Search Results

Search found 7190 results on 288 pages for 'character codes'.

Page 209/288 | < Previous Page | 205 206 207 208 209 210 211 212 213 214 215 216  | Next Page >

  • QT intellisense question

    - by uzay95
    in this code: #include <QApplication> #include <QPushButton> int main(int argc,char *argv[]) { QApplication app(argc,argv); QPushButton *button = new QPushButton("Button Text"); QObject::connect(button,SIGNAL(clicked()),&app,SLOT(quit())); button->show(); return app.exec(); } intellisense is appearing when the cursor is in SIGNAL parenthesis to write button event. But it doesn't appear in SLOT parenthesis to write app method ? is it related with & character in front of app ?

    Read the article

  • Code Golf: Phone Number to Words

    - by Nick Hodges
    Guidelines for code-golf on SO We've all seen phone numbers that are put into words: 1-800-BUY-MORE, etc. What is the shortest amount of code you can write that will produce all the possible combinations of words for a 7 digit US phone number. Input will be a seven digit integer (or string, if that is simpler), and assume that the input is properly formed. Output will be a list of seven character strings that For instance, the number 428-5246 would produce GATJAGM GATJAGN GATJAGO GATJAHM GATJAHN GATJAHO and so on..... Winning criteria will be code from any language with the fewest characters that produce every possible letter combination. Additional Notes: To make it more interesting, words can be formed only by using the letters on a North American Classic Key Pad phone with three letters per number as defined here.That means that Z and Q are excluded. For the number '1', put a space. For the number '0', put a hyphen '-' Bonus points awarded for recognizing output as real English words. Okay, not really. ;-)

    Read the article

  • PostgreSQL String search for partial patterns removing exrtaneous characters

    - by tbrandao
    Looking for a simple SQL (PostgreSQL) regular expression or similar solution (maybe soundex) that will allow a flexible search. So that dashes, spaces and such are omitted during the search. As part of the search and only the raw characters are searched in the table.: Currently using: SELECT * FROM Productions WHERE part_no ~* '%search_term%' If user types UTR-1 it fails to bring up UTR1 or UTR 1 stored in the database. But the matches do not happen when a part_no has a dash and the user omits this character (or vice versa) EXAMPLE search for part UTR-1 should find all matches below. UTR1 UTR --1 UTR 1 any suggestions...

    Read the article

  • Accessing E4X nodes having special characters in name without breaking binding chain in flex.

    - by Jonas
    I am using E4X to bind some values from xml in flex 3. There is a problem when xml tag's (or attribute's) name has special character in it: having xml content var xml:XML = <tag> <special-name att="val" /> </tag> special-name could not be accessed using xml.special-name.@att because it is interpreted as subtraction, on the other hand using square bracket notation xml['special-name'].@att breaks binding chain. Is there an elegant way to solve this (like special language syntax) without writing custom binding setters and listeners?

    Read the article

  • Truncate a UTF-8 string to fit a given byte count in PHP

    - by fsb
    Say we have a UTF-8 string $s and we need to shorten it so it can be stored in N bytes. Blindly truncating it to N bytes could mess it up. But decoding it to find the character boundaries is a drag. Is there a tidy way? [Edit 20100414] In addition to S.Mark’s answer: mb_strcut(), I recently found another function to do the job: grapheme_extract($s, $n, GRAPHEME_EXTR_MAXBYTES); from the intl extension. Since intl is an ICU wrapper, I have a lot of confidence in it.

    Read the article

  • Why this code showing error in W3C validator?

    - by metal-gear-solid
    Why this code showing error in W3C validator "character data is not allowed here" <blockquote>all visible objects, man, are but as pasteboard masks. But in each event -- in the living act, the undoubted deed -- there, some unknown but still reasoning thing puts forth the mouldings of its feature from behind the unreasoning mask. If man will strike, strike through the mask. All visible objects, man, are but as pasteboard masks. But in each event -- in the living act, the undoubted deed -- there, some unknown but still reasoning thing puts forth the mouldings of its feature from behind the unreasoning mask. If man will strike, strike through the mask.</blockquote> It does not giving any error in this validator http://www.onlinewebcheck.com/ and not in https://addons.mozilla.org/en-US/firefox/addon/249/

    Read the article

  • Rewinding std::cout to go back to the beginning of a line

    - by fbrereto
    I'm writing a command-line tool for Mac OS X that processes a bunch of files. I would like to show the user the current file being processed, but do not want a bazillion files polluting the terminal window. Instead I would like to use a single line to output the file path, then reuse that line for the next file. Is there a character (or some other code) to output to std::cout to accomplish this? Also, if I wanted to re-target this tool for Windows, would the solution be the same for both platforms?

    Read the article

  • [PHP] preg_replace: replacing using %

    - by Juan
    Hi all, I'm using the function preg_replace but I cannot figure out how to make it work, the function just doesn't seem to work for me. What I'm trying to do is to convert a string into a link if any word contains the % (percentage) character. For instance if I have the string "go to %mysite", I'd like to convert the mysite word into a link. I tried the following... $data = "go to %mysite"; $result = preg_replace('/(^|[\s\.\,\:\;]+)%([A-Za-z0-9]{1,64})/e', '\\1%<a href=#>\\2</a>', $data); ...but it doesn't work. Any help on this would be much appreciated. Thanks Juan

    Read the article

  • Why is sql server giving a conversion error when submitting date.today to a datetime column?

    - by kpierce8
    I am getting a conversion error every time I try to submit a date value to sql server. The column in sql server is a datetime and in vb I'm using Date.today to pass to my parameterized query. I keep getting a sql exception Conversion failed when converting datetime from character string. Here's the code Public Sub ResetOrder(ByVal connectionString As String) Dim strSQL As String Dim cn As New SqlConnection(connectionString) cn.Open() strSQL = "DELETE Tasks WHERE ProjID = @ProjectID" Dim cmd As New SqlCommand(strSQL, cn) cmd.Parameters.AddWithValue("ProjectID", 5) cmd.ExecuteNonQuery() strSQL = "INSERT INTO Tasks (ProjID, DueDate, TaskName) VALUES " & _ " (@ProjID, @TaskName, @DueDate)" Dim cmd2 As New SqlCommand(strSQL, cn) cmd2.CommandText = strSQL cmd2.Parameters.AddWithValue("ProjID", 5) cmd2.Parameters.AddWithValue("DueDate", Date.Today) cmd2.Parameters.AddWithValue("TaskName", "bob") cmd2.ExecuteNonQuery() cn.Close() DataGridView1.DataSource = ds.Projects DataGridView2.DataSource = ds.Tasks End Sub Any thoughts would be greatly appreciated.

    Read the article

  • Generating short license keys with OpenSSL

    - by Marc Charbonneau
    I'm working on a new licensing scheme for my software, based on OpenSSL public / private key encryption. My past approach, based on this article, was to use a large private key size and encrypt an SHA1 hashed string, which I sent to the customer as a license file (the base64 encoded hash is about a paragraph in length). I know someone could still easily crack my application, but it prevented someone from making a key generator, which I think would hurt more in the long run. For various reasons I want to move away from license files and simply email a 16 character base32 string the customer can type into the application. Even using small private keys (which I understand are trivial to crack), it's hard to get the encrypted hash this small. Would there be any benefit to using the same strategy to generated an encrypted hash, but simply using the first 16 characters as a license key? If not, is there a better alternative that will create keys in the format I want?

    Read the article

  • Selenium: How to enter white space as the value of a text field?

    - by Andrew
    I have a form text field that is being populated with a default value. I would like to clear the value and enter white space to assert that the expected validation occurs. I am using Selenium RC and the PHPUnit Selenium extension. How can I achieve this? Note: I have already tried doing these, but they do not work: $this->type('FirstName', " "); //spaces $this->type('FirstName', "\t"); //tab character They clear the value from the field, but they do not enter the white space into the field.

    Read the article

  • How do you assign a variable with the result of a if..else block?

    - by Pierre Olivier Martel
    I had an argument with a colleague about the best way to assign a variable in an if..else block. His orignal code was : @products = if params[:category] Category.find(params[:category]).products else Product.all end I rewrote it this way : if params[:category] @products = Category.find(params[:category]).products else @products = Product.all end This could also be rewritten with a one-liner using a ternery operator (? :) but let's pretend that product assignment was longer than a 100 character and couldn't fit in one line. Which of the two is clearer to you? The first solution takes a little less space but I thought that declaring a variable and assigning it three lines after can be more error prone. I also like to see my if and else aligned, makes it easier for my brain to parse it!

    Read the article

  • how to detect an escape sequence in a string

    - by mix
    Given a string named line whose raw version has this value: \rRAWSTRING how can I detect if it has the escape character \r? What I've tried is: if repr(line).startswith('\r'): blah... but it doesn't catch it. I also tried find, such as: if repr(line).find('\r') != -1: blah doesn't work either. What am I missing? thx! EDIT: thanks for all the replies and the corrections re terminolgy and sorry for the confusion. OK, if i do this print repr(line) then what it prints is: '\rSET ENABLE ACK\n' (including the single quotes). i have tried all the suggestions, including: line.startswith(r'\r') line.startswith('\\r') each of which returns False. also tried: line.find(r'\r') line.find('\\r') each of which returns -1

    Read the article

  • PostgreSQL - best way to return an array of key-value pairs

    - by Matt W
    I'm trying to select a number of fields, one of which needs to be an array with each element of the array containing two values. Each array item needs to contain a name (character varying) and an ID (numeric). I know how to return an array of single values (using the ARRAY keyword) but I'm unsure of how to return an array of an object which in itself contains two values. The query is something like SELECT t.field1, t.field2, ARRAY(--with each element containing two values i.e. {'TheName', 1 }) FROM MyTable t I read that one way to do this is by selecting the values into a type and then creating an array of that type. Problem is, the rest of the function is already returning a type (which means I would then have nested types - is that OK? If so, how would you read this data back in application code - i.e. with a .Net data provider like NPGSQL?) Any help is much appreciated.

    Read the article

  • Problem with SQL syntax (probably simple)

    - by Bryan Folds
    I'm doing some custom database work for a module for Drupal and I get the following SQL error when trying to create my table: user warning: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'DEFAULT NULL, rooms INT DEFAULT NULL, adults INT DEFAULT NULL, children' at line 14 query: CREATE TABLE dr_enquiry ( eId INT unsigned NOT NULL auto_increment, eKey VARCHAR(16) NOT NULL, dateSent INT NOT NULL DEFAULT 0, status VARCHAR(30) NOT NULL DEFAULT 'Unanswered', custName VARCHAR(50) NOT NULL, custEmail VARCHAR(200) NOT NULL, custPhone VARCHAR(25) NOT NULL, custCountry VARCHAR(40) NOT NULL, custIP VARCHAR(11) DEFAULT NULL, offerName VARCHAR(100) NOT NULL, offerURL VARCHAR(200) NOT NULL, arrival DATETIME DEFAULT NULL, departure DEFAULT NULL, rooms INT DEFAULT NULL, adults INT DEFAULT NULL, children INT DEFAULT NULL, childAges VARCHAR(32) DEFAULT NULL, toddlers INT DEFAULT NULL, toddlerAges VARCHAR(32) DEFAULT NULL, catering VARCHAR(255) DEFAULT NULL, comments VARCHAR(255) DEFAULT NULL, agent VARCHAR(100) DEFAULT NULL, voucher VARCHAR(100) DEFAULT NULL, PRIMARY KEY (eId) ) /*!40100 DEFAULT CHARACTER SET UTF8 */ in /home/travelco/public_html/includes/database.inc on line 550.

    Read the article

  • RMI java doesn't create skeleton class

    - by pavithra
    I wrote a remote service MyremoteImpl.java and used following command after compiled it. rmic MyRemoteImpl I learned that this method suppose to create stub class and a skeleton class but I can only see the stub class, why is that? The other problem I faced after run rmiregistry I started the service but it gives following error, I doubt I get this error as I'm missing skeleton class? java.net.MalformedURLException: invalid URL String: Remote Hello at java.rmi.Naming.parseURL(Unknown Source) at java.rmi.Naming.rebind(Unknown Source) at RMIservice.MyRemoteImpl.main(MyRemoteImpl.java:22) Caused by: java.net.URISyntaxException: Illegal character in path at index 6: Remote Hello at java.net.URI$Parser.fail(Unknown Source) at java.net.URI$Parser.checkChars(Unknown Source) at java.net.URI$Parser.parseHierarchical(Unknown Source) at java.net.URI$Parser.parse(Unknown Source) at java.net.URI.<init>(Unknown Source) at java.rmi.Naming.intParseURL(Unknown Source) ... 3 more Please help me to solve this, Thanx in advance!!!

    Read the article

  • Upload and parse csv file with "universal newline" in python on Google App Engine

    - by greg
    Hi, I'm uploading a csv/tsv file from a form in GAE, and I try to parse the file with python csv module. Like describe here, uploaded files in GAE are strings. So I treat my uploaded string a file-like object : file = self.request.get('catalog') catalog = csv.reader(StringIO.StringIO(file),dialect=csv.excel_tab) But new lines in my files are not necessarily '\n' (thanks to excel..), and it generated an error : Error: new-line character seen in unquoted field - do you need to open the file in universal-newline mode? Does anyone know how to use StringIO.StringIO to treat strings like files open in universal-newline?

    Read the article

  • How to replace 'dash' with 'underscore' in an IIRF rule?

    - by jessegavin
    I have a web app which serves images based on the subdomain. We wanted to provide our users with a url like this: http://{username}.domain.com/images/myimage.jpg Instead of what we used to have: http://www.reallylongdomainname.com/users/{username}/images/myimage.jpg This makes the url shorter and less 'snoopable'. So I set up an IIRF .ini file to do some url rewriting and it works great except for the fact that some of our users folders have an underscore. And from what I've read, underscore is not a valid character in a domain name (even though IIS supports it). I want to know how I could do a find and replace in the $1 back reference so that a url like this: http://some-user.domain.com/... Could be rewritten to this: /users/some_user/.. Here's my IIRF rule. RewriteCond %{HTTP_HOST} ^(?!www)([^\.]+)\.domain\.com RewriteRule ^/(.*)$ /users/*1/$1 [L,I] Thanks for any help.

    Read the article

  • Parameters with dots on the URI

    - by robertokl
    In my application, there is a resource, machine, and a nested resource from machine: ip. I want to be able to access the URI of an Ip typing the ip address. The URI should be something like this: /machines/m123/ips/192.168.0.1.xml Where "m123" is the name of the machine and "192.168.0.1" is one of the ips of that machine. The problem here is that rails miss understand the dots from the ip and the format. When I try to access this page, i get: No route matches "/machines/m123/ips/192.168.0.1.xml" And if I replace the dots for any other character it works, witch means that rails isn't handling the dots on the URI. Is there any way to enter a more complex regexp on the routes to make sure rails can treat it the way I want? I'm using rails 2.3.5 and ruby 1.8.7. Thank you.

    Read the article

  • Can't find which row is causing conversion error

    - by Marwan
    I have the following table: CREATE TABLE [dbo].[Accounts1]( [AccountId] [nvarchar](50) NULL, [ExpiryDate] [nvarchar](50) NULL ) I am trying to convert nvarchar to datetime using this query: select convert(datetime, expirydate) from accounts I get this error: Conversion failed when converting datetime from character string. The status bar says "2390 rows". I go to rows 2390, 2391 and 2392. There is nothing wrong with the data there. I even try to convert those particular rows and it works. How can I find out which row(s) is causing the conversion error?

    Read the article

  • is there a downside to putting N in front of strings in scripts? Is it considered a "best practice"?

    - by jcollum
    Let's say I have a table that has a varchar field. If I do an insert like this: INSERT MyTable SELECT N'the string goes here' Is there any fundamental difference between that and: INSERT MyTable SELECT 'the string goes here' My understanding was that you'd only have a problem if the string contained a Unicode character and the target column wasn't unicode. Other than that, SQL deals with it just fine and converts the string with the N'' into a varchar field (basically ignores the N). I was under the impression that N in front of strings was a good practice, but I'm unable to find any discussion of it that I'd consider definitive. Title may need improvement, feel free.

    Read the article

  • F# - This code isn't compiling for me

    - by stacker
    This code isn't compiling for me: let countDown = [5L .. -1L .. 0L];; I have a book that says it should return this: val countDown : int list = [5L; 4L; 3L; 2L; 1L; 0L] Compiler Error: Program.fs(42,24): error FS0010: Unexpected character '-' in expression > > let countDown = [5L .. -1L .. 0L];; let countDown = [5L .. -1L .. 0L];; -----------------------^

    Read the article

  • Vim 80 column layout concerns

    - by cdleary
    I feel like the way I do 80-column indication in Vim is incorrect: set columns=80. At times I also set textwidth but I like to be able to see and anticipate line overflow with the set columns alternative. This has some unfortunate side effects -- I can't set number for fear of splitting between files that have different orders of line numbers; i.e. < 100 line files and = 100 line files will require two different set columns values because of the extra column used for the additional digit display. I also start new (g)Vim sessions instead of splitting windows vertically, which forces me to use the window manager's clipboard -- vsplits force me to do set columns every time I open or close a pane, so starting a new session is less hassle. How do you handle the 80-character indication when you want to set numbers, vertically split, etc.?

    Read the article

  • How can I get the text that was clicked on in Javascript?

    - by Jake
    Does anyone know if it is possible with javascript to to tell the position of a mouse click in some text? I know it's easy to get the x,y coordinates, but I'm wanting the position in the text. For example if I clicked inside <p>foo bar</p> I want to be able to tell that the click was on/after the 5th character. Or that foo b is before the click and ar is after it. By the way, I'm using jQuery too, I'm happy with pure JS and solutions that use jQ. Thanks in advance.

    Read the article

  • How can I match at the beginning of any line, including the first, with a Perl regex?

    - by JoelFan
    According the the Perl documentation on regexes: By default, the "^" character is guaranteed to match only the beginning of the string ... Embedded newlines will not be matched by "^" ... You may, however, wish to treat a string as a multi-line buffer, such that the "^" will match after any newline within the string ... you can do this by using the /m modifier on the pattern match operator. The "after any newline" part means that it will only match at the beginning of the 2nd and subsequent lines. What if I want to match at the beginning of any line (1st, 2nd, etc.)? EDIT: OK, it seems that the file has BOM information (3 chars) at the beginning and that's what's messing me up. Any way to get ^ to match anyway? EDIT: So in the end it works (as long as there's no BOM), but now it seems that the Perl documentation is wrong, since it says "after any newline"

    Read the article

< Previous Page | 205 206 207 208 209 210 211 212 213 214 215 216  | Next Page >