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  • Operator overloading in C++

    - by user265260
    If you overload - like operator-(), it is to be used to the left of the object, however overloading () like operator()() it is used to the right of the object. How do we know which operator is to be used on the left and which ones to be used on the right?

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  • Must parameter of assignment operator be reference?

    - by Tim
    When overloading assignment operator of a class in C++, must its parameter be reference? For example, class MyClass { public: ... MyClass & operator=(const MyClass &rhs); ... } Can it be class MyClass { public: ... MyClass & operator=(const MyClass rhs); ... } ? Thanks!

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  • Who deletes the copied instance in + operator ? (c++)

    - by Dima
    Hello, I searched how to implement + operator properly all over the internet and all the results i found do the following steps : const MyClass MyClass::operator+(const MyClass &other) const { MyClass result = *this; // Make a copy of myself. Same as MyClass result(*this); result += other; // Use += to add other to the copy. return result; // All done! } I have few questions about this "process" : Isn't that stupid to implement + operator this way, it calls the assignment operator(which copies the class) in the first line and then the copy constructor in the return (which also copies the class , due to the fact that the return is by value, so it destroys the first copy and creates a new one.. which is frankly not really smart ... ) When i write a=b+c, the b+c part creates a new copy of the class, then the 'a=' part copies the copy to himself. who deletes the copy that b+c created ? Is there a better way to implement + operator without coping the class twice, and also without any memory issues ? thanks in advance

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  • Why friend function is preferred to member function for operator<<

    - by skydoor
    When you are going to print an object, a friend operator<< is used. Can we use member function for operator<< ? class A { public: void operator<<(ostream& i) { i<<"Member function";} friend ostream& operator<<(ostream& i, A& a) { i<<"operator<<"; return i;} }; int main () { A a; A b; A c; cout<<a<<b<<c<<endl; a<<cout; return 0; } One point is that friend function enable us to use it like this cout<<a<<b<<c What other reasons?

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  • operator overloading c++

    - by segfault
    When overloading operators, is it necessary to overload = <= and !=? It seems like it would be smart for c++ to call !operator= for !=, ! for operator<= and !< for operator=. Is that the case, or is it necessary to overload every function?

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  • Problems with first argument being string when overloading the + operator in C++

    - by Chris_45
    I have an selfmade Stringclass: //String.h String & operator = (const String &); String & operator = (char*); const String operator+ (String& s); const String operator+ (char* sA); . . //in main: String s1("hi"); String s2("hello"); str2 = str1 + "ok";//this is ok to do str2 = "ok" + str1;//but not this way //Shouldn't it automatically detect that one argument is a string and in both cases?

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  • Can't operator == be applied to generic types in C#?

    - by Hosam Aly
    According to the documentation of the == operator in MSDN, For predefined value types, the equality operator (==) returns true if the values of its operands are equal, false otherwise. For reference types other than string, == returns true if its two operands refer to the same object. For the string type, == compares the values of the strings. User-defined value types can overload the == operator (see operator). So can user-defined reference types, although by default == behaves as described above for both predefined and user-defined reference types. So why does this code snippet fail to compile? void Compare<T>(T x, T y) { return x == y; } I get the error Operator '==' cannot be applied to operands of type 'T' and 'T'. I wonder why, since as far as I understand the == operator is predefined for all types? Edit: Thanks everybody. I didn't notice at first that the statement was about reference types only. I also thought that bit-by-bit comparison is provided for all value types, which I now know is not correct. But, in case I'm using a reference type, would the the == operator use the predefined reference comparison, or would it use the overloaded version of the operator if a type defined one? Edit 2: Through trial and error, we learned that the == operator will use the predefined reference comparison when using an unrestricted generic type. Actually, the compiler will use the best method it can find for the restricted type argument, but will look no further. For example, the code below will always print true, even when Test.test<B>(new B(), new B()) is called: class A { public static bool operator==(A x, A y) { return true; } } class B : A { public static bool operator==(B x, B y) { return false; } } class Test { void test<T>(T a, T b) where T : A { Console.WriteLine(a == b); } }

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  • postfix + opendkim not signing correctly. how to debug this?

    - by Dean Hiller
    EDIT: I did get a little further but all posts on my search say permissions are wrong or regenerate key but I fixed that to be 644 as well as owned by DKIM AND I keep regenerating the key but it is not helping. My latest error now is this Apr 21 21:19:12 Sniffy opendkim[8729]: BB5BF3AA66: dkim_eom(): resource unavailable: d2i_PrivateKey_bio() failed Apr 21 21:19:12 Sniffy postfix/cleanup[8627]: BB5BF3AA66: milter-reject: END-OF-MESSAGE from localhost[127.0.0.1]: 4.7.0 resource unavailable; from=<[email protected]> to=<[email protected]> proto=SMTP helo=<abcs.com> I am looking for a way to simply debug this(don't necessarily need the answer but a way to get logs from opendkim would be good). If I stop opendkim, I see postfix log connection refused which is good. but when I send mail with opendkim started, I see no logs whatsoever. I even add the "LogWhy Yes" line to my opendkim.conf file as well and still see no logs there. Since I see opendkim running under user opendkim, I changed the owner of /etc/opendkim/* and /etc/opendkim and /etc/opendkim.conf all to opendkim user. I am running on ubuntu. My opendkim.conf file is # Log to syslog Syslog yes # Required to use local socket with MTAs that access the socket as a non- # privileged user (e.g. Postfix) UMask 002 # Sign for example.com with key in /etc/mail/dkim.key using # selector '2007' (e.g. 2007._domainkey.example.com) #Domain example.com Domain sniffyapp.com #KeyFile /etc/mail/dkim.key KeyFile /etc/opendkim/keys/sniffyapp.com/default.private #Selector 2007 Selector default # Commonly-used options; the commented-out versions show the defaults. #Canonicalization simple Mode sv #SubDomains no #ADSPDiscard no Socket inet:8891:localhost ExternalIgnoreList refile:/etc/opendkim/TrustedHosts InternalHosts refile:/etc/opendkim/TrustedHosts LogWhy Yes I of course have these lines added to main.cf in postgres smtpd_milters = inet:127.0.0.1:8891 non_smtpd_milters = $smtpd_milters milter_default_action = accept

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  • Tell postfix to merge three Authentication-Results:-Lines into one?

    - by Peter
    I am running a postfix mta with debian wheezy. I am using postfix-policyd-spf-python, openkdim and opendmarc. When receiving e-mails from google (google apps with own domain) for example, the header looks like this: [...] Authentication-Results: mail.xx.de; dkim=pass reason="1024-bit key; insecure key" header.d=yyy.com [email protected] header.b=OswLe0N+; dkim-adsp=pass; dkim-atps=neutral<br> [...] Authentication-Results: mail.xx.de; spf=pass (sender SPF authorized) smtp.mailfrom=yyy.com (client-ip=2a00:1450:400c:c00::242; helo=mail-wg0-x242.google.com; [email protected]; [email protected]) [...] Authentication-Results: mail.xx.de; dmarc=pass header.from=yyy.com<br> [...] This means any of these programs creates it's own Authentication-Results:-Line. Is it possible to tell postfix to merge this into one single Authentication-Results:-Line? When I send an e-mail to google, it says: [...] Authentication-Results: mx.google.com; spf=pass (google.com: domain of [email protected] designates xxx.xxx.xxx.xxx as permitted sender) [email protected]; dkim=pass [email protected]; dmarc=pass (p=NONE dis=NONE) header.from=xxx.com [...] And this is exactly what I want. Just one Authentication-Results-Header. How can I do this? Thanks. Regards, Peter

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  • How can I configure myhostname to work with Postfix?

    - by John Kelly Ferguson
    I'm going through the process of setting up a Discourse forum on my server (Ubuntu 12.04 x64) and am getting stuck at the point where I have to configure mailers. I'm following Discourse's instructions and am stuck trying to configure postfix for Mandrill. It is says to check my fully-qualified domain name by typing hostname -f When I enter in hostname -f, I get localhost. As far as I know, entering in hostname -f should return mydomainname.com. When I just enter in hostname, I get mydomainname which is correct because that is what I set my hostname to in /etc/hostname. Looking at some of my other settings, my /etc/hosts file reads: 127.0.0.1 localhost mydomainname # The following lines are desirable for IPv6 capable hosts ::1 ip6-localhost ip6-loopback fe00::0 ip6-localnet ff00::0 ip6-mcastprefix ff02::1 ip6-allnodes ff02::2 ip6-allrouters And in my /etc/postfix/main.cf file, I have myhostname set like this: myhostname = mydomainname.mydomainname.com (Should this be myhostname = mail.mydomainname.com instead?) And mydestination is the following: mydestination = mydomainname.com, localhost, localhost.localdomain, localhost I'm not that familiar with configuring hostnames. I've been reading Postfix's instructions, but haven't been able to figure it out yet. Any help on how to get this to work would be greatly appreciated. Thanks.

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  • How do I set up postfix to store e-mail in a file instead of relaying it?

    - by GomoX
    I want to run a staging copy of a production server on a local environment. The system runs a PHP application, which sends e-mail to customers in various scenarios and I want to make sure no e-mail is ever sent from the staging environment. I can tweak the code so it uses a dummy e-mail sender, but i'd like to run the exact same code as the production environment. I can use a different MTA (Postfix is just what we use in production), but I'd like something that is easy to set up under Debian/Ubuntu :) So, I'd like to set up the local Postfix install to store all e-mail in (one or more) files instead of relaying it. Actually, I don't really care how it's stored as long as it's feasible to check the e-mail that was sent. Even a set up option that tells postfix to keep the e-mail in the mail queue would work (I can purge the queue when I reload the staging server with a copy from production). I know this is possible, I just haven't found any good solution online for what seems like a fairly common need. Thanks!

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  • What should be the path for storing Maildir e-mails?

    - by Thufir
    Am I storing e-mails to the correct path? Working from the dovecot-postfix package I'm able to deliver e-mails to myself as so: thufir@dur:~$ thufir@dur:~$ telnet localhost 25 Trying 127.0.0.1... Connected to localhost. Escape character is '^]'. 220 dur.bounceme.net ESMTP Postfix (Ubuntu) HELO me 250 dur.bounceme.net mail from:<[email protected]> 250 2.1.0 Ok rcpt to:<thufir@localhost> 250 2.1.5 Ok data 354 End data with <CR><LF>.<CR><LF> subject: to evolution mail we'll see if this goes through. . 250 2.0.0 Ok: queued as 43D6F2A07C1 quit 221 2.0.0 Bye Connection closed by foreign host. thufir@dur:~$ and then here's the message: thufir@dur:~$ ll Maildir/new/ total 20 drwx------ 2 thufir thufir 4096 Nov 16 18:56 ./ drwx------ 5 thufir thufir 4096 Nov 16 18:56 ../ -rw------- 1 thufir thufir 410 Nov 16 11:57 1353095866.M305477P3932.dur,S=410,W=422 -rw------- 1 thufir thufir 424 Nov 16 17:20 1353115248.M841336P2990.dur,S=424,W=436 -rw------- 1 thufir thufir 445 Nov 16 18:56 1353121003.M187706P3838.dur,S=445,W=457 thufir@dur:~$ thufir@dur:~$ nl Maildir/new/1353121003.M187706P3838.dur\,S\=445\,W\=457 1 Return-Path: <[email protected]> 2 X-Original-To: thufir@localhost 3 Delivered-To: thufir@localhost 4 Received: from me (localhost [127.0.0.1]) 5 by dur.bounceme.net (Postfix) with SMTP id 43D6F2A07C1 6 for <thufir@localhost>; Fri, 16 Nov 2012 18:55:55 -0800 (PST) 7 subject: to evolution mail 8 Message-Id: <[email protected]> 9 Date: Fri, 16 Nov 2012 18:55:55 -0800 (PST) 10 From: [email protected] 11 we'll see if this goes through. thufir@dur:~$ Do I perhaps have postfix misconfigured? I ask because evolution seems to use a different path for mail.

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  • overloaded stream insertion operator with a vector

    - by Julz
    hi, i'm trying to write an overloaded stream insertion operator for a class who's only member is a vector. i dont really know what i'm doing. (lets make that clear) it's a vector of "Points" which is a struct containing two doubles. i figure what i want is to insert user input (a bunch of doubles) into a stream that i then send to a modifier method? i keep working off other stream insertion examples such as... std::ostream& operator<< (std::ostream& o, Fred const& fred) { return o << fred.i_; } but when i try a similar..... istream & operator >> (istream &inStream, Polygon &vertStr) { inStream >> ws; inStream >> vertStr.vertices; return inStream; } i get an error "no match for operator etc etc. if i leave off the .vertices it compiles but i figure it's not right? (vertices is the name of my vector ) and even if it is right, i dont actually know what syntax to use in my driver to use it? also not %100 on what my modifier method needs to look like. here's my Polygon class //header #ifndef POLYGON_H #define POLYGON_H #include "Segment.h" #include <vector> class Polygon { friend std::istream & operator >> (std::istream &inStream, Polygon &vertStr); public: //Constructor Polygon(const Point &theVerts); //Default Constructor Polygon(); //Copy Constructor Polygon(const Polygon &polyCopy); //Accessor/Modifier methods inline std::vector<Point> getVector() const {return vertices;} //Return number of Vector elements inline int sizeOfVect() const {return (int) vertices.capacity();} //add Point elements to vector inline void setVertices(const Point &theVerts){vertices.push_back (theVerts);} private: std::vector<Point> vertices; }; #endif //Body using namespace std; #include "Polygon.h" // Constructor Polygon::Polygon(const Point &theVerts) { vertices.push_back (theVerts); } //Copy Constructor Polygon::Polygon(const Polygon &polyCopy) { vertices = polyCopy.vertices; } //Default Constructor Polygon::Polygon(){} istream & operator >> (istream &inStream, Polygon &vertStr) { inStream >> ws; inStream >> vertStr; return inStream; } any help greatly appreciated, sorry to be so vague, a lecturer has just kind of given us a brief example of stream insertion then left us on our own thanks. oh i realise there are probably many other problems that need fixing

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  • overloaded stream insetion operator with a vector

    - by julz666
    hi, i'm trying to write an overloaded stream insertion operator for a class who's only member is a vector. i dont really know what i'm doing. (lets make that clear) it's a vector of "Points" which is a struct containing two doubles. i figure what i want is to insert user input (a bunch of doubles) into a stream that i then send to a modifier method? i keep working off other stream insertion examples such as... std::ostream& operator<< (std::ostream& o, Fred const& fred) { return o << fred.i_; } but when i try a similar..... istream & operator >> (istream &inStream, Polygon &vertStr) { inStream >> ws; inStream >> vertStr.vertices; return inStream; } i get an error "no match for operator etc etc. if i leave off the .vertices it compiles but i figure it's not right? (vertices is the name of my vector ) and even if it is right, i dont actually know what syntax to use in my driver to use it? also not %100 on what my modifier method needs to look like. here's my Polygon class //header #ifndef POLYGON_H #define POLYGON_H #include "Segment.h" #include <vector> class Polygon { friend std::istream & operator >> (std::istream &inStream, Polygon &vertStr); public: //Constructor Polygon(const Point &theVerts); //Default Constructor Polygon(); //Copy Constructor Polygon(const Polygon &polyCopy); //Accessor/Modifier methods inline std::vector<Point> getVector() const {return vertices;} //Return number of Vector elements inline int sizeOfVect() const {return (int) vertices.capacity();} //add Point elements to vector inline void setVertices(const Point &theVerts){vertices.push_back (theVerts);} private: std::vector<Point> vertices; }; #endif //Body using namespace std; #include "Polygon.h" // Constructor Polygon::Polygon(const Point &theVerts) { vertices.push_back (theVerts); } //Copy Constructor Polygon::Polygon(const Polygon &polyCopy) { vertices = polyCopy.vertices; } //Default Constructor Polygon::Polygon(){} istream & operator >> (istream &inStream, Polygon &vertStr) { inStream >> ws; inStream >> vertStr; return inStream; } any help greatly appreciated, sorry to be so vague, a lecturer has just kind of given us a brief example of stream insertion then left us on our own thanks. oh i realise there are probably many other problems that need fixing

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  • Operator== in derived class never gets called.

    - by Robin Welch
    Can someone please put me out of my misery with this? I'm trying to figure out why a derived operator== never gets called in a loop. To simplify the example, here's my Base and Derived class: class Base { // ... snipped bool operator==( const Base& other ) const { return name_ == other.name_; } }; class Derived : public Base { // ... snipped bool operator==( const Derived& other ) const { return ( static_cast<const Base&>( *this ) == static_cast<const Base&>( other ) ? age_ == other.age_ : false ); }; Now when I instantiate and compare like this ... Derived p1("Sarah", 42); Derived p2("Sarah", 42); bool z = ( p1 == p2 ); ... all is fine. Here the operator== from Derived gets called, but when I loop over a list, comparing items in a list of pointers to Base objects ... list<Base*> coll; coll.push_back( new Base("fred") ); coll.push_back( new Derived("sarah", 42) ); // ... snipped // Get two items from the list. Base& obj1 = **itr; Base& obj2 = **itr2; cout << obj1.asString() << " " << ( ( obj1 == obj2 ) ? "==" : "!=" ) << " " << obj2.asString() << endl; Here asString() (which is virtual and not shown here for brevity) works fine, but obj1 == obj2 always calls the Base operator== even if the two objects are Derived. I know I'm going to kick myself when I find out what's wrong, but if someone could let me down gently it would be much appreciated.

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  • C++ Beginner - 'friend' functions and << operator overloading: What is the proper way to overload an

    - by Francisco P.
    Hello, everyone! In a project I'm working on, I have a Score class, defined below in score.h. I am trying to overload it so, when a << operation is performed on it, _points + " " + _name is returned. Here's what I tried to do: ostream & Score::operator<< (ostream & os, Score right) { os << right.getPoints() << " " << right.scoreGetName(); return os; } Here are the errors returned: 1>c:\users\francisco\documents\feup\1a2s\prog\projecto3\projecto3\score.h(30) : error C2804: binary 'operator <<' has too many parameters (This error appears 4 times, actually) I managed to get it working by declaring the overload as a friend function: friend ostream & operator<< (ostream & os, Score right); And removing the Score:: from the function declaration in score.cpp (effectively not declaring it as a member). Why does this work, yet the code describe above doesn't? Thanks for your time! Below is the full score.h /////////////////////////////////////////////////////////// // Score.h // Implementation of the Class Score // Created on: 10-Mai-2010 11:43:56 // Original author: Francisco /////////////////////////////////////////////////////////// #ifndef SCORE_H_ #define SCORE_H_ #include <string> #include <iostream> #include <iostream> using std::string; using std::ostream; class Score { public: Score(string name); Score(); virtual ~Score(); void addPoints(int n); string scoreGetName() const; int getPoints() const; void scoreSetName(string name); bool operator>(const Score right) const; ostream & operator<< (ostream & os, Score right); private: string _name; int _points; }; #endif

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  • Lua Operator Overloading

    - by Pessimist
    I've found some places on the web saying that operators in Lua are overloadable but I can't seem to find any example. Can someone provide an example of, say, overloading the + operator to work like the .. operator works for string concatenation? EDIT 1: to Alexander Gladysh and RBerteig: If operator overloading only works when both operands are the same type and changing this behavior wouldn't be easy, then how come the following code works? (I don't mean any offense, I just started learning this language): printf = function(fmt, ...) io.write(string.format(fmt, ...)) end Set = {} Set.mt = {} -- metatable for sets function Set.new (t) local set = {} setmetatable(set, Set.mt) for _, l in ipairs(t) do set[l] = true end return set end function Set.union (a,b) -- THIS IS THE PART THAT MANAGES OPERATOR OVERLOADING WITH OPERANDS OF DIFFERENT TYPES -- if user built new set using: new_set = some_set + some_number if type(a) == "table" and type(b) == "number" then print("building set...") local mixedset = Set.new{} for k in pairs(a) do mixedset[k] = true end mixedset[b] = true return mixedset -- elseif user built new set using: new_set = some_number + some_set elseif type(b) == "table" and type(a) == "number" then print("building set...") local mixedset = Set.new{} for k in pairs(b) do mixedset[k] = true end mixedset[a] = true return mixedset end if getmetatable(a) ~= Set.mt or getmetatable(b) ~= Set.mt then error("attempt to 'add' a set with a non-set value that is also not a number", 2) end local res = Set.new{} for k in pairs(a) do res[k] = true end for k in pairs(b) do res[k] = true end return res end function Set.tostring (set) local s = "{" local sep = "" for e in pairs(set) do s = s .. sep .. e sep = ", " end return s .. "}" end function Set.print (s) print(Set.tostring(s)) end s1 = Set.new{10, 20, 30, 50} s2 = Set.new{30, 1} Set.mt.__add = Set.union -- now try to make a new set by unioning a set plus a number: s3 = s1 + 8 Set.print(s3) --> {1, 10, 20, 30, 50}

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  • How to change the meaning of pointer access operator

    - by kumar_m_kiran
    Hi All, This may be very obvious question, pardon me if so. I have below code snippet out of my project, #include <stdio.h> class X { public: int i; X() : i(0) {}; }; int main(int argc,char *arv[]) { X *ptr = new X[10]; unsigned index = 5; cout<<ptr[index].i<<endl; return 0; } Question Can I change the meaning of the ptr[index] ? Because I need to return the value of ptr[a[index]] where a is an array for subindexing. I do not want to modify existing source code. Any new function added which can change the behavior is needed. Since the access to index operator is in too many places (536 to be precise) in my code, and has complex formulas inside the index subscript operator, I am not inclined to change the code in many locations. PS : 1. I tried operator overload and came to conclusion that it is not possible. 2. Also p[i] will be transformed into *(p+i). I cannot redefine the basic operator '+'. So just want to reconfirm my understanding and if there are any possible short-cuts to achieve. Else I need fix it by royal method of changing every line of code :) .

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  • /etc/postfix/transport missing

    - by Thufir
    I'm following the mailman guide but cannot locate /etc/postfix/: root@dur:~# ll /etc/postfix/ total 124 drwxr-xr-x 3 root root 4096 Aug 27 20:04 ./ drwxr-xr-x 170 root root 12288 Aug 27 19:58 ../ -rw-r--r-- 1 root root 373 Aug 14 01:44 dynamicmaps.cf -rw-r--r-- 1 root root 2252 Aug 27 20:04 main.cf -rw-r--r-- 1 root root 1280 Aug 16 23:59 main.cf.1.orig -rw-r--r-- 1 root root 3298 Aug 25 16:59 main.cf.2.mysql -rw-r--r-- 1 root root 1323 Aug 26 00:38 main.cf.3.dovecot -rw-r--r-- 1 root root 2092 Aug 27 20:01 main.cf.4 -rw-r--r-- 1 root root 5563 Aug 14 01:43 master.cf -rw-r--r-- 1 root root 150 Aug 17 00:21 mysql_alias.cf -rw-r--r-- 1 root root 150 Aug 17 00:22 mysql_domains.cf -rw-r--r-- 1 root root 150 Aug 17 00:21 mysql_mailbox.cf -rw-r--r-- 1 root root 19707 Apr 13 13:33 postfix-files -rwxr-xr-x 1 root root 8729 Oct 6 2011 postfix-script* -rwxr-xr-x 1 root root 26498 Apr 13 13:33 post-install* drwxr-xr-x 2 root root 4096 Apr 13 13:33 sasl/ root@dur:~#

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  • "Recipient address rejected" when sending an email to an external address with sendgrid

    - by WJB
    In postfix, I'm using relay_host to send an email to an external address using sendgrid, but I get an error about local ricipient table when sending an email from my PHP code. This is my main.cf in /postfix/ ## -- Sendgrid smtp_sasl_auth_enable = yes smtp_sasl_password_maps = static:username:password smtp_sasl_security_options = noanonymous smtp_tls_security_level = may header_size_limit = 4096000 relayhost = [smtp.sendgrid.net]:587 This is the error message from the log: postfix/smtpd[53598]: [ID 197553 mail.info] NOQUEUE: reject: RCPT from localhost[127.0.0.1]: 550 5.1.1 Recipient address rejected: User unknown in local recipient table; from=<[email protected]> to=<[email protected]> proto=ESMTP helo=<localhost.localdomain> One interesting thing is when I use "sendmail [email protected]" from the command line, the email is delivered successfully using SendGrid. I think it's because this uses postfix/smtp instead of postfix/smtpD the log for this says, postfix/smtp[18670]: [ID 197553 mail.info] AAF7313A7E: to=, relay=smtp.sendgrid.net[50.97.69.148]:587, delay=4.1, delays=3.5/0.02/0.44/0.18, dsn=2.0.0, status=sent (250 Delivery in progress) Thank you

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  • Postfix - how to redirect email if they will rejecting?

    - by Bartosz Kowalczyk
    I have problem with spam and postfix + postgray. It generally good works but I have false-positive still and reject good email. And now I have problems. Can I configure postfix (and postgray) that: if_reject than redirect to [email protected] (change recipients). Or I don't know maybe: Each email have to copy and send to [email protected] Then filtering? If hit restriction than just reject (another copy is in [email protected]) How to do it? Sorry for my english. Can you help me? Thank you

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  • How to stop basic Postfix after-queue script from BCC-ing sender?

    - by mjbraun
    I'm building a content filter for Postfix (2.9.3 package installed via apt on an Ubuntu 12.04 test VM) and I'm starting with a very basic Ruby (1.9.3) template and building up functionality. Strangely, when the script is enabled, messages sent are being forwarded on as normal, but also sent back to the sender which is not normal. Disabling the script disables this behavior. Any suggestions about what I have to change to stop that from happening? Thanks for any advice! /etc/postfix/master.cf (only the lines changed from the default) smtp inet n - - - - smtpd -o content_filter=dumper:dummy ... dumper unix - n n - 10 pipe flags=RF user=mailuser argv=/home/mailuser/mailfilter/dumper.rb ${sender} ${recipient}` /home/mailuser/mailfilter/dumper.rb #!/usr/bin/env ruby require 'open3' dir="/home/mailuser/emails" logfile="maillog.log" message = $stdin.read cmd = "/usr/sbin/sendmail -G -i #{ARGV[0]} #{ARGV[1]}" stdin, stdouterr, wait_thr = Open3.popen2e(cmd) stdin.print(message) logfile = File.open("#{dir}/#{logfile}", 'a') logfile.write(stdouterr) stdin.close stdouterr.close exit(0)

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  • postfix, webmin installed. whats next?

    - by Johnny Craig
    Im trying to get imap running and dont know the problem. i a developer, not a network guy.( our network guy left) we had postfix installed already for outgoing mail on 8 domains. we only had incoming on 1 domain. but that mail server is located on a different ip. now we want incoming on another domain, but we dont want it on another ip, we want it on the same ip as the website itself. I installed dovecot today because my hosting company said i needed it. it seems to run fine. do i need dovecot AND postfix? or are they the same thing? dovecot does not show up anywhere in webmin what i cant seem to figure out how to do is add a user email so i can try to telnet in on port 143. i think i have evrything installed, just need the next step.... sorry for the newb question

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  • Is it possible to change the postfix message-id?

    - by Marcus
    Is it possible to change the message-id in postfix? If I send Mails over an Java-Application I get the following message-id: message-id=<143303043.111334605578921.JavaMail.applicationanme@hostname> So I want that the message-id looks like this: message-id=<[email protected]> What I can understand, if I send mails with the Linux program mail it works: message-id=<[email protected]> I have already set my hostname in the postfix-conf, but when I send a mail with the java-application it doen't work. We use a relay host to send email and any messages which are sent without @domain.tld in the mail-id will detected as a spam mail. Do you have any idea how I can fix this?

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  • Why does Postfix deliver mails locally instead of relaying them to Google Apps?

    - by user40388
    I get the following error trying to send an email to my Google Apps Email at [email protected] from my Postfix server. to=, relay=local, delay=0.09, delays=0.07/0/0/0.02, dsn=5.1.1, status=bounced (unknown user: "admin") Is there a way I can force it to not use the LOCAL relay and treat [email protected] as outside email and not look for a user in the current postfix configuration. I am trying to email the full email address "[email protected]" not only "admin". I have the Google Apps MX record on mydomain.com + SPF record which before was: v=spf1 include:_spf.google.com ~all (emailing to [email protected] used to work with that record) But I had to change it to v=spf1 a mx ip4:MY.IP.HERE include:_spf.google.com ~all

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