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  • Ignoring 'A' and 'The' when sorting with XSLT

    - by ChrisV
    I would like to have a list sorted ignoring any initial definite/indefinite articles 'the' and 'a'. For instance: The Comedy of Errors Hamlet A Midsummer Night's Dream Twelfth Night The Winter's Tale I think perhaps in XSLT 2.0 this could be achieved along the lines of: <xsl:template match="/"> <xsl:for-each select="play"/> <xsl:sort select="if (starts-with(title, 'A ')) then substring(title, 2) else if (starts-with(title, 'The ')) then substring(title, 4) else title"/> <p><xsl:value-of select="title"/></p> </xsl:for-each> </xsl:template> However, I want to use in-browser processing, so have to use XSLT 1.0. Is there any way to achieve this in XLST 1.0?

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  • How to pass a string containing both single and double quotes as a parameter to XSLT in PHP?

    - by Boaz
    Hi, I have a simple PHP-based XSLT trasform code that looks like that: $xsl = new XSLTProcessor(); $xsl->registerPHPFunctions(); $xsl->setParameter("","searchterms", $searchterms); $xsl->importStylesheet($xslDoc); echo $xsl->transformToXML($doc); The code passes the variable $searchterms, which contains a string, as a parameter to the XSLT style sheet which in turns uses it as a text: <title>search feed for <xsl:value-of select="$searchterms"/></title> This works fine until you try to pass a string with mixes in it, say: $searchterms = '"some"'." text's quotes are mixed." In that point the XSLT processor screams: Cannot create XPath expression (string contains both quote and double-quotes) What is the correct way to safely pass arbitrary strings as input to XSLT? Note that these strings will be used as a text value in the resulting XML and not as an XPATH paramater. Thanks, Boaz

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  • Renaming nodes and values with xslt

    - by T.K.
    Hello world, I'm new to xslt, and have a task that I'm not really sure where to go with. I want to rename nodes, but maintain the format all node declarations. In the actual context I'll be applying this to, I'll be doing a series of renames like this, but for the sake of brevity, the sample I've written up only involves renaming one node. I am using XSL 1.0. Input: <variables> <var> <RENAME> a </RENAME> </var> <var RENAME='b'/> <var> <DO_NOT_TOUCH> c </DO_NOT_TOUCH> </var> <var DO_NOT_TOUCH='d'/> </variables> Desired Output: <variables> <var> <DONE> a </DONE> </var> <var DONE='b'/> <var> <DO_NOT_TOUCH> c </DO_NOT_TOUCH> </var> <var DO_NOT_TOUCH='d'/> </variables> My xslt: <xsl:template match="RENAME"> <RENAMED> <xsl:apply-templates select="@*|node()"/> </RENAMED> </xsl:template> <xsl:template match="@*|node()"> <xsl:copy> <xsl:apply-templates select="@*|node()"/> </xsl:copy> </xsl:template> Current Output <variables> <var> <RENAMED> a </RENAMED> </var> <var RENAME="b"> </var> <var> <DO_NOT_TOUCH> c </DO_NOT_TOUCH> </var> <var DO_NOT_TOUCH="d"> </var> </variables>

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  • How can I add multiple filters to a XSLT for-each statement?

    - by Huuuze
    I have the following XSLT node: <xsl:for-each select="Book[title != 'Moby Dick']"> .... </xsl:for-each> However, I'd like use multiple filters in the for-each. I've tried the following, but it doesn't seem to work: <!-- Attempt #1 --> <xsl:for-each select="Book[title != 'Moby Dick'] or Book[author != 'Rowling'] "> .... </xsl:for-each> <!-- Attempt #2 --> <xsl:for-each select="Book[title != 'Moby Dick' or author != 'Rowling']"> .... </xsl:for-each>

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  • .NET Extension Objects with XSLT -- how to iterate over a collection?

    - by Pandincus
    Help me, Stackoverflow! I have a simple .NET 3.5 console app that reads some data and sends emails. I'm representing the email format in an XSLT stylesheet so that we can easily change the wording of the email without needing to recompile the app. We're using Extension Objects to pass data to the XSLT when we apply the transformation: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl" xmlns:EmailNotification="ext:EmailNotification"> -- this way, we can have statements like: <p> Dear <xsl:value-of select="EmailNotification:get_FullName()" />: </p> The above works fine. I pass the object via code like this (some irrelevant code omitted for brevity): // purely an example structure public struct EmailNotification { public string FullName { get; set; } } // Somewhere in some method ... var notification = new Notification("John Smith"); // ... XsltArgumentList xslArgs = new XsltArgumentList(); xslArgs.AddExtensionObject("ext:EmailNotification", notification); // ... // The part where it breaks! (This is where we do the transformation) xslt.Transform(fakeXMLDocument.CreateNavigator(), xslArgs, XmlWriter.Create(transformedXMLString)); So, all of the above code works. However, I wanted to get a little fancy (always my downfall) and pass a collection, so that I could do something like this: <p>The following accounts need to be verified:</p> <xsl:for-each select="EmailNotification:get_SomeCollection()"> <ul> <li> <xsl:value-of select="@SomeAttribute" /> </li> </ul> <xsl:for-each> When I pass the collection in the extension object and attempt to transform, I get the following error: "Extension function parameters or return values which have Clr type 'String[]' are not supported." or List, or IEnumerable, or whatever I try to pass in. So, my questions are: How can I pass in a collection to my XSLT? What do I put for the xsl:value-of select="" inside the xsl:for-each ? Is what I am trying to do impossible?

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  • How can I strip line breaks from my XML with XSLT?

    - by Eric
    I have this XSLT: <xsl:strip-space elements="*" /> <xsl:template match="math"> <img class="math"> <xsl:attribute name="src">http://latex.codecogs.com/gif.latex?<xsl:value-of select="text()" /></xsl:attribute> </img> </xsl:template> Which is being applied to this XML (notice the line break): <math>\text{average} = \alpha \times \text{data} + (1-\alpha) \times \text{average}</math> Unfortunately, the transform creates this: <img class="math" src="http://latex.codecogs.com/gif.latex?\text{average} = \alpha \times \text{data} + (1-\alpha) \times&#10;&#9;&#9;&#9;&#9;&#9;\text{average}" /> Notice the whitespace character literals. Although it works, it's awfully messy. How can I prevent this?

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  • How to implement multi-source XSLT mapping in 11g BPEL

    - by [email protected]
    In SOA 11g, you can create a XSLT mapper that uses multiple sources as the input. To implement a multi-source mapper, just follow the instructions below, Drag and drop a Transform Activity to a BPEL process Double-click on the Transform Activity, the Transform dialog window appears. Add source variables by clicking the Add icon and selecting the variable and part of the variable as needed. You can select multiple input variables. The first variable represents the main XML input to the XSL mapping, while additional variables that are added here are defined in the XSL mapping as input parameters. Select the target variable and its part if available. Specify the mapper file name, the default file name is xsl/Transformation_%SEQ%.xsl, where %SEQ% represents the sequence number of the mapper. Click OK, the xls file will be opened in the graphical mode. You can map the sources to the target as usual. Open the mapper source code, you will notice the variable representing the additional source payload, is defined as the input parameter in the map source spec and body<mapSources>    <source type="XSD">      <schema location="../xsd/po.xsd"/>      <rootElement name="PurchaseOrder" namespace="http://www.oracle.com/pcbpel/po"/>    </source>    <source type="XSD">      <schema location="../xsd/customer.xsd"/>      <rootElement name="Customer" namespace="http://www.oracle.com/pcbpel/Customer"/>      <param name="v_customer" />    </source>  </mapSources>...<xsl:param name="v_customer"/> Let's take a look at the BPEL source code used to execute xslt mapper. <assign name="Transform_1">            <bpelx:annotation>                <bpelx:pattern>transformation</bpelx:pattern>            </bpelx:annotation>            <copy>                <from expression="ora:doXSLTransformForDoc('xsl/Transformation_1.xsl',bpws:getVariableData('v_po'),'v_customer',bpws:getVariableData('v_customer'))"/>                <to variable="v_invoice"/>            </copy>        </assign> You will see BPEL uses ora:doXSLTransformForDoc XPath function to execute the XSLT mapper.This function returns the result of  XSLT transformation when the xslt template matching the document. The signature of this function is  ora:doXSLTransformForDoc(template,input, [paramQName, paramValue]*).Wheretemplate is the XSLT mapper nameinput is the string representation of xml input, paramQName is the parameter defined in the xslt mapper as the additional sourceparameterValue is the additional source payload. You can add more sources to the mapper at the later stage, but you have to modify the ora:doXSLTransformForDoc in the BPEL source code and make sure it passes correct parameter and its value pair that reflects the changes in the XSLT mapper.So the best practices are : create the variables before creating the mapping file, therefore you can add multiple sources when you define the transformation in the first place, which is more straightforward than adding them later on. Review ora:doXSLTransformForDoc code in the BPEL source and make sure it passes the correct parameters to the mapper.

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  • How to customise search core results web part Part1

    - by ybbest
    In this post, I’d like to show you how to customise search core results web part. It is a quite simple, most of the times what you need to do is to change the xslt to perform the changes. Here are the steps: 1. You need to change the xslt to the following, so that you can see the raw xml. <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" /> <xsl:template match="/"> <xmp><xsl:copy-of select="*"/></xmp> </xsl:template> </xsl:stylesheet> a. To do so , you need to go to edit page>>Edit search core results web part >>Display Properties and then untick use Location Visualization b. Open the xslt editor and copy the existing XSLT code to your preferred xslt editor so that you can customise it. c. Now you can paste in the XSLT code above. 2.Perform the search after you have completed step1 and you will see the search results returned in raw xml <All_Results> <Result> <id>1</id> <workid>678</workid> <rank>100000000</rank> <title>Ybbest</title> <author></author> <size>137531</size> <url>http://ybbest</url> <urlEncoded>http%3A%2F%2Fybbest</urlEncoded> <description>Ybbest test site</description> <write>3/17/2012</write> <sitename>http://ybbest</sitename> <collapsingstatus>0</collapsingstatus> <hithighlightedsummary> <c0>Ybbest</c0> test site <ddd /> Add a new image, change this welcome text or add new lists to this page by clicking the edit button above. You can click on Shared Documents to add files or on the <ddd /> </hithighlightedsummary> <hithighlightedproperties> <HHTitle> <c0>Ybbest</c0> </HHTitle> <HHUrl>http://<c0>ybbest</c0></HHUrl> </hithighlightedproperties> <contentclass>STS_Site</contentclass> <isdocument>False</isdocument> <picturethumbnailurl></picturethumbnailurl> <popularsocialtags /> <picturewidth>0</picturewidth> <pictureheight>0</pictureheight> <datepicturetaken></datepicturetaken> <serverredirectedurl></serverredirectedurl> <fileextension></fileextension> <ows_metadatafacetinfo></ows_metadatafacetinfo> <imageurl imageurldescription="SharePoint Site Collection">/_layouts/images/siteicon_16x16.png</imageurl> </Result> <TotalResults>69</TotalResults> <NumberOfResults>50</NumberOfResults> </All_Results> 3. Then you can read what has been returned in the raw xml and start modifying the xslt to customise your search results page. 4.You can also link an external xslt to the web part.It can be set in the Miscellaneous of Web Part section. You can also set it pragmatically using a feature receiver , you can download the source code to do so here. References: http://stackoverflow.com/questions/6548104/change-xslt-of-the-searchresultwebpart-during-the-featureactivated http://www.dotnetmafia.com/blogs/dotnettipoftheday/archive/2010/04/05/a-quick-guide-to-coreresultswebpart-configuration-changes-in-sharepoint-2010.aspx http://www.tonytestasworld.com/post/2011/01/30/HowTo-display-SharePoint-Search-results-as-raw-XML.aspx

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  • BAM design pointers

    - by Kavitha Srinivasan
    In working recently with a large Oracle customer on SOA and BAM, I discovered that some BAM best practices are not quite well known as I had always assumed ! There is a doc bug out to formally incorporate those learnings but here are a few notes..  EMS-DO parity When using EMS (Enterprise Message Source) as a BAM feed, the best practice is to use one EMS to write to one Data Object. There is a possibility of collisions and duplicates when multiple EMS write to the same row of a DO at the same time. This customer had 17 EMS writing to one DO at the same time. Every sensor in their BPEL process writes to one topic but the Topic was read by 1 EMS corresponding to one sensor. They then used XSL within BAM to transform the payload into the BAM DO format. And hence for a given BPEL instance, 17 sensors fired, populated 1 JMS topic, was consumed by 17 EMS which in turn wrote to 1 DataObject.(You can image what would happen for later versions of the application that needs to send more information to BAM !).  We modified their design to use one Master XSL based on sensorname for all sensors relating to a DO- say Data Object 'Orders' and were able to thus reduce the 17 EMS to 1 with a master XSL. For those of you wondering about how squeaky clean this design is, you are right ! This is indeed not squeaky clean and that brings us to yet another 'inferred' best practice. (I try very hard not to state the obvious in my blogs with the hope that everytime I blog, it is very useful but this one is an exception.) Transformations and Calculations It is optimal to do transformations within an engine like BPEL. Not only does this provide modelling ease with a nice GUI XSL mapper in JDeveloper, the XSL engine in BPEL is quite efficient at runtime as well. And so, doing XSL transformations in BAM is not quite prudent.  The same is true for any non-trivial calculations as well. It is best to do all transformations,calcuations and sanitize the data in a BPEL or like layer and then send this to BAM (via JMS, WS etc.) This then delegates simply the function of report rendering and mechanics of real-time reporting to the Oracle BAM reporting tool which it is most suited to do. All nulls are not created equal Here is yet another possibly known fact but reiterated here. For an EMS with an Upsert operation: a) If Empty tags or tags with no value are sent like <Tag1/> or <Tag1></Tag1>, the DO will be overwritten with --null-- b) If Empty tags are suppressed ie not generated at all, the corresponding DO field will NOT be overwritten. The field will have whatever value existed previously.  For an EMS with an Insert operation, both tags with an empty value and no tags result in –null-- being written to the DO. Hope this helps .. Happy 4th!

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  • What are the drawbacks of sending XML to browsers and let them apply XSLT?

    - by MainMa
    Context Working as a freelance developer, I often made websites completely based on XSLT. In other words, on every request, an XML file is generated, containing everything we need to know about the page content: the name of the user currently logged in, the top menu entries, if this menu is dynamic/configurable, the text to display in a specific area of the page, etc. Then XSL process (caches, etc.) it to HTML/XHTML page to send to the browser. It has a good point to make it easier to create small-scale websites, especially with PHP. It is a sort of template engine, but which I prefer to other template engines because it's much more powerful than most of template engines, and because I know it better and like it. It is also possible, when need, to give an access to raw XML data on demand for an automated access, without the need to create separate APIs. Of course, it will fail completely on any medium-scale or large-scale website, since, even with good caching techniques, XSL still degrades overall website performance and requires more CPU serverside. Question Modern browsers have the ability to take an XML file and to transform it with an associated XSL file declared in XML like <?xml-stylesheet href="demo.xslt" type="text/xsl"?>. Firefox 3 can do it. Internet Explorer 8 can do it too. It means that it is possible to migrate XSL processing from the server to the client side for 50% of users (according on browser statistics on several websites where I may want to implement this). It means that those 50% of users will receive only the XML file at each request, thus reducing their and server's bandwidth (XML file being much shorter than its processed HTML analog), and reducing server's CPU usage. What are the drawbacks of this technique? I thought about several ones, but it doesn't apply in this situation: Difficult implementation and the need to choose, based on the browser request, when to send raw XML and when to transform it to HTML instead. Obviously, the system will not be much more difficult then the actual one. The only change to make is to add XSL file link to every XML, and to add a browser check. More IO and bandwidth usage, since the XSLT file will be downloaded by the browsers, instead of being cached by the server. I don't think it will be a problem, since XSLT file will be cached by the browsers (like images, or CSS, or JavaScript files are cached actually). Possibly some problems on client side, like maybe problems when saving a page in some browsers. Difficulty to debug code: it is impossible to obtain an HTML source the browser is actually using, since the only displayed source is the downloaded XML. On the other hand, I rarely go look at HTML code on client side, and in most cases, it is unusable directly (whitespace being removed).

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  • Turning XSLT into a simple HTML snippet.

    - by jaasum
    http://drp.ly/yeAex <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:template match="/data/tour/entry"> <img src="{filename}"/> <h2>{heading}</h2> {description} </xsl:template> </xsl:stylesheet> Here is the code I am working with. I am a newbie to XSLT and I suppose I am not understanding how it transforms my XML into HTML entirely. This snippet of code I plan on loading via AJAX, so I really all I need it to output is a blank html document consisting only of these three items. I realize I am omitting the xsl:output tag and that is because I really don't understand how I can get this to just simply match that information to my tags in my xml without adding , tags etc. All it outputs is a string of text in an html document.

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  • Cannot access updated Java object from Saxon XSLT processor

    - by chipk
    I am working with an open source version of the Saxon XSLT processor "Saxon 9.0.0.2J from Saxonica" and am trying to make use of the java extensibility for the first time. I am running into an issue I suspect may be a limitation on the open source version, but wanted to check first whether there might be something I am just missing here. From the snippet below, my result is that the final value of $c1 does not change as a result of the call to greg:setTime() - i.e. the $c1 variable within Saxon appears to be unhooked from the underlying Java object and there is no apparent way to access the object as updated by the setTime() call. NOTE that all code in the snippet is tested and working otherwise - i.e. $c1 is properly instantiated by the getInstance() call, $startdate is of the proper format and $d1 is properly instantiated. Thoughts? <xsl:transform ..... xmlns:sql="java:java.sql.Date" xmlns:greg="java:java.util.GregorianCalendar" ..... > .... <xsl:element name="JobExpireDate"> <xsl:variable name="c1" select="greg:getInstance()" /> <xsl:variable name="d1" select="sql:valueOf($startdate)" /> <xsl:variable name="void" select="greg:setTime($c1,$d1)" /> <xsl:value-of select="$c1" /> </xsl:element>

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  • Sorted exsl:node-set. Return node by it position.

    - by kalininew
    Good afternoon, gentlemen. Help me solve a very simple task. I have a set of nodes <menuList> <mode name="aasdf"/> <mode name="vfssdd"/> <mode name="aswer"/> <mode name="ddffe"/> <mode name="ffrthjhj"/> <mode name="dfdf"/> <mode name="vbdg"/> <mode name="wewer"/> <mode name="mkiiu"/> <mode name="yhtyh"/> and so on... </menuList> I have it sorted now this way <xsl:variable name="rtf"> <xsl:for-each select="//menuList/mode"> <xsl:sort data-type="text" order="ascending" select="@name"/> <xsl:value-of select="@name"/> </xsl:for-each> </xsl:variable> Now I need to get an arbitrary element in the sorted array to the number of its position. I write code <xsl:value-of select="exsl:node-set($rtf)[position() = 3]"/> and get a response error. How to do it right?

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  • Render a Form from an XSLT file

    - by Russ Clark
    I've generated the following XSLT file, and have created a Form that will post to an ASP.Net MVC action called Home/ProcessRequest: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl" > <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <html> <body> <xsl:value-of select="Employee/Name"/> <br /> <xsl:value-of select="Employee/ID"/> <form method="post" action="/Home/ProcessRequest?id=42"> <input id="Action" name="Action" type="radio" value="Approved"></input> Approved <br /> <input id="Action" name="Action" type="radio" value="Rejected"></input> Rejected <br /> <input type="submit" value="Submit"></input> </form> </body> </html> Here is my XML File: <Employee xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Name>Russ</Name> <ID>42</ID> </Employee> This works fine the way it is, but I need to change the id parameter in my from from a hard coded integer, to use the ID element from my XML file. Does anyone know how to do this?

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  • How to recursively delete some xml elements using XSLT

    - by Monomachus
    Hi, So I got this situation which sucks. I have an XML like this <table border="1" cols="200 100pt 200"> <tr> <td>isbn</td> <td>title</td> <td>price</td> </tr> <tr> <td /> <td /> <td> <span type="champsimple" id="9b297fb5-d12b-46b1-8899-487a2df0104e" categorieid="a1c70692-0427-425b-983c-1a08b6585364" champcoderef="01f12b93-b4c5-401b-9da1-c9385d77e43f"> [prénom] </span> <span type="champsimple" id="e103a6a5-d1be-4c34-8a54-d234179fb4ea" categorieid="a1c70692-0427-425b-983c-1a08b6585364" champcoderef="01f12b93-b4c5-401b-9da1-c9385d77e43f">[nom]</span> <span></span> </td> </tr> <tr></tr> <tr> <td></td> <td>Phill It in</td> </tr> <tr> <table id="cas1"> <tr> <td ></td> <td >foo</td> </tr> <tr> <td >bar</td> <td >boo</td> </tr> </table> </tr> <tr> <table id="cas2"> <tr> <td ></td> <td >foo</td> </tr> <tr> <td ></td> <td >boo</td> </tr> </table> </tr> <tr> <table id="cas3"> <tr> <td >bar</td> <td ></td> </tr> <tr> <td >foo</td> <td >boo</td> </tr> </table> </tr> <tr> <table id="cas4"> <tr> <td /> <td /> </tr> <tr> <td>foo</td> <td>boo</td> </tr> </table> </tr> <table id="cas4"> <tr> <td /> <td /> </tr> <tr> <td>foo</td> <td>boo</td> </tr> </table> <tr> <td /> <td /> </tr> </table> Now the question is how would I recursively delete all empty td, tr and table elements? Now I use this XSLT <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="yes" indent="yes"/> <xsl:strip-space elements="*" /> <xsl:template match="node()|@*"> <xsl:copy> <xsl:apply-templates select="node()|@*"/> </xsl:copy> </xsl:template> <xsl:template match="td[not(node())]" /> <xsl:template match="tr[not(node())]" /> <xsl:template match="table[not(node())]" /> </xsl:stylesheet> But it doesn't do very well. After I delete td, a tr becomes empty but it doesn't handle that. Too bad. See the table element with "cas4". <table border="1" cols="200 100pt 200"> <tr> <td>isbn</td> <td>title</td> <td>price</td> </tr> <tr> <td> <span type="champsimple" id="9b297fb5-d12b-46b1-8899-487a2df0104e" categorieid="a1c70692-0427-425b-983c-1a08b6585364" champcoderef="01f12b93-b4c5-401b-9da1-c9385d77e43f"> [prénom] </span> <span type="champsimple" id="e103a6a5-d1be-4c34-8a54-d234179fb4ea" categorieid="a1c70692-0427-425b-983c-1a08b6585364" champcoderef="01f12b93-b4c5-401b-9da1-c9385d77e43f">[nom]</span> <span /> </td> </tr> <tr> <td>Phill It in</td> </tr> <tr> <table id="cas1"> <tr> <td>foo</td> </tr> <tr> <td>bar</td> <td>boo</td> </tr> </table> </tr> <tr> <table id="cas2"> <tr> <td>foo</td> </tr> <tr> <td>boo</td> </tr> </table> </tr> <tr> <table id="cas3"> <tr> <td>bar</td> </tr> <tr> <td>foo</td> <td>boo</td> </tr> </table> </tr> <tr> <table id="cas4"> <tr /> <tr> <td>foo</td> <td>boo</td> </tr> </table> </tr> <table id="cas4"> <tr /> <tr> <td>foo</td> <td>boo</td> </tr> </table> <tr /> </table> How would you solve this problem?

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  • How to sort an XML file by date in XLST

    - by AdRock
    I am trying to sort by date and get an error message about the stylesheet can't be loaded I found an answer on how others have suggested but it doesn't work for me Here is where it is supposed to sort. The commented out line is where the sort should occur <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:template name="hoo" match="/"> <html> <head> <title>Registered Festival Organisers and Festivals</title> <link rel="stylesheet" type="text/css" href="userfestival.css" /> </head> <body> <h1>Registered Festival Organisers and Festivals</h1> <xsl:for-each select="folktask/member"> <xsl:if test="user/account/userlevel='3'"> <!--<xsl:sort select="concat(substring(festival/event/datefrom,1,4),substring(festival/event/datefrom, 6,2),substring(festival/event/datefrom, 9,2))" data-type="number" order="ascending"/>--> Sample node from XML <festival id="1"> <event> <eventname>Oxford Folk Festival</eventname> <url>http://www.oxfordfolkfestival.com/</url> <datefrom>2010-04-07</datefrom> <dateto>2010-04-09</dateto> <location>Oxford</location> <eventpostcode>OX1 9BE</eventpostcode> <coords> <lat>51.735640</lat> <lng>-1.276136</lng> </coords> </event> </festival>

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  • Multiple XML/XSLT files in PHP, transform one with XSLT and add others but process it first with PHP

    - by ipalaus
    I am processing XML files transformations with XSLT in PHP correctly. Actually I use this code: $xml = new DOMDocument; $xml->LoadXML($xml_contents); $xsl = new DOMDocument; $xsl->load($xsl_file); $proc = new XSLTProcesoor; $proc->importStyleSheet($xsl); echo $proc->transformToXml($xml); $xml_contents is the XML processed with PHP, this is done by including the XML file first and then assigning $xml_contents = ob_get_contents(); ob_end_clean();. This forces to process the PHP code on the XML, and it works perfectly. My problem is that I use more than one XML file and this XML files has PHP code on it that need to be processed AND have a XSLT file associated to process the data. Actually I'm including this files in XSLT with the next code: <!-- First I add the XML file --> <xsl:param name="menu" select="document('menu.xml')" /> <!-- Next I add the transformations for menu.xml file --> <xsl:include href="menu.xsl" /> <!-- Finally, I process it on the actual ("parent") XML --> <xsl:apply-templates select="$menu/menu" /> My questiion is how I can handle this. I need to add mutiple XML(+XSLT) files to my first XML file that will containt PHP so it needs to be processed. Thank you in advance!

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  • XSLT: change node inner text.

    - by nabo
    I need to transform the following xml doc: <a> <b/> <c/> myText </a> into this: <a> <b/> <c/> differentText </a> So, i wrote this XSLT document <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" version="1.0" omit-xml-declaration="no" /> <xsl:template match="/a/text()"> <a> <b/> <c/> differentText </a> </xsl:template> </xsl:stylesheet> This way, i get the following result: <?xml version="1.0" encoding="utf-8"?> <a> <b /><c /> differentText </a> <a> <b /><c /> differentText </a> <a> <b /><c /> differentText </a> The result appears repeated 3 times because 3 matches are being done.. Why? I could i fix it? Thanks

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  • Upon doing a XSL Transform to XML how do I remove white space from a Node's attribute or data?

    - by Randy
    I have a part's list built out in XML and each part is labeled as such: <division> <parts> <part number="123456 " drawing="123456 " cad="y"> <attribute> <header>Header</header> <list>2</list> </attribute> </part> And I need to get the data behind the number and drawing attributes without the white space. I tried xsl:strip-space on the specific elements, and across the board, but that only strips the content in between the tags. I unfortunately have no access to the back-end that's producing the XML, so removing the spaces there doesn't look like an option.

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  • Sorting based on existing elements in xslt

    - by Teelo
    Hi , I want to sort in xslt based on existing set of pattern . Let me explain with the code: <Types> <Type> <Names> <Name>Ryan</Name> </Names> <Address>2344</Address> </Type> <Type> <Names> </Name>Timber</Name> </Names> <Address>1234</Address> </Type> <Type> <Names> </Name>Bryan</Name> </Names> <Address>34</Address> </Type> </Types> Right now I m just calling it and getting it like (all hyperlinks) Ryan Timber Bryan Now I don't want sorting on name but I have existing pattern how I want it to get displayed.Like Timber Bryan Ryan (Also I don't want to lose the url attached to my names earlier while doing this) I was thinking of putting earlier value in some array and sort based on the other array where I will store my existing pattern. But I am not sure how to achieve that.. My xslt looks like this now(there can be duplicate names also) <xsl:for-each select="/Types/Type/Names/Name/text()[generate-id()=generate-id(key('Name',.)[1])]"> <xsl:call-template name="typename"> </xsl:call-template> </xsl:for-each> <xsl:template name="typename"> <li> <a href="somelogicforurl"> <xsl:value-of select="."/> </a> </li> </xsl:template> I am using xsl 1.0

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  • How do I get a less than in a javascript for loop in XSL to work?

    - by Kyle
    I am using CDATA to escape the script but in IE8's debugger I still get this message: "Expected ')'" in the for loop conditions. I am assuming it still thinks that the ; in the &lt; generated by CDATA is ending the loop conditions. Original script in my XSL template: <script type="text/javascript" language="javascript"> <![CDATA[ function submitform(form){ var oErrorArray = new Array(); for (i=0;i<form.length;i++) eval("oErrorArray["+i+"]=oError"+i); var goForm = true; for(i=0;i<form.length;i++) { oErrorArray[i].innerHTML = ""; if(form[i].value="")){ oErrorArray[i].innerHTML = "Error - input field is blank"; goForm = false; } } if(goForm == true) form.submit(); } function resetform(form){ form.reset(); } ]]> </script> Code generated after transformation (from IE8 debugger): <script type="text/javascript" language="javascript"> function submitform(form){ var oErrorArray = new Array(); for (i=0;i&lt;form.length;i++) eval("oErrorArray["+i+"]=oError"+i); goForm = true; for(i=0;i&lt;form.length;i++) { oErrorArray[i].innerHTML = ""; if(form[i].value="")){ oErrorArray[i].innerHTML = "Error - input field is blank"; goForm = false; } } if(goForm == true) form.submit(); } function resetform(form){ form.reset(); } </script> Error reported by IE8 debugger: Expected ')' login.xml, line 29 character 30 (which is right after the first "form.length")

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  • XML + Xslt -> Xml with PHP

    - by rokdd
    Hi, I know that there are really a mass of XML XSLT php merging threads at SO. But php specific i could not found what might my problem: $xml = new DOMDocument; $xml-load("f.xml"); $xsl = new DOMDocument; $xsl-load('test.xsl'); // init and configure processor $proc = new XSLTProcessor; $proc-importStyleSheet($xsl); // import xsl document $xml2=$proc-transformToXML($xml); echo $xml2; My xslt file looks a bit empty.. However i tried ´output method="xml"´. but it doesnot help.. PHP returns always the data as text or html but not in XML.. what i am doing wrong. I only want to edit the XML with xslt and save back to XML (file). THanks for your help!

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