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  • Issue Displaying/Hiding Views (Obj-C iPhone Programming)

    - by roswell
    All right all, So I've got a UITableView that is inited in applicationDidFinishLaunching like so: [self showForumList]; Said method does this: -(void)showForumList { ForumList *fl = [ForumList alloc]; [fl initWithNibName:@"ForumList" bundle:[NSBundle mainBundle]]; self.ForumList = fl; [window addSubview:[self.ForumList view]]; [fl release]; }where self.ForumList is previously defined in the interface as ForumList *ForumList;, etc. Now, in ForumList (itself an extension of UITableViewController obviously), I've got didSelectRowAtIndexPath: -- within it I have the following code: Forum *f = [Forum alloc]; NSArray *forums = [f getForumList]; NSDictionary *selectedForum = [forums objectAtIndex:[indexPath row]]; NSString *Url = [selectedForum objectForKey:@"url"]; NSString *Username = [selectedForum objectForKey:@"username"]; NSString *Password = [selectedForum objectForKey:@"password"]; NSLog(@"Identified press on forum %@ (%@/%@)", Url, Username, Password); [self.globalDelegate showForumListFromForumUsingUrl:Url username:Username password:Password]; [self.globalDelegate closeForumList]; NSLog(@"ForumListFromForum init"); Both of the NSLog calls in this function are executed and perform as they should. Now, here is where the issue starts. self.globalDelegate is defined as AppDelegate *globalDelegate; in the Interface specification in my header file. However, [self.globalDelegate showForumListFromForumUsingUrl:username:password] and and [self.globalDelegate closeForumList] are never actually called. They look like so: -(void)closeForumList { NSLog(@"Hiding forum list"); [[self.ForumList view] removeFromSuperview]; } -(void)showForumListFromForumUsingUrl:(NSString *)Url username:(NSString *)Username password:(NSString *)Password { NSLog(@"Showing forum list from forum"); ForumListFromForum *fl = [ForumListFromForum alloc]; [fl initWithNibName:@"ForumListFromForum" bundle:[NSBundle mainBundle]]; [fl initFromForumWithUrl:Url username:Username password:Password]; self.ForumListFromForum = fl; [window addSubview:[self.ForumListFromForum view]]; [fl release]; } The app does not respond to my press and neither of these NSLog calls are made. Any idea where I've gone wrong?

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  • php web services not getting data from iphone application

    - by user317192
    Hi, I am connecting with a php web service from my iphone application, I am doing a simple thing i.e. 1. Getting user inputs for: username password in a text field from the iphone form and sending the same to the PHP Post request web service. At the web service end I receive nothing other than blank fields that are inserted into the MySQL Database....... The code for sample web service is: ***********SAMPLE CODE FOR WEB SERVICES***** mysql_select_db("eventsfast",$con); $username = $_REQUEST['username']; $password = $_REQUEST['password']; echo $username; echo $password; $data = $_REQUEST; $fp = fopen("log.txt", "w"); fwrite($fp, $data['username']); fwrite($fp, $data['password']); $sql="INSERT INTO users(username,password) VALUES('{$username}','{$password}')"; if(!mysql_query($sql,$con)) { die('Error:'.mysql_error()); } echo json_encode("1 record added to users table"); mysql_close($con); echo "test"; ? ***************PHP******** ****** **************IPHONE EVENT CODE******* import "postdatawithphpViewController.h" @implementation postdatawithphpViewController @synthesize userName,password; -(IBAction) postdataid) sender { NSLog(userName.text); NSLog(password.text); NSString * dataTOB=[userName.text stringByAppendingString:password.text]; NSLog(dataTOB); NSData * postData=[dataTOB dataUsingEncoding:NSUTF8StringEncoding allowLossyConversion:YES]; NSString *postLength = [NSString stringWithFormat:@"%d", [postData length]]; NSLog(postLength); NSMutableURLRequest *request = [[[NSMutableURLRequest alloc] init] autorelease]; NSURL *url = [NSURL URLWithString:[NSString stringWithFormat:@"http://localhost:8888/write.php"]]; [request setURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody:postData]; NSURLResponse *response; NSError *error; [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; if(error==nil) NSLog(@"Error is nil"); else NSLog(@"Error is not nil"); NSLog(@"success!"); } Please help.............

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  • how to combine the error message from jquery validation

    - by aon
    how to combine the error message from jquery validation. for example: messages: { first_name: { required: "Please enter your first name." }, email: { required: "Please enter a valid email address.", remote: "Email has been registered." }, username: { required: "Please enter username.", remote: "Username has been registered." } }, Desired message will be like this: Please enter your first name, a valid email address and username or Please enter your first name and username, email has been registered etc.

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  • Looking under the hood of SSRS

    - by Jim Giercyk
    SSRS is a powerful tool, but there is very little available to measure it’s performance or view the SSRS execution log or catalog in detail.  Here are a few simple queries that will give you insight to the system that you never had before.   ACTIVE REPORTS:  Have you ever seen your SQL Server performance take a nose dive due to a long-running report?  If the SPID is executing under a generic Report ID, or it is a scheduled job, you may have no way to tell which report is killing your server.  Running this query will show you which reports are executing at a given time, and WHO is executing them.   USE ReportServerNative SELECT runningjobs.computername,             runningjobs.requestname,              runningjobs.startdate,             users.username,             Datediff(s,runningjobs.startdate, Getdate()) / 60 AS    'Active Minutes' FROM runningjobs INNER JOIN users ON runningjobs.userid = users.userid ORDER BY runningjobs.startdate               SSRS CATALOG:  We have all asked “What was the last thing that changed”, or better yet, “Who in the world did that!”.  Here is a query that will show all of the reports in your SSRS catalog, when they were created and changed, and by who.           USE ReportServerNative SELECT DISTINCT catalog.PATH,                            catalog.name,                            users.username AS [Created By],                             catalog.creationdate,                            users_1.username AS [Modified By],                            catalog.modifieddate FROM catalog         INNER JOIN users ON catalog.createdbyid = users.userid  INNER JOIN users AS users_1 ON catalog.modifiedbyid = users_1.userid INNER JOIN executionlogstorage ON catalog.itemid = executionlogstorage.reportid WHERE ( catalog.name <> '' )               SSRS EXECUTION LOG:  Sometimes we need to know what was happening on the SSRS report server at a given time in the past.  This query will help you do just that.  You will need to set the timestart and timeend in the WHERE clause to suit your needs.         USE ReportServerNative SELECT catalog.name AS report,        executionlogstorage.username AS [User],        executionlogstorage.timestart,        executionlogstorage.timeend,         Datediff(mi,e.timestart,e.timeend) AS ‘Time In Minutes',        catalog.modifieddate AS [Report Last Modified],        users.username FROM   catalog  (nolock)        INNER JOIN executionlogstorage e (nolock)          ON catalog.itemid = executionlogstorage.reportid        INNER JOIN users (nolock)          ON catalog.modifiedbyid = users.userid WHERE  executionlogstorage.timestart >= Dateadd(s, -1, '03/31/2012')        AND executionlogstorage.timeend <= Dateadd(DAY, 1, '04/02/2012')      LONG RUNNING REPORTS:  This query will show the longest running reports over a given time period.  Note that the “>5” in the WHERE clause sets the report threshold at 5 minutes, so anything that ran less than 5 minutes will not appear in the result set.  Adjust the threshold and start/end times to your liking.  With this information in hand, you can better optimize your system by tweaking the longest running reports first.         USE ReportServerNative SELECT executionlogstorage.instancename,        catalog.PATH,        catalog.name,        executionlogstorage.username,        executionlogstorage.timestart,        executionlogstorage.timeend,        Datediff(mi, e.timestart, e.timeend) AS 'Minutes',        executionlogstorage.timedataretrieval,        executionlogstorage.timeprocessing,        executionlogstorage.timerendering,        executionlogstorage.[RowCount],        users_1.username        AS createdby,        CONVERT(VARCHAR(10), catalog.creationdate, 101)        AS 'Creation Date',        users.username        AS modifiedby,        CONVERT(VARCHAR(10), catalog.modifieddate, 101)        AS 'Modified Date' FROM   executionlogstorage e         INNER JOIN catalog          ON executionlogstorage.reportid = catalog.itemid        INNER JOIN users          ON catalog.modifiedbyid = users.userid        INNER JOIN users AS users_1          ON catalog.createdbyid = users_1.userid WHERE  ( e.timestart > '03/31/2012' )        AND ( e.timestart <= '04/02/2012' )        AND  Datediff(mi, e.timestart, e.timeend) > 5        AND catalog.name <> '' ORDER  BY 'Minutes' DESC        I have used these queries to build SSRS reports that I can refer to quickly, and export to Excel if I need to report or quantify my findings.  I encourage you to look at the data in the ReportServerNative database on your report server to understand the queries and create some of your own.  For instance, you may want a query to determine which reports are using which shared data sources.  Work smarter, not harder!

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  • Linksys router cannot change default password

    - by Jessica M.
    My wireless internet suddenly stopped working today. I have Windows 7 and Lindsys WRT54G router. I tried to log into the Linksys setup router page by typing in www.192.168.1.1 into firefox and it prompted me for a username and password as usual. The problem is when i tried to enter my regular username and password it did not work. I finally solved my problem when I came across this post here and the very last post solved my problem. It suggested I try username: root / password: admin. For some reason the username and password has been changed. When i tried username: root / password: admin , it worked and allowed me to get into the Linksys setup page. The problem is I can't change the username or password anymore. Every time I want to log into my Linksys setup page I have to enter username: root / password: admin. I can't change the "WPA shared key" (password). For the security settings I selected WPA2Personal + AES. Also the post said "If the firmware was upgraded to non-linksys firmware - the default will be different" . The problem is I didn't update anything and I'm worried that someone installed a virus or something or somehow changed the firmware on my router. How did I get non-Linksys firmware on my router? EDIT: I figured out how to change the password when I log into the Lynksys setup page. Administration -- Management -- password. I still don't understand if my router firmware was changed or who changed it or if it happened by mistake.

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  • A single AD user can't log into a single Mac bound to the domain (DirectoryServices error). How can I resolve this?

    - by Ben Wyatt
    On our campus, we have about 60 Macs joined to our Active Directory domain. Most users have no problems logging into Macs, as long as their accounts are configured correctly. However, we have one particular user who is unable to log in to just some of the Macs. He has no problem with most of them, but there is one group of them (all built from the same image) that he can't log in to. The machine in question is running OS X 10.6.2. The relevant entries from secure.log are below, with the hostname and username redacted. Aug 16 10:32:43 hostname SecurityAgent[4411]: Could not get the user record for username from DirectoryServices. Aug 16 10:32:43 hostname SecurityAgent[4411]: Will sleep 1 seconds and try again (retryCount = 4) Aug 16 10:32:44 hostname SecurityAgent[4411]: Could not get the user record for username from DirectoryServices. Aug 16 10:32:44 hostname SecurityAgent[4411]: Will sleep 2 seconds and try again (retryCount = 3) Aug 16 10:32:46 hostname SecurityAgent[4411]: Could not get the user record for username from DirectoryServices. Aug 16 10:32:46 hostname SecurityAgent[4411]: Will sleep 4 seconds and try again (retryCount = 2) Aug 16 10:33:10 hostname SecurityAgent[4411]: Could not get the user record for username from DirectoryServices. Aug 16 10:33:10 hostname SecurityAgent[4411]: Will sleep 8 seconds and try again (retryCount = 1) Aug 16 10:33:18 hostname SecurityAgent[4411]: User info context values set for username Aug 16 10:33:18 hostname SecurityAgent[4411]: unknown-user (username) login attempt PASSED for auditing Everything I've found online suggests that our use of Mobile Accounts is causing the issue. I turned that feature off, but I still can't log in as that user. id returns a record for his account, and nothing looks out of the ordinary. Has anyone here run into this before?

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  • Cannot Start Passenger 3.0.18 Using Mountain Lion (OS X Server) and RVM

    - by LightBe Corp
    I recently did a clean install of Mountain Lion on my Mac Mini Server. I installed version 3.0.18 using a gem according to the directions on http://www.phusionpassenger.com with no errors that I could see. rvmsudo gem install passenger-enterprise-server-3.0.18.gem rvmsudo passenger-install-apache2-module Here are my entries in /etc/apache2/httpd.conf with my username masked: LoadModule passenger_module /Users/username/.rvm/gems/ruby-1.9.3-p327/gems/passenger-enterprise-server-3.0.18/ext/apache2/mod_passenger.so PassengerRoot /Users/username/.rvm/gems/ruby-1.9.3-p327/gems/passenger-enterprise-server-3.0.18 PassengerRuby /Users/username/.rvm/wrappers/ruby-1.9.3-p327/ruby I uncommented out the following statement: Include /private/etc/apache2/extra/httpd-vhosts.conf Here is a sample virtual host entry. I have three of them in the file. <VirtualHost *:80> ServerName www.mydomain.com ServerAlias mydomain.com PassengerAppRoot /Users/username/Sites/myfolder/ DocumentRoot /Users/username/Sites/myfolder/public <Directory /Users/username/Sites/myfolder/public> Allow from all AllowOverride all Options -MultiViews </Directory> </VirtualHost> I have restarted Apache several times. Here is information from my server: [~]$ ps -ef | grep Passenger 501 18804 303 0 12:39PM ttys000 0:00.00 grep Passenger [~]$ rvmsudo passenger-status Password: **ERROR: Phusion Passenger doesn't seem to be running.** [~]$ rvmsudo passenger-config --version 3.0.18 I have tried doing online searches on this. I was surprised that there was not all that much on this specific error even though from my understanding Passenger has been around for a few years. I have posted this issue on the Phusion Passenger Google Groups but have not heard anything. Any help would be appreciated, the sooner the better LOL. Seriously I need to have one of my three websites up by tomorrow evening. This is the only issue stopping that from happening. Thanks again.

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  • How to Send user to two different web pages when login

    - by Pradeep
    protected static Boolean Authentication(string username, string password) { string sqlstring; sqlstring = "Select Username, Password, UserType from Userprofile WHERE Username='" + username + "' and Password ='" + password + "'"; // create a connection with sqldatabase System.Data.SqlClient.SqlConnection con = new System.Data.SqlClient.SqlConnection( "Data Source=PRADEEP-LAPTOP\\SQLEXPRESS;Initial Catalog=BookStore;Integrated Security=True"); // create a sql command which will user connection string and your select statement string System.Data.SqlClient.SqlCommand comm = new System.Data.SqlClient.SqlCommand(sqlstring, con); // create a sqldatabase reader which will execute the above command to get the values from sqldatabase System.Data.SqlClient.SqlDataReader reader; // open a connection with sqldatabase con.Open(); // execute sql command and store a return values in reade reader = comm.ExecuteReader(); // check if reader hase any value then return true otherwise return false if (reader.Read()) return true; else return false; } Boolean blnresult; blnresult = Authentication(Login2.UserName, Login2.Password); if (blnresult == true) { Session["User_ID"] = getIDFromName(Login2.UserName); Session["Check"] = true; Session["Username"] = Login2.UserName; Response.Redirect("Index.aspx"); } so a user like Staff or even Administrators loging to same Index.aspx. i want to change it to different web pages. how to change sites for each user types. i have seperate user types. and i have taken UserType in the Authentication function.

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  • function using cl-who:with-html-output ignoring parameter

    - by shanked
    I'm not sure whether this is an issue with my use of cl-who (specifically with-html-output-to-string and with-html-output) or an issue with my understanding of Common Lisp (as this is my first project using Lisp). I created a function to create form fields: (defun form-field (type name label) (cl-who:with-html-output (*standard-output* nil) (:div :class "field" (:label :for name label) (:input :type type :name name)))) When using this function, ie: (form-field "text" "username" "Username") the parameter label seems to be ignored... the HTML output is: <div class="field"><label for="username"></label> <input type="text" name="username"/></div> instead of the expected output: <div class="field"><label for="username">Username</label> <input type="text" name="username"/></div> If I modify the function and add a print statement: (defun form-field (type name label) (cl-who:with-html-output (*standard-output* nil) (print label) (:div :class "field" (:label :for name label) (:input :type type :name name)))) The "Username" string is successfully output (but still ignored in the HTML)... any ideas what might cause this? Keep in mind, I'm calling this function within a cl-who:with-html-output-to-string for use with hunchentoot.

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  • SHA function issues

    - by Damian James
    I have this php code from my login.php if (isset($_POST['logIn'])) { $errmsg = ""; $logname = mysqli_real_escape_string($dbc, trim($_POST['usernameIn'])); $logpassword = mysqli_real_escape_string($dbc, trim($_POST['passwordIn'])); $query = "SELECT user_id, username FROM members WHERE username = '$logname' AND password = SHA('$logpassword')"; $data = mysqli_query($dbc, $query); if (mysqli_num_rows($data) == 1) { $row = mysqli_fetch_array($data); setcookie('user_id', $row['user_id'], time() + (60 * 60 * 24 * 30)); //expires after 30 days setcookie('username', $row['username'], time() + (60 * 60 * 24 * 30)); $home = 'http://' . $_SERVER['HTTP_HOST'] . dirname($_SERVER['PHP_SELF']) . '/index.php'; header('Location: ' . $home); } else { $errmsg = '<p class="errormsg">Username or password is incorrect.</p>'; } } And for some reason, it always ends up setting $errmsg in the else statement. I am sure that I'm entering information (username,password) that is correct and exists in the database. I insert my values (from a signup script) using this query: $query = "INSERT INTO members (username, password, email) VALUES ('$username', SHA('$password'), '$email')"; Anyone see the problem with this script? Thanks!

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  • Adding a class to the $tag surrounding a <label> in a Zend_Form with the Label decorator

    - by Roderik
    I'm trying to get the following html out of Zend_Form <div class="group wat-cf"> <div class="left"> <label class="label right">Username</label> </div> <div class="right"> <input type="text" class="text_field"> </div> </div> Using the following code: $username->setAttrib("class", "text_field") ->setDecorators(array( 'ViewHelper', 'Description', 'Errors', array(array('data'=>'HtmlTag'), array('tag' => 'div', 'class' => 'right')), array('Label', array('tag' => 'div', 'class' => 'label right')), array(array('row'=>'HtmlTag'),array('tag'=>'div', 'class' => 'group wat-cf')) )); I can get the next fragment <div class="group wat-cf"> <div id="username-label"> <label for="username" class="label right required">Username:</label> </div> <div class="right"> <input type="text" name="username" id="username" value="" class="text_field"> </div> </div> so apart from some extra id's and required classes i don't mind, i need to get a class "left" on div id="username-label" Now adding class to the Label line, gets the class added on the element. I also don't see and option to do this in the Label decorator code itself. So i need a custom Label decorator, or is there some other way i'm missing?

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  • Pull specific information from a long list with Perl

    - by melignus
    The file that I've got to work with here is the result of an LDAP extraction but I need to ultimately get the information formatted over to something that a spreadsheet can use. So, the data is as follows: DataDataDataDataDataDataDataDataDataDataDataDataDataDataDataData DataDataDataDataDataDataDataDataDataDataDataDataDataDataDataData displayName: John Doe name: ##userName DataDataDataDataDataDataDataDataDataDataDataDataDataDataDataData DataDataDataDataDataDataDataDataDataDataDataDataDataDataDataData displayName: Jane Doe name: ##userName DataDataDataDataDataDataDataDataDataDataDataDataDataDataDataData DataDataDataDataDataDataDataDataDataDataDataDataDataDataDataData displayName: Ted Doe name: ##userName The format that I need to export to is: firstName lastName userName firstName lastName userName firstName lastName userName Where the spaces are tabs so I can then impor that file into a database. I have experience doing this in VBScript but I'm trying to switch over to using Perl for as much server administration as possible. I'm not sure on the syntax for what I want which is basically while not endoffile{ detect "displayName: " & $firstName & " " & $lastName detect "name: ##" & $userName write $firstName tab $lastName tab $userName to file } Also if someone could point me to a resource specifically on the text parsing syntax that Perl uses, I'd be very grateful. Most of the resources that I've come across haven't been very helpful.

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  • Open txt files from a directory, compare the values, and output the top 15 in PHP

    - by Anon
    Hello, I recently designed a referral game website for the fun of it. There's a simple MySQL user system with a email verification. It's using the UserCake user management system. On top of this i added a php page that the user could give to "victims" that when they visit it they get "infected" and can infect other users or "victims". This page uses GET to get the username from the url. I have a folder that when a user registers it creates a file with 4 digits and then the username. (ex; 0000Username.txt) All the numbers are the same, it's just so that if a user discovers the folder they won't be able to find the files. There is also a txt file in the same format with IPS in the name. (ex; 0000IPSUsername.txt) The file when visited gets the username from the url, then checks if the text file for that username exists. If the username is present in the url, and a valid user it opens the IPS file and adds the IP of the visitor, then opens the user text file, takes the value and adds one to it, and saves. At the end it makes the difference between saying "You are infected, Username has infected (amount) people." or just you have been infected. Now to what i need! I need to add a hi-scores to the website so people can compete to be the one with the most "infections". I thought i could use readdir to get a list of the files and open them with the value in an array, but i need it to also strip the username from the file name. It would be best if it just saves to a text file like "Username | value" because then i can add echo's of the html tags and have it include the file in the page i want it to be one. Many thanks in advance.

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  • Ajax: strange behaviour while checking a textfield

    - by ilnur777
    I have a registration form with checking the available name for username field through ajax. Inputing a username into username field and pushing the "Check!" button, the script sends value to php script. Then php script replaces the username field with the username field + style like this: <input type="text" name="login" value="'.$_GET["user"].'" style="width:205; height:22; border-width:1; border-color:red; border-style:solid; background-color:rgb(255,232,230);"> So when replacing the username field in the form with its equivalent from php script and then submitting a form, it is then get to script on the page that checks whether the username field is empty or not. And it returns an error that it is empty, though after checking through ajax the username field it has value. I don't understand why it gets to empty field checking script, having the same field name and having value?

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  • how to redirect user depending on user type at time of login (codeignitor)

    - by Anam Tahir
    im facing problem while redirecting my user according to its type. how can do it here's my code plz suggest how to do it. <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class VerifyLogin extends CI_Controller { function __construct() { parent::__construct(); } function index() { $this->load->model('user','',TRUE); //This method will have the credentials validation $this->load->library('form_validation'); $this->load->library('session'); $this->form_validation->set_rules('username', 'Username','trim|required|xss_clean'); $this->form_validation->set_rules('password', 'Password' 'trim|required|xss_clean|callback_check_database'); if($this->form_validation->run() == FALSE) { //Field validation failed.&nbsp; User redirected to login page validation_errors(); $this->load->view('error'); } else { //Go to private area basically here i want to redirect if user is admin then redirect to admin page else redirect to home how can i do this ??? redirect('home', 'refresh'); } } function check_database($password) { //Field validation succeeded.&nbsp; Validate against database $username = $this->input->post('username'); //query the database $result = $this->user->login($username, $password); if($result) { $sess_array = array(); foreach($result as $row) { $sess_array = array( 'id' => $row->id, 'username' => $row->username ); $this->session->set_userdata('logged_in', $sess_array); } return TRUE; } else { $this->form_validation->set_message('check_database', 'Invalid username or password'); return false; } } } ?>

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  • Need a refresher course on property access...

    - by Code Sherpa
    Hi. I need help with accessing class properties within a given class. For example, take the below class: public partial class Account { private Profile _profile; private Email _email; private HostInfo _hostInfo; public Profile Profile { get { return _profile; } set { _profile = value; } } public Email Email { get { return _email; } set { _email = value; } } public HostInfo HostInfo { get { return _hostInfo; } set { _hostInfo = value; } } In the class "Account" exists a bunch of class properties such as Email or Profile. Now, when I want to access those properties at run-time, I do something like this (for Email): _accountRepository = ObjectFactory.GetInstance<IAccountRepository>(); string username = Cryptography.Decrypt(_webContext.UserNameToVerify, "verify"); Account account = _accountRepository.GetAccountByUserName(username); if(account != null) { account.Email.IsConfirmed = true; But, I get "Object reference not set..." for account.Email... Why is that? How do I access Account such that account.Email, account.Profile, and so on returns the correct data for a given AccountId or UserName. Here is a method that returns Account: public Account GetAccountByUserName(string userName) { Account account = null; using (MyDataContext dc = _conn.GetContext()) { try { account = (from a in dc.Accounts where a.UserName == userName select a).FirstOrDefault(); } catch { //oops } } return account; } The above works but when I try: account = (from a in dc.Accounts join em in dc.Emails on a.AccountId equals em.AccountId join p in dc.Profiles on em.AccountId equals p.AccountId where a.UserName == userName select a).FirstOrDefault(); I am still getting object reference exceptions for my Email and Profile properties. Is this simply a SQL problem or is there something else I need to be doing to be able to fully access all the properties within my Account class? Thanks!

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  • Make password case unsensitive in shared ASP.Net membership tables web ap

    - by bill
    Hi all, i have two webapps.. that share ASP.Net membership tables. Everything works fine except i cannot remove case-sensitivity in one of the apps the way i am doing it in the other. in the non-working app void Login1_LoggingIn(object sender, LoginCancelEventArgs e) { string username = Login1.UserName.Trim(); if (!string.IsNullOrEmpty(username)) { MembershipUser user = Membership.GetUser(username); if (user != null) { // Only adjust the UserName if the password is correct. This is more secure // so a hacker can't find valid usernames if we adjust the case of mis-cased // usernames with incorrect passwords. string password = Login1.Password.ToUpper(); if (Membership.ValidateUser(user.UserName, password)) { Login1.UserName = user.UserName; } } } } is not working. the password is stored as all upper case. Converted at the time the membership user is created! So if the password is PASSWORD, typing PASSWORD allows me to authenticate. but typing password does not! Even though i can see the string being sent is PASSWORD (converted with toUpper()). I am at a complete loss on this.. in the other app i can type in lower or upper or mixed and i am able to authenticate. In the other app i am not using the textboxes from the login control though.. not sure if this is making the difference??

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  • Insert not working

    - by user1642318
    I've searched evreywhere and tried all suggestions but still no luck when running the following code. Note that some code is commented out. Thats just me trying different things. SqlConnection connection = new SqlConnection("Data Source=URB900-PC\SQLEXPRESS;Initial Catalog=usersSQL;Integrated Security=True"); string password = PasswordTextBox.Text; string email = EmailTextBox.Text; string firstname = FirstNameTextBox.Text; string lastname = SurnameTextBox.Text; //command.Parameters.AddWithValue("@UserName", username); //command.Parameters.AddWithValue("@Password", password); //command.Parameters.AddWithValue("@Email", email); //command.Parameters.AddWithValue("@FirstName", firstname); //command.Parameters.AddWithValue("@LastName", lastname); command.Parameters.Add("@UserName", SqlDbType.VarChar); command.Parameters["@UserName"].Value = username; command.Parameters.Add("@Password", SqlDbType.VarChar); command.Parameters["@Password"].Value = password; command.Parameters.Add("@Email", SqlDbType.VarChar); command.Parameters["@Email"].Value = email; command.Parameters.Add("@FirstName", SqlDbType.VarChar); command.Parameters["@FirstName"].Value = firstname; command.Parameters.Add("@LasttName", SqlDbType.VarChar); command.Parameters["@LasttName"].Value = lastname; SqlCommand command2 = new SqlCommand("INSERT INTO users (UserName, Password, UserEmail, FirstName, LastName)" + "values (@UserName, @Password, @Email, @FirstName, @LastName)", connection); connection.Open(); command2.ExecuteNonQuery(); //command2.ExecuteScalar(); connection.Close(); When I run this, fill in the textboxes and hit the button I get...... Must declare the scalar variable "@UserName". Any help would be greatly appreciated. Thanks.

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  • problem in variables in jquery

    - by Alvin
    Hi, I don't understand why I'm not getting the message as "username already exits" if type the username which is already in database. If the username in a server, then it is returning the value as "1" otherwise empty, and despite of successfully getting the value from the server based on username is present or not, and assigning the value to variable "x", I'm unable to get message when I pass already exist username. May I know? $(document).ready(pageInit); function pageInit() { $('#1').bind('blur',go); } function go() { var value = $('#1').val(); var x = 0; $.post('just.do',{username:value},function(data){ x = data; } ); if(x) { $('#para').show(); $('#para').html("Username already exits"); return false; } else { $('#para').hide(); return true; } }; EDIT: This is what I'm doing in post request in servlets: String user1 = request.getParameter("username"); if(user != null) { String query = "Select * from users where user_name="+"\""+user+"\""; b = db.doExecuteQuery(stmt,query); if(b) { out.write("1"); } }

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  • Faster Javascript text replace

    - by Stacey
    Given the following javascript (jquery) $("#username").keyup(function () { selected.username = $("#username").val(); var url = selected.protocol + (selected.prepend == true ? selected.username : selected.url) + "/" + (selected.prepend == true ? selected.url : selected.username); $("#identifier").val(url); }); This code basically reads a textbox (username), and when it is typed into, it reconstructs the url that is being displayed in another textbox (identifier). This works fine - there are no problems with its functionality. However it feels 'slow' and 'sluggish'. Is there a cleaner/faster way to accomplish this task? Here is the HTML as requested. <fieldset class="identifier delta"> <form action="/authenticate/openid" method="post" target="_top" > <input type="text" class="openid" id="identifier" name="identifier" readonly="readonly" /> <input type='text' id='username' name='username' class="left" style='display: none;'/> <input type="submit" value="Login" style="height: 32px; padding-top: 1px; margin-right: 0px;" class="login right" /> </form> </fieldset> The identifier textbox just has a value set based on the hyperlink anchor of a button.

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  • when i create user it aoutomaticaly logged in to newly created user how can i prevent it?

    - by kalyani
    heloo public partial class CreateUser : System.Web.UI.Page { TextBox username; protected void Page_Load(object sender, EventArgs e) { Class1.OpenConn(); string[] rolesArray; if(!(IsPostBack)) { rolesArray = Roles.GetAllRoles(); rdButtonListRoles.DataSource = rolesArray; rdButtonListRoles.DataBind(); } if(IsPostBack) { Class1 cs = new Class1(); username = (TextBox)CreateUserWizard1.CreateUserStep.ContentTemplateContainer.FindControl("UserName"); ProfileCommon newProf; newProf = Profile.GetProfile(username.Text); TextBox MobileNo, name, Sirname; name = (TextBox)CreateUserWizard1.CreateUserStep.ContentTemplateContainer.FindControl("txtname"); Sirname = (TextBox)CreateUserWizard1.CreateUserStep.ContentTemplateContainer.FindControl("txtSirname"); MobileNo = (TextBox)CreateUserWizard1.CreateUserStep.ContentTemplateContainer.FindControl("MobileNo"); newProf.Name = name.Text; newProf.Sirname = Sirname.Text; newProf.MobileNo = MobileNo.Text; newProf.Save(); RoleDiv.Visible = false; } } protected void ContinueButton_Click(object sender, EventArgs e) { for (int i = 0; i < rdButtonListRoles.Items.Count; i++) { if (rdButtonListRoles.Items[i].Selected == true) { if (!Roles.IsUserInRole(username.Text, rdButtonListRoles.Items[i].Text)) { Roles.AddUserToRole(username.Text, rdButtonListRoles.Items[i].Text.ToString()); } } else { if (Roles.IsUserInRole(username.Text, rdButtonListRoles.Items[i].Text)) { Roles.RemoveUserFromRole(username.Text, rdButtonListRoles.Items[i].Text.ToString()); } } } Response.Redirect("ManageUser.aspx"); } protected void CreateUserWizard1_CreatedUser(object sender, EventArgs e) { } } plz give me the solution help me

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  • The type or namespace name 'WebControls' could not be found (are you missing a using directive or an assembly reference?)

    - by user1467175
    I encountered this error: The type or namespace name 'WebControls' could not be found (are you missing a using directive or an assembly reference?) Source Error: Line 28: Login Login1 = (WebControls.Login)LoginView1.FindControl("Login1"); // here the error code Line 29: TextBox UserName = (TextBox)Login1.FindControl("UserName"); Line 30: TextBox FailureText = (TextBox)Login1.FindControl("FailureText"); I did some research and the solution was to add this into the source code: System.Web.UI.WebControls.Login but I have no idea where this code can be add into. At first I tried putting it as a namespace, but it was wrong. Anyone can tell me where should I place this code at?? EDIT protected void Login1_LoginError(object sender, System.EventArgs e) { //Login Login1 = (WebControls.Login).LoginView1.FindControl("Login1"); Login Login1 = (System.Web.UI.WebControls.Login)LoginView1.FindControl("Login1"); TextBox UserName = (TextBox)Login1.FindControl("UserName"); TextBox FailureText = (TextBox)Login1.FindControl("FailureText"); //There was a problem logging in the user //See if this user exists in the database MembershipUser userInfo = Membership.GetUser(UserName.Text); if (userInfo == null) { //The user entered an invalid username... FailureText.Text = "There is no user in the database with the username " + UserName.Text; } else { //See if the user is locked out or not approved if (!userInfo.IsApproved) { FailureText.Text = "When you created your account you were sent an email with steps to verify your account. You must follow these steps before you can log into the site."; } else if (userInfo.IsLockedOut) { FailureText.Text = "Your account has been locked out because of a maximum number of incorrect login attempts. You will NOT be able to login until you contact a site administrator and have your account unlocked."; } else { //The password was incorrect (don't show anything, the Login control already describes the problem) FailureText.Text = string.Empty; } } }

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  • Error using maven profiles

    - by user3127896
    I've added two profiles to my application and that how it looks: <profiles> <profile> <id>dev</id> <properties> <db.username>root</db.username> <db.password>root</db.password> <db.connectionURL>localhost:3306</db.connectionURL> <db.driverClass>com.mysql.jdbc.Driver</db.driverClass> </properties> </profile> <profile> <id>prod</id> <properties> <db.username>prodroot</db.username> <db.password>prodpass</db.password> <db.connectionURL>localhost:3306</db.connectionURL> <db.driverClass>com.mysql.jdbc.Driver</db.driverClass> </properties> </profile> </profiles> In my jdbc.properties file i changed values like this: jdbc.driverClassName=${db.driverClass} jdbc.dialect=org.hibernate.dialect.MySQLDialect jdbc.databaseurl=jdbc:mysql://${db.connectionURL}/dbname jdbc.username=${db.username} jdbc.password=${db.password} And here's bean from spring-container.xml <bean id="dataSource" class="org.apache.commons.dbcp.BasicDataSource" destroy-method="close" p:driverClassName="${jdbc.driverClassName}" p:url="${jdbc.databaseurl}" p:username="${jdbc.username}" p:password="${jdbc.password}" /> When i try to deploy my application i got following error: SEVERE: Exception sending context initialized event to listener instance of class org.springframework.web.context.ContextLoaderListener org.springframework.beans.factory.BeanDefinitionStoreException: Invalid bean definition with name 'dataSource' defined in ServletContext resource [/WEB-INF/spring-servlet.xml]: Could not resolve placeholder 'db.driverClass' Structure of project: Any ideas what i'm doing wrong? Thanks in advance!

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  • I'm trying to pass a string from my first ViewController to my second ViewController but it returns NULL

    - by Dashony
    In my first view controller I have 3 input fields each of them take the user input into and saves it into a string such as: address, username and password as NSUserDefaults. This part works fine. In my second view controller I'm trying to take the 3 strings from first controller (address, username and password) create a html link based on the 3 strings. I've tried many ways to access the 3 strings with no luck, the result I get is NULL. Here is my code: //.h file - first view controller with the 3 input fields CamSetup.h #import <UIKit/UIKit.h> @interface CamSetup : UIViewController <UITextFieldDelegate> { NSString * address; NSString * username; NSString * password; IBOutlet UITextField * addressField; IBOutlet UITextField * usernameField; IBOutlet UITextField * passwordField; } -(IBAction) saveAddress: (id) sender; -(IBAction) saveUsername: (id) sender; -(IBAction) savePassword: (id) sender; @property(nonatomic, retain) UITextField *addressField; @property(nonatomic, retain) UITextField *usernameField; @property(nonatomic, retain) UITextField *passwordField; @property(nonatomic, retain) NSString *address; @property(nonatomic, retain) NSString *username; @property(nonatomic, retain) NSString *password; @end //.m file - first view controller CamSetup.m #import "CamSetup.h" @interface CamSetup () @end @implementation CamSetup @synthesize addressField, usernameField, passwordField, address, username, password; -(IBAction) saveAddress: (id) sender { address = [[NSString alloc] initWithFormat:addressField.text]; [addressField setText:address]; NSUserDefaults *stringDefaultAddress = [NSUserDefaults standardUserDefaults]; [stringDefaultAddress setObject:address forKey:@"stringKey1"]; NSLog(@"String [%@]", address); } -(IBAction) saveUsername: (id) sender { username = [[NSString alloc] initWithFormat:usernameField.text]; [usernameField setText:username]; NSUserDefaults *stringDefaultUsername = [NSUserDefaults standardUserDefaults]; [stringDefaultUsername setObject:username forKey:@"stringKey2"]; NSLog(@"String [%@]", username); } -(IBAction) savePassword: (id) sender { password = [[NSString alloc] initWithFormat:passwordField.text]; [passwordField setText:password]; NSUserDefaults *stringDefaultPassword = [NSUserDefaults standardUserDefaults]; [stringDefaultPassword setObject:password forKey:@"stringKey3"]; NSLog(@"String [%@]", password); } - (void)viewDidLoad { [addressField setText:[[NSUserDefaults standardUserDefaults] objectForKey:@"stringKey1"]]; [usernameField setText:[[NSUserDefaults standardUserDefaults] objectForKey:@"stringKey2"]]; [passwordField setText:[[NSUserDefaults standardUserDefaults] objectForKey:@"stringKey3"]]; [super viewDidLoad]; } @end //.h second view controller LiveView.h #import <UIKit/UIKit.h> #import "CamSetup.h" @interface LiveView : UIViewController { NSString *theAddress; NSString *theUsername; NSString *thePassword; CamSetup *camsetup; //here is an instance of the first class } @property (nonatomic, retain) NSString *theAddress; @property (nonatomic, retain) NSString *theUsername; @property (nonatomic, retain) NSString *thePassword; @end //.m second view LiveView.m file #import "LiveView.h" @interface LiveView () @end @implementation LiveView @synthesize theAddress, theUsername, thePassword; - (void)viewDidLoad { [super viewDidLoad]; theUsername = camsetup.username; //this is probably not right? NSLog(@"String [%@]", theUsername); //resut here is NULL NSLog(@"String [%@]", camsetup.username); //and here NULL as well } @end

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  • Fixed number format in ANTLR

    - by sarav
    How to specify a fixed digit number in antlr grammar? I want to parse a line which contains fields of fixed number of characters. Each field is a number. 0034|9056|4567|0987|-2340| +345|1000 The above line is a sample line. | indicates field boundaries. The fields can include blank characters +/-

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