Search Results

Search found 3365 results on 135 pages for 'math'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 22/135 | < Previous Page | 18 19 20 21 22 23 24 25 26 27 28 29  | Next Page >

  • python gui generate math equation

    - by Nero Dietrich
    I have a homework question for one specific item with python GUIs. My goal is to create a GUI that asks a random mathematical equation and if the equation is evaluated correctly, then I will receive a message stating that it is correct. My main problem is finding out where to place my statements so that they show up in the labels; I have 1 textbox which generates the random equation, the next textbox is blank for me to enter the solution, and then an "Enter" button at the end to evaluate my solution. It looks like this: [randomly generated equation][Empty space to enter solution] [ENTER] I've managed to get the layout and the evaluate parameters, but I don't know where to go from here. This is my code so far: class Equation(Frame): def __init__(self,parent=None): Frame.__init__(self, parent) self.pack() Equation.make_widgets(self) Equation.new_problem(self) def make_widgets(self): Label(self).grid(row=0, column=1) ent = Entry(self) ent.grid(row=0, column=1) Label(self).grid(row=0, column=2) ent = Entry(self) ent.grid(row=0, column=2) Button(self, text='Enter', command=self.evaluate).grid(row=0, column=3) def new_problem(self): pass def evaluate(self): result = eval(self.get()) self.delete(0, END) self.insert(END, result) print('Correct')

    Read the article

  • Efficient implementation of natural logarithm (ln) and exponentiation

    - by Donotalo
    Basically, I'm looking for implementation of log() and exp() functions provided in C library <math.h>. I'm working with 8 bit microcontrollers (OKI 411 and 431). I need to calculate Mean Kinetic Temperature. The requirement is that we should be able to calculate MKT as fast as possible and with as little code memory as possible. The compiler comes with log() and exp() functions in <math.h>. But calling either function and linking with the library causes the code size to increase by 5 Kilobytes, which will not fit in one of the micro we work with (OKI 411), because our code already consumed ~12K of available ~15K code memory. The implementation I'm looking for should not use any other C library functions (like pow(), sqrt() etc). This is because all library functions are packed in one library and even if one function is called, the linker will bring whole 5K library to code memory.

    Read the article

  • C++Math evaluating incorrectly

    - by Hayden
    I thought I can make life a little easier in data statistics by making a small program which returns the results of sampling distribution of the mean (with standard error). It does this part successfully but in an attempt to return the z-score by using the formula I found here, it returns -1#IND. My interpretation of that formula is: ((1/(sqrt(2*pi)*stdev))*pow(e, (normalpow)) where double normalpow=-0.5*((mean-popmean)*(mean-popmean)/stdev) I did a little more investigating and found that (mean-popmean)*(mean-popmean) was evaluating to 0 no matter what. How can I get around this problem of normalpow evaluating to 0.

    Read the article

  • PHP: Manage roles with math?

    - by Mike
    I once saw an article about how to use a specific type of numbering system to manage roles. A user would be assigned a specific role number and depending on a calculation, the number could stand for multiple roles. Can anybody share this technique with me or share a link? Thanks!

    Read the article

  • python - returns incorrect positive #

    - by tekknolagi
    what i'm trying to do is write a quadratic equation solver but when the solution should be -1, as in quadratic(2, 4, 2) it returns 1 what am i doing wrong? #!/usr/bin/python import math def quadratic(a, b, c): #a = raw_input("What\'s your `a` value?\t") #b = raw_input("What\'s your `b` value?\t") #c = raw_input("What\'s your `c` value?\t") a, b, c = float(a), float(b), float(c) disc = (b*b)-(4*a*c) print "Discriminant is:\n" + str(disc) if disc = 0: root = math.sqrt(disc) top1 = b + root top2 = b - root sol1 = top1/(2*a) sol2 = top2/(2*a) if sol1 != sol2: print "Solution 1:\n" + str(sol1) + "\nSolution 2:\n" + str(sol2) if sol1 == sol2: print "One solution:\n" + str(sol1) else: print "No solution!" EDIT: it returns the following... import mathmodules mathmodules.quadratic(2, 4, 2) Discriminant is: 0.0 One solution: 1.0

    Read the article

  • MySQL Query involving column names containing math operators

    - by devil_fingers
    I'm a MySQL scrub, and I have asked around and checked around the internet for what I'm sure will turn out to be something obvious, but I'm very frustrated with what I thought would be a very, very simple query not working. So here goes. Please be gentle. Basically, in a large database, some of the column names contain mathematical operators like "/" and "+." (Don't ask, it's not my database, I can't do anything about it). Here is the "essence" of my query (I took out the irrelevant stuff for the sake of this question): SELECT PlayerId, Season, WPA/LI AS WPALI FROM tht.stats_batting_master WHERE Season = "2010" AND teamid > 0 AND PA >= 502 GROUP BY playerid ORDER BY WPALI DESC When I run this, it returns "Unknown column 'LI' in 'field list'," I assume because it sees the "/" in WPA/LI as a division sign. Like I said, I'm sure this is easy enough to work around (it must be given how much this database is used), but I haven't' been able to figure out how. Thanks in advance for any help.

    Read the article

  • How to determine the radius and center of a circle when only three noncollinear points are known?

    - by Bob
    I'm working on a C# program that deals with Oracle Spatial geometry. When circle data is stored in a geometry field only three non-collinear points are stored to represent the circle. The problem is that I need to use this data on a Google Maps web page and need the center point and radius of the circle (since my circle drawing function uses that information). Can anyone help with the math involved and translating said math to C#? I think this page may hold the answer, but I'm having a hard time following it. There are formulas for radius and center given three points, but then they define the variables as matrices and I get lost at that point. How would I solve that in code?

    Read the article

  • How to setup Math program

    - by Miles
    I'm needing to write a program (C#) that will allow the user to create generic formulas with variables and numbers. For example: D = A + (A - C / X)(7.8 - 6.6) F = E + (E - C / X)(7.8 - 6.6) FinalResult = (A + D)(0.9) + (E + F)(0.32) + B(0.1) + .023 where all variables would mean for me to go to a database and look something up based on values and return a number in its place. So A would be 2.12 for example (and the same for C and E) Whats the best way to structure this program? How would I make my program read these formulas? I've seen a little bit of the MathML but not sure how to get that started (or an example of it)

    Read the article

  • game currency convert: math efficient

    - by Comradsky
    For variables:4 text views named diamondText, goldText, silverText, and bronzeText;money variable unsigned int money;and an NSTimer, every .1 sec,runs function: -(void)updateMoney{ money++; bronzeText.text = [NSString stringWithFormat:@"%d",money]; silverText.text = [NSString stringWithFormat:@"%d",money%10]; goldText.text = [NSString stringWithFormat:@"%d",money%100]; diamondText.text= [NSString stringWithFormat:@"%d",money%1000]; } Given that my currency is diamond = 10 gold = 10 silver = 10 bronze = 1; What would be most efficient way to calculate and display the money labels? How would you store this variable, with GameCenter and NSDictionary or GameCenter and something else? More details are below if you don't understand. To clarify: bronze has the last 2 numbers, silver has the next 2 numbers, and so on. I understand I could use 4 ints or an array, but i would rather try to use this method, unless theres a much more efficient way. Example: When money = 1000;bronzeText = nothing, silverText = 10,goldText = nothing, diamondText = nothing; What other ways would you do this that you think would be more efficient? I will be calling a function (void)collisionDetector that detects if my player.frame crosses with a flyingObject.frame, and if that object is a coin it gives an added value to money and then calls (void)updateMoney. Im just using the timer to test this and spawn these flying objects.

    Read the article

  • Text + randomchar dosn't work [JavaScript]

    - by user558773
    <script> function makeid() { var text = "var text = document.write(lastNumber);"; var possible = "*+-/"; for( var i=0; i < 1; i++ ) document.write(lastNumber + possible.charAt(Math.floor(Math.random() * possible.length)); return text; } document.write(makeid(1))</script> How do i make this to type for ex: 23* 45- 13/ and so on. What is wrong? It just show me 2 numbers and no char after.

    Read the article

  • Typing math formulas in LaTex and getting them in MathType format?

    - by Tim
    I am asked to type some math formulas that can work in Microsoft Office and MathType equation editor. But I only have access to Ubuntu 12.04 near me, there is LibreOffice available under Ubuntu as well, but I am used to type math formulas in LaTex. So I wonder how to provide math formulas that will work in Microsoft Office and MathType, if I work under Ubuntu, preferably with LaTex but LibreOffice being also acceptable since it is still under Ubuntu? Thanks and regards!

    Read the article

  • Faut-il être bon en math pour être un bon développeur ? Quelle place ont les maths dans votre parcou

    Faut-il être bon en math pour être un bon développeur ? Quelle place ont les maths dans votre métier et votre parcours ? Faut-il être bon en math pour être un bon développeur ? La question mérite d'être posée. Certes, l'informatique est à classer, dans le système universitaire, du coté des sciences "dures", par oppositions aux sciences sociales et humaines. L'enseignement des mathématiques et la rigueur qu'elles amènent paraissent donc indispensable. Pourtant, beaucoup, comme Alan Skorkin - qui vient d'aborder ce sujet sur son blog -, reconnaissent qu'ils n'ont jamais vraiment eu besoin des maths dans leur travail. La position de Alan Skorkin est c...

    Read the article

  • glm matrix conversion for DirectX

    - by niktehpui
    For on of the coursework specification I need to work with DirectX, so I tried to implement a DirectX Renderer in my small cross-platform framework (to have it optionally available for Windows). Since I want to stick to my dependencies I want use glm for vector/matrix/quaternions math. The vectors seem to be fully compatible with DirectX, but the glm::mat4 is not working properly in DirectX Effects Framework. I assumed the reason is that DirectX uses row majors layouts and OpenGL column majors (although if I remember right internally in HLSL DX uses column major as well), so I transposed the matrix, but I still get no proper results compared to using XNA-Math. XNA-Version of the code (works): XMMATRIX world = XMMatrixIdentity(); XMMATRIX view = XMMatrixLookAtLH(XMVectorSet(5.0, 5.0, 5.0, 1.0f), XMVectorZero(), XMVectorSet(0.0f, 1.0f, 0.0f, 0.0f)); XMMATRIX proj = XMMatrixPerspectiveFovLH(0.25f*3.14f, 1.25f, 1.0f, 1000.0f); XMMATRIX worldViewProj = world*view*proj; m_fxWorldViewProj->SetMatrix(reinterpret_cast<float*>(&worldViewProj)); This works flawlessly and displays the expected colored cube. GLM-Version (does not work): glm::mat4 world(1.0f); glm::mat4 view = glm::lookAt(glm::vec3(5.0f, 5.0f, 5.0f), glm::vec3(0.0f, 0.0f, 0.0f), glm::vec3(0.0f, 1.0f, 0.0f)); glm::mat4 proj = glm::perspective(0.25f*3.14f, 1.25f, 1.0f, 1000.0f); glm::mat4 worldViewProj = glm::transpose(world*view*proj); m_fxWorldViewProj->SetMatrix(glm::value_ptr(worldViewProj)); Displays nothing, screen stays black. I really would like to stick to glm on all platforms.

    Read the article

  • How would you solve this graph theory handshake problem in python?

    - by Zachary Burt
    I graduated college last year with a degree in Psychology, but I also took a lot of math for fun. I recently got the book "Introductory Graph Theory" by Gary Chartrand to brush up on my math and have some fun. Here is an exercise from the book that I'm finding particularly befuddling: Suppose you and your husband attended a party with three other married couples. Several handshakes took place. No one shook hands with himself (or herself) or with his (or her) spouse, and no one shook hands with the same person more than once. After all the handshaking was completed, suppose you asked each person, including your husband, how many hands he or she had shaken. Each person gave a different answer. a) How many hands did you shake? b) How many hands did your husband shake? Now, I've been reasoning about this for a while, and trying to draw sample graphs that could illustrate a solution, but I'm coming up empty-handed. My logic is this: there are 8 different vertices in the graph, and 7 of them have different degrees. The values for the degrees must therefore be 0, 1, 2, 3, 4, 5, 6, and x. The # of degrees for one married couple is (0, 6). Since all graphs have an even number of odd vertices, x must be either 5, 3, or 1. What's your solution to this problem? And, if you could solve it in python, how would you do it? (python is fun.) Cheers.

    Read the article

  • How would you solve this graph theory handshake problem in python?

    - by Zachary Burt
    I graduated college last year with a degree in Psychology, but I also took a lot of math for fun. I recently got the book "Introductory Graph Theory" by Gary Chartrand to brush up on my math and have some fun. Here is an exercise from the book that I'm finding particularly befuddling: Suppose you and your husband attended a party with three other married couples. Several handshakes took place. No one shook hands with himself (or herself) or with his (or her) spouse, and no one shook hands with the same person more than once. After all the handshaking was completed, suppose you asked each person, including your husband, how many hands he or she had shaken. Each person gave a different answer. a) How many hands did you shake? b) How many hands did your husband shake? Now, I've been reasoning about this for a while, and trying to draw sample graphs that could illustrate a solution, but I'm coming up empty-handed. My logic is this: there are 8 different vertices in the graph, and 7 of them have different degrees. The values for the degrees must therefore be 0, 1, 2, 3, 4, 5, 6, and x. The # of degrees for one married couple is (0, 6). Since all graphs have an even number of odd vertices, x must be either 5, 3, or 1. What's your solution to this problem? And, if you could solve it in python, how would you do it? (python is fun.) Cheers.

    Read the article

  • Double type returns -1.#IND/NaN error when calculating pi iteratively

    - by Draak
    I am working through a problem for my MCTS certification. The program has to calculate pi until the user presses a key, at which point the thread is aborted, the result returned to the main thread and printed in the console. Simple enough, right? This exercise is really meant to be about threading, but I'm running into another problem. The procedure that calculates pi returns -1.#IND. I've read some of the material on the web about this error, but I'm still not sure how to fix it. When I change double to Decimal type, I unsurprisingly get Overflow Exception very quickly. So, the question is how do I store the numbers correctly? Do I have to create a class to somehow store parts of the number when it gets too big to be contained in a Decimal? Class PiCalculator Dim a As Double = 1 Dim b As Double = 1 / Math.Sqrt(2) Dim t As Double = 1 / 4 Dim p As Double = 1 Dim pi As Double Dim callback As DelegateResult Sub New(ByVal _callback As DelegateResult) callback = _callback End Sub Sub Calculate() Try Do While True Dim a1 = (a + b) / 2 Dim b1 = Math.Sqrt(a * b) Dim t1 = t - p * (a - a1) ^ 2 Dim p1 = 2 * p a = a1 b = b1 t = t1 p = p1 pi = ((a + b) ^ 2) / (4 * t) Loop Catch ex As ThreadAbortException Finally callback(pi) End Try End Sub End Class

    Read the article

  • Solving Naked Triples in Sudoku

    - by Kave
    Hello, I wished I paid more attention to the math classes back in Uni. :) How do I implement this math formula for naked triples? Naked Triples Take three cells C = {c1, c2, c3} that share a unit U. Take three numbers N = {n1, n2, n3}. If each cell in C has as its candidates ci ? N then we can remove all ni ? N from the other cells in U.** I have a method that takes a Unit (e.g. a Box, a row or a column) as parameter. The unit contains 9 cells, therefore I need to compare all combinations of 3 cells at a time that from the box, perhaps put them into a stack or collection for further calculation. Next step would be taking these 3-cell-combinations one by one and compare their candidates against 3 numbers. Again these 3 numbers can be any possible combination from 1 to 9. Thats all I need. But how would I do that? How many combinations would I get? Do I get 3 x 9 = 27 combinations for cells and then the same for numbers (N)? How would you solve this in classic C# loops? No Lambda expression please I am already confused enough :) Many Thanks for any help,

    Read the article

  • What function does .NET NPV() use? Doesn't match manual calculations

    - by Matthew PK
    I am using the NPV() function in VB.NET to get NPV for a set of cash flows. However, the result of NPV() is not consistent with my results performing the calculation manually (nor the Investopedia NPV calc... which matches my manual results) My correct manual results and the NPV() results are close, within 5%.. but not the same... Manually, using the NPV formula: NPV = C0 + C1/(1+r)^1 + C2/(1+r)^2 + C3/(1+r)^3 + .... + Cn/(1+r)^n The manual result is stored in RunningTotal With rate r = 0.04 and period n = 10 Here is my relevant code: EDIT: Do I have OBOB somewhere? YearCashOutFlow = CDbl(TxtAnnualCashOut.Text) YearCashInFlow = CDbl(TxtTotalCostSave.Text) YearCount = 1 PAmount = -1 * (CDbl(TxtPartsCost.Text) + CDbl(TxtInstallCost.Text)) RunningTotal = PAmount YearNPValue = PAmount AnnualRateIncrease = CDbl(TxtUtilRateInc.Text) While AnnualRateIncrease > 1 AnnualRateIncrease = AnnualRateIncrease / 100 End While AnnualRateIncrease = 1 + AnnualRateIncrease ' ZERO YEAR ENTRIES ListBoxNPV.Items.Add(Format(PAmount, "currency")) ListBoxCostSave.Items.Add("$0.00") ListBoxIRR.Items.Add("-100") ListBoxNPVCum.Items.Add(Format(PAmount, "currency")) CashFlows(0) = PAmount '''' Do While YearCount <= CInt(TxtLifeOfProject.Text) ReDim Preserve CashFlows(YearCount) CashFlows(YearCount) = Math.Round(YearCashInFlow - YearCashOutFlow, 2) If CashFlows(YearCount) > 0 Then OnePos = True YearNPValue = CashFlows(YearCount) / (1 + DiscountRate) ^ YearCount RunningTotal = RunningTotal + YearNPValue ListBoxNPVCum.Items.Add(Format(Math.Round(RunningTotal, 2), "currency")) ListBoxCostSave.Items.Add(Format(YearCashInFlow, "currency")) If OnePos Then ListBoxIRR.Items.Add((IRR(CashFlows, 0.1)).ToString) ListBoxNPV.Items.Add(Format(NPV(DiscountRate, CashFlows), "currency")) Else ListBoxIRR.Items.Add("-100") ListBoxNPV.Items.Add(Format(RunningTotal, "currency")) End If YearCount = YearCount + 1 YearCashInFlow = AnnualRateIncrease * YearCashInFlow Loop

    Read the article

  • Run Javascript on the body of a Gmail message

    - by saturn
    I want to display LaTeX math in the gmail messages that I receive, so that for example $\mathbb P^2$ would show as a nice formula. Now, there are several Javascripts available (for example, this one, or MathJax which would do the job, I just need to call them at the right time to manipulate the gmail message. I know that this is possible to do in "basic HTML" and "print" views. Is it possible to do in the standard Gmail view? I tried to insert a call to the javascript right before the "canvas_frame" iframe, but that did not work. My suspicion is that manipulating a Gmail message by any Javascript would be a major security flaw (think of all the malicious links one could insert) and that Google does everything to prevent this. And so the answer to my question is probably 'no'. Am I right in this? Of course, it would be very easy for Google to implement viewing of LaTeX and MathML math simply by using MathJax on their servers. I made the corresponding Gmail Lab request, but no answer, and no interest from Google apparently. So, again: is this possible to do without Google's cooperation, on the client side?

    Read the article

  • Plotting a graph with GD

    - by Nayena
    Here it goes. I have been thinking about this for a long time, and havent really been able to put up a proper way to do it yet. I havent implemented anything yet, as im still designing the thing. The idea is that i crawl a website for internal links, i got this settled, its easy, but after the crawling, i end up with an array with lots of links, and how many times those particular link appears on the site that i crawled (and how they're connected). With this huge array, i want to draw a graph somehow. Assuming i can handle the data correctly, the real question here is how i can draw this in a image by the use of the GD library. I figured if theres less than 12 elements, i can align them up on a unit circle spacing them up as a circle and then connecting them accordingly, so anything up to 12 elements shouldn't be a problem, but if theres more than 12, it could be awesome getting them lined up like this Or well, thats just a rough drawing, but i guess its just to prove a point. So i'm here looking for guidance or tips towards getting the math down to getting the stuff lined up in a good way. I have previously made bar-graphs, so i have little experience doing math with GD. If possible, id prefer not using some plotter-library - in the end, it gives me a better understanding on how things are supposed to be.

    Read the article

  • Optimizing a 3D World Javascript Animation

    - by johnny
    Hi! I've recently come up with the idea to create a tag cloud like animation shaped like the earth. I've extracted the coastline coordinates from ngdc.noaa.gov and wrote a little script that displayed it in my browser. Now as you can imagine, the whole coastline consists of about 48919 points, which my script would individually render (each coordinate being represented by one span). Obviously no browser is capable of rendering this fluently - but it would be nice if I could render as much as let's say 200 spans (twice as much as now) on my old p4 2.8 Ghz (as a representative benchmark). Are there any javascript optimizations I could use in order to speed up the display of those spans? One 'coordinate': <div id="world_pixels"> <span id="wp_0" style="position:fixed; top:0px; left:0px; z-index:1; font-size:20px; cursor:pointer;cursor:hand;" onmouseover="magnify_world_pixel('wp_0');" onmouseout="shrink_world_pixel('wp_0');" onClick="set_askcue_bar('', 'new york')">new york</span> </div> The script: $(document).ready(function(){ world_pixels = $("#world_pixels span"); world_pixels.spin(); setInterval("world_pixels.spin()",1500); }); z = new Array(); $.fn.spin = function () { for(i=0; i<this.length; i++) { /*actual screen coordinates: x/y/z --> left/font-size/top 300/13/0 300/6/300 | / |/ 0/13/300 ----|---- 600/13/300 /| / | 300/20/300 300/13/600 */ /*scale font size*/ var resize_x = 1; /*scale width*/ var resize_y = 2.5; /*scale height*/ var resize_z = 2.5; var from_left = 300; var from_top = 20; /*actual math coordinates: 1 -1 | / |/ 1 ----|---- -1 /| / | 1 -1 */ //var get_element = document.getElementById(); //var font_size = parseInt(this.style.fontSize); var font_size = parseInt($(this[i]).css("font-size")); var left = parseInt($(this[i]).css("left")); if (coast_line_array[i][1]) { } else { var top = parseInt($(this[i]).css("top")); z[i] = from_top + (top - (300 * resize_z)) / (300 * resize_z); //global beacause it's used in other functions later on var top_new = from_top + Math.round(Math.cos(coast_line_array[i][2]/90*Math.PI) * (300 * resize_z) + (300 * resize_z)); $(this[i]).css("top", top_new); coast_line_array[i][3] = 1; } var x = resize_x * (font_size - 13) / 7; var y = from_left + (left- (300 * resize_y)) / (300 * resize_y); if (y >= 0) { this[i].phi = Math.acos(x/(Math.sqrt(x^2 + y^2))); } else { this[i].phi = 2*Math.PI - Math.acos(x/(Math.sqrt(x^2 + y^2))); i } this[i].theta = Math.acos(z[i]/Math.sqrt(x^2 + y^2 + z[i]^2)); var font_size_new = resize_x * Math.round(Math.sin(coast_line_array[i][4]/90*Math.PI) * Math.cos(coast_line_array[i][0]/180*Math.PI) * 7 + 13); var left_new = from_left + Math.round(Math.sin(coast_line_array[i][5]/90*Math.PI) * Math.sin(coast_line_array[i][0]/180*Math.PI) * (300 * resize_y) + (300 * resize_y)); //coast_line_array[i][6] = coast_line_array[i][7]+1; if ((coast_line_array[i][0] + 1) > 180) { coast_line_array[i][0] = -180; } else { coast_line_array[i][0] = coast_line_array[i][0] + 0.25; } $(this[i]).css("font-size", font_size_new); $(this[i]).css("left", left_new); } } resize_x = 1; function magnify_world_pixel(element) { $("#"+element).animate({ fontSize: resize_x*30+"px" }, { duration: 1000 }); } function shrink_world_pixel(element) { $("#"+element).animate({ fontSize: resize_x*6+"px" }, { duration: 1000 }); } I'd appreciate any suggestions to optimize my script, maybe there is even a totally different approach on how to go about this. The whole .js file which stores the array for all the coordinates is available on my page, the file is about 2.9 mb, so you might consider pulling the .zip for local testing: metaroulette.com/files/31218.zip metaroulette.com/files/31218.js P.S. the php I use to create the spans: <?php //$arbitrary_characters = array('a','b','c','ddsfsdfsdf','e','f','g','h','isdfsdffd','j','k','l','mfdgcvbcvbs','n','o','p','q','r','s','t','uasdfsdf','v','w','x','y','z','0','1','2','3','4','5','6','7','8','9',); $arbitrary_characters = array('cat','table','cool','deloitte','askcue','what','more','less','adjective','nice','clinton','mars','jupiter','testversion','beta','hilarious','lolcatz','funny','obama','president','nice','what','misplaced','category','people','religion','global','skyscraper','new york','dubai','helsinki','volcano','iceland','peter','telephone','internet', 'dialer', 'cord', 'movie', 'party', 'chris', 'guitar', 'bentley', 'ford', 'ferrari', 'etc', 'de facto'); for ($i=0; $i<96; $i++) { $arb_digits = rand (0,45); $arbitrary_character = $arbitrary_characters[$arb_digits]; //$arbitrary_character = "."; echo "<span id=\"wp_$i\" style=\"position:fixed; top:0px; left:0px; z-index:1; font-size:20px; cursor:pointer;cursor:hand;\" onmouseover=\"magnify_world_pixel('wp_$i');\" onmouseout=\"shrink_world_pixel('wp_$i');\" onClick=\"set_askcue_bar('', '$arbitrary_character')\">$arbitrary_character</span>\n"; } ?>

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 18 19 20 21 22 23 24 25 26 27 28 29  | Next Page >