Search Results

Search found 18604 results on 745 pages for 'export to xml'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 22/745 | < Previous Page | 18 19 20 21 22 23 24 25 26 27 28 29  | Next Page >

  • Web.xml: Are url-pattern tags relitive to each other?

    - by sixtyfootersdude
    <servlet-mapping> <servlet-name>myName</servlet-name> <url-pattern>/aName</url-pattern> </servlet-mapping> <security-constraint> <web-resource-collection> ... <url-pattern> /* </url-pattern> </web-resource-collection> ... </security-constraint> This is an excerpt from web.xml (using it to configure a jboss/tomcat webservice). Just wondering if the url-pattern in web-resource-collection is relative to the url-pattern in servlet-mapping.

    Read the article

  • how to filter data from xml file for displaying only selected as nodes in treeview

    - by michale
    I have an xml file named "books.xml" provided in the link "http://msdn.microsoft.com/en-us/library/windows/desktop/ms762271(v=vs.85).aspx". What my requirement was to disaplay only the <title> from xml information as nodes in tree view. But when i did the following coding its displaying all the values as nodes like "catalog" as rootnode, book as parent node for all then author,title,genre etc as nodes but i want only root node catalogue and title as nodes not even book. Can any body guide me what modification i need to do in the exisitng logic for displaying title as nodes OpenFileDialog dlg = new OpenFileDialog(); dlg.Title = "Open XML document"; dlg.Filter = "XML Files (*.xml)|*.xml"; dlg.FileName = Application.StartupPath + "\\..\\..\\Sample.xml"; if (dlg.ShowDialog() == DialogResult.OK) { try { //Just a good practice -- change the cursor to a //wait cursor while the nodes populate this.Cursor = Cursors.WaitCursor; //First, we'll load the Xml document XmlDocument xDoc = new XmlDocument(); xDoc.Load(dlg.FileName); //Now, clear out the treeview, //and add the first (root) node treeView1.Nodes.Clear(); treeView1.Nodes.Add(new TreeNode(xDoc.DocumentElement.Name)); TreeNode tNode = new TreeNode(); tNode = (TreeNode)treeView1.Nodes[0]; //We make a call to addTreeNode, //where we'll add all of our nodes addTreeNode(xDoc.DocumentElement, tNode); //Expand the treeview to show all nodes treeView1.ExpandAll(); } catch (XmlException xExc) //Exception is thrown is there is an error in the Xml { MessageBox.Show(xExc.Message); } catch (Exception ex) //General exception { MessageBox.Show(ex.Message); } finally { this.Cursor = Cursors.Default; //Change the cursor back } }} //This function is called recursively until all nodes are loaded private void addTreeNode(XmlNode xmlNode, TreeNode treeNode) { XmlNode xNode; TreeNode tNode; XmlNodeList xNodeList; if (xmlNode.HasChildNodes) //The current node has children { xNodeList = xmlNode.ChildNodes; for (int x = 0; x <= xNodeList.Count - 1; x++) //Loop through the child nodes { xNode = xmlNode.ChildNodes[x]; treeNode.Nodes.Add(new TreeNode(xNode.Name)); tNode = treeNode.Nodes[x]; addTreeNode(xNode, tNode); } } else //No children, so add the outer xml (trimming off whitespace) treeNode.Text = xmlNode.OuterXml.Trim(); }

    Read the article

  • How can I create the XML::Simple data structure using a Perl XML SAX parser?

    - by DVK
    Summary: I am looking a fast XML parser (most likely a wrapper around some standard SAX parser) which will produce per-record data structure 100% identical to those produced by XML::Simple. Details: We have a large code infrastructure which depends on processing records one-by-one and expects the record to be a data structure in a format produced by XML::Simple since it always used XML::Simple since early Jurassic era. An example simple XML is: <root> <rec><f1>v1</f1><f2>v2</f2></rec> <rec><f1>v1b</f1><f2>v2b</f2></rec> <rec><f1>v1c</f1><f2>v2c</f2></rec> </root> And example rough code is: sub process_record { my ($obj, $record_hash) = @_; # do_stuff } my $records = XML::Simple->XMLin(@args)->{root}; foreach my $record (@$records) { $obj->process_record($record) }; As everyone knows XML::Simple is, well, simple. And more importantly, it is very slow and a memory hog—due to being a DOM parser and needing to build/store 100% of data in memory. So, it's not the best tool for parsing an XML file consisting of large amount of small records record-by-record. However, re-writing the entire code (which consist of large amount of "process_record"-like methods) to work with standard SAX parser seems like an big task not worth the resources, even at the cost of living with XML::Simple. I'm looking for an existing module which will probably be based on a SAX parser (or anything fast with small memory footprint) which can be used to produce $record hashrefs one by one based on the XML pictured above that can be passed to $obj->process_record($record) and be 100% identical to what XML::Simple's hashrefs would have been. I don't care much what the interface of the new module is; e.g whether I need to call next_record() or give it a callback coderef accepting a record.

    Read the article

  • XML pass values to timer, AS3

    - by VideoDnd
    My timer has three variables that I can trace to the output window, but don't know how to pass them to the timer. How to I pass the XML values to my timer? Purpose I want to test with an XML document, before I try connecting it to an XML socket. myXML <?xml version="1.0" encoding="utf-8"?> <SESSION> <TIMER TITLE="speed">100</TIMER> <COUNT TITLE="starting position">-77777</COUNT> <FCOUNT TITLE="ramp">1000</FCOUNT> </SESSION> myFlash //myTimer 'instance of mytext on stage' /* fields I want to change with XML */ //CHANGE TO 100 var timer:Timer = new Timer(10); //CHANGE TO -77777 var count:int = 0; //CHANGE TO 1000 var fcount:int = 0; timer.addEventListener(TimerEvent.TIMER, incrementCounter); timer.start(); function incrementCounter(event:TimerEvent) { count++; fcount=int(count*count/1000);//starts out slow... then speeds up mytext.text = formatCount(fcount); } function formatCount(i:int):String { var fraction:int = i % 100; var whole:int = i / 100; return ("0000000" + whole).substr(-7, 7) + "." + (fraction < 10 ? "0" + fraction : fraction); } //LOAD XML var myXML:XML; var myLoader:URLLoader = new URLLoader(); myLoader.load(new URLRequest("time.xml")); myLoader.addEventListener(Event.COMPLETE, processXML); //PARSE XML function processXML(e:Event):void { myXML = new XML(e.target.data); trace(myXML.ROGUE.*); trace(myXML); //TEXT var text:TextField = new TextField(); text.text = myXML.TIMER.*; text.textColor = 0xFF0000; addChild(text); } RESOURCES OReilly's ActionScript 3.0 Cookbook, Chapter 12 Strings, Chapter 20 XML

    Read the article

  • export command within shell script

    - by shantanuo
    When I use export command at command prompt, it works as expected. But it does not work from shell script. [root@server shantanu]# export myip=10 [root@server shantanu]# echo $myip 10 [root@server shantanu]# vi myip.sh #!/bin/sh export myipadd=10 [root@server shantanu]# sh -xv myip.sh #!/bin/sh export myipadd=10 + export myipadd=10 + myipadd=10 [root@server shantanu]# echo $myipadd I want to make the variable available to the same script next time when it runs. In other words I am looking for some way to memorize the variable value.

    Read the article

  • How can I export a folder with many subfolders w/ all msgs in eml format from Thunderbird

    - by Erik Vold
    I'm trying to export a very large folder that has emails and many subfolders into a folder on the file system with the same structure and where all the emails are in .eml format. Or I'd like to export the messages in a way that they are easy to import in to Thunderbird. I can't seem to find a way except slowly drag and drop the email messages, while manually creating each folder, and that could take days to do, so I need a better method.

    Read the article

  • Parsing XML with the PHP XMLReader

    - by coffeecoder
    Hi Guys, I am writing program that reads in some XML from the $_POST variable and then parses using the PHP XMLReader and the data extracted input into a database. I am using the XMLReader as the XML supplied will more than likely be too big to place into memory. However I am having some issues, my XML and basic code as are follows: '<?xml version="1.0"?> <data_root> <data> <info>value</info> </data> <action>value</action> </data_root>' $request = $_REQUEST['xml']; $reader = new XMLReader(); $reader->XML($request); while($reader->read()){ //processing code } $reader->close() My problem is that the code will work perfectly if the XML being passed does not have the <?xml version="1.0"?> line, but if i include it, and it will be included when the application goes into a live production environment, the $reader->read() code for the while loop does not work and the XML is not parsed within the while loop. Has anyone seen similar behaviour before or knows why this could be happening? Thanks in advance.

    Read the article

  • Will JSON replace XML as a data format?

    - by 13ren
    When I first saw XML, I thought it was basically a representation of trees. Then I thought: the important thing isn't that it's a particularly good representation of trees, but that it is one that everyone agrees on. Just like ASCII. And once established, it's hard to displace due to network effects. The new alternative would have to be much better (maybe 10 times better) to displace it. Of course, ASCII has been (mostly) replaced by Unicode, for internationalization. According to google trends, XML has a x43 lead, but is declining - while JSON grows. Will JSON replace XML as a data format? (edited) for which tasks? for which programmers/industries? NOTES: S-expressions (from lisp) are another representation of trees, but which has not gained mainstream adoption. There are many, many other proposals, such as YAML and Protocol Buffers (for binary formats). I can see JSON dominating the space of communicating with client-side AJAX (AJAJ?), and this possibly could back-spread into other systems transitively. XML, being based on SGML, is better than JSON as a document format. I'm interested in XML as a data format. XML has an established ecosystem that JSON lacks, especially ways of defining formats (XML Schema) and transforming them (XSLT). XML also has many other standards, esp for web services - but their weight and complexity can arguably count against XML, and make people want a fresh start (similar to "web services" beginning as a fresh start over CORBA).

    Read the article

  • Export from HTML to PDF (C#)

    - by Sem Dendoncker
    Hi, In our applications we make html documents as reports and exports. But now our customer wants a button that saves that document on their pc. The problem is that the document includes images. You can create a word document with the following code: private void WriteWordDoc(string docName) { Response.Buffer = true; Response.ContentType = "application/msword"; Response.AddHeader("content-disposition", String.Format("attachment;filename={0}.doc", docName.Replace(" ", "_"))); Response.Charset = "utf-8"; } But the problem is that the images are just links an thus not embedded in the word document. Therefore I'm looking for an alternative PDF seems to be a good alternative, does anyone know a good pdf writer for C#? One that has some good references and has been tested properly? Best regards, Sem

    Read the article

  • How to read utf-8 xml from vbs and get correct character code

    - by vkjr
    I'm trying to read xml file from vbs script. Xml is encoded in utf-8 and has appropriate header From vbs script I use microsoft xmldom parser to read xml: Dim objXMLDoc Set objXMLDoc = CreateObject( "Microsoft.XMLDOM" ) objXMLDoc.load("vbs_strings.xml") Inside xml I'm trying to write character by code using &#nnn; notation. Then I read this character from vbscript and try to get it's code using Asc() function. For some characters it works fine and read code is equal to one written. But for some characters Asc() always returns code 63. What could it be? Examples: If xml contains <section>&#195;<section> and in script I have Section variable for representing this xml node then code: Asc(Section.Text) will return value 195 and it's ok. If xml contains <section>&#110;<section> then code: Asc(Section.Text) will return value 110 and it's ok. But if xml contains <section>&#130;<section> or <section>&#156;<section> or <section>&#140;<section> Asc(Section.Text) will return value 63 and it's definitely not good. Do you know why?

    Read the article

  • How do you remove invalid hexadecimal characters from an XML-based data source prior to constructing

    - by Oppositional
    Is there any easy/general way to clean an XML based data source prior to using it in an XmlReader so that I can gracefully consume XML data that is non-conformant to the hexadecimal character restrictions placed on XML? Note: The solution needs to handle XML data sources that use character encodings other than UTF-8, e.g. by specifying the character encoding at the XML document declaration. Not mangling the character encoding of the source while stripping invalid hexadecimal characters has been a major sticking point. The removal of invalid hexadecimal characters should only remove hexadecimal encoded values, as you can often find href values in data that happens to contains a string that would be a string match for a hexadecimal character. Background: I need to consume an XML-based data source that conforms to a specific format (think Atom or RSS feeds), but want to be able to consume data sources that have been published which contain invalid hexadecimal characters per the XML specification. In .NET if you have a Stream that represents the XML data source, and then attempt to parse it using an XmlReader and/or XPathDocument, an exception is raised due to the inclusion of invalid hexadecimal characters in the XML data. My current attempt to resolve this issue is to parse the Stream as a string and use a regular expression to remove and/or replace the invalid hexadecimal characters, but I am looking for a more performant solution.

    Read the article

  • xml declaration not being omitted from page

    - by Mark Schultheiss
    I have an XSLT transform I am using to process an XML file, inserting it into the body of my aspx page. Reference the following for background information: background on xml/xslt I have the following in my xml file: <?xml version="1.0" encoding="utf-8"?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl" xmlns:myCustomStrings="urn:customStrings"> <xsl:output method="xml" version="2.0" media-type="text/html" omit-xml-declaration="yes" indent="yes" />...unrelated stuff left out here Here is the output that is relevent: <div id="example" /> <?xml version="1.0" encoding="utf-8"?><div xmlns:myCustomStrings="urn:customStrings"><div id="imFormBody" class="imFormBody"> My question relates to the output, specifically to the <?xml version="1.0" encoding="utf-8"?> which is getting included in the output anyway. Is the issue related to the custom method I have used? If so, I don't really see the need to include the xml part as the namespace is in the div tag. Is there a way to ensure that this extra stuff gets left out as I asked it to?

    Read the article

  • Export list as .txt (Python)

    - by Nimbuz
    My Python module has a list that contains all the data I want to save as a .txt file somewhere. The list contains several tuples like so: list = [ ('one', 'two', 'three'), ('four', 'five', 'six')] How do I print the list so each tuple item is separated by a tab and each tuple is separated by a newline? Thanks

    Read the article

  • XML problem in the basic menu example

    - by arakn0
    Hi there, I am trying to create an app with some menus, an I am following the basic example available in the official android site: http://developer.android.com/guide/topics/ui/menus.html My problems appear when I define the menu in the XML. After creating the folder res/menu and creating the menu_option.xml file from eclipse.... The project (in general) gives an error that can be read from the Problems tab: Unparsed aapt error(s)! Check the console for output Android Packaging Problem So, changing to the Console tab to get more information about the problem, this can be read: [2010-06-02 11:35:54 - TestAudio] Error in an XML file: aborting build. [2010-06-02 11:35:54 - TestAudio] W/ResourceType(11566): Bad XML block: header size 63327 or total size -144759824 is larger than data size 0 [2010-06-02 11:35:54 - TestAudio] /home/User/workspace/TestAudio/res/menu/options_menu.xml:1: error: Error parsing XML: no element found The strange thing is that eclipse recognizes the menu items that I've defined in the XML,I can reference them in the code with no problems and my main activity builds. (and the rest of the files too). Could it be that when eclipse creates a file, for some reason, the Android SDK has problems to read it, or something similar?? The XML code is exactly the same as the one in the example, so I don't really know what is happening. The code in options_menu.xml is this: <menu xmlns:android="http://schemas.android.com/apk/res/android" <item android:id="@+id/new_game" android:title="New Game" / <item android:id="@+id/quit" android:title="Quit" / </menu Thanks in advance for your help!

    Read the article

  • MySQL Export with Column Heading

    - by st4nt0n
    Hello - I am very, very, new to mySQL. I've got experience in general technical terms, but not with the syntax or concepts of mySQL. I have been tasked with exporting a table from MySQL into a pipe delimited .txt or .xls that I can use to add 7500 more records to manually, then import back into the table. I tried to use INTO OUTFILE, but I don't get column headings, which I need for reference to merge the new records. Is there a good resource that can explain this to a complete novice? I would usually go down to my bookstore and start learning, but I'm on a bit of a time crunch. Thanks all!

    Read the article

  • SecurityException when trying to export a java resource

    - by thecoop
    I'm trying to get the source of a java resource stored in an oracle database using this code (connecting as SYSTEM for testing): DECLARE javalob CLOB; BEGIN DBMS_LOB.CREATETEMPORARY(javalob, false); DBMS_JAVA.EXPORT_RESOURCE('RESOURCENAME', 'SCHEMA', javalob); DBMS_OUTPUT.PUT_LINE(javalob); END; But when I try to run it I get this: Java call terminated by uncaught Java exception: java.lang.SecurityException: cannot read <Resource Handle: RESOURCENAME|SCHEMA|301> because SYSTEM does not have execute privilege on it This thing is, I'm not sure how to grant permissions on <Resource Handle: RESOURCENAME|SCHEMA|301>, as this isn't a SQL or PL/SQL object. And why doesn't SYSTEM have access to it anyway?

    Read the article

  • jQuery XML loading and then innerfade effect

    - by Ryan Max
    Hello, I think I can explain myself without code, so for brevity's sake here we go: I am using jquery to pull data from an xml and put it into a ul on the page with each xml entry as a li. This is working great! However, what I am trying to do afterwards is use the innerfade plugin to make a simple animation between each of the li's. It's not working though, as it is still just loading the static list with each item visible (whereas if innerfade was working it would only display the first....then fade into the second, etc) It's not an innerfade problem however, because if I add the list in manually to the page (not injecting it with jquery) then the innerfade works fine. I'm relatively new to DOM scripting, so I think I am missing something here. I'm not quite sure how jQuery sequences everything, and I'm having trouble phrasing my question in a search engine friendly manner so here I am. Is it possible to have jquery pull the data from xml, then inject it into the page, then have innerfade work it's magic? Or am I thinking about this the wrong way? xml code: $.ajax({ type: "GET", url: "xml/playlist.xml", dataType: "xml", success: function(xml) { $(xml).find('song').each(function(){ var name = $(this).attr('title'); var date = $(this).attr('artist'); var message = $(this).attr('path'); $('<li></li>').html('<span id="an_name">'+name+'</span><span id="an_date">'+date+'</span><span id="an_message">'+message+'</span>').appendTo('#anniversary'); }); } }); innerfade code: <script type="text/javascript"> jQuery.noConflict(); jQuery(document).ready( function(){ jQuery('#anniversary').innerfade({ speed: 1000, timeout: 5000, type: 'sequence', }); });

    Read the article

  • ListView Parsing Persian xml

    - by Namikaze Minato
    I used a tutorial about listview parsing xm from internet and using LasyAdapter shows the items in listview. When I add persian characters in xml (into one of childnodes) the result is some boxes in listview (after showing the text in listview). The format of xml is UTF-8, too. I used typeface too (but didn't work). Besides when I type Pwesian into the application it shows alright but it can't show Persiann content parsed from xml. Thanks in advance. I updated the post with original XMLparser (which was the problem). public String getXmlFromUrl(String url) { String xml = null; try { // defaultHttpClient DefaultHttpClient httpClient = new DefaultHttpClient(); HttpPost httpPost = new HttpPost(url); HttpResponse httpResponse = httpClient.execute(httpPost); HttpEntity httpEntity = httpResponse.getEntity(); xml = EntityUtils.toString(httpEntity); } catch (UnsupportedEncodingException e) { e.printStackTrace(); } catch (ClientProtocolException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } // return XML return xml; } public Document getDomElement(String xml) { Document doc = null; DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); try { DocumentBuilder db = dbf.newDocumentBuilder(); InputSource is = new InputSource(); is.setCharacterStream(new StringReader(xml)); doc = db.parse(is); } catch (ParserConfigurationException e) { Log.e("Error: ", e.getMessage()); return null; } catch (SAXException e) { Log.e("Error: ", e.getMessage()); return null; } catch (IOException e) { Log.e("Error: ", e.getMessage()); return null; } return doc; }

    Read the article

  • What's the best way to retrieve two pieces of data from an XML file?

    - by Morinar
    I've got an XML document that is in either a pre or post FO transformed state that I need to extract some information from. In the pre-case, I need to pull out two tags that represent the pageWidth and pageHeight and in the post case I need to extract the page-height and page-width parameters from a specific tag (I forget which one it is off the top of my head). What I'm looking for is an efficient/easily maintainable way to grab these two elements. I'd like to only read the document a single time fetching the two things I need. I initially started writing something that would use BufferedReader + FileReader, but then I'm doing string searching and it gets messy when the tags span multiple lines. I then looked at the DOMParser, which seems like it would be ideal, but I don't want to have to read the entire file into memory if I could help it as the files could potentially be large and the tags I'm looking for will nearly always be close to the top of the file. I then looked into SAXParser, but that seems like a big pile of complicated overkill for what I'm trying to accomplish. Anybody have any advice? Or simple implementations that would accomplish my goal? Thanks.

    Read the article

  • export a JOGL applet and embedd into a html page

    - by nkint
    hi guys it is some time that i'm testing opengl with java and JOGL. now i have good result and i wanto to pubblish it on web. but i have some problem. i'm in eclipse, and i'm testing an Applet with JOGL. first of all i have this run time error (but the program works correctly): java.lang.IllegalArgumentException: adding a window to a container at java.awt.Container.checkNotAWindow(Container.java:431) at java.awt.Container.addImpl(Container.java:1039) at java.awt.Container.add(Container.java:365) at AppletHelloWorld.init(AppletHelloWorld.java:30) at sun.applet.AppletPanel.run(AppletPanel.java:424) at java.lang.Thread.run(Thread.java:619) then i found this incredibly clear page and i do what is said, i open html with the browser, the libs are downloaded but it stops at "Starting applet AppletHelloWorld" that is the name i gave to my applet. mayebe i miss something like main function or exporting well the jar? this is my main code: public class AppletHelloWorld extends Applet { public static void main(String[] args) { JFrame fr=new JFrame(); fr.setBounds(0,0,1015,600); fr.add(new AppletHelloWorld()); fr.setVisible(true); } public void init() { setLayout(null); MyJOGLProject canvas = new MyJOGLProject(); //MyJOGLProject extends JFrame canvas.run(); Container c = new Container(); c.add(canvas); add(c); } //....

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 18 19 20 21 22 23 24 25 26 27 28 29  | Next Page >