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  • Automatically creating volume partitions on boot

    - by Justin Meltzer
    I followed this guide: http://www.mongodb.org/display/DOCS/Amazon+EC2+Quickstart to set up Mongodb. It had me create a RAID 10 array out of the four devices on EBS. Then it had me create a physical volume, a volume group, and three logical volumes out of that RAID 10 array. Lastly it had me create ext4 filesystems out of the logical volumes and mount them. Now the quickstart guide had me put two things in place so that these steps would be replicated on reboot of the system. It had me add some instructions to the mdadm.conf file to automatically create the RAID 10 array, and it also had me add instructions to the fstab file to automatically mount the filesystem for each logical volume. However, the quickstart guide does not have anything for automatically creating the logical volumes from the RAID 10 array. I checked my system and see that each of the four devices are part of a RAID array: $ sudo mdadm -Q /dev/sdh1 /dev/sdh1: is not an md array /dev/sdh1: device 0 in 4 device unknown raid10 array. Use mdadm --examine for more detail. However, the filesystem is never created or mounted from fstab because it's trying to mount it from logical volumes that were never created (or so it seems). My question is, how can I automatically accomplish all the steps from the quickstart guide on a reboot of the system, and what config file do I need to add data to so that I can automatically create these volume partions after the RAID 10 is created but before the filesystem is mounted. Also I'm unsure whether fstab actually creates and mounts the filesystem or just mounts the filesystem.

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  • Logging communication between two VMs

    - by sYnfo
    Hi, I'm trying to set up "malware lab" described in this paper. So far, I've set up Windows guest system, adding one Host-only Network adapter, and setting this (sorry if the names aren't exactely correct, I don't have an english language version): - IP Address - 10.0.0.3 - Subnet mask - 255.255.255.0 - Default gateway - not set - Preferred DNS - 10.0.0.4 - Alternate DNS - not set And a Linux guest system - Ubuntu 9.04 - with two Network adapters - Bridged (eth0) and Host-only (eth1), and setting eth1 IP Address to 10.0.0.4, leaving the eth0 to be set by DHCP. Then, I have configured iptables as described in the paper, ie.: iptables -F -t nat iptables -F -t mangle iptables -t mangle -P PREROUTING ACCEPT iptables -t mangle -P OUTPUT ACCEPT iptables -t nat -P PREROUTING ACCEPT iptables -t nat -P POSTROUTING ACCEPT iptables -t nat -P OUTPUT ACCEPT iptables -t mangle -A PREROUTING -i eth0 -j ACCEPT iptables -t mangle -A PREROUTING -p udp -i eth1 -d 10.0.0.3 --dport 53 -j ACCEPT iptables -t mangle -A PREROUTING -p tcp -i eth1 --dport 80 -j ACCEPT iptables -t mangle -A PREROUTING -p tcp -i eth1 -d 10.0.0.3 --dport 6000:7000 -j ACCEPT iptables -t mangle -A PREROUTING -i eth1 -j ULOG iptables -t mangle -A PREROUTING -i eth1 -j DROP Now, when I try to ping the windows system from within the Linux system, it does not reply, I guess thats perfectly normal, because iptables is blocking ping responce. Same when I try to ping the Linux system from within the Windows. But when I try to access any web page from within the Windows system, I would expect that this action should get logged by iptables. But thing is, I don't see any of that kind of lines in log file (If I am looking in the right place, that is. :) It is at /var/log/messages, isn't it?). So, what do you think might be the problem here? I should note, that this is the first time I'm using linux, so don't expect ANY working knowledge of Linux at all... :) Also, since english is not my mother tongue, feel free to point out any gramatical mistakes... :) Thanks for any advice.

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  • Make user uploads go to different hard drive?

    - by Andrew Fashion
    I am using a pre-made social networking script where all user uploads go to site.com/public/user/ How can I make /public/user/ my secondary hard drive so all user uploads are uploaded to my second harddrive and not the primary hard drive. I have over 100GB of images, and I want them on my other HDD now. Thank you. I am running CentOS 5.5 64bit w/ Apache and PHP I have two 250GB Sata HDDs sudo parted /dev/sda print Model: ATA WDC WD2500KS-00M (scsi) Disk /dev/sda: 250GB Sector size (logical/physical): 512B/512B Partition Table: msdos Number Start End Size Type File system Flags 1 32.3kB 107MB 107MB primary ext3 boot 2 107MB 8595MB 8488MB primary linux-swap 3 8595MB 10.7GB 2147MB primary ext3 4 10.7GB 250GB 239GB extended 5 10.7GB 250GB 239GB logical ext3 Information: Don't forget to update /etc/fstab, if necessary. 5 10.7GB 250GB 239GB logical ext3

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  • Tail and wildcard characters

    - by Mitch
    I want to get the last 10 lines of multiple files. I know they all end with "-access_log". So I tried: tail -10 *-access_log But this gives me an error, where as: tail -10 file-* Gives me the output I'd expect. I would think this probably has more to do with BASH then tail. However commands like: cat *-access_log Work fine. Any suggestions?

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  • VBA: Parse preceding numbers from string

    - by buttonsrtoys
    I need to parse into two substrings a string that always starts with numeric text followed by alphnumeric text. The strings can vary a bit, but not too much. Below are examples of incoming format and the strings I need: "00 10 50 Information to Bidders" ==> "00 10 50", "Information to Bidders" "001050 Information to Bidders" ==> "001050", "Information to Bidders" "00 10 50 - Information to Bidders" ==> "00 10 50", "Information to Bidders" "001050 -- Information to Bidders" ==> "001050", "Information to Bidders" I was hoping it would only be a half dozen lines of VBA, but my code is turning into a loop where I'm testing every character in the string to see where the changeover from numeric-only to non-numeric, then parsing the string based on the changeover location. Not a big deal, but messier than I was hoping for. Are there VBA functions that would eliminate the need to iterate through each string character?

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  • EXCEL function working like SQL group by + count(distinct *)?

    - by Solo
    Suppose I have an EXCEL sheet with below data CODE (COL A) | VALUE (COL B) ============================== A01 | 10 A01 | 20 A01 | 30 A01 | 10 B01 | 30 B01 | 30 Is there an EXCEL function working like .. SELECT CODE, count (Distinct *) FROM TABLE GROUP BY CODE CODE | Distinct Count of Value =================================== A01 | 3 B01 | 1 or, better yet, Can we have an excel formula pasted in Column C to get something like this: CODE (COL A) | VALUE (COL B) | DISTINCT VALUE COUNT WITH MATCHING CODE (COL C) =============================================================================== A01 | 10 | 3 A01 | 20 | 3 A01 | 30 | 3 A01 | 10 | 3 B01 | 30 | 1 B01 | 30 | 1 I know I can use pivot table to get this result easily. However due to reporting requirements I have to append the "distinct count" column to the excel sheet, hence pivot table is not an option. My last resort is to use Excel Macro (Which is fine), but before that I would like to learn whether excel functions can accomplish this kind of task. Many thanks!

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  • OpenVPN and Squid Setup troubleshooting

    - by Adam
    I am trying to setup squid to tunnel via openvpn so that I can just enter an Ip and port in my browser settings and use it as a US proxy. My server is a OpenVZ VM. Running into some issues: I setup openvpn using : http://safesrv.net/install-openvpn-on-centos/ as part of that guide I also ran: iptables -t nat -A POSTROUTING -o venet0 -j SNAT --to-source iptables -t nat -A POSTROUTING -s 10.8.0.0/24 -j SNAT --to-source Installed squid using this guide: http://www.server-world.info/en/note?os=CentOS_6&p=squid from that guide changed acl lan src 10.0.0.0/24 to acl lan src 10.8.0.0/24 Next, I went to my browser proxy settings and put - 10.8.0.1 in the HTTP field. Put the port I had setup in the squid config file and tried to load a page. Nothing connecting. Any help? What am I doing wrong?

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  • Why are Full GCs not running on my gcInterval I set?

    - by Brad Wood
    ColdFusion 10 Update 10 Windows Server 2008 R2 Java 1.7.0_21 I am trying to figure Full GCs to run every 10 minutes. I have used the gcInterval JVM arg in the past on earlier versions of ColdFusion with success, but I have confirmed with verbose GC logs that Full GCs are still happening on the hour (Unless the Old Gen gets so full that it forces a full collection). Here are the full JVM args from ColdFusion10\cfusion\bin\jvm.config (line breaks added for readability) Is there something else I need to be doing to get this working on ColdFusion 10? java.args= -server -Xms4072m -Xmx4072m -XX:PermSize=512m -XX:MaxPermSize=512m -Dsun.rmi.dgc.client.gcInterval=600000 -Dsun.rmi.dgc.server.gcInterval=600000 -XX:+UseParallelGC -XX:+UseParallelOldGC -Xloggc:gc.log -verbose:gc -XX:+PrintGCDetails -XX:+PrintGCDateStamps -XX:+PrintGCTimeStamps -XX:+UseGCLogFileRotation -XX:NumberOfGCLogFiles=5 -XX:GCLogFileSize=1024K -Xbatch -Dcoldfusion.home={application.home} -Dcoldfusion.rootDir={application.home} -Dcoldfusion.libPath={application.home}/lib -Dorg.apache.coyote.USE_CUSTOM_STATUS_MSG_IN_HEADER=true -Dcoldfusion.jsafe.defaultalgo=FIPS186Random -Dcoldfusion.classPath={application.home}/lib/updates,{application.home}/lib,{application.home}/lib/axis2,{application.home}/gateway/lib/,{application.home}/wwwroot/WEB-INF/flex/jars,{application.home}/wwwroot/WEB-INF/cfform/jars

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  • Mysql InnoDB and quickly applying large updates

    - by Tim
    Basically my problem is that I have a large table of about 17,000,000 products that I need to apply a bunch of updates to really quickly. The table has 30 columns with the id set as int(10) AUTO_INCREMENT. I have another table which all of the updates for this table are stored in, these updates have to be pre-calculated as they take a couple of days to calculate. This table is in the format of [ product_id int(10), update_value int(10) ]. The strategy I'm taking to issue these 17 million updates quickly is to load all of these updates into memory in a ruby script and group them in a hash of arrays so that each update_value is a key and each array is a list of sorted product_id's. { 150: => [1,2,3,4,5,6], 160: => [7,8,9,10] } Updates are then issued in the format of UPDATE product SET update_value = 150 WHERE product_id IN (1,2,3,4,5,6); UPDATE product SET update_value = 160 WHERE product_id IN (7,8,9,10); I'm pretty sure I'm doing this correctly in the sense that issuing the updates on sorted batches of product_id's should be the optimal way to do it with mysql / innodb. I'm hitting a weird issue though where when I was testing with updating ~13 million records, this only took around 45 minutes. Now I'm testing with more data, ~17 million records and the updates are taking closer to 120 minutes. I would have expected some sort of speed decrease here but not to the degree that I'm seeing. Any advice on how I can speed this up or what could be slowing me down with this larger record set? As far as server specs go they're pretty good, heaps of memory / cpu, the whole DB should fit into memory with plenty of room to grow.

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  • Routing between same network

    - by user1389735
    Hi In this scenario there is point -to point serial connection between R6 and R7 , there is router R10 whose interface F0/0 is having ip address of 10.1.1.2/24 and there is a host machine (R9) with ip address 10.1.1.1/24 which is running an application, My problem is that Application on R9 will only work when it will get its Gateway as 10.1.1.1/24 which is of router (R10) , is there any way i can make R6 and R7 transparent for R9 and R10, Or any type of routing using GRE / Route-map or any other way. Thanks in advace

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  • Why mysql 5.5 slower than 5.1 (linux,using mysqlslap)

    - by Zenofo
    my.cnf (5.5 and 5.1 is the same) : back_log=200 max_connections=512 max_connect_errors=999999 key_buffer=512M max_allowed_packet=8M table_cache=512 sort_buffer=8M read_buffer_size=8M thread_cache=8 thread_concurrency=4 myisam_sort_buffer_size=128M interactive_timeout=28800 wait_timeout=7200 mysql 5.5: ..mysql5.5/bin/mysqlslap -a --concurrency=10 --number-of-queries 5000 --iterations=5 -S /tmp/mysql_5.5.sock --engine=innodb Benchmark Running for engine innodb Average number of seconds to run all queries: 15.156 seconds Minimum number of seconds to run all queries: 15.031 seconds Maximum number of seconds to run all queries: 15.296 seconds Number of clients running queries: 10 Average number of queries per client: 500 mysql5.1: ..mysql5.5/bin/mysqlslap -a --concurrency=10 --number-of-queries 5000 --iterations=5 -S /tmp/mysql_5.1.sock --engine=innodb Benchmark Running for engine innodb Average number of seconds to run all queries: 13.252 seconds Minimum number of seconds to run all queries: 13.019 seconds Maximum number of seconds to run all queries: 13.480 seconds Number of clients running queries: 10 Average number of queries per client: 500 Why mysql 5.5 slower than 5.1 ? BTW:I'm tried mysql5.5/bin/mysqlslap and mysql5.1/bin/mysqlslap,result is the same

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  • Why does my ping command (Windows) results alternate between "timeout" and "network is not reachable"?

    - by Sopalajo de Arrierez
    My Windows is in Spanish, so I will have to paste console outputs in that language (I think that translating without knowing the exact terms used in english versions could give worse results than leaving it as it appears on screen). This is the issue: when pinging a non-existent IP from a WinXP-SP3 machine (clean Windows install, just formatted), I get sometimes a "Timeout" result, and sometimes a "network is not reachable" message. This is the result of: ping 192.168.210.1 Haciendo ping a 192.168.210.1 con 32 bytes de datos: Tiempo de espera agotado para esta solicitud. Respuesta desde 80.58.67.86: Red de destino inaccesible. Respuesta desde 80.58.67.86: Red de destino inaccesible. Tiempo de espera agotado para esta solicitud. Estadísticas de ping para 192.168.210.1: Paquetes: enviados = 4, recibidos = 2, perdidos = 2 (50% perdidos), Tiempos aproximados de ida y vuelta en milisegundos: Mínimo = 0ms, Máximo = 0ms, Media = 0ms 192.168.210.1 does not exist on the network. DHCP client is enabled, and the computer gets assigned those network config by the router. My IP: 192.168.11.2 Netmask: 255.255.255.0 Gateway: 192.168.11.1 DNS: 80.58.0.33/194.224.52.36 This is the output from "route print command": =========================================================================== Rutas activas: Destino de red Máscara de red Puerta de acceso Interfaz Métrica 0.0.0.0 0.0.0.0 192.168.11.1 192.168.11.2 20 127.0.0.0 255.0.0.0 127.0.0.1 127.0.0.1 1 192.168.11.0 255.255.255.0 192.168.11.2 192.168.11.2 20 192.168.11.2 255.255.255.255 127.0.0.1 127.0.0.1 20 192.168.11.255 255.255.255.255 192.168.11.2 192.168.11.2 20 224.0.0.0 240.0.0.0 192.168.11.2 192.168.11.2 20 255.255.255.255 255.255.255.255 192.168.11.2 192.168.11.2 1 255.255.255.255 255.255.255.255 192.168.11.2 3 1 Puerta de enlace predeterminada: 192.168.11.1 =========================================================================== Rutas persistentes: ninguno The output of: ping 1.1.1.1 Haciendo ping a 1.1.1.1 con 32 bytes de datos: Tiempo de espera agotado para esta solicitud. Tiempo de espera agotado para esta solicitud. Tiempo de espera agotado para esta solicitud. Tiempo de espera agotado para esta solicitud. Estadísticas de ping para 1.1.1.1: Paquetes: enviados = 4, recibidos = 0, perdidos = 4 1.1.1.1 does not exist on the network. and the output of: ping 10.1.1.1 Haciendo ping a 10.1.1.1 con 32 bytes de datos: Respuesta desde 80.58.67.86: Red de destino inaccesible. Tiempo de espera agotado para esta solicitud. Tiempo de espera agotado para esta solicitud. Respuesta desde 80.58.67.86: Red de destino inaccesible. Estadísticas de ping para 10.1.1.1: Paquetes: enviados = 4, recibidos = 2, perdidos = 2 (50% perdidos), 10.1.1.1 does not exist on the network. I can do some aproximate translation of what you demand if necessary. I have another computers in the same network (WinXP-SP3 and Win7-SP1), and they have, too, this problem. Gateway (Router): Buffalo WHR-HP-GN (official Buffalo firmware, not DD-WRT). I have some Linux (Debian/Kali) machine in my network, so I tested things on it: ping 192.168.210.1 PING 192.168.210.1 (192.168.210.1) 56(84) bytes of data. From 80.58.67.86 icmp_seq=1 Packet filtered From 80.58.67.86 icmp_seq=2 Packet filtered From 80.58.67.86 icmp_seq=3 Packet filtered From 80.58.67.86 icmp_seq=4 Packet filtered to the non-existing 1.1.1.1 : ping 1.1.1.1 PING 1.1.1.1 (1.1.1.1) 56(84) bytes of data. ^C --- 1.1.1.1 ping statistics --- 153 packets transmitted, 0 received, 100% packet loss, time 153215ms (no response after waiting a few minutes). and the non-existing 10.1.1.1: ping 10.1.1.1 PING 10.1.1.1 (10.1.1.1) 56(84) bytes of data. From 80.58.67.86 icmp_seq=20 Packet filtered From 80.58.67.86 icmp_seq=22 Packet filtered From 80.58.67.86 icmp_seq=23 Packet filtered From 80.58.67.86 icmp_seq=24 Packet filtered From 80.58.67.86 icmp_seq=25 Packet filtered What is going on here? I am posing this question mainly for learning purposes, but there is another reason: when all pings are returning "timeout", it creates an %ERRORLEVEL% value of 1, but if there is someone of "Network is not reachable" type, %ERRORLEVEL% goes to 0 (no error), and this could be inappropriate for a shell script (we can not use ping to detect, for example, if the network is down due to loss of contact with the gateway).

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  • Anonymizing OpenVPN Allow SSH Access to Internal Server

    - by Lionel
    I'm using an anonymizing VPN, but want SSH access to internal computer. How do I access my internal computer through SSH? When I do ssh 98.123.45.6, the connection times out. IP address from cable provider: 98.123.45.6 Anonymous IP through VPN: 50.1.2.3 Internal computer: 192.168.1.123 When searching around, I found recommendations to either set up iptables rules, routing rules, or to add ListenAddress to sshd_config. Which of these applies to my case? Here is my route: Kernel IP routing table Destination Gateway Genmask Flags Metric Ref Use Iface 10.115.81.1 10.115.81.9 255.255.255.255 UGH 0 0 0 tun0 10.115.81.9 * 255.255.255.255 UH 0 0 0 tun0 50.1.2.3-sta ddwrt 255.255.255.255 UGH 0 0 0 eth0 192.168.1.0 * 255.255.255.0 U 202 0 0 eth0 169.254.0.0 * 255.255.0.0 U 204 0 0 vboxnet0 loopback * 255.0.0.0 U 0 0 0 lo default 10.115.81.9 128.0.0.0 UG 0 0 0 tun0 128.0.0.0 10.115.81.9 128.0.0.0 UG 0 0 0 tun0 default ddwrt 0.0.0.0 UG 202 0 0 eth0

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  • FFmpeg add multiple audio files to video at specific points

    - by Arran
    I have two audio files, each about 3 minutes long. I want to take the first 10 seconds of each file and add them each to a video file at specific points - 0 seconds and 10 seconds. So the resulting video should be 20 seconds long. I've got this far: ffmpeg -i video.mov -ss 0 -t 20 -itsoffset 0 -i audio1.mp3 -itsoffset 10 -i audio2.mp3 -acodec copy -vcodec copy out.mov ...but the resulting video has 20 seconds of the first audio file only, the second audio file doesn't start at 10 seconds like it should. Any help would be appreciated, thanks!

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  • AuthSub token from Google/YouTube API is always returned as invalid

    - by Miriam Raphael Roberts
    Anyone out there have experience with the YouTube/Google API? I am trying to login to Google/Youtube using clientLogin, retrieve an AuthSub token, exchange it for a multi-session token and then use it in our upload form. Just a note that we are not going to have other users logging into our (secure) website, this is for our use only (no multi-users). We just want a way to upload videos to our YT account via our own website without having to login/upload to YouTube. Ultimately, everything is dependent on the first step. My AuthSub token is always being returned as invalid (Error '403'). All the steps I used are below with username/password changed. Anyone have an insight on why my AuthSub is always invalid? I am spending an enormous amount of time trying to get this to work. STEP 1: Getting the authsub token from Youtube/Google POST /youtube/accounts/ClientLogin HTTP/1.1 User-Agent: curl/7.10.6 (i386-redhat-linux-gnu) libcurl/7.10.6 OpenSSL/0.9.7a ipv6 zlib/1.1.4 Host: www.google.com Pragma: no-cache Accept: image/gif, image/x-xbitmap, image/jpeg, image/pjpeg, */* Content-Type:application/x-www-form-urlencoded Content-Length: 86 Email=MyGoogleUsername&Passwd=MyGooglePasswd&accountType=GOOGLE&service=youtube&source=Test RESPONSE RECEIVED: Auth=AIwbFAR99f3iACfkT-5PXCB-1tN4vlyP_1CiNZ8JOn6P-......yv4d4zeGRemNm4il1e-M6czgfDXAR0w9fQ YouTubeUser=MyYouTubeUsername CURL COMMAND USED: /usr/bin/curl -S -v --location https://www.google.com/youtube/accounts/ClientLogin --data Email=MyGoogleUsername&Passwd=MyGooglePasswd&accountType=GOOGLE&service=youtube&source=Test --header Content-Type:application/x-www-form-urlencoded STEP 2: Exchanging the AuthSub token for a multi-use token GET /accounts/AuthSubSessionToken HTTP/1.1 User-Agent: curl/7.10.6 (i386-redhat-linux-gnu) libcurl/7.10.6 OpenSSL/0.9.7a ipv6 zlib/1.1.4 Host: www.google.com Pragma: no-cache Accept: image/gif, image/x-xbitmap, image/jpeg, image/pjpeg, */* Content-Type:application/x-www-form-urlencoded Authorization: AuthSub token="AIwbFASiRR3XDKs......p5Oy_VA_9U2yV1enxJoVGSgMlZqTcjKw9mS861vlc9GWTH9D9sQ" Response received: 403 Invalid AuthSub token. curl command used: /usr/bin/curl -S -v --location https://www.google.com/accounts/AuthSubSessionToken --header Content-Type:application/x-www-form-urlencoded -H Authorization: AuthSub token="AIwbFAQR_4xG2g.....vp3BQZW5XEMyIj_wFozHSTEQ-BQRfYuIY-1CyqLeQ" STEP 3: Checking to see if the token is good/valid GET /accounts/AuthSubTokenInfo HTTP/1.1 User-Agent: curl/7.10.6 (i386-redhat-linux-gnu) libcurl/7.10.6 OpenSSL/0.9.7a ipv6 zlib/1.1.4 Host: www.google.com Pragma: no-cache Accept: image/gif, image/x-xbitmap, image/jpeg, image/pjpeg, */* Content-Type:application/x-www-form-urlencoded Authorization: AuthSub token="AIwbFASiRR3XDKsNkaIoPaujN5RQhKs3u.....A_9U2yV1enxJoVGSgMlZqTcjKw9mS861vlc9GWTH9D9sQ" Received response: 403 Invalid AuthSub token. curl command used: /usr/bin/curl -S -v --location https://www.google.com/accounts/AuthSubTokenInfo --header Content-Type:application/x-www-form-urlencoded -H Authorization: AuthSub token="AIwbFAQR_4xG2gHoAKDsNdFqdZdwWjGeNquOLpvp3BQZW5XEMyIj_wFozHSTEQ-BQRfYuIY-1CyqLeQ" STEP 4: Trying to get the upload token using the authsub token POST /action/GetUploadToken HTTP/1.1 User-Agent: curl/7.10.6 (i386-redhat-linux-gnu) libcurl/7.10.6 OpenSSL/0.9.7a ipv6 zlib/1.1.4 Host: gdata.youtube.com Pragma: no-cache Accept: image/gif, image/x-xbitmap, image/jpeg, image/pjpeg, */* Content-Type:application/atom+xml Authorization: AuthSub token="AIwbFASiRR3XDKsNkaIoPaujN5RQhp5Oy_VA_9U2yV1enxJoVGSgMlZqTcjKw9mS861vlc9GWTH9D9sQ" X-Gdata-Key:key="AI39si5EQyo-TZPFAnmGjxJGFKpxd_7a6hEERh_3......R82AShoQ" Content-Length:0 GData-Version:2 Recevied Response: 401 Token invalid - Invalid AuthSub token. Curl command used: /usr/bin/curl -S -v --location http://gdata.youtube.com/action/GetUploadToken -H Content-Type:application/atom+xml -H Authorization: AuthSub token="AIwbFASiRR3XDKs....sYDp5Oy_VA_9U2yV1enxJoVGSgMlZqTcjKw9mS861vlc9GWTH9D9sQ" -H X-Gdata-Key:key="AI39si5EQyo-TZPFAnmGjxJGF......Kpxd6dN2J1oHFQYTj_7a6hEERh_3E48R82AShoQ" -H Content-Length:0 -H GData-Version:2

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  • WPF Combobox binding: can't change selection.

    - by SteveCav
    After wasting hours on this, following on the heels of my Last Problem, I'm starting to feel that Framework 4 is a master of subtle evil, or my PC is haunted. I have three comboboxes and a textbox on a WPF form, and I have an out-of-the-box Subsonic 3 ActiveRecord DAL. When I load this "edit record" form, the comboboxes fill correctly, they select the correct items, and the textbox has the correct text. I can change the TextBox text and save the record just fine, but the comboboxes CANNOT BE CHANGED. The lists drop down and highlight, but when you click on an item, the item selected stays the same. Here's my XAML: <StackPanel Orientation="Horizontal" Margin="10,10,0,0"> <TextBlock Width="80">Asset</TextBlock> <ComboBox Name="cboAsset" Width="180" DisplayMemberPath="AssetName" SelectedValuePath="AssetID" SelectedValue="{Binding AssetID}" ></ComboBox> </StackPanel> <StackPanel Orientation="Horizontal" Margin="10,10,0,0"> <TextBlock Width="80">Status</TextBlock> <ComboBox Name="cboStatus" Width="180" DisplayMemberPath="JobStatusDesc" SelectedValuePath="JobStatusID" SelectedValue="{Binding JobStatusID}" ></ComboBox> </StackPanel> <StackPanel Orientation="Horizontal" Margin="10,10,0,0"> <TextBlock Width="80">Category</TextBlock> <ComboBox Name="cboCategories" Width="180" DisplayMemberPath="CategoryName" SelectedValuePath="JobCategoryID" SelectedValue="{Binding JobCategoryID}" ></ComboBox> </StackPanel> <StackPanel Orientation="Horizontal" Margin="10,10,0,0"> <TextBlock Width="80">Reason</TextBlock> <TextBox Name="txtReason" Width="380" Text="{Binding Reason}"/> </StackPanel> Here are the relevant snips of my code (intJobID is passed in): SvcMgrDAL.Job oJob; IQueryable<SvcMgrDAL.JobCategory> oCategories = SvcMgrDAL.JobCategory.All().OrderBy(x => x.CategoryName); IQueryable<SvcMgrDAL.Asset> oAssets = SvcMgrDAL.Asset.All().OrderBy(x => x.AssetName); IQueryable<SvcMgrDAL.JobStatus> oStatus = SvcMgrDAL.JobStatus.All(); cboCategories.ItemsSource = oCategories; cboStatus.ItemsSource = oStatus; cboAsset.ItemsSource = oAssets; this.JobID = intJobID; oJob = SvcMgrDAL.Job.SingleOrDefault(x => x.JobID == intJobID); this.DataContext = oJob; Things I've tried: -Explicitly setting IsReadOnly="false" and IsSynchronizedWithCurrentItem="True" -Changing the combobox ItemSources from IQueryables to Lists. -Building my own Job object (plain vanilla entity class). -Every binding mode for the comboboxes. The Subsonic DAL doesn't implement INotifyPropertyChanged, but I don't see as it'd need to for simple binding like this. I just want to be able to pick something from the dropdown and save it. Comparing it with my last problem (link at the top of this message), I seem to have something really wierd with data sources going on. Maybe it's a Subsonic thing?

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  • Solving Combinatory Problems with LINQ /.NET4

    - by slf
    I saw this article pop-up in my MSDN RSS feed, and after reading through it, and the sourced article here I began to wonder about the solution. The rules are simple: Find a number consisting of 9 digits in which each of the digits from 1 to 9 appears only once. This number must also satisfy these divisibility requirements: The number should be divisible by 9. If the rightmost digit is removed, the remaining number should be divisible by 8. If the rightmost digit of the new number is removed, the remaining number should be divisible by 7. And so on, until there's only one digit (which will necessarily be divisible by 1). This is his proposed monster LINQ query: // C# and LINQ solution to the numeric problem presented in: // http://software.intel.com/en-us/blogs/2009/12/07/intel-parallel-studio-great-for-serial-code-too-episode-1/ int[] oneToNine = new int[] { 1, 2, 3, 4, 5, 6, 7, 8, 9 }; // the query var query = from i1 in oneToNine from i2 in oneToNine where i2 != i1 && (i1 * 10 + i2) % 2 == 0 from i3 in oneToNine where i3 != i2 && i3 != i1 && (i1 * 100 + i2 * 10 + i3) % 3 == 0 from i4 in oneToNine where i4 != i3 && i4 != i2 && i4 != i1 && (i1 * 1000 + i2 * 100 + i3 * 10 + i4) % 4 == 0 from i5 in oneToNine where i5 != i4 && i5 != i3 && i5 != i2 && i5 != i1 && (i1 * 10000 + i2 * 1000 + i3 * 100 + i4 * 10 + i5) % 5 == 0 from i6 in oneToNine where i6 != i5 && i6 != i4 && i6 != i3 && i6 != i2 && i6 != i1 && (i1 * 100000 + i2 * 10000 + i3 * 1000 + i4 * 100 + i5 * 10 + i6) % 6 == 0 from i7 in oneToNine where i7 != i6 && i7 != i5 && i7 != i4 && i7 != i3 && i7 != i2 && i7 != i1 && (i1 * 1000000 + i2 * 100000 + i3 * 10000 + i4 * 1000 + i5 * 100 + i6 * 10 + i7) % 7 == 0 from i8 in oneToNine where i8 != i7 && i8 != i6 && i8 != i5 && i8 != i4 && i8 != i3 && i8 != i2 && i8 != i1 && (i1 * 10000000 + i2 * 1000000 + i3 * 100000 + i4 * 10000 + i5 * 1000 + i6 * 100 + i7 * 10 + i8) % 8 == 0 from i9 in oneToNine where i9 != i8 && i9 != i7 && i9 != i6 && i9 != i5 && i9 != i4 && i9 != i3 && i9 != i2 && i9 != i1 let number = i1 * 100000000 + i2 * 10000000 + i3 * 1000000 + i4 * 100000 + i5 * 10000 + i6 * 1000 + i7 * 100 + i8 * 10 + i9 * 1 where number % 9 == 0 select number; // run it! foreach (int n in query) Console.WriteLine(n); Octavio states "Note that no attempt at all has been made to optimize the code", what I'd like to know is what if we DID attempt to optimize this code. Is this really the best this code can get? I'd like to know how we can do this best with .NET4, in particular doing as much in parallel as we possibly can. I'm not necessarily looking for an answer in pure LINQ, assume .NET4 in any form (managed c++, c#, etc all acceptable).

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  • Trying to sentinel loop this program.

    - by roger34
    Okay, I spent all this time making this for class but I have one thing that I can't quite get: I need this to sentinel loop continuously (exiting upon entering x) so that the System.out.println("What type of Employee? Enter 'o' for Office " + "Clerical, 'f' for Factory, or 's' for Saleperson. Enter 'x' to exit." ); line comes back up after they enter the first round of information. Also, I can't leave this up long on the (very) off chance a classmate might see this and steal the code. Full code following: import java.util.Scanner; public class Project1 { public static void main (String args[]){ Scanner inp = new Scanner( System.in ); double totalPay; System.out.println("What type of Employee? Enter 'o' for Office " + "Clerical, 'f' for Factory, or 's' for Saleperson. Enter 'x' to exit." ); String response= inp.nextLine(); while (!response.toLowerCase().equals("o")&&!response.toLowerCase().equals("f") &&!response.toLowerCase().equals("s")&&!response.toLowerCase().equals("x")){ System.out.print("\nInvalid selection,please enter your choice again:\n"); response=inp.nextLine(); } char choice = response.toLowerCase().charAt( 0 ); switch (choice){ case 'o': System.out.println("Enter your hourly rate:"); double officeRate=inp.nextDouble(); System.out.println("Enter the number of hours worked:"); double officeHours=inp.nextDouble(); totalPay = officeCalc(officeRate,officeHours); taxCalc(totalPay); break; case 'f': System.out.println("How many Widgets did you produce during the week?"); double widgets=inp.nextDouble(); totalPay=factoryCalc(widgets); taxCalc(totalPay); break; case 's': System.out.println("What were your total sales for the week?"); double totalSales=inp.nextDouble(); totalPay=salesCalc(totalSales); taxCalc(totalPay); break; } } public static double taxCalc(double totalPay){ double federal=totalPay*.22; double state =totalPay*.055; double netPay = totalPay - federal - state; federal =federal*Math.pow(10,2); federal =Math.round(federal); federal= federal/Math.pow(10,2); state =state*Math.pow(10,2); state =Math.round(state); state= state/Math.pow(10,2); totalPay =totalPay*Math.pow(10,2); totalPay =Math.round(totalPay); totalPay= totalPay/Math.pow(10,2); netPay =netPay*Math.pow(10,2); netPay =Math.round(netPay); netPay= netPay/Math.pow(10,2); System.out.printf("\nTotal Pay \t: %1$.2f.\n", totalPay); System.out.printf("State W/H \t: %1$.2f.\n", state); System.out.printf("Federal W/H : %1$.2f.\n", federal); System.out.printf("Net Pay \t: %1$.2f.\n", netPay); return totalPay; } public static double officeCalc(double officeRate,double officeHours){ double overtime=0; if (officeHours>=40) overtime = officeHours-40; else overtime = 0; if (officeHours >= 40) officeHours = 40; double otRate = officeRate * 1.5; double totalPay= (officeRate * officeHours) + (otRate*overtime); return totalPay; } public static double factoryCalc(double widgets){ double totalPay=widgets*.35 +300; return totalPay; } public static double salesCalc(double totalSales){ double totalPay = totalSales * .05 + 500; return totalPay; } }

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  • C++ Greatest Number Verification

    - by Daniel
    Hey guys, I was assigned to create a program that creates n arrays composed by 10 random integers. The the program should sum all the integers and display the result. After, it has to verify which of the sums is the greatest and it has to display that array and the result. Im having troubles getting it done and would like to get some help! Thanks once again. Here is my code so far: #include <iostream> #include <iomanip> #include <cmath> using namespace std; double random(unsigned int &seed); unsigned int seed = 5; void generateData(int set[10]); int sumData(int set[10]); void checkData(int sumResult, int arrayNumber); int main (int argc, char * const argv[]) { int arrayNumber, sumResult; int set[10]; do { cout << "Number of Arrays to Compare: " << endl; cin >> arrayNumber; } while (arrayNumber < 0); for (int i = 0; i < arrayNumber; ++i) { generateData(set); sumResult = sumData(set); cout << "Sum --> " << sumResult << endl; checkData(sumResult, arrayNumber); } return 0; } double random(unsigned int &seed) { const int MODULUS = 15749; const int MULTIPLIER = 69069; const int INCREMENT = 1; seed = ((MULTIPLIER * seed) + INCREMENT) % MODULUS; return double(seed) / double(MODULUS); } void generateData(int set[10]) { for (int i = 0; i < 10; ++i) { set[i] = int (5 + 6 * random(seed)); cout << set[i] << " || "; } } int sumData(int set[10]) { int sumTotal = 0; for (int i = 0; i < 10; ++i) sumTotal = sumTotal + set[i]; return sumTotal; } void checkData(int sumResult, int arrayNumber) { int largerNumber; int tempSet[2]; for (int i = 0; i < arrayNumber; ++i) { if (sumResult > largerNumber) { tempSet[i] = sumResult; } } }

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  • Trying to sentinel loop this program. [java]

    - by roger34
    Okay, I spent all this time making this for class but I have one thing that I can't quite get: I need this to sentinel loop continuously (exiting upon entering x) so that the System.out.println("What type of Employee? Enter 'o' for Office " + "Clerical, 'f' for Factory, or 's' for Saleperson. Enter 'x' to exit." ); line comes back up after they enter the first round of information. Also, I can't leave this up long on the (very) off chance a classmate might see this and steal the code. Full code following: import java.util.Scanner; public class Project1 { public static void main (String args[]){ Scanner inp = new Scanner( System.in ); double totalPay; System.out.println("What type of Employee? Enter 'o' for Office " + "Clerical, 'f' for Factory, or 's' for Saleperson. Enter 'x' to exit." ); String response= inp.nextLine(); while (!response.toLowerCase().equals("o")&&!response.toLowerCase().equals("f") &&!response.toLowerCase().equals("s")&&!response.toLowerCase().equals("x")){ System.out.print("\nInvalid selection,please enter your choice again:\n"); response=inp.nextLine(); } char choice = response.toLowerCase().charAt( 0 ); switch (choice){ case 'o': System.out.println("Enter your hourly rate:"); double officeRate=inp.nextDouble(); System.out.println("Enter the number of hours worked:"); double officeHours=inp.nextDouble(); totalPay = officeCalc(officeRate,officeHours); taxCalc(totalPay); break; case 'f': System.out.println("How many Widgets did you produce during the week?"); double widgets=inp.nextDouble(); totalPay=factoryCalc(widgets); taxCalc(totalPay); break; case 's': System.out.println("What were your total sales for the week?"); double totalSales=inp.nextDouble(); totalPay=salesCalc(totalSales); taxCalc(totalPay); break; } } public static double taxCalc(double totalPay){ double federal=totalPay*.22; double state =totalPay*.055; double netPay = totalPay - federal - state; federal =federal*Math.pow(10,2); federal =Math.round(federal); federal= federal/Math.pow(10,2); state =state*Math.pow(10,2); state =Math.round(state); state= state/Math.pow(10,2); totalPay =totalPay*Math.pow(10,2); totalPay =Math.round(totalPay); totalPay= totalPay/Math.pow(10,2); netPay =netPay*Math.pow(10,2); netPay =Math.round(netPay); netPay= netPay/Math.pow(10,2); System.out.printf("\nTotal Pay \t: %1$.2f.\n", totalPay); System.out.printf("State W/H \t: %1$.2f.\n", state); System.out.printf("Federal W/H : %1$.2f.\n", federal); System.out.printf("Net Pay \t: %1$.2f.\n", netPay); return totalPay; } public static double officeCalc(double officeRate,double officeHours){ double overtime=0; if (officeHours>=40) overtime = officeHours-40; else overtime = 0; if (officeHours >= 40) officeHours = 40; double otRate = officeRate * 1.5; double totalPay= (officeRate * officeHours) + (otRate*overtime); return totalPay; } public static double factoryCalc(double widgets){ double totalPay=widgets*.35 +300; return totalPay; } public static double salesCalc(double totalSales){ double totalPay = totalSales * .05 + 500; return totalPay; } }

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  • Trying to create an image list based on what is defined as the order, and loosing

    - by user1691463
    I have a custom created module for Joomla 2.5 and within the params of the module, and have a loop that is not outputting as expected. I have the following parameters (fields) int he module: Order Thumb image Image Title Full-size image Now there are 10 sets of these group of 4 params. What I am trying to do is loop through each of the object sets, 10 of them, and on each iteration, build an HTML image list structure. The if statement is building the HTML structure for the sets that have an order value that is greater than 0, and the else is creating the html for those sets that do not have a value greater that 0. The goal is to create two variables and then concatenate the the strings together; the leading set are the sets that have an order defined. This is not happening and every thrid loop seems like it is missing. Here is the order as it is set in the 10 sets Set 1 = 0 Set 2 = 4 Set 3 = 1 Set 4 = 0 Set 5 = 5 Set 6 = 0 Set 7 = 0 Set 8 = 6 Set 9 = 3 Set 10 = 9 However, the outcomes is: 9 5 1 4 6 7 10 Instead of the expected: 3 9 2 5 8 1 (below here are those sets that were not greater than 0 in order of appearance) 4 6 7 whats wrong here that I can not see <?php for ($i = 1; $i <= 10; $i++) { $order = $params->get('order'.$i);#get order for main loop of 10 $active = ""; if ($order > 0) {#Check if greater than 0 for ($n = 1; $n <= 10; $n++) {#loop through all order fields looking and build html lowest to highest; $ordercheck =$params->get('order'.$n); if ($ordercheck == $i) { $img = $params->get('image'.$n); $fimage = $params->get('image'.$n.'fullimage'); $title = $params->get('image'.$n.'alttext'); $active = ""; $active = $active . '<li>'; $active = $active . '<a href="'.$fimage.'" rel="prettyPhoto[gallery1]" title="'.$title.'">'; $active = $active . '<img src="'.$img.'" alt="'.$title.'" />'; $active = $active . '</a>'; $active = $active . '</li>'; $leading = $leading . $active; } } } else { #if the itteration $order was not greater than 0, build in order of accourance $img = $params->get('image'.$i); $fimage = $params->get('image'.$i.'fullimage'); $title = $params->get('image'.$i.'alttext'); $active = $active . '<li>'; $active = $active . '<a href="'.$fimage.'" rel="prettyPhoto[gallery1]" title="'.$title.'">'; $active = $active . '<img src="'.$img.'" alt="'.$title.'" />'; $active = $active . '</a></li>'; $unordered = $unordered . $active; } $imagesList = $leading . $unordered; } ?>

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  • C - Error with read() of a file, storage in an array, and printing output properly

    - by ns1
    I am new to C, so I am not exactly sure where my error is. However, I do know that the great portion of the issue lies either in how I am storing the doubles in the d_buffer (double) array or the way I am printing it. Specifically, my output keeps printing extremely large numbers (with around 10-12 digits before the decimal point and a trail of zeros after it. Additionally, this is an adaptation of an older program to allow for double inputs, so I only really added the two if statements (in the "read" for loop and the "printf" for loop) and the d_buffer declaration. I would appreciate any input whatsoever as I have spent several hours on this error. #include <stdio.h> #include <fcntl.h> #include <sys/types.h> #include <unistd.h> #include <string.h> struct DataDescription { char fieldname[30]; char fieldtype; int fieldsize; }; /* ----------------------------------------------- eof(fd): returns 1 if file `fd' is out of data ----------------------------------------------- */ int eof(int fd) { char c; if ( read(fd, &c, 1) != 1 ) return(1); else { lseek(fd, -1, SEEK_CUR); return(0); } } void main() { FILE *fp; /* Used to access meta data */ int fd; /* Used to access user data */ /* ---------------------------------------------------------------- Variables to hold the description of the data - max 10 fields ---------------------------------------------------------------- */ struct DataDescription DataDes[10]; /* Holds data descriptions for upto 10 fields */ int n_fields; /* Actual # fields */ /* ------------------------------------------------------ Variables to hold the data - max 10 fields.... ------------------------------------------------------ */ char c_buffer[10][100]; /* For character data */ int i_buffer[10]; /* For integer data */ double d_buffer[10]; int i, j; int found; printf("Program for searching a mini database:\n"); /* ============================= Read in meta information ============================= */ fp = fopen("db-description", "r"); n_fields = 0; while ( fscanf(fp, "%s %c %d", DataDes[n_fields].fieldname, &DataDes[n_fields].fieldtype, &DataDes[n_fields].fieldsize) > 0 ) n_fields++; /* --- Prints meta information --- */ printf("\nThe database consists of these fields:\n"); for (i = 0; i < n_fields; i++) printf("Index %d: Fieldname `%s',\ttype = %c,\tsize = %d\n", i, DataDes[i].fieldname, DataDes[i].fieldtype, DataDes[i].fieldsize); printf("\n\n"); /* --- Open database file --- */ fd = open("db-data", O_RDONLY); /* --- Print content of the database file --- */ printf("\nThe database content is:\n"); while ( ! eof(fd) ) { /* ------------------ Read next record ------------------ */ for (j = 0; j < n_fields; j++) { if ( DataDes[j].fieldtype == 'I' ) read(fd, &i_buffer[j], DataDes[j].fieldsize); if ( DataDes[j].fieldtype == 'F' ) read(fd, &d_buffer[j], DataDes[j].fieldsize); if ( DataDes[j].fieldtype == 'C' ) read(fd, &c_buffer[j], DataDes[j].fieldsize); } double d; /* ------------------ Print it... ------------------ */ for (j = 0; j < n_fields; j++) { if ( DataDes[j].fieldtype == 'I' ) printf("%d ", i_buffer[j]); if ( DataDes[j].fieldtype == 'F' ) d = d_buffer[j]; printf("%lf ", d); if ( DataDes[j].fieldtype == 'C' ) printf("%s ", c_buffer[j]); } printf("\n"); } printf("\n"); printf("\n"); } Post edits output: 16777216 0.000000 107245694331284094976.000000 107245694331284094976.000000 Pi 33554432 107245694331284094976.000000 2954938175610156848888276006519501238173891974277081114627768841840801736306392481516295906896346039950625609765296207682724801406770458881439696544971142710292689518104183685723154223544599940711614138798312668264956190761622328617992192.000000 2954938175610156848888276006519501238173891974277081114627768841840801736306392481516295906896346039950625609765296207682724801406770458881439696544971142710292689518104183685723154223544599940711614138798312668264956190761622328617992192.000000 Secret Key 50331648 2954938175610156848888276006519501238173891974277081114627768841840801736306392481516295906896346039950625609765296207682724801406770458881439696544971142710292689518104183685723154223544599940711614138798312668264956190761622328617992192.000000 -0.000000 -0.000000 The number E Expected Output: 3 rows of data ending with the number "e = 2.18281828" To reproduce the problem, the following two files need to be in the same directory as the lookup-data.c file: - db-data - db-description

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  • R concentrating data frame

    - by user1631503
    I have a data frame like this >X_com Day_1 Day_2 Day_3 Day_4 Day_5 Day_6 Day_7 Day_8 Day_9 Day_10 1 0 0 0 0 0 0 0 0 0 1 2 0 0 0 0 0 0 0 0 0 0 3 0 0 0 0 0 0 0 0 0 0 4 0 0 0 0 0 0 0 0 0 0 5 0 0 0 0 0 0 0 0 0 0 6 0 0 0 0 0 0 0 0 0 0 7 0 0 0 0 0 0 0 0 0 0 8 0 0 0 0 0 0 0 0 0 0 I need to concentrate all the values into one column and add another column with "1;" So I did this > X_new=matrix(1,8,2) > X_new[1,]=paste(X_com[1,1], X_com[1,2],X_com[1,3],X_com [1,4],X_com[1,5],X_com[1,6],X_com[1,7],X_com[1,8],X_com [1,9],X_com[1,10], sep="") > X_new[2,]=paste(X_com[2,1], X_com[2,2],X_com[2,3],X_com [2,4],X_com[2,5],X_com[2,6],X_com[2,7],X_com[2,8],X_com [2,9],X_com[2,10], sep="") > X_new[3,]=paste(X_com[3,1], X_com[3,2],X_com[3,3],X_com [3,4],X_com[3,5],X_com[3,6],X_com[3,7],X_com[3,8],X_com [3,9],X_com[3,10], sep="") > X_new[4,]=paste(X_com[4,1], X_com[4,2],X_com[4,3],X_com [4,4],X_com[4,5],X_com[4,6],X_com[4,7],X_com[4,8],X_com [4,9],X_com[4,10], sep="") > X_new[5,]=paste(X_com[5,1], X_com[5,2],X_com[5,3],X_com [5,4],X_com[5,5],X_com[5,6],X_com[5,7],X_com[5,8],X_com [5,9],X_com[5,10], sep="") > X_new[6,]=paste(X_com[6,1], X_com[6,2],X_com[6,3],X_com [6,4],X_com[6,5],X_com[6,6],X_com[6,7],X_com[6,8],X_com [6,9],X_com[6,10], sep="") > X_new[7,]=paste(X_com[7,1], X_com[7,2],X_com[7,3],X_com [7,4],X_com[7,5],X_com[7,6],X_com[7,7],X_com[7,8],X_com [7,9],X_com[7,10], sep="") > X_new[8,]=paste(X_com[8,1], X_com[8,2],X_com[8,3],X_com [8,4],X_com[8,5],X_com[8,6],X_com[8,7],X_com[8,8],X_com [8,9],X_com[8,10], sep="") > X_new[1:8,2]="1;" > as.data.frame(X_new) V1 V2 1 0000000001 1; 2 0000000000 1; 3 0000000000 1; 4 0000000000 1; 5 0000000000 1; 6 0000000000 1; 7 0000000000 1; 8 0000000000 1; I believe there's definitely a faster way of achieving this but have no clue. The other problem is, I have over a thousand of data frame like this needs to be concentrated. I'm still learning how to loop these repetitive steps but is progressing quite slowly. If the original data frames were named uniquely, does that mean I have no choice but to work on each of them individually? Thank you in advance.

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  • CodePlex Daily Summary for Saturday, March 06, 2010

    CodePlex Daily Summary for Saturday, March 06, 2010New ProjectsAgr.CQRS: Agr.CQRS is a C# framework for DDD applications that use the Command Query Responsibility Segregation pattern (CQRS) and Event Sourcing. BigDays 2010: Big>Days 2010BizTalk - Controlled Admin: Hi .NET folks, I am planning to start project on a Controlled BizTalk Admin tool. This tool will be useful for the organizations which have "Sh...Blacklist of Providers: Blacklist of Providers - the application for department of warehouse logistics (warehouse) at firms.Career Vector: A job board software.Chargify Demo: This is a sample website for ChargifyConceptual: Concept description and animationEric Hexter: My publicly available source code and examplesFluentNHibernate.Search: A Fluent NHibernate.Search mapping interface for NHibernate provider implementation of Lucene.NET.FreelancePlanner: FreelancePlanner is a project tracking tool for freelance translators.HTMLx - JavaScript on the Server for .NET: HTMLx is a set of libraries based on ASP.NET engine to provide JavaScript programmability on the server side. It allows Web developers to use JavaS...IronMSBuild: IronMSBuild is a custom MSBuild Task, which allows you to execute IronRuby scripts. // have to provide some examples LINQ To Blippr: LINQ to Blippr is an open source LINQ Provider for the micro-reviewing service Blippr. LINQ to Blippr makes it easier and more efficent for develo...Luk@sh's HTML Parser: library that simplifies parsing of the HTML documents, for .NETMeta Choons: Unsure as yet but will be a kind of discogs type site but different..NetWork2: NetWork2Regular Expression Chooser: Simple gui for choosing the regular expressions that have become more than simple.See.Sharper: Hopefully useful C# extensions.SharePoint 2010 Toggle User Interface: Toggle the SharePoint 2010 user interface between the new SharePoint 2010 user interface and SharePoint 2007 user interface.Silverlight DiscussionBoard for SharePoint: This is a sharepoint 3.0 webpart that uses a silverlight treeview to display metadata about sharepoint discussions anduses the html bridge to show...Simple Sales Tracking CRM API Wrapper: The Simple Sales Tracking API Wrapper, enables easy extention development and integration with the hosted service at http://www.simplesalestracking...Syntax4Word: A syntax addin for word 2007.TortoiseHg installer builder: TortoiseHg and Mercurial installer builder for Windowsunbinder: Model un binding for route value dictionariesWindows Workflow Foundation on Codeplex: This site has previews of Workflow features which are released out of band for the purposes of adoption and feedback.XNA RSM Render State Manager: Render state management idea for XNA games. 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  • Need a solution to store images (1 billion, 1000,000,000) which users will upload to a website via php or javascript upload [on hold]

    - by wish_you_all_peace
    I need a solution to store images (1 billion) which users will upload to a website via PHP or Javascript upload (website will have 1 billion page views a month using Linux Debian distros) assuming 20 photos per user maximum (10 thumbnails of size 90px by 90px and 10 large, script resized images of having maximum width 500px or maximum height 500px depending on shape of image, meaning square, rectangle, horizontal, vertical etc). Assume this to be a LEMP-stack (Linux Nginx MySQL PHP) social-media or social-matchmaking type application whose content will be text and images. Since everyone knows storing tons of images (website users uploaded images in this case) are bad inside a single directory or NFS etc, please explain all the details about the architecture and configuration of the entire setup of storage solution, to store 1 billion images on any method you recommend (no third-party cloud storage like S3 etc. It has to be within the private data center using our own hardware and resources.). The solution has to include both the storage solution and organizing the images uploaded by users. How will we organize the users images if a single user will not have more than 20 images (10 thumbs and 10 large of having either width or height 500px)? Please consider that this has to be organized in a structural way so we can fetch a single user's images via PHP/Javascript or API programmatically through some type of user's unique identifier(s).

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