Search Results

Search found 8279 results on 332 pages for 'django permissions'.

Page 22/332 | < Previous Page | 18 19 20 21 22 23 24 25 26 27 28 29  | Next Page >

  • File permissions issue with an NFSv4 share, uploaded from a Mac Lion

    - by POP.sicle
    I have an NFSv4 share that was working fine, with Macs using Snow Leopard, to share files across the network. The NFS share has one cloned user/group that all clients autoconnect as. However, when I use a Lion Mac to copy a file from their user directory to the NFS, no other computer (mac SL/mac Lion/Win7) can edit/delete/write to the file that was uploaded - despite having the correct read/write/ex permissions visible on the NFS and through terminal. Attempting to edit the file permissions through Finder completely locks the file. I suspect this has something to do with Lion's ACLs (or maybe its version control) conflicting with NFSv4. Is there a way to disable or ignore extended ACLs or extended file permissions on the NFSv4 side, that would allow users to not run into this conflict? The work around currently is to use NFS Manager and set automounts to ignore ownership but installing NFS manager and configuring automounts for all of the computers seems more troubling than attempting to reconfigure the NFS settings. Advice?

    Read the article

  • OS X clients ignoring Windows print server permissions

    - by Ilumiari
    I'm in the process of testing a Windows Server 2008 R2 print server for a mixed OS X/Windows environment. Any security permissions (AD groups) I set for the printers on the print server are not honoured by the OS X clients. Only if I remove absolutely all permissions for a given printer will an OS X client not print to that printer. The Windows clients honour the permissions as expected. The PrintService log doesn't record any activity when an unprivileged Windows client attempts to print, and records a typical print job when an unprivileged OS X client attempts to print. Has anyone encountered this problem before and have a fix? With 600-700 clients, a number of which are dual-booting, restricting by IP address is not viable. EDIT: The jobs are definitely going through the print server, they show up in the logs with their AD credentials.

    Read the article

  • PHP + IIS Application Pool Identity Windows\Temp permissions

    - by Matt Boothman
    I am currently running PHP (5.3) on IIS 7.5 on a Win2k8 R2 Web Edition Server and would like to know what, if any, problems or security vulnerabilities I may introduct into a system by assigning Read, Write, Modify & Execute permissions to either IUSR account or the IIS_USERS group for %SystemRoot%\Temp? Should I be altering permissions to that folder at all (as Windows reminds me I probably shouldn't when i attempt to change them)? Should I create a temp folder somewhere else and set permissions accordingly? The problem is when i set Anonymous Authentication (I'm guessing is a more secure option???) to use the App Pool identity, when starting sessions PHP gets stuck in a loop because it's unable to create session files in the %SystemRoot%\Temp folder due to lack of permission on the application pool user or IIS_USERS group. Another problem being ImageMagick (PHP Extension) is being denied access to %SystemRoot%\Temp to write temporary files so is throwing exceptions. I have tried searching Google however have not found anything that touches upon this subject specifically. Any help greatly appreciated.

    Read the article

  • Grant user from one domain permissions to shared folder in another domain

    - by w128
    I have two computers set up like this: \\myPC (local Windows 7 SP1 machine); it is in domain1; \\remotePC (Win Server 2008 with SQL Server - a HyperV virtual machine); it is in domain2. In domain2 active directory, I have a user account RemoteAccount. I would like to give this account full permissions to a shared folder located on \\myPC, i.e. folder \\myPC\SharedFolder. The problem is, when I right-click the folder and go to sharing permissions, I can't add permissions for the domain2\RemoteAccount user, because this user cannot be found - I can only see domain1 users. When I click 'Locations' in "Select users, computers, service accounts, or groups" dialog, I only see domain1. Is there a way to do this?

    Read the article

  • Problems setting Hyper-V permissions

    - by Drew Burchett
    I am using a Windows 2012 Hyper-V server to host some test PCs. Our support personnel should be able to take snapshots of these machines and roll a test machine back to a specific snapshot, but they should not have any other permissions. I have followed the directions in this article and, on suggestion of another article have added the specific AD group to the local Hyper-V Administrators group, but whenever one of them attempts to connect to the server to take a snapshot, they get an error stating that they do not have permission to connect to that server. I'm sure I'm missing something, but at this point I'm at a loss as to what that would be. Can anyone tell me how to properly set these permissions? edit: Per request I am attaching a screenshot of the permissions I have set for this group.

    Read the article

  • Server 2008 R2 file access permissions

    - by Napster100
    I'm finding it awkward to sort out permissions for file sharing and access on my LAN. I've created an account on the server node (as a normal user) and shared a drive that has 2 folders at the root, one is for personal file storage and the other shared files, if I connect to the shared area from a workstation running windows 7 and log-in using the account I created on the server, I can look through directories but can't look in some (which I wanted as I changed the permissions for that to happen), but my problem is although the permissions are set for this user account to have full control of the specific folder I can't create a folder in that area or upload files to that folder. Could someone explain why this is? Thanks in advanced

    Read the article

  • about Linux read/write only permissions

    - by Bimal
    My question looks similar to another thread: Linux directory permissions read write but not delete Here, I want to create a directory where I can give the permissions like: A user can create/upload any files. A user can re-upload and overwrite the files. A user cannot remove the file anymore. I am on CentOS 5.5, basic user only. How can I do that? Or is there any third party software that can be installed to do this? Or, create a new process which will lock the permissions right after a new file is uploaded via ssh?

    Read the article

  • Dynamically create and save image with Django and PIL/Django-Photologue

    - by Travis
    I want to generate a page of html with dynamic content and then save the result as an image as well as display the page to the user. So, user signs up to attend conference and gives their name and org. That data is combined with html/css elements to show what their id badge for the conference will look like (their name and org on top of our conference logo background) for preview. Upon approval, the page is saved on the server to an image format (PNG, PDF or JPG) to be printed onto a physical badge by an admin later. I am using Django and django-photologue powered by PIL. The view might look like this # app/views.py def badgepreview(request, attendee_id): u = User.objects.get(id=attendee_id) name = u.name org = u.org return render_to_response('app/badgepreview.html', {'name':name,'org':org,}, context_instance = RequestContext(request), ) The template could look like this {# templates/app/badgepreview.html #} {% extends "base.html" %} {% block page_body %} <div style='background:url(/site_media/img/logo_bg.png) no-repeat;'> <h4>{{ name }}</h4> <h4>{{ org }}</h4> </div> {% endblock %} simple, but how do I save the result? Or is there a better way to get this done?

    Read the article

  • Django upload failing on request data read error

    - by Jake
    Hi All, I've got a Django app that accepts uploads from jQuery uploadify, a jQ plugin that uses flash to upload files and give a progress bar. Files under about 150k work, but bigger files always fail and almost always at around 192k (that's 3 chunks) completed, sometimes at around 160k. The Exception I get is below. exceptions.IOError request data read error File "/usr/lib/python2.4/site-packages/django/core/handlers/wsgi.py", line 171, in _get_post self._load_post_and_files() File "/usr/lib/python2.4/site-packages/django/core/handlers/wsgi.py", line 137, in _load_post_and_files self._post, self._files = self.parse_file_upload(self.META, self.environ[\'wsgi.input\']) File "/usr/lib/python2.4/site-packages/django/http/__init__.py", line 124, in parse_file_upload return parser.parse() File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 192, in parse for chunk in field_stream: File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 314, in next output = self._producer.next() File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 468, in next for bytes in stream: File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 314, in next output = self._producer.next() File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 375, in next data = self.flo.read(self.chunk_size) File "/usr/lib/python2.4/site-packages/django/http/multipartparser.py", line 405, in read return self._file.read(num_bytes) When running locally on the Django development server, big files work. I've tried setting my FILE_UPLOAD_HANDLERS = ("django.core.files.uploadhandler.TemporaryFileUploadHandler",) in case it was the memory upload handler, but it made no difference. Does anyone know how to fix this?

    Read the article

  • Where does django look for sqlite3 installation/libraries?

    - by gath
    Am having a bit of a problem making my django application run in SUSE linux 9. I have Python2.5 installed well, Django 1.0 installed well. Am able to execute django command django-admin startproject fine But when i run the runserver command i get the error below. i have a folder with sqlite3, i can go in there and actually run the sqlite3* application, now am wondering where does Django look for the sqlite libraries? and how can i fix this? Validating models... Unhandled exception in thread started by <function inner_run at 0x2a96cb4f50> Traceback (most recent call last): File "/usr/local/lib/python2.5/site-packages/django/core/management/commands/runserver.py", line 48, in inner_run self.validate(display_num_errors=True) File "/usr/local/lib/python2.5/site-packages/django/core/management/base.py", line 122, in validate num_errors = get_validation_errors(s, app) File "/usr/local/lib/python2.5/site-packages/django/core/management/validation.py", line 22, in get_validation_errors from django.db import models, connection File "/usr/local/lib/python2.5/site-packages/django/db/__init__.py", line 16, in <module> backend = __import__('%s%s.base' % (_import_path, settings.DATABASE_ENGINE), {}, {}, ['']) File "/usr/local/lib/python2.5/site-packages/django/db/backends/sqlite3/base.py", line 27, in <module> raise ImproperlyConfigured, "Error loading %s module: %s" % (module, exc) django.core.exceptions.ImproperlyConfigured: Error loading sqlite3 module: No module named _sqlite3 Gath

    Read the article

  • Django: DatabaseLockError exception with Djapian

    - by jul
    Hi, I've got the exception shown below when executing indexer.update(). I have no idea about what to do: it used to work and now index database seems "locked". Anybody can help? Thanks Environment: Request Method: POST Request URL: http://piem.org:8000/restaurant/add/ Django Version: 1.1.1 Python Version: 2.5.2 Installed Applications: ['django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.comments', 'django.contrib.sites', 'django.contrib.admin', 'registration', 'djapian', 'resto', 'multilingual'] Installed Middleware: ('django.middleware.common.CommonMiddleware', 'django.contrib.sessions.middleware.SessionMiddleware', 'django.contrib.auth.middleware.AuthenticationMiddleware', 'django.middleware.locale.LocaleMiddleware', 'multilingual.middleware.DefaultLanguageMiddleware') Traceback: File "/var/lib/python-support/python2.5/django/core/handlers/base.py" in get_response 92. response = callback(request, *callback_args, **callback_kwargs) File "/home/jul/atable/../atable/resto/views.py" in addRestaurant 639. Restaurant.indexer.update() File "/home/jul/python-modules/Djapian-2.3.1-py2.5.egg/djapian/indexer.py" in update 181. database = self._db.open(write=True) File "/home/jul/python-modules/Djapian-2.3.1-py2.5.egg/djapian/database.py" in open 20. xapian.DB_CREATE_OR_OPEN, File "/usr/lib/python2.5/site-packages/xapian.py" in __init__ 2804. _xapian.WritableDatabase_swiginit(self,_xapian.new_WritableDatabase(*args)) Exception Type: DatabaseLockError at /restaurant/add/ Exception Value: Unable to acquire database write lock on /home/jul/atable /djapian_spaces/resto/restaurant/resto.index.restaurantindexer: already locked

    Read the article

  • Rebuilding old (2010) django project in 2012

    - by birgit
    I am trying to make an old Django project run again. After seemingly having solved issues with old sorl.thumbnail versions and deprecated expressions I now get this error when running python manage.py runserver I also tried to copy & paste my old files into a new Django project and get the exactly same error. Maybe someone here has a clue where the problem lies? Unhandled exception in thread started by <bound method Command.inner_run of <django.contrib.staticfiles.management.commands.runserver.Command object at 0x2a80510>> Traceback (most recent call last): File "/usr/lib/python2.7/dist-packages/django/core/management/commands/runserver.py", line 88, in inner_run self.validate(display_num_errors=True) File "/usr/lib/python2.7/dist-packages/django/core/management/base.py", line 249, in validate num_errors = get_validation_errors(s, app) File "/usr/lib/python2.7/dist-packages/django/core/management/validation.py", line 35, in get_validation_errors for (app_name, error) in get_app_errors().items(): File "/usr/lib/python2.7/dist-packages/django/db/models/loading.py", line 146, in get_app_errors self._populate() File "/usr/lib/python2.7/dist-packages/django/db/models/loading.py", line 61, in _populate self.load_app(app_name, True) File "/usr/lib/python2.7/dist-packages/django/db/models/loading.py", line 78, in load_app models = import_module('.models', app_name) File "/usr/lib/python2.7/dist-packages/django/utils/importlib.py", line 35, in import_module __import__(name) File "/home/me/Documents/wdws/wdws/../wdws/cityofwindows/models.py", line 73, in <module> class Image(models.Model): File "/home/me/Documents/wdws/wdws/../wdws/cityofwindows/models.py", line 83, in Image 'large': {'size': (640, 640)}, File "/usr/lib/python2.7/dist-packages/django/db/models/fields/files.py", line 233, in __init__ super(FileField, self).__init__(verbose_name, name, **kwargs) TypeError: __init__() got an unexpected keyword argument 'extra_thumbnails' I need to re-build the project just for visual documentation locally... so also any hints on how to quickly re-run outdated django-projects are very welcome!! Thanks a lot (using Ubuntu 12.04)

    Read the article

  • In Django, what's the best way to handle optional url parameters from the template?

    - by Thierry Lam
    I have the following type of urls which are both valid: hello/ hello/1234/ My urls.py has the following: urlpatterns = patterns('hello.views', url(r'^$', 'index', name='index'), url(r'^(?P<user_id>\d+)/$', 'index', name='index'), ) In my views.py, when I pass user_id to the template, it defaults to 0 if not specified. My template looks like the following, I'm using namespace hello for my hello app: {% url hello:index user_id %} If user_id is not specified, the url defaults to hello/0/. The only way I can think of preventing the default 0 from showing in the url is by an if stmt: {% if user_id %} {% url hello:index user_id %} {% else %} {% url hello:index %} {% endif %} The above will give me hello/ if there are no user_id and hello/1234/ if it's present. Is the above solution the best way to solve this issue?

    Read the article

  • Django's self.client.login(...) does not work in unit tests

    - by thebossman
    I have created users for my unit tests in two ways: 1) Create a fixture for "auth.user" that looks roughly like this: { "pk": 1, "model": "auth.user", "fields": { "username": "homer", "is_active": 1, "password": "sha1$72cd3$4935449e2cd7efb8b3723fb9958fe3bb100a30f2", ... } } I've left out the seemingly unimportant parts. 2) Use 'create_user' in the setUp function (although I'd rather keep everything in my fixtures class): def setUp(self): User.objects.create_user('homer', '[email protected]', 'simpson') Note that the password is simpson in both cases. I've verified that this info is correctly being loaded into the test database time and time again. I can grab the User object using User.objects.get. I can verify the password is correct using 'check_password.' The user is active. Yet, invariably, self.client.login(username='homer', password='simpson') FAILS. I'm baffled as to why. I think I've read every single Internet discussion pertaining to this. Can anybody help? The login code in my unit test looks like this: login = self.client.login(username='homer', password='simpson') self.assertTrue(login) Thanks.

    Read the article

  • How can I display multiple django modelformset forms in a grouped fieldsets?

    - by JT
    I have a problem with needing to provide multiple model backed forms on the same page. I understand how to do this with single forms, i.e. just create both the forms call them something different then use the appropriate names in the template. Now how exactly do you expand that solution to work with modelformsets? The wrinkle, of course, is that each 'form' must be rendered together in the appropriate fieldset. For example I want my template to produce something like this: <fieldset> <label for="id_base-0-desc">Home Base Description:</label> <input id="id_base-0-desc" type="text" name="base-0-desc" maxlength="100" /> <label for="id_likes-0-icecream">Want ice cream?</label> <input type="checkbox" name="likes-0-icecream" id="id_likes-0-icecream" /> </fieldset> <fieldset> <label for="id_base-1-desc">Home Base Description:</label> <input id="id_base-1-desc" type="text" name="base-1-desc" maxlength="100" /> <label for="id_likes-1-icecream">Want ice cream?</label> <input type="checkbox" name="likes-1-icecream" id="id_likes-1-icecream" /> </fieldset> I am using a loop like this to process the results (after form validation) base_models = base_formset.save(commit=False) like_models = like_formset.save(commit=False) for base_model, likes_model in map(None, base_models, likes_models): which works as I'd expect (I'm using map because the # of forms can be different). The problem is that I can't figure out a way to do the same thing with the templating engine. The system does work if I layout all the base models together then all the likes models after wards, but it doesn't meet the layout requirements. EDIT: Updated the problem statement to be more clear about what exactly I'm processing (I'm processing models not forms in the for loop)

    Read the article

  • How to put an InlineFormSet into a ModelFormSet in Django?

    - by Jannis
    Hi, I'd like to display a number of forms via a ModelFormSet where each one of the forms displays in turn InlineFormSets for all objects connected to the object. Now I'm not really sure how to provide the instances for each ModelFormSet. I thought about subclassing BaseModelFormSet but I have no clue on where to start and would like to know whether this is possible at all before I go through all the trouble. Thanks in advance!

    Read the article

  • How can I display multiple django modelformset forms together?

    - by JT
    I have a problem with needing to provide multiple model backed forms on the same page. I understand how to do this with single forms, i.e. just create both the forms call them something different then use the appropriate names in the template. Now how exactly do you expand that solution to work with modelformsets? The wrinkle, of course, is that each 'form' must be rendered together in the appropriate fieldset. For example I want my template to produce something like this: <fieldset> <label for="id_base-0-desc">Home Base Description:</label> <input id="id_base-0-desc" type="text" name="base-0-desc" maxlength="100" /> <label for="id_likes-0-icecream">Want ice cream?</label> <input type="checkbox" name="likes-0-icecream" id="id_likes-0-icecream" /> </fieldset> <fieldset> <label for="id_base-1-desc">Home Base Description:</label> <input id="id_base-1-desc" type="text" name="base-1-desc" maxlength="100" /> <label for="id_likes-1-icecream">Want ice cream?</label> <input type="checkbox" name="likes-1-icecream" id="id_likes-1-icecream" /> </fieldset> I am using a loop like this to process the results for base_form, likes_form in map(None, base_forms, likes_forms): which works as I'd expect (I'm using map because the # of forms can be different). The problem is that I can't figure out a way to do the same thing with the templating engine. The system does work if I layout all the base models together then all the likes models after wards, but it doesn't meet the layout requirements.

    Read the article

  • Django: Is there any way to have "unique for date range"?

    - by tomwolber
    If my model for Items is: class Item(models.Model): name = models.CharField(max_length=500) startDate = models.DateField("Start Date", unique="true") endDate = models.DateField("End Date") Each Item needs to have a unique date range. for example, if i create an Item that has a date range of June 1st to June 8th, how can I keep and Item with a date range of June 3rd to June 5th from being created (or render an error with template logic)?

    Read the article

  • Django - Can you use property as the field in an aggregation function?

    - by orokusaki
    I know the short answer because I tried it. Is there any way to accomplish this though (even if only on account of a hack)? class Ticket(models.Model): account = modelfields.AccountField() uuid = models.CharField(max_length=36, unique=True) created = models.DateTimeField(auto_now_add=True) class Meta: ordering = ['created'] @property def repair_cost(self): # cost is a @property of LineItem(models.Model) return self.lineitem_set.aggregate(models.Sum('cost'))

    Read the article

  • Django: Can class-based views accept two forms at a time?

    - by Hooman
    If I have two forms: class ContactForm(forms.Form): name = forms.CharField() message = forms.CharField(widget=forms.Textarea) class SocialForm(forms.Form): name = forms.CharField() message = forms.CharField(widget=forms.Textarea) and wanted to use a class based view, and send both forms to the template, is that even possible? class TestView(FormView): template_name = 'contact.html' form_class = ContactForm It seems the FormView can only accept one form at a time. In function based view though I can easily send two forms to my template and retrieve the content of both within the request.POST back. variables = {'contact_form':contact_form, 'social_form':social_form } return render(request, 'discussion.html', variables) Is this a limitation of using class based view (generic views)? Many Thanks

    Read the article

  • How to get a single widget to set 2 fields in Django?

    - by kender
    Hi, I got a model with 2 fields: latitude and longitude. Right now they're 2 CharFields, but I want to make a custom widget to set it in admin - was thinking about displaying Google Maps, then getting the coordinates of the marker. But can I have 1 widget (a single map) to set 2 different fields?

    Read the article

  • How can I copy a queryset to a new model in django admin?

    - by user3806832
    I'm trying to write an action that allows the user to select the queryset and copy it to a new table. So: John, Mark, James, Tyler and Joe are in a table 1( called round 1) The user selects the action that say to "move to next round" and those same instances that were chosen are now also in the table for "round 2". I started trying with an action but don't really know where to go from here: def Round_2(modeladmin, request, queryset): For X in queryset: X.pk = None perform.short_description = "Move to Round 2" How can I copy them to the next table with all of their information (pk doesn't have to be the same)? Thanks

    Read the article

< Previous Page | 18 19 20 21 22 23 24 25 26 27 28 29  | Next Page >