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  • I need to modify the code of a third-party gem, where and how to do?

    - by Freewind
    I'm building a website based on RoR, and using a third-party gem "devise". I have used rake gems:unpack to unpack the "devise" to my "vendor/gems" directory. Now, I found the method "SessionsController.create" provided by "devise" is not fit my requirement, and I want to modify it. But I don't know what it is best way: just modify the method SessionsController.create" directly? create another SessionsController and override the "create" method?

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  • unix How to compare two files and get results to third file?

    - by Martin Mocik
    I have two files 1st file is like this: www.example.com www.domain.com www.otherexample.com www.other-domain.com www.other-example.com www.exa-ample.com 2nd file is like this (numbers after ;;; are between 0-10): www.example.com;;;2 www.domain.com;;;5 www.other-domain;;;0 www.exa-ample.com;;;4 and i want compare these two files and output to third file like this: www.otherexample.com www.other-example.com Both files have large size (over 500mb)

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  • Is there a way to create a WCF DataContract on a third party type?

    - by Michael Hedgpeth
    I am migrating to wcf and trying to figure out how I'm going to declare my Data Contracts properly. Some of the types I have been demoting are from a third party that I am unable to change. Are attributes the only way to explicitly declare data contracts in wcf? I know about the auto data contract functionality in 3.5, but the books I'm readin discourage that. And besides, that way assumes all state is publically available, which is oftentimes not the case.

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  • How do you store third party libraries in your source control?

    - by ajma
    How do you store third party libraries that you use in your project in your source control? When would you store binaries in your source control? When would you store the code in your source control? Would you ever store both? In what situations would you do this? (Btw, I'm using .NET but it doesn't really matter for this question)

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  • SQL SERVER – Implementing IF … THEN in SQL SERVER with CASE Statements

    - by Pinal Dave
    Here is the question I received the other day in email. “I have business logic in my .net code and we use lots of IF … ELSE logic in our code. I want to move the logic to Stored Procedure. How do I convert the logic of the IF…ELSE to T-SQL. Please help.” I have previously received this answer few times. As data grows the performance problems grows more as well. Here is the how you can convert the logic of IF…ELSE in to CASE statement of SQL Server. Here are few of the examples: Example 1: If you are logic is as following: IF -1 < 1 THEN ‘TRUE’ ELSE ‘FALSE’ You can just use CASE statement as follows: -- SQL Server 2008 and earlier version solution SELECT CASE WHEN -1 < 1 THEN 'TRUE' ELSE 'FALSE' END AS Result GO -- SQL Server 2012 solution SELECT IIF ( -1 < 1, 'TRUE', 'FALSE' ) AS Result; GO If you are interested further about how IIF of SQL Server 2012 works read the blog post which I have written earlier this year . Well, in our example the condition which we have used is pretty simple but in the real world the logic can very complex. Let us see two different methods of how we an do CASE statement when we have logic based on the column of the table. Example 2: If you are logic is as following: IF BusinessEntityID < 10 THEN FirstName ELSE IF BusinessEntityID > 10 THEN PersonType FROM Person.Person p You can convert the same in the T-SQL as follows: SELECT CASE WHEN BusinessEntityID < 10 THEN FirstName WHEN BusinessEntityID > 10 THEN PersonType END AS Col, BusinessEntityID, Title, PersonType FROM Person.Person p However, if your logic is based on multiple column and conditions are complicated, you can follow the example 3. Example 3: If you are logic is as following: IF BusinessEntityID < 10 THEN FirstName ELSE IF BusinessEntityID > 10 AND Title IS NOT NULL THEN PersonType ELSE IF Title = 'Mr.' THEN 'Mister' ELSE 'No Idea' FROM Person.Person p You can convert the same in the T-SQL as follows: SELECT CASE WHEN BusinessEntityID < 10 THEN FirstName WHEN BusinessEntityID > 10 AND Title IS NOT NULL THEN PersonType WHEN Title = 'Mr.' THEN 'Mister' ELSE 'No Idea' END AS Col, BusinessEntityID, Title, PersonType FROM Person.Person p I hope this solution is good enough to convert the IF…ELSE logic to CASE Statement in SQL Server. Let me know if you need further information about the same. Reference: Pinal Dave (http://blog.sqlauthority.com)Filed under: PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Server, SQL Tips and Tricks, T SQL

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  • SQL SERVER – SSMS Automatically Generates TOP (100) PERCENT in Query Designer

    - by pinaldave
    Earlier this week, I was surfing various SQL forums to see what kind of help developer need in the SQL Server world. One of the question indeed caught my attention. I am here regenerating complete question as well scenario to illustrate the point in a precise manner. Additionally, I have added added second part of the question to give completeness. Question: I am trying to create a view in Query Designer (not in the New Query Window). Every time I am trying to create a view it always adds  TOP (100) PERCENT automatically on the T-SQL script. No matter what I do, it always automatically adds the TOP (100) PERCENT to the script. I have attempted to copy paste from notepad, build a query and a few other things – there is no success. I am really not sure what I am doing wrong with Query Designer. Here is my query script: (I use AdventureWorks as a sample database) SELECT Person.Address.AddressID FROM Person.Address INNER JOIN Person.AddressType ON Person.Address.AddressID = Person.AddressType.AddressTypeID ORDER BY Person.Address.AddressID This script automatically replaces by following query: SELECT TOP (100) PERCENT Person.Address.AddressID FROM Person.Address INNER JOIN Person.AddressType ON Person.Address.AddressID = Person.AddressType.AddressTypeID ORDER BY Person.Address.AddressID However, when I try to do the same from New Query Window it works totally fine. However, when I attempt to create a view of the same query it gives following error. Msg 1033, Level 15, State 1, Procedure myView, Line 6 The ORDER BY clause is invalid in views, inline functions, derived tables, subqueries, and common table expressions, unless TOP, OFFSET or FOR XML is also specified. It is pretty clear to me now that the script which I have written seems to need TOP (100) PERCENT, so Query . Why do I need it? Is there any work around to this issue. I particularly find this question pretty interesting as it really touches the fundamentals of the T-SQL query writing. Please note that the query which is automatically changed is not in New Query Editor but opened from SSMS using following way. Database >> Views >> Right Click >> New View (see the image below) Answer: The answer to the above question can be very long but I will keep it simple and to the point. There are three things to discuss in above script 1) Reason for Error 2) Reason for Auto generates TOP (100) PERCENT and 3) Potential solutions to the above error. Let us quickly see them in detail. 1) Reason for Error The reason for error is already given in the error. ORDER BY is invalid in the views and a few other objects. One has to use TOP or other keywords along with it. The way semantics of the query works where optimizer only follows(honors) the ORDER BY in the same scope or the same SELECT/UPDATE/DELETE statement. There is a possibility that one can order after the scope of the view again the efforts spend to order view will be wasted. The final resultset of the query always follows the final ORDER BY or outer query’s order and due to the same reason optimizer follows the final order of the query and not of the views (as view will be used in another query for further processing e.g. in SELECT statement). Due to same reason ORDER BY is now allowed in the view. For further accuracy and clear guidance I suggest you read this blog post by Query Optimizer Team. They have explained it very clear manner the same subject. 2) Reason for Auto Generated TOP (100) PERCENT One of the most popular workaround to above error is to use TOP (100) PERCENT in the view. Now TOP (100) PERCENT allows user to use ORDER BY in the query and allows user to overcome above error which we discussed. This gives the impression to the user that they have resolved the error and successfully able to use ORDER BY in the View. Well, this is incorrect as well. The way this works is when TOP (100) PERCENT is used the result is not guaranteed as well it is ignored in our the query where the view is used. Here is the blog post on this subject: Interesting Observation – TOP 100 PERCENT and ORDER BY. Now when you create a new view in the SSMS and build a query with ORDER BY to avoid the error automatically it adds the TOP 100 PERCENT. Here is the connect item for the same issue. I am sure there will be more connect items as well but I could not find them. 3) Potential Solutions If you are reading this post from the beginning in that case, it is clear by now that ORDER BY should not be used in the View as it does not serve any purpose unless there is a specific need of it. If you are going to use TOP 100 PERCENT with ORDER BY there is absolutely no need of using ORDER BY rather avoid using it all together. Here is another blog post of mine which describes the same subject ORDER BY Does Not Work – Limitation of the Views Part 1. It is valid to use ORDER BY in a view if there is a clear business need of using TOP with any other percentage lower than 100 (for example TOP 10 PERCENT or TOP 50 PERCENT etc). In most of the cases ORDER BY is not needed in the view and it should be used in the most outer query for present result in desired order. User can remove TOP 100 PERCENT and ORDER BY from the view before using the view in any query or procedure. In the most outer query there should be ORDER BY as per the business need. I think this sums up the concept in a few words. This is a very long topic and not easy to illustrate in one single blog post. I welcome your comments and suggestions. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Server Management Studio, SQL Tips and Tricks, SQL View, T SQL, Technology

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  • EF Doesn't Like Same Named Tables

    - by Anthony Trudeau
    Originally posted on: http://geekswithblogs.net/tonyt/archive/2013/07/02/153327.aspxIt's another week and another restriction imposed by the Entity Framework (EF). Don't get me wrong. I like EF, but I don't like how it restricts you in different ways. At this point you may be asking yourself the question: how can you have more than one table with the same name?The answer is to have tables in different schemas. I do this to partition the data based on the area of concern. It allows security to be assigned conveniently. A lot of people don't use schemas. I love them. But this article isn't about schemas.In the situation I have two tables:Contact.PersonEmployee.PersonThe first contains the basic, more public information such as the name. The second contains mostly HR specific information. I then mapped these tables to two classes. I stuck to a Table per Class (TPC) mapping, because of problems I've had in the past implementing inheritance with EF. The following code gives you the basic contents of the classes.[Table("Person", Schema = "Employee")]public class Employee {   ...   public int PersonId { get; set; }   [ForeignKey("PersonId")]   public virtual Person Person { get; set; }}[Table("Person", Schema = "Contact")]public class Person {   [Key]   public int Id { get; set; }   ...}This seemingly simple scenario just doesn't work. The problem occurs when you try to add a Person to the DbContext. You get an InvalidOperationException with the following text:The entity types 'Employee' and 'Person' cannot share table 'People' because they are not in the same type hierarchy or do not have a valid one to one foreign key relationship with matching primary keys between them..This is interesting for a couple of reasons. First, there is no People table in my database. Second, I have used the SetInitializer method to stop a database from being created, so it shouldn't be thinking about new tables.The solution to my problem was to change the name of my Employee.Person table. I decided to name it Employee.Employee. It's not ideal, but it gets me past the EF limitation. I hope that this article will help someone else that has the same problem.

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  • Spring MVC configuration problems

    - by Smek
    i have some problems with configuring Spring MVC. I made a maven multi module project with the following modules: /api /domain /repositories /webapp I like to share the domain and the repositories between the api and the webapp (both web projects). First i want to configure the webapp to use the repositories module so i added the dependencies in the xml file like this: <dependency> <groupId>${project.groupId}</groupId> <artifactId>domain</artifactId> <version>1.0-SNAPSHOT</version> </dependency> <dependency> <groupId>${project.groupId}</groupId> <artifactId>repositories</artifactId> <version>1.0-SNAPSHOT</version> </dependency> And my controller in the webapp module looks like this: package com.mywebapp.webapp; import com.mywebapp.domain.Person; import com.mywebapp.repositories.services.PersonService; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.context.annotation.ComponentScan; import org.springframework.context.annotation.Configuration; import org.springframework.stereotype.Controller; import org.springframework.ui.ModelMap; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.bind.annotation.RequestMethod; @Controller @RequestMapping("/") @Configuration @ComponentScan("com.mywebapp.repositories") public class PersonController { @Autowired PersonService personservice; @RequestMapping(method = RequestMethod.GET) public String printWelcome(ModelMap model) { Person p = new Person(); p.age = 23; p.firstName = "John"; p.lastName = "Doe"; personservice.createNewPerson(p); model.addAttribute("message", "Hello world!"); return "index"; } } In my webapp module i try to load configuration files in my web.xml like this: <context-param> <param-name>contextConfigLocation</param-name> <param-value>classpath:/META-INF/persistence-context.xml, classpath:/META-INF/service-context.xml</param-value> </context-param> These files cannot be found so i get the following error: org.springframework.beans.factory.BeanDefinitionStoreException: IOException parsing XML document from class path resource [META-INF/persistence-context.xml]; nested exception is java.io.FileNotFoundException: class path resource [META-INF/persistence-context.xml] cannot be opened because it does not exist These files are in the repositories module so my first question is how can i make Spring to find these files? I also have trouble Autowiring the PersonService to my Controller class did i forget to configure something in my XML? Here is the error message: [INFO] [talledLocalContainer] SEVERE: Exception sending context initialized event to listener instance of class org.springframework.web.context.ContextLoaderListener [INFO] [talledLocalContainer] org.springframework.beans.factory.BeanCreationException: Error creating bean with name 'personServiceImpl': Injection of autowired dependencies failed; nested exception is org.springframework.beans.factory.BeanCreationException: Could not autowire field: private com.mywebapp.repositories.repository.PersonRepository com.mywebapp.repositories.services.PersonServiceImpl.personRepository; nested exception is org.springframework.beans.factory.NoSuchBeanDefinitionException: No matching bean of type [com.mywebapp.repositories.repository.PersonRepository] found for dependency: expected at least 1 bean which qualifies as autowire candidate for this dependency. Dependency annotations: {@org.springframework.beans.factory.annotation.Autowired(required=true)} PersonServiceImple.java: package com.mywebapp.repositories.services; import com.mywebapp.domain.Person; import com.mywebapp.repositories.repository.PersonRepository; import org.springframework.beans.factory.annotation.Autowired; import org.springframework.data.mongodb.core.MongoTemplate; import org.springframework.stereotype.Service; @Service public class PersonServiceImpl implements PersonService{ @Autowired public PersonRepository personRepository; @Autowired public MongoTemplate personTemplate; @Override public Person createNewPerson(Person person) { return personRepository.save(person); } } PersonService.java package com.mywebapp.repositories.services; import com.mywebapp.domain.Person; public interface PersonService { Person createNewPerson(Person person); } PersonRepository.java: package com.mywebapp.repositories.repository; import com.mywebapp.domain.Person; import org.springframework.data.mongodb.repository.MongoRepository; import org.springframework.stereotype.Repository; import java.math.BigInteger; @Repository public interface PersonRepository extends MongoRepository<Person, BigInteger> { } persistance-context.xml <?xml version="1.0" encoding="UTF-8"?> <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:context="http://www.springframework.org/schema/context" xmlns:mongo="http://www.springframework.org/schema/data/mongo" xsi:schemaLocation= "http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context-3.0.xsd http://www.springframework.org/schema/data/mongo http://www.springframework.org/schema/data/mongo/spring-mongo-1.0.xsd http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd"> <context:property-placeholder location="classpath:mongo.properties"/> <mongo:mongo host="${mongo.host}" port="${mongo.port}" id="mongo"> <mongo:options connections-per-host="${mongo.connectionsPerHost}" threads-allowed-to-block-for-connection-multiplier="${mongo.threadsAllowedToBlockForConnectionMultiplier}" connect-timeout="${mongo.connectTimeout}" max-wait-time="${mongo.maxWaitTime}" auto-connect-retry="${mongo.autoConnectRetry}" socket-keep-alive="${mongo.socketKeepAlive}" socket-timeout="${mongo.socketTimeout}" slave-ok="${mongo.slaveOk}" write-number="1" write-timeout="0" write-fsync="true"/> </mongo:mongo> <mongo:db-factory dbname="person" mongo-ref="mongo" id="mongoDbFactory"/> <bean id="personTemplate" name="personTemplate" class="org.springframework.data.mongodb.core.MongoTemplate"> <constructor-arg name="mongoDbFactory" ref="mongoDbFactory"/> </bean> <mongo:repositories base-package="com.mywebapp.repositories.repository" mongo-template-ref="personTemplate"> <mongo:repository id="personRepository" repository-impl-postfix="PersonRepository" mongo-template-ref="personTemplate" create-query-indexes="true"/> </mongo:repositories> Thanks

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  • What facets have I missed for creating a 3 person guerilla dev team?

    - by Penguinix
    Sorry for the Windows developers out there, this solution is for Macs only. This set of applications accounts for: Usability Testing, Screen Capture (Video and Still), Version Control, Task Lists, Bug Tracking, a Developer IDE, a Web Server, A Blog, Shared Doc Editing on the Web, Team and individual Chat, Email, Databases and Continuous Integration. This does assume your team members provide their own machines, and one person has a spare old computer to be the Source Repository and Web Server. All for under $200 bucks. Usability Silverback Licenses = 3 x $49.95 "Spontaneous, unobtrusive usability testing software for designers and developers." Source Control Server and Clients (multiple options) Subversion = Free Subversion is an open source version control system. Versions (Currently in Beta) = Free Versions provides a pleasant work with Subversion on your Mac. Diffly = Free "Diffly is a tool for exploring Subversion working copies. It shows all files with changes and, clicking on a file, shows a highlighted view of the changes for that file. When you are ready to commit Diffly makes it easy to select the files you want to check-in and assemble a useful commit message." Bug/Feature/Defect Tracking (multiple options) Bugzilla = Free Bugzilla is a "Defect Tracking System" or "Bug-Tracking System". Defect Tracking Systems allow individual or groups of developers to keep track of outstanding bugs in their product effectively. Most commercial defect-tracking software vendors charge enormous licensing fees. Trac = Free Trac is an enhanced wiki and issue tracking system for software development projects. Database Server & Clients MySQL = Free CocoaMySQL = Free Web Server Apache = Free Development and Build Tools XCode = Free CruiseControl = Free CruiseControl is a framework for a continuous build process. It includes, but is not limited to, plugins for email notification, Ant, and various source control tools. A web interface is provided to view the details of the current and previous builds. Collaboration Tools Writeboard = Free Ta-da List = Free Campfire Chat for 4 users = Free WordPress = Free "WordPress is a state-of-the-art publishing platform with a focus on aesthetics, web standards, and usability. WordPress is both free and priceless at the same time." Gmail = Free "Gmail is a new kind of webmail, built on the idea that email can be more intuitive, efficient, and useful." Screen Capture (Video / Still) Jing = Free "The concept of Jing is the always-ready program that instantly captures and shares images and video…from your computer to anywhere." Lots of great responses: TeamCity [Yo|||] Skype [Eric DeLabar] FogBugz [chakrit] IChatAV and Screen Sharing (built-in to OS) [amrox] Google Docs [amrox]

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  • using xml type attribute for derived complex types

    - by David Michel
    Hi All, I'm trying to get derived complex types from a base type in an xsd schema. it works well when I do this (inspired by this): xml file: <person xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="Employee"> <name>John</name> <height>59</height> <jobDescription>manager</jobDescription> </person> xsd file: <xs:element name="person" type="Person"/> <xs:complexType name="Person" abstract="true"> <xs:sequence> <xs:element name= "name" type="xs:string"/> <xs:element name= "height" type="xs:double" /> </xs:sequence> </xs:complexType> <xs:complexType name="Employee"> <xs:complexContent> <xs:extension base="Person"> <xs:sequence> <xs:element name="jobDescription" type="xs:string" /> </xs:sequence> </xs:extension> </xs:complexContent> </xs:complexType> However, if I want to have the person element inside, for example, a sequence of another complex type, it doesn't work anymore: xml: <staffRecord> <company>mycompany</company> <dpt>sales</dpt> <person xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="Employee"> <name>John</name> <height>59</height> <jobDescription>manager</jobDescription> </person> </staffRecord> xsd file: <xs:element name="staffRecord"> <xs:complexType> <xs:sequence> <xs:element name="company" type="xs:string"/> <xs:element name="dpt" type="xs:string"/> <xs:element name="person" type="Person"/> <xs:complexType name="Person" abstract="true"> <xs:sequence> <xs:element name= "name" type="xs:string"/> <xs:element name= "height" type="xs:double" /> </xs:sequence> </xs:complexType> <xs:complexType name="Employee"> <xs:complexContent> <xs:extension base="Person"> <xs:sequence> <xs:element name="jobDescription" type="xs:string" /> </xs:sequence> </xs:extension> </xs:complexContent> </xs:complexType> </xs:sequence> </xs:complexType> </xs:element> When validating the xml with that schema with xmllint (under linux), I get this error message then: config.xsd:12: element complexType: Schemas parser error : Element '{http://www.w3.org/2001/XMLSchema}sequence': The content is not valid. Expected is (annotation?, (element | group | choice | sequence | any)*). WXS schema config.xsd failed to compile Any idea what is wrong ? David

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  • How to display a person record just after saving his data to iPhone Address Book?

    - by camelCase
    this is my code and it works flawless, where my_value is a string with separator ','. everythign works fin but i'd like to display the person record from the address book after i saved it, so in the function if(isSaved) { // **** code here *** } here the complete function - (void) addToAgenda: (NSString*) my_value{ //NSArray *strings = [my_value componentsSeparatedByString: @","]; NSArray *dati=[[NSArray alloc] initWithArray:[my_value componentsSeparatedByString:@","]]; NSString *userwebsite = [dati objectAtIndex:0]; NSString *fname = [dati objectAtIndex:1]; NSString *lname = [dati objectAtIndex:2]; NSString *useremail = [dati objectAtIndex:3];; NSString *usermobile = [dati objectAtIndex:4]; NSString *usercompany = @"xxx"; ABRecordRef aRecord = ABPersonCreate(); CFErrorRef anError = NULL; // fisrst name ABRecordSetValue(aRecord, kABPersonFirstNameProperty, fname, &anError); // last name ABRecordSetValue(aRecord, kABPersonLastNameProperty, lname, &anError); // Phone Number. ABMutableMultiValueRef multi = ABMultiValueCreateMutable(kABMultiStringPropertyType); ABMultiValueAddValueAndLabel(multi, (CFStringRef)usermobile, kABWorkLabel, NULL); ABRecordSetValue(aRecord, kABPersonPhoneProperty, multi, &anError); CFRelease(multi); // Company ABRecordSetValue(aRecord, kABPersonDepartmentProperty, usercompany, &anError); // email NSLog(@"%@", useremail); ABMutableMultiValueRef multiemail = ABMultiValueCreateMutable(kABMultiStringPropertyType); ABMultiValueAddValueAndLabel(multiemail, (CFStringRef)useremail, kABWorkLabel, NULL); ABRecordSetValue(aRecord, kABPersonEmailProperty, multiemail, &anError); CFRelease(multiemail); // website NSLog(@"%@", userwebsite); ABMutableMultiValueRef multiweb = ABMultiValueCreateMutable(kABMultiStringPropertyType); ABMultiValueAddValueAndLabel(multiweb, (CFStringRef)userwebsite, kABWorkLabel, NULL); ABRecordSetValue(aRecord, kABPersonURLProperty, multiweb, &anError); CFRelease(multiemail); if (anError != NULL) NSLog(@"error while creating.."); CFStringRef personname, personlname, personcompind, personemail, personwebsite, personcontact; personname = ABRecordCopyValue(aRecord, kABPersonFirstNameProperty); personlname = ABRecordCopyValue(aRecord, kABPersonLastNameProperty); personcompind = ABRecordCopyValue(aRecord, kABPersonDepartmentProperty); personemail = ABRecordCopyValue(aRecord, kABPersonEmailProperty); personwebsite = ABRecordCopyValue(aRecord, kABPersonURLProperty); personcontact = ABRecordCopyValue(aRecord, kABPersonPhoneProperty); ABAddressBookRef addressBook; CFErrorRef error = NULL; addressBook = ABAddressBookCreate(); BOOL isAdded = ABAddressBookAddRecord (addressBook, aRecord, &error); if(isAdded){ NSLog(@"added.."); } if (error != NULL) { NSLog(@"ABAddressBookAddRecord %@", error); } error = NULL; BOOL isSaved = ABAddressBookSave (addressBook, &error); if(isSaved) { // **** code here *** } if (error != NULL) { NSLog(@"ABAddressBookSave %@", error); UIAlertView *alertOnChoose = [[UIAlertView alloc] initWithTitle:@"Unable to save this time" message:nil delegate:self cancelButtonTitle:nil otherButtonTitles:@"Ok", nil]; [alertOnChoose show]; [alertOnChoose release]; } CFRelease(aRecord); CFRelease(personname); CFRelease(personlname); CFRelease(personcompind); CFRelease(personcontact); CFRelease(personemail); CFRelease(personwebsite); CFRelease(addressBook); }

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  • With NHibernate, how can I add a child object when updating a parent object?

    - by BMZ
    I have a simple Parent/Child relationship between a Person object and an Address object. The Person object exists in the DB. After doing a Get on the Person, I add a new Address object to the Address sub-object list of the parent, and do some other updates to the Person object. Finally, I do an Update on the Person object. With a SQL trace window, I can see the update to the Person object to the Person table and the Insert of the Address record to the Address table. The issue is that, after the update is performed, the AddressId (primary key on the Address object) is still set to 0, which is what it defaults to when you first initialize the Address object. I have verified that when I do an Add, this value is set correctly. Is this a known issue when trying to add sub-objects as part of an NHibernate UPDATE? Sample code and mapping files are below Thanks <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"> <class name="BusinessEntities.Wellness.Person,BusinessEntities.Wellness" table="Person" lazy="true" dynamic-insert="true" dynamic-update="false"> <id name="Personid" column="PersonID" type="int"> <generator class="native" /> </id> <version type="binary" generated="always" name="RecordVersion" column="`RecordVersion`"/> <property type="int" not-null="true" name="Customerid" column="`CustomerID`" /> <property type="AnsiString" not-null="true" length="9" name="Ssn" column="`SSN`" /> <property type="AnsiString" not-null="true" length="30" name="FirstName" column="`FirstName`" /> <property type="AnsiString" not-null="true" length="35" name="LastName" column="`LastName`" /> <property type="AnsiString" length="1" name="MiddleInitial" column="`MiddleInitial`" /> <property type="DateTime" name="DateOfBirth" column="`DateOfBirth`" /> <bag name="PersonAddresses" inverse="true" lazy="true" cascade="all"> <key column="PersonID" /> <one-to-many class="BusinessEntities.Wellness.PersonAddress,BusinessEntities.Wellness" / </bag> </class> </hibernate-mapping> <hibernate-mapping xmlns="urn:nhibernate-mapping-2.2"> <class name="BusinessEntities.Wellness.PersonAddress,BusinessEntities.Wellness" table="PersonAddress" lazy="true" dynamic-insert="true" dynamic-update="false"> <id name="PersonAddressId" column="PersonAddressID" type="int"> <generator class="native" /> </id> <version type="binary" generated="always" name="RecordVersion" column="`RecordVersion`" /> <property type="AnsiString" not-null="true" length="1" name="AddressTypeid" column="`AddressTypeID`" /> <property type="AnsiString" not-null="true" length="60" name="AddressLine1" column="`AddressLine1`" /> <property type="AnsiString" length="60" name="AddressLine2" column="`AddressLine2`" /> <property type="AnsiString" length="60" name="City" column="`City`" /> <property type="AnsiString" length="2" name="UsStateId" column="`USStateID`" /> <property type="AnsiString" length="5" name="UsPostalCodeId" column="`USPostalCodeID`" /> <many-to-one name="Person" cascade="none" column="PersonID" /> </class> </hibernate-mapping> Person newPerson = new Person(); newPerson.PersonName = "John Doe"; newPerson.SSN = "111111111"; newPerson.CreatedBy = "RJC"; newPerson.CreatedDate = DateTime.Today; personDao.AddPerson(newPerson); Person updatePerson = personDao.GetPerson(newPerson.PersonId); updatePerson.PersonAddresses = new List<PersonAddress>(); PersonAddress addr = new PersonAddress(); addr.AddressLine1 = "1 Main St"; addr.City = "Boston"; addr.State = "MA"; addr.Zip = "12345"; updatePerson.PersonAddresses.Add(addr); personDao.UpdatePerson(updatePerson); int addressID = updatePerson.PersonAddresses[0].AddressId;

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  • ASP.NET MVC: Using jQuery context menu with tables

    - by DigiMortal
    I needed to add context menus to some tables of my intranet application. After trying some components I found one that does everything I need and has no overhead. In this posting I will show you how to use jQuery context menu plug-in and how to attach it to tables. I found context menu plug-in by Chris Domigan and it was very easy to integrate to my application (when comparing some other plug-ins that work only on demo pages and in simple scenarios). Thanks, Chris, for great work! Now let’s use this context menu plug-in with table. Before we go on let’s see what we are trying to achieve. The following screenshot fragment shows simple context menu that we want to attach to our table. And when we click some menu option then something should happen too. :) Installing context menu plug-in Download plug-in (if download link is broken then open demo page and I think you know how to get plug-in from there). Copy jquery.contextmenu.js to your scripts folder. Include it in your masterpage or in the page where you plan to use context menus. Make sure plug-in is included correctly (use Firebug or some other tool you like). Save the page. Defining context menu Now let’s define context menu. Here is fragment on context menu definition from my code. <div class="contextMenu" id="myMenu1">     <ul>     <li id="email"><img src="/img/e-mail.png" />E-mail</li>     <li id="homepage"><img src="/img/homepage.png" />Homepage</li>     </ul> </div> div with id myMenu1 is container of context menu. Unordered list inside container defines items in context menu – simple and elegant! Adding context menu to table I have table with persons. It is simple HTML. I omitted commands column from this and the next table to keep them simple and more easily readable. <table>   <tr>     <th>Name</th>     <th>Short</th>     <th>Address</th>     <th>Mobile</th>     <th>E-mail</th>   </tr>   <% foreach(var person in Model.Results) { %>   <tr>     <td><%=person.FullName %></td>     <td><%=person.ShortName %></td>     <td><%=person.FullAddress %></td>     <td><%=person.Mobile %></td>     <td><%=person.Email %></td>   </tr>   <% } %> </table> To get context menu linked to table rows first cells we need to specify class for cells and ID. We need ID because we have to know later which ID has the row on which user selected something from context menu. <table>   <tr>     <th>Name</th>     <th>Short</th>     <th>Address</th>     <th>Mobile</th>     <th>E-mail</th>   </tr>   <% foreach(var person in Model.Results) { %>   <tr>     <td class="showContext" id="<%= person.Id %>"><%=person.FullName %></td>     <td><%=person.ShortName %></td>     <td><%=person.FullAddress %></td>     <td><%=person.Mobile %></td>     <td><%=person.Email %></td>   </tr>   <% } %> </table> Now we have only one thing to do – we have to write some code that attaches context menu to table cells. Catching context menu events Now we will make everything work. Relax, it is only couple of lines of code, thank to jQuery. <script type="text/javascript">   $(document).ready(function () {     $('td.showContext').contextMenu('myMenu1', {         bindings: {         'email': function (t) {           document.location.href = '/contact/sendmail/' + t.id;         },         'homepage': function (t) {           document.location.href = '/contact/homepage/' + t.id;         }       }     });   }); </script> I think that first lines doesn’t need any comments. Take a look at bindings. We gave ID to table cells because it is carried also to bound events. We can use also more complex ID-s if we have more than one table with context menus on our form. Now we are done. Save all files, compile solution, run it and try out how context menu works. Conclusion We saw than using jQuery with context menu component allows us easily create powerful context menus for our user interfaces. Context menu was very easy to define. We were also able to attach context menu to table and use ID of current row entity also in events of context menu. To achieve this we needed only some minor modifications in view and couple of lines of JavaScript.

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  • SQL Spatial: Getting “nearest” calculations working properly

    - by Rob Farley
    If you’ve ever done spatial work with SQL Server, I hope you’ve come across the ‘nearest’ problem. You have five thousand stores around the world, and you want to identify the one that’s closest to a particular place. Maybe you want the store closest to the LobsterPot office in Adelaide, at -34.925806, 138.605073. Or our new US office, at 42.524929, -87.858244. Or maybe both! You know how to do this. You don’t want to use an aggregate MIN or MAX, because you want the whole row, telling you which store it is. You want to use TOP, and if you want to find the closest store for multiple locations, you use APPLY. Let’s do this (but I’m going to use addresses in AdventureWorks2012, as I don’t have a list of stores). Oh, and before I do, let’s make sure we have a spatial index in place. I’m going to use the default options. CREATE SPATIAL INDEX spin_Address ON Person.Address(SpatialLocation); And my actual query: WITH MyLocations AS (SELECT * FROM (VALUES ('LobsterPot Adelaide', geography::Point(-34.925806, 138.605073, 4326)),                        ('LobsterPot USA', geography::Point(42.524929, -87.858244, 4326))                ) t (Name, Geo)) SELECT l.Name, a.AddressLine1, a.City, s.Name AS [State], c.Name AS Country FROM MyLocations AS l CROSS APPLY (     SELECT TOP (1) *     FROM Person.Address AS ad     ORDER BY l.Geo.STDistance(ad.SpatialLocation)     ) AS a JOIN Person.StateProvince AS s     ON s.StateProvinceID = a.StateProvinceID JOIN Person.CountryRegion AS c     ON c.CountryRegionCode = s.CountryRegionCode ; Great! This is definitely working. I know both those City locations, even if the AddressLine1s don’t quite ring a bell. I’m sure I’ll be able to find them next time I’m in the area. But of course what I’m concerned about from a querying perspective is what’s happened behind the scenes – the execution plan. This isn’t pretty. It’s not using my index. It’s sucking every row out of the Address table TWICE (which sucks), and then it’s sorting them by the distance to find the smallest one. It’s not pretty, and it takes a while. Mind you, I do like the fact that it saw an indexed view it could use for the State and Country details – that’s pretty neat. But yeah – users of my nifty website aren’t going to like how long that query takes. The frustrating thing is that I know that I can use the index to find locations that are within a particular distance of my locations quite easily, and Microsoft recommends this for solving the ‘nearest’ problem, as described at http://msdn.microsoft.com/en-au/library/ff929109.aspx. Now, in the first example on this page, it says that the query there will use the spatial index. But when I run it on my machine, it does nothing of the sort. I’m not particularly impressed. But what we see here is that parallelism has kicked in. In my scenario, it’s split the data up into 4 threads, but it’s still slow, and not using my index. It’s disappointing. But I can persuade it with hints! If I tell it to FORCESEEK, or use my index, or even turn off the parallelism with MAXDOP 1, then I get the index being used, and it’s a thing of beauty! Part of the plan is here: It’s massive, and it’s ugly, and it uses a TVF… but it’s quick. The way it works is to hook into the GeodeticTessellation function, which is essentially finds where the point is, and works out through the spatial index cells that surround it. This then provides a framework to be able to see into the spatial index for the items we want. You can read more about it at http://msdn.microsoft.com/en-us/library/bb895265.aspx#tessellation – including a bunch of pretty diagrams. One of those times when we have a much more complex-looking plan, but just because of the good that’s going on. This tessellation stuff was introduced in SQL Server 2012. But my query isn’t using it. When I try to use the FORCESEEK hint on the Person.Address table, I get the friendly error: Msg 8622, Level 16, State 1, Line 1 Query processor could not produce a query plan because of the hints defined in this query. Resubmit the query without specifying any hints and without using SET FORCEPLAN. And I’m almost tempted to just give up and move back to the old method of checking increasingly large circles around my location. After all, I can even leverage multiple OUTER APPLY clauses just like I did in my recent Lookup post. WITH MyLocations AS (SELECT * FROM (VALUES ('LobsterPot Adelaide', geography::Point(-34.925806, 138.605073, 4326)),                        ('LobsterPot USA', geography::Point(42.524929, -87.858244, 4326))                ) t (Name, Geo)) SELECT     l.Name,     COALESCE(a1.AddressLine1,a2.AddressLine1,a3.AddressLine1),     COALESCE(a1.City,a2.City,a3.City),     s.Name AS [State],     c.Name AS Country FROM MyLocations AS l OUTER APPLY (     SELECT TOP (1) *     FROM Person.Address AS ad     WHERE l.Geo.STDistance(ad.SpatialLocation) < 1000     ORDER BY l.Geo.STDistance(ad.SpatialLocation)     ) AS a1 OUTER APPLY (     SELECT TOP (1) *     FROM Person.Address AS ad     WHERE l.Geo.STDistance(ad.SpatialLocation) < 5000     AND a1.AddressID IS NULL     ORDER BY l.Geo.STDistance(ad.SpatialLocation)     ) AS a2 OUTER APPLY (     SELECT TOP (1) *     FROM Person.Address AS ad     WHERE l.Geo.STDistance(ad.SpatialLocation) < 20000     AND a2.AddressID IS NULL     ORDER BY l.Geo.STDistance(ad.SpatialLocation)     ) AS a3 JOIN Person.StateProvince AS s     ON s.StateProvinceID = COALESCE(a1.StateProvinceID,a2.StateProvinceID,a3.StateProvinceID) JOIN Person.CountryRegion AS c     ON c.CountryRegionCode = s.CountryRegionCode ; But this isn’t friendly-looking at all, and I’d use the method recommended by Isaac Kunen, who uses a table of numbers for the expanding circles. It feels old-school though, when I’m dealing with SQL 2012 (and later) versions. So why isn’t my query doing what it’s supposed to? Remember the query... WITH MyLocations AS (SELECT * FROM (VALUES ('LobsterPot Adelaide', geography::Point(-34.925806, 138.605073, 4326)),                        ('LobsterPot USA', geography::Point(42.524929, -87.858244, 4326))                ) t (Name, Geo)) SELECT l.Name, a.AddressLine1, a.City, s.Name AS [State], c.Name AS Country FROM MyLocations AS l CROSS APPLY (     SELECT TOP (1) *     FROM Person.Address AS ad     ORDER BY l.Geo.STDistance(ad.SpatialLocation)     ) AS a JOIN Person.StateProvince AS s     ON s.StateProvinceID = a.StateProvinceID JOIN Person.CountryRegion AS c     ON c.CountryRegionCode = s.CountryRegionCode ; Well, I just wasn’t reading http://msdn.microsoft.com/en-us/library/ff929109.aspx properly. The following requirements must be met for a Nearest Neighbor query to use a spatial index: A spatial index must be present on one of the spatial columns and the STDistance() method must use that column in the WHERE and ORDER BY clauses. The TOP clause cannot contain a PERCENT statement. The WHERE clause must contain a STDistance() method. If there are multiple predicates in the WHERE clause then the predicate containing STDistance() method must be connected by an AND conjunction to the other predicates. The STDistance() method cannot be in an optional part of the WHERE clause. The first expression in the ORDER BY clause must use the STDistance() method. Sort order for the first STDistance() expression in the ORDER BY clause must be ASC. All the rows for which STDistance returns NULL must be filtered out. Let’s start from the top. 1. Needs a spatial index on one of the columns that’s in the STDistance call. Yup, got the index. 2. No ‘PERCENT’. Yeah, I don’t have that. 3. The WHERE clause needs to use STDistance(). Ok, but I’m not filtering, so that should be fine. 4. Yeah, I don’t have multiple predicates. 5. The first expression in the ORDER BY is my distance, that’s fine. 6. Sort order is ASC, because otherwise we’d be starting with the ones that are furthest away, and that’s tricky. 7. All the rows for which STDistance returns NULL must be filtered out. But I don’t have any NULL values, so that shouldn’t affect me either. ...but something’s wrong. I do actually need to satisfy #3. And I do need to make sure #7 is being handled properly, because there are some situations (eg, differing SRIDs) where STDistance can return NULL. It says so at http://msdn.microsoft.com/en-us/library/bb933808.aspx – “STDistance() always returns null if the spatial reference IDs (SRIDs) of the geography instances do not match.” So if I simply make sure that I’m filtering out the rows that return NULL… …then it’s blindingly fast, I get the right results, and I’ve got the complex-but-brilliant plan that I wanted. It just wasn’t overly intuitive, despite being documented. @rob_farley

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  • Entity Framework 4, WCF &amp; Lazy Loading Tip

    - by Dane Morgridge
    If you are doing any work with Entity Framework and custom WCF services in EFv1, everything works great.  As soon as you jump to EFv4, you may find yourself getting odd errors that you can’t seem to catch.  The problem is almost always has something to do with the new lazy loading feature in Entity Framework 4.  With Entity Framework 1, you didn’t have lazy loading so this problem didn’t surface.  Assume I have a Person entity and an Address entity where there is a one-to-many relationship between Person and Address (Person has many Addresses). In Entity Framework 1 (or in EFv4 with lazy loading turned off), I would have to load the Address data by hand by either using the Include or Load Method: var people = context.People.Include("Addresses"); or people.Addresses.Load(); Lazy loading works when the first time the Person.Addresses collection is accessed: 1: var people = context.People.ToList(); 2:  3: // only person data is currently in memory 4:  5: foreach(var person in people) 6: { 7: // EF determines that no Address data has been loaded and lazy loads 8: int count = person.Addresses.Count(); 9: } 10:  Lazy loading has the useful (and sometimes not useful) feature of fetching data when requested.  It can make your life easier or it can make it a big pain.  So what does this have to do with WCF?  One word: Serialization. When you need to pass data over the wire with WCF, the data contract is serialized into either XML or binary depending on the binding you are using.  Well, if I am using lazy loading, the Person entity gets serialized and during that process, the Addresses collection is accessed.  When that happens, the Address data is lazy loaded.  Then the Address is serialized, and the Person property is accessed, and then also serialized and then the Addresses collection is accessed.  Now the second time through, lazy loading doesn’t kick in, but you can see the infinite loop caused by this process.  This is a problem with any serialization, but I personally found it trying to use WCF. The fix for this is to simply turn off lazy Loading.  This can be done at each call by using context options: context.ContextOptions.LazyLoadingEnabled = false; Turning lazy loading off will now allow your classes to be serialized properly.  Note, this is if you are using the standard Entity Framework classes.  If you are using POCO,  you will have to do something slightly different.  With POCO, the Entity Framework will create proxy classes by default that allow things like lazy loading to work with POCO.  This proxy basically creates a proxy object that is a full Entity Framework object that sits between the context and the POCO object.  When using POCO with WCF (or any serialization) just turning off lazy loading doesn’t cut it.  You have to turn off the proxy creation to ensure that your classes will serialize properly: context.ContextOptions.ProxyCreationEnabled = false; The nice thing is that you can do this on a call-by-call basis.  If you use a new context for each set of operations (which you should) then you can turn either lazy loading or proxy creation on and off as needed.

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  • I want to consolidate two sites into a third. Will my search engine rankings be penalized if I rewrite and redirect pages one by one?

    - by Patrick Kenny
    I have two Drupal sites with different content-- let's call them Apple and Orange. I recently developed a much more sophisticated third Drupal site-- let's call it Tree. For a large number of reasons, the content on Apple and Orange is useful for the users of Tree, so I want to move the content to Tree. However, much of the content is out of date. (This whole process took about five years.) To update the content, I will rewrite it one article at a time myself. Now here's my question: if I move the articles one by one (as I rewrite them) and then redirect the old articles (using a 301 redirect) on Apple/Orange to the new site on Tree, will this have a huge negative effect on my search engine rankings? Is there a good way to redirect among sites when they merge like this, or would I be better off keeping the old articles on Apple/Orange and simply linking them to the new, rewritten articles on Tree?

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  • How to display strings in activity 3 from activity 1, 2? [migrated]

    - by user107160
    I need to get strings values from two different activities say activity1 and activity2, each activity should have maximum 4 edittext field..so totally eight fields should be displayed orderly in activity3. I have tried the code which is not displaying in the activity3. Look at code, Activity1 String namef = fname.getText().toString(); Intent first = new Intent(AssessmentActivity.this, Second.class); first.putExtra("list1", namef); startActivity(first); String namel = lname.getText().toString(); Intent second = new Intent(AssessmentActivity.this, Second.class); second.putExtra("list2", namel); startActivity(second); String phone = mob.getText().toString(); Intent third = new Intent(AssessmentActivity.this, Second.class); third.putExtra("list3", phone); startActivity(third); String mailid = email.getText().toString(); Intent fourth = new Intent(AssessmentActivity.this, Second.class); fourth.putExtra("list4", mailid); startActivity(fourth); Activity2 String cont = addr.getText().toString(); Intent fifth = new Intent(Second.this, Third.class); fifth.putExtra("list5", cont); startActivity(fifth); String db = dob.getText().toString(); Intent sixth = new Intent(Second.this, Third.class); sixth.putExtra("list6", db); startActivity(sixth); String nation = citizen.getText().toString(); Intent Seventh = new Intent(Second.this, Third.class); Seventh.putExtra("list7", nation); startActivity(Seventh); String subject = course.getText().toString(); Intent Eight = new Intent(Second.this, Third.class); Eight.putExtra("list8", subject); startActivity(Eight); *Activity3* TextView first = (TextView)findViewById(R.id.textView2); String fieldone = getIntent().getStringExtra("list1" ); first.setText(fieldone); TextView second = (TextView)findViewById(R.id.textView3); String fieldtwo = getIntent().getStringExtra("list2" ); second.setText(fieldtwo); TextView third = (TextView)findViewById(R.id.textView4); String fieldthree = getIntent().getStringExtra("list3" ); third.setText(fieldthree); TextView fourth = (TextView)findViewById(R.id.textView5); String fieldfour = getIntent().getStringExtra("list4" ); fourth.setText(fieldfour); TextView fifth = (TextView)findViewById(R.id.textView6); String fieldfive = getIntent().getStringExtra("list5" ); fifth.setText(fieldfive); TextView sixth = (TextView)findViewById(R.id.textView7); String fieldsix = getIntent().getStringExtra("list6" ); sixth.setText(fieldsix); TextView seventh = (TextView)findViewById(R.id.textView8); String fieldseven = getIntent().getStringExtra("list7" ); seventh.setText(fieldseven); TextView eight = (TextView)findViewById(R.id.textView3); String fieldeight = getIntent().getStringExtra("list8"); eight.setText(fieldeight);

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  • Adding a mini admin to a webpage.

    - by DADU
    Hello Picture this: you are creating a little module that people can incorporate into their website easily, for example, a little contact form. It would consist of a PHP file that outputs some HTML, a Javascript file (ajax etc.), a CSS file and a CSS skin. Now the person who doesn't know much about coding wants to integrate it on a webpage (website/index.php). We could do this with three rules of code: <link rel="stylesheet" href="module/css/module.css" /> <script src="module/js/module.js"></script> <?php require_once 'module/module.php'; ?> There's no doubt this part is questionable, right? Now when we want to add an admin for this little module, there are two options: Accessing the admin via an extra URL like website/module/admin.php and after authentication, displaying a page where the person can do all the settings. The person then goes back to index.php to see the results. Enabling the admin via an extra URL like website/module/admin.php and after authentication, redirecting back to index.php. The person can now edit the module directly (HTML5 contenteditable) and see changes live, on the webpage where everybody else will see it when the person saves the changes. Option 2 has a couple of advantages: The person doesn't have to toggle between admin and index.php. The person can see directly how it's looking at the webpage it's integrated in. The person probably feels like the module is more part of the webpage/website. Of course option 2 has some disadvantages too: Not everything works well editing it inline. The person would need to have an HTML5 compliant browser. Probably some more I can't think of right now. Now I have a few concerns that's I can't seem to see a clear answer to. How would we let the person integrate the admin on their webpage? The admin files only need to be included in index.php if the person has choosen to edit the module via the url (website/module/admin.php). But how can we do this if we have a admin.css file that belongs in the head section, an admin.php file that goes into the body, and another admin.js file that's included at the end of the body? How would we know the file that admin.php needs to redirect back to, after authentication? index.php could be any webpage with any name. Any real life website/web apps examples using this principle are welcome too. If there's something unclear, I am glad to add additional info.

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