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  • How can i initialise a server on startup?

    - by djerry
    Hey all, I need to make some connections on startup of a server. I'm using the wcf technology for this client-server application. The problem is that the constructor of the server isn't called at any time, so for the moment, i initialize the connections when the first client makes a connection. But this generates problems in a further part. This is my server setup: private static ServiceHost _svc; static void Main(string[] args) { NetTcpBinding binding = new NetTcpBinding(SecurityMode.Message); Uri address = new Uri("net.tcp://localhost:8000"); _svc = new ServiceHost(typeof(MonitoringSystemService), address); publishMetaData(_svc, "http://localhost:8001"); _svc.AddServiceEndpoint(typeof(IMonitoringSystemService), binding, "Monitoring Server"); _svc.Open(); Console.WriteLine("Listener service gestart op net.tcp://localhost:8000/Monitoring"); Console.ReadLine(); } private static void publishMetaData(ServiceHost svc, string sEndpointAddress) { ServiceMetadataBehavior smb = svc.Description.Behaviors.Find<ServiceMetadataBehavior>(); if (smb != null) { smb.HttpGetEnabled = true; smb.HttpGetUrl = new Uri(sEndpointAddress); } else { smb = new ServiceMetadataBehavior(); smb.HttpGetEnabled = true; smb.HttpGetUrl = new Uri(sEndpointAddress); svc.Description.Behaviors.Add(smb); } } How can i start the server without waiting for a client to logon so i can initialize it. Thanks in advance.

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  • What should I use to replace the WinAPI Beep() function?

    - by Jon Cage
    I've got a Visual C++/CLI app which uses beeps to signify good and bad results (used when the user can't see the screen). Currently I use low pitched beeps for bad results and high pitched beeps for good results: if( goodResult == true ) { Beep(1000, 40); } else { Beep(2000, 20); } This works okay on my Vista laptop, but I've tried it on other laptops and some seem to play the sounds for less time (they sound more like clicks than beeps) or the sound doesn't play at all. So I have two questions here: Is there a more reliable beep function? Is there a (simple) way I can play a short .wav file or something similar instead (preferred solution).

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  • Move an object in the direction of a bezier curve?

    - by Sent1nel
    I have an object with which I would like to make follow a bezier curve and am a little lost right now as to how to make it do that based on time rather than the points that make up the curve. .::Current System::. Each object in my scene graph is made from position, rotation and scale vectors. These vectors are used to form their corresponding matrices: scale, rotation and translation. Which are then multiplied in that order to form the local transform matrix. A world transform (Usually the identity matrix) is then multiplied against the local matrix transform. class CObject { public: // Local transform functions Matrix4f GetLocalTransform() const; void SetPosition(const Vector3f& pos); void SetRotation(const Vector3f& rot); void SetScale(const Vector3f& scale); // Local transform Matrix4f m_local; Vector3f m_localPostion; Vector3f m_localRotation; // rotation in degrees (xrot, yrot, zrot) Vector3f m_localScale; } Matrix4f CObject::GetLocalTransform() { Matrix4f out(Matrix4f::IDENTITY); Matrix4f scale(), rotation(), translation(); scale.SetScale(m_localScale); rotation.SetRotationDegrees(m_localRotation); translation.SetTranslation(m_localTranslation); out = scale * rotation * translation; } The big question I have are 1) How do I orientate my object to face the tangent of the Bezier curve? 2) How do I move that object along the curve without just setting objects position to that of a point on the bezier cuve? Heres an overview of the function thus far void CNodeControllerPieceWise::AnimateNode(CObject* pSpatial, double deltaTime) { // Get object latest pos. Vector3f posDelta = pSpatial->GetWorldTransform().GetTranslation(); // Get postion on curve Vector3f pos = curve.GetPosition(m_t); // Get tangent of curve Vector3f tangent = curve.GetFirstDerivative(m_t); } Edit: sorry its not very clear. I've been working on this for ages and its making my brain turn to mush. I want the object to be attached to the curve and face the direction of the curve. As for movement, I want to object to follow the curve based on the time this way it creates smooth movement throughout the curve.

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  • Delay in the implementation of text change in Statusbar control

    - by ehsan zeynali
    I have a function a time consuming operation that is done I want to start and end operations appear to be user (By statusbar control) But when performed function, both text executed at the end of function. (user can not sees "Start Operation ...") What solution do you recommend to me? private void btnUpdateDataBase_Click(object sender, RoutedEventArgs e) { TextBlockStatus.Text = "Start Operation ..."; //Time consuming operation TextBlockStatus.Text = "End Operation ..."; }

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  • Setting Frame.Content doesn't always work

    - by dan gibson
    I have a Frame control and I'm setting the Content property. If I set it twice, first to one control then to another, it shows the first control instead of the second. If I display a message box after setting it the first time then it works fine (ie it displays the second control). It's like I can only set Content once until the screen has been repainted. Calling Frame.UpdateLayout also doesn't help. What should I call after setting Content so that I can be sure that Content is actually set to what I specify?

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  • Can you view XAML as "regular" .net code (c#\vb.net)?

    - by cody
    There are times when I find some example XAML that I want\need to do in code (c#\vb.net). I assume at some point the XAML becomes code, or at least IL. So my questions: Am I correct in assuming that XAML is converted to IL? (or if not IL what does it become?) If the above is correct, when does XAML become IL (or whatever it becomes)? Is there some way to see the XAML in as "code" Thanks.

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  • Setting a DataGrid background color based on the previous row

    - by Zipper
    I'm trying to setup a grid where I do column sorting, but I wanted to do zebra striping, only rather than every other row or every x rows, I want it to be based on the value of cells. i.e. All cells that contain 0 have a blue background, the next value would have a white background, the next value would be blue, etc.... The problem I have is that I can't seem to find where to actually do the setting of the background colors. I'm using a custom sorter and I tried setting it in there after I re-order the list and set the data source, but it appears that when the data source is set, that the rows don't exist yet. I tried using the DataContextChanged, but that event doesn't seem to be firing. Here is what I have now. namespace Foo.Bar { public partial class FooBar { List<Bla> ResultList { get; set; } SolidColorBrush stripeOneColor = new SolidColorBrush(Colors.Gold); SolidColorBrush stripeTwoColor = new SolidColorBrush(Colors.White); //********************************************************************************************* public Consistency() { InitializeComponent(); } //********************************************************************************************* override protected void PopulateTabWithData() { ResultList = GetBlas(); SortAndGroup("Source"); } //********************************************************************************************* private void SortAndGroup(string colName) { IOrderedEnumerable <Bla> ordered = null; switch (colName) { case "Source": case "ID": ordered = ResultList.OrderBy(r => r.Source).ThenBy(r => r.ID); break; case "Name": ordered = ResultList.OrderBy(r => r.Source).ThenBy(r => r.Name); break; case "Message": ordered = ResultList.OrderBy(r => r.Message); break; default: throw new Exception(colName); } ResultList = ordered.ThenBy(r => r.Source).ThenBy(r => r.ID).ToList(); // tie-breakers consistencyDataGrid.ItemsSource = null; consistencyDataGrid.ItemsSource = ResultList; ColorRows(); } //********************************************************************************************* private void consistencyDataGrid_Sorting(object sender, System.Windows.Controls.DataGridSortingEventArgs e) { SortAndGroup(e.Column.Header.ToString()); e.Handled = true; } private void ColorRows() { for (var i = 0; i < ResultList.Count; i++) { var currentItem = ResultList[i]; var row = myDataGrid.ItemContainerGenerator.ContainerFromItem(currentItem) as DataGridRow; if (row == null) { continue; } if (i > 0) { var previousItem = ResultList[i - 1]; var previousRow = myDataGrid.ItemContainerGenerator.ContainerFromItem(previousItem) as DataGridRow; if (currentItem.Source == previousItem.Source) { row.Background = previousRow.Background; } else { if (previousRow.Background == stripeOneColor) { row.Background = stripeTwoColor; } else { row.Background = stripeOneColor; } } } else { row.Background = stripeOneColor; } } } } } }

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  • How to get the text with in the datatemplate?

    - by rakish
    I have used below code <DataTemplate x:Key="myTemplate"> <TextBlock Text="Hi"></TextBlock> </DataTemplate> in this case i can able to get the textblock text by using below code DataTemplate myTemplate = this.Resources["myTemplate"] as DataTemplate; TextBlock rootElement = myTemplate.LoadContent() as TextBlock; //I can get the text "rootElement.text " but when i use binding means i cant able to get the text <DataTemplate x:Key="myTemplate"> <TextBlock Text="{Binding EmployeeName}"></TextBlock> </DataTemplate>

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  • How to set ItemsSource?

    - by Mark
    This dialog makes no sense to me And I'm having trouble finding good tutorials on it. Most of the examples aren't detailed enough, or do stuff via code, but I'd like to take advantage of the IDE as much as possible. Whats the difference between ItemsSource and DataContext? I'd like to bind it to just a List for starters. I don't need SQL or databases or anything fancy. Where would I declare my list? In MainWindow.xaml.cs? How do I get it to appear in that dialog?

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  • DataTemplate / ContentTemplate - exchange controls

    - by Scott Olson
    How can i solve the following (simplified) problem? M-V-VM context. I want to show text at the UI. In case the user has the rights to change the text, i want to use a textbox to manipulate the text. In case the user has no rights, i want to use a label to only show the text. My main problem: how to exchange textbox and label and bind Text resp. Content to the same property in viewmodel. Thanks for your answers Toni

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  • connecting to multiple resources

    - by Dudu
    I would like to know if there is a way to connect to multiple resources: Specifically I have the following problem abstact class BaseClass { ObservableCollection<BaseClass>; } class GrandSonClass:BaseClass{} class SonClass:BaseClass{} class FatherClass:BaseClass { CollectionViewSource col = new CollectionViewSource ; col.Source = Items.SelectMany(p => p.Items); } FatherClass's Items are of ChildrenClass type, and ChildrenClass's Items are of GrandSonClass type; I want FatherClass to bind to all the GrandSonClass's items it possesses. The solution of using SelectMany is not good as I need this to be dynamically updated whenever FatherClass adds more Items and whenever its Items(SonClasses) add more Items. Now I could go on and write notifiaction events but I was wondering if there is a smarter way to do it -i.e. simply define the sources as the Items of each Item FatherClass posses

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  • C# Read Byte [] to Image

    - by LucasGuitar
    I have an application which I'm adding pictures and these are automatically converted to binary and stored in a single file. how can I save several images, I keep in an XML file start and size of each set of refente to an image byte. But it has several images in bytes, whenever I try to select a different set of bytes just opening the same image. I would like your help to be able to fix this and open different images. Code //Add Image private void btAddImage_Click(object sender, RoutedEventArgs e) { OpenFileDialog op = new OpenFileDialog(); op.Title = "Selecione a Imagem"; op.Filter = "All supported graphics|*.jpg;*.jpeg;*.png|" + "JPEG (*.jpg;*.jpeg)|*.jpg;*.jpeg|" + "Portable Network Graphic (*.png)|*.png"; if (op.ShowDialog() == true) { imgPatch.Source = new BitmapImage(new Uri(op.FileName)); txtName.Focus(); } } //Convert Image private void btConvertImage_Click(object sender, RoutedEventArgs e) { if (String.IsNullOrEmpty(txtName.Text)) { txtName.Focus(); MessageBox.Show("Preencha o Nome", "Error"); } else { save(ConvertFileToByteArray(op.FileName), txtName.Text); } } //Image to Byte Array private static byte[] ConvertFileToByteArray(String FilePath) { return File.ReadAllBytes(FilePath); } //Save Binary File and XML File public void save(byte[] img, string nome) { FileStream f; long ini, fin = img.Length; if (!File.Exists("Escudos.bcf")) { f = new FileStream("Escudos.bcf", FileMode.Create); ini = 0; } else { f = new FileStream("Escudos.bcf", FileMode.Append); ini = f.Length + 1; bin = new TestBinarySegment(); } bin.LoadAddSave("Escudos.xml", "Brasileiro", nome, ini, fin); BinaryWriter b = new BinaryWriter(f); b.Write(img); b.Close(); f.Dispose(); } //Load Image from Byte private void btLoad_Click(object sender, RoutedEventArgs e) { getImageFromByte(); } //Byte to Image public void getImageFromByte(int start, int length) { using (FileStream fs = new FileStream("Escudos.bcf", FileMode.Open)) { byte[] iba = new byte[fs.Length+1]; fs.Read(iba, start, length); Image image = new Image(); image.Source = BitmapFrame.Create(fs, BitmapCreateOptions.None, BitmapCacheOption.OnLoad); imgPatch2.Source = image.Source; } }

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  • How can I get my UserControl to look like a ComboBox?

    - by NoLuke
    I have a user control containing a TextBox, ToggleButton and Popup, just like the real ComboBox. Now my problem is to style it so that it looks just like the normal ComboBox. In Blend, I can "Edit Template/Edit a Copy..." of a real ComboBox to get the bits and pieces I need to get it to look right. For one Windows theme (Aero). If the application is run on another theme (e.g Luna), the control does not change its look, it still has the Aero look. Do I have to supply a style/template for each Windows theme, or can I somehow get hold of (at run-time) the default ComboBox style and apply it to my UserControl? Instead of making a UserControl, I have tried modifying a real ComboBox to my needs, but I just couldn't get it to work. How can I replace ALL the logic of a ComboBox with my own?

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  • Not able to select a row in my ListView

    - by Krishna Thota
    I'm not able to select a row in my list Item Here is my code <Grid DockPanel.Dock="Left" MinWidth="250"> <ListView x:Name="ListVendors" ItemsSource="{Binding SourceCollection}"> <ListView.View> <GridView> <GridView.ColumnHeaderContainerStyle> <Style><Setter Property="FrameworkElement.Visibility" Value="Collapsed"/></Style> </GridView.ColumnHeaderContainerStyle> <GridViewColumn> <GridViewColumn.CellTemplate> <DataTemplate> <Grid> <Grid.RowDefinitions> <RowDefinition /> <RowDefinition /> <RowDefinition /> </Grid.RowDefinitions> <TextBlock Grid.Row="0" Text="{Binding Name}" FontSize="20"/> <TextBlock Grid.Row="1" Text="{Binding Code}" Foreground="Gray" /> <TextBlock Grid.Row="2" Text="{Binding ContactNo}" Foreground="Gray" /> </Grid> </DataTemplate> </GridViewColumn.CellTemplate> </GridViewColumn> <GridViewColumn> <GridViewColumn.CellTemplate> <DataTemplate> <Grid> <Grid.RowDefinitions> <RowDefinition /> </Grid.RowDefinitions> <TextBlock Grid.Row="0" Text="{Binding Path=Address, Converter={StaticResource addNewLineConv}}" Grid.RowSpan="3" /> </Grid> </DataTemplate> </GridViewColumn.CellTemplate> </GridViewColumn> <GridViewColumn> <GridViewColumn.CellTemplate> <DataTemplate> <Grid> <Grid.RowDefinitions> <RowDefinition /> </Grid.RowDefinitions> <TextBlock Grid.Row="2" Text="{Binding Email}"/> </Grid> </DataTemplate> </GridViewColumn.CellTemplate> </GridViewColumn> <GridViewColumn DisplayMemberBinding="{Binding Email}" Header="Email"/> </GridView> </ListView.View> </ListView> How can I select a row in this ListView?

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  • disabling a window

    - by Arno Greiler
    In my application I have a button. If the button is clicked as select against a database is executed and the result is shown in a ListView. As the select is quite complex, it takes some time to retrieve the data. When I click the Button, the Application-Window should be disabled until the data is loaded. But when I set the IsEnabled-Property of the Window to false, the Window gets disabled after the data is loaded. I tried to disable the Window in an other thread with a BackgroundWorker. But then I get an exception that the Window is alreay in use by an other thread. How can I disable the Window bevore it retrieves the data?

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  • DirectX capabilities on different graphics cards

    - by user9876
    I'm writing a Direct3D application, using DirectX 9. Although it works on my PC, I need to make it work on a wide range of systems. I need to know what capabilities I can expect to see on other systems. Is there a list of the DirectX capabilities that graphics cards support? I've found one site, which I'll post as an answer, but it's a bit out of date.

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  • sqlite3 not found but it was already added as reference

    - by Joef Clarin
    System.DllNotFoundException was unhandled Message=Unable to load DLL 'sqlite3': The specified module could not be found. I already reference the DLL. I check it on Debug folder and it was there. I also search how to "include" it in the project but they don't specifically explain how to do it. I'm following this example: http://www.codeproject.com/Articles/22165/Using-SQLite-in-your-C-Application

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  • How do you escape parentheses in a Binding indexer

    - by Chris S
    I have the following XAML: <Grid x:Name="LayoutRoot" Background="White" DataContext="{Binding Source={StaticResource MyDataKey}}"> <TextBox Name="_myId" Text="{Binding MyDictionary[(Textbox.Name)]" /> </Grid> But it thinks the key in my dictionary is called "(Textbox.Name)", instead of "_myId". The format below works, where I have a property in my class called "_myId": <TextBox Name="_myId" Text="{Binding (Textbox.Name)" /> I've tried using ^ and \ to escape the brackets. Is this syntax supported? I'm trying to avoid duplication of the name in two attributes.

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  • how to generate an N level tree using datatable?

    - by Kishore Kumar
    I have a DataTable with column ID, Name, RootID. The tree stucture is implmented using the RootId field. If the RootId is null it is considered as Root Node. How to create an Nlevel tree using the DataTale. eg. 1 Manager null, 2 Project Lead 1, 3 Test Lead 1, 4 Sr Soft Eng 2, 5 Soft eng 2, 6 HR Manager Null, 7 HR exec 6, ......

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