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  • MySQL query for initial filling of order column

    - by Sejanus
    Sorry for vague question title. I've got a table containing huge list of, say, products, belonging to different categories. There's a foreign key column indicating which category that particular product belongs to. I.e. in "bananas" row category might be 3 which indicates "fruits". Now I added additional column "order" which is for display order within that particular category. I need to do initial ordering. Since the list is big, I dont wanna change every row by hand. Is it possible to do with one or two queries? I dont care what initial order is as long as it starts with 1 and goes up. I cant do something like SET order = id because id counts from 1 up regardless of product category and order must start anew from 1 up for every different category.

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  • MySQL - Selecting rows with a minimum number of occurences

    - by RC
    Hi all, I have this query: SELECT DISTINCT brand_name FROM masterdata WHERE in_stock = '1' ORDER BY brand_name It works well, except that I get far too many results. How do I limit this such that rather than just looking for distinct entries, it will only give me distinct entries that exist a minimum of 3 times (for example)? Basically, if the column had this data... brand_name ========== apple banana apple apple orange banana orange orange ...my current query would return "apple, banana, orange". How do I get it such that it only returns "apple, orange" (ignoring banana because it has less than three occurrences)? I'm using PHP to build the query, if it matters. Thanks!

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  • mysql boolean joins

    - by user280381
    I want to use a JOIN to return a boolean result. Here's an example of the data... t1 id | data | 1 | abcd | 2 | 2425 | 3 | xyz | t2 id | data | t1_id | 1 | 75 | 2 | 2 | 79 | 2 | 3 | 45 | 3 | So with these two tables I want to select all the data from t1, and also whether a given variable appears in t2.data for each id. So say the variable is 79, the results should be id | data | t2_boolean 1 | abcd | 0 2 | abcd | 1 3 | xyz | 0 So I'm thinking some sort of join is needed, but without a WHERE clause. I've been banging my head about this one. Is it possible? I really need it inside the same statement as I want to sort results by the boolean field. As the boolean needs to be a field, can I put a join inside of a field? Thanks...

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  • Levenshtein: MySQL + PHP

    - by user317005
    $word = strtolower($_GET['term']); $lev = 0; $q = mysql_uqery("SELECT `term` FROM `words`"); while($r = mysql_fetch_assoc($q)) { $r['term'] = strtolower($r['term']); $lev = levenshtein($word, $r['term']); if($lev >= 0 && $lev < 5) { $word = $r['term']; } } how can I move all that into just one query? don't want to have to query through all terms and do the filtering in php.

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  • MYSQL - multiple count statments

    - by darudude
    I'm trying to do a lookup on our demographioc table to display some stats. However, since out demographic table is quit big I want to do it in one query. There are 2 fields that are important: sex, last_login I want to be able to get the total number of logins for various date ranges (<1day ago, 1-7 days ago, 7-30 days ago, etc) GROUPED BY sex I right now know how to do it for one date range. For example less than 1 day ago: SELECT sex, count(*) peeps FROM player_account_demo WHERE last_demo_update>1275868800 GROUP BY sex Which returns: sex peeps UNKNOWN 22 MALE 43 FEMALE 86 However I'd have to do this once for each range. Is there a way to get all 3 ranges in there? I'd want my end result to look something like this: sex peeps<1day peeps1-7days peeps7-30days Thanks!

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  • MySQL Count If using 4 tables or Perl

    - by user1726133
    Hi I have a relatively convoluted query that relies on 4 different tables, unfortunately I do not have control of this data, but I do have to query it. I ran this simpler query and it works using just table 1 and table 2 SELECT actor, receiver, count(IF(t2.group1 = "anxiety behavior", 1,0)) AS 'anxiety' FROM ethogram_edited_obs_behaviors t1 JOIN ethogram_behaviors t2 on t1.behavior = t2.behavior_code GROUP BY actor; Below are the 4 tables I need and the query I tried that didn't work Table 1 | Table 2 | Table 3 | Table 4 Actor | Behavior | Behavior | type of Behavior | subject | sex | subject |subject_code er frown | frown anxiety behavior | Eric M | Eric | er Here is the query that is failing SELECT actor, count(IF(t2.group1 = "anxiety behavior", 1,0) AND(t3.sex = "M", 1,0)) AS 'anxiety', FROM ethogram_edited_obs_behaviors t1 JOIN ethogram_behaviors t2 on t1.behavior = t2.behavior_code JOIN subject_code t3 on t1.actor = t3.behavior_code1 JOIN subjects t4 on t3.subject = t4.yerkes_code GROUP BY actor; Any help would be much appreciated!! Thanks :) P.S. if this is easier to do in Perl tips also much appreciated

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  • Partitioning a table in mysql after creation

    - by erik
    I have a table with a bunch of data already in it. I know how to create a partitioned table or alter an already existing partitioned table, but can I add partitions to a table after it has been created, has data in it, without losing the data? The other option is to dump all the data, recreate the table with the partitions and then insert it all back it. Is that the only way? Thanks.

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  • Problems with MYSQL database

    - by shinjuo
    I have a database that worked fine until I decided to add a log onto the page. here is what I have now: <body> <?php if($_SERVER['REQUEST_METHOD'] == 'POST') { require("serverInfo.php"); mysql_query("UPDATE `cardLists` SET `AmountLeft` = `AmountLeft` + ".mysql_real_escape_string($_POST['Add'])." WHERE `cardID` = '".mysql_real_escape_string($_POST['Cards'])."'"); echo "\"" .$_POST['Add'] ."\" has been added to the inventory amount for the card \"". $_POST['Cards']. "\""; mysql_query("INSERT INTO `log` (`changes`, `amount`, `cardID`, `person`, Date)VALUES('ADDED','$_POST['Add']','$_POST['Cards']', '$_POST['Person']', NOW())"); mysql_close($link); } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <?php require("serverInfo.php"); ?> <?php $res = mysql_query("SELECT * FROM cardLists order by cardID") or die(mysql_error()); echo "<select name = 'Cards'>"; while($row=mysql_fetch_assoc($res)) { echo "<option value=\"$row[cardID]\">$row[cardID]</option>"; } echo "</select>"; ?> Amount to Add: <input type="text" name="Add" maxlength="8" /> Changes Made By: <select name="Person"> <option value="justin">Justin</option> <option value="chris">Chris</option> <option value="matt">Matt</option> <option value="dan">Dan</option> <option value="tim">Tim</option> <option value="amanda">Amanda</option> </select> <input type="submit" name ="submit" onClick= "return confirm( 'Are you sure you want to add this amount?');"> </form> <br /> <input type="button" name="main" value="Return To Main" onclick="window.location.href='index.php';" /> </body> </html> it works fine until I added the: mysql_query("INSERT INTO `log` (`changes`, `amount`, `cardID`, `person`, Date)VALUES('ADDED','$_POST['Add']','$_POST['Cards']', '$_POST['Person']', NOW())"); mysql_close($link); Can anyone see what is going on?

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  • Multi-Column Primary Key in MySQL 5

    - by Kaji
    I'm trying to learn how to use keys and to break the habit of necessarily having SERIAL type IDs for all rows in all my tables. At the same time, I'm also doing many-to-many relationships, and so requiring unique values on either column of the tables that coordinate the relationships would hamper that. How can I define a primary key on a table such that any given value can be repeated in any column, so long as the combination of values across all columns is never repeated exactly?

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  • PHP/MySQL: Storing and retrieving UUIDS

    - by Greg
    I'm trying to add UUIDs to a couple of tables, but I'm not sure what the best way to store/retrieve these would be. I understand it's far more efficient to use BINARY(16) instead of VARCHAR(36). After doing a bit of research, I also found that you can convert a UUID string to binary with: UNHEX(REPLACE(UUID(),'-','')) Pardon my ignorance, but is there an easy way to this with PHP and then turn it back to a string, when needed, for readability? Also, would it make much difference if I used this as a primary key instead of auto_increment? EDIT: Found part of the answer: $bin = pack("h*", str_replace('-', '', $guid)); How would you unpack it?

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  • Adding relative week number column to MySQl results

    - by Anthony
    I have a table with 3 columns: user, value, and date. The main query returns the values for a specific user based on a date range: SELECT date, value FROM values WHERE user = '$user' AND date BETWEEN $start AND $end What I would like is for the results to also have a column indicating the week number relative to the date range. So if the date range is 1/1/2010 - 1/20/2010, then any results from the first Sun - Sat of that range are week 1, the next Sun - Sat are week 2, etc. If the date range starts on a Saturday, then only results from that one day would be week 1. If the date range starts on Thursday but the first result is on the following Monday, it would be week 2, and there are no week 1 results. Is this something fairly simple to add to the query? The only ideas I can come up with would be based on the week number for the year or the week number based on the results themselves (where in that second example above, the first result always gets week 1).

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  • mySQL: Joining three tables - how?

    - by Industrial
    Hi everybody, I have the following query in my application. It works well, but I need it to also contain the number of products that are associated with each manufacturer. The current query: SELECT * FROM (`manufacturers`) JOIN `languages` ON `manufacturers`.`lang` = `languages`.`id` ORDER BY `languages`.`id` asc, `id` asc My products table looks like this: id | name | manufacturerid 0 | Product1 | 0

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  • MySQL Delete from 1 table, using multiple tables

    - by nute
    I would like to delete all the rows found by that query: SELECT cart_abandon.* FROM cart_abandon, cart_product, txn_product, users WHERE cart_abandon.cartid = cart_product.cartid AND cart_product.productid = txn_product.productid AND txn_product.username = users.username AND users.id = cart_abandon.userid AND txn_product.txndate >= cart_abandon.abandondate The thing to keep in mind is that the query here uses 4 different tables, however I only want to delete rows from 1 table (cart_abandon). Is there an easy way to do that? Maybe this: ? DELETE cart_abandon FROM cart_abandon, cart_product, txn_product, users WHERE cart_abandon.cartid = cart_product.cartid AND cart_product.productid = txn_product.productid AND txn_product.username = users.username AND users.id = cart_abandon.userid AND txn_product.txndate >= cart_abandon.abandondate Is that valid? Correct?

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  • mysql query help please

    - by moustafa
    i have forum_topics table and have topics_posts table now i want to select from forum_topics where have no posts from topics_posts can any one give me the one syntax like this selct from * forum_topics where have no rows in topics_posts table

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  • Multiple OR Clauses in MySQL

    - by Grant
    I'm trying to grab content where id = 3 OR id = 9 OR id = 100... Keep in mind, I can have a few hundred of these ids. What is the most efficient way to write my query? $sql = "SELECT name FROM artists WHERE (id=3 OR id=9 OR .... id-100)"

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  • Mysql Avg function for recent 15 records by date (order date desc) in every symbol

    - by venkatesh
    i am trying to create a statement in sql (for a table which holds stock symbols and price on specified date) with avg of 5 day price and avg of 15 days price for each symbol. table description: symbol open high close date the average price is calculated from last 5 days and last 15 days. i tried this for getting 1 symbol: SELECT avg(close), avg(`trd_qty`) FROM (select * from cashmarket WHERE symbol = \'hdil\' order by `M_day` desc limit 0,15 ) s ...but I couldn't get the desired the list for showing avg values for all symbols.

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  • mysql eliminate responses under certain condition with join

    - by Dustin
    Forgive me if this is an easy question. I teach classes and want to be able to select those students who have taken one class, but not another class. I have two tables: lessons_slots which is the table for every class such as: -------------------- -ID name slots- -1 basics 10 - -2 advanced 10 - -3 basics 10 - --------------------- The other table is class_roll, which holds enrollment info, such as: -------------------- -sID classid firstname lastname- -1 1 Jo Schmo -2 1 Person Two ... -13 2 Jo Schmo --------------------- What I want to do, I select everyone who has not had the advanced class (for example). I've tried doing SELECT * FROM lessons_slots LEFT JOIN class_roll ON lessons_slots.ID = class_roll.classid WHERE lessons_slots.name != 'advanced' But that doesn't work. Any ideas?

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  • MySQL help, counting information on last records

    - by ee12csvt
    I need some advice I have two tables, one holds unique serial numbers of items (items) and the other holds status changes and other information for these items (details) The Tables are set up as follows Item itemID itemName itemDate details detID itemID modlvl status detDate All items have at least one record in the details table, but over time the status has changed or the modification level has changed (Both of these are identified by numbers which are held in other appropriate tables) and a new record is created each time the status/modlvl changes I want to display a table on my webpage using php that identifies the different mod levels of the items and shows a count of each of the current status of the items EDIT Hi Ronnis, This is an example of the data in the tables and what I want to achieve The current Mod Levels range from 1 to 3 Status representations are 1 In Use 2 In Store 3 Being repaired 4 In Transit 5 For Disposal 6 Disposed 7 Lost Item itemID OrigMod created 1000 1 2009-10-01 22:12:12 1001 1 2009-10-01 22:12:12 1002 1 2009-10-01 22:12:12 1003 1 2009-10-01 22:12:12 1004 1 2009-10-01 22:12:12 1005 1 2009-10-01 22:12:12 1006 1 2009-10-01 22:12:12 1007 1 2009-10-01 22:12:12 1008 1 2009-10-01 22:12:12 1009 1 2009-10-01 22:12:12 1010 1 2009-10-01 22:12:12 Details detID itemID modlvl detDate status 1 1000 1 2009-10-01 1 2 1001 1 2009-10-01 1 3 1002 1 2009-10-01 1 4 1003 1 2009-10-01 1 5 1004 1 2009-10-01 1 6 1005 1 2009-10-01 1 7 1006 1 2009-10-01 1 8 1007 1 2009-10-01 1 9 1008 1 2009-10-01 1 10 1009 1 2009-10-01 1 11 1010 1 2009-10-01 1 12 1001 1 2010-02-01 2 13 1001 1 2010-02-03 4 14 1001 1 2010-03-01 3 15 1000 1 2010-03-14 2 16 1001 2 2010-04-01 4 17 1006 1 2010-04-01 2 18 1001 2 2010-04-03 2 19 1006 1 2010-04-14 4 20 1006 1 2010-05-01 5 21 1002 1 2010-05-02 2 22 1003 1 2010-05-10 2 23 1010 1 2010-06-01 2 24 1006 1 2010-06-18 6 25 1010 1 2010-07-01 7 26 1007 1 2010-07-02 2 27 1007 1 2010-07-04 4 28 1003 1 2010-07-10 2 29 1007 1 2010-07-11 3 30 1007 2 2010-07-12 4 31 1007 2 2010-07-15 2 32 1001 2 2010-08-31 1 33 1001 2 2010-09-10 2 34 1001 2 2010-10-01 4 35 1008 1 2010-10-01 2 36 1001 2 2010-10-05 3 37 1008 1 2010-10-05 4 38 1008 1 2010-10-10 3 39 1001 3 2010-10-20 4 40 1001 3 2010-10-25 2 Using the tables above I want to get this result MoLvl Use Store Repd Transit Displ Dispd Lost Total 1 3 3 1 0 0 1 1 9 2 0 1 0 0 0 0 0 1 3 0 1 0 0 0 0 0 1 Total 3 5 1 0 0 1 1 11

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  • Generating Unordered List with PHP + CodeIgniter from a MySQL Database

    - by Tim
    Hello Everyone, I am trying to build a dynamically generated unordered list in the following format using PHP. I am using CodeIgniter but it can just be normal php. This is the end output I need to achieve. <ul id="categories" class="menu"> <li rel="1"> Arts &amp; Humanities <ul> <li rel="2"> Photography <ul> <li rel="3"> 3D </li> <li rel="4"> Digital </li> </ul> </li> <li rel="5"> History </li> <li rel="6"> Literature </li> </ul> </li> <li rel="7"> Business &amp; Economy </li> <li rel="8"> Computers &amp; Internet </li> <li rel="9"> Education </li> <li rel="11"> Entertainment <ul> <li rel="12"> Movies </li> <li rel="13"> TV Shows </li> <li rel="14"> Music </li> <li rel="15"> Humor </li> </ul> </li> <li rel="10"> Health </li> And here is my SQL that I have to work with. -- -- Table structure for table `categories` -- CREATE TABLE IF NOT EXISTS `categories` ( `id` mediumint(8) NOT NULL auto_increment, `dd_id` mediumint(8) NOT NULL, `parent_id` mediumint(8) NOT NULL, `cat_name` varchar(256) NOT NULL, `cat_order` smallint(4) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=1 ; So I know that I am going to need at least 1 foreach loop to generate the first level of categories. What I don't know is how to iterate inside each loop and check for parents and do that in a dynamic way so that there could be an endless tree of children. Thanks for any help you can offer. Tim

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  • PHP and MySQL echoing out a Table

    - by user1631702
    Okay, so I've done this before, and it worked. I am trying to echo out specific rows on my database in a table. Here is my code: <?php $connect = mysql_connect("localhost", "xxx", "xxx") or die ("Hey loser, check your server connection."); mysql_select_db("xxx"); $quey1="select * from `Ad Requests`"; $result=mysql_query($quey1) or die(mysql_error()); ?> <table border=1 style="background-color:#F0F8FF;" > <caption><EM>Student Record</EM></caption> <tr> <th>Student ID</th> <th>Student Name</th> <th>Class</th> </tr> <?php while($row=mysql_fetch_array($result)){ echo "</td><td>"; echo $row['id']; echo "</td><td>"; echo $row['twitter']; echo "</td><td>"; echo $row['why']; echo "</td></tr>"; } echo "</table>"; ?> It gives me no errors, but It just shows a blank table with none of these rows. My Question: How come this wont show any rows in the table, what am I doing wrong?

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