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  • Major Steps of SEO

    In modern world, we find that web marketing is gaining an increased foothold potential. Every organization aims at increasing the number of customers through online promotion and advertising. It can be achieved through higher ranking of the websites in the search engine. The websites which rank high in the search engine will definitely get a good number of visits by the searchers than the other sources.

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  • Tuxedo Load Balancing

    - by Todd Little
    A question I often receive is how does Tuxedo perform load balancing.  This is often asked by customers that see an imbalance in the number of requests handled by servers offering a specific service. First of all let me say that Tuxedo really does load or request optimization instead of load balancing.  What I mean by that is that Tuxedo doesn't attempt to ensure that all servers offering a specific service get the same number of requests, but instead attempts to ensure that requests are processed in the least amount of time.   Simple round robin "load balancing" can be employed to ensure that all servers for a particular service are given the same number of requests.  But the question I ask is, "to what benefit"?  Instead Tuxedo scans the queues (which may or may not correspond to servers based upon SSSQ - Single Server Single Queue or MSSQ - Multiple Server Single Queue) to determine on which queue a request should be placed.  The scan is always performed in the same order and during the scan if a queue is empty the request is immediately placed on that queue and request routing is done.  However, should all the queues be busy, meaning that requests are currently being processed, Tuxedo chooses the queue with the least amount of "work" queued to it where work is the sum of all the requests queued weighted by their "load" value as defined in the UBBCONFIG file.  What this means is that under light loads, only the first few queues (servers) process all the requests as an empty queue is often found before reaching the end of the scan.  Thus the first few servers in the queue handle most of the requests.  While this sounds non-optimal, in fact it capitalizes on the underlying operating systems and hardware behavior to produce the best possible performance.  Round Robin scheduling would spread the requests across all the available servers and thus require all of them to be in memory, and likely not share much in the way of hardware or memory caches.  Tuxedo's system maximizes the various caches and thus optimizes overall performance.  Hopefully this makes sense and now explains why you may see a few servers handling most of the requests.  Under heavy load, meaning enough load to keep all servers that can handle a request busy, you should see a relatively equal number of requests processed.  Next post I'll try and cover how this applies to servers in a clustered (MP) environment because the load balancing there is a little more complicated. Regards,Todd LittleOracle Tuxedo Chief Architect

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  • How to write Bash scribt to open two different terminals

    - by Ahmed Zain El Dein
    How to write Bash script to open two different taped terminal ,and write in both of them commands separately to be executed unrelationally for instance : Terminal number one open skype terminal number two open in the end , i want one more thing , can i write in the bash script my skype username and password to put them in skype when open it in terminal one automatically then login too Thanks

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  • Oracle PSRM V2.4.0 Portuguese UI Now Available

    - by Paula Speranza-Hadley
    This provides a Portuguese user interface (UI) language pack for Oracle PSRM v2.4.0  Please note, this language pack translates the PSRM UI (user interface) to Iberian Portuguese. Language Patch Download: To download the ESA language pack please log in to My Oracle Support http://support.oracle.com/. Select the Patches and Updates tab Type in the Patch number: 18916310 Click the Patch number Download using the yellow download button on the right hand side

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  • Cumulative Updates available for SQL Server 2008 R2

    - by AaronBertrand
    Today the SQL Server Release Services Team has pushed out new cumulative updates for SQL Server 2008 R2: Cumulative Update #14 for SQL Server 2008 R2 RTM - KB article http://support.microsoft.com/kb/2703280 - build number 10.50.1817.0 - 7 fixes - relevant for builds between 10.50.1600 and 10.50.1816 Cumulative Update #7 for SQL Server 2008 R2 Service Pack 1 - KB article http://support.microsoft.com/kb/2703282 - build number 10.50.2817.0 - 24 fixes - relevant for builds between 10.50.2500 and 10.50.2816...(read more)

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  • MySQL Input Parameters Add Flexibility to Crosstab Stored Procedures

    When generating a result set where the query contains an unknown number of column and/or row values we can use a combination of Prepared Statements, which allows us to tailor the output based on the number of data values. We can also add input parameters to a procedure to assign the field names, aliases, and even the aggregate function!

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  • MySQL Input Parameters Add Flexibility to Crosstab Stored Procedures

    When generating a result set where the query contains an unknown number of column and/or row values we can use a combination of Prepared Statements, which allows us to tailor the output based on the number of data values. We can also add input parameters to a procedure to assign the field names, aliases, and even the aggregate function!

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  • java.net outage

    - by alexismp
    The GlassFish website has been down for a number of hours (together with a number of other projects) as a result of a general outage in the java.net datacenter. The team is working hard on getting everything back to normal. You can track progress by following @ProjectKenai. Update: services should now all be back to normal. If you face java.net issues in the future, consider reporting them here. And now, back to work!

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  • Algorithm to find average position

    - by Simran kaur
    In the given diagram, I have the extreme left and right points, that is -2 and 4 in this case. So, obviously, I can calculate the width which is 6 in this case. What we know: The number of partitions:3 in this case The partition number at at any point i.e which one is 1st,second or third partition (numbered starting from left) What I want: The position of the purple line drawn which is positio of average of a particular partition So, basically I just want a generalized formula to calculate position of the average at any point.

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  • December 2012 Cumulative Updates are available for SQL Server 2008 R2

    - by AaronBertrand
    Microsoft released new cumulative updates for SQL Server. SQL Server 2008 R2 Service Pack 1 Cumulative Update # 10 KB Article: KB #2783135 16 fixes are listed at the time of publication Build number is 10.50.2868 Relevant for @@VERSION 10.50.2500 through 10.50.2867 SQL Server 2008 R2 Service Pack 2 Cumulative Update # 4 KB Article: KB #2777358 34 fixes are listed at time of publication Build number is 10.50.4270 Relevant for @@VERSION 10.50.4000 through 10.50.4269 My usual disclaimer: these updates...(read more)

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  • How can I tell if I am out of inotify watches?

    - by Jorge Castro
    I use an application that consumes inotify watches. I've already set fs.inotify.max_user_watches=32768 in /etc/sysctl.conf but last night the application stopped indexing unless I ran it manually, which leads me to suspect I am out of watches. Since I don't know what the trade off is when I increase this number (does it consume more RAM?), I don't know if I should just increase this number, so I'd like to know if there's a way I can tell if it's using all these watches and what the tradeoffs might be for increasing it.

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  • Best practice for marking a bug as resolved in Bugzilla ?

    - by Vincent B.
    I am wondering what is the best way to handle the situation of marking a bug as resolved and providing a version of component/product in which this fix can be found. Context For a project I am working on, we are using Bugzilla for issue tracking, and we have the following: A product "A" with a version number like vA.B.C.D, This product "A" have the following components: Component "C1" with a version number like vA.B.C.D, Component "C2" with a version number like vA.B.C.D, Component "C3" with a version number like vA.B.C.D. Internally we keep track of which component versions have been used to generate the product A version vA.B.C.D. Example: Product "A" version v1.0.0.0 has been produced from component "C1" v1.0.0.3, component "C2" v1.3.0.0 and component "C3" v2.1.3.5. And Product "A" version v1.0.1.0 has been produced from component "C1" v1.0.0.4, component "C2" v1.3.0.0 and component "C3" v2.1.3.5. Each component is a SVN repository. The person in charge of generating the product "A" have only access to the different components tags folder in SVN, and not the trunk of each component repository. Problem Now the problem is the following, when a bug is found in the product "A", and that the bug is related to Component "C1", the version of product "A" is chosen (e.g. v1.0.0.0), and this version allow the developer to know which version of component "C1" has the bug (here it will be v1.0.0.3). A bug report is created. Now let's say that the developer responsible for component "C1" corrects the bug, then when the bug seems to be fixed and after some test and validation, the developer generates a new tag for component "C1", with the version v1.0.0.4. At this time, the developer of component "C1" needs to update the bug report, but what is the best to do: Mark the bug as resolved/fixed and add a comment saying "This bug has been fixed in the tags v1.0.0.4 of C1 component" ? Keep the bug as assigned, add a comment saying "This bug has been fixed in the tags v1.0.0.4 of C1 component, update this bug status to resolved for the next version of the product that will be generated with the newest version (v1.0.0.4 of C1)" ? Another possible way to deal with this problem. Right now the problem is that when a product component CX is fixed, it is not sure in which future version of the product A it will be included, so it is for me not possible to say in which version of the product it will be solved, but it is possible to say in which version of the Component CX it has been solved. So when do we need to mark a bug as solved, when the product A version include the fixed version of CX, or only when CX component has been fixed ? Thanks for your personal feedback and ideas about this !

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  • A lot of "(direct) / (none)" traffic in Google Analytics

    - by Yoga
    my web site has a lot of "(direct) / (none)" traffic (over 50%) in Google Analytics, but under the "Audience", 100% are new visitors, why is that? I am quite sure most of the Audience should be new visitor, but why so many "(direct) / (none)" traffic? Update: Actually we have launch a new site which this number drop significantly, so I am interested in knowing why the number was so high in the past.

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  • Best practice while marking a bug as resolved with Bugzilla (versioning of product and components)

    - by Vincent B.
    I am wondering what is the best way to handle the situation of marking a bug as resolved and providing a version of component/product in which this fix can be found. Context For a project I am working on, we are using Bugzilla for issue tracking, and we have the following: A product "A" with a version number like vA.B.C.D, This product "A" have the following components: Component "C1" with a version number like vA.B.C.D, Component "C2" with a version number like vA.B.C.D, Component "C3" with a version number like vA.B.C.D. Internally we keep track of which component versions have been used to generate the product A version vA.B.C.D. Example: Product "A" version v1.0.0.0 has been produced from component "C1" v1.0.0.3, component "C2" v1.3.0.0 and component "C3" v2.1.3.5. And Product "A" version v1.0.1.0 has been produced from component "C1" v1.0.0.4, component "C2" v1.3.0.0 and component "C3" v2.1.3.5. Each component is a SVN repository. The person in charge of generating the product "A" have only access to the different components tags folder in SVN, and not the trunk of each component repository. Problem Now the problem is the following, when a bug is found in the product "A", and that the bug is related to Component "C1", the version of product "A" is chosen (e.g. v1.0.0.0), and this version allow the developer to know which version of component "C1" has the bug (here it will be v1.0.0.3). A bug report is created. Now let's say that the developer responsible for component "C1" corrects the bug, then when the bug seems to be fixed and after some test and validation, the developer generates a new tag for component "C1", with the version v1.0.0.4. At this time, the developer of component "C1" needs to update the bug report, but what is the best to do: Mark the bug as resolved/fixed and add a comment saying "This bug has been fixed in the tags v1.0.0.4 of C1 component" ? Keep the bug as assigned, add a comment saying "This bug has been fixed in the tags v1.0.0.4 of C1 component, update this bug status to resolved for the next version of the product that will be generated with the newest version (v1.0.0.4 of C1)" ? Another possible way to deal with this problem. Right now the problem is that when a product component CX is fixed, it is not sure in which future version of the product A it will be included, so it is for me not possible to say in which version of the product it will be solved, but it is possible to say in which version of the Component CX it has been solved. So when do we need to mark a bug as solved, when the product A version include the fixed version of CX, or only when CX component has been fixed ? Thanks for your personal feedback and ideas about this !

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  • How to set the monitor to its native resolution when xrandr approach isn't working?

    - by Krishna Kant Sharma
    I am trying to setup my Samsung syncmaster B2030 monitor in ubuntu 12.04. It's native resolution is 1600x900 which I am not getting in ubuntu and which I am trying to get. I tried using xrandr approach provided in these urls: 1) http://www.ubuntugeek.com/how-change-display-resolution-settings-using-xrandr.html 2) How to set the monitor to its native resolution which is not listed in the resolutions list? S1) I used cvt 1600 900 60 to get the modeline. Output was: # 1600x900 59.95 Hz (CVT 1.44M9) hsync: 55.99 kHz; pclk: 118.25 MHz Modeline "1600x900_60.00" 118.25 1600 1696 1856 2112 900 903 908 934 -hsync +vsync S2) I then used xrandr and output was: Screen 0: minimum 8 x 8, current 1152 x 864, maximum 8192 x 8192 DVI-I-0 disconnected (normal left inverted right x axis y axis) VGA-0 connected 1152x864+0+0 (normal left inverted right x axis y axis) 0mm x 0mm 1024x768 60.0 + 1360x768 60.0 59.8 1152x864 60.0* 800x600 72.2 60.3 56.2 680x384 119.9 119.6 640x480 59.9 512x384 120.0 400x300 144.4 320x240 120.1 DVI-I-1 disconnected (normal left inverted right x axis y axis) HDMI-0 disconnected (normal left inverted right x axis y axis) which gave me "VGA-0". S3) Then I used xrandr --newmode "1600x900_60.00" 118.25 1600 1696 1856 2112 900 903 908 934 -hsync +vsync But instead of adding the modeline it just threw an error: X Error of failed request: BadName (named color or font does not exist) Major opcode of failed request: 153 (RANDR) Minor opcode of failed request: 16 (RRCreateMode) Serial number of failed request: 29 Current serial number in output stream: 29 My system details: 1) ubuntu 12.04 LTS 2) Graphic card: GeForce 9400 GT/PCIe/SSE2 (driver is successfully installed. I am checking it in System Settings Details. And it's showing that driver is installed and its "GeForce 9400 GT/PCIe/SSE2") 3) Monitor: Samsung syncmaster B2030 4) Resolutions I am getting: 800x600 1024x768 1152x864 (I am currently using this one) 1360x768 (this one isn't working properly) Does anyone know what I can do? Thanks in advance. UPDATE (1): Today I tried it again. And adding a modeline (using --newmode) worked. But when I used --addmode by: xrandr --addmode VGA-0 1600x900_60.00 It gave this error: X Error of failed request: BadMatch (invalid parameter attributes) Major opcode of failed request: 153 (RANDR) Minor opcode of failed request: 18 (RRAddOutputMode) Serial number of failed request: 29 Current serial number in output stream: 30

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  • SEO Hosting Companies

    There have been a great number of Hosting SEO Companies being set up across the world and their contribution to the internet marketing society has been well accredited. As a result, the number of SEO Hosting Companies being set up on the internet itself has been on the rise given that the web world is the best outsourced IT hub.

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  • Sorting data in the SSIS Pipeline (Video)

    In this post I want to show a couple of ways to order the data that comes into the pipeline.  a number of people have asked me about this primarily because there are a number of ways to do it but also because some components in the pipeline take sorted inputs.  One of the methods I show is visually easy to understand and the other is less visual but potentially more performant.

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  • SQL Server 2008 R2 Cumulative Update 8 now available

    - by Greg Low
    CU8 is now available for SQL Server 2008 R2. You will find it here: http://support.microsoft.com/kb/2534352/en-us It includes the following fixes: VSTS bug number KB article number Description 726734 2522893 (http://support.microsoft.com/kb/2522893/ ) FIX: A backup operation on a SQL Server 2008 or SQL Server 2008 R2 database fails if you enable change tracking on this database 730658 2525665 (http://support.microsoft.com/kb/2525665/ ) FIX: SQL Server 2008 BIDS stops responding when you stop debugging...(read more)

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  • Zelda-style Top-down RPG. Storing data for each tile type

    - by Delerat
    I'm creating a Zelda-style RPG using Tiled, C#, and MonoGame. When my code parses the .tmx file, it will get a number to associate with each tile type based off of their position in the tile sheet. If I ever need to change my sprite sheet, this number will change for many of the tiles. How can I guarantee that when I parse my .tmx file, I will be able to know exactly what tile type I'm getting so that I can associate the proper data with it(transparency, animated, collision, etc.)?

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  • Why is Internet Explorer the only browser to be referred to by version when talking about compatibility?

    - by Rue Leonheart
    Whenever I read something or hear someone talking about HTML5, CSS and JavaScript support, they always refer to Internet Explorer with the version number such as Internet Explorer 6, and Internet Explorer 9. But they only refer to Google Chrome, Firefox, Safari and others without version numbers. Shouldn't they also specify the version number in which certain web technologies are incompatible for other browsers instead of just Internet Explorer?

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  • Issues with LVM partition size in Server 13.04

    - by Michael
    I am new to ubuntu and a little confused about how hard drive partitions and LVM works. I remember setting up Ubuntu server 13.04 and telling to to use 1TB of a 3TB server. Well I have maxed that out with blu-ray rips and want the rest of the drive for space. On log-in it says: System load: 2.24 Processes: 179 Usage of /: 88.7% of 912.89GB Users logged in: 0 Memory usage: 6% IP address for p5p1: 192.168.0.100 Swap usage: 0% => / is using 88.7% of 912.89GB lvdisplay outputs: --- Logical volume --- LV Path /dev/DeathStar-vg/root LV Name root VG Name DeathStar-vg LV Write Access read/write LV Creation host, time DeathStar, 2013-05-18 22:21:11 -0400 LV Status available # open 1 LV Size 2.70 TiB Current LE 707789 Segments 2 Allocation inherit Read ahead sectors auto - currently set to 256 Block device 252:0 --- Logical volume --- LV Path /dev/DeathStar-vg/swap_1 LV Name swap_1 VG Name DeathStar-vg LV Write Access read/write LV Creation host, time DeathStar, 2013-05-18 22:21:11 -0400 LV Status available # open 2 LV Size 3.75 GiB Current LE 959 Segments 1 Allocation inherit Read ahead sectors auto - currently set to 256 Block device 252:1 vgdisplay outputs: VG Name DeathStar-vg System ID Format lvm2 Metadata Areas 1 Metadata Sequence No 4 VG Access read/write VG Status resizable MAX LV 0 Cur LV 2 Open LV 2 Max PV 0 Cur PV 1 Act PV 1 VG Size 2.73 TiB PE Size 4.00 MiB Total PE 715335 Alloc PE / Size 708748 / 2.70 TiB Free PE / Size 6587 / 25.73 GiB df outputs: Filesystem 1K-blocks Used Available Use% Mounted on /dev/mapper/DeathStar--vg-root 957238932 848972636 59634696 94% / none 4 0 4 0% /sys/fs/cgroup udev 1864716 4 1864712 1% /dev tmpfs 374968 1060 373908 1% /run none 5120 4 5116 1% /run/lock none 1874824 148 1874676 1% /run/shm none 102400 24 102376 1% /run/user /dev/sda2 234153 56477 165184 26% /boot And fdisk /dev/sda -l outputs: Disk /dev/sda: 3000.6 GB, 3000592982016 bytes 255 heads, 63 sectors/track, 364801 cylinders, total 5860533168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x00000000 Device Boot Start End Blocks Id System /dev/sda1 1 4294967295 2147483647+ ee GPT Partition 1 does not start on physical sector boundary. I just don't know what to make of all this and am not sure how I can make it use all 2.73TBs. Thanks in advance for any help. EDIT-- Yes I did make changes to the LVM Config, but it didnt do anything. As requested, output of parted -l /dev/sda Model: ATA WDC WD30EFRX-68A (scsi) Disk /dev/sda: 3001GB Sector size (logical/physical): 512B/4096B Partition Table: gpt Number Start End Size File system Name Flags 1 1049kB 2097kB 1049kB bios_grub 2 2097kB 258MB 256MB ext2 3 258MB 3001GB 3000GB lvm Model: ATA WDC WD30EFRX-68A (scsi) Disk /dev/sdb: 3001GB Sector size (logical/physical): 512B/4096B Partition Table: msdos Number Start End Size Type File system Flags Model: Linux device-mapper (linear) (dm) Disk /dev/mapper/DeathStar--vg-swap_1: 4022MB Sector size (logical/physical): 512B/4096B Partition Table: loop Number Start End Size File system Flags 1 0.00B 4022MB 4022MB linux-swap(v1) Model: Linux device-mapper (linear) (dm) Disk /dev/mapper/DeathStar--vg-root: 2969GB Sector size (logical/physical): 512B/4096B Partition Table: loop Number Start End Size File system Flags 1 0.00B 2969GB 2969GB ext4

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  • Configurable tables in sql database

    - by dot
    I have the following tables in my database: Config Table: ====================================== Start_Range | End Range | Config_id 10 | 15 | 1 ====================================== Available_UserIDs ========================== ID | UserID | Used_YN | 1 | 10 | t | 1 | 11 | f | 1 | 12 | f | 1 | 13 | f | 1 | 14 | f | 1 | 15 | f | ========================== Users ========================== UserId | FName | LName | 10 |John | Doe | ========================== This is used in a reservation system of sorts... which lets an administrator specify a range of numbers that will be assigned to users in the config table. Once the range has been defined, the system then populates the Available_userIDs table with all the numbers in between the range, and sets the Used_YN flag to false As users sign up, they grab the next user_id number that's not in use... and reserve it. Then the system adds a record to the Users table. Once the admin has specified a range, it is possible that they can change it. For example, they can start with 10-15... and then when the range is used up, they should be able to specify another range like 16 - 99. I've put a unique constraint on the Available_UserIDs table, as well as on the Users table - to ensure that UserIds can't be duplicated. My questions are as follows: What's the best way to prevent the admins from using a range that's already in use? I thought of the following options: -- check either the Users table to see if the start range or ending range numbers are being used. If they are, assume that all the numbers in between are in use too, and reject the range. -- let them specify whatever they want, try to populate the Available_UserIDs table. If there are duplicates, just ignore that specific error message from the database and continue on. How do I find gaps in the number ranges? For example, if they specify 10-15, and then 20-25, it'd be nice to be able to somehow suggest on my web page that 16-19 is currently available. I found this article: http://stackoverflow.com/questions/1312101/how-to-find-a-gap-in-running-counter-with-sql But it only seems to return the first available number... so in my example above, it would only return the number 16. I'm sure there's a simpler way to do things that I'm overlooking!

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  • Search for duplicate prefix of file names

    - by Mia
    I have a folder contains files name as: xxx.get.txt and xxx.resp.txt xxx.get.txt, xxx.resp.txt yyy.get.txt, yyy.resp.txt zzz.get.txt, zzz.resp.txt, etc each prefix xxx should have two corresponding files, .get.txt and .resp.txt However, now I calculate the number of .get.txt and the number of .resp.txt files, they are not equal, there're ten more .get.txt. I want to find out, which .get.txt files do not have ´.resp.txt´ file Is it possible? Many thanks!

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  • Need help on a problemset in a programming contest

    - by topher
    I've attended a local programming contest on my country. The name of the contest is "ACM-ICPC Indonesia National Contest 2013". The contest has ended on 2013-10-13 15:00:00 (GMT +7) and I am still curious about one of the problems. You can find the original version of the problem here. Brief Problem Explanation: There are a set of "jobs" (tasks) that should be performed on several "servers" (computers). Each job should be executed strictly from start time Si to end time Ei Each server can only perform one task at a time. (The complicated thing goes here) It takes some time for a server to switch from one job to another. If a server finishes job Jx, then to start job Jy it will need an intermission time Tx,y after job Jx completes. This is the time required by the server to clean up job Jx and load job Jy. In other word, job Jy can be run after job Jx if and only if Ex + Tx,y = Sy. The problem is to compute the minimum number of servers needed to do all jobs. Example: For example, let there be 3 jobs S(1) = 3 and E(1) = 6 S(2) = 10 and E(2) = 15 S(3) = 16 and E(3) = 20 T(1,2) = 2, T(1,3) = 5 T(2,1) = 0, T(2,3) = 3 T(3,1) = 0, T(3,2) = 0 In this example, we need 2 servers: Server 1: J(1), J(2) Server 2: J(3) Sample Input: Short explanation: The first 3 is the number of test cases, following by number of jobs (the second 3 means that there are 3 jobs for case 1), then followed by Ei and Si, then the T matrix (sized equal with number of jobs). 3 3 3 6 10 15 16 20 0 2 5 0 0 3 0 0 0 4 8 10 4 7 12 15 1 4 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 4 8 10 4 7 12 15 1 4 0 50 50 50 50 0 50 50 50 50 0 50 50 50 50 0 Sample Output: Case #1: 2 Case #2: 1 Case #3: 4 Personal Comments: The time required can be represented as a graph matrix, so I'm supposing this as a directed acyclic graph problem. Methods I tried so far is brute force and greedy, but got Wrong Answer. (Unfortunately I don't have my code anymore) Could probably solved by dynamic programming too, but I'm not sure. I really have no clear idea on how to solve this problem. So a simple hint or insight will be very helpful to me.

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  • The Internet Key Wave MW833UP is not recognized in Ubuntu

    - by gio900
    I can't use my Onda MW833UP... :( Any advice? Here is something that someone else may understand: ~$: lsb_release -a No LSB modules are available. Distributor ID: Ubuntu Description: Ubuntu 11.10 Release: 11.10 Codename: oneiric ~$: lsusb Bus 001 Device 005: ID 1ee8:0012 ~$: dmesg [ 22.709475] cdc_acm 1-1:1.0: ttyACM0: USB ACM device [ 22.714856] usbcore: registered new interface driver cdc_acm [ 22.714866] cdc_acm: USB Abstract Control Model driver for USB modems and ISDN adapters [ 23.520490] ieee80211 phy0: wl_ops_bss_info_changed: arp filtering: enabled true, count 1 (implement) [ 24.244530] usbcore: registered new interface driver usbserial [ 24.244575] USB Serial support registered for generic [ 24.244673] usbcore: registered new interface driver usbserial_generic [ 24.244681] usbserial: USB Serial Driver core [ 24.265879] USB Serial support registered for GSM modem (1-port) [ 24.285680] usbcore: registered new interface driver option [ 24.285691] option: v0.7.2:USB Driver for GSM modems [ 24.425878] EXT4-fs (sda9): re-mounted. Opts: errors=remount-ro,commit=600 [ 24.736540] EXT4-fs (sda8): re-mounted. Opts: commit=600 [ 35.705796] Easy slow down manager: checking for SABI support. [ 35.706002] Easy slow down manager: SABI is supported (f5189) [ 36.060099] usbcore: deregistering interface driver uvcvideo [ 139.508061] CE: hpet increased min_delta_ns to 20113 nsec [ 6798.378917] usb 1-1: USB disconnect, device number 5 [ 6809.108232] usb 1-1: new high speed USB device number 6 using ehci_hcd [ 6809.242692] scsi5 : usb-storage 1-1:1.0 [ 6810.241257] scsi 5:0:0:0: CD-ROM Onda Datacard CD-ROM 0001 PQ: 0 ANSI: 0 [ 6810.241841] scsi 5:0:0:1: Direct-Access Onda Storage 0001 PQ: 0 ANSI: 0 [ 6810.271410] sr0: scsi3-mmc drive: 0x/0x caddy [ 6810.272099] sr 5:0:0:0: Attached scsi CD-ROM sr0 [ 6810.272852] sr 5:0:0:0: Attached scsi generic sg1 type 5 [ 6810.279954] sd 5:0:0:1: [sdb] Attached SCSI removable disk [ 6810.281210] sd 5:0:0:1: Attached scsi generic sg2 type 0 [ 6810.380591] sr0: CDROM (ioctl) error, command: Xpwrite, Read disk info 51 00 00 00 00 00 00 00 02 00 [ 6810.380617] sr: Sense Key : Hardware Error [current] [ 6810.380625] sr: Add. Sense: No additional sense information [ 6810.613937] sr0: CDROM (ioctl) error, command: Xpwrite, Read disk info 51 00 00 00 00 00 00 00 02 00 [ 6810.613972] sr: Sense Key : Hardware Error [current] [ 6810.613984] sr: Add. Sense: No additional sense information [ 6810.673716] usb 1-1: USB disconnect, device number 6 [ 6815.572142] usb 1-1: new high speed USB device number 7 using ehci_hcd [ 6815.706828] cdc_acm 1-1:1.0: ttyACM0: USB ACM device The last 3 lines are where I inserted the Internet key, then reconnected it. usb-device T: Bus=01 Lev=01 Prnt=01 Port=00 Cnt=01 Dev#= 7 Spd=480 MxCh= 0 D: Ver= 2.00 Cls=ef(misc ) Sub=02 Prot=01 MxPS=64 #Cfgs= 1 P: Vendor=1ee8 ProdID=0012 Rev=00.01 S: Manufacturer=Onda S: Product=MW833UP S: SerialNumber=9230B35D870F9CB7AE684EACC5C12BE5EC33B26E C: #Ifs= 2 Cfg#= 1 Atr=a0 MxPwr=500mA I: If#= 0 Alt= 0 #EPs= 1 Cls=02(commc) Sub=02 Prot=01 Driver=cdc_acm I: If#= 1 Alt= 0 #EPs= 2 Cls=0a(data ) Sub=00 Prot=00 Driver=cdc_acm Then there is /dev/ttyACM0. When the key is connected to the USB port, everything that will meant...

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