.Mime.MediaTypeNames.Image.Jpeg)); emailClient.Send(EmailMsg); lblSent.Visible = true; } } }

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  • Save blob to DB using hibernate

    - by Link123
    Hey! I tried save file to MySQL using blob with hibernate3. But I always have java.lang.UnsupportedOperationException: Blob may not be manipulated from creating session org.hibernate.lob.BlobImpl.excep(BlobImpl.java:127) Here some code. package com.uni.domain; public class File extends Identifier { private byte[] data; private String contentType; public byte[] getData() { return data; } public File() {} public void setData(byte[] photo) { this.data = photo; } public boolean isNew() { return true; } public String getContentType() { return contentType; } public void setContentType(String contentType) { this.contentType = contentType; } } package com.uni.domain; import org.hibernate.Hibernate; import org.hibernate.HibernateException; import org.hibernate.usertype.UserType; import java.io.InputStream; import java.io.OutputStream; import java.io.Serializable; import java.sql.*; import java.util.Arrays; public class PhotoType implements UserType { public int[] sqlTypes() { return new int[]{Types.BLOB}; } public Class returnedClass() { return byte[].class; } public boolean equals(Object o, Object o1) throws HibernateException { return Arrays.equals((byte[]) o, (byte[]) o1); } public int hashCode(Object o) throws HibernateException { return o.hashCode(); } public Object nullSafeGet(ResultSet resultSet, String[] strings, Object o) throws HibernateException, SQLException { Blob blob = resultSet.getBlob(strings[0]); return blob.getBytes(1, (int) blob.length()); } public void nullSafeSet(PreparedStatement st, Object value, int index) throws HibernateException, SQLException { st.setBlob(index, Hibernate.createBlob((byte[]) value)); } public Object deepCopy(Object value) { if (value == null) return null; byte[] bytes = (byte[]) value; byte[] result = new byte[bytes.length]; System.arraycopy(bytes, 0, result, 0, bytes.length); return result; } public boolean isMutable() { return true; } public Serializable disassemble(Object o) throws HibernateException { return null; . } public Object assemble(Serializable serializable, Object o) throws HibernateException { return null; . } public Object replace(Object o, Object o1, Object o2) throws HibernateException { return null; . } <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE hibernate-mapping PUBLIC "-//Hibernate/Hibernate Mapping DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-mapping-3.0.dtd"> <hibernate-mapping package="com.uni.domain"> <class name="com.uni.domain.File"> <id name="id"> <generator class="native"/> </id> <property name="data" type="com.uni.domain.FleType"/> <property name="contentType"/> </class> </hibernate-mapping> Help me please. Where I’m wrong?

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