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  • Does any body see a reson in DesignForExtension Check in Checkstyle?

    - by Roman Ivanov
    Check: http://checkstyle.sourceforge.net/config_design.html#DesignForExtension False positives: Checkstyle "Method Not Designed For Extension" error being incorrectly issued? checkstyle Method is not designed for extension - needs to be abstract, final or empty https://sourceforge.net/p/checkstyle/bugs/688/ Look like all switch that Check off in their configurations. Does anybody could show real code example where this Check is useful ? and good for developers.

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  • Does Socket open another thread? Does it return something?

    - by Roman
    In the client application I call new Socket(serverIP,serverPort). As a result the client application sends a request to the server application to open a socket. Does it start a new thread? I mean which of the following is true? Client application sends a request and immediately starts to execute following commands (not weighting for the answer). Client sends the request and weights for the answer. As soon as the answer is obtained, the client application continues to execute following commands. The second case seems to be more realistic and logical for me. However, I do not understand what happens if the server does not open a socket and it does not say that it does not "want" to open the second (it can happen if the server does not exist or network is broken). What will happen in this case? Will server weight forever? In general it would be nice for the client to know what is the result of its request for the socket. For example I can imagine the following situations: The socket is opened by the server. The server refuses to open a socket. So, server exists, it got the request from the client but it says "no". There is no response from the server. I know that new Socket(serverIP,serverPort) does not "return" this kind of information. But it throws exceptions. One of them is "UnkownHostException". When it is thrown? When the server is not responding for a while (for how long)? ADDED: I just found out that UnknownHostException is thrown to indicate that the IP address of a host could not be determined. So, it is unrelated with the above described situations (server is not responding, server refuses to open a socket).

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  • Can I run two web servers on the same computer?

    - by Roman
    I just found out that I can write a really simple web server using Python. I have already an Apache web server I would like to try the Python based web server on this machine. But I am afraid that I can get some kind of conflict if I try it. I mean how two web server will "decide" who needs to server a request from a client?

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  • How can I specify dependencies in the manifest file and then to include it into my .jar file?

    - by Roman
    I generated .class files by the following command: javac -cp \directoryName\external.jar myPackageDirectory\First.java myPackageDirectory\Second.java I needed to use -cp during compilation and name of .jar file of an "external" library (external.jar) to be able to use this library from my code. Using my .class files I have generated my .jar file in the following way: jar cfm app.jar manifest.txt myPackageDirectory\*.class manifest.txt contains just one line: Main-Class: myPackageName.First My problem is that I am not sure that I will be able to run my .jar file on other computers. I think so because during the compilation I specified the location of the .jar file of the external library. So, my .class files (included into the .jar file will try to find the .jar file of the external library in a specific directory and there is no guaranty that that the .jar file of the external library will be in the same directory as on the my computer. I heard that the above problem can be solved by a usage of a MANIFEST file that I include in my own jar, and which will list dependency locations but I do not understand how it works. I do need to specify location of the "external.jar" at the compilation stage (otherwise the compiler complains).

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  • Why I cannot create DB in MySQL throw PHP?

    - by Roman
    I have this code: $link = mysql_connect("localhost", "ctman", "blablabla"); if ( ! $link ) die ("I cannot connect to MySQL.<br>\n"); else print "Connection is established.<br>\n"; // Create the "ct" database. mysql_query("create database ct", $link) or die("I cannot create the DB: ".mysql_error()."<br>\n"); And I get this error message: I cannot create the DB: Access denied for user 'ctmanager'@'%' to database 'ct' Does anybody have any idea why I cannot create a DB and why I have '@%' symbols in the error message?

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  • an algorhithm for filtering out raw txt files

    - by Roman Luštrik
    Imagine you have a .txt file of the following structure: >>> header >>> header >>> header K L M 200 0.1 1 201 0.8 1 202 0.01 3 ... 800 0.4 2 >>> end of file 50 0.1 1 75 0.78 5 ... I would like to read all the data except lines denoted by >>> and lines below the >>> end of file line. So far I've solved this using read.table(comment.char = ">", skip = x, nrow = y) (x and y are currently fixed). This reads the data between the header and >>> end of file. However, I would like to make my function a bit more plastic regarding the number of rows. Data may have values larger than 800, and consequently more rows. I could scan or readLines the file and see which row corresponds to the >>> end of file and calculate the number of lines to be read. What approach would you use?

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  • How can I force the server socket to re-accept a request from a client?

    - by Roman
    For those who does not want to read a long question here is a short version: A server has an opened socket for a client. The server gets a request to open a socket from the same client-IP and client-port. I want to fore the server not to refuse such a request but to close the old socket and open a new one. How can I do ti? And here is a long (original) question: I have the following situation. There is an established connection between a server and client. Then an external software (Bonjour) says to my client the it does not see the server in the local network. Well, client does nothing about that because of the following reasons: If Bonjour does not see the server it does not necessarily means that client cannot see the server. Even if the client trusts the Bonjour and close the socket it does not improve the situation ("to have no open socket" is worser that "to have a potentially bad socket"). So, client do nothing if server becomes invisible to Bonjour. But than the server re-appears in the Bonjour and Bonjour notify the client about that. In this situation the following situations are possible: The server reappears on a new IP address. So, the client needs to open a new socket to be able to communicate with the server. The server reappears on the old IP address. In this case we have two subcases: 2.1. The server was restarted (switched off and then switched on). So, it does not remember the old socket (which is still used by the client). So, client needs to close the old socket and open a new one (on the same server-IP address and the same server-port). 2.2. We had a temporal network problem and the server was running the whole time. So, the old socket is still available for the use. In this case the client does not really need to close the old socket and reopen a new one. But to simplify my life I decide to close and reopen the socket on the client side in any case (in spite on the fact that it is not really needed in the last described situation). But I can have problems with that solution. If I close the socket on the client side and than try to reopen a socket from the same client-IP and client-port, server will not accept the call for a new socket. The server will think that such a socket already exists. Can I write the server in such a way, that it does not refuse such calls. For example, if it (the server) sees that a client send a request for a socket from the same client-IP and client-port, it (server) close the available socket, associated with this client-IP and client-port and than it reopens a new socket.

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  • Where should I put interface?

    - by Roman
    I program a class in which I have a method which takes an callback object from an external software. At the moment Eclipse says that it does not know the type of the object I gave as argument (it is expectable since I do not specify this type, it's done by the external software). So, I think I need to write an interface for the object which I give as an argument to my method. In this respect I have two questions. Is it really so? Can I solve the mentioned problem in the mentioned way. If it is the case, where should I put this interface? In the same file where my class is? In the class? Outside of the class?

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  • Junit before class ( non static )

    - by Roman
    Are there any best practices to get Junit execute a function once in a test file , and it should also not be static. like @BeforeClass on non static function? Here is an ugly solution : @Before void init(){ if (init.get() == false){ init.set(true); // do once block } } well this is something i dont want to do , and i am looking for an integrated junit solution.

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  • How can I close my software in a save way?

    - by Roman
    Up to now I used my application as a stand alone product. So, when user pressed "Stop" button I called System.exit(0); and it was fine. Now my application will be called (in a programmatic way) from another program. So, I afraid that System.exit(0); will kill not only my process but also the external software which started my program. So, what is the correct way to shutdown my application if a corresponding request from an external software is received? My application is an GUI application. So, I want to close the window but I also want to close all processes performed by my program. ADDED: To be more specific, I want to close all threads started by my program. My program does not start any OS process or any other program.

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  • Can I have a set containing identical elements?

    - by Roman
    It is convenient for me to use a set. I like how I can "add" ("remove") an element to (from) the set. It is also convenient to check if a given element is in the set. The only problem, I found out that I cannot add a new element to a set if the set has already such an element. Is it possible to have "sets" which can contain several identical elements.

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  • What is the event dispatching thread?

    - by Roman
    I know what "thread" means and if I understand the event dispatching thread (EDT) as "just a thread", it explains a lot but, apparently, it does not explain everything. I do not understand what is special about this thread. For example I do not understand why we should start a GUI in a the EDT? Why the "main" thread is bed for GUI? Well, if we just do not want to occupy the main thread why we cannot start GUI just in "another thread" why it should be some "special" thread called EDT? Then I do not understand why we cannot start the EDT like any other thread? Why we should use some special tool (called invokeLater). And why GUI, unlike any other thread, does not start immediately. We should wait until it is ready to accept our job. Is it because EDT can, potentially execute several task simultaneously? If you decide to answer this question, could you pleas use a really simple terminology because otherwise, I am afraid, I will not be able to understand the answer.

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  • Invalidating UITableView contents

    - by Roman
    I have an application with several UITableViewControllers. Now, the user is allowed to change "Data source". In that case I need to invalidate (reset) data in the relevant UITableViews. I figured out, that I can use NSNotificationCenter and add these controllers as observers to events which will be generated when the data source changes. The question is, how do I reset the underlying tables? I can, of course, set some boolean flag, and call UITableView:reloadData in viewWillAppear or viewDidAppear, but I was wondering, if there's a cleaner way of doing it. Or perhaps I'm completely missing the point, and I don't need NSNotificationCenter altogether. Thank you very much in advance.

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  • Why a new instance uses logger from old instances?

    - by Roman
    I generate 2 instances in this way: gameManager manager1 = new CTManager(owner,players1,"en"); manager1.start(); gameManager manager2 = new CTManager(owner,players2,"en"); manager2.start(); The start() method of the gameManager looks like that: void start() { game.start(); } When I create the game instance I create a loger: log = Logger.getLogger("TestLog"); (log is a public field of the class in which the game belongs). In the game.start() I run many processes and give them a reference to the corresponding log. So, I expect that manager1 and manager2 will write to different files. But manager2 writes to its own file and to the log file of the manager1. Why can it happen?

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  • Guice child injector override binding

    - by Roman
    Hi All I am trying to to override a binding in a child injector that was already configured in a base injector. like that : public class PersistenceModule extends Abstract{ @Override protected void configure() { bind(IProductPersistenceHelper.class).to(ProductPersistenceHelper.class); } } then : Injector injector = Guice.createInjector(new PersistenceModule()); injector.createChildInjector(new AbstractModule(){ @Override protected void configure() { bind(IProductPersistenceHelper.class).to(MockProductPersistenceHelper.class); } }) Guice is complaining that it has already a binding for that. Are there any patterns or best practices for that problem ?

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  • calling command line from .NET application

    - by Roman Dorevich
    I want to call from a c# application a command line starting from it an application and retrieve the stat from it. I did this but something is missing: ProcessStartInfo psf = new ProcessStartInfo("cmd.exe", "/C time"); psf.WindowStyle = ProcessWindowStyle.Hidden; psf.RedirectStandardOutput = true; psf.UseShellExecute = false; psf.CreateNoWindow = true; Process p = Process.Start(psf); StreamReader sr = p.StandardOutput; p.WaitForExit(); What is wrong ?

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  • CSS styles gone after Ajax call in IE 7

    - by roman m
    I've had a problem with my styles not being applied after AJAX calls. My styles were not in the < HEAD section of the page, and they were only recognized by IE on initial Page_Load. If you know of any other ways to fix this problem, post them here. This is more of a reference, hope this helps some people.

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