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  • Haskell, list of natural number

    - by Hellnar
    Hello, I am an absolute newbie in Haskell yet trying to understand how it works. I want to write my own lazy list of integers such as [1,2,3,4,5...]. For list of ones I have written ones = 1 : ones and when tried, works fine: *Main> take 10 ones [1,1,1,1,1,1,1,1,1,1] How can I do the same for increasing integers ? I have tried this but it indeed fails: int = 1 : head[ int + 1] And after that how can I make a method that multiplies two streams? such as: mulstream s1 s2 = head[s1] * head[s2] : mulstream [tail s1] [tail s2]

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  • XPath 1.0 to find if an element's value is in a list of values

    - by user364902
    Is there a way to construct an XPath that evaluates whether an element's value is in a predefined list of values? Something akin to this: /Location/Addr[State='TX or AL or MA'] Which would match nodes whith State elements for Texas, Alabama, or Massachusetts? I know that I can unpack the expression: /Location/Addr[State='TX] or /Location/Addr[State='AL'], etc... But this is a bit cumbersome since the xpaths are quite long, as is the list of values. My google-fu isn't turning up much on the issue...

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  • sort a list of objects based on runtime property

    - by jijo
    I have an arraylist of VOs. These objects have many properties and corresponding get/set methods. I want to sort this array list based on a property which I'll be getting in runtime. Let me explain in detail. My VO is like this public class Employee { String name; String id; private String getName() { return name; } private String getId() { return id; } } I will be getting a string ‘sort’ in runtime, which can be either ‘id’ of ‘name’. I want to sort the list based on the value of the string. I have tried to use comparator and reflection together, but no luck. I don’t want to use an if loop and create new comparator classes. Any other thoughts?

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  • Java - java.util.List problem

    - by Yatendra Goel
    I have a java.util.ArrayList<Item> and an Item object. Now, I want to obtain the number of times the Item is stored in the arraylist. I know that I can do arrayList.contains() check but it returns true, irrespective of whether it contains one or more Items. Q1. How can I find the number of time the Item is stored in the list? ================================================================================== Q2. Also, If the list contains more than one Item, then how can I determine the index of other Items because arrayList.indexOf(item) returns the index of only first Item every time?

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  • categorizing items in a list with python

    - by jtc99
    Just as a heads up, I'm really new to python. Currently I have a list of 110,000 donors in Excel. One of the pieces of information they give to us is their occupation. I would like to condense this list down to say 10 or 20 categories that I define. Normally I would just chug through this, going line by line, but since I have to do this for a years worth of data, I don't really have the time to do a line by line of 1,000,000+ rows. Is there anyway to define my 10 or 20 categories and then have python sort it out from there?

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  • list within a list

    - by atm atm
    I'm working on this problem, but I cannot figure out the second part. I tried using reverse list but it did not work out how I planned it. Given a list L (e.g. [1,2,3,4]), write a program that generates the following nested lists: L1 = [[1],[1,2],[1,2,3],[1,2,3,4]], L2 = [[4],[3,4],[2,3,4],[1,2,3,4]]. My code that I have so far: mylist=[,1,2,3,4] print("Orginal list L=",mylist) n=len(mylist) l1=[] l2=[] for x in range(1,n+1,1): l1.append(mylist[0:x]) print("L1=",l1) #prints final product of l1 mylist.reverse() #this is where i get messed up for x in range(1,n+1,1): l2.append(mylist[0:x]) print("L2=",l2)

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  • Iterators over a LInked List in a Game in Java

    - by Matthew
    I am using OpenGl in android and they have a callback method called draw that gets called with out my control. (As fast as the device can handle if I am not mistaken) I have a list of "GameObjects" that have a .draw method and a .update method. I have two different threads that handle each of those. So, the question is, can I declare two different iterators in two different methods in two different threads that iterate over the same Linked List? If so, do I simply declare ListIterator<GameObject> l = objets.listIterator() each time I want a new iterator and it won't interfere with other iterators?

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  • Android search list, String

    - by NightSky
    Hey guys what is the best way to search through my list of objects, they return a few strings, last name and first name for example. Here how i'm currently searching but my search needs to match the entire string which I don't want. The search needs it to match part of the string like our contacts list on our phone and ignore the case. if (searchQ.equalsIgnoreCase(child.first_name)) { addChildToList(child); } Ive tried contains and starts with for example, they did not work. Whats going on? Thanks! Cheers!

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  • Cisco access list logging. Why is there a difference between IPv4 and IPv6?

    - by growse
    I've got a Cisco 877 router. I've got an IPv4 access list and an IPv6 access list set up and configured similar to this: interface Dialer1 ... ip access-group INTERET-IN ipv6 traffic-filter IPV6-IN Each of these access lists has a final rule of deny ip/ipv6 any any log. However, in my syslog I notice that there's a difference in formatting between the two types of entries. IPv4 will say: %SEC-6-IPACCESSLOGP: list INTERNET-IN denied udp 88.89.209.63(137) -> 1.2.3.4(137), 1 packet Whereas the IPv6 list will say %IPV6_ACL-6-ACCESSLOGNP: list IPV6-IN/240 denied 59 2001:0:5EF5:79FD:14F9:B773:3EBA:3EE3 (Dialer1) -> 2001:800:1000:0::1, 8 packets Both have broadly the same information, but the IPv6 log entry is missing the protocol type and port, both of which are very useful if I'm trying to troubleshoot connectivity. Why is this? How do I get IPv6 deny logs to display the protocol and port used, if any?

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  • Is there a piece of software which lets you turn "anything" into a dynamic reorderable list?

    - by Robin Green
    I could write this myself, but I want to know if it already exists. Basically, it must fulfill these criteria: To reorder items, the user must never have to manually renumber them. That would be annoying, and it doesn't scale. Can read from a range of data sources (e.g. a database, a directory on the file system, a text file, another list) When the original data source changes, the list must automatically change with it (possibly with confirmation, e.g. if a list item would be deleted) Ability to persist the list ordering in some fashion Graphical display of list items (so that they can include e.g. images) Optional extras: Ability to modify data and write back to the data source (other than the ordering information)

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  • C# - Cannot implicitly convert type List<Product> to List<IProduct>

    - by Keith Barrows
    I have a project with all my Interface definitions: RivWorks.Interfaces I have a project where I define concrete implmentations: RivWorks.DTO I've done this hundreds of times before but for some reason I am getting this error now: Cannot implicitly convert type 'System.Collections.Generic.List<RivWorks.DTO.Product>' to 'System.Collections.Generic.List<RivWorks.Interfaces.DataContracts.IProduct>' Interface definition (shortened): namespace RivWorks.Interfaces.DataContracts { public interface IProduct { [XmlElement] [DataMember(Name = "ID", Order = 0)] Guid ProductID { get; set; } [XmlElement] [DataMember(Name = "altID", Order = 1)] long alternateProductID { get; set; } [XmlElement] [DataMember(Name = "CompanyId", Order = 2)] Guid CompanyId { get; set; } ... } } Concrete class definition (shortened): namespace RivWorks.DTO { [DataContract(Name = "Product", Namespace = "http://rivworks.com/DataContracts/2009/01/15")] public class Product : IProduct { #region Constructors public Product() { } public Product(Guid ProductID) { Initialize(ProductID); } public Product(string SKU, Guid CompanyID) { using (RivEntities _dbRiv = new RivWorksStore(stores.RivConnString).NegotiationEntities()) { model.Product rivProduct = _dbRiv.Product.Where(a => a.SKU == SKU && a.Company.CompanyId == CompanyID).FirstOrDefault(); if (rivProduct != null) Initialize(rivProduct.ProductId); } } #endregion #region Private Methods private void Initialize(Guid ProductID) { using (RivEntities _dbRiv = new RivWorksStore(stores.RivConnString).NegotiationEntities()) { var localProduct = _dbRiv.Product.Include("Company").Where(a => a.ProductId == ProductID).FirstOrDefault(); if (localProduct != null) { var companyDetails = _dbRiv.vwCompanyDetails.Where(a => a.CompanyId == localProduct.Company.CompanyId).FirstOrDefault(); if (companyDetails != null) { if (localProduct.alternateProductID != null && localProduct.alternateProductID > 0) { using (FeedsEntities _dbFeed = new FeedStoreReadOnly(stores.FeedConnString).ReadOnlyEntities()) { var feedProduct = _dbFeed.AutoWithImage.Where(a => a.ClientID == companyDetails.ClientID && a.AutoID == localProduct.alternateProductID).FirstOrDefault(); if (companyDetails.useZeroGspPath.Value || feedProduct.GuaranteedSalePrice > 0) // kab: 2010.04.07 - new rules... PopulateProduct(feedProduct, localProduct, companyDetails); } } else { if (companyDetails.useZeroGspPath.Value || localProduct.LowestPrice > 0) // kab: 2010.04.07 - new rules... PopulateProduct(localProduct, companyDetails); } } } } } private void PopulateProduct(RivWorks.Model.Entities.Product product, RivWorks.Model.Entities.vwCompanyDetails RivCompany) { this.ProductID = product.ProductId; if (product.alternateProductID != null) this.alternateProductID = product.alternateProductID.Value; this.BackgroundColor = product.BackgroundColor; ... } private void PopulateProduct(RivWorks.Model.Entities.AutoWithImage feedProduct, RivWorks.Model.Entities.Product rivProduct, RivWorks.Model.Entities.vwCompanyDetails RivCompany) { this.alternateProductID = feedProduct.AutoID; this.BackgroundColor = Helpers.Product.GetCorrectValue(RivCompany.defaultBackgroundColor, rivProduct.BackgroundColor); ... } #endregion #region IProduct Members public Guid ProductID { get; set; } public long alternateProductID { get; set; } public Guid CompanyId { get; set; } ... #endregion } } In another class I have: using dto = RivWorks.DTO; using contracts = RivWorks.Interfaces.DataContracts; ... public static List<contracts.IProduct> Get(Guid companyID) { List<contracts.IProduct> myList = new List<dto.Product>(); ... Any ideas why this might be happening? (And I am sure it is something trivially simple!)

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  • Converting hierarchial data into an unordered list Programmatically using asp.net/C#

    - by kranthi
    hi everyone, I've data which looks something like this. | id | name | depth | itemId | +-----+----------------------+-------+-------+ | 0 | ELECTRONICS | 0 | NULL | | 1 | TELEVISIONS | 1 | NULL | | 400 | Tube | 2 | NULL | | 432 | LCD | 3 | 1653 | | 422 | Plasma | 3 | 1633 | | 416 | Portable electronics | 3 | 1595 | | 401 | MP3 Player | 3 | 1249 | | 191 | Flash | 2 | NULL | | 555 | CD Players | 3 | 2198 | | 407 | 2 Way Radio | 3 | 1284 | | 388 | I've a problem with | 3 | 1181 | | 302 | What is your bill pa | 3 | 543 | | 203 | Where can I find my | 3 | 299 | | 201 | I would like to make | 3 | 288 | | 200 | Do you have any job | 3 | 284 | | 192 | About Us | 3 | NULL | | 199 | What can you tell me | 4 | 280 | | 198 | Do you help pr | 4 | 276 | | 197 | would someone help co| 4 | 272 | | 196 | can you help ch | 4 | 268 | | 195 | What awards has Veri | 4 | 264 | | 194 | What's the latest ne | 4 | 260 | | 193 | Can you tell me more | 4 | 256 | | 180 | Site Help | 2 | NULL | | 421 | Where are the | 3 | 1629 | | 311 | How can I access My | 3 | 557 | | 280 | Why isn't the page a | 3 | 512 | To convert the above data into unordered list based on depth, I'm using the following code int lastDepth = -1; int numUL = 0; StringBuilder output = new StringBuilder(); foreach (DataRow row in ds.Tables[0].Rows) { int currentDepth = Convert.ToInt32(row["Depth"]); if (lastDepth < currentDepth) { if (currentDepth == 0) { output.Append("<ul class=\"simpleTree\">"); output.AppendFormat("<li class=\"root\"><span><a href=\"#\" title=\"root\">root</a></span><ul><li class=\"open\" ><span><a href=\"#\" title={1}>{0}</a></span>", row["name"],row["id"]); } else { output.Append("<ul>"); if(currentDepth==1) output.AppendFormat("<li><span>{0}</span>", row["name"]); else output.AppendFormat("<li><span class=\"text\"><a href=\"#\" title={1}>{0}</a></span>", row["name"], row["id"]); } numUL++; } else if (lastDepth > currentDepth) { output.Append("</li></ul></li>"); if(currentDepth==1) output.AppendFormat("<li><span>{0}</span>", row["name"]); else output.AppendFormat("<li><span class=\"text\"><a href=\"#\" title={1}>{0}</a></span>", row["name"], row["id"]); numUL--; } else if (lastDepth > -1) { output.Append("</li>"); output.AppendFormat("<li><span class=\"text\"><a href=\"#\" title={1}>{0}</a></span>", row["name"],row["id"]); } lastDepth = currentDepth; } for (int i = 1; i <= numUL+1; i++) { output.Append("</li></ul>"); } myliteral.text=output.ToString(); But the resulting unordered list doesnt seem to be forming properly(using which i am constructing a tree).For example "Site Help" with id '180' is supposed to appear as a direct child of "Televisions" with id '1',is appearing as a direct child of 'Flash' with id '191' using my code.so in addition to considering depth,I've decided to consider itemid as well in order to get the treeview properly.Those rows of the table with itemId not equal to null are not supposed to have a child node(i.e.,they are the leaf nodes in the tree) and all the other nodes can have child nodes. Please could someone help me in constructing a proper unordered list based on my depth,itemid coulumns? Thanks.

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  • Linked List exercise, what am I doing wrong?

    - by Sean Ochoa
    Hey all. I'm doing a linked list exercise that involves dynamic memory allocation, pointers, classes, and exceptions. Would someone be willing to critique it and tell me what I did wrong and what I should have done better both with regards to style and to those subjects I listed above? /* Linked List exercise */ #include <iostream> #include <exception> #include <string> using namespace std; class node{ public: node * next; int * data; node(const int i){ data = new int; *data = i; } node& operator=(node n){ *data = *(n.data); } ~node(){ delete data; } }; class linkedList{ public: node * head; node * tail; int nodeCount; linkedList(){ head = NULL; tail = NULL; } ~linkedList(){ while (head){ node* t = head->next; delete head; if (t) head = t; } } void add(node * n){ if (!head) { head = n; head->next = NULL; tail = head; nodeCount = 0; }else { node * t = head; while (t->next) t = t->next; t->next = n; n->next = NULL; nodeCount++; } } node * operator[](const int &i){ if ((i >= 0) && (i < nodeCount)) throw new exception("ERROR: Invalid index on linked list.", -1); node *t = head; for (int x = i; x < nodeCount; x++) t = t->next; return t; } void print(){ if (!head) return; node * t = head; string collection; cout << "["; int c = 0; if (!t->next) cout << *(t->data); else while (t->next){ cout << *(t->data); c++; if (t->next) t = t->next; if (c < nodeCount) cout << ", "; } cout << "]" << endl; } }; int main (const int & argc, const char * argv[]){ try{ linkedList * myList = new linkedList; for (int x = 0; x < 10; x++) myList->add(new node(x)); myList->print(); }catch(exception &ex){ cout << ex.what() << endl; return -1; } return 0; }

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  • Common idiom in Java to Scala, traverse/Iterate Java list into Scala list

    - by Berlin Brown
    I am processing a XML document and iterating through nodes. I want to iterate through the nodes and build a new List of some type. How would I do this with Scala: Here is my XML traverse code: def findClassRef(xmlNode: Elem) = { xmlNode\"classDef" foreach { (entry) => val name = entry \ "@name" val classid = entry \ "@classId" println(name + "//" + classid) } } Where the line of println is, I want to append elements to a list.

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  • Why declare "private List contactInfos" without a generic ("private List <ContactInfo> contactInfos"

    - by g_imp
    In this example from the App Engine docs, why does the example declare contactInfos like this (no Generics): import javax.jdo.annotations.Element; // ... @Persistent @Element(dependent = "true") private List contactInfos; instead of like this, using a Generic: import javax.jdo.annotations.Element; // ... @Persistent @Element(dependent = "true") private List <ContactInfo> contactInfos;

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  • not able to add list item between a list using jquery

    - by Pradyut Bhattacharya
    Hi I m having a ordered list having the structure Test another test Add I want to add a list item between sublist 2 and 3 using jquery I used the code: - $("ol#update li ol li:eq(1)").append("<li> test </li>"); But this appends inside the li "another test" and not after the 2 li Here is the example page On-click "sub-comment" adds a li inside li 2 Clicking on "comment" shows the structure of the sub lis Please help Thanks Pradyut

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  • Haskell Add Function Return to List Until Certain Length

    - by kienjakenobi
    I want to write a function which takes a list and constructs a subset of that list of a certain length based on the output of a function. If I were simply interested in the first 50 elements of the sorted list xs, then I would use fst (splitAt 50 (sort xs)). However, the problem is that elements in my list rely on other elements in the same list. If I choose element p, then I MUST also choose elements q and r, even if they are not in the first 50 elements of my list. I am using a function finderFunc which takes an element a from the list xs and returns a list with the element a and all of its required elements. finderFunc works fine. Now, the challenge is to write a function which builds a list whose total length is 50 based on multiple outputs of finderFunc. Here is my attempt at this: finish :: [a] -> [a] -> [a] --This is the base case, which adds nothing to the final list finish [] fs = [] --The function is recursive, so the fs variable is necessary so that finish -- can forward the incomplete list to itself. finish ps fs -- If the final list fs is too small, add elements to it | length fs < 50 && length (fs ++ newrs) <= 50 = fs ++ finish newps newrs -- If the length is met, then add nothing to the list and quit | length fs >= 50 = finish [] fs -- These guard statements are currently lacking, not the main problem | otherwise = finish [] fs where --Sort the candidate list sortedps = sort ps --(finderFunc a) returns a list of type [a] containing a and all the -- elements which are required to go with it. This is the interesting -- bit. rs is also a subset of the candidate list ps. rs = finderFunc (head sortedps) --Remove those elements which are already in the final list, because -- there can be overlap newrs = filter (`notElem` fs) rs --Remove the elements we will add to the list from the new list -- of candidates newps = filter (`notElem` rs) ps I realize that the above if statements will, in some cases, not give me a list of exactly 50 elements. This is not the main problem, right now. The problem is that my function finish does not work at all as I would expect it to. Not only does it produce duplicate elements in the output list, but it sometimes goes far above the total number of elements I want to have in the list. The way this is written, I usually call it with an empty list, such as: finish xs [], so that the list it builds on starts as an empty list.

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  • find if list 1 is a sequence of list 2 in haskell

    - by Isaak Wahb
    im trying to check if a given list is a subsequence of another list: here are example of lists which gives true: subseq "" "w" subseq "w" "w" subseq "ab" "cab" subseq "cb" "cab" subseq "aa" "xaxa" not (subseq "aa" "xax") not (subseq "ab" "ba") i just come to this but in some cases it gives a wrong result subseq :: Eq a => [a] -> [a] -> Bool subseq [] [] = True subseq [] ys = True subseq xs [] = False subseq (x:xs) (y:ys) = x == y || subseq xs ( 1 `drop` ys )

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  • Splitting list into a list of possible tuples

    - by user1742646
    I need to split a list into a list of all possible tuples, but I'm unsure of how to do so. For example pairs ["cat","dog","mouse"] should result in [("cat","dog"), ("cat","mouse"), ("dog","cat"), ("dog","mouse"), ("mouse","cat"), ("mouse","dog")] I was able to form the first two, but am unsure of how to get the rest. Here's what I have so far: pairs :: [a] -> [(a,a)] pairs (x:xs) = [(m,n) | m <- [x], n <- xs]

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  • troubles creating a List of doubles from a list of objects

    - by Michel
    Hi, i have a list with objects. The object has a property 'Sales' which is a string. Now i want to create a list of doubles with the values of all objects' 'Sales' properties. I tried this: var tmp = from n in e.Result select new{ Convert.ToDouble ( n.Sales) }; but this gives me this error: Error 106 Invalid anonymous type member declarator. Anonymous type members must be declared with a member assignment, simple name or member access.

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