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  • C#:checking existing record in database Mysql

    - by Meko
    HI.I searched this question inform and I found solution to change column property Unique Index.Now If I try to insert same record cmd.ExecuteNonQuery() gives error that record exist ,but how can use this exception to give user a message that record exist and must enter new one ? I am trying to make some thing like if(cmd.ExecuteNonQuery() !=true ) { MessageBox.Show("User Exists"); } But I dont know what returns cmd.ExecuteNonQuery() ? Or I must get records using reader in table and compare them with text in Textfiel?

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  • Storing apostrophes, exclamation marks, etc. in mysql database

    - by rein
    I changed from latin1 to utf8. Although all sorts of text was displaying fine I noticed non-english characters were stored in the database as weird symbols. I spent a day trying to fix that and finally now non-english characters display as non-english characters in the database and display the same on the browser. However I noticed that I see apostrophes stored as &#39; and exclamation marks stored as &#33;. Is this normal, or should they be appearing as ' and ! in the database instead? If so, what would I need to do in order to fix that?

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  • mysql inserts & updates optimized

    - by user271619
    This is an optimization question, mostly. I have many forms on my sites that do simple Inserts and Updates. (Nothing complicated) But, several of the form's input fields are not necessary and may be left empty. (again, nothing complicated) However, my SQL query will have all columns in the Statement. My question, is it best to optimize the Inserts/Update queries appropriately? And only apply the columns that are changed into the query? We all hear that we shouldn't use the "SELECT *" query, unless it's absolutely needed for displaying all columns. But what about Inserts & Updates? Hope this makes sense. I'm sure any amount of optimization is acceptable. But I never really hear about this, specifically, from anyone.

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  • MySQL Casting in C#

    - by user798080
    Okay, so I'm attempting to print out the contents of a table in a comma-separated file. using (OdbcCommand com = new OdbcCommand("SELECT * FROM pie_data WHERE Pie_ID = ?", con)) { com.Parameters.AddWithValue("", Request.Form["pie_id"]); com.ExecuteNonQuery(); using (OdbcDataReader reader = com.ExecuteReader()) { string finalstring = ""; while (reader.Read()) { finalstring = reader.GetString(9) + ","; for (int i = 0; i <= 8; i = i + 1) { finalstring = finalstring + reader.GetString(i) + ","; } } } Response.Write(finalstring); noredirect = 1; } My table layout is: CREATE TABLE `rent_data` ( `Pies` INT(10) UNSIGNED NOT NULL, `Name` VARCHAR(85) NOT NULL, `Email` VARCHAR(85) NOT NULL, `Pie_Rent` DATE NOT NULL, `Rent_To` DATE NOT NULL, `Returned_Date` DATE NULL DEFAULT NULL, `Place` VARCHAR(100) NOT NULL, `Purpose` MEDIUMTEXT NOT NULL, `Comments` MEDIUMTEXT NULL, `Pie_ID` SMALLINT(5) UNSIGNED ZEROFILL NOT NULL, INDEX `Pie_ID` (`Equipment_ID`) ) The error I'm getting is this: Exception Details: System.InvalidCastException: Unable to cast object of type 'System.Int64' to type 'System.String'. On the line: finalstring = finalstring + reader.GetString(i) + ",";

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  • Displaying name instead of ID PHP MySQL

    - by Derek
    Hi, I need something simple; I have page where a user clicks an author to see the books associated with that author. On my page displaying the list of books for the author, I want a simple HTML title saying: 'The books for: AUTHORNAME' I can get the page to display author ID but not the name. When the user clicks the link in the previous page of the author, it looks likes this: <a href="viewauthorbooks.php?author_id=<?php echo $row['author_id']?>"><?php echo $row['authorname']?></a> And then on the 'viewauthorbooks.php?author_id=23' I have declared this at the start: $author_id = $_GET['author_id']; $authorname = $_GET['authorname']; And finally, 'The books for: AUTHORNAME, where it says AUTHORNAME, I have this: echo $authorname (With PHP tags, buts its not letting me put them in!) And this doesnt show anything, however if I change it to author_id, it displays the correct author ID that has been clicked, but its not exactly user friendly!! Can anyone help me out!

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  • Help needed with simple mysql group by query

    - by Jack
    This query fails when I add the line shown... :BEGIN FAIL: I have this so far Select Companyid, count(*) as cnt from mytable where State is not null and cnt = 1 <------------------------- FAIL group by CompanyID :END FAIL: Any way to do this? Here's a long winded background if it'll help.... I have a single table query. here's a sample of the table: CompanyID, State 1,OH 1,IL 1,NY 2,IL 3,NY 3,OH 4,NY 5,CA 5,WA I want a query that'll return something like this: 2,IL 4,NY I have this so far Select Companyid, count(*) as cnt from mytable where State is not null group by CompanyID This gives me a count of the number of records for each company. IE: 1,3 2,1 3,2 4,1 5,2 Now I want to filter the above list to just the two records with one result. I tried adding another where clause, but it failed: BEGIN FAIL: I have this so far Select Companyid, count(*) as cnt from mytable where State is not null and cnt = 1 <-------------------- FAIL group by CompanyID END FAIL:

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  • MySQL Join Comma Separated Field

    - by neeraj
    I have two tables. First Table is a batch table that contain comma separated student id in field "batch" batch -------------- id batch -------------- 1 1,2 2 3,4 Second Table is marks marks ---------------------- id studentid subject marks 1 1 English 50 2 2 English 40 3 3 English 70 4 1 Math 65 5 4 English 66 6 5 English 75 7 2 Math 55 How we can find those students of first batch id =1 who have scored more than 45 marks in English without using sub query. Problem i found to get this done using a single query is that we can not use IN as an association operator in JOIN statement What changes are required in below query to make it work? SELECT * FROM batch INNER JOIN marks ON marks.studentid IN(batch.batch) where batch.id = 1

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  • PHP & MySQL checked checkbox problem

    - by BeepU
    I'm trying to check if the checkbox has been checked and display the check mark for the user to see when they check there account settings. I want to know how can I fix this problem using PHP so that the check mark is displayed every time the user views their account settings? Here is the HTML. <input type="checkbox" name="privacy_policy" id="privacy_policy" value="yes" />

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  • formatting mysql data for ouptut into a table

    - by bsandrabr
    Following on from a question earlier today this answer was given to read the data into an array and separate it to print vehicle type and then some data for each vehicle. <?php $sql = "SELECT * FROM apparatus ORDER BY vehicleType"; $getSQL = mysql_query($sql); // transform the result set: $data = array(); while ($row = mysql_fetch_assoc($getSQL)) { $data[$row['vehicleType']][] = $row; } ?> <?php foreach ($data as $type => $rows): ?> <h2><?php echo $type?></h2> <ul> <?php foreach ($rows as $vehicleData):?> <li><?php echo $vehicleData['name'];?></li> <?php endforeach ?> </ul> <?php endforeach ?> This is almost perfect for what I want to do but I need to print out two columns from the database ie ford and mondeo before going into the second foreach loop. I've tried print $rows['model'] and all the other combinations I can think of but that doesn't work. Any help much appreciated

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  • Using NULL in MySQL

    - by JPro
    The data in my dabatase comes from an external source and where ever there is no data passed, I keep NULL in those places. Can anyone tell me if there are any implications in using NULL to represent empty value? Should I follow some other convention like 'data_not_available'? or something like that? Can anyone suggest?

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  • mysql join on two indexes takes long time!!

    - by Alaa
    Hi All I have a custom query in dripal, this query is: select count(distinct B.src) from node A, url_alias B where concat('node/',A.nid)= B.src; now, nid in node is primary key and i have made src as an index in url_alias table. after waiting for more than a minute i got this: +-----------------------+ | count(distinct B.src) | +-----------------------+ | 325715 | +-----------------------+ 1 row in set (1 min 24.37 sec) now my question is: why did this query take this long, and how to optimize it?? Thanks for your help

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  • Best way to limit results in MySQL with user subcategories

    - by JM4
    I am trying to essentially solve for the following: 1) Find all users in the system who ONLY have programID 1. 2) Find all users in the system who have programID 1 AND any other active program. My tables structures (in very simple terms are as follows): users userID | Name ================ 1 | John Smith 2 | Lewis Black 3 | Mickey Mantle 4 | Babe Ruth 5 | Tommy Bahama plans ID | userID | plan | status --------------------------- 1 | 1 | 1 | 1 2 | 1 | 2 | 1 3 | 1 | 3 | 1 4 | 2 | 1 | 1 5 | 2 | 3 | 1 6 | 3 | 1 | 0 7 | 3 | 2 | 1 8 | 3 | 3 | 1 9 | 3 | 4 | 1 10 | 4 | 2 | 1 11 | 4 | 4 | 1 12 | 5 | 1 | 1 I know I can easily find all members with a specific plan with something like the following: SELECT * FROM users a JOIN plans b ON (a.userID = b.userID) WHERE b.plan = 1 AND b.status = 1 but this will only tell me which users have an 'active' plan 1. How can I tell who ONLY has plan 1 (in this case only userID 5) and how to tell who has plan 1 AND any other active plan? Update: This is not to get a count, I will actually need the original member information, including all the plans they have so a COUNT(*) response may not be what I'm trying to achieve.

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  • JQuery Ajax Updating MySQL Database, But Not Running Success Function

    - by myrmidon16
    I am currently using the JQuery ajax function to call an exterior PHP file, in which I select and add data in a database. Once this is done, I run a success function in JavaScript. What's weird is that the database is updating successfully when ajax is called, however the success function is not running. Here is my code: <!DOCTYPE html> <head> <script type="text/javascript" src="jquery-1.6.4.js"></script> </head> <body> <div onclick="addtask();" style="width:400px; height:200px; background:#000000;"></div> <script> function addtask() { var tid = (Math.floor(Math.random() * 3)) + 1; var tsk = (Math.floor(Math.random() * 10)) + 1; if(tsk !== 1) { $.ajax({ type: "POST", url: "taskcheck.php", dataType: "json", data: {taskid:tid}, success: function(task) {alert(task.name);} }); } } </script> </body> </html> And the PHP file: session_start(); $connect = mysql_connect('x', 'x', 'x') or die('Not Connecting'); mysql_select_db('x') or die ('No Database Selected'); $task = $_REQUEST['taskid']; $uid = $_SESSION['user_id']; $q = "SELECT task_id, taskname FROM tasks WHERE task_id=" .$task. " LIMIT 1"; $gettask = mysql_fetch_assoc(mysql_query($q)); $q = "INSERT INTO user_tasks (ut_id, user_id, task_id, taskstatus, taskactive) VALUES (null, " .$uid. ", '{$gettask['task_id']}', 0, 1)"; $puttask = mysql_fetch_assoc(mysql_query($q)); $json = array( "name" => $gettask['taskname'] ); $output = json_encode($json); echo $output; Let me know if you have any questions or comments, thanks.

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  • MySQL: Select pages that are not tagged?

    - by lauthiamkok
    Hi, I have a db with two tables like these below, page table pg_id title 1 a 2 b 3 c 4 d tagged table tagged_id pg_id 1 1 2 4 I want to select the pages which are tagged, I tried with this query below but doesn't work, SELECT * FROM root_pages LEFT JOIN root_tagged ON ( root_tagged.pg_id = root_pages.pg_id ) WHERE root_pages.pg_id != root_tagged.pg_id It returns zero - Showing rows 0 - 1 (2 total, Query took 0.0021 sec) But I want it to return pg_id title 2 b 3 c My query must have been wrong?? How can I return the pages which are not tagged correctly? Thanks.

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  • MySQL whats wrong with my foreign keys?

    - by Skiy
    Hello, what is wrong with the two foreign keys which I have marked with comments? create database db; use db; create table Flug( Flugbez varchar(20), FDatum Date, Ziel varchar(20), Flugzeit int, Entfernung int, Primary Key (Flugbez, FDatum)); create table Flugzeugtyp( Typ varchar(20), Hersteller varchar(20), SitzAnzahl int, Reisegeschw int, primary key (Typ) ); create table flugzeug( Typ varchar(20), SerienNr int, AnschDatum Date, FlugStd int, primary key(Typ,SerienNr), foreign key(Typ) references Flugzeugtyp(Typ)); create table Abflug( Flugbez varchar(20), FDatum Date, Typ varchar(20), Seriennr int, Kaptaen varchar(20), Primary key(Flugbez,FDatum,Typ,SerienNr), Foreign key(Flugbez) references Flug(Flugbez), -- Foreign key(FDatum) references Flug(FDatum), Foreign key(Typ) references Flugzeugtyp(Typ) -- ,Foreign key(SerienNr) references Flugzeug(SerienNr) ); When I uncomment these, I get: ERROR 1005 (HY000): Can't create table 'db.abflug' (errno: 150)

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  • Connect to web-service/API in MySQL?

    - by Jesse Figueroa
    I'm creating a sql based procedure which can Accept a table load the values one at a time send the variables to a remote API Record the response of the API Write the response to a table for viewing later I have successfully implemented 1,2, and 5. I am hoping there may be some way of choosing an address to contact and for SQL to listen too for a response. Please let me know if you have any suggestions!

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  • incrementing a table column's data by one || mySql

    - by Praveen Prasad
    iam having a table with columns like id || counter if i do something (some event) i want the counter's value(at a particular id) to increase by one , currently iam doing this : //get current value current_value = select counter from myTable where id='someValue' // increase value current_value++ //update table with current value update myTable set counter=current_value where id='someValue'; currently iam running 2 queries for this, please suggest me some way do it in one step.

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  • Entering Content Into A MySQL Database Via A Form

    - by ThatMacLad
    I've been working on creating a form that submits content into my database but I decided that rather than using a drop down menu to select the date I'd rather use a textfield. I was wondering what changes I will need to make to my table creation file. <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "CREATE TABLE php_blog ( id int(20) NOT NULL auto_increment, timestamp int(20) NOT NULL, title varchar(255) NOT NULL, entry longtext NOT NULL, PRIMARY KEY (id) )"; $result = mysql_query($sql) or print ("Can't create the table 'php_blog' in the database.<br />" . $sql . "<br />" . mysql_error()); mysql_close(); if ($result != false) { echo "Table 'php_blog' was successfully created."; } ?> It's the timestamp that I need to edit to enter in via a textfield. The Title and Entry are currently being entered via that method anyway.

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  • Generate MySQL data dump in SQL from PHP

    - by Álvaro G. Vicario
    I'm writing a PHP script to generate SQL dumps from my database for version control purposes. It already dumps the data structure by means of running the appropriate SHOW CREATE .... query. Now I want to dump data itself but I'm unsure about the best method. My requirements are: I need a record per row Rows must be sorted by primary key SQL must be valid and exact no matter the data type (integers, strings, binary data...) Dumps should be identical when data has not changed I can detect and run mysqldump as external command but that adds an extra system requirement and I need to parse the output in order to remove headers and footers with dump information I don't need (such as server version or dump date). I'd love to keep my script as simple as I can so it can be hold in an standalone file. What are my alternatives?

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