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  • Expressjs route param as variable in main app

    - by MoDFoX
    For my app I have two route set up, app.get('/', routes.index); app.get('/:name', routes.index); I would like it to be so that if I don't specify a param, say just go to appurl.com (localhost:3000), it would load a default user, but if I do specify a param(localhost:3000/user), use that as the variable "username" in the following function (placed after my routes). (function getUser(){ var body = '', username = 'WillsonSM', options = { host: 'ws.audioscrobbler.com', port: 80, path: '/2.0/?method=user.gettopartists&user=' + username + '&format=json&limit=20&api_key=APIKEYGOESHERE' }; require('http').request(options, function(res) { res.setEncoding('utf8'); res.on('data', function(chunk) { body += chunk; }); res.on('end', function() { body = JSON.parse(body); artists = body.topartists.artist; }); }).end(); })(); Along with this I have my route set up like so: exports.index = function(req, res){ res.render('index', { title: 'LasTube' }); username = req.params.name; console.log(username); }; unfortunately setting username there to req.params.name does not seem to be accessible from the main app function. My question is: How can I set expressjs/nodejs to use the parameter set via /name when available, and just use a default - in this example "WillsonSM" if not available. I've tried taking "username" out of the main app, and just leaving it in the function, but username becomes undefined, as it is inaccessible from the route, and the app will not run. I can spit out "username" via the routes console.log, so assigning it there is not an issue, but as I am new to expressjs, I am unaware of how I should go about doing this. I have tried all I can think of and find from looking around the internet. Also, if there is a better way of doing this, or I am doing something wrong, please let me know. If I've left out any information, just throw in a comment and I'll try to address it.

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  • Use jQuery.post() result in javascript function

    - by Juvlius
    I've got no clue how to do the following, so I wasn't sure what to search for either. For validating my registration form I've a javascript function that checkes the existence of the inserted username in the database onblur of the username textfield. function checkUsername(username){ $.post("checkmail.php", {mail: mailcheck} , function(data){ var $response=$(data); var response = $response.filter('#mail-response').text(); if(response == "taken") { document.getElementById('username').style.borderColor = rood; valid = false; } }); } This works fine, but now I want to validate it again onsubmit of the form in case users decide to submit an existing username. function validateForm() { var valid = true; //checks different fields //now check voor username existence var username = document.getElementById('username').value; checkUsername.call(username); if (!valid) { return false; } else { return true; } } I'm not familiar enough with Javascript to get this working. Probably thinking in the wrong direction...

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  • Why does PHP create these log entries on every page access?

    - by HXCaine
    My server's error log (in cPanel) has an entry for every single time a PHP page is loaded that looks like this (where 'username' has been substituted for my actual username): [2012-06-09 09:02:07]: info: [usr/grp]: username/username cmd: /home/username/public_html/error.php php: /usr/local/php53/bin/php I know it's only an 'info' message but it's filling up my error log. It can't be related to the content of my PHP files because it even happens when I load a page with this as its content: <?php phpinfo(); ?> Any ideas on what it means or if I can get rid of it?

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  • tomcat6 manager

    - by Bary W Pollack
    I've just installed Ubuntu 10.04 LTS Server with LAMP support. Tomcat6 seems to run ok. But, I am unable to get into the manager-webapp... I've updated the tomcat-users.xml file: <?xml version='1.0' encoding='utf-8'?> <tomcat-users> <role rolename="tomcat"/> <role rolename="role1"/> <role rolename="manager"/> <role rolename="admin"/> <user username="tomcat" password="tomcat" roles="tomcat,manager,admin"/> <user username="both" password="tomcat" roles="tomcat,role1"/> <user username="role1" password="tomcat" roles="role1"/> <user username="admin" password="admin" roles="manager,admin"/> </tomcat-users> But, no matter what I try, it keeps rejecting my username/password combo. What might I be missing?

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  • How to setup Cocos2D-X (Android) under Mac OS X?

    - by Beast
    Hi I've made a small game for iPhone that I also want to run on Android but I'm having problems setting up Cocos2D-X for Android. I've downloaded and installed Android SDK and NDK (under my "/Users/username/Android"). Installed all necessary packages under SDK and created an Emulator. Copied Cocos2D-x under "/Users/username/cocos2dx". Installed Eclipse IDE with ADT Plugin. Opened "Users/username/cocos2dx/tests/build_native.sh" and changed "NDK_ROOT_LOCAL=/Users/username/Android/android-ndk", "COCOS2DX_ROOT_LOCAL=/Users/username/cocos2dx" to the values shown. On running the script using Terminal it compiles test project. What's next?

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  • set focus in unfilled edittext how can implemented android application

    - by narasimha
    hi I am implementing one application gust i am adding validations in login page implemented then two fields required username and password button login i am applying validations then focus are not getting then set focus in unfilled edittext if(Username.contentEquals("")) { > Toast.makeText(LBS.this, "Please enter > username ",Toast.LENGTH_SHORT).show(); > } else { if( pwd.contentEquals("")) > Toast.makeText(LBS.this, "Please enter > password ",Toast.LENGTH_SHORT).show(); > else > try { ........................... } not filling username then filling password then username entered some toast displayed fine focus are entered in username edittext this is the problem how can implemented focus in unfilled username

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  • how to get data in sheet2 from sheet1 in excel

    - by romen-leung
    I have two worksheets, Sheet1 Column A = Deptname Column B = Headname Column C = Username Sheet2 Column A = Headname (???) Column B = Username Column C = UserID "Headname" column in Sheet2 is blank and what I wanted to do is to get "Headname" from Sheet1 by using "Username". I have tried to use VLookup but it did not work if username in Sheet1 and Sheet2 is not exactly same. E.G, given two differents Username as shown on below. Username in Sheet1 is "Jenny Oh" and "Chan Shu Mei" Username in Sheet2 is "ITC - Jenny Ong" and "IA: Chan Shu Mei" Any ideas whether it can be done? Thankf in advance for any help.

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  • Import SQL dump into MySQL

    - by BryanWheelock
    I'm confused how to import a SQL dump file. I can't seem to import the database without creating the database first in MySQL. This is the error displayed when database_name has not yet been created: username = username of someone with access to the database on the original server. database_name = name of database from the original server $ mysql -u username -p -h localhost database_name < dumpfile.sql Enter password: ERROR 1049 (42000): Unknown database 'database_name' If I log into MySQL as root and create the database, database_name mysql -u root create database database_name; create user username;# same username as the user from the database I got the dump from. grant all privileges on database_name.* to username@"localhost" identified by 'password'; exit mysql then attempt to import the sql dump again: $ mysql -u username -p database_name < dumpfile.sql Enter password: ERROR 1007 (HY000) at line 21: Can't create database 'database_name'; database exists How am I supposed to import the SQL dumpfile?

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  • Use of Java constructors in persistent entities

    - by Mr Morgan
    Hello I'm new to JPA and using persistence in Java anyway and I have two questions I can't quite work out: I have generated tags as: @JoinColumn(name = "UserName", referencedColumnName = "UserName") @ManyToOne(optional = false) private User userName; @JoinColumn(name = "DatasetNo", referencedColumnName = "DatasetNo") @ManyToOne(optional = false) private Dataset datasetNo; But in one of the constructors for the class, no reference is made to columns UserName or DatasetNo whereas all other columns in the class are referenced in the constructor. Can anyone tell me why this is? Both columns UserName and DatasetNo are 'foreign keys' on the entity Visualisation which corresponds to a database table of the same name. I can't quite work out the ORM. And when using entity classes, or POJO, is it better to have class variables like: private User userName; Where an instance of a class is specified or simply the key of that class instance like: private String userName; Thanks Mr Morgan.

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  • User not being saved, SharedPreferences

    - by Lars
    Hi i have a inlogscreen (inlogdialog.xml), which includes 2 EditText (username, passwd) and i have a CheckBox (saveuser) with which the user can decide weather to save the username or not. On the mainform (main.xml) i have a listner for these 3 values: private class OnReadyListener implements MyCustomForm.ReadyListener { public void ready(String user, String pass, boolean save) { username = user; password = pass; } } Now i first want to save the username through SharedPreferences but it doesn`t get saved, can someone help me please? If i check with system.out.println, the username is present in String username. SharedPreferenes code in main.xml: public static final String USERNM = ""; private SharedPreferences mPrefs; ....... @Override protected void onPause() { Editor e = mPrefs.edit(); e.putString(USERNM, username); <---- e.commit(); Toast.makeText(this, "Items saved.", Toast.LENGTH_SHORT).show(); super.onPause(); }

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  • Passing variables to functions in Python

    - by brno792
    Im writing test scripts in python for selenium web testing. How do I pass parameters through a python function to call in a later function? I first have a login test function. Then I have a new user registration function. Im trying to pass the Username and Password I use in the registration function to the testLogin function that I call inside the testRegister function. This is my python code: userName = "admin" password = "admin" #pass username and password variables to this function def testLogin(userName,password): browser = webdriver.Firefox() browser.get("http://url/login") element = browser.find_element_by_name("userName") element.send_keys(userName) element = browser.find_element_by_name("userPassword") element.send_keys(password) element.send_keys(Keys.RETURN) browser.close() # test registration def testRegister(): browser = webdriver.Firefox() browser.get("http://url/register") #new username variable newUserName = "test" element = browser.find_element_by_name("regUser") element.send_keys(newUserName) #new password variable newUserPassword = "test" element = browser.find_element_by_name("regPassword") element.send_keys(newUserPassword) # #now test if user is registered, I want to call testLogin with the test user name and pw. testLogin(newUserName,newUserPassword) browser.close()

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  • clean method for validation

    - by apoorva
    hi.. i have the following form class with corresponding clean methods... class SOFIATMUserLogin(forms.Form): Username=forms.CharField(label='Username') Password=forms.CharField(label='Password', widget=forms.PasswordInput) def clean_Username(self): user=self.cleaned_data['Username'] try: SOFIALogin.objects.get(UserName=user) except Exception: raise forms.ValidationError('Username invalid...') def clean_Password(self): upass=self.cleaned_data['Password'] In the clean_Password method i wish to check if the password entered for the valid username is correct... So i need to get the Username value... How can i access this in clean_Password method... Please assist!!!!

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  • jquery ajax form function(data)

    - by RussP
    Can some one please tell me where I have gone wrong. What ever I do I get the answer "no" JQuery to send data to php query $j.post("logincheck.php",{ username:$j('#username').attr('value'), password:$j('#password').attr('value'), rand:Math.random() } , function(data) { if(data=='yes') {alert('yes');} else {alert('no');} } ); Here is the php query if(isset($_POST['username'])): $username = $_POST['username']; $password = $_POST['password']; $posts = mysql_query("SELECT * FROM users WHERE username='$username'"); $no_rows = mysql_num_rows($posts ); while($row = mysql_fetch_array($posts)): print 'yes'; endwhile; else: print 'no'; //header('location: index.php'); endif; endif; Thank in adance

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  • Setting Global Variables in VBA

    - by dennis96411
    I'm currently making an "OS" in PowerPoint and I need to know how to set global variables for the settings. I made a module called "Settings" containing: Public Sub Settings() Option Explicit Public UserName, UserIcon, Background, BrowserHomePage As String Public SetupComplete As Boolean SetupComplete = False UserName = "Administrator" UserIcon = Nothing Background = Nothing BrowserHomePage = Nothing 'Set the variables UserName.Text = UserName End Sub Now on the "log in" screen, I have a text box named "UserName". I then made a button just to test out the variables. The button does this: Private Sub CommandButton1_Click() UserName.Value = UserName End Sub The text box has no value when I click the button. I'm super new at VBA, and would like to know how to do this. Also, if anyone knows how to automatically execute codes when starting the PowerPoint, that would be fantastic.

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  • NoneType has no attribute Append

    - by Rosarch
    I'm new to Python. I can't understand why a variable is None at a certain point in my code: class UsersInRoom(webapp.RequestHandler): def get(self): room_id = self.request.get("room_id") username = self.request.get("username") UserInRoom_entities = UserInRoom.gql("WHERE room = :1", room_id).get() if UserInRoom_entities: for user_in_room in UserInRoom_entities: if user_in_room.username == username: user_in_room.put() # last_poll auto updates to now whenenever user_in_room is saved else: user_in_room = UserInRoom() user_in_room.username = username user_in_room.put() UserInRoom_entities = [] UserInRoom_entities.append(user_in_room) // error here # name is `user_at_room` intead of `user_in_room` to avoid confusion usernames = [user_at_room.username for user_at_room in UserInRoom_entities] self.response.out.write(json.dumps(usernames)) The error is: Traceback (most recent call last): File "C:\Program Files\Google\google_appengine\google\appengine\ext\webapp\__init__.py", line 507, in __call__ handler.get(*groups) File "path\to\chat.py", line 160, in get AttributeError: 'NoneType' object has no attribute 'append' How is this possible? I'm setting UserInRoom_entities = [] immediately before that call. Or is something else the None in question?

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  • PHP mySQL query's and PHP Variables

    - by jon
    I'm trying to make an OO Login system for a project I'm working on, and am having trouble with inserting variables into the query strings. In the code below, if I replace "$TBL_NAME" with the actual table name it works. Why isn't $TBL_NAME translating to the value of $TBL_NAME? class UserDB { private $TBL_NAME = "users"; public static function CheckLogin($username, $password) { Database::Connect(); $username = stripslashes($username); $password = stripslashes($password); $username = mysql_real_escape_string($username); $password = mysql_real_escape_string($password); $sql="SELECT uid FROM $TBL_NAME WHERE username='$username' AND password='$password' "; $result =mysql_query($sql); $count=mysql_num_rows($result); if ($count==1) return true; else return false; } The Query is returning false.

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  • Is this the right way of handling command line arguments?

    - by shadyabhi
    ask_username = True ask_password = True ask_message = True ask_number = True def Usage(): print '\t-h, --help: View help' print '\t-u, --username: Username' print '\t-p, --password: Password' print '\t-n, --number: numbber to send the sms' print '\t-m, --message: Message to send' sys.exit(1) opts, args = getopt(sys.argv[1:], 'u:p:m:n:h',["username=","password=","message=","number=","help"]) print opts, args for o,v in opts: if o in ("-h", "--help"): Usage() elif o in ("-u", "--username"): username = v ask_username = False elif o in ("-p", "--password"): passwd = v ask_password = False elif o in ("-m", "--message"): message = v ask_message = False elif o in ("-n", "--number"): number = v ask_number = False #Credentials taken here if ask_username: username = raw_input("Enter USERNAME: ") if ask_password: passwd = getpass() if ask_message: message = raw_input("Enter Message: ") if ask_number: number = raw_input("Enter Mobile number: ") I dont think it is, because I am using 4 objects just for checking if command line argument was provided... Guide me with the best way of doing it..

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  • Can't connect using Jail SFTP account

    - by Fazal
    I've been following this tutorial "Limiting Access with SFTP Jails on Debian and Ubuntu" and whilst I've had no errors setting it up, I've had issues on Ubuntu 10.04LTS logging in as a user on a virtualhost. I've changed my SSH port to 22022, and enter all the credentials when attempting to login. I ran these commands to add a user to the virtualhost: # useradd -d /srv/www/[domain] [username] # passwd [username] # usermod -G filetransfer [username] # chown [username]:[username] /srv/www/[domain]/public_html I should add that this is the only time I've setup the user they have no other /home directories or such. The directory that does exist is at /srv/www/example.com/public_html When I try using a desktop package such as cyberduck to login to the site, I keep getting a "Login failed with this username or password". I am completely lost as what to do next... The reason why I'm trying this method is because I want my clients to use SFTP and not FTP to upload files to their websites. Any help or direction is appreciated.

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  • symbolic link and filezilla over sftp

    - by Doc
    I'm pretty new to debian, and I'm trying to set up a server. I created a user which can only access to his folder /home/username (and its subdirectory). Now I want to use that user for the webserver I set up, and I gave him access to /var/www but I can't see /var/www through sftp and i did a symbolic link like this root@server:/home/username# ln -s /var/www www root@server:/home/username# cd www root@server:/home/username/www# chown username:username * now, with filezilla, I can see www folder like this - but when I try to open it I get this - Where am I going wrong? sorry for my awful english, i hope you can understand my problem...

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  • How to configure installed Ruby and gems?

    - by NARKOZ
    Hi. My current gem env returns: RubyGems Environment: - RUBYGEMS VERSION: 1.3.6 - RUBY VERSION: 1.8.7 (2008-08-11 patchlevel 72) [x86_64-linux] - INSTALLATION DIRECTORY: /home/USERNAME/.gems - RUBYGEMS PREFIX: /home/narkoz - RUBY EXECUTABLE: /usr/bin/ruby1.8 - EXECUTABLE DIRECTORY: /home/USERNAME/.gems/bin - RUBYGEMS PLATFORMS: - ruby - x86_64-linux - GEM PATHS: - /home/USERNAME/.gems - /usr/lib/ruby/gems/1.8 - GEM CONFIGURATION: - :update_sources => true - :verbose => true - :benchmark => false - :backtrace => false - :bulk_threshold => 1000 - "gempath" => ["/home/USERNAME/.gems", "/usr/lib/ruby/gems/1.8"] - "gemhome" => "/home/USERNAME/.gems" - REMOTE SOURCES: - http://rubygems.org/ How can I change path /home/USERNAME/ to my own without uninstalling? OS: Debian Linux

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  • How to configure installed Ruby and gems?

    - by NARKOZ
    My current gem env returns: RubyGems Environment: - RUBYGEMS VERSION: 1.3.6 - RUBY VERSION: 1.8.7 (2008-08-11 patchlevel 72) [x86_64-linux] - INSTALLATION DIRECTORY: /home/USERNAME/.gems - RUBYGEMS PREFIX: /home/narkoz - RUBY EXECUTABLE: /usr/bin/ruby1.8 - EXECUTABLE DIRECTORY: /home/USERNAME/.gems/bin - RUBYGEMS PLATFORMS: - ruby - x86_64-linux - GEM PATHS: - /home/USERNAME/.gems - /usr/lib/ruby/gems/1.8 - GEM CONFIGURATION: - :update_sources => true - :verbose => true - :benchmark => false - :backtrace => false - :bulk_threshold => 1000 - "gempath" => ["/home/USERNAME/.gems", "/usr/lib/ruby/gems/1.8"] - "gemhome" => "/home/USERNAME/.gems" - REMOTE SOURCES: - http://rubygems.org/ How can I change path /home/USERNAME/ to my own without uninstalling? OS: Debian Linux

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  • Read-only file system

    - by John
    The title might not be as descriptive as I would like it to be but couldn't come up with a better one. My server's file system went into Read-only. And I don't understand why it does so and how to solve it. I can SSH into the server and when trying to start apache2 for example I get the following : username@srv1:~$ sudo service apache2 start [sudo] password for username: sudo: unable to open /var/lib/sudo/username/1: Read-only file system * Starting web server apache2 (30)Read-only file system: apache2: could not open error log file /var/log/apache2/error.log. Unable to open logs Action 'start' failed. The Apache error log may have more information. When I try restarting the server I get : username@srv1:~$ sudo shutdown -r now [sudo] password for username: sudo: unable to open /var/lib/sudo/username/1: Read-only file system Once I restart it manually it just start up without any warning or message saying something is wrong. I hope somebody could point me into the right direction to resolve this issue. Thanks in advance!

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  • How to do MVC the right way

    - by Ieyasu Sawada
    I've been doing MVC for a few months now using the CodeIgniter framework in PHP but I still don't know if I'm really doing things right. What I currently do is: Model - this is where I put database queries (select, insert, update, delete). Here's a sample from one of the models that I have: function register_user($user_login, $user_profile, $department, $role) { $department_id = $this->get_department_id($department); $role_id = $this->get_role_id($role); array_push($user_login, $department_id, $role_id); $this->db->query("INSERT INTO tbl_users SET username=?, hashed_password=?, salt=?, department_id=?, role_id=?", $user_login); $user_id = $this->db->insert_id(); array_push($user_profile, $user_id); $this->db->query(" INSERT INTO tbl_userprofile SET firstname=?, midname=?, lastname=?, user_id=? ", $user_profile); } Controller - talks to the model, calls up the methods in the model which queries the database, supplies the data which the views will display(success alerts, error alerts, data from database), inherits a parent controller which checks if user is logged in. Here's a sample: function create_user(){ $this->load->helper('encryption/Bcrypt'); $bcrypt = new Bcrypt(15); $user_data = array( 'username' => 'Username', 'firstname' => 'Firstname', 'middlename' => 'Middlename', 'lastname' => 'Lastname', 'password' => 'Password', 'department' => 'Department', 'role' => 'Role' ); foreach ($user_data as $key => $value) { $this->form_validation->set_rules($key, $value, 'required|trim'); } if ($this->form_validation->run() == FALSE) { $departments = $this->user_model->list_departments(); $it_roles = $this->user_model->list_roles(1); $tc_roles = $this->user_model->list_roles(2); $assessor_roles = $this->user_model->list_roles(3); $data['data'] = array('departments' => $departments, 'it_roles' => $it_roles, 'tc_roles' => $tc_roles, 'assessor_roles' => $assessor_roles); $data['content'] = 'admin/create_user'; parent::error_alert(); $this->load->view($this->_at, $data); } else { $username = $this->input->post('username'); $salt = $bcrypt->getSalt(); $hashed_password = $bcrypt->hash($this->input->post('password'), $salt); $fname = $this->input->post('firstname'); $mname = $this->input->post('middlename'); $lname = $this->input->post('lastname'); $department = $this->input->post('department'); $role = $this->input->post('role'); $user_login = array($username, $hashed_password, $salt); $user_profile = array($fname, $mname, $lname); $this->user_model->register_user($user_login, $user_profile, $department, $role); $data['content'] = 'admin/view_user'; parent::success_alert(4, 'User Sucessfully Registered!', 'You may now login using your account'); $data['data'] = array('username' => $username, 'fname' => $fname, 'mname' => $mname, 'lname' => $lname, 'department' => $department, 'role' => $role); $this->load->view($this->_at, $data); } } Views - this is where I put html, css, and JavaScript code (form validation code for the current form, looping through the data supplied by controller, a few if statements to hide and show things depending on the data supplied by the controller). <!--User registration form--> <form class="well min-form" method="post"> <div class="form-heading"> <h3>User Registration</h3> </div> <label for="username">Username</label> <input type="text" id="username" name="username" class="span3" autofocus> <label for="password">Password</label> <input type="password" id="password" name="password" class="span3"> <label for="firstname">First name</label> <input type="text" id="firstname" name="firstname" class="span3"> <label for="middlename">Middle name</label> <input type="text" id="middlename" name="middlename" class="span3"> <label for="lastname">Last name</label> <input type="text" id="lastname" name="lastname" class="span3"> <label for="department">Department</label> <input type="text" id="department" name="department" class="span3" list="list_departments"> <datalist id="list_departments"> <?php foreach ($data['departments'] as $row) { ?> <option data-id="<?php echo $row['department_id']; ?>" value="<?php echo $row['department']; ?>"><?php echo $row['department']; ?></option> <?php } ?> </datalist> <label for="role">Role</label> <input type="text" id="role" name="role" class="span3" list=""> <datalist id="list_it"> <?php foreach ($data['it_roles'] as $row) { ?> <option data-id="<?php echo $row['role_id']; ?>" value="<?php echo $row['role']; ?>"><?php echo $row['role']; ?></option> <?php } ?> </datalist> <datalist id="list_collection"> <?php foreach ($data['tc_roles'] as $row) { ?> <option data-id="<?php echo $row['role_id']; ?>" value="<?php echo $row['role']; ?>"><?php echo $row['role']; ?></option> <?php } ?> </datalist> <datalist id="list_assessor"> <?php foreach ($data['assessor_roles'] as $row) { ?> <option data-id="<?php echo $row['role_id']; ?>" value="<?php echo $row['role']; ?>"><?php echo $row['role']; ?></option> <?php } ?> </datalist> <p> <button type="submit" class="btn btn-success">Create User</button> </p> </form> <script> var departments = []; var roles = []; $('#list_departments option').each(function(i){ departments[i] = $(this).val(); }); $('#list_it option').each(function(i){ roles[roles.length + 1] = $(this).val(); }); $('#list_collection option').each(function(i){ roles[roles.length + 1] = $(this).val(); }); $('#list_assessor option').each(function(i){ roles[roles.length + 1] = $(this).val(); }); $('#department').blur(function(){ var department = $.trim($(this).val()); $('#role').attr('list', 'list_' + department); }); var password = new LiveValidation('password'); password.add(Validate.Presence); password.add(Validate.Length, {minimum: 10}); $('input[type=text]').each(function(i){ var field_id = $(this).attr('id'); var field = new LiveValidation(field_id); field.add(Validate.Presence); if(field_id == 'department'){ field.add(Validate.Inclusion, {within : departments}); } else if(field_id == 'role'){ field.add(Validate.Inclusion, {within : roles}) } }); </script> The codes above are actually code from the application that I'm currently working on. I'm working on it alone so I don't really have someone to review my code for me and point out the wrong things in it so I'm posting it here in hopes that someone could point out the wrong things that I've done in here. I'm also looking for some guidelines in writing MVC code like what are the things that should be and shouldn't be included in views, models and controllers. How else can I improve the current code that I have right now. I've written some really terrible code before(duplication of logic, etc.) that's why I want to improve my code so that I can easily maintain it in the future. Thanks!

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  • SQL -- How to combine three SELECT statements with very tricky requirements

    - by Frederick
    I have a SQL query with three SELECT statements. A picture of the data tables generated by these three select statements is located at www.britestudent.com/pub/1.png. Each of the three data tables have identical columns. I want to combine these three tables into one table such that: (1) All rows in top table (Table1) are always included. (2) Rows in the middle table (Table2) are included only when the values in column1 (UserName) and column4 (CourseName) do not match with any row from Table1. Both columns need to match for the row in Table2 to not be included. (3) Rows in the bottom table (Table3) are included only when the value in column4 (CourseName) is not already in any row of the results from combining Table1 and Table2. I have had success in implementing (1) and (2) with an SQL query like this: SELECT DISTINCT UserName AS UserName, MAX(AmountUsed) AS AmountUsed, MAX(AnsweredCorrectly) AS AnsweredCorrectly, CourseName, MAX(course_code) AS course_code, MAX(NoOfQuestionsInCourse) AS NoOfQuestionsInCourse, MAX(NoOfQuestionSetsInCourse) AS NoOfQuestionSetsInCourse FROM ( "SELECT statement 1" UNION "SELECT statement 2" ) dt_derivedTable_1 GROUP BY CourseName, UserName Where "SELECT statement 1" is the query that generates Table1 and "SELECT statement 2" is the query that generates Table2. A picture of the data table generated by this query is located at www.britestudent.com/pub/2.png. I can get away with using the MAX() function because values in the AmountUsed and AnsweredCorrectly columns in Table1 will always be larger than those in Table2 (and they are identical in the last three columns of both tables). What I fail at is implementing (3). Any suggestions on how to do this will be appreciated. It is tricky because the UserName values in Table3 are null, and because the CourseName values in the combined Table1 and Table2 results are not unique (but they are unique in Table3). After implementing (3), the final table should look like the table in picture 2.png with the addition of the last row from Table3 (the row with the CourseName value starting with "4. Klasse..." I have tried to implement (3) using another derived table using SELECT, MAX() and UNION, but I could not get it to work. Below is my full SQL query with the lines from this failed attempt to implement (3) commented out. Cheers, Frederick PS--I am new to this forum (and new to SQL as well), but I have had more of my previous problems answered by reading other people's posts on this forum than from reading any other forum or Web site. This forum is a great resources. -- SELECT DISTINCT MAX(UserName), MAX(AmountUsed) AS AmountUsed, MAX(AnsweredCorrectly) AS AnsweredCorrectly, CourseName, MAX(course_code) AS course_code, MAX(NoOfQuestionsInCourse) AS NoOfQuestionsInCourse, MAX(NoOfQuestionSetsInCourse) AS NoOfQuestionSetsInCourse -- FROM ( SELECT DISTINCT UserName AS UserName, MAX(AmountUsed) AS AmountUsed, MAX(AnsweredCorrectly) AS AnsweredCorrectly, CourseName, MAX(course_code) AS course_code, MAX(NoOfQuestionsInCourse) AS NoOfQuestionsInCourse, MAX(NoOfQuestionSetsInCourse) AS NoOfQuestionSetsInCourse FROM ( -- Table 1 - All UserAccount/Course combinations that have had quizzez. SELECT DISTINCT dbo.win_user.user_name AS UserName, cast(dbo.GetAmountUsed(dbo.session_header.win_user_id, dbo.course.course_id, dbo.course.no_of_questionsets_in_course) as nvarchar(10)) AS AmountUsed, Isnull(cast(dbo.GetAnswerCorrectly(dbo.session_header.win_user_id, dbo.course.course_id, dbo.question_set.no_of_questions) as nvarchar(10)),0) AS AnsweredCorrectly, dbo.course.course_name AS CourseName, dbo.course.course_code, dbo.course.no_of_questions_in_course AS NoOfQuestionsInCourse, dbo.course.no_of_questionsets_in_course AS NoOfQuestionSetsInCourse FROM dbo.session_detail INNER JOIN dbo.session_header ON dbo.session_detail.session_header_id = dbo.session_header.session_header_id INNER JOIN dbo.win_user ON dbo.session_header.win_user_id = dbo.win_user.win_user_id INNER JOIN dbo.win_user_course ON dbo.win_user_course.win_user_id = dbo.win_user.win_user_id INNER JOIN dbo.question_set ON dbo.session_header.question_set_id = dbo.question_set.question_set_id RIGHT OUTER JOIN dbo.course ON dbo.win_user_course.course_id = dbo.course.course_id WHERE (dbo.session_detail.no_of_attempts = 1 OR dbo.session_detail.no_of_attempts IS NULL) AND (dbo.session_detail.is_correct = 1 OR dbo.session_detail.is_correct IS NULL) AND (dbo.win_user_course.is_active = 'True') GROUP BY dbo.win_user.user_name, dbo.course.course_name, dbo.question_set.no_of_questions, dbo.course.no_of_questions_in_course, dbo.course.no_of_questionsets_in_course, dbo.session_header.win_user_id, dbo.course.course_id, dbo.course.course_code UNION ALL -- Table 2 - All UserAccount/Course combinations that do or do not have quizzes but where the Course is selected for quizzes for that User Account. SELECT dbo.win_user.user_name AS UserName, -1 AS AmountUsed, -1 AS AnsweredCorrectly, dbo.course.course_name AS CourseName, dbo.course.course_code, dbo.course.no_of_questions_in_course AS NoOfQuestionsInCourse, dbo.course.no_of_questionsets_in_course AS NoOfQuestionSetsInCourse FROM dbo.win_user_course INNER JOIN dbo.win_user ON dbo.win_user_course.win_user_id = dbo.win_user.win_user_id RIGHT OUTER JOIN dbo.course ON dbo.win_user_course.course_id = dbo.course.course_id WHERE (dbo.win_user_course.is_active = 'True') GROUP BY dbo.win_user.user_name, dbo.course.course_name, dbo.course.no_of_questions_in_course, dbo.course.no_of_questionsets_in_course, dbo.course.course_id, dbo.course.course_code ) dt_derivedTable_1 GROUP BY CourseName, UserName -- UNION ALL -- Table 3 - All Courses. -- SELECT DISTINCT null AS UserName, -- -2 AS AmountUsed, -- -2 AS AnsweredCorrectly, -- dbo.course.course_name AS CourseName, -- dbo.course.course_code, -- dbo.course.no_of_questions_in_course AS NoOfQuestionsInCourse, -- dbo.course.no_of_questionsets_in_course AS NoOfQuestionSetsInCourse -- FROM dbo.course -- WHERE is_active = 'True' -- ) dt_derivedTable_2 -- GROUP BY CourseName -- ORDER BY CourseName

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  • FTP into a server using specific usernames

    - by user1854765
    I am trying to ftp into a server, once I'm there, I want to get a file, then put it back after sleeping for 5 minutes. I have that part correct, but i added to the code, two variables that will be inputted when the code is executed. The user will input the username they want to connect with. I am having trouble connecting though. When I input the username t14pb, it still goes to the the first if statement, as if I said t14pmds. here is the code: #!/usr/bin/perl use Net::FTP; $host = "fd00p02"; $username = "$ARGV[0]"; $ftpdir = "/"; $file = "$ARGV[1]"; print "$username\n"; print "$file\n"; if ($username == t14pmds) { $password = "test1"; $ftp = Net::FTP->new($host) or die "Error connecting to $host: $!"; $ftp->login($username, $password) or die "Login failed: $!"; $ftp->cwd($ftpdir) or die "Can't go to $ftpdir: $!"; $ftp->get($file) or die "Can't get $file: $!"; sleep 5; $ftp->put($file) or die "Can't put $file: $!"; $ftp->quit or die "Error closing ftp connection: $!"; } if ($username == t14pb) { $password = "test2"; $ftp = Net::FTP->new($host) or die "Error connecting to $host: $!"; $ftp->login($username, $password) or die "Login failed: $!"; $ftp->cwd($ftpdir) or die "Can't go to $ftpdir: $!"; $ftp->get($file) or die "Can't get $file: $!"; sleep 5; $ftp->put($file) or die "Can't put $file: $!"; $ftp->quit or die "Error closing ftp connection: $!"; } if ($username == t14pmds_out) { $password = "test3"; $ftp = Net::FTP->new($host) or die "Error connecting to $host: $!"; $ftp->login($username, $password) or die "Login failed: $!"; $ftp->cwd($ftpdir) or die "Can't go to $ftpdir: $!"; $ftp->get($file) or die "Can't get $file: $!"; sleep 5; $ftp->put($file) or die "Can't put $file: $!"; $ftp->quit or die "Error closing ftp connection: $!"; } if ($username == t14fiserv) { $password = "test4"; $ftp = Net::FTP->new($host) or die "Error connecting to $host: $!"; $ftp->login($username, $password) or die "Login failed: $!"; $ftp->cwd($ftpdir) or die "Can't go to $ftpdir: $!"; $ftp->get($file) or die "Can't get $file: $!"; sleep 5; $ftp->put($file) or die "Can't put $file: $!"; $ftp->quit or die "Error closing ftp connection: $!"; }

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