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  • EF code first error "The specified index already exists. [ IX_Id ]" for object tree

    - by PascalN
    Using EF code first 4.3 I'm trying to model an object tree with a required-required relationships and a required-optional relationships. Here is a simple representation of those classes public class Top { public int Id { get; set; } public virtual Middle Middle { get; set; } } public class Middle { public int Id { get; set; } public virtual Child Child { get; set; } } public class Child { public int Id { get; set; } } Here is the OnModelCreating code modelBuilder.Entity<Top>().HasRequired(t => t.Middle).WithRequiredPrincipal().WillCascadeOnDelete(); modelBuilder.Entity<Middle>().HasRequired(t => t.Child).WithOptional().WillCascadeOnDelete(); This produces the error "The specified index already exists. [ IX_Id ]" on SQLCE After checking the db schema, both model binder fluent API configuration lines create an index IX_Id on the table Middles. Does anyone know how to work around that problem? Is there a way to set the index name? Thank you! Pascal

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  • ZendFramework Zend_Form_Element_File setDestination vs rename filter

    - by bibstha
    The code says Zend_Form_element_File::setDestination() is depricated and to use the rename filter. However the rename filter is currently codes such that when path is set, only temporary name is given. Original filename is lost. <?php $file = new Zend_Form_Element_File(); $file->setDestination('/var/www/project/public'); ?> vs <?php $file = new Zend_Form_Element_File(); $file->addFilter('Rename', array('target' => '/var/www/project/public')); ?> Any solution to upload files so that it preserves original filename structure but checks for existing file and appends _1.ext or _2.ext?

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  • Passing Func<T> to controller constructure when using Unity IoC with MVC, advantages?

    - by user1361315
    I was looking at a sample of how to setup Unity IoC with MVC, and noticed someone who recommended the approach of having the parameters of Func. I believe the advantage is this is kind of like lazy loading the service, if it never gets called it will never get executed and not consume any resources. private readonly Func<IUserService> _userService; public CourseController(Func<IUserService> userService) { this._userService = userService; } Versus a parameter without a Func: private readonly IUserService _userService; public CourseController(IUserService userService) { this._userService = userService; } Can someone explain to me the differences, is it really more effecient?

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  • MVC - thin controller idea - Codeigniter/Zend

    - by user505988
    Hi, Could some one possibly clarify this for me. In the MVC paradigm, the idea is to keep the controller as thin as possible, it is also true that the model is the bit that communicates with data sources such as the database, XML-RPC etc and this is where the business logic should go. Is the POST and GET data a 'data source' and should that kind of data be handled by the model or should it be by the controller. I would normally call a method in the model and pass it the post data, the data would be quality checked by the controller and the model method would simply do the insertion or whatever. Should it be though that controller just calls the model method if a post has occured and it is responsible for sanity check, data checks etc.

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  • Store Business Rules in XML Document, Validate afterwards in Java, how?

    - by JavaPete
    Example XML Rules document: <user> <username> <not-null/> <capitals value="false"/> <max-length value="15"/> </username> <email> <not-null/> <isEmail/> <max-length value="40"/> </email> </user> How do I implement this? I'm starting from scratch, what I currently have is a User-class, and a UserController which saves the User object in de DB (through a Service-layer and Dao-layer), basic Spring MVC. I can't use Spring MVC Validation however in our Model-classes, I have to use an XML document so an Admin can change the rules I think I need a pattern which dynamically builds an algorithm based on what is provided by the XML Rules document, but I can't seem to think of anything other than a massive amount of if-statements. I also have nothing for the parsing yet and I'm not sure how I'm gonna (de)couple it from the actual implementation of the validation-process.

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  • My store returns no code id and breaks 404 error. Magento

    - by numerical25
    I know what the issue is but I dont know how to fix it. I just migrated my magento store locally and I guess possibly some data may have been lost when transferring the DB. the DB is very large. Anyhow, when I login to my admin page, I get a 404 error, page was not found. I debugged the issue and got down to the wire. The exception is thrown in Mage/Core/Model/App.php. Line 759 to be exacted. The following is a snippet. Mage/Core/Model/App.php if (empty($this->_stores[$id])) { $store = Mage::getModel('core/store'); /* @var $store Mage_Core_Model_Store */ if (is_numeric($id)) { $store->load($id); // THIS ID IS FROM Mage_Core_Model_App::ADMIN_STORE_ID and its empty which causes the error } elseif (is_string($id)) { $store->load($id, 'code'); } if (!$store->getCode()) { // RETURNS FALSE HERE BECAUSE NO ID Specified $this->throwStoreException(); } $this->_stores[$store->getStoreId()] = $store; $this->_stores[$store->getCode()] = $store; } The store returns null because $id is null so it therefore does not load any model which explains why it returns false when calling getCode() [EDIT] If you want clarification, please ask for more before voting my post down. Remember I am still trying to get help not get neglected. I am using Version 1.4.1.1. When I type in the URL for admin, I get a 404 page. I walked through the code thouroughly and found that the Model MAGE_CORE_MODEL_STORE::getCode(); Returns Null which triggers the exception. and ends the script. I do not have any other detail. I further troubleshooted the issue by checking the database and that is what the screen shot is. Showing that there is infact data in the Code Colunn. So my question is why is the Model returning a empty column when the column clearly has a value. What can I do to further troubleshoot and figure out why its not working [EDIT UPDATE NEW] I did some research. the reason its returning NULL is because the store ID is null being passed Mage::getStoreConfigFlag('web/secure/use_in_adminhtml', Mage_Core_Model_App::ADMIN_STORE_ID); // THIS IS THE ID being specified Mage_Core_Model_App::ADMIN_STORE_ID has no value in it, so this method throws the exception. Not sure why how to fix this.

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  • Unable to send an associative array in JSON format in Zend to client

    - by Anorflame
    Hi, In one of my actions in a controller, I'm using the json view helper to send back a response to an ajax request. On the client side I alert the data that is passed to the success callback function. It works fine as long as the response is a number or an array with default keys. Once I try to send an associative array, it alerts with [object Object]. Server code: $childArray = array('key'=>'value'); $this->_helper->json($childArray); javascript: function displayChildren(data){ alert(data); } ... $.ajax({ url: "/po/add", dataType: "json", data: {format: "json"}, success: displayChildren }); I have no idea what am I doing wrong here, so any help would be appreciated...

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  • Why newly created entity object with navigation property is automaticly added to ObjectContext?

    - by Levelbit
    I have to entities: Company and Location (one to many). When I create new Location entity object and assign navigation property(Company) with the navigation property of already existing Location object (Location _new = new Location(); _new.Company = _old.Company). It seems that at that point newly created object is added to Object Context automatically, because when I call SaveChanges method that object is insert to database although I didn't call ObjectContext.AddObject(_new). I'm new in EF so there is probably reason why I have result like this? Is there need to assign also CompanyReference filed too and how to do it? IDaoFactory daoFactory = new DaoFactory(); ILocationDao locaitonDao = daoFactory.GetLocationDao(); IEnumerable<Location> locations = locaitonDao.GetLocations(); Location _old = locations.First(); Location _new = new Location(); _new.LocationName = _old.LocationName; _new.Company = _old.Company;// 1 _new.Address = _old.Address; //... ContactEntities.SaveChanges();//2 If I execute line (1) instantly _new object is added to object context and I can see additional datarow in my datagrid after line (2) is executed.

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  • How to use the Zend_Log instance that was created using the Zend_Application_Resource_Log in a model

    - by Alex
    Our Zend_Log is initialized by only adding the following lines to application.ini resources.log.stream.writerName = "Stream" resources.log.stream.writerParams.mode = "a" So Zend_Application_Resource_Log will create the instance for us. We are already able to access this instance in controllers via the following: public function getLog() { $bootstrap = $this->getInvokeArg('bootstrap'); //if (is_null($bootstrap)) return false; if (!$bootstrap->hasPluginResource('Log')) { return false; } $log = $bootstrap->getResource('Log'); return $log; } So far, so good. Now we want to use the same log instance in model classes, where we can not access the bootstrap. Our first idea was to register the very same Log instance in Zend_Registry to be able to use Zend_Registry::get('Zend_Log') everywhere we want: in our Bootstrap class: protected function _initLog() { if (!$this->hasPluginResource('Log')) { throw new Zend_Exception('Log not enabled'); } $log = $this->getResource('Log'); assert( $log != null); Zend_Registry::set('Zend_Log', $log); } Unfortunately this assertion fails == $log IS NULL --- but why?? It is clear that we could just initialize the Zend_Log manually during bootstrapping without using the automatism of Zend_Application_Resource_Log, so this kind of answers will not be accepted.

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  • Zend_Dojo_Form not rendering in layout

    - by Grant Collins
    Hi, I have a quick question about adding Zend_Dojo_Form into Zend_layouts. I have a Zend_Dojo_Form that I want to display in the layout that is used for a particular controller. I can add the form to the layout without any issue however the dojo elements fail to render, as they would do if I added the form to a standard view. Is there any reason why this would be the case? Do I need to do something to the layout so that it will enable the components for this embedded form in the layout. Any other dojo enabled forms that are added in the view using this layout work fine. My form is created in the usual way: class QuickAddJobForm extends Zend_Dojo_Form{ public function init(){ $this->setName('quickaddjobfrm') ->setMethod('post') ->setAction('/addjob/start/); /*We now create the elements*/ $jobTitle = new Zend_Dojo_Form_Element_TextBox('jobtitle', array( 'trim' => true ) ); $jobTitle->setAttrib('style', 'width:200px;') ->addFilter('StripTags') ->removeDecorator('DtDdWrapper') ->removeDecorator('HtmlTag') ->removeDecorator('Label'); .... $this->addElements(array($jobTitle, ....)); In the controller I declare the layout and the form in the init function: public function init(){ $this->_helper->layout->setLayout('add-layout'); $form = new QuickAddJobForm(); $form->setDecorators(array(array('ViewScript', array('viewScript' => 'quickAddJobFormDecorator.phtml')))); $this->_helper->layout()->quickaddjob = $form; In my layout Where I want the form I have: echo $this->layout()->quickaddjob; Why would adding this form in the layout fail to render/add the Dojo elements? All that is currently being displayed are text boxes, rather than some of the other components such as ComboBoxes/FilteringSelects etc... Thanks in advance.

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  • zend form check record no exists in database

    - by Yafa Su
    I have a form that check if email exists in the database within 2 tables. I'm using Zend_Validate_Db_NoRecordExists for both validate, but it only check the second one. Any idea why it's not working? class Application_Form_ReferUser extends Zend_Form { public $email, $freeDownload, $buyNow; public function init() { $this->setName('referUser'); $EmailExists = new Zend_Validate_Db_NoRecordExists( array( 'table' => 'referrals', 'field' => 'email' ) ); $EmailExists2 = new Zend_Validate_Db_NoRecordExists( array( 'table' => 'users', 'field' => 'email' ) ); $EmailExists->setMessage('This e-mail is already taken'); $EmailExists2->setMessage('This e-mail is already taken'); $this->email = $this->createElement('text', 'email') ->setLabel('Email') ->addValidator($EmailExists) ->addValidator($EmailExists2) ->addValidator('EmailAddress') ->setRequired(true); $this->freeDownload = $this->createElement('button', 'btn_free_download') ->setLabel('Free Download') ->setAttrib('type', 'submit'); $this->buyNow = $this->createElement('button', 'btn_buy_now') ->setLabel('Buy Now') ->setAttrib('type', 'submit'); $this->addElements(array($this->email, $this->freeDownload, $this->buyNow)); $elementDecorators = array( 'ViewHelper' ); $this->setElementDecorators($elementDecorators); } }

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  • EF - Entity Sql contains clausule with string

    - by zikrija
    Hi all, I have one question about EF. If I understand correctly EF does not support Contains. I try to achieve this: I have column(nvarchar) with this: for ex.row1. 1;3;4;5,row2. 3;4;6 row3. 7;8;16 etc. I have list(of string) with 1,6. My goal is to get row1 and row2 in result set. I try with linq to entity and with linq to sql but i can't get this right. I stuck with this and any help would be appreciated... Tnx

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  • Unique number identifier generation

    - by xwrs
    I have to create logic for generation unique number identifier for records in database. id, generated in database is a separate column. At this moment, when user calls "create record" action, I save new record, get its database id, generate record number using this id, then put it to the edit form. Using this way means that all entity fields should be nullable to save record to database. I don't like this way. I know that should be better way. Is there a better practice to generate unique number identifier? What is possibility of generating non-unique random numbers? Thank you

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  • insert with many to many relationship

    - by Luca Romagnoli
    hi, i have 2 object: user, group that have a relationship many to many i want create a user and associate some groups to it. How can i do it? thanks I've tried with this. but it's wrong: user = new User(); List<int> gruppi = new List<int>() {1,2}; utente.Group =db.Group.Where(p => gruppi.Contains(p.GruppoID)

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  • IEnumerator seems to be effecting all objects, and not one at a time

    - by PFranchise
    Hey, I am trying to alter an attribute of an object. I am setting it to the value of that same attribute stored on another table. There is a one to many relationship between the two. The product end is the one and the versions is the many. Right now, both these methods that I have tried have set all the products returned equal to the final version object. So, in this case they are all the same. I am not sure where the issue lies. Here are my two code snipets, both yield the same result. int x = 1 IEnumerator<Product> ie = productQuery.GetEnumerator(); while (ie.MoveNext()) { ie.Current.RSTATE = ie.Current.Versions.First(o => o.VersionNumber == x).RSTATE; x++; } and foreach (var product in productQuery) { product.RSTATE = product.Versions.Single(o => o.VersionNumber == x).RSTATE; x++; } The versions table holds information for previous products, each is distinguished by the version number. I know that it will start at 1 and go until it reaches the current version, based on my query returning the proper number of products. Thanks for any advice.

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  • Trying to understand the Zend_Auth OpenId

    - by Will Olbrys
    I'm using a slightly modified version of the Zend_Auth_OpenId classes to get openid logins from google apps. The results are very positive, as I seem to be getting successful results from Google. I cannot get successful results passed to Zend_Auth, though. For example, Zend_Auth_Adapter_OpenId on line 241: if (!$consumer->login($id, $this->_returnTo, $this->_root, $this->_extensions, $this->_response)) { return new Zend_Auth_Result( Zend_Auth_Result::FAILURE, $id, array("Authentication failed", $consumer->getError())); } The consumer calls login() which in turn calls the private method _checkId() in Zend_OpenId_Consumer. _checkId() always ends in redirecting to the openid server. How is this ever supposed to return a valid Zend_Auth_Result object? I'm pretty close to giving up and trying to implement another OpenId library, but I'm so close to just making this work. I must be missing something so obvious! Maybe I don't understand how openid works exactly, but if someone could help me understand I would really appreciate it.

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  • trying to show a variable in my layout

    - by user1400
    hi i have a simple question where is my code wrong ? in index controller and index action i put $this->view->username="user1"; and when i try in my layout i use echo $this->username; i got fllowing error or null value Notice: Trying to get property of non-object in D:\Zend\Apache2\htdocs\test\application\layouts\layout.phtml on line 115 thanks

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  • OrderBy on children in a LINQ Query

    - by eka808
    Hello everybody I have a user entity who contains a one to many relationship with a role entity So with this linq expression : from user in USER_TABLE.Include("USERROLE_TABLE") order by user.Name select user I can get users with related roles as a child. My problem is that i want to get roles of each user ordered alphabetically. How can i do that ? I googled a lot and don't find anything Thank's by advance !

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  • What to set the scalar type to contain a byte []. Entity in MVC2

    - by Brad8118
    I'm trying out the EF 4.0 and using the Model first approach. I'd like to store images into the database and I'm not sure of the best type for the scalar in the entity. I currently have it(the image scalar type) setup as a binary. From what I have been reading the best way to store the image in the db is a byte[]. So I'm assuming that binary is the way to go. If there is a better way I'd switch. In my controller I have: //file from client to store in the db HttpPostedFileBase file = Request.Files[inputTagName]; if (file.ContentLength > 0) { keyToAdd.Image = new byte[file.ContentLength]; file.InputStream.Write(keyToAdd.Image, 0, file.ContentLength); } This builds fine but when I run it I get an exception writing the stream to keyToAdd.Image. The exception is something like: Method does not exist. Any ideas? Note that when using a EF 4.0 model first approach I only have int16, int32, double, string, decimal, binary, byte, DateTime, Double, Single, and SByte as available types. Thanks

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  • ZF Site in ZF Site? How do I redirect form subdirectory to another subdirecotry?

    - by AD
    The deal is that I have a ZF site for which root directory is /public. How should I go about redirecting to a subdirectory if I want to do next? I want to have another subdirectory under /public/ that would not be linked to a main website in any way except it using save ZF. Lets say I have this: /public/newsite/ which will include a complete modular ZF (just I have it for the main site). That is the root directory for the NEWSITE would be /public/newsite/public. So my question how do I modify my .htaccess rules so it would redirect any requests from /public/newsite/ to /public/newsite/public/? Thank you in advance.

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  • Zend_Controller_Router_Route_Chain more routes - more problems

    - by epmspec
    When i use only langRoute and moduleRoute i have not any problems. But when i add pageRoute it is not work properly. I have tried many another ways do it (Regex etc) but none gives the desired result. Can anybody help me? $front = Zend_Controller_Front::getInstance(); $router = $front->getRouter(); //Route_page needs dispatcher and request $dispatcher = $front->getDispatcher(); $request = $front->getRequest(); // Add languag routes $langRoute = new Zend_Controller_Router_Route_Hostname( ':language.domain.com', array( 'language' => 'ru', ), array( 'language' => '^(ru|en)$', ) ); // Add module routes $moduleRoute = new Zend_Controller_Router_Route_Module(array(),$dispatcher,$request); // Add page routes $pageRoute = new Zend_Controller_Router_Route( ':uri\.html', array( 'controller' => 'index', 'module' => 'default', 'action' => 'index', 'uri' => 'index', ), array ('uri' => '[0-9a-z\-]+') ); // Add chain routes $chainedRoute = new Zend_Controller_Router_Route_Chain(); $chainedRoute->chain($pageRoute); $chainedRoute->chain($langRoute)->chain($moduleRoute); $router->addRoute('default', $chainedRoute);

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