Search Results

Search found 6690 results on 268 pages for 'resource kit'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 20/268 | < Previous Page | 16 17 18 19 20 21 22 23 24 25 26 27  | Next Page >

  • Block IPs if they access a resource

    - by Victor Oliva
    I own a server that it's costantly being attacked by scripts (that try to access to phpMyAdmin's setup file's and stuff like this). I've heard that many people get this kinds of attacks, but I'm starting to worry since they are getting more common (last month I got 2 attacks, and on november 7th there are 3 attempts already (1st, 4th and 6th of nov). I'm not really concerned about it, since I don't have any database. All the info i have on that server is absolutely public, but I'm worried about that attacking-rate increase. So I thought I could -temporarily- block the IPs that come from those attackers, or something that could make my server ignore requests that ask for phpMyAdmin, pma, xamp, etc. Is there something like that? my server is Linux+Apache+Php

    Read the article

  • Puppet exported resource naming

    - by Tim Brigham
    I am working on setting up a collection of Splunk nodes to be deployed by Puppet. One of the steps in this process is importing the trusts to allow these nodes to automatically find each other. I've looked over several options and it appears that exported resources are the only ready way to go for this to work. The files I need to create are under /opt/splunk/etc/auth/distServerKeys//trusted.pem. The source for each of these files should be /opt/splunk/etc/auth/distServerKeys/trusted.pem, one per node. What syntax do I need to make this work? The samples I've looked at all appear to have the same source and destination file name.

    Read the article

  • Resource Pool sharing in Hyper-V Virtual Machines

    - by user67905
    I understand that we can install Hyper-V on one server and run a number of Virtual Machines on it, upto the limit of resources of that server. I want to know if it is possible to install Hyper-V lumped on two or more servers, so that the Virtual Machines can use the underlying resources pool of both the servers? And also if that same is possible for an “n” number of servers, instead of just 2 servers.

    Read the article

  • Installing an exe with Powershell DSC Package resource gets return code 1619

    - by Jay Spang
    I'm trying to use Powershell DSC's Package resource to install an exe... Perforce's P4V to be specific. Here's my code: Configuration PerforceMachine { Node "SERVERNAME" { Package P4V { Ensure = "Present" Name = "Perforce Visual Components" Path = "\\nas\share\p4vinst64.exe" ProductId = '' Arguments = "/S /V/qn" # args for silent mode LogPath = "$env:ProgramData\p4v_install.log" } } } When running this, this is the error Powershell gives me: PowerShell provider MSFT_PackageResource failed to execute Set-TargetResource functionality with error message: The return code 1619 was not expected. Configuration is likely not correct + CategoryInfo : InvalidOperation: (:) [], CimException + FullyQualifiedErrorId : ProviderOperationExecutionFailure + PSComputerName : SERVERNAME According to documentation, return code 1619 means the MSI package couldn't be opened. However, when I manually log in to the machine and run "\\nas\share\p4vinst64.exe /S /V/qn", the install works flawlessly. Does anyone know why this is failing? Alternately, can anyone tell me how to troubleshoot this? I pasted all the error information I got from the terminal, my log file (p4v_install.log) is a 0 byte file, and there are no events in the event viewer. I don't know how to troubleshoot it any further! EDIT: I should note that I also tried using the File resource to copy the file locally, and then install it from there. Sadly, that met with the same result.

    Read the article

  • Cannot debug views in MVC2 project, getting "The resource cannot be found" error

    - by schefdev
    I'm running Visual Studio 2008 sp1 on Win7, with MVC2 RTM installed. I created a new MVC2 project using the wizard and am unable to debug specific pages. With webforms and even MVC1, I was able to sit on a View page, hit F5, and then have the integrated web server in VS2008 start on the page I was working on. Very handy for building up app logic. When I try this now I get a "The resource cannot be found" error page. I retried this just now with a stock new MVC2 Web Application project. Here are the steps I took after creating the new project to reproduce: Open up project settings. Under the Web subtab, set the Start Action to "Current Page". Leave all the other settings as is. Open one of the views up (e.g. Account/Register.aspx) Hit F5 to debug the project Note that the browser window which displays shows the error message "The resource cannot be found". The link I saw in my browser for this run was: http://localhost:49471/Views/Account/Register.aspx I did some googling and found suggestions related to ensuring all HTTP server pieces were installed. I double checked and made sure that "HTTP Errors" and "HTTP Redirection" were both installed. If I leave the project setting as it was originally, set to "Specific Page" with nothing in the text box, then routing works and I always get the default home page. I'm hoping this isn't the only option. Thanks!

    Read the article

  • Resource not found using library project in Android

    - by hgpc
    I'm converting an existing project into a library project. I configured the original project as a library project and added an application project which references the original project as a library. The library project has an activity (MainActivity) and its layout (main.xml). The application project declares this activity as the main activity in the manifest like this: <activity android:name="com.example.MainActivity" android:label="@string/app_name"> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> When I run the application project I get the following error... android.content.res.Resources$NotFoundException: Resource ID #0x7f030002 ...on the following line of the onCreate method of the main activity: setContentView(R.layout.main); 0x7f030002 is the ID of R.layout.main in the library project. The application project has no main resource. If I run the original project I don't get this error. Both projects neither have compilation errors nor warnings and are built with Android 2.2 with min SDK version 3. What might be the problem?

    Read the article

  • how to atomically claim a row or resource using UPDATE in mysql

    - by Igor
    i have a table of resources (lets say cars) which i want to claim atomically. if there's a limit of one resource per one user, i can do the following trick: UPDATE cars SET user = 'bob' WHERE user IS NULL LIMIT 1 SELECT * FROM cars WHERE user IS bob that way, i claim the resource atomically and then i can see which row i just claimed. this doesn't work when 'bob' can claim multiple cars. i realize i can get a list of cars already claimed by bob, claim another one, and then SELECT again to see what's changed, but that feels hackish. What I'm wondering is, is there some way to see which rows i just updated with my last UPDATE? failing that, is there some other trick to atomically claiming a row? i really want to avoid using SERIALIZABLE isolation level. If I do something like this: 1 SELECT id FROM cars WHERE user IS NULL 2 <here, my PHP or whatever picks a car id> 3 UPDATE cars SET user = 'bob' WHERE id = <the one i picked> would REPEATABLE READ be sufficient here? in other words, could i be guaranteed that some other transactions won't claim the row my software has picked during step 2?

    Read the article

  • Strange resource not found issue?

    - by xBroak
    i seem to be having a very strange problem, when the app is run on my test phone it works perfectly, and plays a sound from the raw folder via soundpool on button press, however when i submit my app to testing after building it it crashes on 120+ devices for 'Resource not found' codes below: Please also note, the file is in fact there, in both the R file, in the compiled APK file and i have also cleaned numerous times. http://www.appthwack.com/public/FUVGFZn42q '01-03 21:09:36.828 26762 26762 W System.err: java.lang.RuntimeException: Unable to start activity ComponentInfo{appinventor.ai_Broak.PaintballWiz/com.muo.paintballwiz.PaintballWiz}: android.content.res.Resources$NotFoundException: File res/raw/pballshot.ogg from drawable resource ID #0x7f050000 - 1 occurrence' soundPool = new SoundPool(4, AudioManager.STREAM_MUSIC, 100); //soundPoolMap = new SparseIntArray(); soundPoolMap = new HashMap<Integer, Integer>(); // soundPoolMap.put(soundID, soundPool.load(this, R.raw.midi_sound, 1)); int myAudioFile = getResId("pballshot", R.raw.class); soundPoolMap.put(soundID, soundPool.load(PaintballWiz.this, myAudioFile, 1)); audioManager = (AudioManager) getSystemService(Context.AUDIO_SERVICE); curVolume = audioManager .getStreamVolume(AudioManager.STREAM_MUSIC); maxVolume = audioManager .getStreamMaxVolume(AudioManager.STREAM_MUSIC); leftVolume = curVolume / maxVolume; rightVolume = curVolume / maxVolume; soundPool.play(soundID, leftVolume, rightVolume, priority, no_loop, normal_playback_rate); soundPool.play(soundID, 0, 0, 1, -1, 1f);

    Read the article

  • REST design: what verb and resource name to use for a filtering service

    - by kabaros
    I am developing a cleanup/filtering service that has a method that receives a list of objects serialized in xml, and apply some filtering rules to return a subset of those objects. In a REST-ful service, what verb shall I use for such a method? I thought that GET is a natural choice, but I have to put the serialized XML in the body of the request which works but feels incorrect. The other verbs don't seem to fit semantically. What is a good way to define that Service interface? Naming the resource /Cleanup or /Filter seems weird mainly because in the examples I see online, it is always a name rather than a verb being used for resource name. Am I right to feel that REST services are better suited for CRUD operations and you start bending the rules in situations like this service? If yes, am I then making a wrong architectural choice. I've pushed to develop this service in REST-ful style (as opposed to SOAP) for simplicity, but such awkward cases happen a lot and make me feel like I am missing something. Either choosing REST where it shouldn't be used or may be over-thinking some stuff that doesn't really matter? In that case, what really matters?

    Read the article

  • No resource found that matches given name in main.xml

    - by AndroidBeginner
    This is really starting to drive me crazy. <?xml version="1.0" encoding="utf-8"?> <TextView xmlns:android="http://schemas.android.com/apk/res/android" android:id="@id+/textview" android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="@string/hello"/> Produces the following error message: "Error: no resource found that matches the given name (at 'id' with value '@id+/textview'). This is copy and pasted from the Android hello world example.

    Read the article

  • Temporary table resource limit

    - by Jk
    Hi, i have two applications (server and client), that uses TQuery connected with TClientDataSet through TDCOMConnection, and in some cases clientdataset opens about 300000 records and than application throws exception "Temporary table resource limit". Is there any workaround how to fix this? (except "do not open such huge dataset"?) update: oops i'm sorry there is 300K records, not 3 millions..

    Read the article

  • MySQL & PHP Parameter 1 as Resource

    - by Nik
    Alright, PHP is throwing this error at me (in the log) when I run the code mentioned below: Error mysql_num_rows() expects parameter 1 to be resource, string given in (place) on line 10 Line 9-11 $queryFP = ("SELECT * FROM db"); $countFP = mysql_num_rows($queryFP); $aID = rand(1, $countFP); I think it has something to do with the $queryFP's syntax, but I'm not completely sure how to fix it since $queryFP's syntax is the simplest query I've ever seen.

    Read the article

  • Change resource file on the file

    - by Imran
    I woulld like to localize my WPF application with resource files. It good technics. But I have requirement to give ability to end user to change some localization information (for example some word traslation). It means change information in the resourse files on the fly (in run time). Is it possible ?

    Read the article

  • Change resource file on the fly

    - by Imran
    I woulld like to localize my WPF application with resource files. It good technics. But I have requirement to give ability to end user to change some localization information (for example some word traslation). It means change information in the resourse files on the fly (in run time). Is it possible ?

    Read the article

  • Cannot parse persistence unit from class path resource

    - by Grzegorz S
    so I have this problem in running my Spring WS app which implements JPA ( or should implement..) I have a problem with running a WS, it looks like my Spring context can't find file persistence.xml Which i am able to believe because i did not have generated META-INF folder in my template (which is Maven project template with archetype org.springframework.ws) I have created META-INF manually. Here is the HTTP 500: org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'caChainDao' defined in file [E:\STS\vfabric-tc-server-developer-2.7.2.RELEASE\zz\wtpwebapps\FCAWSv4\WEB-INF\classes\pl\famoc\test\ws\db\dao\caChainDao.class]: Initialization of bean failed; nested exception is org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'entityManagerFactory' defined in ServletContext resource [/WEB-INF/spring-ws-servlet.xml]: Invocation of init method failed; nested exception is java.lang.IllegalArgumentException: Cannot parse persistence unit from class path resource [persistence.xml] org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.doCreateBean(AbstractAutowireCapableBeanFactory.java:527) org.springframework.beans.factory.support.AbstractAutowireCapableBeanFactory.createBean(AbstractAutowireCapableBeanFactory.java:456) org.springframework.beans.factory.support.AbstractBeanFactory$1.getObject(AbstractBeanFactory.java:294) org.springframework.beans.factory.support.DefaultSingletonBeanRegistry.getSingleton(DefaultSingletonBeanRegistry.java:225) org.springframework.beans.factory.support.AbstractBeanFactory.doGetBean(AbstractBeanFactory.java:291) org.springframework.beans.factory.support.AbstractBeanFactory.getBean(AbstractBeanFactory.java:193) org.springframework.beans.factory.support.DefaultListableBeanFactory.preInstantiateSingletons(DefaultListableBeanFactory.java:609) org.springframework.context.support.AbstractApplicationContext.finishBeanFactoryInitialization(AbstractApplicationContext.java:918) org.springframework.context.support.AbstractApplicationContext.refresh(AbstractApplicationContext.java:469) org.springframework.web.servlet.FrameworkServlet.configureAndRefreshWebApplicationContext(FrameworkServlet.java:631) org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:588) org.springframework.web.servlet.FrameworkServlet.createWebApplicationContext(FrameworkServlet.java:645) org.springframework.web.servlet.FrameworkServlet.initWebApplicationContext(FrameworkServlet.java:508) org.springframework.web.servlet.FrameworkServlet.initServletBean(FrameworkServlet.java:449) org.springframework.web.servlet.HttpServletBean.init(HttpServletBean.java:133) javax.servlet.GenericServlet.init(GenericServlet.java:160) org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:472) org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:99) org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:929) org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:407) org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1002) org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:585) org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:310) java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1110) java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:603) java.lang.Thread.run(Thread.java:722) Here it is my persistence.xml <?xml version="1.0" encoding="UTF-8" ?> <persistence xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_2_0.xsd" version="2.0" xmlns="http://java.sun.com/xml/ns/persistence"> <persistence-unit name="persistenceUnit" transaction-type="RESOURCE_LOCAL" /> </persistence> here it is where i am looking for it <property name="persistenceXmlLocation" value="classpath:persistence.xml" /> and here it is path to this xml in my classpath: src/main/webapp/META-INF/persistence.xml Could anyone give me a hint what am i missing?

    Read the article

  • Packaging Android resource files within a distributable Jar file

    - by Jeff Gilfelt
    I am working on some reusable Android code that I would like to distribute to other developers for use within their own applications. The code has some resource dependencies (layouts, xml & png drawables) that I would like to be able to include and reference within a single package (Jar file). Is this possible, and if so what is the best method to do this?

    Read the article

  • Reading Resource Files from my own APK in Android Native Environment

    - by Kyle
    I'm porting to Android. My existing project has a ton of resource files that I'm porting into my Android project. I have them all in /res/raw/, and I would like to access those resources in my native library with functions such as fopen() and such. Can this be done, or do I have to go through JNI for this as well? I would really prefer not to, for ease of porting and possible speed and memory reasons.

    Read the article

  • Why bind hibernate SessionFactory to a JNDI resource?

    - by jschoen
    In my current adventure of learning hibernate and setting it up to use an appserver's connection pool, most examples and resources out there point you in the direction of binding the SessionFactory to a JNDI resource in your appserver in the process. I wondering what the benefit of this is? Since the you can access a the connection pool with out doing this.

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 16 17 18 19 20 21 22 23 24 25 26 27  | Next Page >