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  • How do I ask screen to behave like a standard bash shell?

    - by thornomad
    Just learned about the screen command on linux - it is genius. I love it. However, the actual terminal/prompt in screen looks and behaves differently than my standard bash prompt. That is, the colors aren't the same, tab completion doesn't seem to work, etc. Is there a way I can tell screen to behave just like a normal (at least, normal as in what I am used to) bash prompt ?

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  • I am trying to deploy my first rails app using Capistrano and am getting an error.

    - by Andrew Bucknell
    My deployment of a rails app with capistrano is failing and I hoping someone can provide me with pointers to troubleshoot. The following is the command output andrew@melb-web:~/projects/rails/guestbook2$ cap deploy:setup * executing `deploy:setup' * executing "mkdir -p /var/www/dev/guestbook2 /var/www/dev/guestbook2/releases /var/www/dev/guestbook2/shared /var/www/dev/guestbook2/shared/system /var/www/dev/guestbook2/shared/log /var/www/dev/guestbook2/shared/pids && chmod g+w /var/www/dev/guestbook2 /var/www/dev/guestbook2/releases /var/www/dev/guestbook2/shared /var/www/dev/guestbook2/shared/system /var/www/dev/guestbook2/shared/log /var/www/dev/guestbook2/shared/pids" servers: ["dev.andrewbucknell.com"] Enter passphrase for /home/andrew/.ssh/id_dsa: Enter passphrase for /home/andrew/.ssh/id_dsa: [dev.andrewbucknell.com] executing command command finished andrew@melb-web:~/projects/rails/guestbook2$ cap deploy:check * executing `deploy:check' * executing "test -d /var/www/dev/guestbook2/releases" servers: ["dev.andrewbucknell.com"] Enter passphrase for /home/andrew/.ssh/id_dsa: [dev.andrewbucknell.com] executing command command finished * executing "test -w /var/www/dev/guestbook2" servers: ["dev.andrewbucknell.com"] [dev.andrewbucknell.com] executing command command finished * executing "test -w /var/www/dev/guestbook2/releases" servers: ["dev.andrewbucknell.com"] [dev.andrewbucknell.com] executing command command finished * executing "which git" servers: ["dev.andrewbucknell.com"] [dev.andrewbucknell.com] executing command command finished * executing "test -w /var/www/dev/guestbook2/shared" servers: ["dev.andrewbucknell.com"] [dev.andrewbucknell.com] executing command command finished You appear to have all necessary dependencies installed andrew@melb-web:~/projects/rails/guestbook2$ cap deploy:migrations * executing `deploy:migrations' * executing `deploy:update_code' updating the cached checkout on all servers executing locally: "git ls-remote [email protected]:/home/andrew/git/guestbook2.git master" Enter passphrase for key '/home/andrew/.ssh/id_dsa': * executing "if [ -d /var/www/dev/guestbook2/shared/cached-copy ]; then cd /var/www/dev/guestbook2/shared/cached-copy && git fetch origin && git reset --hard 369c5e04aaf83ad77efbfba0141001ac90915029 && git clean -d -x -f; else git clone [email protected]:/home/andrew/git/guestbook2.git /var/www/dev/guestbook2/shared/cached-copy && cd /var/www/dev/guestbook2/shared/cached-copy && git checkout -b deploy 369c5e04aaf83ad77efbfba0141001ac90915029; fi" servers: ["dev.andrewbucknell.com"] Enter passphrase for /home/andrew/.ssh/id_dsa: [dev.andrewbucknell.com] executing command ** [dev.andrewbucknell.com :: err] Permission denied, please try again. ** Permission denied, please try again. ** Permission denied (publickey,password). ** [dev.andrewbucknell.com :: err] fatal: The remote end hung up unexpectedly ** [dev.andrewbucknell.com :: out] Initialized empty Git repository in /var/www/dev/guestbook2/shared/cached-copy/.git/ command finished failed: "sh -c 'if [ -d /var/www/dev/guestbook2/shared/cached-copy ]; then cd /var/www/dev/guestbook2/shared/cached-copy && git fetch origin && git reset --hard 369c5e04aaf83ad77efbfba0141001ac90915029 && git clean -d -x -f; else git clone [email protected]:/home/andrew/git/guestbook2.git /var/www/dev/guestbook2/shared/cached-copy && cd /var/www/dev/guestbook2/shared/cached-copy && git checkout -b deploy 369c5e04aaf83ad77efbfba0141001ac90915029; fi'" on dev.andrewbucknell.com andrew@melb-web:~/projects/rails/guestbook2$ The following fragment is from cap -d deploy:migrations Preparing to execute command: "find /var/www/dev/guestbook2/releases/20100305124415/public/images /var/www/dev/guestbook2/releases/20100305124415/public/stylesheets /var/www/dev/guestbook2/releases/20100305124415/public/javascripts -exec touch -t 201003051244.22 {} ';'; true" Execute ([Yes], No, Abort) ? |y| yes * executing `deploy:migrate' * executing "ls -x /var/www/dev/guestbook2/releases" Preparing to execute command: "ls -x /var/www/dev/guestbook2/releases" Execute ([Yes], No, Abort) ? |y| yes /usr/lib/ruby/gems/1.8/gems/capistrano-2.5.17/lib/capistrano/recipes/deploy.rb:55:in `join': can't convert nil into String (TypeError) from /usr/lib/ruby/gems/1.8/gems/capistrano-2.5.17/lib/capistrano/recipes/deploy.rb:55:in `load'

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  • Page_load event firing twice. User control not properly loading

    - by Phil
    Here is the code I am using to pull my usercontrol (content.ascx): Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load 'load module If TheModule = "content" Then Dim control As UserControl = LoadControl("~\Modules\Content.ascx") Controls.Add(control) End If End Sub Within the usercontrol is the following code (data access taken care of by DAAB and ive replaced sql statements with 'sql'): Imports System.Data.SqlClient Imports System.Data Imports System.Web.Configuration Imports Microsoft.Practices.EnterpriseLibrary.Common Imports Microsoft.Practices.EnterpriseLibrary.Data Partial Class Modules_WebUserControl Inherits System.Web.UI.UserControl Dim db As Database = DatabaseFactory.CreateDatabase() Dim command As SqlCommand 'database Dim reader As IDataReader 'general vars Dim pageid As Integer Dim did As Integer Dim contentid As Integer Dim dotpos As String Dim ext As String Dim content As String Dim folder As String Dim downloadstring As String Function getimage(ByVal strin As String) As String If strin > "" Then dotpos = InStrRev(strin, ".") ext = Right(strin, Len(strin) - dotpos) getimage = ext & ".gif" Else getimage = String.Empty End If Return getimage End Function Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles MyBase.Load, Me.Load 'test Response.Write("(1 Test from within page_load)") 'get session vars folder = Session("folder") pageid = Session("pageid") did = Session("did") 'main content command = db.GetSqlStringCommand("sql") db.AddInParameter(command, "@pageid", DbType.Int32, pageid) reader = db.ExecuteReader(command) While reader.Read If reader("content") IsNot DBNull.Value Then content = Replace(reader("content"), Chr(38) + Chr(97) + Chr(109) + Chr(112) + Chr(59) + Chr(98) + Chr(104) + Chr(99) + Chr(112) + Chr(61) + Chr(49), "") If reader("id") IsNot DBNull.Value Then contentid = reader("id") End If Else contentid = -1 content = String.Empty End If End While Outputcontent.Text = content 'contacts info If did = 0 Then command = db.GetSqlStringCommand("sql") db.AddInParameter(command, "@contentid", DbType.Int32, contentid) reader = db.ExecuteReader(command) While reader.Read() Contactinforepeater.DataSource = reader Contactinforepeater.DataBind() End While End If If Not did = 0 Then command = (db.GetSqlStringCommand("sql") db.AddInParameter(command, "@contentid", DbType.Int32, contentid) db.AddInParameter(command, "@did", DbType.Int32, did) reader = db.ExecuteReader(command) While reader.Read Contactinforepeater.DataSource = reader Contactinforepeater.DataBind() End While End If 'downloads box command = db.GetSqlStringCommand("sql") db.AddInParameter(command, "@contentid", DbType.Int32, contentid) reader = db.ExecuteReader(command) While reader.Read If reader("filename") IsNot DBNull.Value Then downloadstring += "<a href='/documents/" & folder & "/" & reader("filename") & "'>" downloadstring += "<img src=images/" & getimage(reader("filename")) & " border=0 align=absmiddle />" End If If reader("filesize") IsNot DBNull.Value Then downloadstring += Convert.ToInt32((reader("filesize") / 1000)) & "kb - " End If If reader("filename") IsNot DBNull.Value Then downloadstring += "<a href='/documents/" & Session("folder") & "/" & reader("filename") & "'>" & reader("description") & "</a><br />" End If End While Dim downloadsarray As ArrayList downloadsarray = New ArrayList If downloadstring IsNot Nothing Then downloadsarray.Add(downloadstring) End If If downloadsarray.Count > 0 Then DownloadsRepeater.DataSource = downloadsarray DownloadsRepeater.DataBind() End If 'get links command = db.GetSqlStringCommand("sql") db.AddInParameter(command, "@contentid", DbType.Int32, contentid) reader = db.ExecuteReader(command) While reader.Read Linksrepeater.DataSource = reader Linksrepeater.DataBind() End While End Sub End Class Now instead of seeing my page content and what should be within the repeaters on the page all I get is 2 x the output of Response.Write("(1 Test from within page_load)") (1 Test from within page_load)(1 Test from within page_load) This leads me to believe the page_load is firing twice, but not properly displaying all the information. Please can one of you willing experts help me to get this working? Thanks a lot in advance

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  • Using MVVM, how to pass SelectedItems of a XamDataGrid as parameter to the Command raised by the Co

    - by saddaypally
    Hi, I'm trying to pass the item on XamDataGrid on which I do a mouse right click to open a ContextMenu, which raises a Command in my ViewModel. Somehow the method that the Command calls is not reachable in debug mode. This is the snipped from the view <ig:XamDataGrid DataSource="{Binding DrdResults}" Height="700" Width="600"> <ig:XamDataGrid.ContextMenu> <ContextMenu DataContext="{Binding RelativeSource={RelativeSource Mode=Self}, Path=PlacementTarget.DataContext}" AllowDrop="True" Name="cmAudit"> <MenuItem Header="View History" Command="{Binding ViewTradeHistory}" CommandParameter="{Binding Path=SelectedItems}"> </MenuItem> </ContextMenu> </ig:XamDataGrid.ContextMenu> <ig:XamDataGrid.FieldSettings> <ig:FieldSettings AllowFixing="NearOrFar" AllowEdit="False" Width="auto" Height="auto" /> </ig:XamDataGrid.FieldSettings> </ig:XamDataGrid> My code in the corresponding ViewModel for this View is as follows public WPF.ICommand ViewTradeHistory { get { if (_viewTradeHistory == null) { _viewTradeHistory = new DelegateCommand( (object SelectedItems) = { this.OpenTradeHistory(SelectedItems); }); } return _viewTradeHistory; } } And lastly the actual method that gets called by the Command is as below private void OpenTradeHistory(object records) { DataPresenterBase.SelectedItemHolder auditRecords = (DataPresenterBase.SelectedItemHolder)records; // Do something with the auditRecords now. } I'm not sure what am I doing incorrectly here. Any help will be very much appreciated. Thanks, Shravan

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  • VMWare workstation: from command line, how to start a VM in service mode (run in background)?

    - by GenEric35
    Hi, I have tried the vmrun and vmware.exe executables, but both of them start the vmware GUI when starting the VM. What I want to do is start the VM without starting the VMWare GUI. The reason I am doing this is after a few hours of idle, the guest OS becomes sluggish. It has lots of RAM but the only way I found to keep it's responsiveness optimal is to shutdown(dumps the memory) and the start; a restart of the guest OS doesnt dump the memory so I need to be able to do a stop of the VM, and then a start. So far the command I use are: C:\Program Files (x86)\VMware\VMware Workstationvmrun stop F:\VirtualMachines\R2\R2.vmx C:\Program Files (x86)\VMware\VMware Workstationvmrun start F:\VirtualMachines\R2\R2.vmx But the start command actually starts the VMWare Workstation GUI, which I don't need. I'm looking for a solution to start the VM without the VMWare Wokstation GUI, or a solution to what is causing the VM to become sluggish after a few hours of running idle.

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  • How do I use VS2010 One-Click Publish (MsDeploy) to deploy remotely from the command line?

    - by David
    On the remote web server I have installed the remote service http://x.x.x.x/MsDeployAgentService. If I use the Web Application Project's Publish command in VS2010 I can successfully publish to this remote web server and update a specific IIS website. What I want to do now is execute this capability from the command line. I am guessing it is two steps. First build the web application project using the relevant build configuration: msbuild "C:\MyApplication\MyWebApplication.csproj" /T:Package /P:Configuration=Release Then issue the MsDeploy command to have it publish/sync with the remove IIS server: msdeploy -verb:sync -source:package="C:\MyApplication\obj\Release\Package\MyWebApplication.zip" -dest:contentPath="My Production Website", computerName=http://x.x.x.x/MsDeployAgentService, username=adminuser,password=adminpassword Unfortunately I get an the error: Error: (10/05/2010 3:52:02 PM) An error occurred when the request was processed on the remote computer. Error: Source (sitemanifest) and destination (contentPath) are not compatible for the given operation. Error count: 1. I have tried a number of different combinations for destination provider but no joy :( Has anyone managed to replicate VS2010 Web Application Project "One Click" Publish from the command line?

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  • PHP throwing XDebug errors ONLY in command line mode...

    - by Wilhelm Murdoch
    Hey, all! I've been having a few problems running PHP-based utilities within the command line ever since I enabled the XDebug. It runs just fine when executing script through a browser, but once I try an execute a script on the command line, it throws the following errors: h:\www\test>@php test.php PHP Warning: PHP Startup: Unable to load dynamic library 'E:\development\xampplite\php\ext\php_curl.dll' - The specified module could not be found in Unknown on line 0 PHP Warning: Xdebug MUST be loaded as a Zend extension in Unknown on line 0 h:\www\test> The script runs just fine after this, but it's something I can't seem to wrap my head around. Could it be a path issue within my php.ini config? I'm not sure if that's the case considering it throws the same error no matter where I access the @php environmental variable. Also, all paths within my php.ini are absolute. Not really sure what's going on here. Any ideas? Thanks!

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  • Detecting upload success/failure in a scripted command-line SFTP session?

    - by Will Martin
    I am writing a BASH shell script to upload all the files in a directory to a remote server and then delete them. It'll run every few hours via a CRON job. My complete script is below. The basic problem is that the part that's supposed to figure out whether the file uploaded successfully or not doesn't work. The SFTP command's exit status is always "0" regardless of whether the upload actually succeeded or not. How can I figure out whether a file uploaded correctly or not so that I can know whether to delete it or let it be? #!/bin/bash # First, save the folder path containing the files. FILES=/home/bob/theses/* # Initialize a blank variable to hold messages. MESSAGES="" ERRORS="" # These are for notifications of file totals. COUNT=0 ERRORCOUNT=0 # Loop through the files. for f in $FILES do # Get the base filename BASE=`basename $f` # Build the SFTP command. Note space in folder name. CMD='cd "Destination Folder"\n' CMD="${CMD}put ${f}\nquit\n" # Execute it. echo -e $CMD | sftp -oIdentityFile /home/bob/.ssh/id_rsa [email protected] # On success, make a note, then delete the local copy of the file. if [ $? == "0" ]; then MESSAGES="${MESSAGES}\tNew file: ${BASE}\n" (( COUNT=$COUNT+1 )) # Next line commented out for ease of testing #rm $f fi # On failure, add an error message. if [ $? != "0" ]; then ERRORS="${ERRORS}\tFailed to upload file ${BASE}\n" (( ERRORCOUNT=$ERRORCOUNT+1 )) fi done SUBJECT="New Theses" BODY="There were ${COUNT} files and ${ERRORCOUNT} errors in the latest batch.\n\n" if [ "$MESSAGES" != "" ]; then BODY="${BODY}New files:\n\n${MESSAGES}\n\n" fi if [ "$ERRORS" != "" ]; then BODY="${BODY}Problem files:\n\n${ERRORS}" fi # Send a notification. echo -e $BODY | mail -s $SUBJECT [email protected] Due to some operational considerations that make my head hurt, I cannot use SCP. The remote server is using WinSSHD on windows, and does not have EXEC privileges, so any SCP commands fail with the message "Exec request failed on channel 0". The uploading therefore has to be done via the interactive SFTP command.

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  • Why does cd print when run in command substitution?

    - by reasgt
    If I use the 'cd' BASH built-in in a command substitution, it prints extra stuff to stdout, but only when piped to, eg., less. $ echo `cd .` # The output is a single newline, appended by echo. $ echo `cd .` | less # less displays: ESC]2;my.hostname.com - tmp/testenv^G (END) What's going on there? This behavior isn't documented in the bash man page for cd. Obviously, running just 'cd' in a command substitution is silly, but something like NEWDIR=`cd mypath; pwd` could be useful. I solved this by instead using NEWVAR=`cd mypath > /dev/null 2>&1; pwd` but I still want to know what's going on. Bash Version: GNU bash, version 3.2.25(1)-release (x86_64-redhat-linux-gnu) Copyright (C) 2005 Free Software Foundation, Inc. Distro: Scientific Linux SL release 5.5 (Boron)

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  • How to analyze CBS.log file by SFC command to detect corrupt files in Windows 7?

    - by energydream2007
    Hey I have some problems with my Win7 so I've ran sfc /scannow and I got this message: "Windows Resource Protection found corrupt files and was unable to fix some of them..." I also told to look at the folder of the log file to find the cbs.log. After that I've ran this command to pull out the actual problems/corrupt files: findstr /c:"[SR]" %windir%\Logs\CBS\CBS.log >"%userprofile%\Desktop\sfcdetails.txt" This command have created an sfcdetails text file (download). Can someone help me to analyze this file? I haven't found a detailed article about it so far.

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  • How do you add a certificate for WLAN in Linux, at the command-line?

    - by Neil
    I'm using Maemo on a Nokia n810 Internet tablet, and when given a list of installed certificates to choose from when connecting to a PEAP wireless network, it's always blank. I've already installed a couple of certificates through the gui on the device, and only the certificate authorities show up. I've confirmed that Maemo's connection software that handles certificates is buggy, in such a way that certificates are never added, or properly added certificates cannot be found. Is there a way to add WLAN certificates at the command-line, and connect to a wireless network at the command-line as well? I used to use iwconfig to connect, but I never used it with PEAP. Note: I have nothing in /etc/ssl/certs

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  • How to reset mac PRAM through the command line in Lion/Mountain Lion?

    - by boneyjellyfish
    I'm trying to write a script to automate a PRAM reset and I've seen a lot of old guides that tell me to use the following command to reset the Mac's PRAM via the terminal: nvram boot-args="-p -r" But this command doesn't seem to work anymore, at least not on any of the computers I've tried it on. I'm trying to find a more up-to-date list of available boot-args and I was able to find this question about boot-args strings but there doesn't seem to be anything in there or any of the links about resetting the pram. Any ideas?

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  • jruby rubygems update breaks jgem

    - by brad
    Has anyone seen this: ?? No jgem command works at all?? Though jruby -S gem list does work. I'm using jruby 1.3.1 and Sun Java6 jre root@test:/usr/local: jgem --version 1.3.3 root@test:/usr/local: jgem update --system JRuby limited openssl loaded. gem install jruby-openssl for full support. http://wiki.jruby.org/wiki/JRuby_Builtin_OpenSSL Updating RubyGems Updating rubygems-update Successfully installed rubygems-update-1.3.6 /usr/local/jruby/lib/ruby/site_ruby/1.8/rubygems/commands/update_command.rb:103:Warning: Gem::SourceIndex#search support for String patterns is deprecated Updating RubyGems to 1.3.6 Installing RubyGems 1.3.6 RubyGems 1.3.6 installed root@test:/usr/local: jgem list /usr/local/jruby/bin/jgem: line 8: require: command not found /usr/local/jruby/bin/jgem: line 9: require: command not found /usr/local/jruby/bin/jgem: line 10: require: command not found /usr/local/jruby/bin/jgem: line 12: required_version: command not found /usr/local/jruby/bin/jgem: line 14: unless: command not found /usr/local/jruby/bin/jgem: line 15: abort: command not found /usr/local/jruby/bin/jgem: line 16: end: command not found /usr/local/jruby/bin/jgem: line 18: args: command not found /usr/local/jruby/bin/jgem: line 20: begin: command not found /usr/local/jruby/bin/jgem: line 21: Gem::GemRunner.new.run: command not found /usr/local/jruby/bin/jgem: line 22: rescue: command not found /usr/local/jruby/bin/jgem: line 23: exit: e.exit_code: numeric argument required

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  • How would I modify this ffmpeg command to include 4 videos?

    - by Michael Shnitzer
    Say I had 4 videos with the following names: Main Video.mov Top Left.mov Top Right.mov Top Mid.mov and I wanted to have "Main Video" play with a picture in picture effect with boxes of videos playing in the top left, top right and top mid. Each box would have the video that is similarly named. This command will do picture in picture for 2 videos, with one video in the lower right. ffmpeg -i 2013-07-31\ 231548.MOV -vf "movie=2013-07-31\ 231722.MOV, scale=iw/5:ih/5 [small]; [in][small] overlay=main_w*0.77:main_h*0.77 [out]" -strict -2 output.mov Can someone help me update this command to work with the 4 files I mentioned above? Thanks

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  • What would you like to correct and/or improve in this java implementation of Chain Of Responsibility

    - by Maciek Kreft
    package design.pattern.behavioral; import design.pattern.behavioral.ChainOfResponsibility.*; public class ChainOfResponsibility { public static class Chain { private Request[] requests = null; private Handler[] handlers = null; public Chain(Handler[] handlers, Request[] requests){ this.handlers = handlers; this.requests = requests; } public void start() { for(Request r : requests) for (Handler h : handlers) if(h.handle(r)) break; } } public static class Request { private int value; public Request setValue(int value){ this.value = value; return this; } public int getValue() { return value; } } public static class Handler<T1> { private Lambda<T1> lambda = null; private Lambda<T1> command = null; public Handler(Lambda<T1> condition, Lambda<T1> command) { this.lambda = condition; this.command = command; } public boolean handle(T1 request) { if (lambda.lambda(request)) command.lambda(request); return lambda.lambda(request); } } public static abstract class Lambda<T1>{ public abstract Boolean lambda(T1 request); } } class TestChainOfResponsibility { public static void main(String[] args) { new TestChainOfResponsibility().test(); } private void test() { new Chain(new Handler[]{ // chain of responsibility new Handler<Request>( new Lambda<Request>(){ // command public Boolean lambda(Request condition) { return condition.getValue() >= 600; } }, new Lambda<Request>(){ public Boolean lambda(Request command) { System.out.println("You are rich: " + command.getValue() + " (id: " + command.hashCode() + ")"); return true; } } ), new Handler<Request>( new Lambda<Request>(){ public Boolean lambda(Request condition) { return condition.getValue() >= 100; } }, new Lambda<Request>(){ public Boolean lambda(Request command) { System.out.println("You are poor: " + command.getValue() + " (id: " + command.hashCode() + ")"); return true; } } ), }, new Request[]{ new Request().setValue(600), // chaining method new Request().setValue(100), } ).start(); } }

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  • How do you add a certificate for WLAN in Linux, at the command-line?

    - by Neil
    I'm using Maemo on a Nokia n810 Internet tablet, and when given a list of installed certificates to choose from when connecting to a PEAP wireless network, it's always blank. I've already installed a couple of certificates through the gui on the device, and only the certificate authorities show up. I've confirmed that Maemo's connection software that handles certificates is buggy, in such a way that certificates are never added, or properly added certificates cannot be found. Is there a way to add WLAN certificates at the command-line, and connect to a wireless network at the command-line as well? I used to use iwconfig to connect, but I never used it with PEAP. Note: I have nothing in /etc/ssl/certs

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  • How do I associate Parameters to Command objects in ADO with VBScript?

    - by Krashman5k
    I have been working an ADO VBScript that needs to accept parameters and incorporate those parameters in the Query string that gets passed the the database. I keep getting errors when the Record Set Object attempts to open. If I pass a query without parameters, the recordset opens and I can work with the data. When I run the script through a debugger, the command object does not show a value for the parameter object. It seems to me that I am missing something that associates the Command object and Parameter object, but I do not know what. Here is a bit of the VBScript Code: ... 'Open Text file to collect SQL query string' Set fso = CreateObject("Scripting.FileSystemObject") fileName = "C:\SQLFUN\Limits_ADO.sql" Set tso = fso.OpenTextFile(fileName, FORREADING) SQL = tso.ReadAll 'Create ADO instance' connString = "DRIVER={SQL Server};SERVER=myserver;UID=MyName;PWD=notapassword; Database=favoriteDB" Set connection = CreateObject("ADODB.Connection") Set cmd = CreateObject("ADODB.Command") connection.Open connString cmd.ActiveConnection = connection cmd.CommandText = SQL cmd.CommandType = adCmdText Set paramTotals = cmd.CreateParameter With paramTotals .value = "tot%" .Name = "Param1" End With 'The error occurs on the next line' Set recordset = cmd.Execute If recordset.EOF then WScript.Echo "No Data Returned" Else Do Until recordset.EOF WScript.Echo recordset.Fields.Item(0) ' & vbTab & recordset.Fields.Item(1) recordset.MoveNext Loop End If The SQL string that I use is fairly standard except I want to pass a parameter to it. It is something like this: SELECT column1 FROM table1 WHERE column1 IS LIKE ? I understand that ADO should replace the "?" with the parameter value I assign in the script. The problem I am seeing is that the Parameter object shows the correct value, but the command object's parameter field is null according to my debugger.

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  • How can I make pref changes via defaults command happen immediately?

    - by user329863
    There are many changes to Finder, Dock, etc. preferences that you can do with the defaults command, i.e. defaults write com.apple.finder AppleShowAllFiles -bool yes However, in order to make the changes take effect, you must quit and relaunch the target app: osascript -e 'tell app "Finder" to quit' When the Finder is quit like this (rather than using the killall command, as some published sources advise), it saves and restores its window placements and disk locations (but not the forward-and-back history associated with each window). Is there some way to make such changes take effect immediately, without quitting the target app? After all, when you make changes in the Dock preference panel, they take effect instantly in the Dock application. Is there some Apple Event that I can send to make the change or make the app reread its prefs?

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  • Running a command or script in terminal from anywhere by adding it to the PATH, what am I doing wrong?

    - by Joe
    On osx/linux I want to be able to run a command/script on the terminal from anywhere which links to a program. ie I want to be able to run: alloy that runs: /usr/local/share/npm/lib/node_modules/alloy/bin/alloy I'm guessing adding to .bashrc is the best way? I've tried running: export PATH="$PATH:/usr/local/share/npm/lib/node_modules/alloy/bin" and also: export PATH="$PATH:/usr/local/share/npm/lib/node_modules/alloy/bin/alloy" Then I started a new terminal window but the alloy command doesnt work. Am I missing something?

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  • 7zip: Add files to new folder in archive via command line?

    - by cschol
    I am using 7zip for compressing a bunch of files. The files are in a directory structure, like this: MyDir\File1 MyDir\File2 MyDir\File3 MyDir\MoreFiles\File4 MyDir\MoreFiles\File5 I want to create a 7z file with the following structure via command line: ZippedDir\File1 ZippedDir\File2 ZippedDir\File3 ZippedDir\MoreFiles\File4 ZippedDir\MoreFiles\File5 Basically, I want to zip the content of MyDir\ into a new folder called ZippedDir\. I know I could copy the content into a directory called ZippedDir\ and then zip this new directory. However, I was wondering if there was a way to avoid this extra copy step and directly zip the content, if possible, via command line.

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  • Option and command keys in OSX are swapped and keyboard preferences do not set them back.

    - by bikesandcode
    On my MacBook pro, I occasionally use external keyboards, generally Windows ones and things have been fine. Yesterday, I plugged in a new one, remapped the command/option keys so the windows/alt keys were in the same configuration, again, nothing new here. However, this time when I unplugged the USB keyboard, the laptops option/command keys remained switched. More annoying is that if I go into the System Preferences - Keyboards - Modifier keys, remapping the keys to actions does not work. I can use the drop downs to disable any specific keys, but switching the behaviours does nothing. (Cmd/Option obvious, tried remapping anything to caps lock and a few other combinations, no joy. Restore defaults set the configuration to what I'd expect, but the settings are evidently ignored.) So: Any ideas?

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  • How to monitor a folder for changes, and execute a command if it does, on Windows?

    - by Camilo Martin
    There are similar questions for Linux and Mac, but I'm after a Windows solution here. The problem is as follows: I want to write several (js) script files in a folder, and have a program monitor that folder for file changes and new files being added, and run a command whenever that happens (to compile them all into one single file). The solution has to: Monitor both file changes and new files being added, in a folder. Run a command only if there is any change. It would be best if it either is a built-in solution (like a JScript or VBscript snippet), or something that does not require installation.

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  • VIM: How do you get the last ex command you used?

    - by TrevorBoydSmith
    I find that sometimes I write a really long ex mode command that do lots of stuff. They are sort of "mini-scripts" that I write in the text editor then I start ex mode and copy them into the ex line and execute. But then I always end up editing in the ex mode and then I find it difficult to get the changes i did in ex mode back to my text editing session. Using the keyboard, how do you copy the last ex command you used and paste it into your text editor? (Note: This is sort of the opposite of this question "how do I copy/paste in vim ex mode" where the user asks "how do you copy from the text editor and paste INTO the ex mode?". My question is the opposite because I wish to copy from the ex mode and paste into my text editor.)

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