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• Drupal: allowing users to sign up to content using a form

  - by james6848

  My apologies if this is a little broad, but I'm struggling to know where to start here! OK, so I have a Drupal site and I need users to be able to sign up for certain content, here is the workflow in detail: I need a form within a block consisting of the following elements: First Name (required) Last Name (required) Organisation (optional) Email Address (required) Then there will be a choice of content to sign up to (using checkboxes): Policy Bulletin Action News eBulletin (which only members can sign up to) Then the usual submit button of course! Upon submission, users will: 1) Be taken to a confirmation page, or 2) Be informed about incorrectly filled in fields, and/or the need to become a user to be able to sign up for the eBulletin. Users will then receive an email when new content of the type(s) they signed up to is created, along with a link to the node. There should be details about how to unsubscribe within this email. I have used the Subscriptions module in the past, but I am not sure if it is possible to use a sign-up form with it. Plus, there is the added complexity that one of the content types, eBulletin, is only available for site members. Like I say, I'm struggling to know where to start, and any ideas would be gratefully received!

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• Running code/script as a result of a form submission in ASP.NET

  - by firmbeliever

  An outside vendor did some html work for us, and I'm filling in the actual functionality. I have an issue that I need help with. He created a simple html page that is opened as a modal pop-up. It contains a form with a few input fields and a submit button. On submitting, an email should be sent using info from the input fields. I turned his simple html page into a simple aspx page, added runat=server to the form, and added the c# code inside script tags to create and send the email. It technically works but has a big issue. After the information is submitted and the email is sent, the page (which is supposed to just be a modal pop-up type thing) gets reloaded, but it is now no longer a pop-up. It's reloaded as a standalone page. So I'm trying to find out if there is a way to get the form to just execute those few lines of c# code on submission without reloading the form. I'm somewhat aware of cgi scripts, but from what I've read, that can be buggy with IIS and all. Plus I'd like to think I could get these few lines of code to run without creating a separate executable. Any help is greatly appreciated.

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• How to accept confirmation Automatically in PowerShell for Outlook

  - by user2919845

  How to accept confirmation Automatically in PowerShell for Outlook I have script for Export attachments from email from Outlook - see next It works correctly on one PC, but on another PC is there a problem: Outlook gives message and wants answer: Permit Denny Help If I manually click on Permit or Denny it works correctly. I want to automate it. Can you give me some suggestion how to do it in PowerShell? I have tried to set Outlook to not give this message but I didn’t success. My script: # <-- Script ---------> # script works with outlook Inbox folder # check if email have attachments with ".txt" and save those attachments to $filepath # path for exported files - attachments $filepath = "d:\Exported_files\" # create object outlook $o = New-Object -comobject outlook.application $n = $o.GetNamespace("MAPI") # $f - folder „dorucena posta“ 6 - Inbox $f = $n.GetDefaultFolder(6) # 6 - Inbox # select newest 10 emails, from it olny this one with attachments $f.Items| select -last 10| Where {$_.Attachments}| foreach { # process only unreaded mail if($_.unread -eq $True) { # processed mail set as read, not to process this mail again next day $_.unread = $False $SenderName = $_.SenderName Write-Host "Email from: ", $SenderName # process all attachments $_.attachments|foreach { $a = $_.filename If ($a.Contains(".txt")) { Write-Host $SenderName," ", $a # copy *.txt attachments to folder $filepath $_.saveasfile((Join-Path $filepath "$a")) } } } } Write-Host "Finish" # <------ End Script ---------------------------------->

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• Stored Procedure Parameters Not Available After Declared

  - by SidC

  Hi All, Pasted below is a stored procedure written in SQL Server 2005. My intent is to call this sproc from my ASP.NEt web application through the use of a wizard control. I am new to SQL Server and especially to stored procedures. I'm unsure why my parameters are not available to the web application and not visible in SSMS treeview as a parameter under my sproc name. Can you help me correct the sproc below so that the parameters are correctly instantiated and available for use in my web application? Thanks, Sid Stored Procedure syntax: USE [Diel_inventory] GO /****** Object: StoredProcedure [dbo].[AddQuote] Script Date: 05/09/2010 00:31:10 ******/ SET ANSI_NULLS ON GO SET QUOTED_IDENTIFIER ON GO ALTER procedure [dbo].[AddQuote] as Declare @CustID int, @CompanyName nvarchar(50), @Address nvarchar(50), @City nvarchar(50), @State nvarchar(2), @ZipCode nvarchar(5), @Phone nvarchar(12), @FAX nvarchar(12), @Email nvarchar(50), @ContactName nvarchar(50), @QuoteID int, @QuoteDate datetime, @NeedbyDate datetime, @QuoteAmt decimal, @ID int, @QuoteDetailPartID int, @PartNumber float, @Quantity int begin Insert into dbo.Customers (CompanyName, Address, City, State, ZipCode, OfficePhone, OfficeFAX, Email, PrimaryContactName) Values (@CompanyName, @Address, @City, @State, @ZipCode, @Phone, @FAX, @Email, @ContactName) set @CustID = scope_identity() Insert into dbo.Quotes (fkCustomerID,NeedbyDate,QuoteAmt) Values(@CustID,@NeedbyDate,@QuoteAmt) set @QuoteID = scope_identity() Insert into dbo.QuoteDetail (ID) values(@ID) set @ID=scope_identity() Insert into dbo.QuoteDetailParts (QuoteDetailPartID, QuoteDetailID, PartNumber, Quantity) values (@ID, @QuoteDetailPartID, @PartNumber, @Quantity) END

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• Error with MySQL Query

  - by Ken

  Okay, I must be an idiot, because this is my 3rd question for today. Here's my code: date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "********"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db("`users`, $con) or die(mysql_error()"); $query = ("INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password'))"); mysql_query('$query') or die(mysql_error()); mysql_close($con); echo("Thank you for registering!"); I always get the error returned as: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$query' at line 1. Help a newbie. I'm about to stab my monitor.

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• I can't insert data into my database

  - by Ken

  I don't know why, but my data doesn't go into my database 'users' with the table 'data'. <html> <body> <?php date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db(`users`, $con) or die(mysql_error()); mysql_query(INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password')) or die(mysql_error()); mysql_close($con) echo("Thank you for registering!"); ?> </body> </html> All i get is a blank page.

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• CakePHP Observe field for validation check(already exists)

  - by deck john

  i have already user observe field in cakephp 1.3 Now i want to do the same thing in cakephp 2.0 I have one form.there is a one field named email. When user insert email. onblur there is a popup one message that displays "email already exists" or "right" for that i have write below code in my projects. the below code is my add file code <?php $options = array('url' => array( 'controller' => 'users', 'action' => 'is_exist'), 'update' => 'email_exist'); echo $this->ajax->observeField('UserEmailId',array('url' => array( 'controller' => 'users', 'action' => 'is_exist'), 'update' => 'email_exists')); ?> In my controller i have created one function like public function is_exist($id = null) { $result = "yes"; $this->set('existdata',$result); } i have also created is_exists.ctp fiel in view/uers. i dont know why its not working. i did the same thing in Cakephp 1.3 and its working file but not in cakephp 2.0 can anyone tell me how i implement this ? thanks in advance

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• MongoDB C# - Hide property from serializer

  - by ehftwelve

  This is what my user model looks like: namespace Api.Models { public class User { [BsonId(IdGenerator = typeof(StringObjectIdGenerator))] [BsonRequired] public string Id { get; set; } [Required(ErrorMessage = "Username is required.")] [StringLength(20, MinimumLength=3, ErrorMessage="Username must be between 3 and 20 characters.")] [BsonRequired] public string Username { get; set; } [Required(ErrorMessage="Email is required.")] [EmailAddress(ErrorMessage="Valid email required.")] [BsonRequired] public string Email { get; set; } [Required(ErrorMessage = "Password is required.")] [StringLength(50, MinimumLength=8, ErrorMessage="Password must be between 8 and 50 characters.")] [BsonRequired] public string Password { get; set; } [BsonRequired] public string Salt { get; set; } } } I want to write, and require, all of the properties into the MongoDB Database. What I don't want to do, is expose the Password and Salt properties when I send this through the request. Is there any sort of data attribute that I can set that will write it, but not expose it when displayed to any API user?

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• Regular Expression with Names and Emails

  - by Nina

  I am having a problem with regular expressions at the moment. What I'm trying to do is that for each line through the iteration, it checks for this type of pattern: Lastname, Firstname If it finds the name, then it will take the first letter of the first name, and the first six letters of the lastname and form it as an email. I have the following: $checklast = "[A-z],"; $checkfirst = "[A-z]"; if (ereg($checklast, $parts[1])||ereg($checkfirst, $parts[2])){ $first = preg_replace($checkfirst, $checkfirst{1,1}, $parts[2]); print "<a href='mailto:[email protected];'> $parts[$i] </a>"; } This one obviously broke the code. But I was initially attempting to find only the first letter of the firstname and then after that the first six letters of the lastname followed by the @email.com This didn't work out too well. I'm not sure what to do at this point. Any help is much appreciated.

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• Consume a JSON webservice and process data in Android

  - by user1783391

  I am trying to consume a the webservice below http://62.253.195.179/disaster/webservices/login.php?message=[{"email":"[email protected]","password":"welcome"}] This returns a JSON array [{"companyuserId":"2","name":"ben stein","superiorname":"Leon","departmentId":"26","departmentname":"Development","companyId":"23","UDID":"12345","isActive":"1","devicetoken":"12345","email":"[email protected]","phone":"5456465465654","userrole":"1","chngpwdStatus":"1"}] My code is below try{ String weblink = URLEncoder.encode("http://62.253.195.179/disaster/webservices/login.php?message=[{\"email\":\"[email protected]\",\"password\":\"welcome\"}]"); HttpParams httpParameters = new BasicHttpParams(); int timeoutConnection = 7500; HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection); int timeoutSocket = 7500; HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket); HttpClient client = new DefaultHttpClient(httpParameters); HttpGet request = new HttpGet(); URI link = new URI(weblink); request.setURI(link); HttpResponse response = client.execute(request); BufferedReader rd = new BufferedReader(new InputStreamReader( response.getEntity().getContent())); result = rd.readLine(); JSONObject myData = new JSONObject(result); JSONArray jArray = myData.getJSONArray(""); JSONObject steps = jArray.getJSONObject(0); String name = steps.getString("name"); } catch (JSONException e) { e.printStackTrace(); } But its not working and I am not 100% sure this is the best way to do it. 11-10 10:49:55.489: E/AndroidRuntime(392): java.lang.IllegalStateException: Target host must not be null, or set in parameters.

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• MySQL query returning mysql_error

  - by Sebastian

  This returns mysql_error: <?php $name = $_POST['inputName2']; $email = $_POST['inputEmail2']; $instruments = $_POST['instruments']; $city = $_POST['inputCity']; $country = $_POST['inputCountry']; $distance = $_POST['distance']; // ^^ These all echo properly ^^ // CONNECT TO DB $dbhost = "xxx"; $dbname = "xxx"; $dbuser = "xxx"; $dbpass = "xxx"; $con = mysqli_connect("$dbhost", "$dbuser", "$dbpass", "$dbname"); if (mysqli_connect_errno()) { echo "Failed to connect to MySQL: " . mysqli_connect_error(); } $query = "INSERT INTO depfinder (name, email, instrument1, instrument2, instrument3, instrument4, instrument5, city, country, max_distance) VALUES ($name, $email, $instruments[0], $instruments[1], $instruments[2], $instruments[3], $instruments[4], $city, $country, $max_distance)"; $result = mysqli_query($con, $query) or die(mysqli_error($con)); // script fails here if (!$result) { echo "There was a problem with the signup process. Please try again later."; } else { echo "Success"; } } ?> N.B. I'm not sure whether it's relevant, but the user may not choose five instruments so some $instrument[] array values may be empty. Bonus question: is my script secure enough or is there more I could do?

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• How can I test a form that requires the entry of two random characters from a security phrase?

  - by lawm

  I need to test a two-stage login system which first asks for your email address and password and then presents the user with two select lists containing [a-zA-Z0-9]. The labels beside the drop down's are of the form 'Select character X from your security phrase', where X is a random character index from a known security phrase. I'd rather not stub the code for an acceptance test, so is it possible to write a matcher in cucumber which will, given that we know the whole phrase, select the required character in each of the two lists? Here is the scenario I have so far and the steps involved: Scenario: valid login email, password and secret phrase takes me to the dashboard Given I am not logged in When I log in as "[email protected]" Then I should be on the dashboard page And I should see "Your Dashboard" When /^I log in as "([^\"]*)"$/ do |login| visit path_to('Login page') fill_in "Email", :with => login fill_in "Password", :with => "Password123" click_button "Log in" response.should contain("Please verify some characters from your security phrase") select "a", :from => "Select character X of your security phrase" select "b", :from => "Select character Y of your security phrase" click_button "Submit" end For example, if the security phrase is 'Secret123', X = 3 and Y = 8, the above would have to produce the equivalent of: select "c", :from => "Select character 3 of your security phrase" select "2", :from => "Select character 8 of your security phrase" The numbers X and Y in the actual page are inside span#svc_1 and span#svc_2 respectively. Thanks,

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• Only want "Required field" error to appear ONCE in ASP.NET Validation Summary

  - by PapillonUK

  I have a form with several fields with a RequiredFieldValidator on them. If any of these fields are not filled in I only want the message "Please enter the items marked with an asterisk" to appear once in the ValidationSummary control and an asterisk to appear next to each field. I have done this using the method here. i.e. by setting Text to "*" and ValidationSummary.HeaderText to my message. Great, but no cigar as I also have other fields with other validators e.g. a RegEx for an Email field. This means that if all the required fields are entered but the email is incorrect, the ValidationSummary with "Please enter the items marked with an asterisk" will appear along with the message for the invalid email. Crap! I then tried using a ValidationGroup called "ReqField" and have a one ValidationSummary for this group (with my HeaderText) and another for the other validators, but alas, my Submit button only allows one ValidationGroup to be triggered upon the click event. Does anyone have any ideas as to how I can get this to work? Thanks in adavnce.

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• DotNetOpenAuth getting return_To url as the provider

  - by Jeff

  I have a provider that I'm upgrading from version 2 to version 3. basically a user comes to one of our sites and we say "if you don't have an openID sign up with this one" They click that and are sent to our in house provider what signs them up for an account and has to verify their email address. In the link I send via Email I included the return to url . This way when they click the link to verify their email (sometimes up to a week later) they are sent to our page that knows to send them back to the returnTo to login. I could not find a good way to do this in version 2 so I used a hack. Sadly this hack broke in version 2 so I'm completely stumped as to how to find the login page url that is the return_To Note: I need the full URL not just the domain. old hack: if (ProviderEndpoint.PendingAuthenticationRequest != null) { req = ProviderEndpoint.PendingAuthenticationRequest.ToString(); int startpos = req.LastIndexOf("CheckIdRequest.ReturnTo = '"); startpos += "CheckIdRequest.ReturnTo = '".Length; int endpos = req.LastIndexOf("token=") - startpos-1; if (endpos > 0) { req = req.Substring(startpos, endpos); } else { log.Fatal("Missing token in url" + ProviderEndpoint.PendingAuthenticationRequest.ToString()); return "~/"; } req = req.Replace("&internalLogin=True", ""); req = req.Replace("?internalLogin=True&", "?"); req = req.Replace("?internalLogin=True", ""); }

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• (Android) Seems like my JSON query is getting double encode

  - by A Gardner

  Hi, I am getting some weird errors with my Android App. It appears that this code is double encoding the JSON string. What should be sent is ?{"email":"[email protected]","password":"asdf"} or ?%7B%22email%22:%22..... what the server is seeing is %257B%2522email%2522:%2522 .... which means the server sees %7B%22email%22:%22 ..... This confuses the server. Any ideas why this is happening? Thanks for your help Code: DefaultHttpClient c = new DefaultHttpClient(); if(cookies!=null) c.setCookieStore(cookies); if(loginNotLogout){ jso.put("email", userData.email); jso.put("password", userData.password); } URI u = null; if(loginNotLogout) u= new URI("HTTP","www.website.com","/UserService",jso.toString(),""); else u= new URI("HTTP","www.website.com","/UserService",jso.toString(),""); HttpGet httpget = new HttpGet(u); HttpResponse response = c.execute(httpget); ret.jsonString = EntityUtils.toString(response.getEntity());

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• PHP mail may be filtered out by spam?

  - by Derek

  I am creating a small company, and would like to send out emails to my clients once they have signed up for my service to activate their accounts. I am currently using PHP's mail() function, however I am worried that my emails are being filtered out by spam filters. Is there a better way to go about this? $email = 'XZY Client Email address @ somedomain.com'; $emailSubject = "Welcome to XYZ Service!"; $to = $email; $subject .= "".$emailSubject.""; $headers .= "From: [email protected]\r\n" . "X-Mailer: php"; $headers .= "MIME-Version: 1.0\r\n"; $headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n"; $message = "<html><body>"; $message .= "Welcome to XYZ Service! \n Activate your account by clicking the following link: link..."; mail($to, $subject, $message, $headers); Is there a way to authenticate these emails so that my clients know that they are from my actual service? Thank you in advance!

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• JSON is not being recognised

  - by richzilla

  Hi All, Im having a bit of trouble getting my JSON to be recognised by my web page. I have validated JSON that im getting returned from server, so i know that is correct, however my javascript function is not doing anything with it. My succes function is as follows: success: function(data) { $('input[name=customer_name]').val(data.name); $('textarea[name=customer_address]').text(data.address); $('input[name=customer_email]').val(data.email); $('input[name=customer_tel]').val(data.tel); $('input[name=user_id]').val(item.id); } Yet the fields are not being repopulated with the data that is returned, if it helps, a sample of my JSON data: { "name": "Terry O'Toole", "address": "Terrys House\nTerry Street\nTerrysville\nTerrytown\nTT1 6TT", "email": "[email protected]", "tel": "05110000000" } Any help would be appreciated. [EDIT] Expanded ajax call: $.ajax({ url: "<?php echo site_url('user/users/ajax'); ?>", type: 'POST', data: {"userid": item.id}, success: function(data) { $('input[name=customer_name]').val(data.name); $('textarea[name=customer_address]').text(data.address); $('input[name=customer_email]').val(data.email); $('input[name=customer_tel]').val(data.tel); $('input[name=user_id]').val(item.id); } }) });

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• SQL dealing with rubbish in a phone number field

  - by DoctaJonez

  Hello stackers! I've got a wonderfully fun little SQL problem to solve today and thought I'd ask the community to see what solutions you come up with. We've got a really cool email to text service that we use, you just need to send an email to [email protected] and it will send a text message to the desired phone number. For example to send a text to 0790 0006006, you need to send an email to [email protected], pretty neat huh? The problem is with the phone numbers in our database. Most of the phone numbers are fine, but some of them have "rubbish" mixed in with the phone number. Take these wonderful examples of the rubbish you need to deal with (I've anonymised the phone numbers by placing zeroes in): 07800 000647(mobile) 07500 000189 USE 1ST SEE NOTES 07900 000415 HO ONLY try 1st 0770 0000694 then home 07500 000465 Cannot Requirements The solution needs to be in SQL (for MS SQL server). So the challenge is as follows, we need to get the phone number without spaces, and without any of the rubbish seen in the samples. For example: This: try 1st 0770 0000694 then home Should become this: 07700000694 Anything without a phone number in it (e.g. "SEE NOTES") should be null.

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• Struts2 Hibernate Login with User table and group table

  - by J2ME NewBiew

  My problem is, i have a table User and Table Group (this table use to authorization for user - it mean when user belong to a group like admin, they can login into admincp and other user belong to group member, they just only read and write and can not login into admincp) each user maybe belong to many groups and each group has been contain many users and they have relationship are many to many I use hibernate for persistence storage. and struts 2 to handle business logic. When i want to implement login action from Struts2 how can i get value of group member belong to ? to compare with value i want to know? Example I get user from username and password then get group from user class but i dont know how to get value of group user belong to it mean if user belong to Groupid is 1 and in group table , at column adminpermission is 1, that user can login into admincp, otherwise he can't my code: User.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import java.util.Date; import java.util.HashSet; import java.util.Set; import javax.persistence.CascadeType; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.FetchType; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.JoinColumn; import javax.persistence.JoinTable; import javax.persistence.ManyToMany; import javax.persistence.Table; import javax.persistence.Temporal; /** * * @author Administrator */ @Entity @Table(name="User") public class User implements Serializable{ private static final long serialVersionUID = 2575677114183358003L; private Long userId; private String username; private String password; private String email; private Date DOB; private String address; private String city; private String country; private String avatar; private Set<Group> groups = new HashSet<Group>(0); @Column(name="dob") @Temporal(javax.persistence.TemporalType.DATE) public Date getDOB() { return DOB; } public void setDOB(Date DOB) { this.DOB = DOB; } @Column(name="address") public String getAddress() { return address; } public void setAddress(String address) { this.address = address; } @Column(name="city") public String getCity() { return city; } public void setCity(String city) { this.city = city; } @Column(name="country") public String getCountry() { return country; } public void setCountry(String country) { this.country = country; } @Column(name="email") public String getEmail() { return email; } public void setEmail(String email) { this.email = email; } @ManyToMany(fetch = FetchType.LAZY, cascade = CascadeType.ALL) @JoinTable(name="usergroup",joinColumns={@JoinColumn(name="userid")},inverseJoinColumns={@JoinColumn( name="groupid")}) public Set<Group> getGroups() { return groups; } public void setGroups(Set<Group> groups) { this.groups = groups; } @Column(name="password") public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } @Id @GeneratedValue @Column(name="iduser") public Long getUserId() { return userId; } public void setUserId(Long userId) { this.userId = userId; } @Column(name="username") public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } @Column(name="avatar") public String getAvatar() { return avatar; } public void setAvatar(String avatar) { this.avatar = avatar; } } Group.java /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.model; import java.io.Serializable; import javax.persistence.Column; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.Id; import javax.persistence.Table; /** * * @author Administrator */ @Entity @Table(name="Group") public class Group implements Serializable{ private static final long serialVersionUID = -2722005617166945195L; private Long idgroup; private String groupname; private String adminpermission; private String editpermission; private String modpermission; @Column(name="adminpermission") public String getAdminpermission() { return adminpermission; } public void setAdminpermission(String adminpermission) { this.adminpermission = adminpermission; } @Column(name="editpermission") public String getEditpermission() { return editpermission; } public void setEditpermission(String editpermission) { this.editpermission = editpermission; } @Column(name="groupname") public String getGroupname() { return groupname; } public void setGroupname(String groupname) { this.groupname = groupname; } @Id @GeneratedValue @Column (name="idgroup") public Long getIdgroup() { return idgroup; } public void setIdgroup(Long idgroup) { this.idgroup = idgroup; } @Column(name="modpermission") public String getModpermission() { return modpermission; } public void setModpermission(String modpermission) { this.modpermission = modpermission; } } UserDAO /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.dao; import java.util.List; import org.dejavu.software.model.User; import org.dejavu.software.util.HibernateUtil; import org.hibernate.Query; import org.hibernate.Session; /** * * @author Administrator */ public class UserDAO extends HibernateUtil{ public User addUser(User user){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); session.save(user); session.getTransaction().commit(); return user; } public List<User> getAllUser(){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); List<User> user = null; try { user = session.createQuery("from User").list(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } public User checkUsernamePassword(String username, String password){ Session session = HibernateUtil.getSessionFactory().getCurrentSession(); session.beginTransaction(); User user = null; try { Query query = session.createQuery("from User where username = :name and password = :password"); query.setString("username", username); query.setString("password", password); user = (User) query.uniqueResult(); } catch (Exception e) { e.printStackTrace(); session.getTransaction().rollback(); } session.getTransaction().commit(); return user; } } AdminLoginAction /* * To change this template, choose Tools | Templates * and open the template in the editor. */ package org.dejavu.software.view; import com.opensymphony.xwork2.ActionSupport; import org.dejavu.software.dao.UserDAO; import org.dejavu.software.model.User; /** * * @author Administrator */ public class AdminLoginAction extends ActionSupport{ private User user; private String username,password; private String role; private UserDAO userDAO; public AdminLoginAction(){ userDAO = new UserDAO(); } @Override public String execute(){ return SUCCESS; } @Override public void validate(){ if(getUsername().length() == 0){ addFieldError("username", "Username is required"); }if(getPassword().length()==0){ addFieldError("password", getText("Password is required")); } } public String getPassword() { return password; } public void setPassword(String password) { this.password = password; } public String getRole() { return role; } public void setRole(String role) { this.role = role; } public User getUser() { return user; } public void setUser(User user) { this.user = user; } public String getUsername() { return username; } public void setUsername(String username) { this.username = username; } } other question. i saw some example about Login, i saw some developers use interceptor, im cant understand why they use it, and what benefit "Interceptor" will be taken for us? Thank You Very Much!

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• method for creating PHP templates (ie html with variables)?

  - by Haroldo

  I'm designing my html emails, these are to be a block of html containing variables that i can store in a $template variable. My problem comes with the storing in the variable part. putting all my html into php makes it a pain in the bum to work with. for example, the below code is fine for a simple email but once i start getting nested tables etc its going to get really confusing... $template.= 'Welcome ' . $username . '<br /><br /><br />'; $template.= 'Thank-you for creating an account <br /><br />'; $template.= 'Please confirm your account by click the link below! <br /><br />'; $template.= '<a href="' . $sitepath . '?email=' . $email . '&conf_key=' . $key . '" style="color: #03110A;"><font size="5" font-family="Verdana, Geneva, sans-serif" color="#03110A">' . $key . '</font></a>'; $template.='</body></html>'; is there a way i can still store the html in a $var but not have to write it like this?

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• Filtering string in Python

  - by Ecce_Homo

  I am making algorithm for checking the string (e-mail) - like "E-mail addres is valid" but their are rules. First part of e-mail has to be string that has 1-8 characters (can contain alphabet, numbers, underscore [ _ ]...all the parts that e-mail contains) and after @ the second part of e-mail has to have string that has 1-12 characters (also containing all legal expressions) and it has to end with top level domain .com EDIT email = raw_input ("Enter the e-mail address:") length = len (email) if length > 20 print "Address is too long" elif lenght < 5: print "Address is too short" if not email.endswith (".com"): print "Address doesn't contain correct domain ending" first_part = len (splitting[0]) second_part = len(splitting[1]) account = splitting[0] domain = splitting[1] for c in account: if c not in "abcdefghijklmopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789_.": print "Invalid char", "->", c,"<-", "in account name of e-mail" for c in domain: if c not in "abcdefghijklmopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789_.": print "Invalid char", "->", c,"<-", "in domain of e-mail" if first_part == 0: print "You need at least 1 character before the @" elif first_part> 8: print "The first part is too long" if second_part == 4: print "You need at least 1 character after the @" elif second_part> 16: print "The second part is too long" else: # if everything is fine return this print "E-mail addres is valid" EDIT: After reproting what is wrong with our input, now I need to make Python recognize valid address and return ("E-mail adress is valid") This is the best i can do with my knowledge....and we cant use regular expressions, teacher said we are going to learn them later.

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• Creating 1 page PDF of iPad Screen view - How?

  - by user314695

  Hi All, I've asked this question on a couple other forums and have had zero response, so I'm hoping someone here can help point me in the right direction. I have a pretty simple one screen application for my work. It's basically just a recreation of a 1 page paper report that has a company logo, some labels, a few text boxes and a scroll text box for the report. I need to be able to fill out the report then click a button to save it in a graphical form so I can fax, print or email it later. Currently, I'm just programmatically taking a screen capture and saving it to the photo's library (default for screen capture). Then I can just email it from photo's. This works ok, but is kind of hacky, at best. I've read through the new iPad 3.2 guide for creating PDF's (apparently it's supposed to be much easier than before) but I can not get it to work and I've spent countless hours on it now. I'm hoping someone has the answer for me. Alternatively, if anyone knows how I can redirect where the screen capture is stored (default is in the photo album) then maybe I can make that function work. If I could redirect the screen capture to store in my applications document folder, then I can use MFMailCompose to attach it to an email. Lastly, on a side note, does anyone know of a good way to capture a digital signature via touch. For instance, I'd love to have my users be able to just sign their name via touch at the bottom of the document before I convert to PDF or take a screen capture. Thanks in advance for your help. -Ray

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• selenium and firefox timeout behavior

  - by Md. Reazul Karim

  I am facing this strange timeout behavior. I tried to load some page using: WebDriver drv = new FirefoxDriver(); drv.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS); drv.get(url); String email = ""; try { WebElement aElem = Util.safeFindElementByXpath(drv, "//p[1]/a[1]"); if (aElem != null) { email = aElem.getAttribute("href"); } } catch (Exception e) { } drv.quit(); return email; The safeFindElementByXpath is: static WebElement safeFindElementByXpath(WebDriver driver, String xpath) { try { return driver.findElement(By.xpath(xpath)); } catch (NoSuchElementException e) { return null; } } Now I set the firefox network.http.connection-timeout and network.http.connection-retry-timeout both to 10. Now if I restart the firefox I can see the new values. But if I try to run the above code - the firefox window opens and it waits for a particular website for a long time. Hence I open another tab in the same firefox window and check the values of timeout and find them to be 90 and 250. If I change the values on that same window, the selenium code immediately finishes requesting for the page (ie it goes after the exception block). So the thing is that the same code will work on many sites and I don't know beforehand which site is invalid/down and I was thinking of putting this code in a separate thread and kill the thread after some time from the calling thread. But that is not possible I guess because the child thread has no way to poll anything as it is stuck at page request and can't go to the polling code afterwards. Now the thing is that I want any kind of hack/workaround to accomplish this: try getting the emails for good sites and if there are bad sites just give up after a certain period (press the panic button sorta thing). Thanks

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• HELP A NEWB (AGAIN) PLZ

  - by Ken

  Okay, I must be an idiot, because this is my 3rd question for today. Here's my code: date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "********"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db("`users`, $con) or die(mysql_error()"); $query = ("INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password'))"); mysql_query('$query') or die(mysql_error()); mysql_close($con); echo("Thank you for registering!"); I always get the error returned as: "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '$query' at line 1. Help a newbie. I'm about to stab my monitor.

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• Devise password reset issue (new_user?)

  - by rabid_zombie

  When a user's email is inputted into the forgot password form and submitted, I am receiving an error saying login can't be blank. I looked around devise.en.yml for this error message, but can't seem to find it anywhere. Here is my views/devise/passwords/new.html.haml: %div.registration_page %h2 Forgot your password? = form_for(resource, :as => resource_name, :url => user_password_path, :html => { :method => :post, :id => 'forgot_pw_form', :class => 'forgot_pw' }) do |f| %div = f.email_field :email, :placeholder => 'Email', :autofocus => true, :autocomplete => 'off' %div.email_error.error %input.btn.btn-success{:type => 'submit', :value => 'Send Instructions'} = render "devise/shared/links" The form is posting to users/password like it should, but I noticed that my forgot password form attaches class = 'new_user'. Here is what my form displays: <form accept-charset='UTF-8' action='/users/password' class='new_user' id='forgot_pw_form' method='post' novalidate='novalidate'></form> My routes for devise (I have custom sessions and registrations controllers): devise_for :users, :controllers => {:sessions => 'sessions', :registrations => 'registrations'} How can I setup devise's forgot password functionality? Why am I receiving this error message and why is that class being added there? I've tried: Adding my own passwords controller and adding new routes for my custom controller. Same error Adding my own class and id to the form. This successfully changes the id and class of the form, but reverts back to class and id of new_user Thanks.

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