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  • How to import *.pyc file from different version of python?

    - by Almog
    Hello, I used python 2.5 and imported a file named "irit.py" from C:\util\Python25\Lib\site-packages directory. This files imports the file "_irit.pyc which is in the same directory. It worked well and did what I wanted. Than, I tried the same thing with python version 2.6.4. "irit.py" which is in C:\util\Python26\Lib\site-packages was imported, but "_irit.pyc" (which is in the same directory of 26, like before) hasn't been found. I got the error message: File "C:\util\Python26\lib\site-packages\irit.py", line 5, in import _irit ImportError: DLL load failed: The specified module could not be found. Can someone help me understand the problem and how to fix it?? Thanks, Almog.

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  • Django how to handle # in variable name.

    - by Jack
    I've got a dictionary in python which is assigned as a template variable. One of the keys is named "#text" but when i try to access it using {{ artist.image.3."#text"}} I get an error which is File "/home/jack/Desktop/test/appengine/lib/django/django/template/__init__.py", line 558, in __init__ raise TemplateSyntaxError, "Could not parse the remainder: %s" % token[upto:] TemplateSyntaxError: Could not parse the remainder: "#text" So how can I use this in the template? I've tried putting quotes around it but to no avail. I'd like to not modify the dictionary if possible, but if its easy enough to do then I guess its okay. Thanks

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  • How to add ACTIVE DOMAIN user to Sharepoint group

    - by standley-nguyen
    Hi all. I got an exception when executing this snippet code SPSecurity.RunWithElevatedPrivileges(delegate() { using (SPSite site = new SPSite(siteUrl.Trim())) { using (SPWeb web = site.OpenWeb()) { try { web.AllowUnsafeUpdates = true; SPUser spUser = web.AllUsers[userName]; if (spUser != null) { SPGroup spGroup = web.Groups[groupName]; if (spGroup != null) spGroup.AddUser(spUser); } } catch (Exception ex) { this.TraceData(LogLevel.Error, "Error at function Named [AddUserToSPGroupWidget.AddUserToGroup] . With Error Message: " + ex.ToString()); } finally { web.AllowUnsafeUpdates = false; } } } }); PLease guide me. Thanks in advance.

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  • ImportError and Django driving me crazy

    - by John Peebles
    OK, I have the following directory structure (it's a django project): - project -- app and within the app folder, there is a scraper.py file which needs to reference a class defined within models.py I'm trying to do the following: import urllib2 import os import sys import time import datetime import re import BeautifulSoup sys.path.append('/home/userspace/Development/') os.environ['DJANGO_SETTINGS_MODULE'] = 'project.settings' from project.app.models import ClassName and this code just isn't working. I get an error of: Traceback (most recent call last): File "scraper.py", line 14, in from project.app.models import ClassName ImportError: No module named project.app.models This code above used to work, but broke somewhere along the line and I'm extremely confused as to why I'm having problems. On SnowLeopard using python2.5.

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  • Generating code for service proxies

    - by Hadi Eskandari
    I'm trying to generate some additional code base on the auto-generated webservice proxies in my VS2010 solution, I'm using a T4 template to do so. The problem is, automatically generated proxies are added in "Service Reference" folder but ProjectItems (files) are hidden by default and the following code does not find them in the project structure: var sr = GetProjectItem(project, "Service References"); if(sr != null) { foreach(ProjectItem item in sr.ProjectItems) { foreach(var file in item.ProjectItems) { //Services.Add(new ServiceInfo { Name = file.Name }); } } } The above code runs and although service reference is found, and there are ProjectItems under that node (named by the webservice reference name), under object under that node is of type System.__ComObject and I'm not sure how to progress. Any help is appreciated.

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  • How to rewrite url to include subdirectory?

    - by Jason Roberts
    The following set of rewrite rules rewrite any urls formatted as foo.mydomain.com/bar to mydomain.com/mysubs/foo/bar.php. This all works fine except if I have a subdirectory named 'blah' in the original url such as foo.mydomain.com/blah/bar, then it will rewrite it as mydomain.com/mysubs/foo/bar (without the blah subdirectory) when what I need is the url to be rewritten as mydomain.com/mysubs/foo/blah/bar. So, what do I need to change to make this work correctly? Options +FollowSymLinks Options -Indexes RewriteEngine On RewriteBase / RewriteCond %{HTTP_HOST} !www.mydomain.com$ [NC] RewriteCond %{HTTP_HOST} ^([^./]+)\.mydomain\.com$ RewriteRule !^mysubs/ mysubs/%1%{REQUEST_URI} [L] RewriteCond %{REQUEST_FILENAME} !-d RewriteCond %{REQUEST_FILENAME}\.php -f RewriteRule ^(.*)$ $1.php

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  • to change the style of div

    - by ramyatk06
    hi guys, I have 2 buttons and 2 divs div1 and div2.On click button1 div1 is made visible and div2 invisible,On clicking button2 div2 is made visible and div1 is invisible. For that i used javascript. function showdiv2() { document.getElementById("div2").style.visibility="visible"; document.getElementById("div2").style.display="inline"; document.getElementById("div1").style.visibility="hidden"; document.getElementById("div1").style.display = "none"; document.getElementById("lbl_msg").innerHTML = "" } function showdiv1() { document.getElementById("div1").style.visibility="visible"; document.getElementById("div1").style.display="inline"; document.getElementById("div2").style.visibility="hidden"; document.getElementById("div2").style.display = "none"; document.getElementById("lbl_msg").innerHTML = "" } In div2 i have a gridview in which i have a linkbutton named lnkDelete.In its click control is going to div1.In click of lnkDelete,i want to make div1 invisible,but on clicking button1 div1 should be visible.Can anybody help to make div1 invisible in clickevent of lnkDelete in codebehind?

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  • Replication - User defined table type not propogating to subscriber

    - by Aamod Thakur
    I created a User defined table type named tvp_Shipment with two columns (id and name) . generated a snapshot and the User defined table type was properly propogated to all the subscribers. I was using this tvp in a stored procedure and everything worked fine. Then I wanted to add one more column created_date to this table valued parameter.I dropped the stored procedure (from replication too) and also i dropped and recreated the User defined table type with 3 columns and then recreated the stored procedure and enabled it for publication When i generate a new snapshot, the changes in user defined table type are not propogated to the subscriber. The newly added column was not added to the subscription. the Error messages: The schema script 'usp_InsertAirSa95c0e23_218.sch' could not be propagated to the subscriber. (Source: MSSQL_REPL, Error number: MSSQL_REPL-2147201001) Get help: http://help/MSSQL_REPL-2147201001 Invalid column name 'created_date'. (Source: MSSQLServer, Error number: 207) Get help: http://help/207

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  • Is it magic or what ??

    - by STRIDER
    I am writing a big C code... The code includes recursive bactracking function named Branch() that is called so much... My goal is to write the fastest code to get the best running time... I also have another function Redundant() void Redundant() { int* A; A=(int*)malloc(100*sizeof(int)); } I created two versions. Version A: Redundant() is included in Branch(). Version B: Redundant() is not included in Branch() A run 10 times faster than B !!!! Is is Magic or is it kind of process scheduling or what ??

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  • How can I compare my PHPASS-hashed stored password to my incoming POST data?

    - by Ygam
    Here's a better example, just a simple checking..stored value in database has password: fafa (hashed with phpass in registration) and username: fafa; i am using the phpass password hashing framework public function demoHash($data) //$data is the post data named password { $hash =new PasswordHash(8, false); $query = ORM::factory('user'); $result = $query ->select('username, password') ->where('username', 'fafa') ->find(); $hashed = $hash->HashPassword($data); $check = $hash->CheckPassword($hashed, $result->password); echo $result->username . "<br/>"; echo $result->password . "<br/>"; return $check; } check is returning false

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  • Handling duplicate nodes in XML

    - by JYelton
    Scenario: I am parsing values from an XML file using C# and have the following method: private static string GetXMLNodeValue(XmlNode basenode, string strNodePath) { if (basenode.SelectSingleNode(strNodePath) != null) return (basenode.SelectSingleNode(strNodePath).InnerText); else return String.Empty; } To get a particular value from the XML file, I generally pass the root node and a path like "parentnode/item" I recently ran into an issue where two nodes at the same document level share the same name. Question: What is the best way to get the values for duplicate-named nodes distinctly? My thought was to load all values matching the node name into an array and then using the array index to refer to them. I'm not sure how to implement that, though. (I'm not well-versed in XML navigation.)

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  • How can I pipe a large amount of data as a runtime argument?

    - by Zombies
    Running an executable JAR on a linux platform here. The program it self works on a somewhat large amount of data, basically a list of URLs... could be up to 2k. Currently I get this from a simple DB call. But I was thinking that instead of creating a new mode and writing SQL to get a new result set and having to redploy everytime, I could just make the program more robust by passing in the result set (the list of URLs) that need to be worked on... so, within a linux environment, is there a pain-free/simple way to get the result set and pass it in dynamically? I know file i/o is one, but it doesn't seem to be effecient because each file has to be named, as well more logic to handle grabbing the correct file, creating a file with a unique name, etc.

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  • django m2m how can i get m2m table elements in a view

    - by dana
    i have a model using m2m feature: class Classroom(models.Model): user = models.ForeignKey(User, related_name = 'classroom_creator') classname = models.CharField(max_length=140, unique = True) date = models.DateTimeField(auto_now=True) open_class = models.BooleanField(default=True) members = models.ManyToManyField(User,related_name="list of invited members", through = 'Membership') and i want to take all members of one class in a view and display them using the template system. In the view, i'm trying to take all the members from a classroom like that: def inside_classroom(request,classname): try: theclass = Classroom.objects.get(classname = classname) members = Members.objects.all() etc but it doesn't work,(though the db_table is named Classroom_Members) i guess i have to use another query for getting all the members from the classroom classname. also, i want to verify if the request.user is a member using (if request.user in members) how can i het those members? Thanks in advance!

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  • getting core file

    - by ashwani66476
    Hello All I am running a Core JAVA application on AIX machine, and it creates a file named "core". My concern are 1. I am not able to open this "core" file in "Heap Analyzer" or "Thread Analyzer". 2. Which tools do I need to use, So that I can analyze this "core" file. 3. Could any one elaborate more about this file? why this "core" file creates. Waiting for response..... Many Thanks

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  • How to configure git repository so a branch other than master is checked out after a cloning?

    - by Suraj Barkale
    I am trying to set up a git server with bunch of repositories. I am planning to use the branching model described in http://nvie.com/git-model article. So I will have at least two branches (named master and develop) in the repository. After a clone the master branch is checked out by git. Is there a git config option so that develop branch will be checked out instead? In effect I want git clone my_repo_url to behave as git clone -b develop my_repo_url.

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  • How to change order in ordered+persisted collection?

    - by Jaroslav Záruba
    I just need to change order of items in a (previously persisted) ordered collection... I tried simply passing the re-arranged collection to a setter: after committing a transaction the collection is gone. Then I tried to clear() the existing collection and addAll() afterwards: clear() makes persistent manager to mark all the elements as deleted. (But obviously I would like to be able to work with the collection items in the very transaction.) (The collection is not in a default fetch group, so I tried the above also with the named fetch group added into the fetch plan. No luck.) This must be the most stupid question, but I ran out of ideas and I'm stuck here two days already. I swear I googled. :(

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  • deserialization on client sied in Domain Service

    - by ankit
    i have 2 classes. Person and Contact. Person class has property named "ContactNumber" which returns the Contact type, and this property is marked as "Datamember" for serialization. i have marked Contact type as "DAtaContract". on client side i am able to get the values, but when i try to insert a value and then do submit, i get the below exception. Failed to deserialize change-set. Failed to convert value of type 'Dictionary`2' to type 'Contact' Stack Trace is: at System.Web.Ria.DataServiceSubmitRequest.GetChangeSet(DomainService domainService) at System.Web.Ria.DataServiceSubmitRequest.Invoke(DomainService domainService) at System.Web.Ria.DataService.System.Web.IHttpHandler.ProcessRequest(HttpContext context) can anyone give me the solution ?

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  • Trees and macros with tikz

    - by Tsf
    I am trying to build my trees using macros but I don't get the result I want. Here is a minimal example: \documentclass{article} \usepackage{tikz} \usetikzlibrary{trees} \newcommand{\LeafNode}[1]{% child {node {#1}} } \newcommand{\InnerNode}[3]{% child {node {#3} #1 #2 } } \begin{document} \begin{tikzpicture} \node (A) {A} \LeafNode{B} \LeafNode{C} ; \end{tikzpicture}% \hspace{2cm}% \begin{tikzpicture} \node (A) {A} \InnerNode{\LeafNode{D}}{\LeafNode{E}}{B} \LeafNode{C} ; \end{tikzpicture} \end{document} I expected this to produce two trees: A A / \ / \ B C B C / \ D E but I am getting: A | A B | | B D | | C C Am I missing something or there is no way to do it? BTW, if I omit the label on my root node, I get a PGF error: ! Package pgf Error: No shape named is known. -- Tsf

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  • how to link table to table

    - by Niño Seymour L. Rodriguez
    I am a comsci student and I'm taking up database now. I got a problem in or should I say I dont know how to link table to table. It is not like you'll just use a foreign key and connect it to the primary key. The outcome should be like this: In the table Course there are three fields namely "course_id", "Description" and "subjects". When you click the name field Subject, a table named Subject should appear. Can you help me with this? hope you understnd my grammar, hehe..im not good in english......it will be a big help if you can answer it.........thank you po..............

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  • Haskell Syntax: Parse Error On Input

    - by NuNu
    As part of a mini-haskell compiler that I'm writing, I have a function named app. What I want this function to do is take in these arguments epp (App e1 e2). The first step would be to evaluate e1 recursively (epp e1) and check if the output would be an error. If not then evaluate e2 and then call another function eppVals to evaluate the outputs of the calls on e1 and e2 which I defined as v1 and v2 respectively. epp (App e1 e2) | epp e1 /= Error = eppVals v1 v2 | otherwise = Error where v1 = epp e1 v2 = epp e2 <- parse error on input `=' Logically I believe what I have written so far works but I'm getting a parse error on input = where I stated above. Any idea why? My second try epp :: Exp -> Error Val epp (App e1 e2) = (eppVals v1 v2) where v1 = (epp e1) v2 = (epp e2) But now throws Couldn't match expected type Val with actual type Error Val

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  • Python: Dynamic attribute name generation without exec() or eval()

    - by PyNewbie27
    Hi, I'm trying to dynamically create buttons at runtime with PyQT4.7 However, this being my first python program I'm not sure how to get the functionality I want. I would like to be able to substitute a text string for an attribute name: i.e. for each in xrange(4): myname = "tab1_button%s" % each #tab1_button0, tab1_button1, tab1_button2 #self.ui.tab1_button0 = QtGui.QPushButton(self.ui.tab) <--normal code to create a named button setattr(self.ui,myname,QtGui.QPushButton(self.ui.tab)) #rewrite of line above to dynamicly generate a button #here's where I get stuck. this code isn't valid, but it shows what i want to do self.ui.gridLayout.addWidget(self.ui.%s) % myname #I need to have %s be tab1_button1, tab1_button2, etc. I know the % is for string substituion but how can I substitute the dynamically generated attribute name into that statement? I assume there's a basica language construct I'm missing that allows this. Since it's my first program, please take it easy on me ;)

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  • Import boto from local library

    - by ensnare
    I'm trying to use boto as a downloaded library, rather than installing it globally on my machine. I'm able to import boto, but when I run boto.connect_dynamodb() I get an error: ImportError: No module named dynamodb.layer2 Here's my file structure: project/ project/ __init__.py libraries/ __init__.py flask/ boto/ views/ .... modules/ __init__.py db.py .... templates/ .... static/ .... runserver.py And the contents of the relevant files as follows: project/project/modules/db.py from project.libraries import boto conn = boto.connect_dynamodb( aws_access_key_id='<YOUR_AWS_KEY_ID>', aws_secret_access_key='<YOUR_AWS_SECRET_KEY>') What am I doing wrong? Thanks in advance.

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  • Class Not found exception in JApplet.

    - by Nitesh Panchal
    Hello, I created a simple Applet using JApplet and everything seems to work fine but as soon i create an object of my userdefined class named ChatUser in my applet, i get this error :- SEVERE: java.lang.ClassNotFoundException: applet.ChatUser at com.sun.enterprise.loader.ASURLClassLoader.findClassData(ASURLClassLoader.java:713) at com.sun.enterprise.loader.ASURLClassLoader.findClass(ASURLClassLoader.java:626) at java.lang.ClassLoader.loadClass(ClassLoader.java:307) at java.lang.ClassLoader.loadClass(ClassLoader.java:252) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:320) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:247) at java.io.ObjectInputStream.resolveClass(ObjectInputStream.java:604) at java.io.ObjectInputStream.readNonProxyDesc(ObjectInputStream.java:1575) at java.io.ObjectInputStream.readClassDesc(ObjectInputStream.java:1496) at java.io.ObjectInputStream.readOrdinaryObject(ObjectInputStream.java:1732) at java.io.ObjectInputStream.readObject0(ObjectInputStream.java:1329) at java.io.ObjectInputStream.readObject(ObjectInputStream.java:351) at misc.ChatClient.run(ChatClient.java:43) Any idea what can be wrong? It only happens when i create an object of any user defined class. Do i need to set some security settings or something? Please help :(

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  • Ruby get inheriting class

    - by Brian D.
    I'm working on creating my first plugin for rails. I'm still pretty new to ruby and I was wondering if its possible to get the inheriting class? For example, I'm trying to create a plugin that will allow unit testing and functional testing when you are not using migrations. What I'm trying to do is initialize a class variable named controller to be initialized to the type of controller that is being tested. If I have a base class ControllerTest: class ControllerTest < Test::Unit::TestCase attr_accessor :controller def initialize super @controller = "call function that will find the inheriting classes name and create an instance of that controller type." end end So what I'm currently stuck on is getting the name of the inheriting class. Is this possible? And if not, does anyone know another way on how I could go about implementing this? Thanks in advance.

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  • drupal body class

    - by anru
    drupal version is 6. just want to know where are those $body_classes comes form. I knew in template_preprocess_page , there is a variable called 'body_classes'. but my problem is, not all body_classes are come from preprocess page. for instance: I have a term named 'activities and attractions', then in my page.tpl.php, there is a class 'page-activities and attractions' in my tag. looks like taxonomy module generates a body_class, but i could find it after search seource code of taxonomy module.

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