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  • How to provide KeyPress event to WebBrowser control?

    - by Pritorian
    Hi all, i really need to catch "ESC" key press while focus is on WebBrowser control. I tried something like this: (webControl as Control).KeyPress += new KeyPressEventHandler(MyKeyPressEventHandler); But it doesnt work. The method is not called. I tried some methods, described here, but dont get any result ( Help, please.

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  • Canceling BackgroundWorker within the Thread

    - by Mike Wills
    I have a longer running multi-step process using BackgroundWorker and C#. I need to be sure that each step is completed successfully before moving on to the next step. I have seen many references to letting the BackgroundWorker catch errors and canceling from clicking on a Cancel button, but I want to check for an error myself and then gracefully end the process. Do I treat it just like someone clicked the cancel button, or is there another way?

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  • To get which function threw exception in javascript

    - by uzay95
    I am trying to create a Exception class to get and send errors from client to server. I want to catch exception in javascript function and push the details to the web service to write to database. But i couldn't get how to get which function/line throwed this exception. Is there any way to solve this?

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  • Web request timeout in c#

    - by victor_foster
    I am trying to make a web service request call to a third part web site who's server is a little unreliable. Is there a way I can set a timeout on a request to this site? Something like this pseudo code: try for 1 minute { // Make web request here using (WebClient client new WebClient())...etc. } catch { }

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  • android zxing intentintegrator

    - by cristi _b
    I've written the following code that works fine if you decide to scan a QR code (using zxing) and store it in private storage but in case you decide to cancel scanning, it crashes and the file previously stored content disappears. I think it might be a design error, not sure why. Below is relevant code ... /** * menu generation */ @Override public boolean onCreateOptionsMenu(Menu menu) { MenuInflater inflater = getMenuInflater(); inflater.inflate(R.menu.menu, menu); return true; } /** * menu handling */ @Override public boolean onOptionsItemSelected(MenuItem item) { Context context = getApplicationContext(); Toast toast = Toast.makeText(context, "", Toast.LENGTH_LONG); toast.setGravity(Gravity.FILL_HORIZONTAL, 0, 0); switch (item.getItemId()) { case R.id.qrScan: IntentIntegrator integrator = new IntentIntegrator(this); integrator.initiateScan(); return true; case R.id.qrReset: File dir = getFilesDir(); File file = new File(dir, qrCodeFile); boolean deleted = file.delete(); return true; case R.id.appClose: this.finish(); return true; default: return super.onOptionsItemSelected(item); } } ... public void onActivityResult(int requestCode, int resultCode, Intent intent) { IntentResult scanResult = IntentIntegrator.parseActivityResult(requestCode, resultCode, intent); Context context = getApplicationContext(); Toast toast = Toast.makeText(context, "", Toast.LENGTH_SHORT); if (scanResult != null) { FileOutputStream fos = null; CharSequence text = scanResult.getContents(); try { fos = openFileOutput(qrCodeFile, Context.MODE_PRIVATE); try { fos.write(text.toString().getBytes()); fos.close(); toast.setGravity(Gravity.FILL_HORIZONTAL, 0, 0); toast.setText("Code saved"); toast.show(); } catch (IOException ex) { toast.setGravity(Gravity.FILL_HORIZONTAL, 0, 0); toast.setText("Invalid code"); toast.show(); Logger.getLogger(MainActivity.class.getName()).log(Level.SEVERE, null, ex); } } catch (FileNotFoundException ex) { toast.setGravity(Gravity.FILL_HORIZONTAL, 0, 0); toast.setText("Error while saving"); toast.show(); Logger.getLogger(MainActivity.class.getName()).log(Level.SEVERE, null, ex); } } else { toast.setGravity(Gravity.FILL_HORIZONTAL, 0, 0); toast.setText("Invalid code"); toast.show(); } }

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  • In Java What is the guaranteed way to get a FileLock from FileChannel while accessing a RandomAcces

    - by narasimha.bhat
    I am trying to use FileLock lock(long position, long size,boolean shared) in FileChannel object As per the javadoc it can throw OverlappingFileLockException. When I create a test program with 2 threads lock method seems to be waiting to acquire the lock (both exclusive and non exclusive) But when the number threads increases in the acutal scenario over lapping file lock exception is thrown and processing slows down due the block at File lock table. What is the best way to acquire lock avoiding the OverlappingFileLockException ?

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  • how to make IXMLHTTPRequest work over HTTPS, client being WinCE

    - by siddharth
    hi, i am creating a client, which uploads to and dowloads from WinCE client. the code works properly for HTTP but not for HTTPS. Can any one help me about the changes that needs to be done. Code of client on PC : private void btnUpload_Click(object sender, EventArgs e) { try { MSXML2.DOMDocument xmlDOM = new DOMDocumentClass(); xmlDOM.load(txtUpload.Text); MSXML2.IXMLHTTPRequest x = new XMLHTTPClass(); x.open("POST", "http://192.168.1.12/server.asp?cmd=1", false, "", ""); x.send(xmlDOM); string result = x.responseText; if (x.status == 200) { MessageBox.Show(result); MessageBox.Show("upload file successfully"); } else { MessageBox.Show("upload file unsuccessful"); MessageBox.Show(x.status.ToString() + "\n" + x.statusText); } } catch(Exception ex) { MessageBox.Show(ex.Message + "\n" + ex.Data); } } private void btnDownload_Click(object sender, EventArgs e) { try { HttpWebRequest WebReq = (HttpWebRequest)WebRequest.Create("http://192.168.1.12/server.asp?cmd=2"); WebReq.Method = "GET"; HttpWebResponse WebResp = null; WebResp = (HttpWebResponse)WebReq.GetResponse(); Stream myResponseStream = WebResp.GetResponseStream(); StreamReader myStreamReader = new StreamReader(myResponseStream); string s = myStreamReader.ReadToEnd(); MessageBox.Show(s); StreamWriter SW; SW = File.CreateText(txtDownload.Text); SW.WriteLine(s); SW.Close(); MessageBox.Show(@"save file at" + txtDownload.Text); myStreamReader.Close(); myResponseStream.Close(); WebResp.Close(); } catch (Exception ex) { MessageBox.Show(ex.Message + "\n" + ex.Data); } The client asp page that acts according to the command is : On Error Resume Next Response.Expires = 0 Dim cmd cmd = Request.QueryString("cmd") if cmd = "2" Then Dim xml_dom1 set xml_dom1 = CreateObject("MSXML2.DOMDocument") xml_dom1.load("\Windows\Config.xml") '(Server.MapPath("Config.xml")) Response.Write(xml_dom1.xml) set xml_dom1 = nothing end if if cmd = "1" Then dim xml_dom set xml_dom = CreateObject("MSXML2.DOMDocument") xml_dom.load(request) xml_dom.save("\Windows\Config.xml") set xml_dom = Nothing end if If err.number < 0 Then Response.Write(err.Description) Response.Write(err.number) End If

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  • gdb - thread log

    - by sthustfo
    Hi all, While I trying to debug a 'C' program with gdb, I always get the following continuously on the gdb console. [Thread 0xb7fe4b70 (LWP 30576) exited] [New Thread 0xb7fe4b70 (LWP 30577)] [Thread 0xb7fe4b70 (LWP 30577) exited] [New Thread 0xb7fe4b70 (LWP 30578)] [Thread 0xb7fe4b70 (LWP 30578) exited] Is there any reason why this is printed? And anyway to block this? note: the program makes use of timers. Is that a possible cause?

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  • Android: Memory leak due to AsyncTask

    - by Manu
    Hello, I'm stuck with a memory leak that I cannot fix. I identified where it occurs, using the MemoryAnalizer but I vainly struggle to get rid of it. Here is the code: public class MyActivity extends Activity implements SurfaceHolder.Callback { ... Camera.PictureCallback mPictureCallbackJpeg = new Camera.PictureCallback() { public void onPictureTaken(byte[] data, Camera c) { try { // log the action Log.e(getClass().getSimpleName(), "PICTURE CALLBACK JPEG: data.length = " + data); // Show the ProgressDialog on this thread pd = ProgressDialog.show(MyActivity.this, "", "Préparation", true, false); // Start a new thread that will manage the capture new ManageCaptureTask().execute(data, c); } catch(Exception e){ AlertDialog.Builder dialog = new AlertDialog.Builder(MyActivity.this); ... dialog.create().show(); } } class ManageCaptureTask extends AsyncTask<Object, Void, Boolean> { protected Boolean doInBackground(Object... args) { Boolean isSuccess = false; // initialize the bitmap before the capture ((myApp) getApplication()).setBitmapX(null); try{ // Check if it is a real device or an emulator TelephonyManager telmgr = (TelephonyManager) getSystemService(Context.TELEPHONY_SERVICE); String deviceID = telmgr.getDeviceId(); boolean isEmulator = "000000000000000".equalsIgnoreCase(deviceID); // get the bitmap if (isEmulator) { ((myApp) getApplication()).setBitmapX(BitmapFactory.decodeFile(imageFileName)); } else { ((myApp) getApplication()).setBitmapX(BitmapFactory.decodeByteArray((byte[]) args[0], 0, ((byte[])args[0]).length)); } ((myApp) getApplication()).setImageForDB(ImageTools.resizeBmp(((myApp) getApplication()).getBmp())); // convert the bitmap into a grayscale image and display it in the preview ((myApp) getApplication()).setImage(makeGrayScale()); isSuccess = true; } catch (Exception connEx){ errorMessageFromBkgndThread = getString(R.string.errcapture); } return isSuccess; } protected void onPostExecute(Boolean result) { // Pass the result data back to the main activity if (MyActivity.this.pd != null) { MyActivity.this.pd.dismiss(); } if (result){ ((ImageView) findViewById(R.id.apercu)).setImageBitmap(((myApp) getApplication()).getBmp()); ((myApp) getApplication()).setBitmapX(null); } else{ // there was an error ErrAlert(); } } } }; private void ErrAlert(){ // notify the user about the error AlertDialog.Builder dialog = new AlertDialog.Builder(this); ... dialog.create().show(); } } MemoryAnalyzer indicated the memory leak at: ((myApp) getApplication()).setBitmapX(BitmapFactory.decodeByteArray((byte[]) args[0], 0, ((byte[])args[0]).length)); I am grateful for any suggestion, thank you in advance.

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  • Ruby: Continue a loop after catching an exception

    - by Santa
    Basically, I want to do something like this (in Python, or similar imperative languages): for i in xrange(1, 5): try: do_something_that_might_raise_exceptions(i) except: continue # continue the loop at i = i + 1 How do I do this in Ruby? I know there are the redo and retry keywords, but they seem to re-execute the "try" block, instead of continuing the loop: for i in 1..5 begin do_something_that_might_raise_exceptions(i) rescue retry # do_something_* again, with same i end end

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  • How to get Alfresco login ticket without user password, but with impersonating user with user principal name (UPN)

    - by dok
    I'm writing a DLL that has function for getting Alfresco login ticket without using user password, using only a user principal name (UPN). I’m calling alfresco REST API service /wcservice. I use NTLM in Alfresco. I’m impersonating users using WindowsIdentity constructor as explained here http://msdn.microsoft.com/en-us/library/ms998351.aspx#paght000023_impersonatingbyusingwindowsidentity. I checked and user is properly impersonated (I checked WindowsIdentity.GetCurrent().Name property). After impersonating a user, I try to make HttpWebRequest and set its credentials with CredentialsCache.DefaultNetworkCredentials. I get the error: The remote server returned an error: (401) Unauthorized. at System.Net.HttpWebRequest.GetResponse() When I use new NetworkCredential("username", "P@ssw0rd") to set request credentials, I get Alfresco login ticket (HttpStatusCode.OK, 200). Is there any way that I can get Alfresco login ticket without user password? Here is the code that I'm using: private string GetTicket(string UPN) { WindowsIdentity identity = new WindowsIdentity(UPN); WindowsImpersonationContext context = null; try { context = identity.Impersonate(); MakeWebRequest(); } catch (Exception e) { return e.Message + Environment.NewLine + e.StackTrace; } finally { if (context != null) { context.Undo(); } } } private string MakeWebRequest() { string URI = "http://alfrescoserver/alfresco/wcservice/mg/util/login"; HttpWebRequest request = WebRequest.Create(URI) as HttpWebRequest; request.CookieContainer = new CookieContainer(1); //request.Credentials = new NetworkCredential("username", "p@ssw0rd"); // It works with this request.Credentials = CredentialCache.DefaultNetworkCredentials; // It doesn’t work with this //request.Credentials = CredentialCache.DefaultCredentials; // It doesn’t work with this either try { using (HttpWebResponse response = request.GetResponse() as HttpWebResponse) { StreamReader sr = new StreamReader(response.GetResponseStream()); return sr.ReadToEnd(); } } catch (Exception e) { return (e.Message + Environment.NewLine + e.StackTrace); } } Here are records from Alfresco stdout.log (if it helps in any way): 17:18:04,550 DEBUG [app.servlet.NTLMAuthenticationFilter] Processing request: /alfresco/wcservice/mg/util/login SID:7453F7BD4FD2E6A61AD40A31A37733A5 17:18:04,550 DEBUG [web.scripts.DeclarativeRegistry] Web Script index lookup for uri /mg/util/login took 0.526239ms 17:18:04,550 DEBUG [app.servlet.NTLMAuthenticationFilter] New NTLM auth request from 10.**.**.** (10.**.**.**:1229) 17:18:04,566 DEBUG [app.servlet.NTLMAuthenticationFilter] Processing request: /alfresco/wcservice/mg/util/login SID:7453F7BD4FD2E6A61AD40A31A37733A5 17:18:04,566 DEBUG [web.scripts.DeclarativeRegistry] Web Script index lookup for uri /mg/util/login took 0.400909ms 17:18:04,566 DEBUG [app.servlet.NTLMAuthenticationFilter] Received type1 [Type1:0xe20882b7,Domain:<NotSet>,Wks:<NotSet>] 17:18:04,566 DEBUG [app.servlet.NTLMAuthenticationFilter] Client domain null 17:18:04,675 DEBUG [app.servlet.NTLMAuthenticationFilter] Sending NTLM type2 to client - [Type2:0x80000283,Target:AlfrescoServerA,Ch:197e2631cc3f9e0a]

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  • asp.net cannot update database

    - by tom
    string ConnectionString = WebConfigurationManager.ConnectionStrings["dbnameConnectionString"].ConnectionString; SqlConnection myConnection = new SqlConnection(ConnectionString); myConnection.Open(); try { string qry = "UPDATE customers SET firstname=@firstname WHERE cid=1"; SqlCommand insertQuery = new SqlCommand(qry, myConnection); insertQuery.Parameters.Add(new SqlParameter("@firstname", txtFirstname.Text)); insertQuery.ExecuteNonQuery(); myConnection.Close(); } catch (Exception ee) { } Any suggestions?

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  • Spring's JMS Design Question : Decouple processing of messages

    - by java_pill
    I'm using a message listener to process some messages from MQ based on Spring's DefaultMessageListenerContainer. After I receive a message, I have to make a Web Service (WS) call. However, I don't want to do this in the onMessage method because it would block the onMessage method until the invocation of WS is successful and this introduces latency in dequeuing of messages from the queue. How can I decouple the invocation of the Web Service by calling it outside of the onMesage method or without impacting the dequeuing of messages? Thanks,

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  • Running Network Application on port Server side give me error how can i solve it?

    - by Phsika
    if i run Server App. Exception occurs: on Dinle.Start() System.Net.SocketException - Only one usage of each socket address (protocol/network address/port) is normally permitted How can i solve this error? Server.cs using System; using System.Collections.Generic; using System.ComponentModel; using System.Data; using System.Drawing; using System.Linq; using System.Text; using System.Windows.Forms; using System.IO; using System.Net; using System.Net.Sockets; using System.Threading; namespace Server { public partial class Server : Form { Thread kanal; public Server() { InitializeComponent(); try { kanal = new Thread(new ThreadStart(Dinle)); kanal.Start(); kanal.Priority = ThreadPriority.Normal; this.Text = "Kanla Çalisti"; } catch (Exception ex) { this.Text = "kanal çalismadi"; MessageBox.Show("hata:" + ex.ToString()); kanal.Abort(); throw; } } private void Server_Load(object sender, EventArgs e) { Dinle(); } private void btn_Listen_Click(object sender, EventArgs e) { Dinle(); } void Dinle() { // IPAddress localAddr = IPAddress.Parse("localhost"); // TcpListener server = new TcpListener(port); // server = new TcpListener(localAddr, port); //TcpListener Dinle = new TcpListener(localAddr,51124); TcpListener Dinle = new TcpListener(51124); try { while (true) { Dinle.Start(); Exception is occured. Socket Baglanti = Dinle.AcceptSocket(); if (!Baglanti.Connected) { MessageBox.Show("Baglanti Yok"); } else { TcpClient tcpClient = Dinle.AcceptTcpClient(); if (tcpClient.ReceiveBufferSize 0) { byte[] Dizi = new byte[250000]; Baglanti.Receive(Dizi, Dizi.Length, 0); string Yol; saveFileDialog1.Title = "Dosyayi kaydet"; saveFileDialog1.ShowDialog(); Yol = saveFileDialog1.FileName; FileStream Dosya = new FileStream(Yol, FileMode.Create); Dosya.Write(Dizi, 0, Dizi.Length - 20); Dosya.Close(); listBox1.Items.Add("dosya indirildi"); listBox1.Items.Add("Dosya Boyutu=" + Dizi.Length.ToString()); listBox1.Items.Add("Indirilme Tarihi=" + DateTime.Now); listBox1.Items.Add("--------------------------------"); } } } } catch (Exception ex) { MessageBox.Show("hata:" + ex.ToString()); } } } }

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  • A lock could not obtained within the time requested issue

    - by Wayne Daly
    The title is the error I'm getting, when I click load my program freezes. I assume its because I'm doing a statement inside a statement, but from what I see its the only solution to my issue. By loading I want to just repopulate the list of patients, but to do so I need to do their conditions also. The code works, the bottom method is what I'm trying to fix. I think the issue is that I have 2 statements open but I am not sure. load: public void DatabaseLoad() { try { String Name = "Wayne"; String Pass= "Wayne"; String Host = "jdbc:derby://localhost:1527/Patients"; Connection con = DriverManager.getConnection( Host,Name, Pass); PatientList.clear(); Statement stmt8 = con.createStatement(ResultSet.TYPE_SCROLL_INSENSITIVE, ResultSet.CONCUR_UPDATABLE); String SQL8 = "SELECT * FROM PATIENTS"; ResultSet rs8 = stmt8.executeQuery( SQL8 ); ArrayList<PatientCondition> PatientConditions1 = new ArrayList(); while(rs8.next()) { PatientConditions1 = LoadPatientConditions(); } Statement stmt = con.createStatement(ResultSet.TYPE_SCROLL_INSENSITIVE, ResultSet.CONCUR_UPDATABLE); String SQL = "SELECT * FROM PATIENTS"; ResultSet rs = stmt.executeQuery( SQL ); while(rs.next()) { int id = (rs.getInt("ID")); String name = (rs.getString("NAME")); int age = (rs.getInt("AGE")); String address = (rs.getString("ADDRESS")); String sex = (rs.getString("SEX")); String phone = (rs.getString("PHONE")); Patient p = new Patient(id, name, age, address, sex, phone, PatientConditions1); PatientList.add(p); } UpdateTable(); UpdateAllViews(); DefaultListModel PatientListModel = new DefaultListModel(); for (Patient s : PatientList) { PatientListModel.addElement(s.getAccountNumber() + "-" + s.getName()); } PatientJList.setModel(PatientListModel); } catch(SQLException err) { System.out.println(err.getMessage()); } } This is the method that returns the arraylist of patient conditions public ArrayList LoadPatientConditions() { ArrayList<PatientCondition> PatientConditionsTemp = new ArrayList(); try { String Name = "Wayne"; String Pass= "Wayne"; String Host = "jdbc:derby://localhost:1527/Patients"; Connection con = DriverManager.getConnection( Host,Name, Pass); Statement stmt = con.createStatement(ResultSet.TYPE_SCROLL_INSENSITIVE, ResultSet.CONCUR_UPDATABLE); String SQL = "SELECT * FROM PATIENTCONDITIONS"; ResultSet rs5 = stmt.executeQuery( SQL ); int e = 0; while(rs5.next()) { e++; String ConName = (rs5.getString("CONDITION")); PatientCondition k = new PatientCondition(e,ConName); PatientConditionsTemp.add(k); } } catch(SQLException err) { System.out.println(err.getMessage()); } return PatientConditionsTemp; }

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  • Trying to write a loop that uses an OutputStream to write to a text file.

    - by Steve McLain
    I'm not a java programmer, I'm a VB programmer. I am doing this as part of an assignment, however, I'm not asking for help on something assignment related. I'd like to figure out how to get the OutputStreamWriter to work properly in this instance. I just want to capture the values I'm generating and place them into a text document. The file is generated, but only one entry exists, not the 40 I'm expecting. I could do this in a heartbeat with VB, but java feels very strange to me right now. Your help is appreciated. Thanks, Steve Here's the code: public static void main(String[] args){ long start, end; double result,difference; try {//OutputStream code assistance from http://tutorials.jenkov.com/java-io/outputstreamwriter.html OutputStream outputStream = new FileOutputStream("c:\\Temp\\output1.txt"); Writer out = new OutputStreamWriter(outputStream); for(int n=1; n<=20; n++){ //Calculate the Time for n^2. start = System.nanoTime(); //Add code to call method to calculate n^2 result = mN2(n); end = System.nanoTime(); difference = (end - start); //Output results to a file out.write("N^2 End time: " + end + " Difference: " + difference + "\n"); out.close(); } } catch (IOException e){ } try { OutputStream outputStream = new FileOutputStream("c:\\Temp\\output1.txt"); Writer out = new OutputStreamWriter(outputStream); for(int n=1; n<=20; n++){ //Calculate the Time for 2^n. start = System.nanoTime(); //Add code to call method to calculate 2^n result = m2N(n); end = System.nanoTime(); difference = (end - start); //Output results to a file out.write("N^2 End time: " + end + " Difference: " + difference + "\n"); out.close(); } } catch (IOException e){ } } //Calculate N^2 public static double mN2(double n) { n = n*n; return n; } //Calculate 2N public static double m2N (double n) { n = 2*n; return n; }

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  • Is it a good way to close a thread?

    - by Roman
    I have a short version of the question: I start a thread like that: counter.start();, where counter is a thread. At the point when I want to stop the thread I do that: counter.interrupt() In my thread I periodically do this check: Thread.interrupted(). If it gives true I return from the thread and, as a consequence, it stops. And here are some details, if needed: If you need more details, they are here. From the invent dispatch thread I start a counter thread in this way: public static void start() { SwingUtilities.invokeLater(new Runnable() { public void run() { showGUI(); counter.start(); } }); } where the thread is defined like that: public static Thread counter = new Thread() { public void run() { for (int i=4; i>0; i=i-1) { updateGUI(i,label); try {Thread.sleep(1000);} catch(InterruptedException e) {}; } // The time for the partner selection is over. SwingUtilities.invokeLater(new Runnable() { public void run() { frame.remove(partnerSelectionPanel); frame.add(selectionFinishedPanel); frame.invalidate(); frame.validate(); } }); } }; The thread performs countdown in the "first" window (it shows home much time left). If time limit is over, the thread close the "first" window and generate a new one. I want to modify my thread in the following way: public static Thread counter = new Thread() { public void run() { for (int i=4; i>0; i=i-1) { if (!Thread.interrupted()) { updateGUI(i,label); } else { return; } try {Thread.sleep(1000);} catch(InterruptedException e) {}; } // The time for the partner selection is over. if (!Thread.interrupted()) { SwingUtilities.invokeLater(new Runnable() { public void run() { frame.remove(partnerSelectionPanel); frame.add(selectionFinishedPanel); frame.invalidate(); frame.validate(); } }); } else { return; } } };

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  • Single console in eclipse for both Server and Client

    - by rits
    I am building a client server application using Java Sockets (in Windows XP). For that I need different consoles for both Client and Server(for Input and Output operations). But in eclipse both share a single console. Is there any plugin or some sort of cheat through which I can do this. After googling I got this, http://dev.eclipse.org/newslists/news.eclipse.newcomer/msg17138.html But, this seems to be only for write operations, not read operations. Also, I tried the following to launch application manually, but even this is not working........ package mypack; import java.io.BufferedOutputStream; import java.io.File; import java.io.FileOutputStream; import java.io.IOException; import java.io.OutputStream; import java.io.PrintStream; public class MySystem { public static void changeStream(String mainFile) throws IOException{ File temp = new File(".") ; String parentPath = temp.getCanonicalPath() ; System.out.println(parentPath); //creation of batch file starts here try{ File f = new File(parentPath + "\\a.bat") ; System.out.println("Created : " + f.createNewFile()); //f.deleteOnExit() ; FileOutputStream fos = new FileOutputStream(f) ; String str = "java " + mainFile ; String batchCommand="@echo off\n"+str+"\npause\nexit"; char arr[] = batchCommand.toCharArray() ; System.out.println(str) ; for(int i = 0 ; i < arr.length ; i++){ fos.write(arr[i]) ; } fos.close() ; } catch(Exception e){ } //creation of batch file ends here //execution of batch file starts here try{ Runtime r = Runtime.getRuntime() ; System.out.println(parentPath + "\\a.bat") ; Process p = r.exec(new String[]{"cmd","/k","start a.bat"},null,new File(parentPath)) ; OutputStream os = (OutputStream)p.getOutputStream() ; System.setOut( new PrintStream(os) ) ; System.out.println("Hello"); } catch(Exception e){ e.printStackTrace(); } //execution of batch file ends here } public static void main(String[] args) throws IOException { MySystem.changeStream("MySystem") ; } }

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  • Get Autonumber from newly inserted record in Access 2007 using Enterprise Library 4.1

    - by silverCORE
    It's been ages since I last used Access as a back end but I'm being forced to. I'm using Enterprise Library 4.1, the Data Access Application Block.. with .NET 3.5 and I wanted to know the best way (code sample if possible) to write an insert query that will automatically give me the newly inserted auto-number back..or if it's not possible to do it in one step, how do you recommend doing it? thanks for your help.

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  • Display\Capture InnerException Message

    - by madlan
    I was using the following to provide more information on a common exception that can occour in a piece of my code, the only problem is this errors if an exception is generated that has no InnerException message. Catch ex As Exception 'MessageBox.Show(ex.Message) 'If there is no InnerException. MessageBox.Show(ex.InnerException.InnerException.Message) End Try Is there a better method of doing this?

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