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• two where conditions in a mysql query

  - by Kaartz

  I have a table like below |date|dom|guid|pid|errors|QA|comm| |2010-03-22|xxxx.com|jsd3j234j|ab|Yes|xxxxxx|bad| |2010-03-22|xxxx.com|jsd3j234j|ab|No|xxxxxx|| |2010-03-22|xxxx.com|jsd3j234j|if|Yes|xxxxxx|bad| |2010-03-22|xxxx.com|jsd3j234j|if|No|xxxxxx|| |2010-03-22|xxxx.com|jsd3j234j|he|Yes|xxxxxx|bad| |2010-03-22|xxxx.com|jsd3j234j|he|No|xxxxxx|| I want to retrieve the total count of "dom" referred to each "QA" and also I need the count of "errors" detected by the "QA" SELECT date, count(dom), QA FROM reports WHERE date="2010-03-22" GROUP BY QA |2010-03-22|2|ab| |2010-03-22|2|if| |2010-03-22|2|he| SELECT date, count(dom), count(errors), QA FROM reports WHERE errors="Yes" GROUP BY QA |2010-03-22|1|ab| |2010-03-22|1|if| |2010-03-22|1|he| I want to combine the above two queries, is it possible. If I use the below query, I am not getting the desired result. SELECT date, count(dom), QA, count(errors) FROM reports WHERE date="2010-03-22" AND errors="Yes" GROUP BY QA I want the below output |2010-03-22|2|ab|1| |2010-03-22|2|if|1| |2010-03-22|2|he|1| Please help me.

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• mysql : Recieve data only per months

  - by Tristan

  Hello, few times ago, i asked how to do to display datas per month, i must told a bad explanation because i just figured out that it's not what i want : Here's what I got : $req1 = ... AND v.date > (DATE_SUB(CURDATE(), INTERVAL 2 MONTH)) AND v.date < (DATE_SUB(CURDATE(), INTERVAL 1 MONTH)) $req2= ... AND v.date > (DATE_SUB(CURDATE(), INTERVAL 3 MONTH)) AND v.date < (DATE_SUB(CURDATE(), INTERVAL 2 MONTH)) But the problem, imagine that today you are the 10th june, it's going to calculate ALL the data between the 10 june to the 10 may then the 10 may until the 10 april... But what i want is data : from 1st may to 1 st june, from 1st june to 1st july... do you see what i mean ? thank you ;)

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• php / mysql - select id from one table excepting ids which are in second table

  - by John

  hello. for example i have 2 tables: 1 . users: id Name 1 Mike 2 Adam 3 Tom 4 John 5 Andy 6 Ray 2 . visits: userID date 1 ... 3 ... 6 ... i want to make a page which can be visited once in 12 hours, when user visits that page his id is included in database ( visits ), how i can select all users ( from database users) excepting users who visited page in <= 12 hours ( users from database visits )?

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• MYSQL JOIN SELECT Statment - omit duplicated

  - by mouthpiec

  Hi, I am tying to join the following 2 queries but I am having duplicated .... it is possible to remove duplacted fro this: ( SELECT bar_id, bar_name, town_name, bar_telephone, (subscription_type_id *2) AS subscription_type_id FROM bar, sportactivitybar, towns, subscriptiontype WHERE sport_activity_id_fk =14 AND bar_id = bar_id_fk AND town_id = town_id_fk AND subscription_type_id = subscription_type_id_fk ) UNION ( SELECT bar_id, bar_name, town_name, bar_telephone, subscription_type_id FROM bar, towns, subscriptiontype WHERE town_id = town_id_fk AND subscription_type_id = subscription_type_id_fk ) ORDER BY subscription_type_id DESC , RAND( ) Please note that I need to omit those duplicates that will have a lower subscription_type_id

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• MYSQL JOIN WHERE ISSUES - need some kind of if condition

  - by Breezer

  Hi Well this will be hard to explain but ill do my best The thing is i have 4 tables all with a specific column to relate to eachother. 1 table with users(agent_users) , 1 with working hours(agent_pers), 1 with sold items(agent_stat),1 with project(agent_pro) the user and the project table is irrelevant in the issue at hand but to give you a better understanding why certain tables is included in my query i decided to still mention them =) The thing is that I use 2 pages to insert data to the working hour and the sold items during that time tables, then i have a third page to summarize everything for current month, the query for that is as following: SELECT *, SUM(sv_p_kom),SUM(sv_p_gick),SUM(sv_p_lunch) FROM (( agent_users LEFT JOIN agent_pers ON agent_users.sv_aid = agent_pers.sv_p_uid) LEFT JOIN agent_stat ON agent_pers.sv_p_uid = agent_stat.sv_s_uid) LEFT JOIN agent_pro ON agent_pers.sv_p_pid=agent_pro.p_id WHERE MONTH(agent_pers.sv_p_datum) =7 GROUP BY sv_aname so the problem is now that i dont want sold items from previous months to get included in the data received, i know i could solve that by simple adding in the WHERE part MONTH(agent_stat.sv_s_datum) =7 but then if no items been sold that month no data at all will show up not the time or anything. Any aid on how i could solve this is greatly appreciated. if there's something that's not so clear dont hesitate to ask and ill try my best to answer. after all my english isn't the best out there :P regards breezer

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• MySQL VARCHAR strange column behavior

  - by Mat

  I have the following SQL statement which returns a single record as expected: select * from geodatasource_cities C, geodatasource_countries D where C.CC_FIPS = D.CC_FIPS and D.CC_ISO='AU' and UCASE(TRIM(C.FULL_NAME_ND)) LIKE '%JAN JUE%'; However, If I use the following SQL statement, no records are returned. I have only changed the LIKE clause to an equal to clause: select * from geodatasource_cities C, geodatasource_countries D where C.CC_FIPS = D.CC_FIPS and D.CC_ISO='AU' and UCASE(TRIM(C.FULL_NAME_ND)) = 'JAN JUE'; Can anybody please help me understand why this may be happening?

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• MySQL date query only returns one year, when multiple exist

  - by Bowman

  I'm a part-time designer/developer with a part-time photography business. I've got a database of photos with various bits of metadata attached. I want to query the database and return a list of the years that photos were taken, and the quantity of photos that were taken in that year. In short, I want a list that looks like this: 2010 (35 photos) 2009 (67 photos) 2008 (48 photos) Here's the query I'm using: SELECT YEAR(date) AS year, COUNT(filename) as quantity FROM photos WHERE visible='1' GROUP BY 'year' ORDER BY 'year' DESC Instead of churning out all the possible years (the database includes photos from 2010-2008), this is the sole result: 2010 (35 photos) I've tried a lot of different syntax but at this point I'm giving in and asking for help!

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• Simple Chatroom in PHP & MySQL !

  - by acer

  What is a simple and easy-to-use php-sql chatroom with no external signin (like meebo or ...) I want to use it for my own registered users.!

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• MySQL: Count occurrences of known (or enumerated) distinct values

  - by Eilidh

  After looking at how to count the occurrences of distinct values in a field, I am wondering how to count the occurrences of each distinct value if the distinct values are known (or enumerated). For example, if I have a simple table - TrafficLight Colour ------------ ------ 1 Red 2 Amber 3 Red 4 Red 5 Green 6 Green where one column (in this case Colour) has known (or enumerated) distinct values, how could I return the count for each colour as a separate value, rather than as an array, as in the linked example. To return an array with a count of each colour (using the same method as in the linked example), the query would be something like SELECT Colour COUNT(*) AS ColourCount FROM TrafficLights GROUP BY Colour, and return an array - Colour ColourCount ------ ----------- Red 3 Amber 1 Green 2 What I would like to do is to return the count for each Colour AS a separate total (e.g. RedCount). How can I do this?

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• I need to auto_increment a field in MySQL that is not primary key

  - by behrk2

  Hey everyone, Right now, I have a table whose primary key is an auto_increment field. However, I need to set the primary key as username, date (to ensure that there cannot be a duplicate username with a date). I need the auto_increment field, however, in order to make changes to row information (adding and deleting). What is normally done with this situation? Thanks!

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• access denied for user root, mysql database

  - by Yang

  when i am using sequel pro to connect to a remote database, the server says access denied. I am 100% percent sure that the username and password are correct. I also try to use phpmyadmin to connect to the server, it works. I don't know what happened when I am using sequel pro to connect to the server.

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• VB.Net MySql command parameter MD5

  - by lampej

  Is it possible to execute a command like this? select * from tbl where col1=md5(@param1) or will the parameter throw off the md5 function? I have been unsuccessful in getting the command to work so far. Please let me know if this needs any further explanation and thank you in advance!

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• PHP and MySQL echoing out a Table

  - by user1631702

  Okay, so I've done this before, and it worked. I am trying to echo out specific rows on my database in a table. Here is my code: <?php $connect = mysql_connect("localhost", "xxx", "xxx") or die ("Hey loser, check your server connection."); mysql_select_db("xxx"); $quey1="select * from `Ad Requests`"; $result=mysql_query($quey1) or die(mysql_error()); ?> <table border=1 style="background-color:#F0F8FF;" > <caption><EM>Student Record</EM></caption> <tr> <th>Student ID</th> <th>Student Name</th> <th>Class</th> </tr> <?php while($row=mysql_fetch_array($result)){ echo "</td><td>"; echo $row['id']; echo "</td><td>"; echo $row['twitter']; echo "</td><td>"; echo $row['why']; echo "</td></tr>"; } echo "</table>"; ?> It gives me no errors, but It just shows a blank table with none of these rows. My Question: How come this wont show any rows in the table, what am I doing wrong?

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• Mysql Query problem ?

  - by deep

  ID NAME AMT 1 Name1 1000 2 Name2 500 3 Name3 3000 4 Name1 5000 5 Name2 2000 6 Name1 3000 consider above table as sample. am having a problem in my sql query, Am using like this. Select name,amt from sample where amt between 1000 and 5000 it returns all the values in the table between 1000 and 5000, instead I want to get maximum amount record for each name i.e., 3 name3 3000 4 name1 5000 5 name2 2000

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• MySQL Need some help with a query

  - by Jules

  I'm trying to fix some data by adding a new field. I have a backup from a few months ago and I have restored this database to my server. I'm looking at table called pads, its primary key is PadID and the field of importance is called RemoveMeDate. In my restored (older) database there is less records with an actual date set in RemoveMeDate. My control date is 2001-01-01 00:00:00 meaning that the record is not hidden aka visible. What I need to do is select all the records from the older database / table with the control date and join with those from the newer db /table where the control date is not set. I hope I've explained that correctly. I'll try again, with numbers. I have 80,000 visible records in the older table (with control date set) and 30,000 in the newer db/table. I need to select the 50,000 from the old database, to perform an update query. Heres my query, which I'd can't get to work as I'd like. jules-fix-reasons is the old database, jules is the newer one. select p.padid from `jules-fix-reasons`.`pads` p JOIN `jules`.`pads` ON p.padid = `jules`.`pads`.`PadID` where p.RemoveMeDate <> '2001-01-01 00:00:00' AND `jules`.`pads`.RemoveMeDate = '2001-01-01 00:00:00'

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• Splitting tables by field to optimize MySQL?

  - by AK

  Do splitting fields into multiple tables ever yield faster queries? Consider the following two scenarios: Table1 ----------- int PersonID text Value1 float Value2 or Table1 ----------- int PersonID text Value1 Table2 ----------- int PersonID float Value2 If Value1 and Value2 are always being displayed together, I imagine Table1 is always faster because the second schema would require two SELECT statements. But are there any situations where you would choose the second? If the number of records were expected to be really large?

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• MySQL Query exceptions

  - by Wayne

  In one page, it should show records that has the following selected month from the drop down menu and it is set in the ?month=March So the query will do this $sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) . "' AND finished='0' ORDER BY date ASC"; But it shows records that has a value of 2 in the finished column and I don't want the query to include this. I've tried $sql = "SELECT * FROM schedule WHERE month = '" . Clean($_GET['month']) . "' AND finished='0' OR finished = '1' OR finished = '3' ORDER BY date ASC"; But it shows records on different months when it shouldn't be. So basically I want the record to exclude the records that has the value of 2 in the record that will not be shown in the page.

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• PHP/MYSQL Year Month table for news archive

  - by ee12csvt

  Hi all, I am creating a news archive for my site and want to create an overview page from the following DB table id - Unique identifier newsDate - in a format XXXX-XX-XX title - News Item title details - News item photo - News Item Photo caption - News Item Photo caption update - Timestamp for record The news on the site is current but I hope to add some data from years gone by over the next few months and years. What I want to do is create a new line for each year and highlight the month which corresponds to a record in the DB table, similar to that below. 2002 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC 2004 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC 2005 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC 2008 JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC Any help or advice would be much appreciated Cheers

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• PHP returns invalid MySQL resource

  - by DeadMG

  $LDATE = '#' . $_REQUEST['LDateDay'] . '/' . $_REQUEST['LDateMonth'] . '/' . $_REQUEST['LDateYear'] . '#'; $RDATE = '#' . $_REQUEST['RDateDay'] . '/' . $_REQUEST['RDateMonth'] . '/' . $_REQUEST['RDateYear'] . '#'; include("../../sql.php"); $myconn2 = mysql_connect(/*removed*/, $username, $password); mysql_select_db(/*removed*/, $myconn2); $LSQLRequest = "SELECT * FROM flight WHERE DepartureDate = ".$LDATE; $LFlights = mysql_query($LSQLRequest, $myconn2); $RSQLRequest = "SELECT * FROM flight WHERE DepartureDate = ".$RDATE; $RFlights = mysql_query($RSQLRequest, $myconn2); Assuming that all the $_REQUESTs are valid numerical values for their appropriate fields in the day/month/year field, how can LFlights and RFlights be invalid? When I polled the whole database I got hundreds of results so I know that the database and connection data is fine, and the field DepartureDate exists too.

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• Mysql - Grouping the result based on a mathematical operation and SUM() function

  - by SpikETidE

  Hi all... I'm having the following two tables... Table : room_type type_id type_name no_of_rooms max_guests rate 1 Type 1 15 2 1254 2 Type 2 10 1 3025 Table : reservation reservation_id start_date end_date room_type booked_rooms 1 2010-04-12 2010-04-15 1 8 2 2010-04-12 2010-04-15 1 2 Now... I have this query SELECT type_id, type_name FROM room_type WHERE id NOT IN (SELECT room_type FROM reservation WHERE start_date >= '$start_date' AND end_date <= '$end_date') What the query does is it selects the rooms that are not booked between the start date and end date. Also, as you can see from the reservation table, we also have 'number of rooms booked between the two dates' factor also... I need to add this 'no.of booked rooms between the two dates' factor also in to the query... The query should return the type of rooms for which at least one room is free between the two dates. I worked out the logic but just can't represent it as a query....! How will you do this...? Thanks for your suggestions..!

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• MySQL won't use index for query?

  - by Jack Sleight

  I have this table: CREATE TABLE `point` ( `id` INT(11) NOT NULL AUTO_INCREMENT, `siteid` INT(11) NOT NULL, `lft` INT(11) DEFAULT NULL, `rgt` INT(11) DEFAULT NULL, `level` SMALLINT(6) DEFAULT NULL, PRIMARY KEY (`id`), KEY `point_siteid_site_id` (`siteid`), CONSTRAINT `point_siteid_site_id` FOREIGN KEY (`siteid`) REFERENCES `site` (`id`) ON DELETE CASCADE ) ENGINE=INNODB AUTO_INCREMENT=35 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci And this query: SELECT * FROM `point` WHERE siteid = 1; Which results in this EXPLAIN information: +----+-------------+-------+------+----------------------+------+---------+------+------+-------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+-------+------+----------------------+------+---------+------+------+-------------+ | 1 | SIMPLE | point | ALL | point_siteid_site_id | NULL | NULL | NULL | 6 | Using where | +----+-------------+-------+------+----------------------+------+---------+------+------+-------------+ Question is, why isn't the query using the point_siteid_site_id index?

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• Levenshtein: MySQL + PHP

  - by user317005

  $word = strtolower($_GET['term']); $lev = 0; $q = mysql_uqery("SELECT `term` FROM `words`"); while($r = mysql_fetch_assoc($q)) { $r['term'] = strtolower($r['term']); $lev = levenshtein($word, $r['term']); if($lev >= 0 && $lev < 5) { $word = $r['term']; } } how can I move all that into just one query? don't want to have to query through all terms and do the filtering in php.

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• ORDER BY column_name help (via link in HTML table view) (PHP MySQL

  - by Derek

  My output for my table in HTML has several columns such as userid, name, age, dob. The table heading is simply the title of the column name, I want this to be a link, and when clicked, the selected column is sorted in order, ASC, and then DESC (on next click). I thought this was pretty straight forward but I'm having some difficulty. So far, I have produced this, and no output is taken, apart from the URL works by displaying 'users.php?orderby=userid' <?php if(isset($_GET['orderby'])){ $orderby = $_GET['orderby']; $query_sv = "SELECT * FROM users BY ".mysql_real_escape_string($orderby)." ASC"; } //default query else{ $query_sv = "SELECT * FROM users BY user_id DESC"; } ?> <tr> <th><a href="<?php echo $_SERVER['php_SELF']."?orderby=userid";?>">User ID</a></th> Hoefully if I get this working, I can sort the users by D.O.B. next also using the same principles. Does anyone have any ideas?

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• MySQL cross table regular expression match

  - by Josef Sábl

  I have a web application and I am working on engine that analyzes referals. Now I have table with pageviews along with referes that looks something like this: pv_id referer ------------------------------------------------------------ 5531854534 http://www.google.com/search?ie=UTF-8... 8161876343 http://google.cn/search?search=human+rights 8468434831 http://search.yahoo.com/search;_... The second table contains sources definitions like: source regex ------------------------------------------------------------ Google ^https?:\/\/[^\/]*google\.([a-z]{2,4})(\/.*|)$ Yahoo ^https?:\/\/[^\/]*yahoo\.com(\/.*|)$ What I want is third table created by joinin these two: pv_id source ------------------------------------------------------------ 5531854534 Google 8161876343 Google 8468434831 Yahoo How to join these tables with regular expression?

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• mysql and indexes with more than one column

  - by clarkk

  How to use indexes with more than one column The original index has an index on block_id, but is it necesarry when it's already in the unique index with two column? Indexes with more than one column (a,b,c) you can search for a, b and c you can search for a and b you can search for a you can not search for a and c Does this apply to unique indexes too? table id block_id account_id name indexes origin PRIMARY KEY (`id`) UNIQUE KEY `block_id` (`block_id`,`account_id`) KEY `block_id` (`block_id`), KEY `account_id` (`account_id`), indexes alternative PRIMARY KEY (`id`) UNIQUE KEY `block_id` (`block_id`,`account_id`) KEY `account_id` (`account_id`),

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