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  • Mysql Avg function for recent 15 records by date (order date desc) in every symbol

    - by venkatesh
    i am trying to create a statement in sql (for a table which holds stock symbols and price on specified date) with avg of 5 day price and avg of 15 days price for each symbol. table description: symbol open high close date the average price is calculated from last 5 days and last 15 days. i tried this for getting 1 symbol: SELECT avg(close), avg(`trd_qty`) FROM (select * from cashmarket WHERE symbol = \'hdil\' order by `M_day` desc limit 0,15 ) s ...but I couldn't get the desired the list for showing avg values for all symbols.

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  • jQuery + sexy alerts + javascript menus

    - by BibiBuBu
    Good Day! i am working on page which has Javascript Menus (dont know how made, i think they are in compressed form) Jquery Sexy Alerts now my problem is that when i want to add any type of jquery calender, it wont work :(, i have tried different possibilities found here, but yet invain. Can somebody guide me. OR some body give me suggestion to use a calender that is compatible with any other framework. help is appreciated. Thanks

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  • How can a Rails newbie find a job as a Rails developer?

    - by esavard
    I'm a Ruby on Rails newbie. I'm learning Rails in my spare time (my day job is C++ developer) and I like it. I would like to be paid to do Rails development full-time instead of C++. How can I find a job in Rails when most job offering requires 2-5 years of Rails experience? What is the most effective strategy to get some credibility as a Rails Developer? Thanks in advance for your answers.

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  • facebook photo album grouping photos in news feed

    - by John Klingelhoets
    We have a social media "platform" - when we schedule photos to be published to Facebook, if a user schedules photos - they all go into the same album, as they schedule photos throughout the day - the photos become grouped and do not appear as a large photo - but rather a bunch of photos in a album. Is there any way to prevent photos from being grouped in the new feed and it just showing the newest uploaded photo in stream? I do not see an option.

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  • K-nearest neighbour with closed-loop dimensions

    - by Tomas
    Hi, I've got a K-nearest neighbour problem where some of the dimensions are closed loops. For example one is 'time of day' and I'm matching for similarity so 'very early morning' is close to 'late evening', you can't just make it a linear scale from 'very early morning' at one end to 'late evening' at the other. How can I represent this in the data model? Is there an established way to handle this or a way to work around it?

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  • which ad solution is best for iPhone apps

    - by nbojja
    Hi All, i have a iPhone free app downloaded by 3000 users. mostly every one uses my app atleast once in a day. So i am planning to keep ads on my app. Which ad solution is best. and i looked in some sites. No one is giving clear details about CPMs. my direct question is "How much will i get for 1000 impressions using different ad solutions?" thanks

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  • [bash] files indexed by production date

    - by caas
    Each day an application creates a file called file_YYYYMMDD.csv where YYYYMMDD is the production date. But sometimes the generation fails and no files are generated for a couple of days. I'd like an easy way in a bash or sh script to find the filename of the most recent file, which has been produced before a given reference date. Typical usage: find the last generated file, disregarding those produced after the May 1st. Thanks for your help

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  • Store more than 24 hours in a DateTime

    - by Rob
    I work in a bizarre and irrational industry where we need to be able to represent the time of day as 06:00:00 to 30:00:00 instead of 0:00:00 to 24:00:00. Is there any way to do this using the DateTime type? If I try to construct a date time with an hour value greater than 24 it throws an exception.

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  • LINQ transform Dictionary<key,value> to Dictionary<value,key>

    - by code4life
    I'm having a low-brainwave day... Does anyone know of a quick & elegant way to transform a Dictionary so that the key becomes the value and vice-versa? Example: var originalDictionary = new Dictionary<int, string>() { {1, "One"}, {2, "Two"}, {3, "Three"} }; becomes var newDictionary = new Dictionary<string, int>(); // contents: // { // {"One". 1}, {"Two". 2}, {"Three", 3} // };

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  • RoR Server won't detach with -d option

    - by Rodrigo
    I had to reinstall a bunch of my port installs the other day and now when I launch my RoR server with "ruby script/server -d -p 3000" the server wont work. I am not seeing any errors in the logs. If I start it with "ruby script/server -p 3000" it works fine. Any ideas of what I might have uninstalled that would cause this behavior?

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  • Can a System Analyst come outside of programming?

    - by WeNeedAnswers
    Back in the day, if you wanted to be a Systems Analyst you had to work up the ranks from humble programmer. But these days there are University Courses/Programmes based on this topic alone. Is it thus valid for a graduate or post graduate to come into the world and just do systems analyst without doing the graft of being a programmer first, getting to know the nuances of what code is all about.

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  • Generating report with MySQL and Rails - how?

    - by Arywista
    Here is my data model from my application: id :integer(4) not null, primary key spam :boolean(1) not null duplicate :boolean(1) not null ignore :boolean(1) not null brand_id :integer(4) not null attitude :string not null posted_at :datetime not null Attitude could have 3 states: negative, positive, neutral. I want to generate resultset in table, this way, for each day between start and end date: date | total | positive | neutral | negative 2009-10-10 | 12 | 4 | 7 | 1 (...) 2009-10-30 | 5 | 2 | 1 | 1 And ignore all records which have: duplicate = true ignore = true spam = true How it's could be done?

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  • Complex query with two tables and multilpe data and price ranges

    - by TiuTalk
    Let's suppose that I have these tables: [ properties ] id (INT, PK) name (VARCHAR) [ properties_prices ] id (INT, PK) property_id (INT, FK) date_begin (DATE) date_end (DATE) price_per_day (DECIMAL) price_per_week (DECIMAL) price_per_month (DECIMAL) And my visitor runs a search like: List the first 10 (pagination) properties where the price per day (price_per_day field) is between 10 and 100 on the period for 1st may until 31 december I know thats a huge query, and I need to paginate the results, so I must do all the calculation and login in only one query... that's why i'm here! :)

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  • What are the books about Open-Source that everyone interested in should read?

    - by Edu Zamora
    Currently I am working and running my first Open-Source project and though I am quite happy how things are working so far, I have the feeling that a lot of things could be done better. So, what books about Open-Source would you recommend me in order to help filling this gap and making things better every day? What are the books that influenced you the most? I am especially interested in: - How to organize and run an Open-Source project - Best practices - Manage and involve users and developers - How to announce and do the releases - Legal issues

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