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  • Parsing HTML: Call to a member function > children() on a non-object

    - by sm56d
    Hello all, I was just helped with this question but I can't get it to move to the next block of HTML. $html = file_get_html('http://music.banadir24.com/singer/aasha_abdoo/247.html'); $urls = $html->find('table[width=100%] table tr'); foreach($urls as $url){ $song_name = $url->children(2)->plaintext; $url = $url->children(6)->children(0)->href; } It returns the list of the names of the first album (Deesco) but it does not continue to the next album (The Best Of Aasha)? It just gives me this error: Notice: Trying to get property of non-object in C:\wamp\www\test3.php on line 26 Fatal error: Call to a member function children() on a non-object in C:\wamp\www\test3.php on line 28 Why is this and how can I get it to continue to the next table element? I appreciate any help on this! Please note: This is legal as the songs are not bound by copyright and they are available to download freely, its just I need to download a lot of them and I can't sit there clicking a button all day. Having said that, its taken me an hour to get this far.

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  • Chrome extension custom cursor

    - by the_nakos
    Hi, I building an Google Chrome extension that place some IMG tag in sites. This img tag on :hover must show a custom cursor. The extension uses jQuery as its injected core script. I tried the following methods: 1. var cursor = 'url('+chrome.extension.getURL('icons/cursor.cur')+')'; $('#myImgId').css({ 'position': 'absolute', 'top':'5px', 'left':'5px', 'cursor':cursor }); This is the best working. On smaller sites its shows the cursor. On slower loading sites it does not. But on little sites it fails sometimes. 2. var cursor = 'url('+chrome.extension.getURL('icons/cursor.cur')+')'; $('<style>#myImgId{cursor:'+cursor+'}</style>').appendTo('head'); This did nothing at all. 3. In manifest.json I injected the css. "content_scripts": [ { "matches": ["http://*/*"], "css": ["css/style.css"], "js": ["j/c.js", "j/s.js"] } The css file just had the cursor:url(icons/cursor.cur) as I don't have idea, how to get real url in a css file. This isn't working at all. I think it must work like this, I didn't find reference for this on code.google though.

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  • Java Trying to get a line of source from a website

    - by dsta
    I'm trying to get one line of source from a website and then I'm returning that line back to main. I keep on getting an error at the line where I define InputStream in. Why am I getting an error at this line? public class MP3LinkRetriever { private static String line; public static void main(String[] args) { String link = "www.google.com"; String line = ""; while (link != "") { link = JOptionPane.showInputDialog("Please enter the link"); try { line = Connect(link); } catch(Exception e) { } JOptionPane.showMessageDialog(null, "MP3 Link: " + parseLine(line)); String text = line; Toolkit.getDefaultToolkit( ).getSystemClipboard() .setContents(new StringSelection(text), new ClipboardOwner() { public void lostOwnership(Clipboard c, Transferable t) { } }); JOptionPane.showMessageDialog(null, "Link copied to your clipboard"); } } public static String Connect(String link) throws Exception { String strLine = null; InputStream in = null; try { URL url = new URL(link); HttpURLConnection uc = (HttpURLConnection) url.openConnection(); in = new BufferedInputStream(uc.getInputStream()); Reader re = new InputStreamReader(in); BufferedReader r = new BufferedReader(re); int index = -1; while ((strLine = r.readLine()) != null && index == -1) { index = strLine.indexOf("<source src"); } } finally { try { in.close(); } catch (Exception e) { } } return strLine; } public static String parseLine(String line) { line = line.replace("<source", ""); line = line.replace(" src=", ""); line = line.replace("\"", ""); line = line.replace("type=", ""); line = line.replace("audio/mpeg", ""); line = line.replace(">", ""); return line; } }

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  • Getting response status code 0 in SmartGWT webservice call using json

    - by Girish
    I have developed application using SmartGWT, now i need to call webservice using json to another application which is deployed in another server for submitting username and password. When i make a request with url and POST method, getting the response status code as 0 and response text as blank. Here is my code, public void sendRequest() throws Exception { // Get login json data to be sent to server. String strData = createLoginReqPacket(); String url = "some url"; RequestBuilder builder = new RequestBuilder(RequestBuilder.POST, url); builder.setHeader("Content-Type", "application/json"); builder.setHeader("Content-Length", strData.length() + ""); Request response = builder.sendRequest(strData, new RequestCallback() { @Override public void onResponseReceived(Request request, Response response) { int statusCode = response.getStatusCode(); System.out.println("Response code ----"+response.getStatusCode()+""); if (statusCode == Response.SC_OK) { String responseBody = response.getText(); System.out.println("Respose :" + responseBody); // do something with the response } else { GWT.log("Response error at server side ----",null); // do in case of server error } }// end of method. @Override public void onError(Request request, Throwable exception) { GWT.log("**** Error in service call ******",null); }// end of method. }); builder.send(); }// end of send request. Please anybody knows the solution?? Give some reference code or links for this. Thanks.

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  • App-Engine Parse a UrlFetch UTF-8 encoded stream

    - by Davidrd91
    I am trying to parse an XML from a URL using the xml.sax parser. I know there are other libraries to use but coming from Java this is the one I am most familiar with and seems the least complicated to me. The code I'm using to parse is as follows: parser = xml.sax.make_parser() handler = MangaHandler() parser.setContentHandler(handler) url = urlfetch.Fetch('http://www.mangapanda.com/alphabetical', allow_truncated = False, follow_redirects = False, deadline = False) xml.sax.parseString(url.content, handler) This returns a SaxException (invalid token) once the parser reaches the first & sign: SAXParseException: <unknown>:582:34: not well-formed (invalid token) Because urlfetch returns a string and not a stream I cannot use the parse() (which only works with streams) and am left to use parseString() instead. To see if parsing as a stream would fix this I tried: parser.parse(io.StringIO(url.content).encode('utf-8')) but this returns: TypeError: initial_value must be unicode or None, not str I have also tried to use the urllib2 libraries which do return a stream instead of urlfetch but the file is too large and is automatically truncated, leaving me with missing data. Any Sort of work-around for this would be greatly appreciated as I've spent days getting around one obstacle just to be stopped by another.

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  • overwrite parameters passed by querystring

    - by opensas
    I have the following problem I have a web framework built with classic asp that saves the page state in hidden textboxes, and then issues a submit to itself. Before submitting, we have a javascript functions that saves the action in a hidden "action" input, and then performs the submit. The page loads the state from those hidden texts, reads the action issued, reads extra parameters, like the id of the record to edit, and then builds the page accordingly. I'd like to make a url link to automatically start the page with "edit" action on a "x" id. So I was thinking about building the following url, for example http://myapp/user?action=edit&id=23 the problem is that when the page auto-submits, que url string keeps the parameters. I'd like to achieve the following: when the user clicks on http://myapp/user?action=edit&id=23 my page should receive the posted values action=edit and id=23 but the url should be just http://myapp/user and both parameters should be kept in the hidden texts... (I wonder if I make myself clear...) thanks a lot saludos sas ps: I have a couple of ideas about how to solve it, but I'll post them as answers...

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  • Adding a variable href attribute to a hyperlink using XSLT

    - by Pete
    I need to create links using dynamic values for both the URL and the anchor text. I have column called URL, which contains URL's, i.e., http://stackoverflow.com, and I have a column called Title, which contains the text for the anchor, i.e., This Great Site. I figure maybe all I need to do is nest this tags, along with a little HTML to get my desired result: <a href="> <xsl:value-of select="@URL">"> <xsl:value-of select="@Title"/> </xsl:value-of> </a> In my head, this would render: <a href=" http://stackoverflow.com"> This Great Site </a> I know there's more to it, but I haven't been able to clearly understand what more I need. I think this issue has been addressed before, but not in a way I could understand it. I'd be more than happy to improve the question's title to help noobs like myself find this item, and hopefully an answer. Any help is greatly appreciated.

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  • JQuery SelectList Option Changed doesn't refresh

    - by Jean-Philippe
    Hi. I have this select list: <select url="/Admin/SubCategories" name="TopParentId" id="ParentList"> <option value="">Please select a parent category</option> <option value="1" selected="selected">New Store</option> <option value="2">Extensions</option> <option value="3">Remodel</option> <option value="4">Bespoke Signage</option> <option value="5">Tactical Signage</option> <option value="6">Size Chart</option> <option value="7">Contact Info</option> </select> As you can see the option 1 is marked as selected. When I change the selection, I use this code to do an ajax call to get some values to populate a new select list: $("#ParentList").unbind("change"); $("#ParentList").change(function() { var itemId = $(this).val(); var url = $(this).attr("url"); var options; $.getJSON(url, itemId, function(data) { var defaultoption = '<option value="0">Please select a sub-category</option>'; options += defaultoption; $.each(data, function(index, optionData) { var option = '<option value="' + optionData.valueOf + '">' + optionData.Text + '</option>'; options += option; }); $("#SubParentList").html(options); }); }); My problem is that whenever I change the selection, the itemId is always the id of option 1, because it is marked as selected. It doesn't pick up the value of the option it is being changed too. Can someone please enlighten me of their knowledge. Regards, Jean-Philippe

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  • ASP.NET MVC twitter/myspace style routing

    - by Astrofaes
    Hi guys, This is my first post after being a long-time lurker - so please be gentle :-) I have a website similar to twitter, in that people can sign up and choose a 'friendly url', so on my site they would have something like: mydomain.com/benjones I also have root level static pages such as: mydomain.com/about and of course my homepage: mydomain.com/ I'm new to ASP.NET MVC 2 (in fact I just started today) and I've set up the following routes to try and achieve the above. public static void RegisterRoutes(RouteCollection routes) { routes.IgnoreRoute("{resource}.axd/{*pathInfo}"); routes.IgnoreRoute("content/{*pathInfo}"); routes.IgnoreRoute("images/{*pathInfo}"); routes.MapRoute("About", "about", new { controller = "Common", action = "About" } ); // User profile sits at root level so check for this before displaying the homepage routes.MapRoute("UserProfile", "{url}", new { controller = "User", action = "Profile", url = "" } ); routes.MapRoute("Home", "", new { controller = "Home", action = "Index", id = "" } ); } For the most part this works fine, however, my homepage is not being triggered! Essentially, when you browser to mydomain.com, it seems to trigger the User Profile route with an empty {url} parameter and so the homepage is never reached! Any ideas on how I can show the homepage?

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  • Why does my Perl CGI program fail with "Software error: ..."?

    - by kiran
    When I try to run my Perl CGI program, the returned web page tells me: Software error: For help, please send mail to the webmaster (root@localhost), giving this error message and the time and date of the error. Here is my code in one of the file: #!/usr/bin/perl use lib "/home/ecoopr/ecoopr.com/CPAN"; use CGI; use CGI::FormBuilder; use CGI::Session; use CGI::Carp (fatalsToBrowser); use CGI::Session; use HTML::Template; use MIME::Base64 (); use strict; require "./db_lib.pl"; require "./config.pl"; my $query = CGI-new; my $url = $query-url(); my $hostname = $query-url(-base = 1); my $login_url = $hostname . '/login.pl'; my $redir_url = $login_url . '?d=' . $url; my $domain_name = get_domain_name(); my $helpful_msg = $query-param('m'); my $new_trusted_user_fname = $query-param('u'); my $action = $query-param('a'); $new_trusted_user_fname = MIME::Base64::decode($new_trusted_user_fname); ####### Colin: Added July 12, 2009 ####### my $view = $query-param('view'); my $offset = $query-param('offset'); ####### Colin: Added July , 2009 ####### #print $session-header; #print $new_trusted_user; my $helpful_msg_txt = qq[]; my $helpful_msg_div = qq[]; if ($helpful_msg)

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  • Webview shouldoverrideurlloading doesn't work

    - by Zak
    I have this code in my app: public class Home extends Activity{ @Override public void onCreate(Bundle savedInstanceState){ super.onCreate(savedInstanceState); setContentView(R.layout.home); final ProgressDialog progressBar; if(isOnline()){ WebView webView = (WebView) findViewById(R.id.home_web); webView.setBackgroundColor(Color.parseColor(getString(R.color.colore_bg))); webView.getSettings().setJavaScriptEnabled(true); webView.getSettings().setBuiltInZoomControls(true); webView.getSettings().setPluginsEnabled(true); webView.setWebViewClient(new MyWebViewClient()); progressBar = ProgressDialog.show(this,getString(R.string.caricamento),getString(R.string.attendere)); webView.setWebViewClient(new WebViewClient(){ public void onPageFinished(WebView view, String url) { if (progressBar.isShowing()) { progressBar.dismiss(); } } }); webView.loadUrl("http://www.mysite.com/android.php"); }else{ Toast.makeText(this,getString(R.string.no_connessione),Toast.LENGTH_LONG).show(); } } private class MyWebViewClient extends WebViewClient { @Override public boolean shouldOverrideUrlLoading(WebView view, String url) { System.out.println("here"); if (Uri.parse(url).getHost().equals("mysite.com")) { // This is my web site, so do not override; let my WebView load the page return false; } // Otherwise, the link is not for a page on my site, so launch another Activity that handles URLs Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(url)); startActivity(intent); return true; } } public boolean isOnline(){ ConnectivityManager cm=(ConnectivityManager)getSystemService(Context.CONNECTIVITY_SERVICE); NetworkInfo ni = cm.getActiveNetworkInfo(); if(ni==null){ return false; } return ni.isConnected(); } } The shouldOverrideUrlLoading doesn't work, neither print the system.out, it seems to be never called. How can I repair this? I need to open all the link (except the main page www.mysite.com/iphone.php) in the default browser

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  • Android: Problems downloading images and converting to bitmaps

    - by Mike
    Hi all, I am working on an application that downloads images from a url. The problem is that only some images are being correctly downloaded and others are not. First off, here is the problem code: public Bitmap downloadImage(String url) { HttpClient client = new DefaultHttpClient(); HttpResponse response = null; try { response = client.execute(new HttpGet(url)); } catch (ClientProtocolException cpe) { Log.i(LOG_FILE, "client protocol exception"); return null; } catch (IOException ioe) { Log.i(LOG_FILE, "IOE downloading image"); return null; } catch (Exception e) { Log.i(LOG_FILE, "Other exception downloading image"); return null; } // Convert images from stream to bitmap object try { Bitmap image = BitmapFactory.decodeStream(response.getEntity().getContent()); if(image==null) Log.i(LOG_FILE, "image conversion failed"); return image; } catch (Exception e) { Log.i(LOG_FILE, "Other exception while converting image"); return null; } } So what I have is a method that takes the url as a string argument and then downloads the image, converts the HttpResponse stream to a bitmap by means of the BitmapFactory.decodeStream method, and returns it. The problem is that when I am on a slow network connection (almost always 3G rather than Wi-Fi) some images are converted to null--not all of them, only some of them. Using a Wi-Fi connection works perfectly; all the images are downloaded and converted properly. Does anyone know why this is happening? Or better, how can I fix this? How would I even go about testing to determine the problem? Any help is awesome; thank you!

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  • Images in IFRAME no longer showing after I log out of Flickr?

    - by contact-kram
    I have a iframe window which displays user's flickr images. I use the flickr.photos.search api to download the user's image from flickr. This works great when the user is logged into flickr. But when I explicitly log off the user from flickr and the yahoo network and then attempt to download the flickr images, I get redirected to www.yahoo.com in a full browser window (not in my iframe). If I remember correctly, I did not have this issue when I was not using iframes and I was being redirected to the yahoo login screen. Any suggestions? To elaborate, this URI - http://www.flickr.com/services/api/auth.howto.web.html, lists the below step - Create an auth handler When users follow your login url, they are directed to a page on flickr.com which asks them if they want to authorize your application. This page displays your application title and description along with the logo, if you uploaded one. When the user accepts the request, they are sent back to the Callback URL you defined in step 2. The URL will have a frob parameter added to it. For example, if your Callback URL was http://test.com/auth.php then the user might be redirected to http://test.com/auth.php?frob=185-837403740 (The frob value in this example is '185-837403740'). This does not happen when I am in my iframe window but it does happen in my full browser window.

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  • If attacker has original data, and encrypted data, can they determine the passphrase?

    - by Brad Cupit
    If an attacker has several distinct items (for example: e-mail addresses) and knows the encrypted value of each item, can the attacker more easily determine the secret passphrase used to encrypt those items? Meaning, can they determine the passphrase without resorting to brute force? This question may sound strange, so let me provide a use-case: User signs up to a site with their e-mail address Server sends that e-mail address a confirmation URL (for example: https://my.app.com/confirmEmailAddress/bill%40yahoo.com) Attacker can guess the confirmation URL and therefore can sign up with someone else's e-mail address, and 'confirm' it without ever having to sign in to that person's e-mail account and see the confirmation URL. This is a problem. Instead of sending the e-mail address plain text in the URL, we'll send it encrypted by a secret passphrase. (I know the attacker could still intercept the e-mail sent by the server, since e-mail are plain text, but bear with me here.) If an attacker then signs up with multiple free e-mail accounts and sees multiple URLs, each with the corresponding encrypted e-mail address, could the attacker more easily determine the passphrase used for encryption? Alternative Solution I could instead send a random number or one-way hash of their e-mail address (plus random salt). This eliminates storing the secret passphrase, but it means I need to store that random number/hash in the database. The original approach above does not require this extra table. I'm leaning towards the the one-way hash + extra table solution, but I still would like to know the answer: does having multiple unencrypted e-mail addresses and their encrypted counterparts make it easier to determine the passphrase used?

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  • Android - BitmapFactory.decodeByteArray - OutOfMemoryError (OOM)

    - by Bob Keathley
    I have read 100s of article about the OOM problem. Most are in regard to large bitmaps. I am doing a mapping application where we download 256x256 weather overlay tiles. Most are totally transparent and very small. I just got a crash on a bitmap stream that was 442 Bytes long while calling BitmapFactory.decodeByteArray(....). The Exception states: java.lang.OutOfMemoryError: bitmap size exceeds VM budget(Heap Size=9415KB, Allocated=5192KB, Bitmap Size=23671KB) The code is: protected Bitmap retrieveImageData() throws IOException { URL url = new URL(imageUrl); InputStream in = null; OutputStream out = null; HttpURLConnection connection = (HttpURLConnection) url.openConnection(); // determine the image size and allocate a buffer int fileSize = connection.getContentLength(); if (fileSize < 0) { return null; } byte[] imageData = new byte[fileSize]; // download the file //Log.d(LOG_TAG, "fetching image " + imageUrl + " (" + fileSize + ")"); BufferedInputStream istream = new BufferedInputStream(connection.getInputStream()); int bytesRead = 0; int offset = 0; while (bytesRead != -1 && offset < fileSize) { bytesRead = istream.read(imageData, offset, fileSize - offset); offset += bytesRead; } // clean up istream.close(); connection.disconnect(); Bitmap bitmap = null; try { bitmap = BitmapFactory.decodeByteArray(imageData, 0, bytesRead); } catch (OutOfMemoryError e) { Log.e("Map", "Tile Loader (241) Out Of Memory Error " + e.getLocalizedMessage()); System.gc(); } return bitmap; } Here is what I see in the debugger: bytesRead = 442 So the Bitmap data is 442 Bytes. Why would it be trying to create a 23671KB Bitmap and running out of memory?

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  • PHP Form - Edit & Delete via Text File Db

    - by Jax
    hi, I pieced together the script below from various tutorials, examples, etc... Right now the script currently: Saves Id, Name, Url with a "|" delimiter to a text file Db like: 1|John|http://www.john.com| 2|Mark|http://www.mark.com| 3|Fred|http://www.fred.com| But I'm having a hard time trying to make the "UPDATE" and "DELETE" buttons work. Can someone please post code which will: let me update/save any changed data for that row (for UPDATE button) let me delete that row (for DELETE button) PLEASE copy n paste the code below and try for yourself. I would like to keep the output format of the script below too. thanks D- $file = "data.txt"; $name = $_POST['name']; $url = $_POST['url']; $data = file('data.txt'); $i = 1; foreach ($data as $line) { $line = explode('|', $line); $i++; } if (isset($_POST['submits'])) { $fp = fopen($file, "a+"); fwrite($fp, $i."|".$name."|".$url."|\n"); fclose($fp); } ? '); } ?

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  • How to display data in spinner from json

    - by user1605913
    I am retrieving values from a json url and then storing it in a string variable. Now I want to display that value in a spinner. I have created an array list in my strings.xml file. The xml file contains following code: <string name="credit_card_title">Card Type</string> <string-array name="credit_card"> <item >Select</item> <item >Visa</item> <item >MC</item> <item >Amex</item> <item >Discover</item> my spinner code is: <Spinner android:id="@+id/crdtcrd_crdtype" android:layout_width="match_parent" android:layout_height="wrap_content" android:entries="@array/credit_card" android:prompt="@string/credit_card_title" /> After retriving the value from the json url I am storing it in variable name String cardtype Now how can I display the value of cardtype in the Spinner crtdcrd_crdtype.... the json url is: http://mygogolfteetime.com/iphone/login/[email protected]/123456 From this URL I have to retrieve the value of cardtype and after retrieving the value i have to display it in the spinner.. There are different values for cardype like visa, mc, amex and discover All these values are in my strings.xml file and after retrieving the value I have to display it in Spinner.. Help needed still not able to find the solution.. Thanks in advance...

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  • UIAlertView Will not show

    - by John
    I have a program that is requesting a JSON string. I have created a class that contains the connect method below. When the root view is coming up, it does a request to this class and method to load up some data for the root view. When I test the error code (by changing the URL host to 127.0.0.1), I expect the Alert to show. Behavior is that the root view just goes black, and the app aborts with no alert. No errors in debug mode on the console, either. Any thoughts as to this behavior? I've been looking around for hints to this for hours to no avail. Thanks in advance for your help. Note: the conditional for (error) is called, as well as the UIAlertView code. - (NSString *)connect:(NSString *)urlString { NSString *jsonString; UIApplication *app = [UIApplication sharedApplication]; app.networkActivityIndicatorVisible = YES; NSError *error = nil; NSURLResponse *response = nil; NSURL *url = [[NSURL alloc] initWithString:urlString]; NSURLRequest *req = [NSURLRequest requestWithURL:url cachePolicy:NSURLRequestReloadIgnoringCacheData timeoutInterval:10]; NSData *_response = [NSURLConnection sendSynchronousRequest: req returningResponse: &response error: &error]; if (error) { /* inform the user that the connection failed */ //AlertWithMessage(@"Connection Failed!", message); UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Oopsie!" message:@"Unable to connect! Try later, thanks." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles: nil]; [alert show]; [alert release]; } else { jsonString = [[[NSString alloc] initWithData:_response encoding:NSUTF8StringEncoding] autorelease]; } app.networkActivityIndicatorVisible = NO; [url release]; return jsonString; }

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  • Java Applet 411 Content Length

    - by user1903006
    I am new to Java. I wrote an applet with a gui that sends results (int w and int p) to a server, and I get the "411 Length Required" error. What am I doing wrong? How do you set a Content-Length? This is the method that communicates with the server: public void sendPoints1(int w, int p){ try { String url = "http://somename.com:309/api/Results"; String charset = "UTF-8"; String query = String.format("?key=%s&value=%s", URLEncoder.encode(String.valueOf(w), charset), URLEncoder.encode(String.valueOf(p), charset)); String length = String.valueOf((url + query).getBytes("UTF-8").length); HttpURLConnection connection = (HttpURLConnection) new URL(url + query).openConnection(); connection.setRequestMethod("POST"); connection.setRequestProperty("Content-Length", length); connection.connect(); System.out.println("Responce Code: " + connection.getResponseCode()); System.out.println("Responce Message: " + connection.getResponseMessage()); } catch (Exception e) { System.err.println(e.getMessage()); } }

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  • Simple search form passing the searched string through GET

    - by Brian Roisentul
    Hi, I'd like my Search form to return the following url after submit: /anuncios/buscar/the_text_I_searched My form is the following: <% form_for :announcement, :url => search_path(:txtSearch) do |f| %> <div class="searchBox" id="basic"> <%= text_field_tag :txtSearch, params[:str_search].blank? ? "Busc&aacute; tu curso r&aacute;pido y f&aacute;cil." : params[:str_search], :maxlength=> 100, :class => "basicSearch_inputField", :onfocus => "if (this.value=='Busc&aacute; tu curso r&aacute;pido y f&aacute;cil.') this.value=''", :onblur => "if(this.value=='') { this.value='Busc&aacute; tu curso r&aacute;pido y f&aacute;cil.'; return false; }" %> <div class="basicSearch_button"> <input type="submit" value="BUSCAR" class="basicSearch_buttonButton" /> <br /><a href="#" onclick="javascript:jQuery('#advance').modal({opacity:60});">Busqueda avanzada</a> </div> </div> <% end %> My routes' line for search_path is this: map.search '/anuncios/buscar/:str_search', :controller => 'announcements', :action => 'search' Well, this will work if I manually type the url I want in the brower, but definitely, if you look at the form's url, you'll find a ":txtSearch" parameter, which is not giving me the actual value of the text field when the form is submitted. And that's what I'd like to get! Could anybody help me on this?

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  • Calling a jQuery plugin inside itself

    - by Real Tuty
    I am trying to create a comet like thing. I have a plugin that collects data from a php page. The problem is that i dont know how to call the plugin inside itself. If it were a function i could go like this: function j () {setTimeout(j(), 1000);}, but i am using a jQuery plugin. Here is my plugin code: (function($) { $.fn.watch = function(ops) { var $this_ = this, setngs = $.extend({ 'type' : 'JSON', 'query' : 'GET', 'url' : '', 'data' : '', 'wait' : 1000 }, ops); if (setngs.type === '') { return false; } else if (setngs.query === '') { return false; } else if (setngs.url === '') { return false; } else if (setngs.wait === '') { return false; } else if (setngs.wait === 0) { setngs.wait = 1000; } var xhr = $.ajax({ type : setngs.query, dataType : setngs.type, url : setngs.url, success : function(data) { var i = 0; for (i = 0; i < data.length; i++) { var html = $this_.html(), str = '<li class="post" id="post-' + data[i].id + '"><div class="inner"><div class="user">' + data[i].user + '</div><div class="body">' + data[i].body + '</div></div></li>'; $this_.html(str + html); } setTimeout($this_, 1000); } }); }; })(jQuery); where it says setTimeout($this_, 1000); this is where im having trouble. I don't know what to call the plugin as. $this_ is what I thought might work but I am wrong. That is what i need to replace. Thanks for your help.

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  • Any one point me how to customize facebook share

    - by Venkat
    I am trying to share my own custom url, image, title and description using Facebook and twitter. I am having lot of images and videos in my website. So i want to make my content viral on social websites. I am trying to keep share options for both facebook and twitter for everything individually. If some one share one image i want that image in the sharing thumbnail and url will be the page url with my own title, description. Based on the url i will point the user to that pic in my website. I tried in the below way. Facebook share: <a href="javascript:;" onclick="window.open('http://www.facebook.com/share.php?u=your_page_url','facebook share','resizable=yes,width=700,height=500,scrollbars=yes,status=yes')"><img alt="facebook" src="yourimage.jpg" /></a> Twitter share: <a href="javascript:;" onclick="window.open('https://twitter.com/share','twitter share','resizable=yes,width=700,height=500,scrollbars=yes,status=yes')"><img alt="twitter" src="yourimage.jpg" /></a>

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  • A question on webpage representation in Java

    - by Gemma
    Hello there. I've followed a tutorial and came up with the following method to read the webpage content into a CharSequence public static CharSequence getURLContent(URL url) throws IOException { URLConnection conn = url.openConnection(); String encoding = conn.getContentEncoding(); if (encoding == null) { encoding = "ISO-8859-1"; } BufferedReader br = new BufferedReader(new InputStreamReader(conn.getInputStream(),encoding)); StringBuilder sb = new StringBuilder(16384); try { String line; while ((line = br.readLine()) != null) { sb.append(line); sb.append('\n'); } } finally { br.close(); } return sb; } It will return a representation of the webpage specified by the url. However,this representation is hugely different from what I use "view page source" in my Firefox,and since I need to scrape data from the original webpage(some data segement in the original "view page source" file),it will always fail to find required text on this Java representation. Did I go wrong somewhere?I need your advice guys,thanks a lot for helping!

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  • Catch hibernate exceptions with errorpage handler?

    - by membersound
    I'm catching all exceptions within: java.lang.Throwable /page.xhtml java.lang.Error /page.xhtml But what If I get eg a hibernate ex: org.hibernate.exception.ConstraintViolationException Do I have to define error-pages for EVERY maybe occuring exception? Can't I just say "catch every exception"? Update Redirect on a 404 works. But on a throwable does not! <servlet> <servlet-name>Faces Servlet</servlet-name> <servlet-class>javax.faces.webapp.FacesServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>Faces Servlet</servlet-name> <url-pattern>*.jsf</url-pattern> <url-pattern>*.xhtml</url-pattern> </servlet-mapping> <error-page> <exception-type>java.lang.Throwable</exception-type> <location>/error.xhtml</location> </error-page> <error-page> <error-code>404</error-code> <location>/error.xhtml</location> </error-page>

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  • how to get contents of site use HTTPS

    - by cashmoney
    ex of site using ssl ( HTTPs ) : https://www.eb2a.com 1 - i tried to get its content using file_get_contents, but not work and give error ex : <?php $contents = file_get_contents("https://www.eb2a.com/"); echo $contents; ?> 2 - i tried to use fopen, but not work and give error ex: <?php $url = 'https://www.eb2a.com/'; $contents = fopen($url, 'r'); echo "$contents"; ?> 3 - i tried to use CURL, but not work and give BLANK PAGE ex : function cURL($url, $ref, $header, $cookie, $p){ $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); curl_setopt($ch, CURLOPT_SSL_VERIFYHOST, 0); curl_setopt($ch, CURLOPT_USERAGENT, $_SERVER['HTTP_USER_AGENT']); curl_setopt($ch, CURLOPT_REFERER, $ref); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, 0); if ($p) { curl_setopt($ch, CURLOPT_CUSTOMREQUEST, "POST"); curl_setopt($ch, CURLOPT_POST, 1); curl_setopt($ch, CURLOPT_POSTFIELDS, $p); } $result = curl_exec($ch); curl_close($ch); if ($result){ return $result; }else{ return ''; } } $file = cURL('https://www.eb2a.com/','https://www.eb2a.com/',0,0,null); echo $file any one have any idea ??

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