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  • Entity framework error: The conversion of a datetime2 data type to a datetime data

    - by EdenMachine
    I know there are a ton of posts about this issue but none of them seem to solve my problem. Here's the scenario: I have a CreateDate DateTime column in my MS SQL Server database User table that is non-nullable and is automatically set using GetDate() method in "Default Value or Binding" setting. I am able to create a User just fine with the standard EF Insert but when I try to update the user, I get this error: The conversion of a datetime2 data type to a datetime data type resulted in an out-of-range value. What is the trick to not having the EF worry about the CreateDate column for updates? I have the StoreGenerationPattern = Identity but that isn't helping. Here are the EF properties for my Entity Property: http://screencast.com/t/8ndQRn9N And here is my Update method: http://screencast.com/t/UXIzhkhR

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  • How to use MySql date_add in Nhibernate?

    - by jalchr
    This really puzzled for hours, I searched all over the internet, but got no working solution. Can someone point where the problem is ... thanks ! I created my own dialect class public class MySQLDialectExtended : MySQLDialect { public MySQLDialectExtended() { RegisterFunction("date_add_interval", new SQLFunctionTemplate(NHibernateUtil.Date, "date_add(?1, INTERVAL ?2 ?3)")); } } Then I try to use it as follows: query.Append( " ( date_add_interval(D.ApprovalDate, 1, YEAR) < current_timestamp() < date_add_interval(D.RenewalDate, -1, YEAR) )"); It fails with following exception: NHibernate.Hql.Ast.ANTLR.QuerySyntaxException : Exception of type 'Antlr.Runtime.NoViableAltException' was thrown. near line 1, column 677 where the column number is at the end of the first 'YEAR' word. Edit: here is my configuration <property name="dialect">MyCompanyName.MySQLDialectExtended, MyCompanyName</property> <property name="hbm2ddl.keywords">none</property>

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  • Getting consecutive version numbers from Hibernate's @Version usage once per transaction

    - by Cheradenine
    We use Hibernate with the following version definition for optimistic locking et. al: <version name="version" access="field" column="VERSION" type="long" unsaved-value="negative"/> This is fine and dandy; however, there is one small problem, which is that the first version for some entities is '0', and for others, it is '1'. Why this is happening, is that for some object graphs, an entity will be subject to both onSave and flushDirty - this is reasonable, such as if two object are circular dependencies. However, the version number gets incremented on both occasions, leading to the above '0' / '1' discrepancy. I'd really like the version number only to ever increment once per transaction. However, I can't see a simple way to do this in the hibernate versioning implementation, without hacking about with an Interceptor (which was how I generated a column value for version before, but I wanted hibernate to do it itself)..

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  • qtableview (libqt) how do I correctly create a QModelIndex

    - by Chris Camacho
    I'm trying to enter edit mode on a specific cell like this void MainWindow::on_addButton_released(void) { tm->addRow(); tableView->scrollToBottom(); int ec=tm->firstWritableColumn(); int r=tm->rowCount(QModelIndex()); QModelIndex id = tm->index(r, ec, QModelIndex()); tableView->setCurrentIndex(id); tableView->edit(id); qDebug() << "row:" << r << " col:" << ec << "index:" << id; } my model creates an index like this QModelIndex TableModel::index(int row,int column,QModelIndex parent) const { Q_UNUSED(parent); return createIndex(row,column,0); } the debug output looks like this row: 9 col: 1 index: QModelIndex(9,1,0x0,TableModel(0xbf3f50) ) I'm fairly sure that the index is somehow invalid as setCurrentIndex doesn't seem to be working

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  • ALTER TABLE without locking the table?

    - by Daniel
    When doing an ALTER TABLE statement in MySQL, the whole table is read-locked for the duration of the statement. If it's a big table, that means insert or update statements could be locked for a looooong time. Is there a way to do a "hot alter", like adding a column in such a way that the table is still updatable throughout the process? Mostly I'm interested in a solution for MySQL but I'd be interested in other RDBMS if MySQL can't do it. To clarify, my purpose is simply to avoid downtime when a new feature that requires an extra table column is pushed to production. Any database schema will change over time, that's just a fact of life. I don't see why we should accept that these changes must inevitably result in downtime; that's just weak.

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  • BigDecimal precision not persisted with javax.persistence annotations

    - by dkaczynski
    I am using the javax.persistence API and Hibernate to create annotations and persist entities and their attributes in an Oracle 11g Express database. I have the following attribute in an entity: @Column(precision = 12, scale = 9) private BigDecimal weightedScore; The goal is to persist a decimal value with a maximum of 12 digits and a maximum of 9 of those digits to the right of the decimal place. After calculating the weightedScore, the result is 0.1234, but once I commit the entity with the Oracle database, the value displays as 0.12. I can see this by either by using an EntityManager object to query the entry or by viewing it directly in the Oracle Application Express (Apex) interface in a web browser. How should I annotate my BigDecimal attribute so that the precision is persisted correctly? Note: We use an in-memory HSQL database to run our unit tests, and it does not experience the issue with the lack of precision, with or without the @Column annotation.

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  • how/resources to compile a procedural language into [sql]

    - by Philip
    I am looking into the possibility/feasibility/resources for building a cross compiler which takes a procedural or Object Oriented language like C, or Java and compiling it into SQL. I understand that the advantage of SQL code is performing set operations which is fundamentally different from procedural languages which generally process 1 at a time. If anyone has done this before, or if it is thought of as too complicated to do or any other ideas/concerns/suggestions would be greatly appreciated. Thanks in advance Philip

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  • DataList Control in vb.net windows application forms

    - by KoolKabin
    Hi guys, I am upgrading my application from vb6 to vb.net. I used to populate my data in datalist control in vb6 forms. I am not finding it in vb.net windows form application. Which one control is the equivalent to it? How can i list my data in that control? just like: I had a table with data like id, name I want the name should be the displayed column and id the bound column? how can i do that

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  • do console apps run faster than windows based app?

    - by omair iqbal
    i am reletivly new to world of programming i have a few performance questions 1. do console apps run faster than windows based app? 2.are languages like c and pascal faster than object oriented languages like c++ and delphi?i know language speed depends more on compiler than on language itself but do compilers for prcedural languages like c and pascal produce faster code than oo ones like delphi,c++(including c++ compilers that can procuce c code) sorry for my bad english

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  • JPA query for getting the whole tree

    - by Javi
    Hello, I have a class which models all categories and they can be ordered hierarchically. @Entity @Table(name="categories") public class Category { @Id @GeneratedValue(strategy=GenerationType.SEQUENCE, generator="sequence") @SequenceGenerator(name="sequence", sequenceName="categories_pk_seq", allocationSize=1) @Column(name="id") private Long id; @Column private String name; @OneToOne @JoinColumn(name="idfather") private Category father; } I need to get all categories ordered hierarchically (I mean every father followed by its children and fathers ordered alphabetically on each level) as they could be made for example with PRIOR in oracle. Is it possible to do this with a JPA Query (not a SQL one)? Thanks.

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  • How can I call a module in a Perl one-liner?

    - by Zaid
    Say I have a data file that I want to process; I want to take the maximum value of each of the column and append it to the end of each line. INPUT: T1 T2 T3 35.82 34.67 31.68 32.20 34.52 33.59 37.41 38.64 37.56 OUTPUT: T1 T2 T3 35.82 34.67 31.68 35.82 32.20 34.52 33.59 34.52 37.41 38.64 37.56 38.64 I'm trying to implement this as a one-liner. So far, this is what I've come up with, although it complains that &main::max is undefined: perl -MList::Util -ani.bak -e "print qq(@F).q( ).max(@F).qq(\n)" file1.txt It seems that I haven't loaded the List::Util module. What's wrong? And is the header column an issue? perlrun doesn't have a decent example on how to do this (actually it does now, my documentation was a little out-of-date).

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  • Understanding the output from svn export

    - by ThatBlairGuy
    Working on some tweaks for a build script, I noticed that the output from svn export has an 'A' in column 1 for each file exported. A C:\build\file1 A C:\build\file2 A C:\build\file3 The subversion book describes the meaning of the various columns for svnlook changes and svn status, but I'm not having much luck finding the meaning behind this one. What does the 'A' in column 1 mean? Are there any other values displayed there? Any other columns? Thanks!

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  • Mathematica - Import CSV and process columns?

    - by Casey
    I have a CSV file that is formatted like: 0.0023709,8.5752e-007,4.847e-008 and I would like to import it into Mathematica and then have each column separated into a list so I can do some math on the selected column. I know I can import the data with: Import["data.csv"] then I can separate the columns with this: StringSplit[data[[1, 1]], ","] which gives: {"0.0023709", "8.5752e-007", "4.847e-008"} The problem now is that I don't know how to get the data into individual lists and also Mathematica does not accept scientific notation in the form 8.5e-007. Any help in how to break the data into columns and format the scientific notation would be great. Thanks in advance.

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  • XML Output is Truncated in SQL

    - by Muhammad Akhtar
    Hi, I need to return my result set in XML and this works fine, but if the number of records are increased, my xml output is truncated here is my query select t.id,t.name,t.address from test FOR XML AUTO, ROOT('Response'), ELEMENTS However I have set some option to increase the output result set like.. Tools --> Options --> Query Results --> SQL Server --> Results to Text --> Maximum number of characters displayed in each column Tools --> Options --> Results --> Maximum characters per column but still I am unable to get my desired result. please suggest my solution Thanks....

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  • SSIS web service task parsing result.

    - by dbengals
    I have an ssis (2005) package that uses the web service task to download to a file destination. The file contains a string of xml data. After downloaded the file looks like this. <?xml version="1.0" encoding="utf-16"?> <string>--here is XML data with escaped characters--</string> My thought was I could then use the XML source data flow source to pull the <string> data, but when I set this up the XML source will not read the <string> as a column. It will generate an xsd and it seems normal, but no luck seeing the column. Any ideas on getting this to work? Or would there be a better way to pull the data within the file generated from the web service? Thanks.

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  • PostgreSql XML Text search

    - by cro
    I have a text column in a table. We store XML in this column. Now I want to search for tags and values Example data: Citi Bank ..... ..... / I would like to run the following query: select * from xxxx where to_tsvector('english',xml_column) @@ to_tsquery('Citi Bank') This works fine but it also works for tags like name1 or no tag. How do I have to setup my search in order for this to work so I get an exact match for the tag and value ?

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  • How does MySQL's ORDER BY RAND() work?

    - by Eugene
    Hi, I've been doing some research and testing on how to do fast random selection in MySQL. In the process I've faced some unexpected results and now I am not fully sure I know how ORDER BY RAND() really works. I always thought that when you do ORDER BY RAND() on the table, MySQL adds a new column to the table which is filled with random values, then it sorts data by that column and then e.g. you take the above value which got there randomly. I've done lots of googling and testing and finally found that the query Jay offers in his blog is indeed the fastest solution: SELECT * FROM Table T JOIN (SELECT CEIL(MAX(ID)*RAND()) AS ID FROM Table) AS x ON T.ID >= x.ID LIMIT 1; While common ORDER BY RAND() takes 30-40 seconds on my test table, his query does the work in 0.1 seconds. He explains how this functions in the blog so I'll just skip this and finally move to the odd thing. My table is a common table with a PRIMARY KEY id and other non-indexed stuff like username, age, etc. Here's the thing I am struggling to explain SELECT * FROM table ORDER BY RAND() LIMIT 1; /*30-40 seconds*/ SELECT id FROM table ORDER BY RAND() LIMIT 1; /*0.25 seconds*/ SELECT id, username FROM table ORDER BY RAND() LIMIT 1; /*90 seconds*/ I was sort of expecting to see approximately the same time for all three queries since I am always sorting on a single column. But for some reason this didn't happen. Please let me know if you any ideas about this. I have a project where I need to do fast ORDER BY RAND() and personally I would prefer to use SELECT id FROM table ORDER BY RAND() LIMIT 1; SELECT * FROM table WHERE id=ID_FROM_PREVIOUS_QUERY LIMIT 1; which, yes, is slower than Jay's method, however it is smaller and easier to understand. My queries are rather big ones with several JOINs and with WHERE clause and while Jay's method still works, the query grows really big and complex because I need to use all the JOINs and WHERE in the JOINed (called x in his query) sub request. Thanks for your time!

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  • Buddy List: Relational Database Table Design

    - by huntaub
    So, the modern concept of the buddy list: Let's say we have a table called Person. Now, that Person needs to have many buddies (of which each buddy is also in the person class). The most obvious way to construct a relationship would be through a join table. i.e. buddyID person1_id person2_id 0 1 2 1 3 6 But, when a user wants to see their buddy list, the program would have to check the column 'person1_id' and 'person2_id' to find all of their buddies. Is this the appropriate way to implement this kind of table, or would it be better to add the record twice.. i.e. buddyID person1_id person2_id 0 1 2 1 2 1 So that only one column has to be searched. Thanks in advance.

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  • how can I get data in the table cell that is checked after submit

    - by arnold
    can someone give me help, please. here's my basic html <form action="addSomething.php" method="POST"> <table> <tr> <th>Add Data</th> <th>Description</th> <th>Quantity</th> </tr> <tr> <td><input type="checkbox" name="data[]" value="sample1" /> </td> <td class="desc">Newbie</td> <td>2</td> </tr> <tr> <td><input type="checkbox" name="data[]" value="sample1" /> </td> <td class="desc">Pro</td> <td>1</td> </tr> <tr> <td><input type="checkbox" name="data[]" value="sample1"/> </td> <td class="desc" > Master </td> <td>1</td> </tr> <br/> <input type="submit" name="add" value="SUBMIT"/> ..... how can I get the one with the class "desc" and the column for quantity that is checked after submitting the form because the only I can add when querying in mysql is the value of checkbox but I want also the value of the data in "Description" column and "Quantity" column In my addSomething.php the code I have is if(isset($_POST['add'])) { foreach($_POST['data'] as $value) { $sql = "INSERT INTO tablename (column1) VALUES('$value');" //query stuff } } what I will do , Any hints guys?

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  • Binding Linq To Entities query results to a datagridview

    - by Nickson
    I just started playing with Linq to entities in a windows forms application and am not understanding one behavior that looks so simple though. If i type code below, i get ReadOnly records in my dataGridView Dim x = From n in Table1 _ Select n.FirstName, n.LastName, N.Department DataGridView1.DataSource = x But if i type the following code, i get editable rows in my dataGridView Dim x = From n in Table1 _ Select n DataGridView1.DataSource = x So, basically if i specify the column names to select and databind to my DataGridView1, the rows are readonly but if i do not specify the column names and databind to the DataGridView, the rows are editable and i don't understand why.

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  • nhibernate : One to One mapping

    - by frosty
    I have the following map. I wish to map BasketItem to the class "Product". So basically when i iterate thru the basket i can get the product name <class name="BasketItem" table="User_Current_Basket"> <id name="Id" type="Int32" column="Id" unsaved-value="0"> <generator class="identity"/> </id> <property name="ProductId" column="Item_ID" type="Int32"/> <one-to-one name="Product" class="Product"></one-to-one> </class> How do specifiy that product should match BasketItem.ProductId with Product.Id Also i've read that i should avoid one-to-one and just use one-to-many? If i was to do that how do i ensure i just get one product and not a collection.

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  • Unique identifiers for users

    - by Christopher McCann
    If I have a table of a hundred users normally I would just set up an auto-increment userID column as the primary key. But if suddenly we have a million users or 5 million users then that becomes really difficult because I would want to start becoming more distributed in which case an auto-increment primary key would be useless as each node would be creating the same primary keys. Is the solution to this to use natural primary keys? I am having a real hard time thinking of a natural primary key for this bunch of users. The problem is they are all young people so they do not have national insurance numbers or any other unique identifier I can think of. I could create a multi-column primary key but there is still a chance, however miniscule of duplicates occurring. Does anyone know of a solution? Thanks

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