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  • Disturbing or politically incorrect classes

    - by Jonas B
    Please don't take this seriously! - Community wikied Satire is always fun. Try to come up with the most shocking, disturbing or politically incorrect class you can think of. (But please no racism or anything seriously offensive or anything that can't be interpeted as satire). I'll go first with my example: public class Person { public bool Female; public Person(bool female) { Female = female; } public static bool operator <(Person j1, Person j2) { if (j1.Female && !j2.Female) return true; else return false; } public static bool operator >(Person j1, Person j2) { if (!j1.Female && j2.Female) return true; else return false; } public static bool operator <=(Person j1, Person j2) { if ((j1.Female == j2.Female) || (j1.Female && !j2.Female)) return true; else return false; } public static bool operator >=(Person j1, Person j2) { if ((j1.Female == j2.Female) || (!j1.Female && j2.Female)) return true; else return false; } }

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  • Find items with belongs_to associations in Rails?

    - by dannymcc
    Hi Everyone, I have a model called Kase each "Case" is assigned to a contact person via the following code: class Kase < ActiveRecord::Base validates_presence_of :jobno has_many :notes, :order => "created_at DESC" belongs_to :company # foreign key: company_id belongs_to :person # foreign key in join table belongs_to :surveyor, :class_name => "Company", :foreign_key => "appointedsurveyor_id" belongs_to :surveyorperson, :class_name => "Person", :foreign_key => "surveyorperson_id" I was wondering if it is possible to list on the contacts page all of the kases that that person is associated with. I assume I need to use the find command within the Person model? Maybe something like the following? def index @kases = Person.Kase.find(:person_id) or am I completely misunderstanding everything again? Thanks, Danny EDIT: If I use: @kases= @person.kases I can successfully do the following: <% if @person.kases.empty? %> No Cases Found <% end %> <% if @person.kases %> This person has a case assigned to them <% end %> but how do I output the "jobref" field from the kase table for each record found?

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  • Eager loading OneToMany in Hibernate with JPA2

    - by pihentagy
    I have a simple @OneToMany between Person and Pet entities: @OneToMany(mappedBy="owner", cascade=CascadeType.ALL, fetch=FetchType.EAGER) public Set<Pet> getPets() { return pets; } I would like to load all Persons with associated Pets. So I came up with this (inside a test class): @RunWith(SpringJUnit4ClassRunner.class) @ContextConfiguration public class AppTest { @Test @Rollback(false) @Transactional(readOnly = false) public void testApp() { CriteriaBuilder qb = em.getCriteriaBuilder(); CriteriaQuery<Person> c = qb.createQuery(Person.class); Root<Person> p1 = c.from(Person.class); SetJoin<Person, Pet> join = p1.join(Person_.pets); TypedQuery<Person> q = em.createQuery(c); List<Person> persons = q.getResultList(); for (Person p : persons) { System.out.println(p.getName()); for (Pet pet : p.getPets()) { System.out.println("\t" + pet.getNick()); } } However, turning the SQL logging on shows, that it executes 3 queries (having 2 Persons in the DB). Hibernate: select person0_.id as id0_, person0_.name as name0_, person0_.sex as sex0_ from Person person0_ inner join Pet pets1_ on person0_.id=pets1_.owner_id Hibernate: select pets0_.owner_id as owner3_0_1_, pets0_.id as id1_, pets0_.id as id1_0_, pets0_.nick as nick1_0_, pets0_.owner_id as owner3_1_0_ from Pet pets0_ where pets0_.owner_id=? Hibernate: select pets0_.owner_id as owner3_0_1_, pets0_.id as id1_, pets0_.id as id1_0_, pets0_.nick as nick1_0_, pets0_.owner_id as owner3_1_0_ from Pet pets0_ where pets0_.owner_id=? Any tips? Thanks Gergo

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  • JavaFx 2.1, 2.2 TableView update issue

    - by Lewis Liu
    My application uses JPA read data into TableView then modify and display them. The table refreshed modified record under JavaFx 2.0.3. Under JavaFx 2.1, 2.2, the table wouldn't refresh the update anymore. I found other people have similar issue. My plan was to continue using 2.0.3 until someone fixes the issue under 2.1 and 2.2. Now I know it is not a bug and wouldn't be fixed. Well, I don't know how to deal with this. Following are codes are modified from sample demo to show the issue. If I add a new record or delete a old record from table, table refreshes fine. If I modify a record, the table wouldn't refreshes the change until a add, delete or sort action is taken. If I remove the modified record and add it again, table refreshes. But the modified record is put at button of table. Well, if I remove the modified record, add the same record then move the record to the original spot, the table wouldn't refresh anymore. Below is a completely code, please shine some light on this. import javafx.application.Application; import javafx.beans.property.SimpleStringProperty; import javafx.collections.FXCollections; import javafx.collections.ObservableList; import javafx.event.ActionEvent; import javafx.event.EventHandler; import javafx.geometry.HPos; import javafx.geometry.Insets; import javafx.geometry.Pos; import javafx.scene.Group; import javafx.scene.Scene; import javafx.scene.control.*; import javafx.scene.control.cell.PropertyValueFactory; import javafx.scene.layout.GridPane; import javafx.scene.layout.HBox; import javafx.scene.layout.VBox; import javafx.scene.text.Font; import javafx.stage.Modality; import javafx.stage.Stage; import javafx.stage.StageStyle; public class Main extends Application { private TextField firtNameField = new TextField(); private TextField lastNameField = new TextField(); private TextField emailField = new TextField(); private Stage editView; private Person fPerson; public static class Person { private final SimpleStringProperty firstName; private final SimpleStringProperty lastName; private final SimpleStringProperty email; private Person(String fName, String lName, String email) { this.firstName = new SimpleStringProperty(fName); this.lastName = new SimpleStringProperty(lName); this.email = new SimpleStringProperty(email); } public String getFirstName() { return firstName.get(); } public void setFirstName(String fName) { firstName.set(fName); } public String getLastName() { return lastName.get(); } public void setLastName(String fName) { lastName.set(fName); } public String getEmail() { return email.get(); } public void setEmail(String fName) { email.set(fName); } } private TableView<Person> table = new TableView<Person>(); private final ObservableList<Person> data = FXCollections.observableArrayList( new Person("Jacob", "Smith", "[email protected]"), new Person("Isabella", "Johnson", "[email protected]"), new Person("Ethan", "Williams", "[email protected]"), new Person("Emma", "Jones", "[email protected]"), new Person("Michael", "Brown", "[email protected]")); public static void main(String[] args) { launch(args); } @Override public void start(Stage stage) { Scene scene = new Scene(new Group()); stage.setTitle("Table View Sample"); stage.setWidth(535); stage.setHeight(535); editView = new Stage(); final Label label = new Label("Address Book"); label.setFont(new Font("Arial", 20)); TableColumn firstNameCol = new TableColumn("First Name"); firstNameCol.setCellValueFactory( new PropertyValueFactory<Person, String>("firstName")); firstNameCol.setMinWidth(150); TableColumn lastNameCol = new TableColumn("Last Name"); lastNameCol.setCellValueFactory( new PropertyValueFactory<Person, String>("lastName")); lastNameCol.setMinWidth(150); TableColumn emailCol = new TableColumn("Email"); emailCol.setMinWidth(200); emailCol.setCellValueFactory( new PropertyValueFactory<Person, String>("email")); table.setItems(data); table.getColumns().addAll(firstNameCol, lastNameCol, emailCol); //--- create a edit button and a editPane to edit person Button addButton = new Button("Add"); addButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { fPerson = null; firtNameField.setText(""); lastNameField.setText(""); emailField.setText(""); editView.show(); } }); Button editButton = new Button("Edit"); editButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { if (table.getSelectionModel().getSelectedItem() != null) { fPerson = table.getSelectionModel().getSelectedItem(); firtNameField.setText(fPerson.getFirstName()); lastNameField.setText(fPerson.getLastName()); emailField.setText(fPerson.getEmail()); editView.show(); } } }); Button deleteButton = new Button("Delete"); deleteButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { if (table.getSelectionModel().getSelectedItem() != null) { data.remove(table.getSelectionModel().getSelectedItem()); } } }); HBox addEditDeleteButtonBox = new HBox(); addEditDeleteButtonBox.getChildren().addAll(addButton, editButton, deleteButton); addEditDeleteButtonBox.setAlignment(Pos.CENTER_RIGHT); addEditDeleteButtonBox.setSpacing(3); GridPane editPane = new GridPane(); editPane.getStyleClass().add("editView"); editPane.setPadding(new Insets(3)); editPane.setHgap(5); editPane.setVgap(5); Label personLbl = new Label("Person:"); editPane.add(personLbl, 0, 1); GridPane.setHalignment(personLbl, HPos.LEFT); firtNameField.setPrefWidth(250); lastNameField.setPrefWidth(250); emailField.setPrefWidth(250); Label firstNameLabel = new Label("First Name:"); Label lastNameLabel = new Label("Last Name:"); Label emailLabel = new Label("Email:"); editPane.add(firstNameLabel, 0, 3); editPane.add(firtNameField, 1, 3); editPane.add(lastNameLabel, 0, 4); editPane.add(lastNameField, 1, 4); editPane.add(emailLabel, 0, 5); editPane.add(emailField, 1, 5); GridPane.setHalignment(firstNameLabel, HPos.RIGHT); GridPane.setHalignment(lastNameLabel, HPos.RIGHT); GridPane.setHalignment(emailLabel, HPos.RIGHT); Button saveButton = new Button("Save"); saveButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { if (fPerson == null) { fPerson = new Person( firtNameField.getText(), lastNameField.getText(), emailField.getText()); data.add(fPerson); } else { int k = -1; if (data.size() > 0) { for (int i = 0; i < data.size(); i++) { if (data.get(i) == fPerson) { k = i; } } } fPerson.setFirstName(firtNameField.getText()); fPerson.setLastName(lastNameField.getText()); fPerson.setEmail(emailField.getText()); data.set(k, fPerson); table.setItems(data); // The following will work, but edited person has to be added to the button // // data.remove(fPerson); // data.add(fPerson); // add and remove refresh the table, but now move edited person to original spot, // it failed again with the following code // while (data.indexOf(fPerson) != k) { // int i = data.indexOf(fPerson); // Collections.swap(data, i, i - 1); // } } editView.close(); } }); Button cancelButton = new Button("Cancel"); cancelButton.setOnAction(new EventHandler<ActionEvent>() { @Override public void handle(ActionEvent event) { editView.close(); } }); HBox saveCancelButtonBox = new HBox(); saveCancelButtonBox.getChildren().addAll(saveButton, cancelButton); saveCancelButtonBox.setAlignment(Pos.CENTER_RIGHT); saveCancelButtonBox.setSpacing(3); VBox editBox = new VBox(); editBox.getChildren().addAll(editPane, saveCancelButtonBox); Scene editScene = new Scene(editBox); editView.setTitle("Person"); editView.initStyle(StageStyle.UTILITY); editView.initModality(Modality.APPLICATION_MODAL); editView.setScene(editScene); editView.close(); final VBox vbox = new VBox(); vbox.setSpacing(5); vbox.getChildren().addAll(label, table, addEditDeleteButtonBox); vbox.setPadding(new Insets(10, 0, 0, 10)); ((Group) scene.getRoot()).getChildren().addAll(vbox); stage.setScene(scene); stage.show(); } }

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  • Domain model for an optional many-many relationship

    - by Greg
    Let's say I'm modeling phone numbers. I have one entity for PhoneNumber, and one for Person. There's a link table that expresses the link (if any) between the PhoneNumber and Person. The link table also has a field for DisplayOrder. When accessing my domain model, I have several Use Cases for viewing a Person. I can look at them without any PhoneNumber information. I can look at them for a specific PhoneNumber. I can look at them and all of their current (or past) PhoneNumbers. I'm trying to model Person, not only for the standard CRUD operations, but for the (un)assignment of PhoneNumbers to a Person. I'm having trouble expressing the relationship between the two, especially with respects to the DisplayOrder property. I can think of several solutions but I'm not sure of which (if any) would be best. A PhoneNumberPerson class that has a Person and PhoneNumber property (most closely resembles database design) A PhoneCarryingPerson class that inherits from Person and has a PhoneNumber property. A PhoneNumber and/or PhoneNumbers property on Person (and vis-a-versa, a Person property on PhoneNumber) What would be a good way to model this that makes sense from a domain model perspective? How do I avoid misplaced properties (DisplayOrder on Person) or conditionally populated properties?

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  • What is difference between Where and Join in linq ?

    - by Freshblood
    hello What is difference between of these 2 queries ? they are completely equal ? from order in myDB.OrdersSet from person in myDB.PersonSet from product in myDB.ProductSet where order.Persons_Id==person.Id && order.Products_Id==product.Id select new { order.Id, person.Name, person.SurName, product.Model,UrunAdi=product.Name }; and from order in myDB.OrdersSet join person in myDB.PersonSet on order.Persons_Id equals person.Id join product in myDB.ProductSet on order.Products_Id equals product.Id select new { order.Id, person.Name, person.SurName, product.Model,UrunAdi=product.Name };

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  • Doubt in abstract classes

    - by mohit
    public abstract class Person { private String name; public Person(String name) { this.name = name; System.out.println("Person"); } public String getName() { return name; } abstract public String getDescription(); } public class Student extends Person { private String major; public Student(String name, String major) { super(name); this.major = major; } public String getMajor() { return major; } @Override public String getDescription() { return "student" + super.getName() + " having" + major; } } public class PersonTest { public static void main(String[] args) { Person person = new Student("XYZ", "ABC"); System.out.println(person.getDescription()); } } Ques: We cannot create objects of abstract classes, then why Person Constructor has been invoked, even its an abstract class?

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  • Constructors taking references in C++

    - by sasquatch
    I'm trying to create constructor taking reference to an object. After creating object using reference I need to prints field values of both objects. Then I must delete first object, and once again show values of fields of both objects. My class Person looks like this : class Person { char* name; int age; public: Person(){ int size=0; cout << "Give length of char*" << endl; cin >> size; name = new char[size]; age = 0; } ~Person(){ cout << "Destroying resources" << endl; delete[] name; delete age; } void init(char* n, int a) { name = n; age = a; } }; Here's my implementation (with the use of function show() ). My professor said that if this task is written correctly it will return an error. #include <iostream> using namespace std; class Person { char* name; int age; public: Person(){ int size=0; cout << "Give length of char*" << endl; cin >> size; name = new char[size]; age = 0; } Person(const Person& p){ name = p.name; age = p.age; } ~Person(){ cout << "Destroying resources" << endl; delete[] name; delete age; } void init(char* n, int a) { name = n; age = a; } void show(char* n, int a){ cout << "Name: " << name << "," << "age: " << age << "," << endl; } }; int main(void) { Person *p = new Person; p->init("Mary", 25); p->show(); Person &p = pRef; pRef->name = "Tom"; pRef->age = 18; Person *p2 = new Person(pRef); p->show(); p2->show(); system("PAUSE"); return 0; }

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  • PostgreSQL - select only when specific multiple apperance in column

    - by Horse SMith
    I'm using PostgreSQL. I have a table with 3 fields person, recipe and ingredient person = creator of the recipe recipe = the recipe ingredient = one of the ingredients in the recipe I want to create a query which results in every person who whenever has added carrot to a recipe, the person must also have added salt to the same recipe. More than one person can have created the recipe, in which case the person who added the ingredient will be credited for adding the ingredient. Sometimes the ingredient is used more than once, even by the same person. If this the table: person1, rec1, carrot person1, rec1, salt person1, rec1, salt person1, rec2, salt person1, rec2, pepper person2, rec1, carrot person2, rec1, salt person2, rec2, carrot person2, rec2, pepper person3, rec1, sugar person3, rec1, carrot Then I want this result: person1 Because this person is the only one who whenever has added carrot also have added salt.

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  • LINQ - Using where or join - Performance difference ?

    - by Patrick Säuerl
    Hi Based on this question: http://stackoverflow.com/questions/3013034/what-is-difference-between-where-and-join-in-linq My question is following: Is there a performance difference in the following two statements: from order in myDB.OrdersSet from person in myDB.PersonSet from product in myDB.ProductSet where order.Persons_Id==person.Id && order.Products_Id==product.Id select new { order.Id, person.Name, person.SurName, product.Model,UrunAdi=product.Name }; and from order in myDB.OrdersSet join person in myDB.PersonSet on order.Persons_Id equals person.Id join product in myDB.ProductSet on order.Products_Id equals product.Id select new { order.Id, person.Name, person.SurName, product.Model,UrunAdi=product.Name }; I would always use the second one just because it´s more clear. My question is now, is the first one slower than the second one? Does it build a cartesic product and filters it afterwards with the where clauses ? Thank you.

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  • Using a backwards relation (i.e FOO_set) for ModelChoiceField in Django

    - by Bwmat
    I have a model called Movie, which has a ManyToManyField called director to a model called Person, and I'm trying to create a form with ModelChoiceField like so: class MovieSearchForm(forms.Form): producer = forms.ModelChoiceField(label='Produced by', queryset=movies.models.Person.producer_set, required=False) but this seems to be failing to compile (I'm getting a ViewDoesNotExist exception for the view that uses the form, but it goes away if I just replace the queryset with all the person objects), I'm guessing because '.producer_set' is being evaluated too 'early'. How can I get this work? here are the relevant parts of the movie/person classes: class Person(models.Model): name = models.CharField(max_length=100) class Movie(models.Model): ... producer = models.ForeignKey(Person, related_name="producers") director = models.ForeignKey(Person, related_name="directors") What I'm trying to do is get ever Person who is used in the producer field of some Movie.

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  • How to capture child links clicked using jquery?

    - by user244394
    I am trying to capture the event when a child element link is clicked and add class called "highlightchild" to it. Also I want to check if there are any child element link exist or not, if no child element exits ie "third level" highlight with "highlightparent" the parent. How can I do that using jquery? $(document).ready(function() { $('.menu ul').hide(); $('.menu .arrowUp').click(function() { $('.menu ul').hide(); $(this).find(".third-level").toggle(); }); }); html <ul class="menu"> <li class="arrowUp"><a href="#">link1</a> <ul class="third-level" > <!-- third level non-active --> <li class="arrowUp"><a href="/somelink/">Some Link</a></li> </ul> </li> <li class="arrowUp"><a href="#">link2</a> <ul class="third-level" > <!-- third level non-active --> <li class="arrowUp"><a href="/links2/">some Links 2</a></li> </ul> </li> <li class="arrowUp"><a href="#">link3</a> <ul class="third-level" > <!-- third level non-active --> <li class="arrowUp"><a href="/Agri/">Agricultural</a></li> <!-- third level non-active --> <li class="arrowUp"><a href="/sugar/">Sugar</a></li> <!-- third level non-active --> <li class="arrowUp"><a href="/bbc/">Coffee</a></li> <!-- third level non-active --> <li class="arrowUp"><a href="/cnn/">Energy</a></li> <!-- third level non-active --> <li class="arrowUp"><a href="funstuff">Fun stuff</a></li> </ul> </li> <li class="arrowUp"><a href="#">link4</a></li> <li class="arrowUp"><a href="#">link5</a></li> <li class="arrowUp"><a href="#">link6</a></li> </ul>

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  • Show a django relationship in a template

    - by kevin_82
    I have a django model as follows: class Person(models.Model): name = models.CharField(max_length=255) class Relationship(models.Model): parent = models.ForeignKey(Person) child = models.ForeignKey(Person) description = models.TextField(blank=True) In my view, I pass a certain person, and the relationships in which he/she is parent: person = Person.objects.filter(name ='some name') descendant_relationships = Relationship.objects.filter(parent = person) An I want to show this person's descendants in a list in a template: <ul> {% for item in descendant_relationships%} <li> {{item.child.name}} - {{item.description}} </li> {% endfor %} </ul> But this template code will not show the children of children (i.e. grandchildren, great-grandchildren etc.). How can I get these lower level descendants to show up? I imagine recursion is necessary somewhere, but where?

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  • Speed up this query joining to a table multiple times

    - by Mongus Pong
    Hi, I have this query that (stripped right down) goes something like this : SELECT [Person_PrimaryContact].[LegalName], [Person_Manager].[LegalName], [Person_Owner].[LegalName], [Person_ProspectOwner].[LegalName], [Person_ProspectBDM].[LegalName], [Person_ProspectFE].[LegalName], [Person_Signatory].[LegalName] FROM [Cache] LEFT JOIN [dbo].[Person] AS [Person_Owner] WITH (NOLOCK) ON [Person_Owner].[PersonID] = [Cache].[ClientOwnerID] LEFT JOIN [dbo].[Person] AS [Person_Manager] WITH (NOLOCK) ON [Person_Manager].[PersonID] = [Cache].[ClientManagerID] LEFT JOIN [dbo].[Person] AS [Person_Signatory] WITH (NOLOCK) ON [Person_Signatory].[PersonID] = [Cache].[ClientSignatoryID] LEFT JOIN [dbo].[Person] AS [Person_PrimaryContact] WITH (NOLOCK) ON [Person_PrimaryContact].[PersonID] = [Cache].[PrimaryContactID] LEFT JOIN [dbo].[Person] AS [Person_ProspectOwner] WITH (NOLOCK) ON [Person_ProspectOwner].[PersonID] = [Cache].[ProspectOwnerID] LEFT JOIN [dbo].[Person] AS [Person_ProspectBDM] WITH (NOLOCK) ON [Person_ProspectBDM].[PersonID] = [Cache].[ProspectBDMID] LEFT JOIN [dbo].[Person] AS [Person_ProspectFE] WITH (NOLOCK) ON [Person_ProspectFE].[PersonID] = [Cache].[ProspectFEID] Person is a huge table and each join to it has a pretty significant hit in the execution plan. Is there anyway I can adjust this query so that I am only linking to it once, or at least get SQL Server to scan through it only once?

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  • Strange response from WCF service, how to return json easily

    - by Exitos
    I want to get a service to respond with just JSON. I have written the following code: namespace BM.Security { [ServiceContract(Namespace = "")] [AspNetCompatibilityRequirements(RequirementsMode = AspNetCompatibilityRequirementsMode.Allowed)] public class AssocFileService { [OperationContract] [WebGet(ResponseFormat = WebMessageFormat.Json)] public List<Person> GetPeople(int message) { List<Person> myList = new List<Person>(); Person p = new Person() { Age = 28, Name="Name1" }; Person p2 = new Person() { Age = 26, Name = "Name2" }; myList.Add(p); myList.Add(p2); return myList; } } [DataContract] public class Person { [DataMember] public string Name { get; set; } [DataMember] public int Age { get; set; } } } But im getting the following JSON back which is really wierd... { "d" : [ { "Age" : 28, "Name" : "Name1", "__type" : "Person:#Bm.Security" }, { "Age" : 26, "Name" : "Name2", "__type" : "Person:#BM.Security" } ] } I'm totally stumped by the "d" no idea where that has come from. And also by the __type variable, no thanks don't really want that in my Json :-( How do I set the root node in my data to replace that d? Where did the d come from? So many questions... Hope someone can help....

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  • Trying to overload + operator

    - by FrostyStraw
    I cannot for the life of me understand why this is not working. I am so confused. I have a class Person which has a data member age, and I just want to add two people so that it adds the ages. I don't know why this is so hard, but I'm looking for examples and I feel like everyone does something different, and for some reason NONE of them work. Sometimes the examples I see have two parameters, sometimes they only have one, sometimes the parameters are references to the object, sometimes they're not, sometimes they return an int, sometimes they return a Person object. Like..what is the most normal way to do it? class Person { public: int age; //std::string haircolor = "brown"; //std::string ID = "23432598"; Person(): age(19) {} Person operator+(Person&) { } }; Person operator+(Person &obj1, Person &obj2){ Person sum = obj1; sum += obj2; return sum; } I really feel like overloading a + operator should seriously be the easiest thing in the world except I DON'T KNOW WHAT I AM DOING. I don't know if I'm supposed to create the overload function inside the class, outside, if it makes a difference, why if I do it inside it only allows one parameter, I just honestly don't get it.

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  • My boss decided to add a "person to blame" field to every bug report. How can I convince him that it's a bad idea?

    - by MK_Dev
    In one of the latest "WTF" moves, my boss decided that adding a "Person To Blame" field to our bug tracking template will increase accountability (although we already have a way of tying bugs to features/stories). My arguments that this will decrease morale, increase finger-pointing and would not account for missing/misunderstood features reported as bug have gone unheard. What are some other strong arguments against this practice that I can use? Is there any writing on this topic that I can share with the team and the boss? I find this sort of culture unacceptable to work in but want to try and change it before jumping ship. Any input is appreciated.

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  • Should i repeat person name in alt text of <img> if name is already in source under image?

    - by metal-gear-solid
    if I'm already having person name under/over image then should i use same name in ALT text? <p><img width="125" height="157" alt="George Washington" src="media/gw.jpg"><span>George Washington</span><p> <p><span>George Washington</span> <img width="125" height="157" alt="George Washington" src="media/gw.jpg"><p> Should i repeat <span> in alt in both condition ? image has no link.

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  • How to connect to a third party website in classic asp using javascript for password encryption and yet not giving in the password.

    - by Abbi
    Hi I have to make changes to classic asp website where once a button is clicked it autologins to a third party website with a intermediate page that warns that you are logging in to a third party website. The thirdparty is providing us with a username and password and gave us an examle javascript to encode the password to send to them. Now where do I store the userid and password. I cannot execute the javascript on the serverside. It has to go to the client. If the asp page which has the encryption javascript goes to the client side then the source can be viewed and the username and password is given out. Is there a way that I can have hidden asp page whose only job is to encrypt the password and create a new url and auto redirect it to that new url. So when the user clicks ok on the intermediate warning page I redirect it to this hidden asp page which does the encryption and a creates a url for get method and redirects to that page. I am a novice as far as java script and classic asp is concerned. Any ideas/ advice will be appreciated. Thanks, --Abbi

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  • How do you search for backdoors from the previous IT person?

    - by Jason Berg
    We all know it happens. A bitter old IT guy leaves a backdoor into the system and network in order to have fun with the new guys and show the company how bad things are without him. I've never personally experienced this. The most I've experienced is somebody who broke and stole stuff right before leaving. I'm sure this happens, though. So, when taking over a network that can't quite be trusted, what steps should be taken to ensure everything is safe and secure?

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  • What mobile phones are viable for a "nerdy" person? [closed]

    - by Blixt
    This community wiki is for determining a list of good mobile phone choices if you are "nerdy" (definition follows.) As a point of reference, the almost two years old N95 8GB will be used. Mostly because that's what I can most relate to since I've had it since it came out. Today, iPhone and other modern mobile phones really out-shine it in usability and interface. However, it still does everything I want it to do (and here's the definition of "nerdy"; modify as needed): Syncs contacts, calendar, tasks and mail in the background Can run multiple installable applications in the background (Google Maps with Latitude, for example) Good amount of space for music etc. Lets you develop your own little toy applications (Python; not to mention it can also run an Apache server with a public URL!) Tethering! Supports Flash (maybe not very important, but it has its uses) Has a manufacturer that believes in the nerdiness! (The people at Nokia Labs make lots of cool stuff and share early versions with the community and are generally open) A high resolution screen (at least 320x240) Special hardware features such as an accelerometer and GPS What's missing from the N95 8GB but still qualifies as good, "nerdy", qualities: 7.2 Mbit/s (or faster) internet through HSDPA or HSPA+. A good web browser that can do most of the stuff a desktop browser can (especially render sites properly and run JavaScript correctly) Touch (especially multi-touch) More special hardware features such as a compass Intuitive and fluent user interface (Shiny stuff) Ability to configure it to trust root certificates of my own choice A processor fast enough to run Quake 3! =)

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  • Gmail: Received an email intended for another person. [closed]

    - by jonescb
    I'm not really sure how email routing works, but someone ordered something on Amazon and I received the email instead of them. Or maybe we both got it, I don't know. The order doesn't show up in my account, so I'm certain I wasn't charged for it, but I shouldn't be getting other peoples' emails. We'll say that my email is [email protected], and somebody who's email is [email protected] places an order on Amazon. The confirmation email is sent to me at [email protected]. I checked the email header, and it did say To: [email protected] which is not my email address. At first I thought that Google ignores periods in email addresses, but I tested the account setup and it doesn't give any error when you put a period in the address. I didn't create the account; I just used the "check availability" function and the address I chose with a period was fine. Maybe someone with knowledge about how Email works could tell me why this happened. Is this a bug in the way Amazon sends emails? Or is it a bug in how Google receives them? Who should I report this issue to?

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  • I am not the most logically-organized person. Do I have any chance at being a good 'low-level' programmer?

    - by user217902
    Background: I am entering college next year. I really enjoy making stuff and solving logical problems, so I'm thinking of majoring in compsci and working in software development. I hope to have the kind of job where I can work with implementing / improving algorithms and data structures on a regular basis.. as opposed to, say, a job that's purely concerned with mashing different libraries together, or 'finding the right APIs for the job'. (Hence the word 'low-level' in the title. No, I don't wish to write assembly all day.) Thing is, I've never been the most logically-sharp person. Thus far I have only worked on hobby projects, but I find that I make the silliest of errors ever so often, and it can take me ages to find it. Like anywhere between three hours to a day to locate a simple segfault, off-by-one error, or other logical mistake. (Of course, I do other things in the meantime, like browsing SO, reddit, and the like..) It's not like I'm 'new' to programming either; I first tried C++ maybe five years ago. My question is: is this normal? Should a programmer with any talent solve it in less time? Having read Spolsky's Smart and gets things done, where he talks about the large variance in programming speed, am I near the bottom of the curve, and therefore destined to work in companies that cannot afford to hire quality programmers? I'd like to think that conceptually I'm okay -- I can grasp algorithms and concepts pretty well, I do fine in math and science, although I probably drop signs in my equations more often than the next guy. Still, grokking concepts makes me happy, and is the reason why I want to work with algorithms. I'm hoping to hear from those of you with real-world programming experience. TL;DR: I make many careless mistakes, should I not consider programming as a career?

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  • How can I create a new Person object correctly in Javascript?

    - by TimDog
    I'm still struggling with this concept. I have two different Person objects, very simply: ;Person1 = (function() { function P (fname, lname) { P.FirstName = fname; P.LastName = lname; return P; } P.FirstName = ''; P.LastName = ''; var prName = 'private'; P.showPrivate = function() { alert(prName); }; return P; })(); ;Person2 = (function() { var prName = 'private'; this.FirstName = ''; this.LastName = ''; this.showPrivate = function() { alert(prName); }; return function(fname, lname) { this.FirstName = fname; this.LastName = lname; } })(); And let's say I invoke them like this: var s = new Array(); //Person1 s.push(new Person1("sal", "smith")); s.push(new Person1("bill", "wonk")); alert(s[0].FirstName); alert(s[1].FirstName); s[1].showPrivate(); //Person2 s.push(new Person2("sal", "smith")); s.push(new Person2("bill", "wonk")); alert(s[2].FirstName); alert(s[3].FirstName); s[3].showPrivate(); The Person1 set alerts "bill" twice, then alerts "private" once -- so it recognizes the showPrivate function, but the local FirstName variable gets overwritten. The second Person2 set alerts "sal", then "bill", but it fails when the showPrivate function is called. The new keyword here works as I'd expect, but showPrivate (which I thought was a publicly exposed function within the closure) is apparently not public. I want to get my object to have distinct copies of all local variables and also expose public methods -- I've been studying closures quite a bit, but I'm still confused on this one. Thanks for your help.

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