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  • New Skool Crosstabbing

    - by Tim Dexter
    A while back I spoke about having to go back to BIP's original crosstabbing solution to achieve a certain layout. Hok Min has provided a 'man' page for the new crosstab/pivot builder for 10.1.3.4.1 users. This will make the documentation drop but for now, get it here! The old, hand method is still available but this new approach, is more efficient and flexible. That said you may need to get into the crosstab code to tweak it where the crosstab dialog can not help. I had to do this, this week but more on that later. The following explains how the crosstab wizard builds the crosstab and what the fields inside the resulting template structure are there for. To create the crosstab a new XDO command "<?crosstab:...?>" has been created. XDO Command: <?crosstab: ctvarname; data-element; rows; columns; measures; aggregation?> Parameter Description Example Ctvarname Crosstab variable name. This is automatically generated by the Add-in. C123 data-element This is the XML data element that contains the data. "//ROW" Rows This contains a list of XML elements for row headers. The ordering information is specified within "{" and "}". The first attribute is the sort element. Leaving it blank means the sort element is the same as the row header element. The attribute "o" means order. Its value can be "a" for ascending, or "d" for descending. The attribute "t" means type. Its value can be "t" for text, and "n" for numeric. There can be more than one sort elements, example: "emp-full-name {emp-lastname,o=a,t=n}{emp-firstname,o=a,t=n}. This will sort employee by last name and first name. "Region{,o=a,t=t}, District{,o=a,t=t}" In the example, the first row header is "Region". It is sort by "Region", order is ascending, and type is text. The second row header is "District". It is sort by "District", order is ascending, and type is text. Columns This contains a list of XML elements for columns headers. The ordering information is specified within "{" and "}". The first attribute is the sort element. Leaving it blank means the sort element is the same as the column header element. The attribute "o" means order. Its value can be "a" for ascending, or "d" for descending. The attribute "t" means type. Its value can be "t" for text, and "n" for numeric. There can be more than one sort elements, example: "emp-full-name {emp-lastname,o=a,t=n}{emp-firstname,o=a,t=n}. This will sort employee by last name and first name. "ProductsBrand{,o=a,t=t}, PeriodYear{,o=a,t=t}" In the example, the first column header is "ProductsBrand". It is sort by "ProductsBrand", order is ascending, and type is text. The second column header is "PeriodYear". It is sort by "District", order is ascending, and type is text. Measures This contains a list of XML elements for measures. "Revenue, PrevRevenue" Aggregation The aggregation function name. Currently, we only support "sum". "sum" Using the Oracle BI Publisher Template Builder for Word add-in, we are able to construct the following Pivot Table: The generated XDO command for this Pivot Table is as follow: <?crosstab:c547; "//ROW";"Region{,o=a,t=t}, District{,o=a,t=t}"; "ProductsBrand{,o=a,t=t},PeriodYear{,o=a,t=t}"; "Revenue, PrevRevenue";"sum"?> Running the command on the give XML data files generates this XML file "cttree.xml". Each XPath in the "cttree.xml" is described in the following table. Element XPath Count Description C0 /cttree/C0 1 This contains elements which are related to column. C1 /cttree/C0/C1 4 The first level column "ProductsBrand". There are four distinct values. They are shown in the label H element. CS /cttree/C0/C1/CS 4 The column-span value. It is used to format the crosstab table. H /cttree/C0/C1/H 4 The column header label. There are four distinct values "Enterprise", "Magicolor", "McCloskey" and "Valspar". T1 /cttree/C0/C1/T1 4 The sum for measure 1, which is Revenue. T2 /cttree/C0/C1/T2 4 The sum for measure 2, which is PrevRevenue. C2 /cttree/C0/C1/C2 8 The first level column "PeriodYear", which is the second group-by key. There are two distinct values "2001" and "2002". H /cttree/C0/C1/C2/H 8 The column header label. There are two distinct values "2001" and "2002". Since it is under C1, therefore the total number of entries is 4 x 2 => 8. T1 /cttree/C0/C1/C2/T1 8 The sum for measure 1 "Revenue". T2 /cttree/C0/C1/C2/T2 8 The sum for measure 2 "PrevRevenue". M0 /cttree/M0 1 This contains elements which are related to measures. M1 /cttree/M0/M1 1 This contains summary for measure 1. H /cttree/M0/M1/H 1 The measure 1 label, which is "Revenue". T /cttree/M0/M1/T 1 The sum of measure 1 for the entire xpath from "//ROW". M2 /cttree/M0/M2 1 This contains summary for measure 2. H /cttree/M0/M2/H 1 The measure 2 label, which is "PrevRevenue". T /cttree/M0/M2/T 1 The sum of measure 2 for the entire xpath from "//ROW". R0 /cttree/R0 1 This contains elements which are related to row. R1 /cttree/R0/R1 4 The first level row "Region". There are four distinct values, they are shown in the label H element. H /cttree/R0/R1/H 4 This is row header label for "Region". There are four distinct values "CENTRAL REGION", "EASTERN REGION", "SOUTHERN REGION" and "WESTERN REGION". RS /cttree/R0/R1/RS 4 The row-span value. It is used to format the crosstab table. T1 /cttree/R0/R1/T1 4 The sum of measure 1 "Revenue" for each distinct "Region" value. T2 /cttree/R0/R1/T2 4 The sum of measure 1 "Revenue" for each distinct "Region" value. R1C1 /cttree/R0/R1/R1C1 16 This contains elements from combining R1 and C1. There are 4 distinct values for "Region", and four distinct values for "ProductsBrand". Therefore, the combination is 4 X 4 è 16. T1 /cttree/R0/R1/R1C1/T1 16 The sum of measure 1 "Revenue" for each combination of "Region" and "ProductsBrand". T2 /cttree/R0/R1/R1C1/T2 16 The sum of measure 2 "PrevRevenue" for each combination of "Region" and "ProductsBrand". R1C2 /cttree/R0/R1/R1C1/R1C2 32 This contains elements from combining R1, C1 and C2. There are 4 distinct values for "Region", and four distinct values for "ProductsBrand", and two distinct values of "PeriodYear". Therefore, the combination is 4 X 4 X 2 è 32. T1 /cttree/R0/R1/R1C1/R1C2/T1 32 The sum of measure 1 "Revenue" for each combination of "Region", "ProductsBrand" and "PeriodYear". T2 /cttree/R0/R1/R1C1/R1C2/T2 32 The sum of measure 2 "PrevRevenue" for each combination of "Region", "ProductsBrand" and "PeriodYear". R2 /cttree/R0/R1/R2 18 This contains elements from combining R1 "Region" and R2 "District". Since the list of values in R2 has dependency on R1, therefore the number of entries is not just a simple multiplication. H /cttree/R0/R1/R2/H 18 The row header label for R2 "District". R1N /cttree/R0/R1/R2/R1N 18 The R2 position number within R1. This is used to check if it is the last row, and draw table border accordingly. T1 /cttree/R0/R1/R2/T1 18 The sum of measure 1 "Revenue" for each combination "Region" and "District". T2 /cttree/R0/R1/R2/T2 18 The sum of measure 2 "PrevRevenue" for each combination of "Region" and "District". R2C1 /cttree/R0/R1/R2/R2C1 72 This contains elements from combining R1, R2 and C1. T1 /cttree/R0/R1/R2/R2C1/T1 72 The sum of measure 1 "Revenue" for each combination of "Region", "District" and "ProductsBrand". T2 /cttree/R0/R1/R2/R2C1/T2 72 The sum of measure 2 "PrevRevenue" for each combination of "Region", "District" and "ProductsBrand". R2C2 /cttree/R0/R1/R2/R2C1/R2C2 144 This contains elements from combining R1, R2, C1 and C2, which gives the finest level of details. M1 /cttree/R0/R1/R2/R2C1/R2C2/M1 144 The sum of measure 1 "Revenue". M2 /cttree/R0/R1/R2/R2C1/R2C2/M2 144 The sum of measure 2 "PrevRevenue". Lots to read and digest I know! Customization One new feature I discovered this week is the ability to show one column and sort by another. I had a data set that was extracting month abbreviations, we wanted to show the months across the top and some row headers to the side. As you may know XSL is not great with dates, especially recognising month names. It just wants to sort them alphabetically, so Apr comes before Jan, etc. A way around this is to generate a month number alongside the month and use that to sort. We can do that in the crosstab, sadly its not exposed in the UI yet but its doable. Go back up and take a look a the initial crosstab command. especially the Rows and Columns entries. In there you will find the sort criteria. "ProductsBrand{,o=a,t=t}, PeriodYear{,o=a,t=t}" Notice those leading commas inside the curly braces? Because there is no field preceding them it means that the crosstab should sort on the column before the brace ie PeriodYear. But you can insert another column in the data set to sort by. To get my sort working how I needed. <?crosstab:c794;"current-group()";"_Fund_Type_._Fund_Type_Display_{_Fund_Type_._Fund_Type_Sort_,o=a,t=n}";"_Fiscal_Period__Amount__._Amt_Fm_Disp_Abbr_{_Fiscal_Period__Amount__._Amt_Fiscal_Month_Sort_,o=a,t=n}";"_Execution_Facts_._Amt_";"sum"?> Excuse the horribly verbose XML tags, good ol BIEE :0) The emboldened columns are not in the crosstab but are in the data set. I just opened up the field, dropped them in and changed the type(t) value to be 'n', for number, instead of the default 'a' and my crosstab started sorting how I wanted it. If you find other tips and tricks, please share in the comments.

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  • How to overcome politics of the net (Google translate code refuses to work from a specific region) [closed]

    - by Jawad
    Possible Duplicate: How to overcome politics of the net (Google translate code refuses to work from a specific region) I have this Web Site. It uses the Google Translate API (Can't post the link, does not open from this region) with the following code. <meta name="google-translate-customization" content="9f841e7780177523-3214ceb76f765f38-gc38c6fe6f9d06436-c"></meta> <script type="text/javascript"> function googleTranslateElementInit() { new google.translate.TranslateElement({pageLanguage: 'en'}, 'google_translate_element'); } </script> <script type="text/javascript" src="http://translate.google.com/translate_a/element.js?cb=googleTranslateElementInit"></script> The problem is since this, it just stopped working. On the site you can see that I had to actually remove the above from here, here, and here while left it here, here, here and here. This is so because the the web site "refuses" to load at all with the pages that have the code (i.e., from this region.) If I use Firefox Stealthy Plugin and open the site in Firefox, It works like a charm without any problems. But with Google Chrome, Apple Safari and Opera Web browser, the site does not load/open at all because of the Google translate. (I know this because If I remove the Google Translate Code, the site works/loads fine) It was one thing to program for "cross browser compatability" and alltogether another to program for "cross region compatability". What can I do to make sure that the site works from anywhere? Do I completely remove the Google Translate code and just have to do without the additional functionality or Do I look for alternatives like this or according to this?

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  • How to select parent row only if has at least one child?

    - by Matt McCormick
    I have a simple one-to-many relationship. I would like to select rows from the parent only when they have at least one child. So, if there are no children, then the parent row is not returned in the result set. Eg. Parent: +--+---------+ |id| text | +--+---------+ | 1| Blah | | 2| Blah2 | | 3| Blah3 | +--+---------+ Children +--+------+-------+ |id|parent| other | +--+------+-------+ | 1| 1 | blah | | 2| 1 | blah2 | | 3| 2 | blah3 | +--+------+-------+ I want the results to be: +----+------+ |p.id|p.text| +----+------+ | 1 | Blah | | 2 | Blah2| +----+------+

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  • Select statement that combines similar rows with certain ids?

    - by vegatron
    hi I have a warehouse_products table which defines how many products in the warehouses so lets say I have 20 records/rows in the table, some rows may contain the same product id but in a different warehouse I need to create select statement that give every product one row, and in this row I must have the quantity in warehouse A and warehouse B .. so in the end I will get for example 10 rows that contain all the data

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  • Why can't I SELECT a parent field that doesn't have a child?

    - by myaccount
    (rest_branches) is the table of restaurants. (phone_numbers) is another table which contains the restaurants phone_numbers, and it has a field called (branch_id) which references the restaurant id. When I try: SELECT * FROM rest_branches NATURAL JOIN phone_numbers I only get the restaurants which have a phone_number. What should I do to get all restaurants even if they don't have a phone number?

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  • Complex SELECT statement; one-to-many all details in one row

    - by RubyWedge
    There are two tables: Products ID (Primary Key), ProductName PlannedByMonths ProductID (Primary Key) (Link to the Products table many-to-one), MonthNumber (Primary Key), QtytoProduce, How to write SELECT statement to retrieve results in the following format? ProductName, QtytoProduceMonth1, QtytoProduceMonth2, QtytoProduceMonth3, QtytoProduceMonth4, QtytoProduceMonth5, QtytoProduceMonth6, QtytoProduceMonth7, QtytoProduceMonth8, QtytoProduceMonth9, QtytoProduceMonth10, QtytoProduceMonth11, QtytoProduceMonth12 Thank you.

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  • [MYSQL] select statement that combines similar rows with certain ids ?

    - by vegatron
    hi I have a warehouse_products table which defines how many products in the warehouses so lets say I have 20 records/rows in the table, some rows may contain the same product id but in a different warehouse I need to create select statement that give every product one row, and in this row I must have the quantity in warehouse A and warehouse B .. so in the end I will get for example 10 rows that contain all the data id domain_id warehouse_id wh_product_id quantity 2 1 2 2 84 3 1 1 3 221 4 1 3 3 0 5 1 1 3 14 6 1 1 2 73 7 1 1 1 123

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  • WPF Orthographic Camera. Region of view

    - by Evgeny
    Hello. I added Orthographic Camera to my project. I want to show my chart on screen proportional. For example height is 4 and width 4 (region from -2 to 2). I set width to 4 and it perfectly fit my square in widht. but i have problem with height. The chart top and bottom is always out of screen space. Why this happens and how to set to camera view the same width and height ? Camera position: 0,0,5 Viewport have size: 571.5x497 On image we can see on vertical axis points from 2 to -2 but on vertical much more. How to make them same? Image: http://i076.radikal.ru/1003/96/273c74ed9add.png Sorry for my English.

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  • SQL Server CE - Internal error: Cannot open the shared memory region

    - by blu
    I have a SQL Server CE database that works fine in dev, but when installed on the client has an issue. The SQL Server CE 3.5 dependencies are copied as part of the deployment. The target machine is a clean Windows 7 32-bit Ultimate image. The message for the exception in the event log is: Internal error: Cannot open the shared memory region. It looks like this is SSCE_M_CANTOPENSHAREDMEMORY and the site says there isn't a connection string value to change this and that these issues are typically not resolvable by the end developers. Has anyone run into this, and if so were you able to resolve this issue?

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  • Text size for drop down menu/input select not working in Safari

    - by Nick
    Hello All, First question... I'm having trouble getting ANY of the Drop down menu/Input Select's to appear with size 18 font in Safari. Works fine in FF. Code: <form class="form"> <select name="make"> <option value="0"> All</option> </select> </form> Css: .form input{ font-size:18px; margin-bottom:0px; } Any ideas? Can view live at [http://www.motolistr.com][1] Best, Nick EDIT 1: Thanks for the quick reply. I added a style to the select itself to avoid confusion. I tried; <select name='make' style='font-size: 18pt;'> </select> And <select name='make' style='font-size: 18px;'> </select> And <select name='make' style='font-size: 1.3em;'> </select> Still not working in SAFARI...Again FF works fine with all 3. Best, Nick

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  • Need to combine common result of two select statements

    - by Anup
    i have to select the common coloumns c1 ,c2,c3 from result of two sql satements. 1) select c1, c2, c3,count(c3) from (select * from form_name where data_created >'1273446000' and data_creazione<'1274569200') group by c1,c2, c3 having count(c3)>1 2) select c1, c2, c3,count(c3) from (select * from form_name where data_created>'1272236400' and data_creazione<'1274569200') group by c1,c2, c3 having count(c3)>2 I need to select c1,c2,c3 all same and common found in both the result of query. how could this be done...could anyone help please?

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  • selecting a select list in jquery

    - by tessa
    There has to be something really simple that I am overlooking, but for some reason I cannot find any information about this and it keeps coming up so.. I am trying to select a select element in jquery. Right now I don't care about it's options, I just want the select element. If I have the following element: <select id="testSelect"><option>1</option></select> and I use jquery to select it: var selectElement = $("#testSelect"); I get an array of all the options in the select list, but not the select element itself. What am I missing?

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  • How do I Put Several Select Statements into Different Columns

    - by Russ Bradberry
    I basically have 7 select statement that I need to have the results output into separate columns. Normally I would use a crosstab for this but I need a fast efficient way to go about this as there are over 7 billion rows in the table. I am using the vertica database system. Below is an example of my statements: SELECT COUNT(user_id) AS '1' FROM event_log_facts WHERE date_dim_id=20100101 SELECT COUNT(user_id) AS '2' FROM event_log_facts WHERE date_dim_id=20100102 SELECT COUNT(user_id) AS '3' FROM event_log_facts WHERE date_dim_id=20100103 SELECT COUNT(user_id) AS '4' FROM event_log_facts WHERE date_dim_id=20100104 SELECT COUNT(user_id) AS '5' FROM event_log_facts WHERE date_dim_id=20100105 SELECT COUNT(user_id) AS '6' FROM event_log_facts WHERE date_dim_id=20100106 SELECT COUNT(user_id) AS '7' FROM event_log_facts WHERE date_dim_id=20100107

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  • Javascript Function for related select elements onSubmit

    - by Livingston
    I am trying to create (4) Select elements within a form element. Each select element has a different number of options. So if a user click one option on Select #1 and then click another option on Select #2, after hitting submit they will be taken to www.blah.com/option1/option2 page which will display the filtered results. Or they can chose an option from all 4 select menus and be taken to option1/option2/option3/option4 page. The categories are all related .Select #1 is a category, Select #2 is a subcategory of 1, Select #3 is a subcategory of #2 and Select #4 is a subcategory of #3. A great example would be on (LINK) http://www.safavieh.com/rugs (LINK) except only four Select elements. I would also like to add the "Reset" button next to "Submit." I know I need to construct a function in my header and use onSubmit attribute within the form but other than that I am unsure of what's involved so I'm hoping someone could point me in the right direction. It's important I learn most of this for myself. Thanks for your time Livingston

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  • explain these select statements!

    - by user329820
    Hi, I can not get the difference betwwn these statements? would you please help me,I have read some sample of select statements but I did not get these ones. SELECT 'B' FROM T WHERE A = (SELECT NULL); SELECT 'C' FROM T WHERE A = ANY (SELECT NULL); SELECT 'D' FROM T WHERE A = A; I use MySQL

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  • Efficiently select top row for each category in the set

    - by VladV
    I need to select a top row for each category from a known set (somewhat similar to this question). The problem is, how to make this query efficient on the large number of rows. For example, let's create a table that stores temperature recording in several places. CREATE TABLE #t ( placeId int, ts datetime, temp int, PRIMARY KEY (ts, placeId) ) -- insert some sample data SET NOCOUNT ON DECLARE @n int, @ts datetime SELECT @n = 1000, @ts = '2000-01-01' WHILE (@n>0) BEGIN INSERT INTO #t VALUES (@n % 10, @ts, @n % 37) IF (@n % 10 = 0) SET @ts = DATEADD(hour, 1, @ts) SET @n = @n - 1 END Now I need to get the latest recording for each of the places 1, 2, 3. This way is efficient, but doesn't scale well (and looks dirty). SELECT * FROM ( SELECT TOP 1 placeId, temp FROM #t WHERE placeId = 1 ORDER BY ts DESC ) t1 UNION ALL SELECT * FROM ( SELECT TOP 1 placeId, temp FROM #t WHERE placeId = 2 ORDER BY ts DESC ) t2 UNION ALL SELECT * FROM ( SELECT TOP 1 placeId, temp FROM #t WHERE placeId = 3 ORDER BY ts DESC ) t3 The following looks better but works much less efficiently (30% vs 70% according to the optimizer). SELECT placeId, ts, temp FROM ( SELECT placeId, ts, temp, ROW_NUMBER() OVER (PARTITION BY placeId ORDER BY ts DESC) rownum FROM #t WHERE placeId IN (1, 2, 3) ) t WHERE rownum = 1 The problem is, during the latter query execution plan a clustered index scan is performed on #t and 300 rows are retrieved, sorted, numbered, and then filtered, leaving only 3 rows. For the former query three times one row is fetched. Is there a way to perform the query efficiently without lots of unions?

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