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  • How can I correctly calculate the direction for a moving object?

    - by Jakub Hampl
    I'm solving the following problem: I have an object and I know its position now and its position 300ms ago. I assume the object is moving. I have a point to which I want the object to get. What I need is to get the angle from my current object to the destination point in such a format that I know whether to turn left or right. The idea is to assume the current angle from the last known position and the current position. I'm trying to solve this in MATLAB. I've tried using several variations with atan2 but either I get the wrong angle in some situations (like when my object is going in circles) or I get the wrong angle in all situations. Examples of code that screws up: a = new - old; b = dest - new; alpha = atan2(a(2) - b(2), a(1) - b(1); where new is the current position (eg. x = 40; y = 60; new = [x y];), old is the 300ms old position and dest is the destination point. Edit Here's a picture to demonstrate the problem with a few examples: In the above image there are a few points plotted and annotated. The black line indicates our estimated current facing of the object. If the destination point is dest1 I would expect an angle of about 88°. If the destination point is dest2 I would expect an angle of about 110°. If the destination point is dest3 I would expect an angle of about -80°.

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  • API to calculate drive distance between 2 US street addresses?

    - by ggonsalv
    Seems simple but users have no internet access. The application will be hosted internally on as Intranet site. The application will be able to make webservice calls to the internet. I tested and tried Mapquest. However all the other providers seems to assume the users are able to access the internet so their API's are javascript based with src tags pointing to internet URL's Any ideas?

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  • How do I calculate a good hash code for a list of strings?

    - by Ian Ringrose
    Background: I have a short list of strings. The number of strings is not always the same, but are nearly always of the order of a “handful” In our database will store these strings in a 2nd normalised table These strings are never changed once they are written to the database. We wish to be able to match on these strings quickly in a query without the performance hit of doing lots of joins. So I am thinking of storing a hash code of all these strings in the main table and including it in our index, so the joins are only processed by the database when the hash code matches. So how do I get a good hashcode? I could: Xor the hash codes of all the string together Xor with multiply the result after each string (say by 31) Cat all the string together then get the hashcode Some other way So what do people think? (If you care we are using .NET and SqlServer)

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  • How do you calculate div and mod of floating point numbers?

    - by boost
    In Perl, the % operator seems to assume integers. For instance: sub foo { my $n1 = shift; my $n2 = shift; print "perl's mod=" . $n1 % $n2, "\n"; my $res = $n1 / $n2; my $t = int($res); print "my div=$t", "\n"; $res = $res - $t; $res = $res * $n2; print "my mod=" . $res . "\n\n"; } foo( 3044.952963, 7.1 ); foo( 3044.952963, -7.1 ); foo( -3044.952963, 7.1 ); foo( -3044.952963, -7.1 ); gives perl's mod=6 my div=428 my mod=6.15296300000033 perl's mod=-1 my div=-428 my mod=6.15296300000033 perl's mod=1 my div=-428 my mod=-6.15296300000033 perl's mod=-6 my div=428 my mod=-6.15296300000033 Now as you can see, I've come up with a "solution" already for calculating div and mod. However, what I don't understand is what effect the sign of each argument should have on the result. Wouldn't the div always be positive, being the number of times n2 fits into n1? How's the arithmetic supposed to work in this situation?

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  • How to calculate 8 business days from today's date?

    - by user309191
    I have a scenario where i want to find the date by subtacting 8 business days from today's date. Suppose if today's date is 04/21/10 .Now i want to show the date to be 04/09/10.Weekends should be excluded. For Example. If today's date is 04/21/10 Subtract Weekends : Saturday- 04/10/10 ,04/17/10 Sunday-04/11/10,04/18/10 The output comes out to be 04/09/10. I would like to do this with C#. Any help or suggestion would be helpful. Thanks, Sumit

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  • How do you calculate the storage size of a SimpleDB domain?

    - by C. Dragon 76
    The official documentation states: Raw byte size (GB) of all item IDs + 45 bytes per item + Raw byte size (GB) of all attribute names + 45 bytes per attribute name + Raw byte size (GB) of all attribute-value pairs + 45 bytes per attribute-value pair What is the raw size of an attribute-value pair? Is it precisely the size of the value? (I would expect so, but then why is it worded "attribute-value pair"?) Or is it the size of the attribute name plus the size of the attribute value? (In that case, there would be motivation to give your attributes really short names.) For example, what is the size of the tiny domain below? +---------------------------------------------------------+ | Item Name/ID | "Price" attribute | "Calories" attribute | |--------------+-------------------+----------------------| | "apple" | "0000.43" | "0046" | | "orange" | "0000.70" | "0053" | +---------------------------------------------------------+

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  • why IEEE floating point number calculate exponent using a biased form?

    - by lenatis
    let's say, for the float type in c, according to the IEEE floating point specification, there are 8-bit used for the fraction filed, and it is calculated as first taken these 8-bit and translated it into an unsigned number, and then minus the BIASE, which is 2^7 - 1 = 127, and the result is an exponent ranges from -127 to 128, inclusive. But why can't we just treat these 8-bit pattern as a signed number, since the resulting range is [-128,127], which is almost the same as the previous one.

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  • SQL: Is there a more efficient way to calculate elapsed hours, minutes, seconds?

    - by hamlin11
    I'm using Computed Columns to provide me with the following information: Hours, Minutes, and Seconds between a Start DateTime and Finish DateTime (Where Minutes and Seconds are between 0 and 59 and Hours can be any value 0 or greater) Computed Column for Seconds: datediff(second,[Start],[Finish]) % 60 Computed Column for Minutes: floor(datediff(second,[Start],[Finish]) / 60.0) % 60 Computed Column for Hours: floor(datediff(second,[Start],[Finish]) / 3600.0) Here's the table for reference Note: I'm also calculating TotalElapsedSeconds, TotalElapsedMinutes, and TotalElapsedHours in other computed columns, but those are easy. I just feel like I might be missing out on a nice built in function in SQL.

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  • How does MediaWiki calculate the file path to an image?

    - by Gillian
    Hi All, I'm just installing MediaWiki (loving it). I'm lookin at this for adding images. I can se the logic of [[File:MediaWiki:Image sample|50px]] but where so I set the filepath for "File" (nothing obvious in LocalSettings.php) ... or is there some other logic at work? I'd appreciate any help Thanks

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  • How to combine two rows and calculate the time difference between two timestamp values in MySQL?

    - by Nadar
    I have a situation that I'm sure is quite common and it's really bothering me that I can't figure out how to do it or what to search for to find a relevant example/solution. I'm relatively new to MySQL (have been using MSSQL and PostgreSQL earlier) and every approach I can think of is blocked by some feature lacking in MySQL. I have a "log" table that simply lists many different events with their timestamp (stored as datetime type). There's lots of data and columns in the table not relevant to this problem, so lets say we have a simple table like this: CREATE TABLE log ( id INT NOT NULL AUTO_INCREMENT, name VARCHAR(16), ts DATETIME NOT NULL, eventtype VARCHAR(25), PRIMARY KEY (id) ) Let's say that some rows have an eventtype = 'start' and others have an eventtype = 'stop'. What I want to do is to somehow couple each "startrow" with each "stoprow" and find the time difference between the two (and then sum the durations per each name, but that's not where the problem lies). Each "start" event should have a corresponding "stop" event occuring at some stage later then the "start" event, but because of problems/bugs/crashed with the data collector it could be that some are missing. In that case I would like to disregard the event without a "partner". That means that given the data: foo, 2010-06-10 19:45, start foo, 2010-06-10 19:47, start foo, 2010-06-10 20:13, stop ..I would like to just disregard the 19:45 start event and not just get two result rows both using the 20:13 stop event as the stop time. I've tried to join the table with itself in different ways, but the key problems for me seems to be to find a way to correctly identify the corresponding "stop" event to the "start" event for the given "name". The problem is exactly the same as you would have if you had table with employees stamping in and out of work and wanted to find out how much they actually were at work. I'm sure there must be well known solutions to this, but I can't seem to find them...

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  • How do I display and calculate numbers from a database on iPhone?

    - by JoshD
    I am new to designing apps and have a basic understand of Ob-C and how everything works. What I would like to do is have two tabs, one is a home screen that displays numbers and percentages that are entered on the second tab. The user will be able to store that information and refer back to it and update it. What is the best way to complete that math from the database to the "home screen"? Any tutorials, advice is great! Thanks.

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  • how to calculate the beginning of a day given milliseconds?

    - by conman
    i want to figure out the time from the beginning of the day given a days milliseconds. so say i'm given this: 1340323100024 which is like mid day of 6/21/2012. now i want the milliseconds from the beginning of the day, which would be 1340262000000 (at least i think that's what it's supposed to be.) how do i get 1340262000000 from 1340323100024? i tried doing Math.floor(1340323100024/86400000) * 86400000 but that gives me 1340236800000, which if i create a date object out of it, says its the 20th. i know i can create a date object from 1340323100024, then get the month, year, and date, to create a new object which would give me 1340262000000, but i find it ridiculous i can't figure out something so simple. any help would be appreciated. btw, i'm doing this in javascript if it makes any difference.

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  • Javascript: How to calculate the exact position of the viewport?

    - by batmanfu
    My problem is I need to get the position of the viewport relative to the extent of the entire document. I am only concerned with Firefox. My issue is that everything I have read says that: viewport height is window.innerHeight scroll position is window.pageYOffset document total height is document.height So, I would expect that if I scrolled to the bottom of a page that window.innerHeight + window.pageYOffset = document.height But it doesn't! Can someone please explain to me why this is?

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  • Calculate difference in days ActiveSupport:TimeWithZone in the most "rubyish" style?

    - by Nick
    I have a feeling someone is going to point me to another question that answers this but I've been searching with no luck over this simple issue. I have a Activerecord with a datetime property. It returns as an ActiveSupport:TimeWithZone. I know I can't compare that to DateTime.now because that doesn't include a zone so I need to use Time.zone. Makes sense. What I'm wondering is stylewise is there a "cleaner" way to do this than subtracting and dividing the result by 86400? Here's what I do: ((Time.zone.now - myActiveRecord.visit_date)/86400).to_i Works but seems un-rubyish and I feel like I'm missing something. Should I be casting, comparing or converting some other route or is this really the typical way to do this in rails? Appreciate any tips or a link to a question that already covers this. Thank you

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  • How to calculate Content-Length for a file download within Kohana PHP?

    - by moritzd
    I'm trying to send a file from within a Kohana model to the browser, but as soon as I add a Content-Length header, the file doesn't start downloading right away. Now the problem seems to be that Kohana is already outputting buffers. An ob_clean at the begin of the script doesn't help this though. Also adding ob_get_length() to the Content-Length isn't helping since this just returns 0. The getFileSize() function returns the right number: if I run the script outside of Kohana, it works. I read that exit() still calls all destructors and it might be that something is outputted by Kohana afterwards, but I can't find out what exactly. Hope someone can help me out here... This is the piece of code I'm using: public function download() { header("Expires: ".gmdate("D, d M Y H:i:s",time()+(3600*7))." GMT\n"); header("Content-Type: ".$this->getFileType()."\n"); header("Content-Transfer-Encoding: binary\n"); header("Last-Modified: " . gmdate("D, d M Y H:i:s",$this->getCreateTime()) . " GMT\n"); header("Content-Length: ".($this->getFileSize()+ob_get_length().";\n"); header('Content-Disposition: attachment; filename="'.basename($this->getFileName())."\"\n\n"); ob_end_flush(); readfile($this->getFilePath()); exit(); }

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  • How do you calculate expanding mean on time series using pandas?

    - by mlo
    How would you create a column(s) in the below pandas DataFrame where the new columns are the expanding mean/median of 'val' for each 'Mod_ID_x'. Imagine this as if were time series data and 'ID' 1-2 was on Day 1 and 'ID' 3-4 was on Day 2. I have tried every way I could think of but just can't seem to get it right. left4 = pd.DataFrame({'ID': [1,2,3,4],'val': [10000, 25000, 20000, 40000],'Mod_ID': [15, 35, 15, 42], 'car': ['ford','honda', 'ford', 'lexus']}) right4 = pd.DataFrame({'ID': [3,1,2,4],'color': ['red', 'green', 'blue', 'grey'], 'wheel': ['4wheel','4wheel', '2wheel', '2wheel'], 'Mod_ID': [15, 15, 35, 42]}) df1 = pd.merge(left4, right4, on='ID').drop('Mod_ID_y', axis=1)

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  • Calculate time taken by each cpp file to compile in VS2005?

    - by Rajiv Podar
    Hi Guys, I am writing a tool which can be used to make the matrix for the current performance of the project. For that I required to get the time taken by each file to get compiled. I tried with the following option but didn't succeed :( Tools-Options-Proejcts & Solutions - VC++ Project Settings - Build Timing- Yes From the above option I am able to get the whole time taken to build the solution but my problem is to get for each one. I am using VS2005 So anyone is having any idea then pls revert back ASAP....

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  • How to calculate the y-pixels of someones weight on a graph? (math+programming question)

    - by RexOnRoids
    I'm not that smart like some of you geniuses. I need some help from a math whiz. My app draws a graph of the users weight over time. I need a surefire way to always get the right pixel position to draw the weight point at for a given weight. For example, say I want to plot the weight 80.0(kg) on the graph when the range of weights is 80.0 to 40.0kg. I want to be able to plug in the weight (given I know the highest and lowest weights in the range also) and get the pixel result 400(y) (for the top of the graph). The graph is 300 pixels high (starts at 100 and ends at 400). The highest weight 80kg would be plot at 400 while the lowest weight 40kg would be plot at 100. And the intermediate weights should be plotted appropriately. I tried this but it does not work: -(float)weightToPixel:(float)theWeight { float graphMaxY = 400; //The TOP of the graph float graphMinY = 100; //The BOTTOM of the graph float yOffset = 100; //Graph itself is offset 100 pixels in the Y direction float coordDiff = graphMaxY-graphMinY; //The size in pixels of the graph float weightDiff = self.highestWeight-self.lowestWeight; //The weight gap float pixelIncrement = coordDiff/weightDiff; float weightY = (theWeight*pixelIncrement)-(coordDiff-yOffset); //The return value return weightYpixel; }

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  • Qt: How to force a hidden widget to calculate its layout?

    - by Chris
    What I am trying to do is render a qwidget onto a different window (manually using a QPainter) I have a QWidget (w) with a layout and a bunch of child controls. w is hidden. Until w is shown, there is no layout calculations happening, which is expected. When I call w->render(painter, w->mapToGlobal(QPoint(0,0)), I get a bunch of controls all overlapping each other. w->layout()->activate();w->layout()->update() doesn't seem to do anything. Is there a way to force the layout to happen without showing w?

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