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• Changing JButton background colour temporarily?

  - by sashep

  Hi, I'm super new to Java, and in need of some help. I'm making a little java desktop application where I basically have a grid of 4 JButtons ( 2 x 2 grid), and I need the background colour of individual JButtons to change, and after one second, change back to the original colour (the game I'm trying to make is like Simon, where you have to follow a pattern of buttons that light up). I have a vector that contains randomly generated numbers in the range of 1 to 4, and I want to be able to get each element from the vector and get the corresponding button to change to a different colour for one second (for example, if the vector contains 2 4 1, I would want button 2 to change, then button 4 to change, then button 1 to change). Is this possible or is there a better way to go about doing this with something other than JButtons? How do I implement this? Also, I'm running Mac OS X, which apparently (based on some things I've read on forums) doesn't like JButtons background changing (I think it's because of system look and feel), how can I change this so it works on mac? Thank you in advance for any help :)

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• VB.NET invalid cast exception

  - by user127147

  Hi there, I have a simple application to store address details and edit them. I have been away from VB for a few years now and need to refreash my knowledge while working to a tight deadline. I have a general Sub responsible for displaying a form where user can add contact details (by pressing button add) and edit them (by pressing button edit). This sub is stored in a class Contact. The way it is supposed to work is that there is a list with all the contacts and when new contact is added a new entry is displayed. If user wants to edit given entry he or she selects it and presses edit button Public Sub Display() Dim C As New Contact C.Cont = InputBox("Enter a title for this contact.") C.Fname = frmAddCont.txtFName.Text C.Surname = frmAddCont.txtSName.Text C.Address = frmAddCont.txtAddress.Text frmStart.lstContact.Items.Add(C.Cont.ToString) End Sub I call it from the form responsible for adding new contacts by Dim C As New Contact C.Display() and it works just fine. However when I try to do something similar using the edit button I get errors - "Unable to cast object of type 'System.String' to type 'AddressBook.Contact'." Dim C As Contact If lstContact.SelectedItem IsNot Nothing Then C = lstContact.SelectedItem() C.Display() End If I think it may be something simple however I wasn't able to fix it and given short time I have I decided to ask for help here. Thank you

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• UIImagePickerController shows last picture taken instead of camera input

  - by jules

  I'm having a strange behaviour within my app. For taking pictures i'm using the following pretty standard code for displaying the UIImagePickerController: UIImagePickerController *picker = [[UIImagePickerController alloc] init]; picker.delegate = self; picker.allowsEditing = NO; picker.sourceType = UIImagePickerControllerSourceTypeCamera; [self presentViewController:picker animated:YES completion:nil]; It works perfectly fine the first time I tap the button which calls this action. The strange behaviour starts when I tap that button again. The UIImagePickerController starts again BUT it doesnt show the input from the camera anymore. It shows the last picture I've taken. More Details of this state: Tapping on the image shows the yellow square of the auto focus. (which it actually uses to focus the camera correctly) When I tap on the ImageCapture button - the correct image is taken and presented on the screen. If I take a picture and press 'Retake' the regular camera image is presented as input. More weirdness: It has nothing to do with the iPad I'm using. Creating a new example app which only has button which calls the code from above everything works perfectly fine. I assume it has something to do with the configuration of the app. Therefore I checked everything but could not find any differences which may cause this issue. Thanks in advance for any advice! Update: I do implement the UIImagePickerControllerDelegate in order to dismiss the UIImagePickerController.

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• Problem after dismissing a modal view used in conjunction with a uisplitviewcontroller

  - by user336274

  I'm having a hard time understanding why the following is happening (and how to fix it). I've created an application using the split-view based application. I've added a UiBarButtonItem called showTheModal which calls this method found in RootViewController.m: - (IBAction)showTheModal:(id)sender { theModalController.modalPresentationStyle = UIModalPresentationFullScreen; theModalController.modalTransitionStyle = UIModalTransitionStyleCrossDissolve; [self presentModalViewController:theModalController animated:YES]; if ([detailViewController popoverController] != nil) [[detailViewController popoverController] dismissPopoverAnimated:YES]; The BarButtonItem of course, is shown at the bottom of the Default Root Controller (left side of the of the split view in landscape) or at the bottom of the popup (if in landscape). The modal view is dismissed by a button placed in a toolbar. It calls the following: [self dismissModalViewControllerAnimated: YES]; The problem I'm having is if rotate the screen, while the modal is up. Here is what happens in different scenarios (start refers to the orientation when the showTheModal button is hit, end refers to the orientation when I hit the dismissModal button). 1)Start landscape, end landscape: Everything appears fine. willHideViewController and willShowViewController methods are not called in the RootViewController (as expected) 2) Start landscape, end portrait: UI appears fine. willHideViewController is run TWICE (WHY?) 3) Start portrait, end portrait: UI appears fine. willHideViewController is run once (as expected) 4) Start portrait, end landscape: The 'Root List' button remains in the detail view (right side of the split view. Neither willHideViewController and willShowViewController are invoked (WHY??) Any thoughts as to why #2 and #4 don't behave quite the expected way?

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• Adding a Layout to bottom of the screen inside a ScrollView in Landscape mode

  - by andreea

  I have the following layout which works in Portrait mode: the Layout with the id LinearLayout02 is placed at the bottom of the screen. The problem appears when flipping to Lanscape mode, when the #LinearLayout02 is placed at the top of the screen. The question is how do I position #LinearLayout02 at the bottom of the screen in both Portrait and Landscape mode? (This happens on G1 and Xperia) Thank you The following code is placed inside a ScrollView android:layout_height="fill_parent" android:layout_width="fill_parent" android:fillViewport="true" <LinearLayout android:id="@+id/sLayout" android:layout_height="wrap_content" android:layout_width="fill_parent" android:orientation="vertical" android:paddingTop="2dip" android:layout_alignParentTop="true" android:gravity="top" > ..... </LinearLayout> <LinearLayout android:id="@+id/LinearLayout02" android:background="@drawable/bottombar_bg" android:layout_width="fill_parent" android:paddingTop="10dip" android:layout_height="56dip" android:layout_alignParentBottom="true" android:gravity="bottom" > <Button android:id="@+id/navigate" style="@style/mainBottomTabsButtonNormal" android:drawableLeft="@drawable/icon_navigation" android:text="@string/navigationSettings" android:layout_gravity="left"> </Button> <Button android:id="@+id/search" style="@style/mainBottomTabsButtonActive" android:drawableLeft="@drawable/icon_search" android:text="@string/search.label" android:layout_gravity="right"> </Button> </LinearLayout> </RelativeLayout>

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• Web user expectations

  - by Ash

  When designing a good Web GUI what expectations can we expect from an end user? I've come up with the following, but I wonder if there are any others which can suggest.. If I click on a hyperlink it will take me to another page/part of this page If I tick/untick a checkbox it might alter the page state (enable/disable elements) If I click on a button I expect it to do something to data. If I click on a button I expect something to happen immediately (either to the current page, or for me to be taken to another page) If I have clicked on a hyperlink and it has taken me to another page, I expect to be able to use the Back button to get back to the previous page in a state similar to that which I left it in If I change something in a form, I can change it back to its previous value if necessary Unless I click on the 'Submit' button nothing should happen to my data. If I bookmark/favourite a page then it should show the same related data each time I visit it If text is underlined and looks like a link, it should be a link and act as one The reasoning behind this question is more a 'UI from hell' one. For example I have come across pages which checking a tickbox next to a record will delete it, straight away, via ajax. To me that just seems wrong, a checkbox is a toggle - something which a delete operation definitely isn't!

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• How does overlayViewTouched notification work in the MoviePlayer sample code

  - by Jonathan

  Hi, I have a question regarding the MoviePlayer sample code provided by apple. I don't understand how the overlayViewTouch notification works. The NSlog message I added to it does not get sent when I touch the view (not button). // post the "overlayViewTouch" notification and will send // the overlayViewTouches: message - (void)overlayViewTouches:(NSNotification *)notification { NSLog(@"overlay view touched"); // Handle touches to the overlay view (MyOverlayView) here... } I can, however, get the NSlog notification if I place it in -(void)touchesBegan in "MyOverlayView.m". Which makes me think it is recognizing touches but not sending a notification. // Handle any touches to the overlay view - (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { UITouch* touch = [touches anyObject]; if (touch.phase == UITouchPhaseBegan) { NSLog(@"overlay touched(from touchesBegan") // IMPORTANT: // Touches to the overlay view are being handled using // two different techniques as described here: // // 1. Touches to the overlay view (not in the button) // // On touches to the view we will post a notification // "overlayViewTouch". MyMovieViewController is registered // as an observer for this notification, and the // overlayViewTouches: method in MyMovieViewController // will be called. // // 2. Touches to the button // // Touches to the button in this same view will // trigger the MyMovieViewController overlayViewButtonPress: // action method instead. NSNotificationCenter *nc = [NSNotificationCenter defaultCenter]; [nc postNotificationName:OverlayViewTouchNotification object:nil]; } } Can anyone shed light on what I am missing or doing wrong? Thank you.

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• How to figure out what error my Java Eclipse project has?

  - by Greg Mattes

  I've created a Java project from existing source with an Ant build script in Eclipse. I cannot run my project because Eclipse tells me that there is at least one error in it. Now, I know that the project runs fine on the command line, so I suspect an Eclipse configuration error. As far as I can tell, the only feedback that I have from Eclipse is a little red X on my project in the Package Explorer window and dialog window when I try to run the project says there are errors in the project This is all wonderful, but what is the error? Is there a "show me the next error" button somewhere? In the past, on other Eclipse projects, I've notice other little red X's on folders containing source files with errors, the little red X's appear on the source files as well. I scanned (manually) through all of the source files and I haven't found any other red X's (again, where is the "next error" button?). If I select the "Proceed" button I am greeted with a java.lang.NoClassDefFoundError for my main class, which makes me suspect a classpath issue. I've checked the classpath, and I'm fairly certain that it's correct. Is there a way to see the exact jvm command line that Eclipse is invoking? I realize that it might be invoking the JVM programmatically, and not on a "real" command line. In any case, is there a way, other than the run configuration dialog, to see what is actually happening when I hit the "Proceed" button?

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• Django Forms - change the render multiple select widget

  - by John

  Hi, In my model I have a manytomany field mentors = models.ManyToManyField(MentorArea, verbose_name='Areas', blank=True) In my form I want to render this as: drop down box with list of all MentorArea objects which has not been associated with the object. Next to that an add button which will call a javascript function which will add it to the object. Then under that a ul list which has each selected MentorArea object with a x next to it which again calls a javascript function which will remove the MentorArea from the object. I know that to change how an field element is rendered you create a custom widget and override the render function and I have done that to create the add button. class AreaWidget(widgets.Select): def render(self, name, value, attrs=None, choices=()): jquery = u''' <input class="button def" type="button" value="Add" id="Add Area" />''' output = super(AreaWidget, self).render(name, value, attrs, choices) return output + mark_safe(jquery) However I don't know how to list the currently selected ones underneath as a list. Can anyone help me? Also what is the best way to filter down the list so that it only shows MentorArea objects which have not been added? I currently have the field as mentors = forms.ModelMultipleChoiceField(queryset=MentorArea.objects.all(), widget = AreaWidget, required=False) but this shows all mentors no matter if they have been added or not. Thanks

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• Javascript error when attempting to open a modal window in a modal window

  - by The Sheek Geek

  The application is running on a windows server 2003 box using asp.net 2.0 and is an IE specific web app. There is a button that opens a form in an iframe using showModalDialog(...) from a function call located in the javascript. Here is an example of the fucntion: function ShowBusinessHoursSubForm( source ) { var retval = window.showModalDialog("htm/" + locLocaleID + "/SubFormHostFrame.htm", source, "dialogWidth:265px;dialogHeight:261px;help:no;scroll:no;status:no;"); } The host frame is loading an aspx page which contains the actual form that is being used. On the form that is opened there is a button that, when clicked, submits changed to the form. However, if no changed were made before the form was submitted, another modal window pops up stating that there were no changed to the form. This modal window is opened through registration of some javascript in the button click event. The code is as follows (C#): string l_S_ErrorScript = "<script type='text/javascript' language='javascript'>window.showModalDialog('htm/" + l_S_Culture + "/NotChangedErrorDialog.htm', '../../" + l_S_SkinPath + "', 'dialogWidth:310px;dialogHeight:145px;scroll:no;help:no;status:no;');</script>"; if(!m_Page.ClientScript.IsStartupScriptRegistered("ErrorScript")) { m_Page.ClientScript.RegisterStartupScript(this.GetType(), "ErrorScript", l_S_ErrorScript); } When the button is clicked and this dialog needs to appear the following javascript error appears: Error: Object doesn't support this property or method The weird thing is, if I access the application locally and try it everything works fine, but accessing from another computer causes the error. Also, depending on what server (we have many servers for testing all with windows server 2003) the error may not occur on another computer either. These computers are running the same software version using the same version of IE with the same settings. I'm inclined to believe that there is some configuration issue somewhere, but with the settings being the same it is hard to tell. I cannot really change how the app works or the technologies used either. Anyone have any ideas as to what may be causing this?

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• Custom UIButton for Iphone.

  - by Amal

  I have an view in my App which has a number of buttons based on the number of items returned by the server. So if the server returns say 10 items, there should be 10 buttons and clicking on each button should call a different person. For the above purpose I created a custom button class deriving from UIButton. @implementation HopitalButton @synthesize index; @synthesize button_type; - (id)initWithFrame:(CGRect)frame { if (self = [super initWithFrame:frame]) { UIImage* img = [UIImage imageNamed:@"dr_btn.png"]; [img stretchableImageWithLeftCapWidth:10 topCapHeight:10]; [self setBackgroundImage:img forState:UIControlStateNormal]; [self setTitleColor:[UIColor colorWithRed:0.698 green:0.118 blue:0.376 alpha:1] forState:UIControlStateNormal] ; [self setFont:[UIFont fontWithName:@"Helvetica Bold" size:13]]; self.titleLabel.textColor = [UIColor colorWithRed:178 green:48 blue:95 alpha:1]; self.adjustsImageWhenHighlighted = YES; } return self; } - (void)dealloc { [super dealloc]; } @end Now the problem with the above code is that it does not create buttons that look similar to the buttons created by default in Interface builder. The borders are missing. And I create buttons of the above type by the following code: HopitalButton* hb = [[HopitalButton alloc] init]; hb.button_type = @"call"; hb.frame = CGRectMake(50, 50 + i * 67, 220, 40); [self.scroll_view addSubview:hb]; [hb setTitle:[[[self.office_full_list objectAtIndex:i] objectForKey:@"Staff" ]objectForKey:@"FullName"] forState:UIControlStateNormal]; hb.index = [NSNumber numberWithInt:[self.button_items count]]; [self.button_items insertObject:hb atIndex:[self.button_items count]]; [hb addTarget:self action:@selector(buttonClicked:) forControlEvents:UIControlEventTouchUpInside]; I am not finding a way to set the button type for this custom button. Is there a way i can do it ? Or is there a better way to design the code.

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• Android -Layout Manager not showing buttons

  - by Arun

  The following is my code. I want an interface where I have a single line textbox, a multiline textbox with 2 buttons below. I want the multiline textbox to occupy all the space available after rendering the buttons and textbox. For this I created two LinearLayouts inside the main layout. The first one has vertical orientation with layout_width set to fill_parent. The second one is horizontal with fill_parent again. The first one has a textbox for which I have set the layout_height to fill parent. The second one has two textboxes OK and Cancel. When I run this application I get the UI, but the Buttons are very small. I have to set the button height manually. What am I doing wrong here. I don't want to hard code the button height. <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <LinearLayout android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:layout_weight="1"> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Name"></TextView> <EditText android:layout_width="fill_parent" android:layout_height="wrap_content"></EditText> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Contents"></TextView> <EditText android:layout_width="fill_parent" android:layout_height="fill_parent" android:gravity="top" /> </LinearLayout> <LinearLayout android:orientation="horizontal" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_weight="1"> <Button android:id="@+id/okbutt" android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="OK" android:layout_weight="1" /> <Button android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="Cancel" android:layout_weight="1" /> </LinearLayout> Thanks, Arun

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• In JSF How can I understand of multi checkboxes whether all of them is checked or not?

  - by Bariscan

  As you understand from the title above, I have a datatable and checkboxes in each row. I want to enable a button when at least one checkbox is selected, and disable it when there is no selected checkboxes (I mean all of them is unselected). I could achieve this as like if one of the checkboxes is selected, the button becomes enable. However, the reversable case I have to do is when the checkboxes is being unselected, when the last selected checbox becomes unselected, the button immediately must become disabled... BTW, I must do it without using a setter method nor a backing bean. Can I perform it by using jquery or a jsfunction, richfaces, etc? As a result, I want to learn how I can disable a button at the moment when all of the checkboxes are unselected? In order to clarify the case, here is my code below; <h:selectBooleanCheckbox id="selectionCheck" onclick="document.getElementById('form1:button1').disabled=false" value="#{_apiV2Product.selectValue}" > </h:selectBooleanCheckbox> Any help would be appreciated, Many thanks, Baris

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• Best way to pass image to server?

  - by Chris

  I have an SL3 application that needs to be able to pass an image to the server, and then the server will generate a PDF file with the image in it, and display it to the user. What I already have in place are the following: (1) Code to convert image to byte array (2) Code to generate PDF file with image The main problem that I am running into is the following: In order to bypass the pop-up blocker, which is a requirement for my application, I am using the following code: var button = new NavigationButton(); button.NavigateUri = new Uri("http://localhost:3616/PrintReport.aspx?ReportIndex=11&ActionType=Get&ReportIdentifier=" + reportIdentifier.ToString() + ""); button.TargetName = "_blank"; button.PerformClick(); Initially, I would pass the image to a WCF web service (as a byte array), and then "navigate" to the ASP.NET page that would display the report. However, if I do this, then I can not use my custom HyperlinkButton class, and, certain browsers, including Safari, will block a new window from opening up. Therefore, it appears that the only option is to use the HyperlinkButton class. What I need to be able to do is to somehow pass the image, as a byte array or some other data type, to the server, such that it can temporarily store the image, even if it is in a server variable, and then immediately retrieve it when I navigate to the PrintReport.aspx page. If I upload the image to an ASP.NET form and then use the HyperlinkButton class to navigate to the PrintReport page, it doesn't work, as the app navigates to the PrintReport page before the system has finished uploading the image. I can't pass it to a web service, as that would require that I navigate to the PrintReport.aspx page in the callback code of the web method that I would be passing the image to, and the HyperlinkButton will not allow that, based on security rules. Any help or ideas would be appreciated. Thanks. Chris

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• Android - Linear Layout arrangement, not positioning as expected

  - by Arun

  The following is my code. I want an interface where I have a single line textbox, a multiline textbox with 2 buttons below. I want the multiline textbox to occupy all the space available after rendering the buttons and textbox. For this I created two LinearLayouts inside the main layout. The first one has vertical orientation with layout_width set to fill_parent. The second one is horizontal with fill_parent again. The first one has a textbox for which I have set the layout_height to fill parent. The second one has two textboxes OK and Cancel. When I run this application I get the UI, but the Buttons are very small (about 5px in height). I have to set the button height manually. What am I doing wrong here. I don't want to hard code the button height. <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <LinearLayout android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent" android:layout_weight="1"> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Name"></TextView> <EditText android:layout_width="fill_parent" android:layout_height="wrap_content"></EditText> <TextView android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="Contents"></TextView> <EditText android:layout_width="fill_parent" android:layout_height="fill_parent" android:gravity="top" /> </LinearLayout> <LinearLayout android:orientation="horizontal" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_weight="1"> <Button android:id="@+id/okbutt" android:layout_width="fill_parent" android:layout_height="wrap_content" android:text="OK" android:layout_weight="1" /> <Button android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="Cancel" android:layout_weight="1" /> </LinearLayout> Thanks, Arun

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• Facebook Connect - Using both FBML and PHP Client

  - by Ryan

  I am doing my second Facebook connect site. On my first site, I used the facebook coonect FBML to sign a user in, then I could access other information via the PHP Client. With this site, using the same exact code, it doesn't seem to be working. I'd like someone to be able to sign in using the Facebook button: <fb:login-button length="long" size="medium" onlogin="facebook_onlogin();"></fb:login-button> After they have logged in, the facebook_onlogin() function makes some AJAX requests to a PHP page which attempts to use the Facebook PHP Client. Here's the code from that page: $facebook = new Facebook('xxxxx API KEY xxxxx', 'xxxxx SECRET KEY xxxxx'); //$facebook->require_login(); ** I DONT WANT THIS LINE!! $userID = $facebook->api_client->users_getLoggedInUser(); if($userID) { $user_details = $facebook->api_client->users_getInfo($userID, 'last_name, first_name'); $firstName = $user_details[0]['first_name']; $lastName = $user_details[0]['last_name']; $this->view->userID = $userID; $this->view->firstName = $firstName; $this->view->lastName = $lastName; } The problem is that the PHP Client thinks I don't have a session key, so the $userID never get set. If I override the $userID with my facebook ID (which I am logged in with) I get this error: exception 'FacebookRestClientException' with message 'A session key is required for calling this method' in C:\wamp\www\mab\application\Facebook\facebookapi_php5_restlib.php:3003 If I uncomment the require_login(), it will get a session ID, but it redirects pages around a lot and breaks my AJAX calls. I am using the same code I successfully did this with on another site. Anyone have any ideas why the PHP client don't know about the session ID after a user has logged in with the connect button? Any ideas would be greatly appreciated. Thanks!

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• How can I close a window in Perl/Tk?

  - by guy ergas

  In my Perl/Tk script I have opened two windows. After a specific button click I want to close one of them. How can I do that? Here's what I have so far: $main = new MainWindow; $sidebar = $main->Frame(-relief => "raised", -borderwidth => 2) ->pack (-side=>"left" , -anchor => "nw", -fill => "y"); $Button1 = $sidebar -> Button (-text=>"Open\nNetlist", -command=> \&GUI_OPEN_NETLIST) ->pack(-fill=>"x"); MainLoop; sub GUI_OPEN_NETLIST { $component_dialog = new MainWindow; $Button = $component_dialog -> Button (-text=>"Open\nNetlist", -command=> **close new window**) ->pack(-fill=>"x"); MainLoop; }

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• how to update Sr. No. COLUMN after removing a TR from TABLE

  - by user251336

  i have a table like <table> <tr> <td>Sr. No.</td> <td> Name</td> <td>$nbsp;</td> </tr> <tr> <td>1</td> <td>abc</td> <td>remove button</td> </tr> <tr> <td>2</td> <td>xyz</td> <td>remove button</td> </tr> <tr> <td>3</td> <td>def</td> <td>remove button</td> </tr> onclick of ' remove button ' i send ajax request & after successful response i remove the respective TR using $('#id_of_tr').remove();. till here everything goes fine but now i want to update Sr. No.s of each row. Because Initially order is 1 2 3 , when i remove second row then it becames 1 3 which i want to update it to 1 2. I hope this would help.

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• jQuery menu active link

  - by antosha

  Hello, I am trying to make a jquery menu that when I click on one of the links (without reloading the page), it changes its class to "active" and removes this class when I click on another link. here is my code : <script type="text/javascript"> $(document).ready(function() { $(".buttons").children().("a").click(function() { $(".buttons").children().toggleClass("selected").siblings().removeClass("selected"); }); }); </script> <ul class="buttons"> <li><a class="button" href="#">Link1</a></li> <li><a class="button" href="#">Link2</a></li> <li><a class="button" href="#">Link3</a></li> <li><a class="button" href="#">Link4</a></li> </ul> Can someone tell me why my code is not working and how to fix it? Thanks :)

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• jQuery + Jeditable - detect when select is changed

  - by Bryan Roth

  I'm using Jeditable for in-place editing. One the controls I am working with has the select type. When a user clicks on the field, the following select control is generated: <div id="status" class="editable_select"> <form> <select name="value"> <option value="Active">Active</option> <option value="Inactive">Inactive</option> </select> <button type="submit">Save</button> <button type="cancel">Cancel</button> </form> </div> What I am trying to figure out is how to use jQuery to detect when that select control is changed, especially since it doesn't have an ID attribute. This is what I have so far, but the event is not getting triggered: $(document).ready(function () { $('#status select').change(function () { alert("Change Event Triggered On:" + $(this).attr("value")); }); });

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• Is there a better way to refresh WebView?

  - by cdg

  Hi all. Ok. I have looked EVERYWHERE and my little brain just can't understand a better way to refresh an activity. Any suggestions that I can understand would be great. :) Here is the java code: package com.dge.dges; import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.webkit.WebView; import android.widget.Button; public class dgeActivity extends Activity { WebView mWebView; /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); mWebView = (WebView) findViewById(R.id.webview); mWebView.getSettings(); mWebView.loadUrl("http://www.websitehere.php"); Button newButton = (Button)findViewById(R.id.new_button); newButton.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { Intent intent = new Intent(dgeActivity.this, dgeActivity.class); startActivity(intent); } }); } } And here is the main.xml <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:id="@+id/RelativeLayout" android:layout_width="fill_parent" android:layout_height="fill_parent" android:background="#000000" > <WebView android:id="@+id/webview" android:layout_width="fill_parent" android:layout_height="wrap_content" android:scrollbars="none" /> <Button android:id="@+id/new_button" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_alignParentBottom="true" android:layout_centerHorizontal="true" android:text="Refresh" /> </RelativeLayout> I don't like the idea of just re-stacking activity after activity. There has to be an easier way to refresh the webview. Please help. :)

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• jQuery Tools alert works once (but only once)

  - by Jim Miller

  I'm trying to build a simple alert mechanism with jQuery Tools -- in response to a bit of Javascript code, pop up an overlay with a message and an OK button that, when clicked, makes the overlay go away. Trivial, or it should be. I've been slavishly following http://flowplayer.org/tools/demos/overlay/trigger.html, and have something that works fine the first time it's invoked, but only that time. If I repeat the JS action that should expose the overlay, it doesn't. My content/DIV: <div class='modal' id='the_alert'> <div id='modal_content' class='modal_content'> <h2>hi there</h2> this is the body <p> <button class='close'>OK</button> </p> </div> <div id='modal_background' class='modal_background'><img src='/images/overlay/f9f9f9-180.png' class='stretch' alt='' /></div> </div> and the Javascript: function showOverlayDialog() { $('#the_alert').overlay({ mask: {color: '#cccccc', loadSpeed: 200, opacity: 0.9}, closeOnClick: false, load: true }); } As I said: When showOverlayDialog() is invoked the first time, the overlay appears just like it should, and goes away when the "OK" button is clicked. But if I cause showOverlayDialog() to run again, without reloading the page, nothing happens. If I reload the page, then the pattern repeats -- the first invocation brings up the overlay, but the second one doesn't. I'm obviously missing something -- any advice out there? Thanks!

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• Using repaint() method.

  - by owca

  I'm still struggling to create this game : http://stackoverflow.com/questions/2844190/choosing-design-method-for-ladder-like-word-game .I've got it almost working but there is a problem though. When I'm inserting a word and it's correct, the whole window should reload, and JButtons containing letters should be repainted with different style. But somehow repaint() method for the game panel (in Main method) doesn't affect it at all. What am I doing wrong ? Here's my code: Main: import java.util.Scanner; import javax.swing.*; import java.awt.*; public class Main { public static void main(String[] args){ final JFrame f = new JFrame("Ladder Game"); Scanner sc = new Scanner(System.in); System.out.println("Creating game data..."); System.out.println("Height: "); //setting height of the grid while (!sc.hasNextInt()) { System.out.println("int, please!"); sc.next(); } final int height = sc.nextInt(); /* * I'm creating Grid[]game. Each row of game contains Grid of Element[]line. * Each row of line contains Elements, which are single letters in the game. */ Grid[]game = new Grid[height]; for(int L = 0; L < height; L++){ Grid row = null; int i = L+1; String s; do { System.out.println("Length "+i+", please!"); s = sc.next(); } while (s.length() != i); Element[] line = new Element[s.length()]; Element single = null; String[] temp = null; String[] temp2 = new String[s.length()]; temp = s.split(""); for( int j = temp2.length; j>0; j--){ temp2[j-1] = temp[j]; } for (int k = 0 ; k < temp2.length ; k++) { if( k == 0 ){ single = new Element(temp2[k], 2); } else{ single = new Element(temp2[k], 1); } line[k] = single; } row = new Grid(line); game[L] = row; } //############################################ //THE GAME STARTS HERE //############################################ //create new game panel with box layout JPanel panel = new JPanel(); panel.setLayout(new BoxLayout(panel, BoxLayout.Y_AXIS)); panel.setBackground(Color.ORANGE); panel.setBorder(BorderFactory.createEmptyBorder(10, 10, 10, 10)); //for each row of the game array add panel containing letters Single panel //is drawn with Grid's paint() method and then returned here to be added for(int i = 0; i < game.length; i++){ panel.add(game[i].paint()); } f.setContentPane(panel); f.pack(); f.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); f.setVisible(true); boolean end = false; boolean word = false; String text; /* * Game continues until solved() returns true. First check if given word matches the length, * and then the value of any row. If yes - change state of each letter from EMPTY * to OTHER_LETTER. Then repaint the window. */ while( !end ){ while( !word ){ text = JOptionPane.showInputDialog("Input word: "); for(int i = 1; i< game.length; i++){ if(game[i].equalLength(text)){ if(game[i].equalValue(text)){ game[i].changeState(3); f.repaint(); //simple debug - I'm checking if letter, and //state values for each Element are proper for(int k=0; k<=i; k++){ System.out.print(game[k].e[k].letter()); } System.out.println(); for(int k=0; k<=i; k++){ System.out.print(game[k].e[k].getState()); } System.out.println(); //set word to true and ask for another word word = true; } } } } word = false; //check if the game has ended for(int i = 0; i < game.length; i++){ if(game[i].solved()){ end = true; } else { end = false; } } } } } Element: import javax.swing.*; import java.awt.*; public class Element { final int INVISIBLE = 0; final int EMPTY = 1; final int FIRST_LETTER = 2; final int OTHER_LETTER = 3; private int state; private String letter; public Element(){ } //empty block public Element(int state){ this("", 0); } //filled block public Element(String s, int state){ this.state = state; this.letter = s; } public JButton paint(){ JButton button = null; if( state == EMPTY ){ button = new JButton(" "); button.setBackground(Color.WHITE); } else if ( state == FIRST_LETTER ){ button = new JButton(letter); button.setBackground(Color.red); } else { button = new JButton(letter); button.setBackground(Color.yellow); } return button; } public void changeState(int s){ state = s; } public void setLetter(String s){ letter = s; } public String letter(){ return letter; } public int getState(){ return state; } } Grid: import javax.swing.*; import java.awt.*; public class Grid extends JPanel{ public Element[]e; private Grid[]g; public Grid(){} public Grid( Element[]elements ){ e = new Element[elements.length]; for(int i=0; i< e.length; i++){ e[i] = elements[i]; } } public Grid(Grid[]grid){ g = new Grid[grid.length]; for(int i=0; i<g.length; i++){ g[i] = grid[i]; } Dimension d = new Dimension(600, 600); setMinimumSize(d); setPreferredSize(new Dimension(d)); setMaximumSize(d); } //for Each element in line - change state to i public void changeState(int i){ for(int j=0; j< e.length; j++){ e[j].changeState(3); } } //create panel which will be single row of the game. Add elements to the panel. // return JPanel to be added to grid. public JPanel paint(){ JPanel panel = new JPanel(); panel.setLayout(new GridLayout(1, e.length)); panel.setBorder(BorderFactory.createEmptyBorder(2, 2, 2, 2)); for(int j = 0; j < e.length; j++){ panel.add(e[j].paint()); } return panel; } //check if the length of given string is equal to length of row public boolean equalLength(String s){ int len = s.length(); boolean equal = false; for(int j = 0; j < e.length; j++){ if(e.length == len){ equal = true; } } return equal; } //check if the value of given string is equal to values of elements in row public boolean equalValue(String s){ int len = s.length(); boolean equal = false; String[] temp = null; String[] temp2 = new String[len]; temp = s.split(""); for( int j = len; j>0; j--){ temp2[j-1] = temp[j]; } for(int j = 0; j < e.length; j++){ if( e[j].letter().equals(temp2[j]) ){ equal = true; } else { equal = false; } } if(equal){ for(int i = 0; i < e.length; i++){ e[i].changeState(3); } } return equal; } //check if the game has finished public boolean solved(){ boolean solved = false; for(int j = 0; j < e.length; j++){ if(e[j].getState() == 3){ solved = true; } else { solved = false; } } return solved; } }

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• Prevent deferred creation of controls.

  - by Scott Chamberlain

  Here is a test framework to show what I am doing, just create a new project add a tabbed control, on tab 1 put a button on tab 2 put a check box (default names) and paste this code for its code public partial class Form1 : Form { private List<bool> boolList = new List<bool>(); BindingSource bs = new BindingSource(); public Form1() { InitializeComponent(); boolList.Add(false); bs.DataSource = boolList; checkBox1.DataBindings.Add("Checked", bs, ""); } bool updating = false; private void button1_Click(object sender, EventArgs e) { updating = true; boolList[0] = true; bs.ResetBindings(false); Application.DoEvents(); updating = false; } private void checkBox1_CheckedChanged(object sender, EventArgs e) { if (!updating) MessageBox.Show("CheckChanged fired outside of updating"); } } The issue is if you run the program and look at tab 2 then press the button on tab 1 the program works as expected, however if you press the button on tab 1 then look at tab 2 the event for the checkbox will not fire untill you look at tab 2. The reason for this is the controll on tab 2 is not in the "created" state, so its binding to change the checkbox from unchecked to checked does not happen until after the control has been "Created". checkbox1.CreateControl() does not do anything because according to MSDN CreateControl does not create a control handle if the control's Visible property is false. You can either call the CreateHandle method or access the Handle property to create the control's handle regardless of the control's visibility, but in this case, no window handles are created for the control's children. I tried getting the value of Handle(there is no CreateHandle for Button) but still the same result. Any suggestions other than have the program quickly flash all of my tabs that have data-bound check boxes when it first loads?

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• Toggle row visibility one at a time

  - by kuswantin

  I have a couple of tables with similar structures like this: <table> <tbody> <tr>content</tr> <tr>content</tr> <tr>content</tr> <tr>content</tr> <tr>content</tr> <tr>content</tr> <tr>content</tr> <tr>content</tr> ..etc --- The fake button is added here <div class="addrow">Add another</div> </tbody> </table> Since this is a long list, I have a need to toggle the rows one at a time. I just need to show the first row, of course, the rest should be toggled. The action is when I click a dynamic fake button, it will show row no. 2, and clicking again will show another next row. This is what I have done so far: $("table#field_fruit_values tr.draggable").not(':first').hide(); $("table#field_vegetables_values tr.draggable").not(':first').hide(); $("body.form table.content-multiple-table tbody").append('<div class="addrow">Add</div>'); $(".addrow").click(function() { var hiddenRow = $(this).prev('tr.draggable'); $(this).prev(hiddenRow + 1).show(); //if (hiddenRow + ':last').length) { // <= silly logic // $(this).hide(); //} }); The button only works for one row. I must have done something wrong :) When the final is reached, I also want the button to disappear. Sorry if this question sound silly. Any help would be very much appreciated. Thanks.

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