Search Results

Search found 14182 results on 568 pages for 'andrew answer'.

Page 210/568 | < Previous Page | 206 207 208 209 210 211 212 213 214 215 216 217  | Next Page >

  • jQuery and Firebug

    - by Jeffrey Karbowski
    I am using jQuery's cycle plugin, and found that I can call up the default for "speed" by typing this into Firebug's console: $.fn.cycle.defaults.speed 1000 I would like to know how to call up the override I have for speed: $('.xxx').cycle({ speed: 1700 }); If you have the answer, please let me know the steps taken to figure it out so I can understand Firebug better. Thanks a bunch!

    Read the article

  • Preventing a WPF Expander from expanding when header is clicked

    - by emddudley
    How can I prevent a WPF Expander from expanding when its header is clicked? I would like my Expander to expand or collapse only when the expand button itself is clicked. I imagine the answer has something to do with canceling a bubbled event. If possible I would like to implement the solution in XAML while avoiding retemplating the entire Expander.

    Read the article

  • Limit for Google calendar SMS notification per day

    - by pit777
    What is the limit for Google calendar SMS notification per day? How to detect I reached sms limit? Google write only this: http://www.google.com/support/calendar/bin/answer.py?hl=en&answer=36589 You might have reached the limit for SMS notifications. There is a limit to the number of SMS notifications you can receive each day. This limit shouldn't affect most users, but it's something to keep in mind if you've scheduled a large number of events and are no longer receiving SMS notifications. I created sms reminder based on google calendar api(apps-script), but I think now I reached the daily limit for SMS notifications... but google not informed what is exactly amount of sms limit restriction :/ function emailNotification() { // POWIADOMIENIA SMS O NOWEJ POCZCIE var calendarID = "[email protected]"; // id kalendarza o nazwie „sms4email” var gmailLabelTODO = "autoscriptslabels/sms"; // etykieta „AutoScriptsLabels/SMS” var gmailLabelDONE = "done/_sms"; // etykieta „DONE/_SMS” var calendarEventDescription = "this-is-sms_notification-mark"; // etykieta utworzonego zdarzenia, dzieki której mozna bedzie je znalezc podczas kasowania var calendar = CalendarApp.getCalendarById(calendarID); // otwieramy kalendarz var threads = GmailApp.getUserLabelByName(gmailLabelTODO).getThreads(); // zmienna przechowujaca kolekcje lancuszków z etykieta TODO var now = new Date(); if(threads == 0) return; // zaprzestanie wykonywania, jezeli brak nowych lancuszków for(i in threads) // tworzymy zdarzenia { var title = threads[i].getFirstMessageSubject(); // tytul emaila var startDate = new Date(now.getTime()+120000); var endDate = new Date(now.getTime()+120000); var messages = threads[i].getMessages(); var senderEmail = messages[0].getFrom(); // nadawca emaila var advancedArgs = {location:senderEmail, description:calendarEventDescription}; calendar.createEvent(title, startDate, endDate, advancedArgs); } Utilities.sleep(1000); GmailApp.getUserLabelByName(gmailLabelDONE).addToThreads(threads); // dodawanie etykiety DONE Utilities.sleep(1000); GmailApp.getUserLabelByName(gmailLabelTODO).removeFromThreads(threads); // usuwanie etykiety TODO Utilities.sleep(120000); // czekamy az kalendarz wysle SMS var TodaysEvents = calendar.getEventsForDay(now); for (i in TodaysEvents) // wyszukiwanie wedlug zdarzenia i kasowanie po wyslaniu { if (TodaysEvents[i].getDescription()==calendarEventDescription) TodaysEvents[i].deleteEvent(); } }

    Read the article

  • Is there an algorithm for converting quaternion rotations to Euler angle rotations?

    - by Will Baker
    Is there an existing algorithm for converting a quaternion representation of a rotation to an Euler angle representation? The rotation order for the Euler representation is known and can be any of the six permutations (i.e. xyz, xzy, yxz, yzx, zxy, zyx). I've seen algorithms for a fixed rotation order (usually the NASA heading, bank, roll convention) but not for arbitrary rotation order. Furthermore, because there are multiple Euler angle representations of a single orientation, this result is going to be ambiguous. This is acceptable (because the orientation is still valid, it just may not be the one the user is expecting to see), however it would be even better if there was an algorithm which took rotation limits (i.e. the number of degrees of freedom and the limits on each degree of freedom) into account and yielded the 'most sensible' Euler representation given those constraints. I have a feeling this problem (or something similar) may exist in the IK or rigid body dynamics domains. Solved: I just realised that it might not be clear that I solved this problem by following Ken Shoemake's algorithms from Graphics Gems. I did answer my own question at the time, but it occurs to me it may not be clear that I did so. See the answer, below, for more detail. Just to clarify - I know how to convert from a quaternion to the so-called 'Tait-Bryan' representation - what I was calling the 'NASA' convention. This is a rotation order (assuming the convention that the 'Z' axis is up) of zxy. I need an algorithm for all rotation orders. Possibly the solution, then, is to take the zxy order conversion and derive from it five other conversions for the other rotation orders. I guess I was hoping there was a more 'overarching' solution. In any case, I am surprised that I haven't been able to find existing solutions out there. In addition, and this perhaps should be a separate question altogether, any conversion (assuming a known rotation order, of course) is going to select one Euler representation, but there are in fact many. For example, given a rotation order of yxz, the two representations (0,0,180) and (180,180,0) are equivalent (and would yield the same quaternion). Is there a way to constrain the solution using limits on the degrees of freedom? Like you do in IK and rigid body dynamics? i.e. in the example above if there were only one degree of freedom about the Z axis then the second representation can be disregarded. I have tracked down one paper which could be an algorithm in this pdf but I must confess I find the logic and math a little hard to follow. Surely there are other solutions out there? Is arbitrary rotation order really so rare? Surely every major 3D package that allows skeletal animation together with quaternion interpolation (i.e. Maya, Max, Blender, etc) must have solved exactly this problem?

    Read the article

  • Custom Event - invokation list implementation considerations

    - by M.A. Hanin
    I'm looking for some pointers on implementing Custom Events in VB.NET (Visual Studio 2008, .NET 3.5). I know that "regular" (non-custom) Events are actually Delegates, so I was thinking of using Delegates when implementing a Custom Event. On the other hand, Andrew Troelsen's "Pro VB 2008 and the .NET 3.5 Platform" book uses Collection types in all his Custom Events examples, and Microsoft's sample codes match that line of thought. So my question is: what considerations should I have when choosing one design over the other? What are the pros and cons for each design? Which of these resembles the inner-implementation of "regular" events? Below is a sample code demonstrating the two designs. Public Class SomeClass Private _SomeEventListeners As EventHandler Public Custom Event SomeEvent As EventHandler AddHandler(ByVal value As EventHandler) _SomeEventListeners = [Delegate].Combine(_SomeEventListeners, value) End AddHandler RemoveHandler(ByVal value As EventHandler) _SomeEventListeners = [Delegate].Remove(_SomeEventListeners, value) End RemoveHandler RaiseEvent(ByVal sender As Object, ByVal e As System.EventArgs) _SomeEventListeners.Invoke(sender, e) End RaiseEvent End Event Private _OtherEventListeners As New List(Of EventHandler) Public Custom Event OtherEvent As EventHandler AddHandler(ByVal value As EventHandler) _OtherEventListeners.Add(value) End AddHandler RemoveHandler(ByVal value As EventHandler) _OtherEventListeners.Remove(value) End RemoveHandler RaiseEvent(ByVal sender As Object, ByVal e As System.EventArgs) For Each handler In _OtherEventListeners handler(sender, e) Next End RaiseEvent End Event End Class

    Read the article

  • How to obtain position in file (byte-position) from java scanner?

    - by september2010
    How to obtain a position in file (byte-position) from the java scanner? Scanner scanner = new Scanner(new File("file")); scanner.useDelimiter("abc"); scanner.hasNext(); String result = scanner.next(); and now: how to get the position of result in file (in bytes)? Using scanner.match().start() is not the answer, because it gives the position within internal buffer.

    Read the article

  • simplest way to confirm payment via PayPal?

    - by Giles Bowkett
    Hi - what's the best way to simply get feedback from PayPal to confirm that your customer paid? It looks as if the answer is IPN - if so, my followup question is, can I enable IPN for only specific buttons? I don't want PayPal pinging my IPN listener for purchases that don't require any kind of IPN integration. I'm all about Agile and YAGNI, I don't want to do ANYTHING unnecessary.

    Read the article

  • Java LockSupport Memory Consistency

    - by Lachlan
    Java 6 API question. Does calling LockSupport.unpark(thread) have a happens-before relationship to the return from LockSupport.park in the just-unparked thread? I strongly suspect the answer is yes, but the Javadoc doesn't seem to mention it explicitly.

    Read the article

  • Performance comparison of Dictionaries

    - by Hun1Ahpu
    I'm interested in performance values (big-O analysis) of Lookup and Insert operation for .Net Dictionaries: HashTable, SortedList, StringDictionary, ListDictionary, HybridDictionary, NameValueCollection Link to a web page with the answer works for me too.

    Read the article

  • What's the meaning of “Monty Python’s Flying Circus” phrase on Python?

    - by Zignd
    I just started studying Python using the Python 3.2 Tutorial and on the introduction is written: By the way, the language is named after the BBC show “Monty Python’s Flying Circus” and has nothing to do with reptiles. Making references to Monty Python skits in documentation is not only allowed, it is encouraged! But I have to say that I did not understood this part: “Monty Python’s Flying Circus”, I'm Brazilian and even Google Translator don't know how to answer it. Can someone explain me this phrase?

    Read the article

  • Mercurial error: abort no username supplied

    - by Kevin Won
    Problem on WindowsXP (likely will happen on all Win installs), first time using Mercurial. I found the answer in an inobvious place so I'm asking/answering the question myself so others don't have to search like I did. First time using Mercurial on machine. Add new repoz: c:\bla\>hg add no problem. Next, commit: c:\bla\hg commit error: abort: no username supplied (see "hg help config")

    Read the article

  • Groovy syntax <? , <?>>

    - by bsreekanth
    Hello, I was going through one of the answer in SO, where I see the following syntax private Class<? extends Enum<?>> clazz what all the <? , <?>> expression means. Looks like generalize the implementation based on regex kind of expression. What is it called in Groovy... many thanks..

    Read the article

  • Get size of UIView after applying CGAffineTransform

    - by Ican Zilb
    I was surprised not to find an answer to this question, maybe is something very simple I somehow overlook : How to get the real size of an UIView after I apply a CGAffineTransform to it? eg. my UIView has size 300 x 200, I apply a scaling transform let's say factor 2 both horizontal and vertical, so the UIView now takes 600 x 400 on the screen, but it's bounds and it's layer's bounds are still returning a size of 300 x 200 ... where do I find the real size of the UIView ?

    Read the article

  • FIPS-compliant Isolated Storage in WinXP?

    - by lance
    I've read (but not tested) that Isolated Storage uses Sha1Managed, which is not FIPS-compliant? Is that accurate, and can anything be done to use Isolated Storage on a FIPS-compliant WinXP SP2 box? I've seen mention of "Isolated Storage" within both the ClickOnce and Silverlight spaces. I'd appreciate an informed answer regarding either (or both!).

    Read the article

  • Interface Builder can't see classes in a static library

    - by teabot
    I have refactored some UIView sub-classes into a static library. However, when using Interface Builder to create view components for a project that uses the static library I find that it is unaware of the library classes. What do I need to do to make the class interfaces visible to Interface Builder? Update: The correct answer refers to dragging the headers into the 'XIB browser'. The '.h' files can be dragged from a finder window to the window area identified in this image:

    Read the article

  • C#/WPF: Print a ListView

    - by Joseph Melettukunnel
    Does anyone have an idea how to Print (A4) the Content of a ListView (e.g. with all the ColumnHeaders, fit to the Page-Width and without the Scrollbar)? I've found several old threads about this on stackoverflow, but no complete answer. Thank you. Cheers

    Read the article

  • django error:The model Tribe is already registered

    - by zjm1126
    when i python manage.py syncdb,it show this: The following content types are stale and need to be deleted: maps | tribe Any objects related to these content types by a foreign key will also be deleted. Are you sure you want to delete these content types? If you're unsure, answer 'no'. Type 'yes' to continue, or 'no' to cancel: no when i put 'no' ,and then python manage runserver: AlreadyRegistered at / The model Tribe is already registered what should i do ? thanks

    Read the article

  • Dont understand Python Method

    - by user836087
    I dont understand what is going on in the move method. I am taking the AI course from Udacity.com. The video location is: http://www.udacity.com/view#Course/cs373/CourseRev/apr2012/Unit/512001/Nugget/480015 Below is the code I dont get, its not working as shown in the video .. The answer I should be getting according to Udacity is [0, 0, 1, 0, 0] Here is what I get [] p=[0, 1, 0, 0, 0] def move(p, U): q = [] for i in range(len(p)): q.append(p[(i-U) % len(p)]) return q print move(p, 1)

    Read the article

< Previous Page | 206 207 208 209 210 211 212 213 214 215 216 217  | Next Page >